an interference pattern is produced by four parallel and equally spaced narrow slits. by drawing appropriate phasor diagrams, explain why there is an interference minimum when the phase difference from adjacent slits is:

The relative motion of gaseous particles increases with increase in the temperature of the gas molecules just like the motion of popcorn in a popper increases when heat is applied to the popper.

The kinetic theory of gases or matter states that matter consists of tiny particles which are constant motion, colliding with one another and with walls of the containing vessels.

Just like a popcorn in a popcorn popper pops when heat is applied to the popper, gases contained in a cylinder increases their speed when they acquire more kinetic energy as the temperature of the cylinder increases.

Thus, the motion of gas particles depends on the temperature of the containing vessel so also does the random motion of popcorn depends on the temperature of the popper.

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The given problem is related to the calorimetry. The definition of calorimetry states that, "Calorimetry is the science of determining the change in energy of a system by measuring the heat exchange of the system with the surroundings". According to this, the temperature change of A will be one sixth of the temperature change of B. Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

Temperature change of A related to the temperature change of B

In this case, for object A:

QA = cA× mA× (ΔT)A

and for object B:

QB = cB× mB× (ΔT)B

You know:

Object A has double the specific heat of object B. ⇒ cA= 2× cB

Object A has triple the mass of object B. ⇒ mA= 3× mB

If the same amount of heat is applied to both objects ⇒ QA= QB

Then:

cA× mA× (ΔT)A= QB = cB× mB× (ΔT)B

2× cB × 3× mB× (ΔT)A=  cB× mB× (ΔT)B

Solving:

6× cB × mB× (ΔT)A= cB× mB× (ΔT)B

(ΔT)A= (cB× mB× (ΔT)B) ÷ (6× cB × mB)

(ΔT)A= (ΔT)B

Finally, the temperature change of A will be one sixth of the temperature change of B.

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The mass of the truck is 12,974.4kg .

As a measure of inertia, which is a fundamental characteristic of all matter, mass is used in physics. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force.

Measures a substance's resistance to acceleration in physics. A measure of an object's mass is roughly equivalent to counting the atoms that make up the object. The kilogram serves as the fundamental mass unit. Mass multiplied by the gravitational acceleration equals weight.

50km/h =50×5/18 m/s= 13.88 = 13.9

momentum (p)=180,345 kg.m/s

P=mv

180,345= m X 13.9

m = 180345/13.9

m = 12,974.46

m = 12,974.4

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To understand the questions, one should know the structure of an atom.

An atom is made up of some subatomic particles. These particles are positively charged, negatively charged and neutral particles.

The positive and negative charged particles neutralize the atom and the neutral subatomic particles are neutrons.

The answer to the questions are as follows:

1. The subatomic particle with no electrical charge is the "neutron".

2. The subatomic particle with a positive charge is the "proton".

3. The subatomic particle with a negative charge is the "electrons".

4. There are the same number of these two particles in an atom are "electrons" & "protons".

5. The atomic number is the same as the number of "protons" in an atom.

To sum up, an atom has different particles such as protons, electrons and neutrons. With protons being the positively charged, electrons are negatively charged and neutrons are neutral. Neutrons and protons are found in the nucleus and the electrons are spread around the nucleus.

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When the ball leaves the hand, it's kinetic energy is 160 Joules.

The kinetic energy of object is due to its virtue of motion. So, as the ball leaves the hand, it is in motion. The formula representing kinetic energy is: K.E. = 1/2×m×v², where K.E. is kinetic energy, m is mass and v is velocity.

Keep the values in formula to find the kinetic energy of the ball.

K.E. = 1/2×20×4²

Taking square on Right Hand Side of the equation

K.E. = 1/2×20×16

Performing multiplication and division on Right Hand Side of the equation

K.E. = 160 Joules

Thus, kinetic energy of ball is 160 Joules.

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ANSWER

EXPLANATION

If force F keeps the object in equilibrium

Answer:

See below

Explanation:

Find the x components of all of the forces shown, add them together, the x-component of the force F will be exactly opposite ( same magnitude but 180 degrees different)

30 cos 55  +     40 cos 205   +   50 cos 320  =  19.26    <====x component sum of all of the forces shown

F  (the x component of ) will be   Either    - 19.26   At zero degrees

                                                                 Or 19.26 at 180 degrees

Torque Formula:

T = d * F * sin angle

a) if the force is doubled, torque is doubled ( directly proportional)

For example, if force is 2 N, and distance is 2 m ,

T= 2*2* sin 90 = 4 Nm

If force is doubled:

T= 2*4 * sin90 = 8 Nm

b) If the distance of the center of rotation is doubled , Torque is also doubled ( same as "a")

c) If angle decreases 45° (90 - 45 = 45 )

T= 2*2*sin45 = 2.82 Nm

Torque also decreases

Answer:

Duck to avoid the ball and dodge the rhino’s attack and then try and climb the nearest tree. Hope that helps.

Explanation:

For me I’d say it’d be instinct for the answer.

Given data

*The given mass of the car is m = 1475 kg

*The maximum tension is T = 2551 N

The formula for the maximum possible acceleration of the truck is given by Newton's second law as

Substitute the known values in the above expression as

Hence, the maximum possible acceleration of the truck is a_max = 1.72 m/s^2

The value of force exerted on the women will be normal of the lift in positive x direction .

Acceleration is defined as change of velocity divided by time.

Since lift is moving upward at a steady speed , that means no change of speed has been taken place . hence no acceleration.

There is no external acceleration acting on the lift . Hence there will be  two forces, one is the force of gravity and the other is upward normal force from the elevator.

N = mg if the elevator is at rest or moving at constant velocity

The value of force exerted on the women will be normal of the lift in positive x direction

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At wavelength 2.898 x 10^-7 m radiation is maximum in UV region and at wavelength 2.898x 10^-10 meter in X ray region.

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From Newton's second law of motion,

F = ma

We know m = 65 kg. Next, we have to find a through this formula:

v² = v₀² + 2ad

0² = (18 m/s)² + 2(a)(1 m)

Solving for a,

a = -162 m/s²

So,

F = (65 kg)(-162 m/s²) = -10,530 Newtons.

A crumpled zone in the front of the car gradually slows the car down and increases the braking time. A safety cell is a rigid cage that prevents passengers from becoming trapped. Inside the car seat belts and airbags prevent the driver from hitting the windshield steering wheel and dashboard.

Crumple zones are typically found in the front and rear of a vehicle and are designed to crumple and crush under high-force impacts. The Crumple Zone transfers a portion of the vehicle's kinetic energy during impact to a controlled crash while maintaining the integrity of the occupant cell.

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Given:

The mass of the system is m' =m/2

The net force acting on it is F' = 2F

To find the acceleration.

Explanation:

The acceleration will be

Thus, the acceleration would be quadrupled(x4).

The rock reaches a maximum height in 2.4 seconds which implies the rock was thrown at a speed of 24m/s.

Let:

Using the First equation of motion:

                         v = u + at

                         0 = u + (-10)(2.4)

                         0 = u + (- 24)

                         u = 24m/s

The First equation of motion establishes a relation between velocities and time. With the provided information, the most suitable equation which can be used to derive the answer is the First equation of motion.

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The speed of the beam of light moving along the shoreline when it is 1 km from p 62.83 km/min revolution.

A revolution is the motion of 1 object around a center or some other object, a forceful overthrow of a government by using the people, or any sudden or grand trade. An example of revolution is the movement of the earth around the solar.

dθ/dt = 3 rev/min

         = 3×2π = 6π rad/min

tanθ = x/3

[tex]\frac{d}{dt}[/tex] tanθ = [tex]\frac{d}{dt}[/tex] (x/3)

sec²θ dθ/dt = 1/3 dx/dt

dx/dt = 3sec²θdθ/dt

At x = 1km; tanθ =x/3 =1/3

sec²θ = 1 + tan²θ = 1+(1/3)²

sec²θ =10/9

dx/dt = 3sec²θ dθ/dt

dx/dt = 3×10/9×6π

dx/dt = 62.83 km/min

Hence, the beam of light along the shoreline when it is 1 km away from point P is 62.83 km/min

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As a result of the law of conservation of momentum, the man will recoil as far as 0.034 m.

The law of conservation of momentum:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Where:

u₁ , u₂ = initial velocity of object 1 and object 2

v₁ , v₂ = final velocity of object 1 and object 2

Since both the player and the puck are initially at rest, hence  u₁ = 0, u₂ = 0.

Therefore,

m₁v₁ + m₂v₂ = 0

Parameters given:

m₁ = 80 kg

m₂ = 0.150 kg

v₂ = 47 m/s

Plug the parameters into the equation,

80 . v₁ + 0.15 . 47 = 0

v₁ = - 0.088 m/s

Time the puck reach 18 m goal:

t = distance / velocity = 18 / 47 = 0.38 s

The player will recoil:

distance = velocity x t = 0.088 x  0.38 = 0.034 m = 3.4 cm

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The work done on the force on the block is 23.516J

We are given that,

The mass of the block = m= 4.0 kg

The vertical component of the wall at an angle = sinθ = sin 30°

The horizontal component of the wall at an angle = cosθ = cos30°

The acceleration due to gravity = g = 9.81 m/s²

The coefficient of kinetic friction between the block and the wall= μ=0.40

So that to calculate the work done by the force on the block can be given by the expression, for vertical and horizontal component

Wf = Fycosθ

The Wf is the work done by the force Fy (on y-axis) on the block by the horizontal component,

Wf = Fxsinθ

The Wf is the work done by the force Fx (on x-axis) on the block by the vertical component,

Net Fy = sinθ N -mg =0

Net Fx = 0

Therefore, the work done by the force on the block can be assumed by above equations,

Wf = (mgdsinθ)/(sinθ -  μcosθ)

Wf = (4.0kg)(1.0m)(9.81m/s²)/sin30° -(0.40)cos30°

Wf = 33.981/1.445 J

Wf = 23.516J

Thus , the work done by the force on the block would be 23.516J

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Dan drove for 6 hours before catching up with Rob who left his home sometime later than Dan.

Dan left the white house and drove toward the recycling plant at an average speed of 40 km/h.  Let d1 be Dan's start in km.

Rob left some time later driving in the same direction at an average speed of 48 km/h. Let d2 be rob's start in km.

Let t1 be the time between dan and rob's leaving.

After Rob leaves, Dan travels around  40×5 =200km.

During the same time, rob travels a distance of

48×5=240km

d1= 240-200

   = 40 km

t1 = 40/40 = 1

So Dan traveled 1 more hour, which means he traveled for 6 hours.

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1.926kg is the maximum book mass you can hold this way and keep from slipping.

This book with 27 N, so Normal rection force N = 27N.  

let mass of brook =  m Kg

here gravitational force acting downwards which tend book to more downwards and frictional force moving  is acting vertically upwards to held

frictional force a must be equal to gravitational force here frictional force

fr = μN

so for body to be rest fr = mg

                                     μN =  mx 9.81

                                      m =     μN / 9.81

here maximum value of coefficient static friction   μ = 0.70

                                      m = 0.70x  27/9.81

                                     m = 1.926kg

Friction is the force that opposes motion when the surface of one object comes into contact with the surface of another. The mechanical advantage of the machine is reduced by friction,  in other words, the ratio of power to input decreases due to friction. A car uses a quarter of its energy to limit friction. However, the friction of the tires also allows the car to stay on the road, and the friction of the clutch allows it to drive. From matches to machines and molecular structures, friction is one of the most important phenomena in the physical world.

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Radially outward is both the direction and magnitude of the inertial force. as it is moving uniformly in a circle, from the bob's frame. Radially emanating from the source of the charge is an electric field that is positively charged.

Radially outward means  This is so because an electric field is produced when a positive charge is forced by the field. The electric field pulls the positive charge with a force that is directed away from the charge's origin. It is called  Radially outward.

In physics, magnitude is referred to as an object's maximal size and direction. Both vector and scalar values use magnitude as a common factor. We know that scalar quantities are those that have magnitude and nothing else by definition.

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As the mass of an object is increased, the acceleration of the object is decreased.

According to Newton's second law, an object's acceleration is determined by its mass and the net force that is acting on it. The body's acceleration is inversely related to its mass and directly proportional to the net force acting on it. This implies that as the force applied to an item increases, so does the object's acceleration. Similar to how an object's acceleration decreases as its mass increases, so do its mass.

As per Newton's second law of motion:

f = ma ------ (1)

f = (Δp) / t  ⇒ Rate of change of momentum

f = (mu - mv) / t = [m(u - v)] / t ----- (2)

From equation (1) and equation (2) we get:

[m(u-v)] / t = ma

a = (u - v) / t

The experimental acceleration value will be less than the theoretical acceleration value. because it is impossible to sustain a constant rate of velocity change for an extended period of time. The difference between practical and theoretical acceleration will therefore be smaller.

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The minimum distance in which car will stop is  256m.

What is distance?

distance is the length of the space between two points.

distance is a numerical or its  the occasionally qualitative measurement of how to far apart objects or points .

Sol-here we can apply Newton’s second law to the  car of to determine of the maximum static friction to the force acting on the car:

€Fy=ma^y+ n-mg=0

Fs≤us mg

This maximum magnitude of static friction acts so long as the tires roll without skidding.

€Fx=ma^x-----> -fs=ma

The maximum acceleration is

a=-u^s g

The initial and final conditions are- xi=0, vi=50.0mi/h =22.4 m/s and vf =0.Then,

v^2=v^2+2a(xf-xi)---->v^2

     f          i                                       I

Xf=(22.4m/s)^2/2(0.100)(9.80m/s^2)=256

Thus through the minimum distance in which car will stop is 256m.

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Answer:

there are the three basic

first law also called the law of inertia

the second one is the second law of motion and its equation is

F = ma

where m is the mass and a is the acceleration

its SI units are mass is kg and Acceleration is m/[tex]s^{2}[/tex]

the third law is called the action-reaction law

also the law of gravitation in which we survive our own earth-like plane due to the basic concept of the law of gravitation because the idea of gravitation is deal with this important law

F=GmMe/[tex]R^{2}[/tex]

The G value is 6.673*10^-11

m is the mass of an object

Me is the mass of the earth in our case we consider the object and the earth.

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The magnitude of the least acceleration the monkey must have if it is to lift the package off the ground: is 9.8 m/[tex]s^2[/tex]

From free body diagram,

The minimum acceleration of the monkey of mass (m) to lift the package off the ground is

[tex]m_{1}a_{min} = m_2g -m_1g\\a_{min} = \frac{m_2 - m_1}{m_1} g \\a_{min} = \frac{28 - 14}{14} 9.8 m/s^2 \\ \\a_{min} = 9.8 m/s^2 \\\\\\[/tex]

Mass is the amount of matter in a physical body. It  also measures the body's inertia, the resistance to acceleration when a net force is applied. The mass of an object also determines  its gravitational force on other objects. The basic SI  unit of mass is the kilogram. Mass is best understood as the amount of matter  in any object or body. Everything we see around us has mass. For example, a table, a chair, a bed, a football, a glass, and even air have mass.

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The phone can be 8.35cm small.

Frequency is the variety of occurrences of a repeating occasion in line with a unit of time. it is also from time to time referred to as temporal frequency to emphasize the assessment of spatial frequency, and regular frequency to emphasize the evaluation of angular frequency.

Frequency is an expression of ways regularly a periodic wave shape or signal repeats itself at a given amplitude. it is able to be expressed in hertz (Hz), kilohertz (kHz), megahertz (MHz), and so on.

Frequency is a vital parameter used in technological know-how and engineering to specify the temporal rate of trade discovered in oscillatory and periodic phenomena, such as mechanical vibrations, audio alerts (sound), radio waves, and mild.

GSM 900 band corresponds to a wavelength (\lambda) of

λ= c/f

where c is the speed of light and frequency is f which is 900 MHz

This gives \lambda=33.4cm

Antenna length   L=\lambda/4=8.35cm

So the phone should at least be 8.35cm long.

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The swan will travel 55.15 m during uniform motion before becoming airbone.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 0 m/s

vt = 5.8 m/s

a = 0.305 m/s²

By using the second equation, we can calculate the distance before becoming airbone

vt² = vo² + 2a . s

5.8² = 0² + 2 . 0.305 . s

0.61s = 33.64

s = 55.15 m

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If Alex throws a 0.25-kg rubber ball down onto the floor, the ball's speed just before impact is 4.5 m/s, and just after is 2.9 m/s.The change in the magnitude of the ball's momentum is 1.85 [tex]kg \frac{m}{s}[/tex]

Calculation

Change in momentum= [tex]mv_{1} -mv_{2}[/tex]

where, m is mass of the object, m= 0.25 kg

[tex]v_{1}[/tex] is velocity before collision, [tex]v_{1}[/tex] = 4.5 m/s

[tex]v_{2}[/tex] is velocity after collision, [tex]v_{2}[/tex] = 2.9 m/s

therefore, [tex]mv_{1} -mv_{2} =m(v_{1}-v_{2} )[/tex]

⇒0.25(4.5-(-2.9)) = 0.25(4.5 + 2.9) = 0.25* 2.4

= 1.85 [tex]kg\frac{m}{s}[/tex]

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Current is dwindling at 0.125 , where v is the voltage in volts, i is the current in amperes, and r is the resistance in ohms

Voltage = Current * Resistance ,

The Ohm's law is given by

V = IR eq. 1

Where V is the voltage across Resistance R and I is the current flowing through the Resistance R

Taking outgrowth of eq. 1 with respect to time t yields

dV/ dt = I * dR/ dt dI/ dt * R

dI/ dt * R = - I * dR/ dt dV/ dt

dI/ dt = (- I * dR/ dt dV/ dt)/ R eq. 2

Now substitute the given values into eq. 2

dI/ dt = (-0.02 *0.04(-0.02)) 300

dI/ dt = (-0.0008-0.02)/ 300

dI/ dt = -0.0208/ 300

Charge will go via the external circuit if the two conditions of an electrical circuit are satisfied. Flow of charge is appertained to as a current. In this case, the word" current" simply means that" charge is moving," indicating that commodity is taking place in the cables. The physical property of current, still, may be measured and quantified. The quantum of charge that moves past a point on a circuit at a given time is called current as a physical volume. The quantum of charge Q travelling through a line's cross section in a given quantum of time, as shown in the illustration below, can be measured to determine the current in a circuit.

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Based on this knowledge,he is  most justified in concluding that the   originates between the Sun and the asteroid belt.

Comets are frozen leftovers from the formation of the solar system composed of dust, rock, and ices. They variety from a few miles to tens of miles wide, however as they orbit in the direction of the sun, they warmth up and spew gases and dirt right into a sparkling head that can be large than a planet. This cloth bureaucracy a tail that stretches thousands and thousands of miles.

Asteroids lack the magnetic area and atmosphere that shield us on earth from harm. Living internal an asteroid is one way to defend your self from harmful radiation, it is expected that by tunneling 100 meters deep beneath an asteroid, people would be sufficiently shielded from radiation.

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