Answer: a = 0.647 m/s^2
Explanation:
Acceleration = change in speed / time → a = 22 / 34 → a = .647 m/s^2
If something weighs 2891N on earth, what’s it’s mass?
Answer:
289.1kg
Explanation:
because W=M*G, and M=W/G, so 2891N/10m/s²=289.1kg
Alex (31kg) and Cassie (19Kg) sit on a 10kg metre-long see-saw at the local park. The pivot of the see-saw is in the middle of its length. If Cassie sits at one end of the see-saw, where relative to the other end must Alex sit so the net torque is balanced? (unit:metres)
Answer:
M1 g L1 = 19 kg * 9.8 m/s^2 * 5 m = counter clockwise torque - Cassie at left end
M1 g L1 = M2 g L2 for torques to balance
L2 = M1 L1 / M2 = 19 * 5 / 31 = 3.06 M
Alex should sit at 3.1 m from the fulcrum (at 5 m from each end)
An unbalanced force acting on an object results in ______.
A. inertia
B. friction
C. acceleration
D. faster
E. slower
Answer:
friction
Explanation:
A vector is 0.888 m long and
points
in a
205 degree
direction.
Find the y-component of the
vector.
Answer:
Since the second quadrant ends at 180 deg,
205 will be 25 deg into the third quadrant (-x and -y)
y = -.888 sin 25 = -.375
One can also write y = .888 sin 205 = -.375
static frictional Force
Answer:
The static frictional force is the force between the magnetic forces statically and contains only two objects during this physical reaction. It results in electricity and a slight shock.
5. Apply Concepts A heat engine has an energy input of 300 J. Its output of use-
ful energy is 150 J. What is the total output of non-useful energy from the heat
engine? Explain how you know.
Given the data from the question, the total output of non-useful energy from the heat engine is 150 J
What is a heat engine?A heat engine is a device / equipment that can convert or transfer thermal energy into useful-work. Some examples of heat engines include
refrigeratorsInternal combustion Thermal power stationfirearms heat pumpsHow to determine output non-useful energyFrom the question given above, the following data were obtained:
Input energy = 300 JOutput (useful) = 150 JOutput (non-useful) =?Output (non-useful) = Input – Output (useful)
Output (non-useful) = 300 – 150
Output (non-useful) = 150 J
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state the formula to compute average speed acquired by a vehicle to cover a distance between two points.
ty! :)
What is the solution of this?
Answer:
1.2 is the correct answer due to the graph
Explanation:
math teacher
The electric potential, which is a scalar field, may be represented graphically by equipotential curves. The lines of electric field may be obtained from those equipotentials.
Four rectangles have been placed on the graph below. Assess the region of the graph where the magnitude of the electric field is greatest. Drag the label Emax to the rectangle in that region. Assess the region of the graph where the magnitude of the electric field is smallest. Drag the label Emin to the rectangle in that region.
The region with high electric potential (80 V and 70 V) will have high electric field while the region with low electric potential (20 V) will have low electric field.
What is Electric field?
Electric field is the field that surrounds electrically charged particles and exerts force on all other charged particles in the field.
Relationship between electric potential and electric fieldE = V/d
where;
V is electric potential (V)E is electric field (V/m)d is the distance (m)Since electric field is directly proportional to electric potential, the region with high electric potential (80 V and 70 V) will have high electric field while the region with low electric potential (20 V) will have low electric field.
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A curve is banked at an angle of 29.1 degrees above the horizontal and the road surface has a coefficient of static friction of 0.4. What must the radius of curvature be for the safe minimum speed of 27.1 m/s?
Hi there!
We can begin by summing the forces acting on the car.
Along the axis of the incline, the forces of friction and gravity are working. The force of friction points towards the top of the ramp, while the force of gravity works towards the bottom.
We can use trigonometry to determine the force due to gravity along the ramp.
[tex]F_g = Mg sin\theta[/tex]
The force due to friction is equal to:
[tex]F_f = \mu N[/tex]
The normal force is the vertical component of the force due to gravity, so:
[tex]F_f = \mu Mgcos\theta[/tex]
Now, the combination of these two forces produces a component of the centripetal force. Drawing a diagram, we see that the true centripetal force is the HYPOTENUSE, while these forces sum up to its horizontal component along the ramp.
Therefore:
[tex]F_c sin\theta = Mgsin\theta - \mu Mgcos\theta[/tex]
The centripetal force is equivalent to:
[tex]F_c = \frac{Mv^2}{r}[/tex]
m = mass (kg)
v = velocity (m/s)
r = radius (m)
Rewrite:
[tex]\frac{Mv^2}{r}sin\theta = Mgsin\theta - \mu Mgcos\theta[/tex]
Cancel out 'M'.
[tex]\frac{v^2}{r}sin\theta = gsin\theta - \mu gcos\theta[/tex]
Rearrange to solve for 'r'.
[tex]r = \frac{v^2sin\theta}{gsin\theta - \mu gcos\theta}[/tex]
Plug in values and solve.
[tex]r = \frac{(27.1^2)sin(29.1)}{(9.8)sin(29.1) - 0.4(9.8)cos(29.1)} = \boxed{266.365 m}[/tex]
help me get a answer
Answer:
I think D sorry if I'm wrong
If a transverse wave osculates 7 times every second and the speed of the wave is 27 m/s what is the wavelength of the wave
Explanation:
formula is ˠ=vf
f=1/T
1/7
f=0.14
wavelength=27Ⅹ0.14
=3.78m
OR
7Ⅹ27
=189m
How much force is required to pull a spring 3.0 cm from its equilibrium position if the spring constant is 20 N/m?
[tex]\\ \rm\rightarrowtail F=-kx[/tex]
[tex]\\ \rm\rightarrowtail F=-20(0.03)[/tex]
[tex]\\ \rm\rightarrowtail F=-0.6N[/tex]
Need help with this question. Thirty points.
[tex]1)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12 mv^2 \\\\\implies m = \dfrac{2E_k}{v^2} = \dfrac{2\times 4500}{30^2}=10~ kg\\ \\2)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12mv^2 \\\\\implies v^2 = \dfrac{2E_k}m\\\\\implies v = \sqrt{\dfrac{2E_k}{m}}=\sqrt{\dfrac{2 \times 320}{\dfrac{20}{9.8}}}= 17.709 ~ ms^{-1}\\\\3)\\\\\text{Kinetic energy,}\\\\E_k=\dfrac 12 mv^2=\dfrac 12 \times 50 \times 10^2=2500 ~J\\\\\\[/tex]
[tex]4)\\\\\text{Potential energy,}\\\\E_p =mgh = 5\times 9.8\times 1.5 = 73.5 ~J[/tex]
Which number represents runoff on the hydrologic cycle diagram?
1
2
3
4
Answer:
number 3
Explanation:
3 represents runoff
Runoff is the water collected after rainfall that drains from the surface area of land. It will be tricky to choose 4 which is likely a smaller waterbody draining to a bigger waterbody
hope it helped
Two identical charges are located 1 m apart and feel a 1 N repulsive electric force. What is the charge of each particle.
The charge on each particles which are 1 m apart and feeling a repulsive force of 1 N is 1.05×10¯⁵ C
AssumptionLet the charge on each particles be q
How to determine the charge Final force (F) = 1 NDistance apart (r) = 1 mElectrical constant (K) = 9×10⁹ Nm²/C²Charge on 1st particle (q₁) = q =? Charge on 2nd particle (q₂) = q =?The charge on each particle can be obtained by using the Coulomb's law equation as shown below:
F = Kq₁q₂ / r²
F = Kq² / r²
1 = (9×10⁹ × q²) / 1²
1 = 9×10⁹ × q²
Divide both side by 9×10⁹
q² = 1 / 9×10⁹
Take the square root of both side
q = √(1 / 9×10⁹)
q = 1.05×10¯⁵ C
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define key terms related to the muscular, skeletal, and nervous systems
Answer:
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An object of mass m is oscillating with a period T. The position x of the object as a function of time is given by the equation x(t)=Acosωt . The maximum net force exerted on the object while it is oscillating has a magnitude F. Which of the following expressions is correct for the maximum speed of the object during its motion?
What the equation given?
x(t)=Acos[tex]\omega[/tex]tMaximum velocity occurs at the equilibrium position
So
x=0Now
x(0)=Acos0[/tex]x(0)=ANow
As we know the formula
[tex]\\ \rm\rightarrowtail V_max=A\omega[/tex]
These expressions can be used
The maximum speed of the oscillating object will be given by [tex]V_{max}=Aw[/tex]
What is oscillation?An oscillation is defined as the repitative periodic motion of any object about its mean or equilibrium position.
The given equation is as follows:
x(t)=Acost
Maximum velocity occurs at the equilibrium position x=0
x(0)=Acos0
x(0)=A
Hence the maximum velocity will be [tex]V_{max}=Aw[/tex]
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The resultant of two vectors is of magnitude 3 units and 4 units is 1 units, what is the value of their dot product?
Answer:
A dot B = C is the vector equation for this expression
A · B = A B cos θ
3 * 4 cos θ = 1 the value 1 is their dot product
cos θ = 1 / 12 = .083 θ = 85.2 deg
What are the three symbols used in Ohm's law. Explain what each symbol represents and give the units for each of the variables.
Answer:
Step by step explanation:
Who is the father of the humans
Answer:
Adam Was the first person
Explanation:
Answer:
God is
Explanation:
Adam was the first human, Yes but God is the one who man Adam in his image and likeness, that is God looks just like the human
because we are made in God's image
You are standing on roller skates if you try to throw a 20-pound bowling ball while standing on skates,
what happens. How does this show Newton 3rd law
Answer:
I'd probably drop it on my toes. That would happen.
Explanation:
Please answer and show formula
Voltage = 5 volts
[tex]\sf \dfrac{number \ of \ turns \ in \ primary \ coil}{voltage\ in \ primary \ coil} = \dfrac{number \ of \ turns \ in \ secondary\ coil}{voltage\ in \ secondary\ coil}[/tex]
[tex]\hookrightarrow \sf \dfrac{400}{100} = \dfrac{20}{V_2}[/tex]
[tex]\hookrightarrow \sf 400V_2}{} = 20*100[/tex]
[tex]\hookrightarrow \sf V_2 = 5 V[/tex]
You want to improve your dominant trait score, and you decide to take daily walks by yourself. What trait will you strengthen with this activity?
Muscles such as quadriceps, hamstrings, the calf muscles and the hip adductors get stronger by walking.
Which muscles get stronger due to walking?The quadriceps, hamstrings, the calf muscles and the hip adductors are the muscles which get stronger by doing walking because impact is produced on these muscles while walking. Walking is a good exercise which have many health benefits.
So we can conclude that muscles such as quadriceps, hamstrings, the calf muscles and the hip adductors get stronger by walking.
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Answer:
introversion is the correct answer
Explanation:
God bless! Have a great day!
An elastic string of length 20cm stretch by 7mm under a load 50N . The strain in the spring is?
Answer:
0.035
Explanation:
7÷1000
=0.007m
0.007/0.2
=0.035
Mechanical strain of an elastic substance is the ratio of its change in length to the original length. The strain of the elastic string of length 20 cm when stretched by 7 mm is 0.035.
What is strain ?Strain is a physical quantity used to express the change in dimension of an elastic material. It is the ratio of change in length to the original length. Stress is the force that causing the deformation.
According to Hook's law of elasticity, the strain is directly proportional to the strain. They show a linear relation. Let L be the original length of a string and its change in length be ΔL.
Thus, strain = ΔL / L
Given that, the change in length = 7 mm = 0.7 cm
original length of the string = 20 cm
strain = 0.7 cm/ 20 cm
= 0.035
Therefore, the strain of the elastic string of length 20 cm when stretched by 7 mm is 0.035.
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A light bulb operating at a dc voltage of 120 V has a power rating of 60 W. How much current is flowing through this bulb
[tex]\\ \rm\rightarrowtail I=\dfrac{P}{V}=\dfrac{60}{120}=\dfrac{1}{2}=0.5A[/tex]
The amount of energy released when 45 g of -175° C steam is cooled to 90° C is
A. 101,700 J
B. 317,781 J
C. 419,481 J
D. 417,600 J
Answer:
The answer should be choice B.
16. The energy absorbed in 10minutes by an electrical heater is 1.5 MJ. The supply voltage is 240 V. calculate: a) The current drawn b) The quantity of electricity in Coulombs taken in 5 minutes c) The energy absorbed in 100 hours.
Answer:
If by 1.5 MJ you mean 1.5E6 Joules then
W = P t = power X time
W / t = P power
P = 1.5E6 J / 600 sec = 2500 J / s
P = I V
a) I = 2500 J/s / (240 J/c) = 10.4 C / sec = 10.4 amps
b) Q = I t = 10.4 C / sec * 300 sec = 3120 Coulombs
c) E = P * t = 2500 J / sec * 100 hr * 3600 sec / hr = 9.0E8 Joules
In question 8 from “Problems 2”, you calculated that an archery arrow shot with an initial velocity of 45 m/s at an angle of 10 degrees would travel 70.67 m (2 d.p.) before hitting a target at the same height from which it was released. If the archery target was moved further away from the archer, discuss some kinematic-based strategies that the archer could adopt to ensure that the arrow reaches the target. Ensure that the variables discussed are relevant to your answer. Assume air resistance is negligible.
The distance traveled by the arrow and horizontal velocity are directly proportional, thus when the distance increases, an increase in initial velocity will allow the arrow to hit the target.
Time of motion of the projectileIf the horizontal distance the projectile would travel before hitting the target is 70.67 m, the time of motion of the projectile is calculated as;
X = Vx(t)
t = X/Vx
t = X/Vcosθ
t = (70.67) / (45 x cos10)
t = 1.6 s
When the archery target is moved further away from the archer, the archer needs increase the initial velocity of the arrow assuming the angle of projection is constant.
Since the distance and horizontal velocity are directly proportional to each other, thus when the distance increases, an increase in initial velocity will allow the arrow to hit the target.
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A 100 Ohm, 200 Ohm, and 400 Ohm resistors are in parallel with each other. What is the equivalent
resistance? Which resistor would draw the most current, and why?
Answer:
1/R = 1/R1 + 1/R2 + 1/R3
1/1 + 1/2 + 1/4 = 1 + .5 + .25 = 1.75
1/1.75 = .572
multiplying this by 100 gives us
R = 57.2 ohms
The smallest resistor (100 ohms) will draw the most current
(One can also use R = R1 R2 R3 / (R1 R2 + R1 R3 + R2 R3)
Hi there!
We can use the following equation to solve for equivalent resistance:
[tex]\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}[/tex]
We can plug in the givens and solve.
[tex]\frac{1}{R_T} = \frac{1}{100} + \frac{1}{200} + \frac{1}{400} \\\\\frac{1}{R_T} = 0.175\\\\R_T = \frac{1}{0.175} = \boxed{57.143 \Omega}[/tex]
The resistor that would draw the most current is the 100 Ohm resistor because current chooses the path of LEAST RESISTANCE. This can also be proved mathematically with the following:
For resistors in parallel, the POTENTIAL DIFFERENCE (VOLTAGE) is the same.
Since I = V/R, a smaller 'R' means a larger 'I'. Thus, the smallest resistor would have the greatest current through it.