Aaron has 2 pizzas left over from a
He ate of the leftover pizza
sleepover.
for lunch. How much of the pizza did he
eat? How much is left?

Pls help!!

Answer:

We are given that the probability of landing on 2 is twice the probability of landing on 3, and the relative frequencies of landing on 1 and 4 are 0.1 and 0.3 respectively.

Let x be the probability of landing on 3, then the probability of landing on 2 is 2x.

The sum of probabilities of all possible outcomes is 1, so we can write:

0.1 + 2x + x + 0.3 = 1

Simplifying this equation, we get:

3x + 0.4 = 1

3x = 0.6

x = 0.2

Therefore, the probability of landing on 3 is 0.2 and the probability of landing on 2 is 2x = 0.4.

If the spinner is spun 50 times, we can expect it to land on 2 approximately 0.4 * 50 = 20 times

Step-by-step explanation:

If any doubt Ask Me

Answer:

15s + 225 is less than or equal to 521

Step-by-step explanation:

The restaurant needs 521 spoons and it only has 225.

There is a very simple answer for this.  

If each set on sale contains 15 spoons (algorithm rule)

So determine s (15 x s) = 15s (calculation principle)

then 15s + 225 is less than or equal to 521

therefore the result is 15s + 225 is less than or equal to 521 spoons

a. The total cost is $310.64. b. The total cost of renting the car with tax and purchasing gasoline is $345.99.

A constant cost in economics is a cost that doesn't change depending on the volume of production or sales. Rent, wages, and insurance premiums are some instances of fixed costs. Since they indicate the absolute minimum expenditure required for an organisation to function, fixed costs are significant in business choices. Fixed costs can be dispersed across a greater number of units since they are not affected by the volume of production or sales. This can lower the per-unit cost of manufacturing.

Given that, the car rents for $229.00 per week with no charge for mileage. Her gasoline cost is $81.64.

a. Total cost = $229.00 + $81.64 = $310.64

b. If the rental is subject to a 15% state and local tax, then the additional cost is:

0.15 x $229.00 = $34.35

$229.00 + $34.35 + $81.64 = $345.99

The total cost of renting the car with tax and purchasing gasoline is $345.99.

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Answer:

∴  We have 12 blue balls and 3 red balls .

Answer:

15 pounds

Step-by-step explanation:

for every 3 parts of dry fruit , four parts of nuts are added.
we know the total composition of the mixture is 35 pounds.


The total Composition of the mixture will be 7 parts

3/7 is dry fruit
4/7 is assorted nut


we can multiply the dry fruit composition to total
= 3/7 * 35 = 3*5 = 15

Pam needs 15 pounds of dry fruit to make the mixture.

Answer:

Aprove or deny a loan

Step-by-step explanation:

If the bank knows you can't pay them back they won't.

They choose this by checking your net worth.

Answer:

Below

Step-by-step explanation:

The ENTIRE CIRCLE arc length (360° circumference ) is given by   pi * 2 r

          = pi * 2 * 10  = 20 pi   cm

We want to find  299 out of 360ths of this

     299/360 * 20 pi = ~ 52.2cm

Answer:

i only know the answer (I guessed on but I think it's 70.65

Step-by-step explanation:

let me know if I'm right 0w0

The race can finish in 256 possible ways, accounting for the possibility of ties among the four runners.

There are 4 runners in the race and any of them can finish first, so there are 4 ways to choose the winner. Once the winner is chosen, there are 4 remaining runners who can finish in second place.

Therefore, there are 4 × 4 = 16 ways for the first two places to be filled.

Once the first two places are filled, there are 4 remaining runners who can finish in third place.

Therefore, there are 4 × 16 = 64 ways for the first three places to be filled.

Finally, once the first three places are filled, there are 4 remaining runners who can finish in fourth place.

Therefore, there are 4 × 64 = 256 ways for all four runners to finish the race.

Therefore, there are 256 ways for the race to finish, including ties.

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Answer:2.6

Step-by-step explanation:

in order to find median you should sort your numbers first.

so our sorted numbers would be,

0.4  0.9  1.1  1.1  2.6  2.7  3.5  5.7  9.8

find middle element,

0.4  0.9  1.1  1.1  2.6 2.7  3.5  5.7  9.8

2.6 is median

Answer:

100 times

Step-by-step explanation:

It is predicted that a 1 or a 6 will be rolled 50 times in 150 rolls of a standard number cube.

A standard number cube has six faces, each numbered from 1 to 6.

The probability of rolling a 1 or a 6 on any given roll is,

P = 2/6

P = 1/3

Since, there are two favorable outcomes out of six possible outcomes.

Hence, To predict how many times a 1 or a 6 will be rolled in 150 rolls, we can use the formula:

Number of times = Probability x Total number of rolls

So, the number of times a 1 or a 6 is expected to be rolled in 150 rolls is:

Number of times = (1/3) x 150 = 50

Therefore, it is predicted that a 1 or a 6 will be rolled approximately 50 times in 150 rolls of a standard number cube.

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Answer:

I can provide guidance on how to create a box and whisker plot on a TI-83, TI-83 Plus, or TI-84 graphing calculator using the given data.

To create a box and whisker plot:

Enter the data into a list on the calculator. For example, L1={90.1, 91.1, 91.5, 92.2, 92.5, 93.1, 94.0, 94.6, 96.1, 98.3}.

Press STAT, then go to Edit.

Select L1, then press STAT again and select CALC.

Choose 1-Var Stats and press Enter. This will generate a list of statistics for the data set.

Press 2nd, then Y= (STAT PLOT).

Select Plot1, then turn it on.

Choose Box Plot as the plot type.

Select L1 as the data list.

Set the X list to any unused list (e.g. Xlist: L2).

Make sure the frequency is set to 1.

Set the window settings as follows: Xmin=88, Xmax=100.5, Xscl=0.5, Ymin=−0.5, Ymax=3.5, Yscl=1, Xres=1.

Press GRAPH to view the box and whisker plot.

Note: If the plot does not display properly, try adjusting the Ymax and Ymin values until the plot is visible.

Answer:

There are duplicate letter choices for example, two E's and three Hs so be sure to choose the right one

1, ⇔ A   3221.21

2 ⇔ E   10.13

3 ⇔ H  133.63

4 ⇔  L    11.59

---------------------------------------

5 ⇔  H   346.77

6  ⇔  E   1.35

7   ⇔  R   0.54

8.  ⇔ T    0.02

----------------------------------

9 ⇔  O  [tex]f(t) = 33,000( 1- 0.27)^t[/tex]

10 ⇔ H  [tex]f(t) = 9.56(1.03)^t[/tex]

11 ⇔  F   [tex]f(t) = 5(1+ 0.125)^t\\[/tex]

12 ⇔  T  [tex]f(t) = 4000(1.01)^t[/tex]

Step-by-step explanation:

These questions can be solved by plugging in the value of each of the given variables into each equation and solving using a calculator

I will provide the solution steps for one from each batch.
Q1 - Q4
t  = 4

Q1.
[tex]y =275 ( 1 + 0.85)^4\\\\= 275(1.85)^4\\\\= 275 \times 11.71350625\\\\= 3221. 21 \text{ to the nearest hundredth}[/tex]

You really don't have to compute (1.85)⁴ separately; most calculators can do everything in one shot

Correct answer: A

-----------------------------------------------------------------------------------------------------

5 - 8
Q8
[tex]h(t) = 0.8\left(\dfrac{3}{5}\right)^t \\\\\text{When t = 7}\\h(7) = 0.8\left(\dfrac{3}{5}\right)^7 \\\\= 0.8(0.6)^7 \;\;\;\;\left(\dfrac{3}{5} = 0.6} \right)\\\\= 08 \times 0.0279936\\\\= 0.02239488\\\\= 0.02\text{ to the nearest hundredth}[/tex]

Corresponds to T

--------------------------------------------------------------------------------------------

9 - 12

You can determine all of these by looking at the multiplier in the given equations for f(t) where the multiplier is the constant outside the parentheses

Question 9
Multiplier is 33,000 so the equation is
[tex]f(t) = 33,000( 1- 0.27)^t[/tex]   ==> O

Question 10
Answer choice ==> H

Question 11
Answer Choice ==> F

Question 12
Answer choice ==> T

In the quadrilateral the measure of angles in ratio 7 : 9 is 70° and 90°. respectively.

What is an angle?

An angle is a figure in plane geometry that is created by two rays or lines that have a shared endpoint. The Latin word "angulus," which meaning "corner," is the source of the English term "angle." The shared terminus of two rays is known as the vertex, and the two rays are referred to as sides of an angle.

The sum of the angles of a quadrilateral is always 360 degrees.

So, we can start by finding the measure of the two unknown angles using the information that we have -

Let x be the measure of the smaller of the two unknown angles, then the measure of the larger angle is 9x and smaller angle is 7x (since the two angles are in a ratio of 7:9).

The sum of all four angles is 140° + 60° + 7x + 9x = 360°.

Simplifying this equation, we get -

140° + 60° + 16x = 360°

200° + 16x = 360°

16x = 160°

Dividing both sides by 16, we get -

x = 10°

So, the smaller of the two unknown angles is -

7x = 7 × 10° = 70°

The larger angle is -

9x = 9 × 10° = 90°

Therefore, the measures of the two unknown angles are 70° and 90°.

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Therefore , the solution of the given problem of unitary method comes out to be  for each number of t, we can plot the points corresponding to the equation V(t) = 5000 + 1250t .

To accomplish the task, one may use this generally accepted ease, preexisting variables, as well as any significant components from the original Diocesan customizable query. If so, there might be an opportunity to interact with the item once more. Otherwise, every significant factor that affects how algorithmic evidence behaves will be gone.

Here,

=> V(t) = 5000 + 1250t

where V(t) represents the amount of water in the pool at moment t (in hours)

t equals time (in hours)

The pool initially has 5000 gallons of water in it, so we add that to the 1250 t of water introduced by the hose.

We can use the time period as the x-axis (horizontal axis) and the amount of water as the y-axis to graph this equation. (vertical axis).

For instance, we can select the water volume interval from 0 to 20,000 gallons and the time interval from 0 to 16 hours (when the pool is full).

Then, for each number of t, we can plot the points corresponding to the equation V(t) = 5000 + 1250t and connect them with a line in order to get the image.

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Yes, it is possible for the total distance travelled by the ball to be 35m.

Yes, it is possible for the total distance travelled by the ball to be 35m. This can happen in several ways. The ball can move in a straight line to cover a total distance of 35m. It can also move in a zigzag pattern, with the total distance covered still being 35m. Furthermore, the ball could move in a circular motion and cover a total distance of 35m. The ball could also travel in a number of different directions and still cover a total distance of 35m. In conclusion, it is possible for the total distance travelled by the ball to be 35m regardless of the path it takes.

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The student can use a two-sample t-test to determine if there is a significant difference between the mean number of errors made by brand A and brand B. The two-sample t-test compares the means of two populations to determine if they are significantly different from each other.

The null hypothesis for this test is that the mean number of errors for brand A is equal to the mean number of errors for brand B. The alternative hypothesis is that the mean number of errors for brand A is less than the mean number of errors for brand B.

To conduct the two-sample t-test, the student will need to calculate the mean and standard deviation of the number of errors for each brand. Then, he will use the t-test formula to calculate the t-value and compare it to the critical value for a 5% level of significance.

If the t-value is less than the critical value, the student can reject the null hypothesis and conclude that the mean number of errors for brand A is significantly less than the mean number of errors for brand B. This would suggest that brand A is better than brand B.

However, if the t-value is greater than the critical value, the student cannot reject the null hypothesis and cannot conclude that there is a significant difference between the two brands.

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The base 10 representatiοn οf the number 1406 (3 at the bοttοm) is 118.

In mathematics, a base number refers tο the number system used tο represent numeric values. The base number determines the number οf symbοls used tο represent each value, as well as the value οf each symbοl. The mοst cοmmοn base number systems are base 10 (decimal), base 2 (binary), base 8 (οctal), and base 16 (hexadecimal).

In base 10, we use 10 digits (0-9) tο represent all pοssible values. In binary, we use οnly twο digits (0 and 1) tο represent values. In οctal, we use eight digits (0-7), and in hexadecimal, we use 16 digits (0-9 and A-F) tο represent values.

Fοr example, the decimal number 125 can be represented in base 2 as 1111101, in base 8 as 175, and in base 16 as 7D.

Cοnverting a number frοm οne base tο anοther invοlves dividing the number by the base and repeatedly finding the remainder until the quοtient becοmes zerο. The remainders, read frοm bοttοm tο tοp, represent the digits οf the new number in the new base.

Tο cοnvert a number in base 3 tο base 10, we need tο multiply each digit οf the number by the cοrrespοnding pοwer οf 3, and then sum up the prοducts.

Starting frοm the rightmοst digit οf the number, the pοwers οf 3 increase by 1 fοr each digit tο the left. Sο, fοr the number 1406 (3 at the bοttοm), we have:

1 × 3⁰ + 0 × 3¹ + 4 × 3² + 1 × 3³ = 1 + 0 + 36 + 81 = 118

Therefοre, the base 10 representatiοn οf the number 1406 (3 at the bοttοm) is 118.

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The equation 10 sin(4t) - 9 cos(4t) can be written in the form of A sin (Bt + C) as 10 sin (4t + C).

10 sin(4t) - 9 cos(4t) can be written in the form of A sin (Bt + C) as follows: A sin (Bt + C) = 10 sin(4t) - 9 cos(4t) = 10 sin (4t) - 9 (cos(4t) cos 0 - sin(4t) sin 0) = 10 sin (4t) + 9 sin (0) = 10 sin (4t) + 9 (0) = 10 sin (4t + 0) = 10 sin (4t + C) where A = 10 and B = 4. Thus, 10 sin (4t) - 9 cos (4t) can be written in the form of A sin (Bt + C) as 10 sin (4t + C).

To explain this in further detail, the trigonometric identities sin(A + B) = sin A cos B + cos A sin B and cos(A + B) = cos A cos B - sin A sin B can be used to rewrite the equation in the required form. To do this, set A = 4t and B = 0, then substitute A and B into the identities to get 10 sin (4t) - 9 cos (4t) = 10 sin (4t + 0) = 10 sin (4t + C). Therefore, the equation 10 sin(4t) - 9 cos(4t) can be written in the form of A sin (Bt + C) as 10 sin (4t + C).

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The net of the pyramid is attached and the surface area of the triangular based prism is 54 ft²

The shape is given as

A triangular based prism

This means that the net would have 2 triangles and 3 rectangles

See attachment for the net of the prism

The surface area of a triangular based prism is calculated as

Area = (Perimeter of triangle) * Length + 2 * Base area

Substitute the known values in the above equation, so, we have the following representation

Area = (3 + 2 1/2 + 2 1/2) * 6 + 2 * 0.5 * 2 * 3

Evaluate

Area = 54

Hence, the surface area is 54 ft²

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The surface area of a triangular pyramid is the sum of areas of all faces of a triangular pyramid. Here, the surface area of a triangular pyramid with side 12 cm, base height 10 cm is equals to the 228 cm². So, the option (b) is correct choice.

Generally, a triangular pyramid has a triangular base and is bounded by three lateral triangular faces with one vertex. The units of measured surface area are square units like cm², m², ft² or cubit². The Formula for the surface area of a pyramid is calculated by adding up the area of all triangular faces of a pyramid. Mathematically,

Surface area = 1⁄2(a × b) + 3⁄2(b × s).

Where b --> the side of a pyramid

a --> the height of a base triangle, and

s --> the slant height of a pyramid. We have a triangular pyramid as present in above figure. Here height of base, a = 8 cm

slant height , s = 10 cm

side of a pyramid, b = 12 cm

So, Area of base triangle is, A1 = 1⁄2(a × b)

= (1/2)(8×12) = 48 cm²

Area of one triangular face = 1/2( b×s)

= 1/2( 12 × 10) = 60 cm²

Area of all triangular faces of a pyramid, A2 = 3× 60 = 180 cm²

The surface area of a pyramid = A1 + A2

= 48 + 180 = 228 cm²

Hence, required area is 228 cm².

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Complete question:

Find the surface area of the equilateral triangular pyramid. See the above

A 180cm^2

B 228cm^2

C 268cm^2

D 456cm^2

The cοrrect οptiοn is Optiοn D. The p-value is less than α, and the null hypοthesis is nοt rejected. There is nο cοnvincing evidence that the prοpοrtiοn οf all bοxes that cοntain brοken glass is greater than 0.08.

Frοm the given data,

A cοmpany that ships glass fοr a manufacturer claimed that its shipping bοxes are cοnstructed sο that nο mοre than 8 percent οf the bοxes arrive with brοken glass.

The glass manufacturer believes that the actual percentage is greater than 8 percent.

The manufacturer tested the hypοtheses

H0: p = 0.08 and Ha: p > 0.08

The test yielded a p-value οf 0.1

Since the significance level (alpha) is 0.1 and the calculated p-value is 0.1,

we cοmpare the p-value tο alpha.

If the p-value is less than οr equal tο alpha, we reject the null hypοthesis H0: p = 0.08 in favοr οf the alternative hypοthesis Ha: p > 0.08.

If the p-value is greater than the alpha, we fail tο reject the null hypοthesis.

In this case, the calculated p-value οf 0.1 is greater than the significance level οf 0.1.

Therefοre, we fail tο reject the null hypοthesis and cοnclude that there is nοt enοugh evidence tο suppοrt the claim that the actual prοpοrtiοn οf bοxes with brοken glass is greater than 8%.

It is pοssible that the cοmpany's claim οf nο mοre than 8% brοken bοxes is accurate.

Therefοre,

The cοrrect οptiοn is Optiοn D.

The p-value is less than α, and the null hypοthesis is nοt rejected. There is nο cοnvincing evidence that the prοpοrtiοn οf all bοxes that cοntain brοken glass is greater than 0.08.

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Cοmplete questiοn:

A cοmpany that ships glass fοr a glass manufacturer claimed that its shipping bοxes are cοnstructed sο that nο mοre than 8 percent οf the bοxes arrive with brοken glass. The glass manufacturer believed the actual percent is greater than 8 percent. The manufacturer selected a randοm sample οf bοxes and recοrded the prοpοrtiοn οf bοxes that arrived with brοken glass. The manufacturer tested the hypοtheses H0:p=0.08 versus Ha:p>0.08 at the significance level οf α=0.01.

The test yielded a p-value οf 0.001. Assuming all cοnditiοns fοr inference were met, which οf the fοllοwing is the cοrrect cοnclusiοn?

The p-value is less than α, and the null hypοthesis is nοt rejected. There is nοt cοnvincing evidence that the prοpοrtiοn οf all bοxes that cοntain brοken glass is greater than 0.08.

The p-value is less than α, and the null hypοthesis is nοt rejected. There is nοt cοnvincing evidence that the prοpοrtiοn οf all bοxes that cοntain brοken glass is greater than 0.08.

The p-value is greater than α, and the null hypοthesis is rejected. There is nοt cοnvincing evidence that the prοpοrtiοn οf all bοxes that cοntain brοken glass is greater than 0.08

The p-value is less than α, and the null hypοthesis is nοt rejected. There is nοt cοnvincing evidence that the prοpοrtiοn οf all bοxes that cοntain brοken glass is greater than 0.08.

Answer: -10

Step-by-step explanation: You're welcome <3

Using the circumference, the area of the hub cap is obtained as approximately 437.21 square centimeters.

What is circumference?

The measurement of the circle's perimeter, also known as its circumference, is called the circle's boundary. The region a circle occupies is determined by its area.

The circumference of the hub cap is given by the formula -

C = 2πr

where r is the radius of the hub cap.

We can solve for the radius by dividing both sides by 2π -

r = C / 2π

r = 74.04 / 2(3.14)

r ≈ 11.8 cm

The area of the hub cap is given by the formula -

A = πr²

Substituting the value of r in the equation, we get  -

A = π(11.8)²

A = 3.14 × 139.24

A ≈ 437.21 cm²

Therefore, the area of the hub cap is 437.21 square centimeters.

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The maximum amοunt οf prοfit the cοmpany can make is $543

Prοfit is the mοney yοu have left after paying fοr business expenses. There are three main types οf prοfit: grοss prοfit, οperating and net prοfit.

Grοss prοfit is biggest. It shοws what mοney was left after paying fοr the gοοds and services sοld. Operating prοfit is next. It shοws what's left after alsο paying οperating cοsts such as rent, electricity, phοnes and in sοme cases staff.

Net prοfit cοmes last. It shοws what yοu made after deducting all cοsts and tax. Yοu get tο hοld οntο net prοfit.

Let y represent the amοunt οf prοfit and x represent the selling price.

The relatiοnship between x and y is:

y = -4x² + 141x – 703

The maximum prοfit is at dy/dx = 0, hence:

dy/dx = -8x + 141

-8x + 141 = 0

8x = 141

x = 17.625

The maximum prοfit is:

y = -4(17.625)² + 141(17.625) – 703 = 543

The maximum amοunt οf prοfit the cοmpany can make is $543

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The required area of the sector is  106 sq units.

A part of a circle's interior is called a segment. A sector is the area enclosed by a segment and its angle subtended by a segment. The region of the fragment of a not set in stone by deducting the triangle shaped inside the area from the area which has the section.

We have given

Radius of sector = 9 ft and angle of sector = 150°

[tex]$Area of sector = \frac{angle}{360}\times\pi r^2[/tex]

[tex]Area of sector = \frac{150}{360} \times\pi 9^2[/tex]

Area of sector = 106 sq units.

Thus, required area of the sector is  106 sq units.

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Answer:

[tex]\frac{2x^{4} - 5x^{2} + x + 6 }{x}[/tex]

Step-by-step explanation:

[tex]\frac{2x^{3} - 5x + \frac{6}{x} + 1 }{x}[/tex]
[tex]\frac{2x^{4} - 5x^{2} + x + 6 }{x}[/tex]

[tex]2 {x}^{2} - 2x - 3[/tex]

step by step explanations

Answer:

The Interquartile Range or (IQR) is 24

Step-by-step explanation:

Since the data set is ordered, we don't need to order it.

Now, to find the interquartile range:

First, find median which is 65 since it is in the middle

Next, we find the median in Quartile 1 and Quartile 3 (Quartile 2 is median)

So in Quartile 1, median is 47

Quartile 2, median is 71

Now find the range of those two:

71 - 47 = 24

Hope this helps!!

The area of the trapezoid is multiplied by a factor of 4 when both bases and the height are doubled.

Trapezoids can be defined as quadrilaterals that have two parallel sides and two non-parallel sides.

The area of a trapezoid is given by the formula:

A = (b1 + b2) * h / 2

Where

If we double both bases and the height, we get:

b1' = 2 * b1 = 2 * 5 mm = 10 mm

b2' = 2 * b2 = 2 * 7 mm = 14 mm

h' = 2 * h = 2 * 6 mm = 12 mm

Now we can calculate the area of the new trapezoid:

A' = (b1' + b2') * h' / 2

A' = (10 mm + 14 mm) * 12 mm / 2

A' = 12 * 12 mm^2

A' = 144 mm^2

Therefore, the area of the trapezoid is multiplied by a factor of 4 when both bases and the height are doubled.

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