The conclusion reached by the student who is most warranted is that the comet originates between the Sun and the asteroid belt.
Can humans survive on an aster?
The magnetic field and atmosphere that protect humans on Earth from harm are absent on asteroids. One approach to shield yourself from dangerous radiation is to live inside an asteroid. It is expected that humans would be sufficiently protected from radiation by excavating 100 meters beneath an asteroid.
How likely is it that an asteroid will strike Earth?
While space rocks of this size are most likely to reach Earth only about once every hundred million years, NEOs that are 50 to 100 meters (164 to 328 feet) broad have the potential to strike much more frequently—roughly every thousand years.
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Comets orbit the Sun in incredibly eccentric paths. They move in close proximity to the Sun from the outer solar system to the inner solar system via their orbits. Comets may have carried water and other materials to Earth through crashes early in the planet's history.
As the comet approaches the Sun, the outer ice layers melt and create a luminous coma, which causes comet tails to develop. This gas and dust are pushed into a long tail by particles streaming from the Sun. Always facing away from the Sun is the tail. The coma appears vivid because it reflects sunlight . Comets only briefly appear when they are close to the Sun. As they move, they appear to vanish.
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a 500 gram stone tied to the end of 1.2 m cord is swung into a vertical circular motion with a radius equal to the cord length. find the speed of the stone at the bottom of the circle if the tension in the cord is three times the stone's weight.
The speed of the stone at the bottom of the circle is 4.85 ms⁻¹.
Speed is the time fee at which an object is moving alongside a course, even as the pace is the charge and path of an object's movement. The rate of speed of the function of an object in any course.
velocity is measured because of the ratio of distance to the time in which the space became blanketed. the pace is a scalar amount because it has the most effective route and no magnitude. Speed is the time fee at which an object is moving alongside a path, while the pace is the fee and direction of an item's motion. put another way, the pace is a scalar value, whilst pace is a vector.
At the bottom position,
T - mg = Fc = mv²/r
∴ (T - mg/m)r = v²
V² = (3mg - mg ) r/ m = 2mgr/m
v = [tex]\sqrt{2gr}[/tex]
= 4.85 ms⁻¹
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A father fashions a swing for his children out of a long rope that he fastens to the limb of a tall tree. As one of the children swings from this rope that is 5.70 m long, his tangential speed at the bottom of the swing is 9.10 m/s.What is the centripetal acceleration, in m/s2, of the child at the bottom of the swing?
Given,
The length is r=5.70 m
The tangential speed is r=9.10 m/s
The centripetal acceleration is:
[tex]\begin{gathered} a=\frac{v^2}{r} \\ \Rightarrow a=\frac{9.10^2}{5.70} \\ \Rightarrow a=\frac{14.52m}{s^2} \end{gathered}[/tex]The acceleration is:
[tex]a=14.52m/s^2[/tex]One drops a penny from top of the Empire State Building on the ground below. The hight of the Empire State Building is 443m How long will it take for a penny yo strike the ground assuming no air resistance
Answer:
See below
Explanation:
Assuming no resistance
DISTANCE = 1/2 a t^2
443 = 1/2 (9.81)t^2 Shows t = 9.5 seconds
a boy pushes his little sister on a sled. the sled accelerates from 0 to 3.2 m/s . if the combined mass of his sister and the sled is 40.0 kg and 18 w of power were generated, how long did the boy push the sled?
The boy pushed the sled for 15 seconds. The Work-Energy theorem can be applied in circumstances when a rigid body must move while being subjected to several forces.
What is Energy Theorem?The Work - Energy theorem states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle.
The Work-Energy theorem can be applied in circumstances when a rigid body must move while being subjected to several forces. A rigid body can only have kinetic energy because of its rigid structure, which prevents it from storing potential energy in its lattice.
The sled is initially at rest → initial velocity (u) = 0.
Final velocity (v) = 3.2 m/s
Mass of boy and sled (M) = 40 kg
Power developed (P) = 18 W = 18 Joules/sec
According to work - energy theorem -
Work done (W) = Δ E(K) = E(f) - E(i)
Therefore -
W=[tex](1/2*40*3.2*3.2-1/2*40*0)[/tex]=204 joule
Now, Power is defined as the rate of doing work -
P =[tex]pw/dt[/tex]= [tex]w/t[/tex]
18 = 204/t
t = 15 seconds
Hence, the boy pushed the sled for 15 seconds.
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The boy pushed the sled for 15 seconds.
What is Energy Theorem?The Work - Energy theorem states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle.The Work-Energy theorem can be applied in circumstances when a rigid body must move while being subjected to several forces. A rigid body can only have kinetic energy because of its rigid structure, which prevents it from storing potential energy in its lattice.The sled is initially at rest → initial velocity (u) = 0.
Final velocity (v) = 3.2 m/s
Mass of boy and sled (M) = 40 kg
Power developed (P) = 18 W = 18 Joules/sec
According to work - energy theorem -
Work done (W) = Δ E(K) = E(f) - E(i)
Therefore -
[tex]$$\mathrm{W}=(1 / 2 * 40 * 3.2 * 3.2-1 / 2 * 40 * 0)=204 \text { joule }$$[/tex]
Now, Power is defined as the rate of doing work -
[tex]&\mathrm{P}=p w / d t=w / t \\[/tex]
[tex]&18=204 / \mathrm{t} \\[/tex]
[tex]&\mathbf{t}=15 \text { seconds }[/tex]
Hence, the boy pushed the sled for 15 seconds.
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what is happening in each section by looking at the slope
Answer:
a - constant speed walking north (positive)
b,c,d - accelerating north (positive)
e - stopped
f - negative walking at a constant speed
Explanation:
When the line is straight with a constant slope the person is hiking at a constant speed. If the line curves they are accelerating if it is flat they are not moving and if it has a negative slope the hiker is moving south
the pitcher's mound is 18.5 m to home plate. if the pitcher throws a ball there in 0.46 seconds how fast is that?
Answer:
see below
Explanation:
18.5 m in .46 sec = 18.5 /.46 m/s = 40.2 m/s
What type of energy is the sum of kinetic and potential energy in an object that is used to do work?.
Mechanical energy type of energy is the sum of kinetic and potential energy in an object that is used to do work.
What is an example mechanical energy?Potential energy plus kinetic energy are combined to form mechanical energy. It refers to the power underlying an object's location and motion. A compressed spring, for instance, has mechanical energy in the form of potential energy, while a moving vehicle has mechanical energy in the form of kinetic energy.
How does mechanical energy become electrical energy?A sequence of blades installed on a rotor shaft in a turbine generator are pushed by a flowing fluid, including such air, water, steam, combustion gases, or water. A generator's rotor shaft rotates or spins due to the fluid's force on the blades. In turn, the generator converts the rotor's physical (kinetic) energy into electricity.
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how far from the front of the car will the cm be when two people sit in the front seat 2.30 mm from the front of the car, and three people sit in the back seat 3.40 mm from the front? assume that each person has a mass of 60.0 kgkg . express your answer to three significant figures and include the appropriate units.
The center of mass exists a position defined relative to an object or system of objects.
The proper significant figures and proper rounding of digits exists 2.603 m.
What is meant by center of mass?The unique location where the weighted relative position of the scattered mass adds to zero is known as the center of mass in physics. Here is where a force can be applied to produce a linear acceleration without also producing an angular acceleration.
A position established in relation to an object or set of objects is the center of mass. It represents the system's average location as weighted by each component's mass. The center of mass for straightforward stiff objects with homogeneous density is found at the centroid.
Given:
Mass of car, m = 1150 kg
Distance, d = 2.35 m
The new position of center of mass will be:
[tex]$=\frac{1150 \times 2.35+160 \times 2.7+240 \times 3.75}{240+260+1150} \\[/tex]
simplifying the above equation, we get
= (2702.5 + 432 + 900) / 1650
= 4034.5 / 1650
= 2.603 m
Therefore, the proper significant figures and proper rounding of digits exists 2.603 m.
The complete question is:
The CM of an empty 1150 kg car is 2.35 m behind the front of the car. How far from the front of the car will the CM be when two people sit in the front seat 2.70 m from the front of the car, and three people sit in the back seat 3.75 m from the front? Assume that each person has a mass of 80.0 kg.
express answers in proper significant figures and proper rounding of digits.
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a car is travelling at a velocity of 2.0m/s. it accelerates at a constant 0.20m/s^2 for 2.5 min what is the final velocity of the car
The velocity of a body or object determines its direction of motion. Speed is a scalar quantity in its most fundamental form. Velocity is essentially a vector quantity. It is the rate of change in distance. The displacement change rate is the issue.
The rate at which an object's position changes when observed from a specific point of view and when measured against a specific unit of time is known as its velocity.
V = u + a*t
V = 2 + 0.20 * (2.5*60)
V = 32 m/s
The rate at which the speed and direction of a moving object change over time is known as acceleration. Something is said to be accelerating when it starts to move faster or slower. Motion on a circle accelerates even while the speed is constant because the direction is always changing. Due to the frequent change in direction, motion on a circle accelerates even while the speed is constant.
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Students were asked about the speed of cars involved in an accident. When the verb was changed from "contacted" to "smashed", ________.
Students were asked about the speed of cars involved in an accident. When the verb was changed from "contacted" to "smashed", students were more likely to report that there was broken glass involved in the accident.
What is a verb?A verb is one of the parts of speech in English language and it can be defined as a type of word which is used to describe an action, occurrence, experience, or a state of existence such as, smashed, living, contacted, clean, drive, etc.
What is speed?Speed can be defined as the distance covered by a physical object per unit of time. This ultimately implies that, the higher the speed of a car that is involved in a road crash or accident, the higher would be the level of impact and damage that would be caused.
In this context, we can reasonably infer and logically deduce that changing the verb from contacted to smashed, ultimately implies that the road crash or accident was ghastly and fatal and such would cause broken glasses in the cars that were involved.
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Complete Question:
Students were asked about the speed of cars involved in an accident. When the verb was changed from "contacted" to "smashed" ______,
students were more likely to report that there was broken glass involved in the accident
students were less likely to report that the cars were traveling at high speeds
students were more likely to report that no one was injured in the accident
there was no differences noted.
Applying Concepts Does a car's speedometer show instantaneous speed, average speed, or velocity? Explain.
Answer:
The speedometer of a car reveals information about the instantaneous speed of your car. It shows your speed at a particular instant in time.
Explanation:
Jose applies a force of 20 N North, Johnny applies a force of 10 N West and Janie applies a force of 25 N south on a heavy dresser. Find the resultant force on the dresser.
Answer:
Resultant force of the given forces: approximately [tex]11.2\; {\rm N}[/tex] at approximately [tex]53^{\circ}[/tex] west of south.
Explanation:
The resultant force of these forces will be:
[tex]25\; {\rm N} - 20\; {\rm N} = 5\; {\rm N}[/tex] to the south (the [tex]20\; {\rm N}[/tex] force to the north partially balances the [tex]25\; {\rm N}[/tex] force to the south), and[tex]10\; {\rm N}[/tex] to the west.Refer to the diagram attached. The resultant [tex]5\; {\rm N}[/tex] force to the south and the [tex]10\; {\rm N}[/tex] force to the west are perpendicular to each other, forming the two legs of a right triangle. The hypotenuse of this right triangle will be the net effect of these two forces.
Apply Pythagorean's Theorem on this triangle to find the magnitude of this net effect:
[tex]\begin{aligned}(\text{length of hypotenuse}) &= \sqrt{10^{2} + 5^{2}} \approx 11.2\end{aligned}[/tex].
Hence, the magnitude of this net effect will be approximately [tex]11.2\; {\rm N}[/tex].
Let [tex]\theta[/tex] denote the angle between this resultant force and west. In this right triangle:
[tex]\begin{aligned} \tan(\theta) &= \frac{(\text{opposite})}{(\text{adjacent})} \\ &= \frac{5\; {\rm N}}{10\; {\rm N}} \\ &= \frac{1}{2}\end{aligned}[/tex].
[tex]\begin{aligned} \theta &= \arctan\left(\frac{1}{2}\right) \approx 27^{\circ}\end{aligned}[/tex].
Hence, the angle between this resultant force and south will be approximately [tex](90^{\circ} - 27^{\circ}) = 63^{\circ}[/tex]. This resultant force will be at approximately [tex]63^{\circ}[/tex] west of south.
if a cylindrical space station 275 mm in diameter is to spin about its central axis, at how many revolutions per minute ( rpmrpm ) must it turn so that the outermost points have an acceleration equal to gg ?
Rotation speed of the space station so that the outermost points have an acceleration equal to 'g' = 2.55 rpm
What is Rotation speed ?
The rate at which the Aeroplan should begin rotating into takeoff attitude is known as V r.
V r, the rotational speed, cannot be lower than V1. A subsequent rejected takeoff may not be achievable within the remaining runway length and is likely to result in a Runway Excursion if it is more than V1 and it is discovered that, at V r, rotation cannot be completed.
V r depends on the weight of the aircraft and the flap position, but it can also change according on temperature, pressure, and altitude.
Gravitational acceleration = g = 9.8 m/s2
Diameter of the space station = D = 275 m
Radius of the space station = R
R = D/2
R = 275/2
R = 137.5 m
Angular speed of the space station = [tex]\omega (rad/s[/tex])
Centripetal acceleration at the outermost points = ac = g = 9.8 m/s2
ac = [tex]\omega2R\\[/tex]
9.8 =[tex]\omega2(137.5)[/tex]
[tex]\omega \\[/tex]= 0.267 rad/s
Converting from rad/s to rpm, (1 revolution = [tex]2\pi radians[/tex] , 1 minute = 60 seconds)
\omega = 0.267 [tex]\times (\frac{60}{2\pi })[/tex]
\omega = 2.55 rpm
Rotation speed of the space station so that the outermost points have an acceleration equal to 'g' = 2.55 rpm
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b. Which station broadcasts waves with a shorter wavelength
Answer:
blue and purple light
Explanation:
Light waves have very, very short wavelengths. Red light waves have wavelengths around 700 nanometers (nm), while blue and purple light have even shorter waves with wavelengths around 400 or 500 nm.
a brick is thrown upward from the top of a building at an angle of 25 degreees to the horizontal and with an initial speed of 15 m/s. if the brick is in flight for 3.0 s, how tall is the buiding
Angle 32rad turn during that time if the angular accelaration is constant.
What is accelaration?
acceleration, rate at which the velocity changes with time, in terms of both speed and the direction. A point or else it's an object moving in a straighten line is accelerated if it is speeds up or slows down. Motion on a circle is the accelerated even if the speed is constant, because of the direction is continually changing.
Sol- In an uniformly accelerated circular motion, the angle traveled by the object is given by-
∆=wf+wo/2×t
Here wf is the final angular speed .
It is the initial angular speed and t is the time of the motion. Replacing the given values-
∆= 12 rad/s + 4 rad/s /2 (4s)
∆= 32rad .
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A river has current of 4 m/s south with respect to the shore.
A swimmer is swimming in the river (which is redundant).
If the swimmer is swimming 2 m/s north with respect to the water, what is his velocity relative to the shore?
If the swimmer is swimming 3 m/s south with respect to the water, what is his velocity relative to the shore?
PLEASE ANSWER FAST I HAVE TO SUBMIT THIS QUESTION TODAY!!
The velocity of the swimmer relative to the shore is 2 m/s south by vector addition
What is vector addition ?
Vector addition means putting two or more vectors together. In the addition of vectors, we are adding two or more vectors using the addition operation in order to obtain a new vector that is equal to the sum of the vectors. Vector addition finds its application in physical quantities where vectors are used to represent velocity, displacement, and acceleration.
We can solve this problem by using vector addition.
In fact, we can take north as positive direction, and we can write the following:
vc = - 4m/s is the velocity of the current (which is negative, since it is south)
v s= +2m/s is the velocity of the swimmer (which is positive, since it is north)
Therefore, the velocity of the swimmer relative to the shore is
v = vs + vc = 2+(-4) = - 2m/s
And the negative sign means the direction is south, so the answer is
v = 2 m/s south
The velocity of the swimmer relative to the shore is 2 m/s south by vector addition
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when 1 kg of water and 1 kg of wood absorb the same amount of heat, the change in temperature of water is less than the changes in temperature of the wood. which statement helps to explain this difference?
A. The latent heat of fusion of water is less than of wood.
B. Intermolecular forces in water are less than those in wood.
C. Intermolecular forces in water are greater than those in wood.
D. The latent heat of fusion of water is greater than that of wood.
When 1 kg of water and 1 kg of wood absorb the same amount of heat, the change in the temperature of the water is less than the change in temperature of the wood because the intermolecular forces in water are greater than those in wood.
What are intermolecular forces?Intermolecular forces are the forces of attraction that exist between the molecules of the same substance.
Intermolecular forces help to keep the molecules of a substance.
The stronger the intermolecular forces between molecules of a substance, the more heat energy it will require to separate the molecules of the substance.
The molecules of water have in addition to the covalent bond between the atoms of hydrogen, hydrogen bonds that exists between its molecules.
These intermolecular forces present in water are responsible for the high heat capacity of water.
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a girl delivering newspapers travels three blocks west, four blocks north, and then six blocks east. a. what is her resultant displacement? b. what is the total distance she travels?
After a girl delivering newspapers travels three blocks west, four blocks north, and then six blocks east, her total displacement is 5 blocks. While the total distance covered is 13 blocks.
What is displacement?A displacement is a vector in geometry and mechanics whose length is the smallest distance between the beginning and final positions of a moving point P.
If an item moves relative to a reference frame, such as a lecturer moving to the right of a whiteboard or a passenger moving toward the back of an airliner, the object's location changes. This shift in location is referred to as displacement.
Displacement (change in position) = Last position – initial position
To Calculate displacement, let displacement be (d)
d = -3i + 4j + 6i (-i because she turned west, +i because she turned east)
d = 3i + 4j
d = √(3² + 4²)
d = √(9 + 16)
d = √25
d = 5 blocks.
Total distance (Td_ = Sum of all the blocks traveled.
Td = 3 + 4 + 6
Td = 13 blocks.
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Car A starts from rest at t =0 and travels along a
straight road with a constant acceleration of 2 ft/s^2 of until it
reaches a speed of 74 ft/s^2 . Afterwards it maintains this
speed. Also, when t = 0 , car B located 5760 ft down the
road is traveling towards A at a constant speed of 56 ft/s^2 .
Determine the distance traveled by car A when they pass
each other.
The distance traveled by car A when they pass each other is 3278.2 ft.
What is the time taken for the two cars to meet each other?The time taken for the two cars to meet each other is calculated by applying the concept of relative velocity.
(Va + Vb)t = d
where;
Va is the velocity of car AVb is the velocity of car Bt is the time of motion of the two carsd is the distance between the cars(74 + 56)t = 5760
130t = 5760
t = 5760/130
t = 44.3 s
The distance traveled by car A when they pass each other is calculated as follows;
da = 74 ft/s x 44.3 s
da = 3,278.2 ft
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a single-turn circular loop of radius 5.5 cm is to produce a field at its center that will just cancel the earth's field of magnitude 0.7 g directed at 70 below the horizontal north direction. find the current in the loop.
The current in the loop will be 6.13 A.
What is a magnetic field ?The magnetic field is the area in and around a magnet that is subject to the effects of magnetism. We employ the magnetic field as a tool to describe the distribution of the magnetic force in the vicinity and inside something magnetic in nature.
According to the question,
Radius of loop,
r =5.5 cm or,
r = 0.055 m
Earth's magnetic field, = 0.7G = 0.7 × 10⁻⁴ T
Number of turns, N = 1
We know the relation,
B = µ₀ ×N×I/2r
B = [tex]B_{e\\}[/tex]
then,
[tex]B_{e\\}[/tex] = µ₀ ×N×I/2r
By substituting the values,
0.7 × 10⁻⁴ = 4π × 10⁻⁷×1 × I / 2× 0.055
hence,
The current will be
I = 2× 0.055 × 0.7 × 10⁻⁴/ 4π ×10⁻⁷×1
I = 6.13A
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The longest shish kebab ever made was 881.0m long. Suppose the meat and veggies need to be delivered in a cart from one end of this shish kebab skewer to the other end. A cook pulls the cart by applying a force of friction acting on the cart is 28.00N, what is the net work done on the cart and it’s content during the delivery.
Answer:
Explanation:
Given:
L = 881.0 m
F = 28.0 N
___________
A - ?
The work :
A = L*F = 881.0 * 28.0 ≈ 24 670 J
PLEASE HELP
Question: How would the paths of motion of the planets change if the gravitational force of the sun were to suddenly disappear?
The planets currently move in ___ paths. Newton observed that objects always move in straight paths unless ____. This means that removing the force of gravity would cause them to ____.
The paths of motion of the planets, if the gravitational force of the sun were to suddenly disappear will be a straight line.
The orbits in which the planets revolve around the Sun is elliptical in shape. Johannes Kepler was the first to discover the elliptical shape of orbits which was called as Kepler's laws of planetary motion.
According to Newton's first law of motion, objects always move in straight paths unless acted upon by an external force. This means that removing the force of gravity would cause them to move a straight line tangential to the orbit that it was revolving about.
Therefore,
The planets currently move in elliptical pathsNewton observed that objects always move in straight paths unless acted upon by an external forceThis means that removing the force of gravity would cause them to move a straight lineTo know more about Kepler's laws of planetary motion
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a 4.0 kg block on a horizontal, frictionless surface is connected by a massless string and a massless, frictionless pulley to a hanging mass. for what value of the hanging mass does the block accelerate at 1.8 m/s2 ?
13a value of the hanging mass does the block accelerate at 1.8 m/s2
For 8 kg mass,
m 1 g - T = m 1 a
8g - T = 8a —————(I)
For 5 kg mass,
T - m 2 g = m 2 a
T - 5g = 5a —————(II)
Adding both equations, we get
8g - 5g = 13a
On a surface with no friction, is there acceleration?The constant velocity of the body on the frictionless surface is represented by the frictionless surface acceleration. No net force on the moving object can stop it from going when the surface is frictionless. As a result, the body keeps moving at the same speed. The skater has no net acceleration if no forces are operating on him and he is on a frictionless surface. The acceleration must be zero since the skier must have mass. If there is no acceleration when an item is moving, its velocity stays constant.
We must understand that acceleration always occurs in areas where there is friction. There are several types of forces at work on moving objects.
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an air-track glider attached to a spring oscillates between the 15.0 cm mark and the 66.0 cm mark on the track. the glider completes 12.0 oscillations in 41.0 s. what is the period of oscillations?
The time period is 3.3 s, frequency is 0.303 Hz, amplitude is 0.25 m, and maximum speed is 0.47575 m/s.
Based on the given information,
• The air-track glider connected with a spring oscillates between the 10 cm mark and the 60 cm mark.
• In 33 seconds, the glider completes 10 oscillations.
Here we have to find the period, frequency,amplitude and maximum speed of glider.
The time period of one oscillation is 33s/10 = 3.3s
The frequency f is the reciprocal of the time period.
f= 1/T =1/3.3 S = 0.303 Hz
The amplitude A is
A = 1/2 (60cm - 10cm)
= 25cm
Maximum speed of glider is
V max = 2π/t (0.25m)
V max = 0.47575m/s
Thus, time period is 3.3 s, frequency is 0.303 Hz, amplitude is 0.25 m, and maximum speed is 0.47575 m/s.
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A stone is projected upwards to an angle of 30° to the horizontal from the top of a tower of height 100m and it hits the
ground at a point Q. if the initial velocity of projection is 100m/s, calculate:
(0
Maximum height of the stone above the ground. (ii) Time it takes to reach this height (iii) Time of flight of the
stone. (iv) Horizontal distance from the foot of the tower to the point Q.
The correct answer are as follows
(i) 250 m is the maximum height
(ii) Time to reach the height is 5 s
(iii) Time of the flight is 10 s
(iv) Horizontal distance from the foot of the tower to point Q is 433 m
Given, π°= stand as the angle= 30°
h= height= 100m
u= initial velocity= 100m/s
g= acceleration due to gravity= 10m/s²
(i) maximum height= h(max)= u²sin²π°/g
= 100²(sin30°)²/10
= 10000(0.25)/10
= 1000(0.25)
= 250m
height(max)= 250m
(ii)time it takes to reach the height= using π°/g
= 100sin30°/10
= 10 × 0.5
= 5
t= 5s
(iii)time of flight, T= 2t
T= 2(5)= 10
T= 10s
(iv)horizontal distance=H= u²cosπ°/2g
= 100²(cos 30°)/2(10)
= 10000(0.866)/20
= 500(0.866)
= 433
H ( distance)= 433m.
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The fact that the voyager spacecraft continue to speed out of the solar system, even though its rockets have no fuel, is an example of.
The truth that Voyager maintains to hurry out of the sun system, despite the fact that its rockets haven't any fuel, is an instance of Newton's first regulation(law) of movement.
Newton's first regulation states that each item will continue to be at relaxation or in uniform movement in a immediately line except pressured to extrude its kingdom via way of means of the movement of an outside force. This tendency to withstand modifications in a kingdom of movement is inertia. The 3 legal guidelines of movement have been first said via way of means of Isaac Newton in his Philosophie nutralize Principia Mathematica (Mathematical Principles of Natural Philosophy), firstly posted in 1687.
Newton used them to research and provide an explanation for the movement of many bodily gadgets and systems, which laid the muse for classical mechanics. In the time seeing that Newton, the conceptual content material of classical physics has been reformulated in opportunity ways, concerning unique mathematical techniques which have yielded insights which have been obscured withinside the original, Newtonian formulation.
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a charged particle of mass 0.0020 kg is subjected to a 6.0 t magnetic field which acts at a right angle to its motion. if the particle moves in a circle of radius 0.20 m at a speed of 5.0 m/s what is the magnitude of the charge on the particle?
The magnitude of the charge on the particle is 0.0083 C.
The centripetal force acting on the charged particle is equal tp the magnetic force.
[tex]\frac{mv^{2} }{r}[/tex] = qB
q = [tex]\frac{mv}{rB}[/tex]
= [tex]\frac{(0.0020kg)(5.0m/s))}{(0.20 m)(60T)}[/tex]
= 8.33 × 10⁻³ C 0r 0.0083 C
A magnetic field is a vector discipline that describes the magnetic influence on transferring electric fees, electric currents, and magnetic materials. A shifting charge in a magnetic subject experiences a pressure perpendicular to its very own pace and to the magnetic area.
This force causes the magnets to attract or repel each other. Examples of magnetic force are a compass, a motor, the magnets that maintain stuff at the fridge, educate tracks, and new roller coasters. All transferring costs deliver upward thrust to a magnetic subject and the costs that circulate via its regions, revel in pressure.
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a clod of dirt falls from the bed of a moving truck. it strikes the ground directly below the end of the truck. what is the direction of its velocity relative to the truck just before it hits? is this the same as the direction of its velocity relative to ground just before it hits? explain your answers.
The direction of the velocity of the clod of dirt relative to the truck just before it hits is in the same direction as that of the truck.
The direction of the velocity of the clod of dirt relative to the ground just before it hits is in the opposite direction as that of the ground.
What is relative velocity?The relative velocity of an object in motion is the velocity of that object when viewed from a reference point.
The direction of the velocity of the clod of dirt before it hits the ground is in the same direction as that of the truck.
However, compared to the ground, the direction of the relative velocity is in the opposite direction.
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how do we estimate the age of the universe? how do we estimate the age of the universe? by measuring the recession velocities and the distances of distant galaxies and noticing that these parameters are intimately related to time. by observing the rotation rate of spiral galaxies and determining when they must have begun to rotate. by reading ancient texts, which instruct us on the origin of the universe. by examining the spectra of cepheid variable stars in neighboring galaxies.
By measuring the recession velocities and therefore the distant galaxies and noticing that these parameters are intimately related to time. Option A.
Find the oldest stars, measure the expansion rate of the universe, and extrapolate back to the large Bang. a bit like a detective can trace the origin of a sphere through a hole in the wall.
Current measurements put the world at about 4.54 billion years old and therefore the universe at About 13.8 billion years. Scientists measure the dimensions of the universe in a myriad of different ways. they will measure ripples from the early universe known as baryonic acoustic oscillations that fill the cosmic microwave background. you'll also use a standard candle, like a Type 1A supernova, to live within distance.
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Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. How do the average intensities of the waves compare?.
The correct answer is option C.
Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. The average intensity of Wave 1 is nine times the intensity of Wave 2.
By comparing the two electromagnetic waves, we get:
Maximum Electric Field Strength of Wave(1) = 3 x Maximum Electric Field Strength of Wave (2), i.e.
[tex]E_{1}[/tex] = 3 x [tex]E_{2}[/tex]
Now comparing the average intensities of the two waves. we get [tex]\frac{I1}{I2}[/tex]
The average intensity of electromagnetic wave 1 can be expressed as:
[tex]I_{1}[/tex] = [tex]\frac{1}{2}[/tex] x ε0 x [tex]E1^{2}[/tex] x c ------- (1)
Now, the average intensity of the electro-magnetic wave 2 can be expressed as:
[tex]I_{2}[/tex] = [tex]\frac{1}{2}[/tex] x ε0 x [tex]E2^{2}[/tex] x c -----(2)
Now comparing equations 1 and 2 we get.
[tex]\frac{I1}{I2}[/tex] = [tex]E1^{2}[/tex] / [tex]E2^{2}[/tex]
[tex]\frac{I1}{I2}[/tex] = ( 3 x [tex]E2)^{2}[/tex]/ [tex]E2^{2}[/tex]
[tex]\frac{I1}{I2}[/tex] = 9
Thus, we can say that the average intensity of Wave 1 is nine times the intensity of Wave 2.
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The complete question is:
Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of Wave 2. How do the average intensities of the waves compare?
a. The average intensity of Wave 1 is three times the intensity of Wave 2.
b. The average intensity of Wave 2 is three times the intensity of Wave 1.
c. The average intensity of Wave 1 is nine times the intensity of Wave 2.
d. The average intensity of Wave 2 is nine times the intensity of Wave 1.