a tire plant makes 10 tires perm inute. If the tire plant runs for 10hours a day, how many days will it take to make 6 million tires?

Answer:

(4x^2 - 2)^2 - (4x^2)^2 = 4(1 - 2x)(1 + 2x)

16x^4 - 16x^2 + 4 - 16x^4 = 4(1 - 2x)(1 + 2x)

4 - 16x^2 = 4(1 - 2x)(1 + 2x)

4(1 - 4x^2) = 4(1 - 2x)(1 + 2x)

4(1 - 2x^2)(1 + 2x) = 4(1 - 2x)(1 + 2x)

Answer: 7 miles per hour

Step-by-step explanation:

3 1/2 miles = 7/2 miles

1/2 hours= 30 minutes

So,

In 30 mins, travelled 7/2 miles

In 1 min, travelled 7/2 ÷ 30= 7/2× 1/30 = (7×1)/(2×30) = 7/60 miles

In 60 mins, travelled (7×60)/60 miles = 420/60 miles = 7 miles.

Hence, the speed is 7 miles per hour.

Step-by-step explanation:

if you really want to get answer you should follow me

Answer:

138889/144

Step-by-step explanation:

Answer:

here.

3/4x−4−5/8x=−3

or, 3/4x−5/8x=−3+4

or, 3/4x−5/8x=1

or, 3*2/2*(4x)-5/8x=1

or,6/8x-5/8x=1

or,(6-5)/8x=1

or,1/8x=1

or,1=8x

or,x=1/8

Answer: 13

Step-by-step explanation:

12 x 2 = 24 (because of the two sides)

50 - 24 = 26 (to find the remaining amount)

26 / 2 = 13 (to equally distribute the remaining amount.)

Answer:

$23.10

Step-by-step explanation:

To get how much money you will have to pay for  7kg, you need to find out how much you have to pay for 1 kg. You will divided y divided by x = y.

8.25 (y) divided by 2.5 (x) = $3.30

You will pay $3.30 for 1 kg

So $3.30 x 7 = 23.10

You will pay $23.10 for 7 kg of potatoes.

** I hope this helps

Answer:

the last one is

four cubed plus 8 to the 4th power

4^3 + 8^4

4160

Step-by-step explanation:

Answer:

First one is equivalent second one is not equivalent

Step-by-step explanation:

Answer:

l

Step-by-step explanation:

answer: -24

tbh I’m not sure but thats what I got!

:D

Functions can be used to model real life scenarios

The function is given as:

[tex]\mathbf{V(t) = -t^3 + t^2 + 12t}[/tex]

(a) Sketch V(t)

See attachment for the graph of [tex]\mathbf{V(t) = -t^3 + t^2 + 12t}[/tex]

(b) The reasonable domain

t represents the number of weeks.

This means that: t cannot be negative.

So, the reasonable domain is: [tex]\mathbf{[0,\infty)}[/tex]

(c) Average rate of change from t = 0 to 2

This is calculated as:

[tex]\mathbf{m = \frac{V(a) - V(b)}{a - b}}[/tex]

So, we have:

[tex]\mathbf{m = \frac{V(2) - V(0)}{2 - 0}}[/tex]

[tex]\mathbf{m = \frac{V(2) - V(0)}{2}}[/tex]

Calculate V(2) and V(0)

[tex]\mathbf{V(2) = (-2)^3 + (2)^2 + 12 \times 2 = 20}[/tex]

[tex]\mathbf{V(0) = (0)^3 + (0)^2 + 12 \times 0 = 0}[/tex]

So, we have:

[tex]\mathbf{m = \frac{20 - 0}{2}}[/tex]

[tex]\mathbf{m = \frac{20}{2}}[/tex]

[tex]\mathbf{m = 10}[/tex]

Hence, the average rate of change from t = 0 to 2 is 20

(d) The instantaneous rate of change using limits

[tex]\mathbf{V(t) = -t^3 + t^2 + 12t}[/tex]

The instantaneous rate of change is calculated as:

[tex]\mathbf{V'(t) = \lim_{h \to \infty} \frac{V(t + h) - V(t)}{h}}[/tex]

So, we have:

[tex]\mathbf{V(t + h) = (-(t + h))^3 + (t + h)^2 + 12(t + h)}[/tex]

[tex]\mathbf{V(t + h) = (-t - h)^3 + (t + h)^2 + 12(t + h)}[/tex]

Expand

[tex]\mathbf{V(t + h) = (-t)^3 +3(-t)^2(-h) +3(-t)(-h)^2 + (-h)^3 + t^2 + 2th+ h^2 + 12t + 12h}[/tex][tex]\mathbf{V(t + h) = -t^3 -3t^2h -3th^2 - h^3 + t^2 + 2th+ h^2 + 12t + 12h}[/tex]

Subtract V(t) from both sides

[tex]\mathbf{V(t + h) - V(t)= -t^3 -3t^2h -3th^2 - h^3 + t^2 + 2th+ h^2 + 12t + 12h - V(t)}[/tex]

Substitute [tex]\mathbf{V(t) = -t^3 + t^2 + 12t}[/tex]

[tex]\mathbf{V(t + h) - V(t)= -t^3 -3t^2h -3th^2 - h^3 + t^2 + 2th+ h^2 + 12t + 12h +t^3 - t^2 - 12t}[/tex]

Cancel out common terms

[tex]\mathbf{V(t + h) - V(t)= -3t^2h -3th^2 - h^3 + 2th+ h^2 + 12h}[/tex]

[tex]\mathbf{V'(t) = \lim_{h \to \infty} \frac{V(t + h) - V(t)}{h}}[/tex] becomes

[tex]\mathbf{V'(t) = \lim_{h \to \infty} \frac{ -3t^2h -3th^2 - h^3 + 2th+ h^2 + 12h}{h}}[/tex]

[tex]\mathbf{V'(t) = \lim_{h \to \infty} -3t^2 -3th - h^2 + 2t+ h + 12}[/tex]

Limit h to 0

[tex]\mathbf{V'(t) = -3t^2 -3t\times 0 - 0^2 + 2t+ 0 + 12}[/tex]

[tex]\mathbf{V'(t) = -3t^2 + 2t + 12}[/tex]

(e) V(2) and V'(2)

Substitute 2 for t in V(t) and V'(t)

So, we have:

[tex]\mathbf{V(2) = (-2)^3 + (2)^2 + 12 \times 2 = 20}[/tex]

[tex]\mathbf{V'(2) = -3 \times 2^2 + 2 \times 2 + 12 = 4}[/tex]

Interpretation

V(2) means that, 20 people were infected after 2 weeks of the virus spread

V'(2) means that, the rate of infection of the virus after 2 weeks is 4 people per week

(f) Sketch the tangent line at (2,V(2))

See attachment for the tangent line

The slope of this line is:

[tex]\mathbf{m = \frac{V(2)}{2}}[/tex]

[tex]\mathbf{m = \frac{20}{2}}[/tex]

[tex]\mathbf{m = 10}[/tex]

The slope of the tangent line is 10

(g) Estimate V(2.1)

The value of 2.1 is

[tex]\mathbf{V(2.1) = (-2.1)^3 + (2.1)^2 + 12 \times 2.1}[/tex]

[tex]\mathbf{V(2.1) = 20.35}[/tex]

(h) The maximum number of people infected at the same time

Using the graph, the maximum point on the graph is:

[tex]\mathbf{(t,V(t) = (2.361,20.745)}[/tex]

This means that:

The maximum number of people infected at the same time is approximately 21.

The rate of infection at this point is:

[tex]\mathbf{m = \frac{V(t)}{t}}[/tex]

[tex]\mathbf{m = \frac{20.745}{2.361}}[/tex]

[tex]\mathbf{m = 8.79}[/tex]

The rate of infection is 8.79 people per week

Read more about graphs and functions at:

https://brainly.com/question/18806107

The 90% confidence interval is between R96.94 and R105.06

The confidence (C) = 90% = 0.9, Mean (μ) = 101, standard deviation (σ) = 39, sample size (n) = 250

α = 1 - C = 1 - 0.9 = 0.1

α/2 = 0.1 / 2 = 0.05

The z score of α/2 corresponds with the z score of 0.45 (0.5 - 0.05) which is equal to 1.645

The margin of error (E) is given by:

[tex]E=Z_\frac{\alpha }{2} *\frac{\sigma}{\sqrt{n} } \\\\E=1.645 *\frac{39}{\sqrt{250} } =4.06[/tex]

The confidence interval = μ ± E = 101 ± 4.06 = (96.94, 105.06)

Therefore the 90% confidence interval is between R96.94 and R105.06

Find out more at: https://brainly.com/question/18914334

Answer:

[tex]\sqrt[]{9} i[/tex]

Step-by-step explanation:

[tex]\sqrt[]{ab}=\sqrt[]{a} *\sqrt[]{b} \\Therefore, \sqrt[]{-9} =\sqrt[]{9}*\sqrt[]{-1} \\\\\sqrt[]{-1}=i\\\\So, \sqrt[]{-9}= \sqrt[]{9}i[/tex]

Answer:

30,012.5

Step-by-step explanation:

We power the number by itself for the past years so in this it will be 3.5  powered by itself four times equaling 150.0625 multiplied by the first deposit which is 200 so 200*150.0625= 30,012.5

Hope this helps

Answer:

(

Step-by-step explanation:

[tex]( - {4}^{5} ) + {20x}^{2} [/tex]

Answer:

[tex]{ \tt{ - {4}^{5} }} \\ = { \tt{ - (4 \times 4 \times 4 \times 4 \times 4)}} \\ \\ = - { \tt{(16 \times 16 \times 4)}} \\ \\ = - { \rm{1024}}[/tex]

If seven radical 2 means [tex]7\sqrt{2}[/tex], then the number is irrational.

It means that it goes on and on after the decimal place.

√2 is a surd, so it's irrational.

Answer:

x=20

Step-by-step explanation:

It all equals 360º and there are two of each angle. So, we can add 5x+5x+(3x+20)+(3x+20)=360º. Subtracted 40 and simplify. So 16x=320.So divide by 16 and you get that x=20.

Answer:

-6(b+2) +8

= -6b -12 +8

= -6b -4

Step-by-step explanation:

Answer:

Pythagorean triple (PT) can be defined as a set of three positive whole numbers that perfectly satisfy the Pythagorean theorem: a2 + b2 = c2.

theorem: a2 + b2 = c2.

This set of numbers are usually the three side lengths of a right triangle. Pythagorean triples are represented as: (a, b, c), where, a = one leg; b = another leg; and c = hypotenuse.

There are two types of Pythagorean triples:

Primitive Pythagorean triples

Non-primitive Pythagorean triples

Primitive Pythagorean triples

A primitive Pythagorean triple is a reduced set of the positive values of a, b, and c with a common factor other than 1. This type of triple is always composed of one even number and two odd numbers.

For example, (3, 4, 5) and (5, 12, 13) are examples of primitive Pythagorean triples because each set has a common factor of 1 and also satisfies the

Step-by-step explanation:

Pythagorean theorem: a2 + b2 = c2.

(3, 4, 5) → GCF =1

a2 + b2 = c2

32 + 42 = 52

9 + 16 = 25

25 = 25

(5, 12, 13) → GCF = 1

a2 + b2 = c2

52 + 122 = 132

25 + 144 = 169

169 = 169.

hope you all like this answer.

mark this answer as brainlist.

rate this answer quys.

Thank you ❤️.

Answer:

B

Step-by-step explanation:

Answer: B

Step-by-step explanation:

Answer:

the correct answer is C there ya go

Answer:

C. Typing 28 words in 2/3 of a min

Step-by-step explanation:

42 words : 60 secs = ? words : ? secs

42:60 16:40 / This could not be an answer because 1/3 of 42 is 14. And 16 exceeds 14. So this couldn't be a possible answer choice.

42:60 16:80 / This could not be an answer because 16 is less than 42 and the time given here is over 60 secs.

42:60 28:40 / This would be an answer because 1/3 of 42 is 14. SO if we multiplied 14 by 2 we would be 28.

42:60 28:80 / This could not be an answer because 28 is less than 42 and the time given here is over 60 secs.

[tex]y = -3x + 27[/tex]

Step-by-step explanation:

A parallel line will have the same slope as the given line so we can write the slope-intercept form of the equation as

[tex]y = -3x + b[/tex]

Since the other line goes through the point (9, 0), we can use this to solve for b:

[tex]0 = -3(9) + b \Rightarrow b = 27[/tex]

Therefore, the equation of the parallel line that goes through (9, 0) is

[tex]y = -3x + 27[/tex]

Answer:

What kind of problem? Multiplication? Division? What?

Step-by-step explanation:

Answer:

183

Step-by-step explanation:

If they are two consecutive odd numbers, than these two numbers will be close to half of the sum (364).

364/2=182

Now Find the two odd numbers in between 182, which are 181 and 183.

I had this type of question a few times recently, and this method worked every time :).

Bonus information:

For two consecutive odd/even numbers, find the half of the sum.

For three consecutive odd/even numbers, start off by finding the third of the sum. And so on...

Hope this helped! :D