Answer:
8 large frames and 13 small frames
Step-by-step explanation:
Given:
$18 each = large frames
$8 each = small frames
To Find:
⇒ Bought 21 frames for $248, find how many of each type she bought
Solve:
1 Large frame costs = 18 $
Therefore, x large frames costs = 18x $
{where x is the number of large frames she bought}
1 Small frame costs = 8 $
Therefore, x Small frames costs = 8y $
{where y is the number of small frames she bought}
By the given condition :
18x + 8y = 248 {equation 1}
x + y = 21 {equation 2}
Solve these equations simultaneously, from second equation we get :
x = 21- y
18⋅(21−y)+8y= 248
378 - 18y+8y = 248
-10y = -130
y = 13
Put y = 13 in eq x = 21- y
x = 21 - y
x = 21 - 13
x = 8
So the woman bought 8 large frames and 13 small frames.
~lenvy~
Find the value of y for the given value of x.
y=2−9x;x=2/3
Answer:
-4
Step-by-step explanation:
y=2-9×(2/3)=2-6= -4
What is the area, in square meters, of the shaded part of the rectangle shown below?
how is 12 x √3/2 = 6√3 ?
[tex]12x\sqrt{\cfrac{3}{2}}~~ = ~~6\sqrt{3}\implies (6)(2)x\cdot \cfrac{\sqrt{3}}{\sqrt{2}}~~ = ~~6\sqrt{3}\implies \cfrac{(2x)(6\sqrt{3})}{\sqrt{2}}=6\sqrt{3} \\\\\\ \cfrac{2x}{\sqrt{2}}=\cfrac{6\sqrt{3}}{6\sqrt{3}}\implies \cfrac{2x}{\sqrt{2}}=1\implies 2x=\sqrt{2}\implies x=\cfrac{\sqrt{2}}{2}[/tex]
A quality analyst wants to construct a sample mean chart for controlling a packaging process. He knows from past experience that whenever this process is in control, package weight is normally distributed with a mean of 20 ounces and a standard deviation of two ounces. Each day last week, he randomly selected four packages and weighed each: Day Weight (ounces) Monday 23 22 23 24 Tuesday 23 21 19 21 Wednesday 20 19 20 21 Thursday 18 19 20 19 Friday 18 20 22 20 What is the sample mean package weight for Thursday
Using it's concept, it is found that the sample mean package weight for Thursday is of 19 ounces.
What is the mean of a data-set?The mean of a data-set is given by the sum of the observations divided by the number of observations.
For Thursday, the package weights in ounces are given by: {18, 19, 20, 19}.
Hence, the sample mean in ounces is of:
M = (18 + 19 + 20 + 19)/4 = 19.
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The function f is given in three equivalent forms. Which form most quickly reveals the zeros (or "roots") of the function?
A) f(x) = 1/2x^2-5x+21/2
B) f(x) = 1/2(x-3)(x-7)
C) f(x) = 1/2(x-5)^2-2
Write one of the zeroes
pls help im sorry this looks so messy
1 point
2. Three boards are unloaded into the factory.
А
B
С
Board A is three times the length of board C, plus 5 inches. Board B is two
times the length of board C, plus 3 inches. The total length of all three boards
is 104 inches. How long is each board?
Your answer
??
1. Oscar and Eli set up a lemonade stand. If they have prepared 2 1/2 gallons of lemonade, how many 1-cup servings can they sell? A) 10 B 20 C
40 D 80
Answer:
40 cups
Step-by-step explanation:
There are 16 cups in one gallon. So 16 * 2 1/2 = 40
How do do this problem
Answer:
42 in
Step-by-step explanation:
The lengths of the tangent segments drawn from an external point to a circle are equal.
AT and RT meet at point T
⇒ AT = RT = 9 in
RE and GE meet at point E
⇒ RE = GE = 5 in
AN and NG meet at point N
⇒ AN = GN = 7 in
Total perimeter = AT + RT + RE + GE + GN + AN
= 9 + 9 + 5 + 5 + 7 + 7
= 42 in
Please help quick!
Subtracting a number is the same as adding its opposite.
Use this understanding to complete each of the equations below.
Enter numbers to evaluate −5−(−7).
‐5 –(‐7)= ‐5 + _______
= ________
Enter numbers to evaluate −5−7.
‐5− 7 = ‐5 + _______
= ________
Answer:
First space: 7
second space: 2
third space: -7
last space: -12
Step-by-step explanation:
To subtract, use "Add the opposite". In the problem the minus has aready been changed to adding, so you just change the second number (-7 in the first part or 7 in the second part) to their opposite sign. see image.
15/2 + 13/8+ 14/4+ 2/1+52/8+36/4=
Answer:
30.125
the answer is 30.125 so that is the answer of this question
A researcher is studying the growth of bacteria. He starts with 260 of the bacteria. It grows continuously at a rate of 1% per hour. How many bacteria will there be in 6 hours?
Please help asap !!!!
C
Step-by-step explanation:
You do 5 - 2 = 3 and -y = -x so the answer would be C.
The Changs updated their bedroom by purchasing a new lamp for $89.95 and a comforter set for $239.99. They paid 6 3/5% sales tax on their purchases. If the Changs paid $351.72 total, determine if they paid the correct amount.
Answer:
Step-by-step explanation:
In order to determine the correct answer, we need to confirm it first by making the solution below:Costs: $89.95 = New Lamp $239.99 = Comforter 6 3/5% = Sales Tax (convert this to decimal and we get 6.6%) $351.72 = Total amount the Chang's paidLet's get the total costs first which is $329.946.6% of 329.94 is $21.78The total cost with the tax would be $351.72.Therefore, the Chang's paid the correct amount. The correct answer would be option D. The Chang's family paid the correct amount for their purchases.
When fully charged, Jaylin's
computer works for 20 hours.
She uses her computer for about
1.5 hours each day. A low battery
warning comes on when there is
hours of use or less remaining
Answer:
The battery seems to be charging at a rate of 1 percentage point per minute. So the battery should be fully charged at 10:11 AM.
Step-by-step explanation:
The volume of the sphere is 500 - cubic units.
3
What is the value of x?
04 units
O 5 units
----
O 8 units
O 10 units
Answer:
8 po yan po sagot ko .. correct me if I wrong
Type The Correct Answer,
Answer:
0.72 meters
Step-by-step explanation:
by dividing 6.48 by 9, we get 0.72 meters
Answer:
here
Step-by-step explanation:
What is the name of the line? *
GH is a tangent to the given circle.
What is a Tangent?A line that only touches a circle or an ellipse at one point is said to be tangential in geometry. If a line contacts a curve at point P, that point is referred to as the point of tangency. In other words, it is described as the line that, at that particular location, indicates the slope of a curve.
As per the given diagram:
The line segments AB, AC, DC and EF are drawn in the diagram also a line GH is drawn in the diagram.
A line GH is drawn such that it's extending from both of its end towards infinity, and it touches the circle at only one point, which is G. This satisfies all the conditions for the line GH to be a tangent.
Hence, GH is a tangent to the given circle.
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What is the solution to 2x + 5 = 6x – 5? Show your work.
Answer:
2x - 6x = -5-5
-4x = -10
4x = 10
x = 10/4
Therefore, x= 5/2.
Solve 96 =3w+ 15, where w is a real number.
2
Round your answer to the nearest hundredth?
Answer:
3+15=18 i guess
Step-by-step explanation:
dont judge me im only in 2 grade
The length of a rectangle is six times its width.
If the perimeter of the rectangle is 126 in, find its area. Answer in inch ^2
Answer:
486 square inches.
Step-by-step explanation:
126 = w + 6w + w + 6w
126 = 14w
width = 9 inches
A = wl
A = (9)(9*6)
A = 486 square inches
On January 1, 2022 Hideki Matsuyama provides services in exchange for a $10,000 zero-interest bearing note due in 4 years. The effective interest rate for a note of this type is 15 percent. How much revenue does Hideki recognize on January 1, 2022?
Hideki recognizes a $17,490.06 revenue.
RevenueGiven that on January 1, 2022 Hideki Matsuyama provides services in exchange for a $10,000 zero-interest bearing note due in 4 years, and the effective interest rate for a note of this type is 15 percent, to determine how much revenue does Hideki recognize on January 1, 2022 the following calculation must be made:
10000 x 1.15^4 = X10000 x 1.749 = x17490.06 = XTherefore, Hideki recognizes a $17,490.06 revenue.
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Answer:
Hideki recognizes a $17,490.06 revenue.
Step-by-step explanation:
Two forces of 560 N and 222 N act at a point. The resultant force is 634 N. Find the angle between the forces.
The angle between the two forces of 560 N and 222 N is 80.96°
What is the resultant of two vectors?The resultant of two vectors P and Q refer to the magnitudes of the vectors and it can be expressed by the formula [tex]\mathbf{R = \sqrt{P^2 +Q^2 +2PQ cos \theta }}[/tex]
Now, using the above equation, we can easily determine the angle between the forces of the two vectors as follows:
[tex]\mathbf{634 = \sqrt{560^2 +222^2 + 2(560 \times 222) \ Cos \theta }}[/tex]
[tex]\mathbf{401956 =313600 +49284 + 248640 \ Cos \theta }}[/tex]
[tex]\mathbf{401956 -313600 -49284 = 248640 \ Cos \theta }}[/tex]
[tex]\mathbf{39072= 248640 \ Cos \theta }}[/tex]
[tex]\mathbf{ Cos \theta = \dfrac{39072}{248640}}}[/tex]
[tex]\mathbf{Cos \theta =0.1571}[/tex]
[tex]\mathbf{ \theta =80.96^0}[/tex]
Therefore, we can conclude that the angle between the forces is 80.96°
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What value of x makes the equation true? 6 6x + 8 = 3x - 19 : A. X=-9 B. -- 3 C. = -3 D. x= 3
Answer:
A. x = -9
Step-by-step explanation:
6x + 8 = 3x - 19 <== subtract 3x from both sides
-3x -3x
3x + 8 = -19 <== subtract 8 from both sides
- 8 - 8
3x = -27 <== divide both sides by 3
/3 /3
x = -9
Hope this helps!
Answer:
[tex]\tt x=-9[/tex]
Step-by-step explanation:
[tex]\tt 6x + 8 = 3x - 19[/tex]
Subtract 8 from both sides:-
[tex]\tt 6x+8-8=3x-19-8[/tex]
[tex]\tt 6x=3x-27[/tex]
Subtract 3x from both sides:-
[tex]\tt 6x-3x=3x-27-3x[/tex]
[tex]\tt 3x=-27[/tex]
Divide both sides by 3:-
[tex]\tt \cfrac{3x}{3}=\cfrac{-27}{3}[/tex]
[tex]\tt x=-9[/tex]
The vaule of x that makes the equation true is A) x= -9.
Find SU, TU, and ST.
Answer:
SU=6
TU=6
ST=12
Step-by-step explanation:
SU and TU are equal because their hypotenuses are equal (10).
With this knowledge, you know that 2x+2=3x.
Subtracting 2x from both sides shows that x=2, so you can substitute that into the original line segment values in order to get 6 for both SU and TU. Double this to find the value of ST (12).
Solve:
x + 1/x = 4 1/4
Ans: 4,1/4
Answer:
x = 4, 1/4
solving steps
[tex]\sf \rightarrow x + \dfrac{1}{x}=4\dfrac{1}{4}[/tex]
make the denominators same
[tex]\sf \rightarrow \dfrac{x(x)}{x} + \dfrac{1}{x}=4\dfrac{1}{4}[/tex]
simplify the following
[tex]\sf \rightarrow \dfrac{x^2}{x} + \dfrac{1}{x}=\dfrac{17}{4}[/tex]
join both fractions together
[tex]\sf \rightarrow \dfrac{x^2+1}{x}=\dfrac{17}{4}[/tex]
cross multiply
[tex]\sf \rightarrow 4(x^2+1)=17(x)[/tex]
simplify
[tex]\sf \rightarrow 4x^2-17(x)+4=0[/tex]
completing square
[tex]\sf \rightarrow 4x^2-16(x)-x+4=0[/tex]
factor
[tex]\sf \rightarrow 4x(x-4)-1(x-4)=0[/tex]
group the variables
[tex]\sf \rightarrow (4x-1)(x-4)=0[/tex]
simplify
[tex]\sf \rightarrow (x-4)=0, \ (4x-1) =0[/tex]
final answer
[tex]\sf \rightarrow x=4, \ x =\dfrac{1}{4}[/tex]
Answer:
[tex]\boxed{x = \dfrac{1}{4}}[/tex] and [tex]\boxed{x = 4}[/tex]
Step-by-step explanation:
Given equation:
[tex]x + \dfrac{1}{x} = 4\dfrac{1}{4}[/tex]
Step-1: Convert the mixed fraction on the R.H.S into improper fraction
[tex]x + \dfrac{1}{x} = 4\dfrac{1}{4}[/tex]
[tex]x + \dfrac{1}{x} = \dfrac{4 \times4 + 1}{4}[/tex]
[tex]x + \dfrac{1}{x} = \dfrac{16 + 1}{4}[/tex]
[tex]x + \dfrac{1}{x} = \dfrac{17}{4}[/tex]
Step-2: Make common denominators on the L.H.S:
[tex]x + \dfrac{1}{x} = \dfrac{17}{4}[/tex]
[tex]\dfrac{x^{2} }{x} + \dfrac{1}{x} = \dfrac{17}{4}[/tex]
Step-3: Combine the denominators on the L.H.S
[tex]\dfrac{x^{2} }{x} + \dfrac{1}{x} = \dfrac{17}{4}[/tex]
[tex]\dfrac{x^{2} +1}{x} = \dfrac{17}{4}[/tex]
Step-4: Use cross multiplication
[tex]\dfrac{x^{2} +1}{x} = \dfrac{17}{4}[/tex]
[tex]x^{2} +1} = \dfrac{17x}{4}[/tex]
[tex]4(x^{2} +1}) = {17x}[/tex]
Step-5: Simplify the distributive property
[tex]4(x^{2} +1}) = {17x}[/tex]
[tex]4x^{2} +4} = {17x}[/tex]
[tex]-17x + 4x^{2} +4} = 0[/tex]
Step-6: Change "-17x" to "-16x - x" as it is equivalent
[tex]-17x + 4x^{2} +4} = 0[/tex]
[tex](-16x - x) + 4x^{2} +4} = 0[/tex]
Step-7: Factor the common terms
[tex](-16x - x) + 4x^{2} +4} = 0[/tex]
[tex]-16x - x + 4x^{2} +4} = 0[/tex]
[tex]4x(-4 + x) - 1(x - 4) = 0[/tex]
Step-8: Group the terms
[tex]4x(-4 + x) - 1(x - 4) = 0[/tex]
[tex](x - 4)(4x - 1) = 0[/tex]
Step-9i: Use cross multiplication for (x - 4)
[tex](x - 4)(4x - 1) = 0[/tex]
[tex]x - 4 = \dfrac{0}{4x - 1 } = 0[/tex]
Step-9ii: Use cross multiplication for (4x - 1)
[tex](x - 4)(4x - 1) = 0[/tex]
[tex]4x - 1 = \dfrac{0}{x - 4} = 0[/tex]
Thus [tex]x - 4 = 0[/tex] and [tex]4x - 1 = 0[/tex].
Step-10: Simplify both equations
[tex]4x - 1 = 0[/tex] [tex]x - 4 = 0[/tex]
[tex]4x = 0 + 1[/tex] [tex]x = 0 + 4[/tex]
[tex]4x = 1[/tex] [tex]\boxed{x = 4}[/tex]
[tex]\boxed{x = \dfrac{1}{4}}[/tex]
Which of the following is the correct factorization of the polynomial below?
p^3 - 125q^3
A. (p - 5q)(p^2 + 5pq + 25q^2)
B. (p - 25q)(p^2 + 25pq + 25q^2)
C. (p^2 + 10q)(p^3 + 25pq + 5q^2)
D. The polynomial is irreducible.
The correct factored form of the expression p³ - 125q³ is,
(p - 5q)(p² + 5pq + 25q²).
What is a polynomial?A polynomial is an algebraic expression.
A polynomial of degree n in variable x can be written as,
a₀xⁿ + a₁xⁿ⁻¹ + a₂xⁿ⁻² +...+ aₙ.
What is a factor of a polynomial?We know that if x = a is one of the roots of a given polynomial x - a = 0 is a factor of the given polynomial.
To confirm if x - a = 0 is a factor of a polynomial we replace f(x) with f(a) and if the remainder is zero then it is confirmed that x - a = 0 is a factor.
We know, a³ - b³ = (a - b)(a² + ab + b²).
Given, An expression p³ - 125q³.
= p³ - (5q)³.
= (p - 5q)(p² + p.5q + (5q)²).
= (p - 5q)(p² + 5pq + 25q²).
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What is the value of (-4)-3?
1
64
О.
—
1
12
64
ОО
1
12
Answer:
Answer is -1/64
Step-by-step explanation:
Mark me the brilliant
When do I use the quadratic formula?
Answer:
Step-by-step explanation:
Quadratic equations are commonly used in situations where two things are multiplied together and they both depend on the same variable. For example, when working with area, if both dimensions are written in terms of the same variable, you use a quadratic equation.
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar.
A complex number, (a + bi), multiplied by (2 + 3i) and added to -i gives the product of (-11 + 5i) and (1 – i).
a = and b =
The value of a is equal to 3 and the value of b is equal to 4.
Complex Number
A Complex Number is represented by z=a+bi, where:
a= real part
bi= imaginary number
b= imaginary part
i= [tex]\sqrt{-1}[/tex], therefore i²= -1
For solving this question, you should solve the product (-11 + 5i) * (1 – i). After that, you should compare the previous results with the result for expression ( (a + bi)* (2 + 3i) )-i. From this comparison, using the linear system you will find the variables a and b.
Step 1 - Solve the product (-11 + 5i) * (1 – i)(-11 + 5i) * (1 – i)=
-11 +11i +5i -5i²
-11 +16i -5i², as i²= -1 you can rewrite
-11 +16i -5(-1)
-11 +16i +5
-6+16i
Then,
(-11 + 5i) * (1 – i)= -6+16i
Step 2 - Simplify the expression ( (a + bi)* (2 + 3i) )-i( (a + bi)* (2 + 3i) )-i
(2a+3ai +2bi +3bi²) -i, as i²= -1 you can rewrite
(2a+3ai +2bi +3b(-1)) -i
(2a+3ai +2bi -3b) -i
( (2a-3b) + i(3a +2b) ) -i ,
For adding complex numbers, you must add or subtract the corresponding real and imaginary parts. Thus, you will have:
(2a-3b) + i(3a +2b-1)
Then,
( (a + bi)* (2 + 3i) )-i= (2a-3b) + i(3a +2b-1)
Step 3 - Identify real and imaginary parts for previous results
For (-11 + 5i) * (1 – i)= -6+16i
real part = -6
imaginary part = 16
For ( (a + bi)* (2 + 3i) )-i= (2a-3b) + i(3a +2b-1)
real part = 2a-3b
imaginary part = 3a +2b-1
Step 4 - Construct a linear system from real and imaginary parts2a-3b= -6
3a +2b-1=16, you can rewrite as 3a +2b=17.
Thus the system will be:
[tex]\begin{bmatrix}2a-3b=-6\\ 3a+2b=17\end{bmatrix}[/tex]
Step 5 - Solving the linear system
2a-3b=-6 (1)
3a+2b=17 (2)
Multiplying equation 1 by 2 and equation 2 by 3, you can rewrite as:
4a-6b= -12
9a+6b=51
Sum the equations
4a-6b+9a+6b= -12 +51
13a= 39
a=39/13=3
Replacing the value of a=3 in equation 1, you can find b.
2a-3b=-6 (1)
2*3-3b= -6
6 -3b = -6
-3b = -6 -6
-3b= -12
b= -12/-3 = 4
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multiplication problem
Answer:
No, that is incorrect.
When doing a multiplication problem, you cannot simply take out a number from a number and expect the same result. This is under some circumstances. Let's solve the equations to see the results.[tex]21 * 34 = 714\\20 * 35 = 700[/tex]
As shown in the expressions, the results differ, proving our theory from earlier.__________________________________________________________
Questions?Ask me in the comments box, please.