can be answered using momentum.
momentum = p
p1= mass1 * velocity1
p1 = p2
therefore
p1 = 6kg * 4m/s
p1 = 24kgm/s
p2=m2 * v2
24 kgm/s = 7kg * v2
v2 = 24 kgm/s / 7kg
v2= 3.42 m/s
On Earth, a spring stretches by 5.0 cm when a mass of 3.0 kg is suspended from one end.
The gravitational field strength on the Moon is
1/6 of that on Earth.
Which mass, on the Moon, would stretch the spring by the same extension?
Reasons too :(
igcse physics
Answer:
Mass = 18.0 kg
Explanation:
From Hooke's law,
F = ke
where: F is the force, k is the spring constant and e is the extension.
But, F = mg
So that,
mg = ke
On the Earth, let the gravitational force be 10 m/[tex]s^{2}[/tex].
3.0 x 10 = k x 5.0
30 = 5k
⇒ k = [tex]\frac{30}{5}[/tex] ................ 1
On the Moon, the gravitational force is [tex]\frac{1}{6}[/tex] of that on the Earth.
m x [tex]\frac{10}{6}[/tex] = k x 5.0
[tex]\frac{10m}{6}[/tex] = 5k
⇒ k = [tex]\frac{10m}{30}[/tex] ............. 2
Equating 1 and 2, we have;
[tex]\frac{30}{5}[/tex] = [tex]\frac{10m}{30}[/tex]
m = [tex]\frac{900}{50}[/tex]
= 18.0
m = 18.0 kg
The mass required to produce the same extension on the Moon is 18 kg.
Answer:
18 kg
Explanation:
weight (N) = mass (kg) × gravitational acceleration (m/s²)force (N) = k (spring constant) × extension (m)On Earth, acceleration of gravity is 10 m/s²
weight = 3.0 (kg) × 10 (m/s²)weight = 30 (N)Since weight is a force, the force is 30 N. The value of spring constant is unknown
30 (N) = k × 5 (m)k = 6 (m/N)Spring constant is 6. Now let's find the mass on the Moon
mass (kg) × gravitational acceleration (m/s²) = k (spring constant) × extension (m)Gravitational acceleration of the moon is 1/6 of that on Earth. Earth's g = 10, so Moon's g = 10/6
m × 10/6 = 6 × 5m = 30/(10/6)m = 18The mass is 18 kg
Brian Berg of lowa built a house of cards 4.88 m tall. Suppose Berg throws a ball from ground level
with a velocity of 9.98 m/s straight up. What is the velocity of the ball as it first passes the top of
the card house?
Answer:
Vf = final velocity = 1.96 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f}^{2}=v_{o}^{2}-2*g*x[/tex]
where:
Vf = final velocity [m/s]
Vo = initial velocity = 9.98 [m/s]
g = gravity acceleration = 9.81 [m/s²]
x = vertical distance [m]
[tex]v_{f}^{2}=(9.98)^{2}-2*9.81*4.88\\v_{f}^{2} = 99.6-95.74\\v_{f}=\sqrt{3.8544}\\v_{f}=1.96[m/s][/tex]
Note: The negative sign of the gravity acceleration means that the gravity acceleration is pointing in the opposite direction of the movement.
An object is subject to a 84 Nm torque about a point when a
21 N of force is applied to a second point along the object's
length. How far apart are the two points
Answer:
d = 4[m]
Explanation:
Torque in physics is defined as the product of force by distance. This way you can use the following equation to calculate the torque.
[tex]T=F*d[/tex]
where:
T = torque [N*m]
F = force [N]
d = distance [m]
Now replacing in the equation above.
[tex]84=21*d\\\\d= 4[m][/tex]
Explain why refraction takes place.
Please help explain in a simple way
Answer:
lCdfKFBWRblNLWFNJLBe
Explanation:
jk jk Refraction is an effect that occurs when a light wave, incident at an angle away from the normal, passes a boundary from one medium into another in which there is a change in velocity of the light
I need help please I will give points
Answer:
-5 N of force
Explanation:
Hope it helps!
Match each term with the appropriate definition.
mass
the amount of matter in an object
balance
the downward pull on an object due to
gravity.
weight
a tool used to measure weight
scale
a tool used to measure mass
Answer:
mass- the amount of matter in an object
balance- tool used to measure mass
scale- a tool used to measure weight
weight- the downward pull on an object due to gravity
Nina's measurements, shown in the table here, BEST represent a wave with
A)
decreasing frequency.
B)
increasing frequency.
C)
increasing amplitude.
D)
decreasing amplitude.
Nina's data in this table most accurately depict a wave with decreasing frequency. Option A is right.
What is frequency?A recurring event's frequency is measured by how many times it occurs in a unit of time.
To emphasize distinctions with spatial and angular frequencies, respectively, it is also sometimes referred to as ordinary frequency or temporal frequency.
If the duration, or time interval, required to complete one cycle or vibration is half a second, the frequency is 2 per second; if it is one hundredth of an hour, the frequency is 100 per hour.
The frequency and period, or time interval, are often reciprocally equal, therefore frequency = 1/period = 1 in most circumstances.
The Moon rotates about Earth about a little bit more than 12 times a year. In a violin A string vibrates at a frequency of 440 cycles per second.
Thus, the correct option is A.
For more details regarding frequency, visit:
https://brainly.com/question/5102661
#SPJ5
If the boy travelled 2 meters to the right and 4 meters to the left what is the total distance that he travelled?
4 m
-4 m
6 m
2 m
Answer:
6m
Explanation:
2+4=6
2. Arrange the following types of electromagnetic waves in order by wavelength, from longest to
shortest: Gamma rays, visible light, infrared radiation, ultraviolet radiation, microwaves, radio
waves, X-rays
Answer:
Radiowaves > microwaves> Infrared radiation > visible light > Ultraviolet radiation > x -rays > gamma rays
Explanation:
To solve this problem, we use the electromagnetic spectrum as a reference. On the electromagnetic spectrum, the lesser the wavelength, the higher the frequency and more energetic a wave is.
Therefore;
Radiowaves > microwaves> Infrared radiation > visible light > Ultraviolet radiation > x -rays > gamma rays
So, radiowaves have the longest wavelength and gamma rays have the shortest.
Answer:
Radio, microwave, infrared radiation, visible light, ultraviolet radiation, x-rays and gamma rays.
Explanation:
These electromagnetic waves are arranged from longest to shortest wavelengths.
Have an amazing day!
Test populations are studied. Population one is found to obey the differential equation dy1/da=o.2y1 and the population two obeys dy2/da = -0.3y2 , where t is the time in years? Which population is growing and which is declining
Answer:
Population 1 indicates growth while Population 2 indicates a declining population
Explanation:
Here, using the given rate of change of the population, we want to determine which of the two is growing and which is declining
From the rate of change of both, we can determine this. Looking at the differential equation for the first one, we can see that it is of positive value. Looking at the differential equation for the second one. we can see it is of negative value
While a positive change rate indicates growth, a negative change rate will indicate otherwise
Hence, we can conclude that the one with a negative rate change will indicate a declining population
Please help I’ll give you brain
Answer:
Explanation:
distance (km)
a) As near as I can tell from the graph, the distance travelled was 4km
b) I would answer 40 minutes, but don't be surprised if your instructor says 30 minutes.
c) The average speed is 4 km/40 minutes = 0.1 km/minute
If Bert the Bat travels East at 200 meters in 10 seconds, what is his velocity?
Answer:
20m/s due east
Explanation:
Given parameters:
Displacement eastward = 200m
Time = 10s
Unknown:
Velocity = ?
Solution:
Velocity is the displacement divided by time;
Velocity = [tex]\frac{displacement}{time}[/tex]
Velocity = [tex]\frac{200}{10}[/tex] = 20m/s due east
If the mass of an object increases, then its kinetic energy will ____________ because __________________________
Answer:
when mass will increase then kinetic energy will also increase because both have positive relationship
Explanation:
when volume increase then molecule come closer then more movement will occurs and kinetic energy increase
Two spheres have a gravitational force between
them of 45 N. If the distance between the masses
is increased to 4.0 times its original distance, what
is the new force?
Answer:
The new force is 2.8125 N
Explanation:
Newton’s Law of Universal Gravitation
Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.
[tex]\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Where:
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects' center of masses
G = gravitational constant: 6.67\cdot 10^{-11}~Nw*m^2/Kg^2
Suppose two spheres have a gravitational force between them of F = 45 N. Now increase the distance to r'=4r. The new force F' is:
[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{(4r)^{2}}}[/tex]
[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{16r^{2}}}[/tex]
[tex]\displaystyle F'=\frac{1}{16}\ G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Substituting the original value of the force:
[tex]\displaystyle F'=\frac{1}{16}\ 45 N[/tex]
F' = 2.8125 N
The new force is 2.8125 N
Which two life functions of animals help maintain the water cycle by recycling water back into the environment?
Answer:
Respiration and excretion
Explanation:
Respiration. When animals breathe, their lungs release water vapour to the atmosphere.
Animals excrete water by respiration and by passing urine.
Will mark brainliest Why are acoustic panels are used in concert halls
Answer:
what person above said is correct
Explanation:
The walls of the concert halls are used to control the acoustic. ... Rough surfaces can also be used to disperse sound in all directions – this might be used in concert halls to get rid of echoes that would distract from performances.
An acoustic panel is a sound-absorbing panel used to mitigate noise and reduce the reverberation and echo in a space. For both types, we can talk about different principles of good acoustics: absorption, diffusion, and attenuation. These are all linked to the acoustic performance of the panels.
brainliest?When one end of a metal bar is heated, the opposite end will eventually become hot. Which of the following processes transfers the heat through the bar?
Group of answer choices
condensation
radiation
convection
conduction
Question 17 of 25
A sound wave from a brass bell passes through the air with a
wavelength of 3.5 m. When the sound wave originated in the
brass bell, its wavelength was 47 m. If the sound wave has a
constant frequency of 100 Hz, what was its speed as it
traveled through the brass bell? (The equation for wave speed
is v= f*1.)
A. 3,500 m/s
B. 4,700 m/s
C. 350 m/s
D. 470 m/s
Answer:
The speed of the wave as it travelled through the brass bell is;
B. 4,700 m/s
Explanation:
The given parameters are;
The wavelength of the sound wave produced from the brass bell, [tex]\lambda _{(air)}[/tex] = 3.5 m
The wavelength of the wave in the brass bell, [tex]\lambda _{(brass \ bell)}[/tex] = 47 m
The frequency of the wave in the brass bell, f = 100 Hz
The given equation for wave speed, v = f × λ
Therefore, the speed of the wave as it travelled through the brass bell, [tex]v _{(brass \ bell)}[/tex], is given as follows;
[tex]v _{(brass \ bell)}[/tex] = f × [tex]\lambda _{(brass \ bell)}[/tex] = 100 Hz × 47 m = 4,700 m/s
The speed of the wave as it travelled through the brass bell = [tex]v _{(brass \ bell)}[/tex] = 4,700 m/s
Answer:
B.) 4700 m/s
Explanation:
explain how balanced and unbalanced forces effect an objects motion differently
Answer:
Balanced Forces will not change the object's motion.
Unbalanced Forces will change the object's motion.
Explanation:
please answerrr asapp tyty Laura goes for cycle from her house to the post office 4km away how long did it take for Laura to reach the post office
Answer:
See the answer below
Explanation:
The time Laura took to reach the post office would depend on the speed of cycling.
We know that;
speed = [tex]\frac{distance}{time}[/tex]
hence,
time = [tex]\frac{distance}{speed}[/tex]
Since the distance from Laura's house to the post office is 4 km, the equation becomes;
time = [tex]\frac{4}{speed}[/tex]
Just ensure that the speed is in km per hour, minute, or seconds in order to obtain the time in hours, minutes, or seconds respectively.
Hi!! Does anyone know this answer? :D
Answer:
Im not fully corrrect but I would say C
Explanation:
1. A kangaroo hops 84 m to the east in 7 seconds.
o What is the kangaroo's speed? 12 m/s
o What is the kangaroo's velocity?
Explanation:
Given parameters:
Distance hopped = 84m
Displacement = 84m due east
Time = 7s
Unknown:
Speed of kangaroo = ?
Velocity of kangaroo = ?
Solution:
To solve this problem,
Speed = [tex]\frac{distance}{time }[/tex] = [tex]\frac{84}{7}[/tex] = 12m/s
Velocity = [tex]\frac{displacement}{time}[/tex] = [tex]\frac{84}{7}[/tex] = 12m/s due east
a train has an initial velocity of 44m/s and an accelaration of _4m/s calculate its velocity
Answer:
It's 4m/s
Explanation:
V = u _ at, at u = 44m/s
44 + [-4]10
4m/s
.A water tank has dimensions
of 6m x 4m x 4m. Find the pressure exerted by
water at the base of dam when it is half
filled. ( Density of water - 1000 kg/ m2,
acceleration
due to to gravity is 9.8m/s2
Answer:
9800Nm⁻²
Explanation:
Given parameters:
Dimensions of the water tank = 6m x 4m x 4m
Density of water = 1000kgm⁻³
Gravity = 9.8m/s²
Unknown:
Pressure exerted by the water at the base of the dam = ?
Solution:
The pressure exerted by the water is given as:
Pressure = density of water x acceleration due to gravity x height of water
The height of the water here is half = 1m
Pressure = 1000 x 9.8 x 1 = 9800Nm⁻²
Please what is the work done by a man who is pulling a box of 45kg of mass by means of rope which makes angle of 45 degrees ?
Answer:
No work is done since no distance is given
Explanation:
Since no distance is given, the force is not doing any work
No work is done by the man since we do not know the distance or displacement.
Work is only said to be done when the force applied on an object moves it through a particular distance.
Work done = Force x distance.
Since no distance is given in this problem, we can as well assume that the force applied is doing no work on the object.
What is the volume of a liquid in a 50 mL cup?
A. 50mL
B. 10mL
C. There is not enough information to answer this question.
Answer:
there is not enough information
A sample of gas in a syringe releases heat to its surroundings while the
plunger is pulled out. What are the correct signs of heat and work for this
change?
A. +Q+W
B. --W
O C. +Q, -W
D. -Q. +W
Answer: b
Explanation:
When heat is released by the system i.e. system loses heat. So, we take it as negative -Q
When the work is done on the system then it is considered as negative work on the system i.e. -W
In this case, the plunger is pulled out, and work is done on the system. So, we take work as negative work -W
Correct option is b
The answer is D.
-Q +W
How much force is needed to accelerate 250 kg at a rate of 6 m/s/s?
Answer:
[tex]1500 \: \mathrm{N}[/tex]
Explanation:
The equation [tex]F=ma[/tex] represents the force needed.
Plugging in [tex]m=250[/tex] and [tex]a=6\: \mathrm{m/s^2}[/tex], we find that the force needed to accelerate a 250 kg object at a rate of [tex]6 \: \mathrm{m/s^2}[/tex] to be [tex]\fbox{$1500 \: \mathrm{N}$}[/tex].
Please help me this is worth allot
PLEASE HELP ASAP!!!!!
Carrie pulls a 41.5 kg bin across the floor of her garage using a rope that is attached to the bin. She pulls with a force of 138 N, at an angle of 28.0° above horizontal. The coefficient of kinetic friction between the floor and the box is 0.290 . What is the acceleration of the box?
Answer: 0.81N
Explanation: Fwx = .165x 9.81 Silicon 30 = 0.81N