Adi drew a circle with a radius of 10 cm. What is the area of the circle? Use 3. 14 for pi

Answer:

[tex]\displaystyle \large{y=x^2-2x-3}[/tex]

Step-by-step explanation:

The given points are (-1,0) and (3,0) to find an equation of parabola. Notice that they say or the given points are x-intercepts, which means they make it easier for us to find an equation of parabola using these x-intercepts.

Quick Note:

So what we are going to do is to write the roots’ equation back as [tex]\displaystyle \large{x+\alpha =0}[/tex]

Our points or roots are given, therefore:

If x = -1 then x+1=0

If x = 3 then x-3=0

Then multiply x+1 with x-3 because if (x-1)(x+3)=0 then x-1=0 or x+3=0:

[tex]\displaystyle \large{(x+1)(x-3)=0}[/tex]

Convert 0 to y since we want to find a function:

[tex]\displaystyle \large{(x+1)(x-3)=y}\\\displaystyle \large{y=(x+1)(x-3)}[/tex]

Expand the expressions in and simplify to standard form:

[tex]\displaystyle \large{y=x^2-3x+x-3}\\\displaystyle \large{y=x^2-2x-3}[/tex]

Therefore, the equation is [tex]\displaystyle \large{y=x^2-2x-3}[/tex]

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Summary

If we are given the points [tex]\displaystyle \large{(\alpha ,0)}[/tex] and [tex]\displaystyle \large{(\beta ,0)}[/tex] with wideness of the graph or a-value = 1 then the parabola equation is:

[tex]\displaystyle \large{y=(x-\alpha )(x-\beta )}\\\displaystyle \large{y=x^2-\beta x-\alpha x+\alpha \beta }\\\displaystyle \large{y=x^2-(\beta +\alpha )x+\alpha \beta }[/tex]

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Others

If you have any doubts about my answer, explanation or this question, do not hesitate to let me know in the comment!

Let's see point E in its original position: (3.-4)

Now lets transform the point (x,y) -->  (x + 8, y +5)

               (3, -4) --> (3 + 8, -4 + 5) --> (11, 1)

Therefore coordinate E's new position is (11, 1)

Hope that helps!

Answer:

Lower Quartile is 8 according to the diagram.

Answer:

Step-by-step explanation:

57 of them were cinnamon.

Explanation:

100-40 = 60 and 3 of those were glazed so that leaves us with 57

Answer:

so the equation would look like this, x - 3 = 5

the number or x = 8

Step-by-step explanation:

8 - 3 = 5

Hope this helps! :)

Both lines would be the same length.

4x-6 = 50

Add 6 to both sides:

4x = 56

Divide both sides by 4:

x = 14

Answer:

11 + x

Step-by-step explanation:

x + 11 can be reversed as 11 + x and it would still mean the same thing.

11x means 11 * x so does not match

11 + x and x + 11 same this is correct answer tho

last two are also same  11 - x  and -x +11

Answer:

The last answer [tex]\sqrt{65}[/tex]

Step-by-step explanation:

[tex]7^2+4^2 = 65[/tex]

The formula to find it is [tex]a^2+b^2=c^2[/tex]

so [tex]\sqrt{65}[/tex] is correct

Answer:

⠀

Step-by-step explanation:

⠀

We'll solve this using the Pythagorean Theorem.

⠀

⠀

We know that,

[tex]{ \longrightarrow \pmb{\qquad \: (AB) {}^{2} = (AC) {}^{2} + ( BC) {}^{2}}}[/tex]

⠀

[tex]{ \longrightarrow \sf{\qquad \: (AB) {}^{2} = (7) {}^{2} + ( 4) {}^{2}}}[/tex]

⠀

[tex]{ \longrightarrow \sf{\qquad \: (AB) {}^{2} = 49 + 16}}[/tex]

⠀

[tex]{ \longrightarrow \sf{\qquad \: (AB) {}^{2} = 65}}[/tex]

⠀

[tex]{ \longrightarrow \sf {\pmb {\qquad \: AB}}} = \pmb{ \frak{\sqrt{65}}}[/tex]

⠀

Therefore,

Answer:

87.5 percent

Step-by-step explanation:

80 passed the first, 70 passed the second. 7/8 passed both. 7/8 as a percentage is 87.5.

Answer:

C. 87.5%

Step-by-step explanation:

[tex]P(A|B)[/tex]

this is what you are trying to find.

P(A | B) can be found by dividing the percentage who passed both, by the percentage who passed the first.

70/80 = 0.875

multiply by 100 to get percentage instead of decimal

87.5

Answer:

9

It is 9 because 9 is the only number that multiplied by itself is 81.

Answer:

x = 16

Step-by-step explanation:

Given:

Therefore, total marks = 15 × 6 = 90

To find the value of x, add up the individual marks:

12 + 16 + 14 + 13 + 19 + x = 74 + x

Now equate this to the total number of marks found previously:

74 + x = 90

Solve for x:

⇒ 74 + x - 74 = 90 - 74

⇒ x = 16

Therefore, the value of x is 16.

Answer:

its 323 so you were right :) if 323 is your answer lol

Step-by-step explanation:

abs(T-50)=323 Where T is in degrees Kelvin.

abs () means absolute value.

So T=323 plus or minus 50

The histogram is an illustration of a discrete probability, and the probability that this tomato plant has a height greater than 82.5 cm is 0.40

The histogram is given such that the distribution of the plant heights is:

75 < h ≤ 85

To estimate the probability that this tomato plant has a height greater than 82.5 cm, we make use of the following formula

P(h >82.5) = P(85)

From the histogram, we have:

P(85) = 24/60

Evaluate

P(85) = 0.40

Substitute P(85) = 0.4 in P(h >82.5) = P(85)

P(h >82.5) = 0.40

Hence, the estimated probability is 0.40

Read more about probability at:

https://brainly.com/question/251701

Answer:

C≈25.13ft

Step-by-step explanation:

C=2πr=2·π·4≈25.13274ft

Answer:

Frida

Step-by-step explanation:

y = 1000(2)^x

Mrs. Smith is saying that the number of termites will double each week, and Mr. Smith is saying that the number of termites will increase by 100% each week.

Let's just look at (2)^x. If we substitute numbers for x, we get:

We can see that the output number doubles by 2, or in other words, increases by 100% of its value.

Therefore, Frida is correct in thinking that both Mr. and Mrs. Smith's interpretations are correct.

Answer:

Step-by-step explanation:

Answer:

a. 0

Step-by-step explanation:

Which values from the set {0, 12, 2.5, 4} make the inequality 8g < 4 true?

Our inequality:

8g < 4

Substitute each values from the set {0, 12, 2.5, 4} for g, to find which value makes the inequality true.

For 0:

8g < 4

8(0) < 4

0 < 4

This statemen is true, because 0 is less than 4

For 12:

8g < 4

8(12) < 4

96 < 4

This statemen is false, because 96 is NOT less than 4

For 2.5:

8g < 4

8(2.5) < 4

20 < 4

This statemen is false, because 20 is NOT less than 4

For 4:

8g < 4

8(4) < 4

32 < 4

This statemen is false, because 32 is NOT less than 4

Hope this helps!

Answer:

300-400

Step-by-step explanation:

The first step is finding the total of the data we have. So, we take 5 + 10 + 15 + 20 + 25 + 15 + 10 which equals 80.

The median is the middle point of all the data. If it's an odd number, you can calculate the median with the equation (n+1) / 2, plugging in the total amount of data for n.

When it's an even number though, there is no one middle point since the data splits evenly in 2, so we have to use 2 equations: n/2 & (n/2) + 1. Then, we find the average of those two data points. (Although, you don't have to do that for this particular question).

When we plug 80 in for n in both of these equations, we get 40 and 41.

To where this is in the question, we have to count up from the bottom of the chart. 1-5 is below 100, 6-15 is 100-200, 16-30 is 200-300, and 31-50 is 300-400.

Since 40 and 41 are between 31 and 50, the answer is 300-400.

Hope this helps! :)

Answer:

Step-by-step explanation:

This is a quadrilateral. A quadrilateral is a plane figure that has four sides or edges, and also has four corners or vertices.

The interior angles of a simple quadrilateral ABCD add up to 360 degrees of arc.

Answer:

Angle x = 40°

Step-by-step explanation:

All angles of any quadrilateral sum up to 360°.

So here, already measure of 3 angles are given.

So if we add up all angles + Angle x then it sums up to 360°.

So, the following steps will lead you to the answer:

73° + 157° + 90° + Angle x = 360°

(Now add up the measure of the three given angles)

320° + Angle x = 360°

(Now, through transposition moves 320° to the RHS) (Remember when transposing the signs change)

Angle x = 360° - 320°

Finally,

Angle x = 40°

Hope it helps!!!

C = pi x d

3,14 x d = 47,1

d = 15

Answer:

why you delete my answer before question

teddy bears = 80

hope it helps..!!!

Answer:

w = 60

Step-by-step explanation:

the midsegment SU is half the measure of side RV , then

SU = [tex]\frac{1}{2}[/tex] RV , so

w - 30 = [tex]\frac{1}{2}[/tex] w ( multiply through by 2 to clear the fraction )

2w - 60 = w ( subtract w from both sides )

w - 60 = 0 ( add 60 to both sides )

w = 60

Answer:

the answer is y = 2x + 7

Step-by-step explanation:

for it to be parallel has to have the slope

Answer:

your answer would be zero

Step-by-step explanation:

Parllel lines never crosses or intercept, which means they have 0 solutions

Answer:

24π inches

Step-by-step explanation:

The area of a circle is denoted by: , where r is the radius. Here, we know that the area is A = , so we can plug this in to find r:

A = [tex]\pi r^{2}[/tex]

[tex]144\pi = \pi r^{2}[/tex]

[tex]r^{2}[/tex] = 144

r = 12

The circumference is denoted by: , where r is the radius. We've found the radius so just plug 12 in for r:

Thus, the circumference is 24π inches.

Hope this helps!

Correct Question :

The area of a circle is 144π in². What is the circumference, in inches? Express your answer in terms of pi.

[tex] \: [/tex]

Step-by-step explanation:

Before finding the circumference of the circle, we have to find the radius of it.

We already know that,

[tex] \longrightarrow \qquad{ \underline {\boxed{ \pmb{ \mathfrak{ \pi r{}^{2} = \: \: Area_{(circle)}}}}}} \: \: \bigstar \\ \\ [/tex]

So, using this formula we'll find the radius and now we'll substitute the given values :

[tex] \longrightarrow \qquad{ \sf{ \pi \times r{}^{2} = \: 144 \pi }} \\ \\[/tex]

Cancelling π from both sides we get :

[tex]\longrightarrow \qquad{ \sf{ \cancel\pi \times r{}^{2} = \: 144 \cancel\pi }} \\ \\[/tex]

[tex]\longrightarrow \qquad{ \sf{ r{}^{2} = \: 144 }} \\ \\ [/tex]

[tex]\longrightarrow \qquad{ \sf{ r{}^{} = \: \sqrt{144} }} \\ \\ [/tex]

[tex]\longrightarrow \qquad{ \sf{ \pmb{ r{}^{} = \: 12 }}} \\ \\ [/tex]

So,

[tex] \\ [/tex]

Now we'll find the circumference of the circle :

[tex] \\{ \longrightarrow \qquad{ \underline {\boxed{ \pmb{ \mathfrak{ \: \: Circumference_{(circle)} = 2 \pi r}}}}}} \: \: \bigstar \\ \\ [/tex]

Now, we'll substitute the required values in the formula :

[tex] \\ { \longrightarrow \qquad{ \sf{ \: \: Circumference_{(circle)} = 2 \times \pi \times 12}}} \: \: \\ \\ [/tex]

[tex]{ \longrightarrow \qquad{ \sf{ \: \: Circumference_{(circle)} = 2 \times 12 \pi }}} \: \: \\ \\ [/tex]

[tex]{ \longrightarrow \qquad{ \sf{ \pmb{ \: \: Circumference_{(circle)} = 24 \pi }}}} \: \: \\ \\ [/tex]

Therefore,