An example of a natural electric field is thunder or lightning

Answers

Answer 1

An example of natural electric field is Lightning

Answer 2

Answer:

Lightning

Explanation:

Lightning during a thunderstorm is an example of electrical energy. It is the visible discharge of atmospheric electricity. As lightning heats the air, it creates a shock wave that causes the sound of thunder.

hope this helps :)

Related Questions

Which nucleus completes the following equation?

Answers

Answer:

I think that CL IS THE ONLY BEST ANSWER

Explanation:

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE

If you have a mass of 0.9kg and a velocity 12 m/s what is your momentum?

Answers

Momentum
= mass x velocity
= 0.9 x 12
= 10.8 kgm/s.

The current in the wires of a circuit is 60.0 milliAmps. If the
voltage impressed across the ends of the circuit were tripled
(with no change in its resistance), then its new current would
be milliAmps.

Answers

Answer:

180 m amp

Explanation:

V = IR

v/r = i mutiply both sides by

3v / r = 3 i so the current will triple to 180 mAmp

what are the two most important traits between a whale and a shark?

Answers

Answer:

Both are aquatic animals and are hunters

Explanation:

A rock is suspended from the lower end of a light string. When the rock is totally immersed in water, the tension in the string is 1.20 N. When the rock is totally immersed in ethanol, the tension in the string is 1.60 N. Calculate the weight of the rock.

Answers

For a rock is suspended from the lower end of a light string, the weight of the rock is mathematically given as

W = 3.10 N

What is the weight of the rock.?

Generally, the equation for the W = Fh1+ is mathematically given as

W = Fh+T1

Where

PiVg+T1 = P2V9+T

(1000) V(9.8) + 1.2 = (790) V(9.8) + 1.6

V = 1.944* 10^-4 m3

In conclusion

W = Fh+T1

W = (1000) (1.944 * 10-4) (9.8) + 1.2

W = 3.10 N

Answers

Answer:

P = VI

Explanation:

the power is equal to the current × voltage

Answer:

P = V • I

Explanation:

Power = Voltage • Current

Assume that the body's muscle mechanism can be approximated by a spring with a uniform continuous mass distribution that follows Hooke's law. Concerning this,
A) find the effective mass of the spring with mass m.
Then, estimate the potential energy which can be mechanically stored in B) the muscles of each arm, and
C) the muscles of each leg,
and estimate the spring constant of
D) each arm muscles, and
E) each leg muscle.
F) Now, could estimate the speed of a runner by using these results?

Answers

Based on Hooke's law, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.

What is the spring constant?

The spring constant or stiffness constant of an elastic spring is constant which describes the extent a bit forceapplied to an elastic spring will extend it.

Spring constant, K = force/extension

Assuming, a body's muscle mechanism is a spring obeying Hooke's law, the effective mass of the spring with mass m is 1/3 of the mass of the spring = m/3

The potential energy that can be stored = ke^2 / 2

where K is spring constant and e is the extension produced.

Therefore, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.

Learn more about Hooke's law at: https://brainly.com/question/12253978

which is closely related to a whale? a shark, a toad, an alligator, a penguin or a bat?

Answers

Answer:

Any artidiodactyls such as hoofed animals. Deer, camels, cows, pigs, hippos are just some that are closely related to the whale.

yea what the person above said !!

A potter's wheel is spinning with an initial angular velocity of 11 rad/s . It rotates through an angle of 80.0 rad in the process of coming to rest.
What was the angular acceleration of the wheel?
How long does it take for it to come to rest?

Answers

The angular acceleration of the wheel approximately -0.76 rad/s² or proportionally as deceleration approximately 0.76 rad/s.It need approximately 14.474 s to come to rest.

Introduction

Hi ! I will help you to discuss about Proportionally Changes in Circular Motion. The analogy of proportionally changes in circular motion is same as the analogy of proportionally changes in direct motion. Here you will hear again the terms acceleration and change in speed, only expressed in the form of a certain angle coverage. Before that, in circular motion, it is necessary to know the following conditions:

1 rotation = 2π rad1 rps = 2π rad/s1 rpm = [tex] \sf{\frac{1}{60} \: rps}[/tex] = [tex] \sf{\frac{1}{30}\pi \: rad/s}[/tex]

Formula Used

The following equations apply to proportionally changes circular motion:

Relationship between Angular Acceleration and Change of Angular Velocity

[tex] \boxed{\sf{\bold{\omega_t = \omega_0 + \alpha \times t}}}[/tex]

With the following conditions:

[tex]\sf{\omega_t}[/tex] = final angular velocity (rad/s)[tex]\sf{\omega_0}[/tex] = initial angular velocity (rad/s)[tex]\sf{\alpha}[/tex] = angular acceleration (rad/s²)t = interval of the time (s)Relationship between Angular Acceleration and Change of [tex]\sf{\theta}[/tex] (Angle of Rotation)

[tex] \boxed{\sf{\bold{\theta = \omega_0 \times t + \frac{1}{2} \times \alpha \times t^2}}}[/tex]

[tex] \boxed{\sf{\bold{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta}}}[/tex]

With the following condition :

[tex]\sf{\theta}[/tex] = change of the sudut (rad)[tex]\sf{\alpha}[/tex] = angular acceleration (rad/s²)t = interval of the time (s)[tex]\sf{\omega_t}[/tex] = final angular velocity (rad/s)[tex]\sf{\omega_0}[/tex] = initial angular velocity (rad/s)

Problem Solving

We know that :

[tex]\sf{\omega_t}[/tex] = final angular velocity = 0 rad/s >> see in the sentence "in the process of coming to rest."[tex]\sf{\omega_0}[/tex] = initial angular velocity = 11 rad/s[tex]\sf{\theta}[/tex] = change of the sudut = 80.0 rad

What was asked :

[tex]\sf{\alpha}[/tex] = angular acceleration = ... rad/s²t = interval of the time = ... s

Step by step :

[tex]\sf{\alpha}[/tex] = ... rad/s²

[tex] \sf{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta} [/tex]

[tex] \sf{0^2= (11)^2 + 2 \times \alpha \times 80} [/tex]

[tex] \sf{0 = 121 + 160 \alpha} [/tex]

[tex] \sf{-160 \alpha = 121} [/tex]

[tex] \sf{\alpha = \frac{121}{-160}}[/tex]

[tex] \sf{\alpha = -0.75625 \: rad/s^2 \approx \boxed{-0.76 \: rad/s^2}}[/tex]

t = ... s

[tex] \sf{\alpha = \frac{\omega_0 - \omega_t}{t}}[/tex]

[tex] \sf{-0.76 = \frac{0 - 11}{t}}[/tex]

[tex] \sf{-0.76t = -11}[/tex]

[tex] \sf{t = \frac{- 11}{-0.76}}[/tex]

[tex] \boxed{\sf{t \approx 14.474 \: s}}[/tex]

Conclusion

So :

The angular acceleration of the wheel approximately -0.76 rad/s² or proportionally as deceleration approximately 0.76 rad/s.It need approximately 14.474 s to come to rest.

1 Choose the picture you think shows the gravity forces on the Earth and the Sun.
(a longer arrow to represents a big force, and a shorter arrow represent a smaller force)
b)
c)
a)
.
d)
e)
o

Answers

The force of gravity of the sun on Earth is a large force, and it can be represented by a longer arrow.

Force of gravity of sun on Earth

The force of gravity of the sun on Earth is determined using the following formula.

F = mg

where;

m is mass of the earth = 5.97 x 10²⁴ kgg is acceleration due to gravity of EARTH due to SUN = 9.8 m/s²

F = 5.97 x 10²⁴ x 9.8

F = 5.85 x 10²⁵ N

Thus, the force of gravity of the sun on Earth is a large force, and it can be represented by a longer arrow.

Learn more about force of gravity here: https://brainly.com/question/2537310

Residents of a community currently pay a fee for recreational services in their neighborhood, such as tennis courts, running trails, a pool. To assess whether there is support for raising a fee for the upcoming summer, a random sample of 50 residents is contracted and asked this question: “Would you support a $10 increase in the recreational fee to support programs for the health and well-being of the children in the community?” Of the 50 residents contacted, 42 approved of the fee increase. Which statement describes a likely source of bias present in survey results?

Answers

A likely source of bias in the survey is undercoverage bias because some parts of the community may not be represented in the survey results.

Bias present in the survey

The bias present in the survey may lead to error in the result obtained from the random sampling survey.

Source of bias in the survey

One of the likely source of bias in the survey is undercoverage.

It is not possible to ascertain the accurate opinion of the entire community from the 50 residents chosen for the survey.

Thus, a likely source of bias present in survey is undercoverage bias because some parts of the community may not be represented in the survey results.

Learn more about undercoverage bias here: https://brainly.com/question/21977459

Answer:

B. Question wording bias may be present because the question leads those responding toward a certain response.

Explanation:

D. Calculate the electric force (F.) between an electron and
proton that are 5.29 x 10-11 meters apart.

Answers

Answer:

See below

Explanation:

F = C q1 q2 /r^2

8.988 x 10^9 * (1.60217 x 10^-19)^2 / ( 5.29 x 10^-11)^2 =

.00000008244 N

82.4 nano N

In addition to their remarkable top speeds of almost 60 mph, cheetahs have impressive cornering abilities. In one study, the maximum centripetal acceleration of a cheetah was measured to be 18 m/s2. What minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?

Answers

coefficient of static friction is 1.7329

Explanation:

given data

velocity = 60 mph

acceleration = 17 m/s²

to find out

coefficient of static friction

solution

we will apply here centripetal force equation

that is

m×v²/r = µ × m × g ..................1

here v²/r is centripetal acceleration and m is mass and µ is coefficient static friction so

µ = a / g

µ = 17 / 9.81

µ = 1.7329

so coefficient of static friction is 1.7329

You perform an experiment to test how far a cannon will shoot a performer at
different angles. The data are shown below.
Angle
Distance (feet)
110
32°
36°
120
40°
128
440
133
48°
127
52
119
56°
109
60°
100
64°
91
68°
77
72°
63
At which angle will the performer travel the longest distance?

Answers

Answer:

44°

Explanation:

Look for the longest distance under the 'Distance ' column....look to the left to find the corresponding angle

Table clearly shows that the longest distance (133 ft) occurs at angle of 44°

I need help with this please

Answers

Answer:

i think its 100

Explanation:

A garage hoist lifts a truck up 2 m above the ground in 15seconds.Find the power delivered to the truck (given 1000kg as the mass of the truck and gas 9.81m/s

Answers

The power delivered to the truck of mass 1000 kg that was lifted by a garage hoist, 2 m high above the ground in 15 seconds is 1308 W.

What is power?

Power can be deifned as the rate at which work is done.

To calculate the power delivered to the truck, we use the formula below.

Formula:

P = mgh/t.............. Equation 1

Where:

P = Power delivered to the truckm = Mass of the truckh = Heightg = Acceleration due to gravityt = time

From the question,

Given:

m = 1000 kgh = 2 mt = 15 secondsg = 9.81 m/s²

Subsitute these values into equation 1

P = (1000×2×9.81)/15P = 19620/15P = 1308 W

Hence, The power delivered to the truck of mass 1000 kg that was lifted by a garage hoist, 2 m high above the ground in 15 seconds is 1308 W.

Learn more about power here: https://brainly.com/question/1634438

A total charge of Q coulomb is uniformly distributed along a rod 40cm in length.find find the electric field intensity 20cm away from the rod along its perpendicular bisector?

Answers

For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length, the electric field intensity 20cm away from the rod is mathematically given as

E1=1.598*10^11v/m

What is the electric field intensity 20cm away from the rod along its perpendicular bisector?

Generally, the equation for the initial electric field intensity is mathematically given as

[tex]dEp=\int{kd/r}cosd\theta[/tex]

Therefore

[tex]e1=kd/r{sin\theta2+sinR1}[/tex]

Hence

[tex]E1=(9*10^9/20*10^{-2})({sin45+sin45})*B/40*10^-2[/tex]

E1=B*9*10^{13})/(10*110)*[tex]\sqrt{2}[/tex]

E1=1.598*10^11v/m

In conclusion, the electric field intensity

E1=1.598*10^11v/m

Answers

Answer:

50 cubic cm

Explanation:

As the water displaces 50 cubic centimeters the amount of water that must leave the container for it to be able to be dropped into it is also 50 cubic as the water which was in its place must have gone somewhere.

List three methods of energy transport in nature and explain how the energy is being transferred in each of those methods. Which two are means by which energy is transported inside the Sun?

This question is for my college astronomy class!

Answers

First normal transportation is the light energy of sun is transmitted to our earth .

Next for transportation inside sun they are

Fusion and fission

Fusion means when two hydrogen atoms reacts to form helium nucleus .

Fission means when one nucleus is broken into two or more nucleus

Explanation:

#Make_the smartest_answer

#sorry_if_wrong

#I hope this helps

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#No copas

#Thank_you_for_watching

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For the statements based on whether they are described as outcomes of results from thermal energy being added or removed particles move faster particles move slower temperature increases temperature decreases kinetic energy increases kinetic energy decreases thermal energy added thermal energy removed

Answers

For thermal energy added: particles move faster, temperature increases, kinetic energy increases.
Thermal energy removed: particles move slower, temperature decreases, kinetic energy decreases

What is the cycle of a breaststroke?

Answers

Answer:

Breaststroke can be divided up into 4 distinct phases, which consists of the out sweep, in sweep, breathing phase, and lunge, extension, or recovery phase.

Explanation:

pa follow po

Radioactive isotopes can be used to find the age of rocks, fossils, or other artifacts. Carbon-14 has a half-life of 5,730 years. Suppose a sample of charcoal from a primitive fire pit contains one eighth of its original amount of carbon-14. How old is the sample?

Answers

Answer:

1/8 = (1/2)^3

This implies the sample has decayed for 3 half lives

3 * 5730 yrs = 17,200 years

A student is investigating acceleration using objects with different masses. She claims that
mass affects the acceleration of objects when the force remains constant. The student
creates a graph to represent the findings of her investigation.
acceleration
mass
Which argument best supports the student's claim?
O As mass decreases, the accleration of an object decreases because less force is required.
As mass increases, the acceleration of an object increases because less force is required.
O As mass increases, the acceleration of an object decreases because more force is required.
As mass decreases, the acceleration of an object increases because more force is required.

Answers

Answer:

As mass increases, the acceleration of an object decreases because more force is required.

Explanation:

The question states that the student made a mass acceleration graph with the force being constant, if you think about this in everyday life, would pushing a 30 kg box be easier than that of a 15 kg box? Obviously not because if you have the same force for both of them the 15 kg box would have a greater acceleration than the 30 kg one (assuming they are on the same surfaces and the same amount of force is applied.)

Therefore we can say that as the mass of an object increases the acceleration must decrease because we need more force to push the object.

A kitten sits in a lightweight basket near the edge

Answers

Answer:

So where's the problem now?

A kitten is just sitting

A ball is thrown directly upwards at 25 ms and the same time another ball is released from height of loom. At what height and time will the balls meets?

Answers

Answer:

Explanation:

When the balls meets, the time should be the same, let say t.

For the first ball (released from a loom):

[tex]\bar{h}=\frac{1}{2}gt^{2}[/tex] (Free fall motion) ([tex]\bar{h}[/tex] = the distance travelled by the first ball, measured from the loom)

So, we can find that [tex]\bar{h}=\frac{1}{2}(10t^{2})=5t^{2}[/tex]

For the second ball (which is thrown directly upwards):

[tex]y=v_{o}t-\frac{1}{2}gt^{2} = 25t-5t^{2}[/tex]

Because the height of the loom is h :

[tex]h=\bar{h}+y[/tex]

[tex]h=25t[/tex]

So, the time when two balls meets is : [tex]t=\frac{h}{5}[/tex] (In this question, the height of the loom h is not declared). When the height of the loom is known, you can calculate the time and the value of [tex]\bar{h}[/tex] or y

An unknown fluid flows at a speed of 31 m/s. Suppose the fluid has a mass of 47 kg runs at this speed. What is the fluid’s kinetic energy?

Answers

Answer:

22583.5J

Explanation:

KE=1/2 mv^2

=1/2*47Kg*(31m/s^2)

=23.5Kg * 961m/s^2

=22583.5J

Mrs. Martin is holding a ball from a height of 3.2 m that has the potential energy of 23 J, calculate the mass of the ball.

Answers

Answer:

0.73kg

Explanation:

Potential gravitational energy is equal to [tex]Pe=mgh[/tex], where Pe is potential gravitational energy, m is mass in kilograms, g is gravity in m/s^2 and h is height in meters.

Substitute:

[tex]Pe=mgh\\23=m*9.8*3.2\\23=31.36m\\0.73=m[/tex]

A parachute falling to the ground.

Answers

Answer:

a parachute falling to the ground is uniform

(13.04 HC)

The nose works with the brain and other body parts through a series of steps that help us smell odors. What step immediately follows the step of your nose taking in the smell of something burning in the kitchen?

The brain realizes that it is the smell of something burning.
The brain sends a message to the muscles in your legs to move.
The muscles pull on the bones in your legs and you move toward the kitchen.
The nose sends the information of the smell to the brain.

Answers

Answer:

The nose sends the information of the smell to the brain.

Explanation:

i think but I'm not really sure

The warning tag on a lawn mower states that it produces noise at a level of 91.0 dB. What is the intensity of this sound in watts per meter squared

Answers

For a lawnmower that produces noise at a level of 91.0 dB, the intensity of this sound is mathematically given as

I=1.26*10^-3W/m^2

What is the intensity of this sound in watts per meter squared?

Generally, the equation for the sound is mathematically given as

B=(10dB)log10(1/1_0)

Therefore

91/10=log(I/10^{-12})

I=1.26*10^-3W/m^2

In conclusion, the intensity

I=1.26*10^-3W/m^2