A truck is traveling at a constant velocity of 30 m/s. It will take the time to travel 1000 meters is (t)=33.33 S.
What is velocity?The velocity means the ratio of distance and time. Mathematically it means the distance divided by time. It can be measured in m/s and cm/s.
How can we calculate the time?To calculate the time we are using thee formula here is,
S=vt
Or, t=S/v
Here we are given,
S = The covered distance of the car = 1000 m
v= The velocity of the car. = 30 m/s.
We have to calculate the time taken by truck = t
Now we put the values in the above equation, we get
t=S/v
Or, t=1000/30
Or, t=33.33 S
From the calculation we can say that, It will take the time to travel 1000 meters is (t)=33.33 S.
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help plssss
Your car is traveling at an initial speed of Vo. At t = 0, you start increasing your speed at a constant acceleration. After 20s, the speed of the car is 54 km/ h, after 60 s — 108 km/ h.
a) What was your acceleration?
b) What was your initial speed?
c) What was the speed after 40s?
Given Data:
The applied acceleration is constant.
speed of the car after time,t1 = 20s, is V1= 54 km/h = 15 m/s
speed of the car after time,t2 = 60s, is V2= 108 km/h = 30m/s
we use the formula, V = Vo + a x t
where, Vo is the initial speed, a is the acceleration(constant),
t is the time taken by the object.
a) Acceleration = rate of change of speed with time = V2 - V1 / t2 - t1
a = 30-15/60-20
a = 15/40 = 0.375 m/[tex]{s^{2} }[/tex]
b) Initial speed, Vo = V1 - a x t1
= 15 - 0.375 x 20
= 7.5 m/s
c) Speed after 40 s, V = Vo + a x t, t = 40s
= 7.5 + 0.375 x 40
= 22.5 m/s
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alex throws a 0.25-kg rubber ball down onto the floor. the ball's speed just before impact is 4.5 m/s, and just after is 2.9 m/s. what is the change in the magnitude of the ball's momentum?
If Alex throws a 0.25-kg rubber ball down onto the floor, the ball's speed just before impact is 4.5 m/s, and just after is 2.9 m/s.The change in the magnitude of the ball's momentum is 1.85 [tex]kg \frac{m}{s}[/tex]
Calculation
Change in momentum= [tex]mv_{1} -mv_{2}[/tex]
where, m is mass of the object, m= 0.25 kg
[tex]v_{1}[/tex] is velocity before collision, [tex]v_{1}[/tex] = 4.5 m/s
[tex]v_{2}[/tex] is velocity after collision, [tex]v_{2}[/tex] = 2.9 m/s
therefore, [tex]mv_{1} -mv_{2} =m(v_{1}-v_{2} )[/tex]
⇒0.25(4.5-(-2.9)) = 0.25(4.5 + 2.9) = 0.25* 2.4
= 1.85 [tex]kg\frac{m}{s}[/tex]
What is momentum?The definition of momentum is "mass in motion." Since every item has mass, if it is moving, it must have momentum because its mass is in motion. The amount of motion and the speed of the motion are the two factors that determine how much momentum an item possesses. The factors mass and velocity affect momentum. According to an equation, an object's momentum is determined by multiplying its mass by its velocity.Momentum = mass * velocityMass times velocity would be the units for momentum. The kg*m/s is the common metric unit for momentum.To learn more about momentum, refer to https://brainly.com/question/402617
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If a tenth planet were to be discovered with a sidereal period of 125 years, what would be the radius or the orbit (distance from the Sun)? In your answer you need to have the number in the first blank and the correct abbreviated units in the second blank.
From the computation and the use of the Kepler's law, the period of the orbit is period of the orbit is 25 AU.
What is Kepler's law?The term Kepler's law has to do with the relationship between the relationship between the period of the satellite and the radius of the orbit in which the satellite is found.
According to the Kepler's law, we know that the square of the period of the satellite is directly proportional to the cube of the radius of the orbit. Having said this, we need to find the radius of the orbit and we have been told from the question as we have it above that the period of the satellite that is under consideration is 125 years.
Now;
T^2 = r^3
Given that;
T = period
r = radius of the orbit
Then;
r = T^2/3
r = (125)^2/3
r = 25 Au
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What are three modern inventions that could not have been invented without the earlier contributions of sir isaac newton?.
Answer:
there are the three basic
first law also called the law of inertia
the second one is the second law of motion and its equation is
F = ma
where m is the mass and a is the acceleration
its SI units are mass is kg and Acceleration is m/[tex]s^{2}[/tex]
the third law is called the action-reaction law
also the law of gravitation in which we survive our own earth-like plane due to the basic concept of the law of gravitation because the idea of gravitation is deal with this important law
F=GmMe/[tex]R^{2}[/tex]
The G value is 6.673*10^-11
m is the mass of an object
Me is the mass of the earth in our case we consider the object and the earth.
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a 14- kg monkey climbs up a massless rope that runs over a frictionless tree limb and back down to a 28- kg package on the ground. what is the magnitude of the least acceleration the monkey must have if it is to lift the package of the ground?
The magnitude of the least acceleration the monkey must have if it is to lift the package off the ground: is 9.8 m/[tex]s^2[/tex]
From free body diagram,
The minimum acceleration of the monkey of mass (m) to lift the package off the ground is
[tex]m_{1}a_{min} = m_2g -m_1g\\a_{min} = \frac{m_2 - m_1}{m_1} g \\a_{min} = \frac{28 - 14}{14} 9.8 m/s^2 \\ \\a_{min} = 9.8 m/s^2 \\\\\\[/tex]
What is Mass?Mass is the amount of matter in a physical body. It also measures the body's inertia, the resistance to acceleration when a net force is applied. The mass of an object also determines its gravitational force on other objects. The basic SI unit of mass is the kilogram. Mass is best understood as the amount of matter in any object or body. Everything we see around us has mass. For example, a table, a chair, a bed, a football, a glass, and even air have mass.
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a cave rescue team lifts an injured spelunker directly upward and out of a sinkhole by means of a motor-driven cable. the lift is performed in three stages, each requiring a vertical distance of 10.0 m. (1) first, the initially stationary spelunker is accelerated to a speed of 5.30 m/s. (2) then he is then lifted at the constant speed of 5.30 m/s. (3) finally he is decelerated to zero speed. how much work is done on the 73.0 kg rescuee by the force lifting him during each stage?
Mass m = 73kg
Vertical height in each stage h = 10 m
A). Initial speed u = 0
Final speed v = 4.3m / s
Work done W= mgh + ( 1/ 2) m[v 2 - u 2 ]
= 7063.2 +665.64
= 7728.84 J
B).Work done W = mgh
= 7063.2J
C).Work done W = mgh + ( 1/ 2) m [ V 2 - v 2 ]
Where V = final speed
= 0
v =4.3m / s
Substitute the values we get W =7063.2 - 665.64
= 6397.56 J
To slow down a vehicle The vehicle slows down when it sees a police car. Thesaurus synonyms, antonyms, and examples. slow down. Slowing down The car slowed down and stopped next to her. A motionless object has zero velocity. If an object has zero acceleration its velocity must be constant.
Whenever an object's acceleration is in the same direction as its velocity, the car is accelerating and is said to be accelerating. If the acceleration is simultaneously opposed to the speed, the car is said to be slower and slower. Delay slows down: An unexpected slowdown in your car could mean you're running out of gas.
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6. Force is being applied to a rotating disk at an angle of 90 degrees to itsradial line. How does the torque change if...
Torque Formula:
T = d * F * sin angle
a) if the force is doubled, torque is doubled ( directly proportional)
For example, if force is 2 N, and distance is 2 m ,
T= 2*2* sin 90 = 4 Nm
If force is doubled:
T= 2*4 * sin90 = 8 Nm
b) If the distance of the center of rotation is doubled , Torque is also doubled ( same as "a")
c) If angle decreases 45° (90 - 45 = 45 )
T= 2*2*sin45 = 2.82 Nm
Torque also decreases
you press a book perpendicularly against a vertical wall with a force of 27 n . the coefficient of static friction is 0.70 between your hand and the book and 0.50 between the book and the wall. what is the maximum book mass you can hold this way and keep from slipping?
1.926kg is the maximum book mass you can hold this way and keep from slipping.
This book with 27 N, so Normal rection force N = 27N.
let mass of brook = m Kg
here gravitational force acting downwards which tend book to more downwards and frictional force moving is acting vertically upwards to held
frictional force a must be equal to gravitational force here frictional force
fr = μN
so for body to be rest fr = mg
μN = mx 9.81
m = μN / 9.81
here maximum value of coefficient static friction μ = 0.70
m = 0.70x 27/9.81
m = 1.926kg
What is frictional force?
Friction is the force that opposes motion when the surface of one object comes into contact with the surface of another. The mechanical advantage of the machine is reduced by friction, in other words, the ratio of power to input decreases due to friction. A car uses a quarter of its energy to limit friction. However, the friction of the tires also allows the car to stay on the road, and the friction of the clutch allows it to drive. From matches to machines and molecular structures, friction is one of the most important phenomena in the physical world.
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a 80.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 47.0 m/s. if both are initially at rest and if the ice is frictionless, how far (in m) does the player recoil in the time it takes the puck to reach the goal 18.0 m away?
As a result of the law of conservation of momentum, the man will recoil as far as 0.034 m.
The law of conservation of momentum:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Where:
u₁ , u₂ = initial velocity of object 1 and object 2
v₁ , v₂ = final velocity of object 1 and object 2
Since both the player and the puck are initially at rest, hence u₁ = 0, u₂ = 0.
Therefore,
m₁v₁ + m₂v₂ = 0
Parameters given:
m₁ = 80 kg
m₂ = 0.150 kg
v₂ = 47 m/s
Plug the parameters into the equation,
80 . v₁ + 0.15 . 47 = 0
v₁ = - 0.088 m/s
Time the puck reach 18 m goal:
t = distance / velocity = 18 / 47 = 0.38 s
The player will recoil:
distance = velocity x t = 0.088 x 0.38 = 0.034 m = 3.4 cm
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The of earth’s orbit is among the planet’s unique characteristics. this characteristic allows water to exist in solid, liquid, and gas forms on earth. earth’s distance from the as well as the near- nature of its orbit, allow this phenomenon to take place.
It is distinguished from the other planets by the presence of liquid water on its surface, the presence of life, and active plate movement. It rotates on its axis once every 24 hours (a day) and orbits the Sun once every 365 days (a year). The Earth has a single moon.
What are the unique characteristics of Earth that allows the existence of life? It is the proper distance from the Sun, its magnetic field protects it from harmful solar radiation, an insulating atmosphere keeps it warm, and it contains the necessary chemical ingredients for life, including water and carbon.The Earth's orbit around the Sun is an ellipse, and the eccentricity measures how far the orbit deviates from a circle . The point on the orbit closest to the Sun is known as the perihelion, and the point farthest from the Sun is known as the aphelion.To learn more about : Earth's orbit
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a car travelling at a speed of 45km/h takes 20 minutes to reach its destination.what distance has the car travelled
First, we need to do a type conversion. Because the types of the two given quantities are different. One is in minutes. The other is in hours. A vehicle that travels [tex]45[/tex] kilometers in an hour travels how many meters in a second?
[tex]45km/h=\frac{45km}{1hour} =\frac{45km.1000}{1hour.3600} =12.5m/s[/tex]A vehicle that travels [tex]12.5[/tex] meters in a second travels how many meters in [tex]20[/tex] minutes?
[tex]1200.(12.5)=15000m=15km[/tex]If the mass of a system is halved (m’=m/2) and the net force acting on it is doubled (F’=2F), then its acceleration would be:* 7 points unchanged (x1) halved (x0.5) quartered (x0.25) doubled (x2) quadrupled (x4)
Given:
The mass of the system is m' =m/2
The net force acting on it is F' = 2F
To find the acceleration.
Explanation:
The acceleration will be
[tex]\begin{gathered} a^{\prime}=\frac{F^{\prime}}{m^{\prime}} \\ =\frac{2F}{\frac{m}{2}} \\ =\frac{4F}{m} \\ a^{\prime}=4a \end{gathered}[/tex]Thus, the acceleration would be quadrupled(x4).
during a tennis match, a player serves the ball at 23.6 m/s, with the center of the ball leaving the racquet horizontally 2.37 m above the court surface. the net is 12m away and 0.90 m high. when the ball reaches the net, a) does the ball clear it? show your solution. b) what is the distance between the center of the ball and the top of the net?
a) Yes the ball clear it. Through, equation of motion is 1.104 m > 0.9 m
b) The distance between the center of the ball and the top of the net is 0.204 m
a) As we know the equation of motion,
y = 1/2(at^2)
y= 1/2 (9.81)(0.508)^2
y = 1.266 m
height = Y net - y
h = 2.37m - 1.266m
h = 1.104m
b)
height in y direction - net height
= 1.104m - 0.9m
= 0.204m
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Victor is using his Geiger-counter to record the amount of radiation that is leaking into the soil from a nearby nuclear disposal site. This radiation decreases by the square of the distance from the source. If he starts measurements 100 m from the disposal site how close will he need to stand if he hopes to measure soil with 4 times the radiation?
According to inverse square proportionality, measuring 4 times more radiation will require Victor to _____ his distance. Victor will need to stand _____ m from the disposal site.
If Victor starts measurements 100 m from the disposal site, he needs to stand 50 m from the source if he hopes to measure soil with 4 times the radiation.
I = 1 / r²
I = Intensity
r = Distance
At a distance of 100 m from the source,
I = 1 / 100²
I = 1 / 10000
I = [tex]10^{-4}[/tex] J / m² s
Four times this radiation will have an intensity of,
I = 4 * [tex]10^{-4}[/tex] J / m² s
4 * [tex]10^{-4}[/tex] = 1 / d²
d² = 1 / 4 * [tex]10^{-4}[/tex]
d² = 0.25 * [tex]10^{4}[/tex]
d = √ 25 * 10²
d = 5 * 10
d = 50 m
Therefore, he needs to stand 50 m from the source
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the large blade of a helicopter is rotating in a horizontal circle. the length of the blade is 7.99 m, measured from its tip to the center of the circle. find the ratio of the centripetal acceleration at the end of the blade to that which exists at a point located 6.16 m from the center of the circle.
The ratio of the centripetal acceleration at the end of the blade to that which exists at a point located 6.16 m from the centre of the circle: 1.29
Centripetal acceleration is given by :
a = ω2R
where,
ω is the angular speed
R is the distance of the point from the centre
Let the point at the tip be A and that at distance 6.16 m from centre be B
Distance of point A from centre (RA) = 7.99 m
Distance of point B from centre (RB) = 6.16 m
Centripetal acceleration at A (aA) = ω2RA = 7.99ω2
Centripetal acceleration at B (aB) = ω2RB = 6.16ω2
The ratio (aA/aB) = 7.99/6.16 = 1.29
What is centripetal acceleration ?
centripetal acceleration is defined as the motion characteristic of an object moving along a circular path. Any object moving in a circle whose acceleration vector points towards the centre of that circle is called centripetal acceleration. You must have seen various examples of medium acceleration in your daily life. When you drive a car around a circle, your car experiences an average acceleration, and the average acceleration is also observed by a satellite orbiting the Earth. Middle means towards the centre.
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a navy blue car and a mint green cars drive on two different lanes of the same same very curved road. the radius of curvature of the path of the navy blue car, which has a mass of 1616 kg, is approximately 4/5 of that of the mint green car, which instead has a mass of 1818 kg. assume that neither car skids on the road. how do the static friction forces on the two cars compare, if the drivers are on the same street, both going at the local speed limit?
The friction force ratio between navy blue car and mint green car due to the centripetal force is 10/9.
We need to know about centripetal force to solve this problem. When an object moves in a circular motion, the object is experiencing centripetal force. The magnitude of centripetal force is
Fc = m . v²/R
where Fc is the centripetal force, m is mass, v is velocity and R is the radius.
The friction force is proportional to the centripetal force
From the question, we know that
mblue = 1616 kg
mgreen = 1818 kg
Rblue = 4/5 Rgreen
vblue = vgreen
Find the centripetal force ratio
Fcblue / Fcgreen = (mblue . vblue² / Rblue) / (mgreen . vgreen² / Rgreen)
Fcblue / Fcgreen = (1616 / 4/5 Rgreen ) / (1818 / Rgreen)
Fcblue / Fcgreen = 10 / 9
Hence, the tension in the cord is 32 newton.
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A golfer takes three strokes to putt a golf ball into a hole. On the first stroke, the ball moves 5.1 m due east. On the second, it moves 1.8 m at an angle 20° north of east. On the third, it moves 0.50 m due north. If the golfer had instead hit the ball directly into the hole on the first stroke, what would have been the magnitude (in m) and direction of the ball's displacement? Give the direction as a positive angle measured counterclockwise from due east.
The three strokes to put the golf ball into a hole is given. we have to find the overall displacement of the golf ball and its direction measured counterclockwise due east. So, we take due east as 0°, north as 90°, and so on.
For 1st stroke, the ball moves 5.1m due east means 5.1m at 0°.
The displacement along x- direction for 1st stroke = 5.1m × cos 0° = 5.1m, and y-displacement = 5.1m × sin 0° = 0m.
For 2nd stroke, the ball moves 1.8m at an angle 20° north of east.
Its x-displacement = 1.8m × cos (20°) = 1.691m, and y-displacement = 1.8m × sin (20°) = 0.6156m.
For third stroke, the ball moves 0.50m due north, means 0.50m by 90°.
Its x-displacement = 0.5m × cos (90°) = 0m, and y-displacement = 0.5m × sin(90°) = 0.5m.
The overall x- and y- displacements of the ball are:
x = 5.1 + 1.691 + 0 m = 6.791 m, and
y = 0 + 0.6156 + 0.5 m = 1.1156 m, respectively.
And its direction is θ = y/x = 1.1156 ÷ 6.791 = 0.164° due east.
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A bus traveling at a speed of 50 km/h has a momentum of 180,345
kg.m/s. What is the mass of the bus?
The mass of the truck is 12,974.4kg .
Describe bulk in plain terms.As a measure of inertia, which is a fundamental characteristic of all matter, mass is used in physics. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force.
An object's mass is what?Measures a substance's resistance to acceleration in physics. A measure of an object's mass is roughly equivalent to counting the atoms that make up the object. The kilogram serves as the fundamental mass unit. Mass multiplied by the gravitational acceleration equals weight.
50km/h =50×5/18 m/s= 13.88 = 13.9
momentum (p)=180,345 kg.m/s
P=mv
180,345= m X 13.9
m = 180345/13.9
m = 12,974.46
m = 12,974.4
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the simplest design for a radio/microwave transmitter antenna is a vertical conducting rod about one quarter-wavelength long. a mobile-phone manufacturer wants to build such an antenna into a gsm-900 (900 mhz) phone. how small can the phone be?
The phone can be 8.35cm small.
Frequency is the variety of occurrences of a repeating occasion in line with a unit of time. it is also from time to time referred to as temporal frequency to emphasize the assessment of spatial frequency, and regular frequency to emphasize the evaluation of angular frequency.
Frequency is an expression of ways regularly a periodic wave shape or signal repeats itself at a given amplitude. it is able to be expressed in hertz (Hz), kilohertz (kHz), megahertz (MHz), and so on.
Frequency is a vital parameter used in technological know-how and engineering to specify the temporal rate of trade discovered in oscillatory and periodic phenomena, such as mechanical vibrations, audio alerts (sound), radio waves, and mild.
GSM 900 band corresponds to a wavelength (\lambda) of
λ= c/f
where c is the speed of light and frequency is f which is 900 MHz
This gives \lambda=33.4cm
Antenna length L=\lambda/4=8.35cm
So the phone should at least be 8.35cm long.
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A horizontal rope is attached from a truck to a 1475-kg car. As the truck tows the car on a horizontal straight road, the rope will break if the tension is greater than 2551 N. Ignoring friction, what is the maximum possible acceleration of the truck if the rope does not break?
Given data
*The given mass of the car is m = 1475 kg
*The maximum tension is T = 2551 N
The formula for the maximum possible acceleration of the truck is given by Newton's second law as
[tex]\begin{gathered} T=ma_{\max } \\ a_{\max }=\frac{T}{m} \end{gathered}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} a_{\max }=\frac{2551}{1475} \\ =1.72m/s^2 \end{gathered}[/tex]Hence, the maximum possible acceleration of the truck is a_max = 1.72 m/s^2
If a batter can apply the same amount of maximum force from their hands to each bat to swing it, why
would the speed of the bat swing decrease as the mass of the bat increases?
If a batter can apply the same amount of maximum force from their hands to each bat to swing it , the speed of the bat swing decrease as the mass of the bat increases because of greater moment of inertia .
Moment of inertia is directly proportional to the mass , hence if mass of the bat increased , moment of inertia will also increase and it will be more difficult to swing the bat .
hence , the speed of the bat swing decrease as the mass of the bat increases
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Minerals and vitamins are called
Answer:
micronutrients.
Explanation:
a car is traveling at on a horizontal highway. if the coefficient of kinetic friction between road and tires on a rainy day is , what is the minimum distance (in m) in which the car will stop?
The minimum distance in which car will stop is 256m.
What is distance?
distance is the length of the space between two points.
distance is a numerical or its the occasionally qualitative measurement of how to far apart objects or points .
Sol-here we can apply Newton’s second law to the car of to determine of the maximum static friction to the force acting on the car:
€Fy=ma^y+ n-mg=0
Fs≤us mg
This maximum magnitude of static friction acts so long as the tires roll without skidding.
€Fx=ma^x-----> -fs=ma
The maximum acceleration is
a=-u^s g
The initial and final conditions are- xi=0, vi=50.0mi/h =22.4 m/s and vf =0.Then,
v^2=v^2+2a(xf-xi)---->v^2
f i I
Xf=(22.4m/s)^2/2(0.100)(9.80m/s^2)=256
Thus through the minimum distance in which car will stop is 256m.
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Scientists suspect that mars once had abundant liquid water on its surface. For this to have been true, early mars must have had __________ than mars today.
Scientists suspect that mars once had abundant liquid water on its surface. For this to have been true, early mars must have had a significantly greater atmospheric pressure and a far bigger greenhouse impact than mars today
What exactly is the greenhouse effect?The greenhouse effect describes how "greenhouse gases" trap heat at the Earth's surface. These heat-trapping gases act like a blanket wrapped around Earth, keeping it warmer than it would be without them. Carbon dioxide, methane, nitrous oxides, and water vapor are examples of greenhouse gases. Scientists have discovered that the warming effect of carbon dioxide aids in the stabilization of the Earth's atmosphere. The terrestrial greenhouse effect would collapse if carbon dioxide were removed. Without CO2, the Earth's surface would be 33°C (59°F) colder.
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suppose your friend tells you that light from the nearest star, alpha centauri, requires a time of about 4.37 light-years to reach the earth. what is incorrect about this statement? explain your reasoning
The statement is incorrect about the light year .
What is a light year ?
A Light year is the distance that light travels in a vacuum in one year.
The fastest thing we know is light, which travels through empty space at 186,000 miles or 300,000 kilometers per second. To give you an idea of how fast it is, light can circle the Earth about seven times in one second. Astronomers use the speed of light to measure distance in space. A light year (ly) is the distance that light can travel in one year. In one year, light travels approximately 5,880,000,000,000 miles or 9,460,000,000,000 kilometers. So this distance is 1 light year. For example, our closest star is about 4.3 light years away. Our galaxy, the Milky Way, is about 150,000 light-years across, and the nearest large galaxy, the Andromeda Galaxy, is 2.3 million light-years away from her.
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the combination of crumple zones and air bags and seat belts might increase the distance over which a person stops in a collision to as much as 1.00 mm . what is the force exerted on a 65.0- kgkg driver who decelerates from 18.0 m/sm/s to rest over a distance of 1.00 mm ?
From Newton's second law of motion,
F = ma
We know m = 65 kg. Next, we have to find a through this formula:
v² = v₀² + 2ad
0² = (18 m/s)² + 2(a)(1 m)
Solving for a,
a = -162 m/s²
So,
F = (65 kg)(-162 m/s²) = -10,530 Newtons.
A crumpled zone in the front of the car gradually slows the car down and increases the braking time. A safety cell is a rigid cage that prevents passengers from becoming trapped. Inside the car seat belts and airbags prevent the driver from hitting the windshield steering wheel and dashboard.
Crumple zones are typically found in the front and rear of a vehicle and are designed to crumple and crush under high-force impacts. The Crumple Zone transfers a portion of the vehicle's kinetic energy during impact to a controlled crash while maintaining the integrity of the occupant cell.
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if light of wavelength 257 nm is shined on a metal surface, electrons are ejected from the metal surface with a velocity 6.80 x 105 m/s. what is the wavelength of the ejected electrons?
The wavelength released during photoelectric effect is 353 nm.
We need to know about the photoelectric effect to solve this problem. The photoelectric effect is electron ejected from metal because of light source. The kinetic energy of the ejected electron is
K = (hc / λ) - (hc /λo)
where K is kinetic energy, h is Max Planck constant (6.6 x 10¯³⁴ Js), λ is the wavelength of light source and λo is the wavelength released from the metal.
From the question above, we know that
λ = 257 nm = 257 x 10¯⁹ m
c = 3 x 10⁸ m/s
v = 6.8 x 10⁵ m/s
me = 9.1 × 10¯³¹ kg
Find the wavelength released
K = hc . (1/λ - 1/λo)
1/2 . me .v² = 6.6 x 10¯³⁴ x 3 x 10⁸ . (1/257 x 10¯⁹ - 1/λo)
1/2 . 9.1 × 10¯³¹ . (6.8 x 10⁵)² = 6.6 x 10¯³⁴ x 3 x 10⁸ . (1/257 x 10¯⁹ - 1/λo)
2.10 x 10¯¹⁹ = 1.98 x 10¯²⁵ . (1/257 x 10¯⁹ - 1/λo)
2.10 x 10¯¹⁹ = (7.70 x 10¯¹⁹) - (1.98 x 10¯²⁵ / λo)
(1.98 x 10¯²⁵ / λo) = 5.60 x 10¯¹⁹
λo = 0.353 x 10¯⁶ m
λo = 353 nm
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Please help me quickly
"That's just the tip of the iceberg" is a popular expression you may have heard. It means that what you can see is only a small part of the overall problem. As the diagram shows, most of an iceberg is actually out of sight, below the water level. Based on this diagram, what is the most likely density of the iceberg? (Assume a density of 1.03 g/mL for seawater.)
The possible density of the iceberg from the options that have been given in the question is 0.88 g/mL.
What is the iceberg?We know that the term density has to do with the ratio of the mass to the volume of an object. Now when we find that an object is denser than another, the denser object would tend to sink on the one that has a lesser density.
In accordance with the floatation principle which states that an object would displace only its own volume of the fluid. We can see that even if an object has an equal density as the other then it can float on the other liquid.
Here we have been shown the image of an iceberg which is close to what we have known as the "tip of the iceberg". We are now being asked to be able to obtain what should be the accurate density of the iceberg.
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a lighthouse is located on a small island 4 km away from the nearest point p on a straight shoreline and its light makes two revolutions per minute. how fast is the beam of light moving along the shoreline when it is 1 km from p? (round your answer to one decimal place.)
The speed of the beam of light moving along the shoreline when it is 1 km from p 62.83 km/min revolution.
A revolution is the motion of 1 object around a center or some other object, a forceful overthrow of a government by using the people, or any sudden or grand trade. An example of revolution is the movement of the earth around the solar.
dθ/dt = 3 rev/min
= 3×2π = 6π rad/min
tanθ = x/3
[tex]\frac{d}{dt}[/tex] tanθ = [tex]\frac{d}{dt}[/tex] (x/3)
sec²θ dθ/dt = 1/3 dx/dt
dx/dt = 3sec²θdθ/dt
At x = 1km; tanθ =x/3 =1/3
sec²θ = 1 + tan²θ = 1+(1/3)²
sec²θ =10/9
dx/dt = 3sec²θ dθ/dt
dx/dt = 3×10/9×6π
dx/dt = 62.83 km/min
Hence, the beam of light along the shoreline when it is 1 km away from point P is 62.83 km/min
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