A two-stage air compressor operates at steady state, compressing 10 m3 /min of air from 100 kPa, 300 K, to 1200 kPa. An intercooler between the two stages cools the air to 300 K at a constant pressure of 350 kPa. The compression processes are isentropic. Calculate the power required to run the compressor, in kW, and compare the result to the power required for isentropic compression from the same inlet state to the same final pressure.

Answers

Answer 1

check photos (answer)

A Two-stage Air Compressor Operates At Steady State, Compressing 10 M3 /min Of Air From 100 KPa, 300
A Two-stage Air Compressor Operates At Steady State, Compressing 10 M3 /min Of Air From 100 KPa, 300
Answer 2

Comparing this to the actual power required for the two-stage compressor (242.6 kW), we can see that the actual power required is significantly higher.

What is work done?

Work done is the amount of energy transferred to or from a system as a result of a force acting on it over a distance.

To solve this problem, we can use the following steps:

Step 1: Determine the state points of the air at various stages of the compression process.

Stage 1: Inlet state = State 1

P1 = 100 kPa, T1 = 300 K, V1 = 10 m³/min

Stage 2: After the first stage of compression = State 2

P2 = 1200 kPa, T2 = ? (isentropic compression)

Stage 3: After intercooling = State 3

P3 = 350 kPa, T3 = 300 K, V3 = V2

Stage 4: After the second stage of compression = State 4

P4 = 1200 kPa, T4 = ? (isentropic compression)

Step 2: Calculate the temperature and specific volume at states 2 and 4 using the isentropic compression process.

For an isentropic compression process, we have:

(P2/P1)^((γ-1)/γ) = T2/T1

(P4/P3)^((γ-1)/γ) = T4/T3

where γ is the ratio of specific heats for air, which is approximately 1.4.

Solving for T2 and T4, we get:

T2 = T1*(P2/P1)^((γ-1)/γ) = 300*(1200/100)^((1.4-1)/1.4) = 742.6 K

T4 = T3*(P4/P3)^((γ-1)/γ) = 300*(1200/350)^((1.4-1)/1.4) = 892.5 K

Next, we can use the ideal gas law to calculate the specific volume of air at states 2 and 4:

V2 = V1*(P1/P2)(T2/T1) = 10(100/1200)(742.6/300) = 0.1867 m³/kg

V4 = V3(P3/P4)(T4/T3) = 10(350/1200)*(892.5/300) = 0.2604 m³/kg

Step 3: Calculate the work done in each stage of the compressor.

For an isentropic compression process, the work done can be calculated using the following equation:

W = (mCp)(T2-T1) = (mCp)(T4-T3)

where m is the mass flow rate of air, which can be calculated using the specific volume and inlet volumetric flow rate:

m = V1/(v160) = 10/(0.831460) = 0.2016 kg/s

Cp is the specific heat at constant pressure for air, which is approximately 1.005 kJ/kg-K.

Thus, the work done in each stage of the compressor is:

W1 = (0.20161.005)(742.6-300) = 77.2 kW

W2 = (0.20161.005)(892.5-300) = 116.9 kW

The total work done by the compressor is:

W_total = W1 + W2 = 77.2 + 116.9 = 194.1 kW

Step 4: Calculate the power required to run the compressor.

The power required to run the compressor can be calculated using the following equation:

Power = W_total/η

where η is the compressor efficiency.

We are not given the efficiency, but for a two-stage compressor, a reasonable estimate for η is reasonable estimate for the efficiency of a two-stage compressor is around 75-85%. Therefore, we can assume η = 0.8.

Using this efficiency value, the power required to run the compressor is:

Power = W_total/η = 194.1/0.8 = 242.6 kW

Step 5: Compare the result to the power required for isentropic compression from the same inlet state to the same final pressure.

For isentropic compression from the same inlet state to the same final pressure, the work done can be calculated using the following equation:

W = (mCp)(T2-T1) = (mCp)(T4-T3) = (m*Cp)*ΔT

where ΔT = T2-T1 = T4-T3 = 442.5 K

Thus, the work done for isentropic compression is: W_iso = (0.2016*1.005)*442.5 = 89.1 kW

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Related Questions

Who is Mario and Luigi

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Answer:

they are fictional characters featured in video games etc

Answer: Mario and Luigi are game characters, which feature in the Super Mario Maker series, the Paper Mario series, but most notably, the Super Mario Bros. series. Mario debuted in Donkey Kong (1981), while Luigi debuted in Mario Bros (1983, not to be confused with Super Mario Bros, which released two years after Mario Bros).

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Both A and B are correct

why a hard disk called a random access stroage device

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RAM is called “random access” because any storage location on the computer can be accessed directly (as opposed to randomly).

Which of the following most accurately describes an institutional conflict of interest?

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Answer:

Defined as a situation in which the financial investments or holdings of Stanford University or the personal financial interests or holdings of institutional leaders might affect or reasonably appear to affect institutional processes for the design, conduct, reporting, review, or oversight of human subjects research.

1. The reference OSHA standard requires several important characteristics of a PFAS:
It must limit the maximum arresting force imparted to the body to
with the full
body harness.

Answers

The reference OSHA standard requires several important characteristics of a PFAS. The employer must ensure that personal fall arrest systems (PFAs) must:

a. Limit the maximum arresting force on the employee to 1,800 pounds (8 kN). The figure used above must be based on the use of a full body harness.

Maximum arresting force is the highest amount of force that the fall protection system and the individual attached to the system will face as gotten by the deceleration device.

OSHA regulations gives the system performance criteria for a personal fall arrest system.

From the above, we can therefore say that The reference OSHA standard requires several important characteristics of personal fall arrest systems (PFAs) as employers must reduce the maximum arresting force on the employee to 1,800 pounds (8 kN) using full body harness.

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a hallow steel tube 3.5m long has external diameter of 120mm. in order to determine the internal diameter the tube was subjected to a tensile load of 400KN and extension was measured to be 2 mm. if the modulus of elasticity for the tube material is 200 GPa. determine the internal diameter of the tube.​

Answers

Answer:

Please check the photo (solve)

A gas turbine power plant is being designed using an air-standard Brayton cycle. Air enters the compressor with a volumetric flow rate of 7 m3 /s at 100 kPa, 300 K. The turbine inlet temperature is expected to be 1400 K. The compressor pressure ratio is 10. The turbine exhaust goes back to the atmosphere at 100 kPa. (a) Draw the schematic and T-s diagrams. (b) Determine the thermal efficiency. (c) Determine the back work ratio of this power plant.

Answers

check all the photos

Where you attend college could costmore to borrow and refinance loans

Answers

Ans: Researchers did the analysis on the average of the rates offered by Wells Fargo to determine monthly and total payments over the life of the loans. A community college borrower would pay $1,134.31 more on a $10,000 loan than a student with the same credit history at a four-year school.

In a pipe of diameter 350 mm and length 75m water is flowing at a velocity of 2.8 m/s. Find the head lost due to friction by using Darcy Weisbach equation?

Answers

Answer:

  1.71 m

Explanation:

The attachment shows the equation and values used in it. The Moody Friction Factor is not specified in this problem statement, so we have used the value provided by the calculator web site (0.02). The head loss is proportional to that factor, so it is not difficult to find the loss if your factor is different.

4. When welding, the practice metal is called a

Answers

Answer:

Nonstandard

Explanation:

The mechanical energy of an object is a combination of its potential energy and its

Answers

The mechanical energy of an object is a combination of its potential energy and its kinetic energy.

Your vehicle is/ are not part of regulated safety system 

Answers

Answer:

Amends the FMVSS on air brake systems to improve the stopping distance performance of truck tractors. The rule requires the vast majority of new heavy truck tractors to achieve a 30 percent reduction in stopping distance compared to currently required levels. For these heavy truck tractors (approximately 99 percent of the fleet), the amended standard requires those vehicles to stop in not more than 250 feet when loaded to their gross vehicle weight rating (GVWR) and tested at a speed of 60 miles per hour (mph). For a small number of very heavy severe service tractors, the stopping distance requirement will be 310 feet under these same conditions. In addition, this final rule requires that all heavy truck tractors must stop within 235 feet when loaded to their “lightly loaded vehicle weight” (LLVW).

Amends the FMVSS on air brake systems to improve the stopping distance performance of truck tractors. The rule requires the vast majority of new heavy truck tractors to achieve a 30 percent reduction in stopping distance compared to currently required levels. For these heavy truck tractors (approximately 99 percent of the fleet), the amended standard requires those vehicles to stop in not more than 250 feet when loaded to their gross vehicle weight rating (GVWR) and tested at a speed of 60 miles per hour (mph). For a small number of very heavy severe service tractors, the stopping distance requirement will be 310 feet under these same conditions. In addition, this final rule requires that all heavy truck tractors must stop within 235 feet when loaded to their “lightly loaded vehicle weight” (LLVW).

Answer:

power window controls

Explanation:

Investigate the ripple factor of half wave and full wave rectifier, which rectifier has improved ripple factor?

Answers

Answer:The ripple factor is the ratio between the RMS value of the AC voltage (on the input side) and the DC voltage (on the output side) of the rectifier. The formula for ripple factor is: Which can also be rearranged to equal: The ripple factor of half wave rectifier is equal to 1.21 (i.e. γ = 1.21).

Explanation: i no it

Alvaro designs machinery and equipment for ships. His job title is best described as . Jeanette draws maps and plans for freeway projects. Her job title is best described as . Joseph designs a new airport. His job title is best described as . Geraldine designs imaging systems that use light. Her job title is best described as .

Answers

Answer:

Alvaro designs machinery and equipment for ships. His job title is best described as Marine Engineer.

Jeanette draws maps and plans for freeway projects. Her job title is best described as Civil Drafter.

Joseph designs a new airport. His job title is best described as Transportation Engineer.

Geraldine designs imaging systems that use light. Her job title is best described as Photonics Engineer.

Hope this helps sorry I am late to respond, but anyone else who needs the answer it is here.

Based on the above, Alvaro is a Marine Engineer;

Jeanette is a Civil Drafter.Joseph is a Transportation Engineer.Geraldine  is a  Photonics Engineer.

What is machinery and equipment?

Machinery and Equipment are known to be a type of industrial tools, devices, and items that aids facilities.

Conclusively, They are said to be tangible personal property that are used as a tool for repair parts, etc. Professions in ship jobs includes, Marine Engineer, Photonics Engineer, etc.

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Determine the gage pressure at the center of pipe A in pounds per square inch and

in kilopascals.

Answers

Answer: the stress is 384 pounds per square inch.

Step-by-step explanation:

Let S represent the stress in the material of the pipe.

Let P represent internal pressure of the pipe.

Let D represent internal diameter of the pipe.

Let T represent the thickness of the pipe.

The stress in the material of a pipe subject to internal pressure varies jointly with the internal pressure and the internal diameter of the pipe and inversely with the thickness of the pipe. Introducing a constant of proportionality, k, the expression becomes

S = kPD/T

The stress is 100 pounds per square inch when the diameter is 5 inches, the thickness is 0.75 inch, and the internal pressure is 25 pounds per square inch. It means that

100 = (k × 25 × 5)/0.75

125k = 100 × 0.75 = 75

k = 75/125 = 0.6

The equation representing the relationship becomes

S = 0.6PD/T

If the internal pressure is 40 pounds per square inch, the diameter is 8 inches and the thickness is 0.50 inch, then the stress would be

S = (0.6 × 40 × 8)/0.5

S = 384

It is given thatopen parenthesis, x minus 2y, close parenthesis, times open parenthesis, x + 2y, close parenthesis, = 4Quantity A: x squared, minus, 4 times the quantity y squared Quantity B: 8 A. Quantity A is greater. B. Quantity B is greater. C. The two quantities are equal. D. The relationship cannot be determined from the information given.

Answers

Answer:

  Quantity B is greater.

Explanation:

Given:

  (x -2y)(x +2y) = 4

  A = x² -4y²

  B = 8

Find:

  the relationship between A and B

Solution:

The given expression can be expanded to give ...

  x(x +2y) -2y(x +2y) = x² +2xy -2xy -4y² = x² -4y²

This is precisely the expression designated as A. Its value is 4.

  4 < 8

  A < B

Quantity B is greater.

2. A silo (base not included) is to be constructed in the form of a cylinder surmounted by a hemisphere. The cost of construction per square unit

of surface area is twice as great for the for the hemisphere as it is for the cylindrical side wall. Determine the dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum. Neglect the thickness of the silo and waste in construction.​

Answers

An extremum is a point where the function has its highest or lowest value, and at which the slope is zero.

The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum is as follows;

Height of cylinder = 2 × Radius of cylinder

Reason:

The given parameters are;

Form of silo = Cylinder surmounted by a hemisphere

Cost of construction of hemisphere per square unit = 2 × The cost of of construction of the cylindrical side wall

Required:

The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum

Solution:

The fixed volume of the silo, V, can be expressed as follows;

[tex]V = \pi \cdot r^2 \cdot h + \dfrac{2}{3} \cdot \pi \cdot r^3[/tex]

[tex]h = \dfrac{V - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 }[/tex]

Where;

h = The height of the cylinder

r = The radius of the cylinder

The surface area is, Surface Area = 2·π·r·h + 2·π·r²

The cost, C = 2·π·r·h + 2×2·π·r² = 2·π·r·h + 4·π·r²

Therefore;

[tex]C = 2 \times \pi \times r\times \dfrac{V - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } + 4 \cdot \pi \cdot r^2 = \dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r}[/tex]

[tex]C = \dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r}[/tex]

At the minimum value, we have;

[tex]\dfrac{dC}{dr} =0 = \dfrac{d}{dr} \left(\dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r} \right) = \dfrac{16 \cdot r^3 \cdot \pi - 6 \cdot V}{3 \cdot r^2}[/tex]

Which gives;

16·π·r³ = 6·V

[tex]V = \dfrac{16 \cdot \pi \cdot r^3}{6} = \dfrac{8 \cdot \pi \cdot r^3}{3}[/tex]

Which gives;

[tex]h = \dfrac{\dfrac{8 \cdot \pi \cdot r^3}{3} - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } = 2 \cdot r[/tex]

h = 2·r

The height of the silo, h = 2 × The radius, 2

Therefore, the dimensions to be used if the volume is fixed and the cost is to be kept to a minimum is, height, h = 2 times the radius

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Steam enters the first-stage turbine shown in the figure at 40 bar and 400oC with a mass flow rate of 60,000 kg/hr. Steam exits the first-stage turbine at 20 bar and 400oC. The steam is then reheated at constant pressure to 500oC before entering the second-stage turbine. Steam leaves the second stage as saturated vapor at 0.6 bar. Assume steady state operation and ignore stray heat transfer and kinetic and potential energy effects. Determine the volumetric flow rate of the steam at the inlet to the first-stage turbine, in m3/min, the rate of heat transfer to the steam flowing through the reheater, in kW, and the total power produced by the two stages of the turbine, in kW.

Answers

Answer:

a) 62460 kg/hr

(b) 17,572.95 kW

(c) 3,814.57 kW

Explanation:

i need your help to answer in the picture plss help me!​

Answers

this looks like its the different phases of a single cylinder 4 stroke engine what are you doing in the picture or assignment though matching the numbers to the descriptions on the side?

The device in Figure P6.27 is a sloshing bath used to wash vegetable produce. For the configuration shown, use the relative velocity method to graphically determine the angular velocity of the water bath as the crank is driven clockwise at 75 rpm.

Answers

check photo (answer)

The angular velocity of the water bath as the crank is driven clockwise is 6.66rpm/ms.

How to calculate the angular velocity?

From the complete information, we are to use the relative velocity method to determine the angular velocity of the water bath.

This will be:

60/V = 1085.4/120.58

Cross multiply.

(1085.4 × V) = (120.58 × 60)

V = (120.58 × 60/1085.4)

V = 6.66rpm/ms

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The use of seatbelts in a car has significantly reduced the number of crash fatalities. Which statement best explains how societal demand guided the development of the seatbelt technology

Answers

as the public need for preventing injuries and deaths from car crashes became known,laws were enacted to mandate the inclusion of seatbelts in almost all passengers vehicles

Which of the following procedures best applies to assessing the embodied energy of a building?


analyzing the building’s materials

analyzing the building’s function

analyzing the building’s age

analyzing the building’s blueprints
100 POINTS

Answers

analyzing building materials???????????? but i can try i think it is analyzing the materials of the building

Which of the following workers are not likely to be paid during an election?
campaign press secretary
volunteer coordinator
poll worker
director of communications

Answers

Answer:

volunteer coordinator

Explanation:

because they are volunteering for that and in most of the cases they do not expect to be paid

1. Plot the normal and shear components of stress on the fictitious element relative to (1) Cartesian coordinator system, (2) a cylindrical coordinator system, and (3) a spherical coordinate system. Note: Your drawing should be by hand and in a 3D manner. Write the stress notation in matrix form for three coordinator systems. Explain the biological motivations for using the above three coordinator systems.

Answers

Answer:

d

Explanation:

5. What is the biggest danger when using
electric drills?
O A. Using the wrong size bit for the hole
required can ruin the drill.
O B. The bit could get caught and throw the
user.
O C. The bit coming loose in the drill can
cause a loss of torque.
O D. Static electricity can build up and
deliver an electric shock to the user.

Answers

Answer:

Static electricity can build up and

deliver an electric shock to the user drilling with an electric drill or any drill can create static electricity but with electric drills the static electricity can react with the drills power supply creating a short circuit proceeding to shock you which is why electric drills have rubber grips around them to INSULATE the shock if It does happen (also that's why the drills mostly are made up of non conductive materials.)

Explain the relationship between separation and economic efficiency in mineral processing.

Answers

Answer:

Post navigation. The technical excellence of separation achieved in a mineral concentration process, or any other process where two constituents of any kind are physically separated from each other, is expressed uniquely and quantitatively by the Separation Efficiency: Es = (R – Rg)

Explanation:

hope it helps.

How to make coconut harder

Answers

Now hear me out: Steel-Coated Coconuts

If you want to make a coconut harder you can take that shell up to heights its natural husk never even knew it could reach! Combining the raw, brown scraglley-ness with the tough, durable properties of steel would most definitely make a coconut harder.

Valid answer? Probably not.

Thank you for coming to TedTalk :))

Make it out of metal


Escribe dos gemplos de los cambios de conducta que
adquiere el trabajador
al momento de capacitarse.

Answers

Aprendizajes del buen vivir ya que al compartir con la comunidad y te desarrollas, tu desarrollas otra manera de pensar y adquieres el aprendizaje del buen vivir con todos sin excepción alguna

Además el aprendizaje de experimentar compartir con otras personas que no son tu familia, eso hará que desarrolles el aprendizaje de tus cualidades y en este caso sería la cualidad de la imparcialidad

1. A drawing of a cabinet shows that its dimensions are 9cm. by 4cm. The drawing indicates 1:50 scaling. What are the actual dimensions of the cabinet? 


2. Bongbong is tasked to draw a floor plan with a scale of 1:100. If the total length of the actual house is 8 meters, what will be its corresponding measurement in centimeters in floor plan?


3.The length of a bedroom measures 2.5 m., what will be the measurement in centimeters to be used in the drawing if it is in 1:50 scale?​

Answers

Explanation:

This means that for every 1 cm on the drawing, there is 80 cm in reality. To put it another way, take this

1:80 means that the building is 80 times the size of the drawing

80:1 means that the drawing is 80 times the size of the building

If it were 80:1, the drawing itself would be over 100m long.

If a construction company is considering a new type of material to use in their construction, which factors would they
focus on? (Select all that apply.)
that the new material does the same thing as an existing material but better
that the new material does the same thing as an existing material but cheaper
that the science behind the material be familiar to and understood by its employees
that the properties of the new material meet their construction needs

Answers

I would honestly select every one of the given options. Gor a company evaluating this new material it would be very valuable to hit each of these factors.

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