A person needs $
4500 to visit foreign countries. If $ 1 = NRs. 120.92 and the bank charge 2% as onmmission, bow many Nepali rupees does the person require to exchange $4500? Find it.​

Answer:

x=2

Step-by-step explanation:

Vertical angles are equal.

5x+1=4x+3

   -1        -1

5x=4x+2

-4x -4x

1x=2

x=2

The value of x is 2.

5(2)=4(2)+2

10=8+2

10=10

Hope this helps.

Answer:

0,-1 , -2 ,-3 ,-4 ,-5

Step-by-step explanation:

i think this is the answer but i can't confirm because your theory and my theory can be different

let me know if this was helpful

a) The greatest number of gift boxes that can be put together is 4.

b) Number of mint chocolate in gift box =  5

    Number of caramel pecan bars in gift box = 6

Highest common factor or greatest common factor of two number is the greatest factor that divides the numbers.

According to the question we have been given that

   number of  mint chocolate = 20

   number of caramel pecan bars = 24

a) We have to find the greatest number of gift boxes. For that we will find H.C.F of 20 and 24.

Factors of 20 = 2 * 2 * 5

Factors of 24 = 2 * 2 * 2 * 3

The H.C.F is 4 as it is the greatest that divides the two numbers.

Thus the greatest number of gift boxes that can be put together is 4

b) Number of mint chocolate in gift box = 20/4 = 5

    Number of caramel pecan bars in gift box = 24/4 = 6

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The width of rectangle is 20 cm

As is seen in the picture, there are 6 squares at the length of rectangle and 4 squares at the width of rectangle. Also, as per the known fact, each side of square is same. So, we will find the side of square to calculate width of rectangle.

Length of rectangle = 6 × side of square

Side of square = 30 ÷ 6

Side of square = 5 cm

Width of rectangle = 4 × side of square

Width of rectangle = 4 × 5

Width of rectangle = 20 cm

Hence, the width of rectangle is 20 cm.

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The value of the partial sum of geometric sequence with terms a3 = 36 and a6 = 288 is given by 297. This is obtained by using the concept of partial sum of a geometric progression.

What is geometric progression?

Geometric progression is defined as a series of numbers having a fixed ratio between each term and its preceding term. It is also known as a geometric sequence or G.P., and is exemplified as a1, a2, a3, ….., an

Here, the first term is denoted by a1 and its common ratio is shown by r, which is calculated using the formula a2 by a1. The partial sum of a G.P. is given by a1 ( rn - 1 ) / ( r - 1 ), when r > 1 and a1 ( 1 - rn ) / ( 1 - r ), when r < 1

Calculation of the partial sum of the geometric sequence that satisfies the given conditions. a3 = 36, a6 = 288, n = 5

Given:

Value of a3 = 36

Value of a6 = 288

n = 5

a3 = ar2           — 1

a6 = ar5

Now, a6 / a3 = ar5 / ar2 = 288 / 36

r3 = 8

Taking cube root both sides, we get,

r = 2

Putting the value of r in equation 1,

a3 = a(2)2

36 = 4a

a = 9

As r > 1, using the formula for Sn as a(rn - 1) / (r - 1)

Sn = 9(2n - 1) / (2 - 1)

Sn = 9(2n - 1)

Using n = 5, we have,

Sn = 9[(2)5 - 1]

Sn = 9(32 - 1)

Sn = 9 × 33

Sn = 297

Hence, the value of the partial sum of a G.P. is 297

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Answer:

2.5 60÷24=2.5 so there is ur answer hope it helps

Using the z-distribution, it is found that mean weights less than 135.1g and more than 144.9 would lead to a rejection of the hypothesis.

We have a two-tailed test, with a significance value of α = 0.05, hence, using a z-distribution calculator, the critical value is given by:

|z| = 1.96 -> z < -1.96 or z > 1.96.

The test statistic is given as follows:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which:

For this problem, the parameters are given as follows:

[tex]\mu = 140, \sigma = 15, n = 36[/tex]

The lower bound of acception is found as X when z = -1.96, hence:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

-1.96 = (X - 140)/(15/6)

-1.96 = (X - 140)/(2.5)

X - 140 = -1.96 x 2.5

X = 135.1.

The upper bound of acception is found as X when z = 1.96, hence:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

1.96 = (X - 140)/(15/6)

1.96 = (X - 140)/(2.5)

X - 140 = 1.96 x 2.5

X = 144.9.

Hence:

Mean weights less than 135.1g and more than 144.9 would lead to a rejection of the hypothesis.

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Answer:

10+ 7 is equal to 17 cube is the answer

she made an error in the third step. The correct answer is - 9.7b + 25

(-4.23b + 13) - (5.47b - 12)

Therefore, let's open the bracket on the right side.

-4.23b + 13 - 5.47b + 12

Hence, let's combine the like terms

-4.23b + 13 - 5.47b + 12

-4.23b - 5.47b + 12 + 13

Do the arithmetic of the like terms

-4.23b - 5.47b + 12 + 13

- 9.7b + 25

Therefore, she made an error in the third step.

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The standard form of the given number is  (5 × 10⁻³)/6.

The standard form of 0.005/6 is:

Therefore, the standard form of the given number is  (5 × 10⁻³)/6.

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Answer: itll be less than 3/4 pound

Step-by-step explanation:

the amount of watermelon would be 1.5/4 or 3/8. this is because all of the recipe would be divided by 2

Answer:

less than 3/4 pound

Step-by-step explanation:

Answer: 4 − 1 = 3

Step-by-step explanation: 6 - 2 = 4    32 + 42 = 25    4 − 1 = 3

Answer:

Hello,

Step-by-step explanation:

I can only explain in mathematics not in English (i am French).
c: number of customers

n: number of good reviews

k: factor of proportionality

1)

p=k*c*n

15000=k*75*100 ==> k=2

if c=250 and n=150 then p=2*250*150=75000

2)

A=b*a/2 since b= 9 and a=4 then 9*4/2=18 (cm²)

A=4*7/2=14 (cm²)

Answer: D) 794

Step-by-step explanation:

[tex]10lgI=29[/tex]

Divide both parts of the equation by 10:

[tex]lgI=2.9\\\\I=10^{2.9}\\\\I\approx794[/tex]

A) The expression for the number of tires used to make x lane-miles of asphalt rubber is y = 2000x.

B) The number of tires used to make 11, 50, and 150 lane-miles of asphalt rubber are as follows:

y =  22000

y = 100000

y = 300000

Approximately 2000 tires are recycled to produce one lane-mile of asphalt rubber.

Therefore, an expression for the number of tires used to make x lane-miles of asphalt rubber is as follows:

y = 2000x

where;

x = number of lanes-miles

y = number of tires

Therefore, the number of tires used to make 11, 50, and 150 lane-miles of asphalt rubber are as follows:

y = 2000(11) = 22000

y = 2000(50) = 100000

y = 2000(150) = 300000

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Complete question is;

Approximately 2000 tires are recycled to produce one lane-mile of asphalt rubber.

A.Write an expression for the number of tires used to make x lane-miles of asphalt rubber.

B. Find the number of tires used to make 11, 50, and 150 lane-miles of asphalt rubber.

Answer:

9.3

Step-by-step explanation:

9.3 squared = 86.49

9.8 squared =  96.04

8.5 squared = 72.25

10.1 just gonna be higher

The calculation that estimates the primary macronutrient the body uses for energy at any given point in time is the Catabolic quotient.

The Catabolic quotient is used to show the amount of macronutrients that are being catabolized to produce energy at any given time.

This allows us to know how much macronutrients the body needs depending on the activities that a person is engaged in at the time. This is important for nutritional requirements as a result.

Options for this question are:

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Answer: 13

Step-by-step explanation:

an=a(n-1)+1

a1=10

a2=

a(2-1)+1=

a1+1=

10+1=11

a3=

a2+1=

11+1=12

a4=

a3+1=

12+1=13

a4=13

Answer:

a = 3 , b = - 2

Step-by-step explanation:

5a + b = 17 → (1)

3a + 2b = 5 → (2)

multiplying (1) by 2 and adding to (2) will eliminate b

10a + 2b = 34 → (3)

add (2) and (3) term by term to eliminate b

13a + 0 = 39

13a = 39 ( divide both sides by 13 )

a = 3

substitute a = 3 into either of the 2 equations and solve for b

substituting into (1)

5(3) + b = 17

15 - b = 17 ( subtract 15 from both sides )

- b = 2 ( multiply both sides by - 1 )

b = - 2

then solution is a = 3 , b = - 2

Answer:

SOLVE FOR X

x∈[−7,8)

step explanation:

there is no solve for x just straight answer

The mean of the data set is 37.30

Given that

            29, 38, 39, 26, 29, 29, 39, 77, 38, 29

To find

So, according  to the question

We have,

So, we know that

               mean = [tex]\frac{sum\;of\;\;data}{number\;of\;data}[/tex]

                   ∑ Ta =  29+ 38+ 39+ 26+ 29+ 29+ 39+ 77+ 38+ 29

                   ∑ Ta =  373

                     Tn =  10        

Now, The Mean of teachers ages

                     Tm =  [tex]\frac{sum\;of\;the\;teachers\;ages}{number\;of\;teachers}[/tex]

                     Tm =  [tex]\frac{T_a}{T_n}[/tex]

                            =  [tex]\frac{373}{10}[/tex]

                     Tm  =  37.30

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Multicollinearity refers to the degree of correlation among independent variables in a regression model.

In a multiple regression model, one predictor variable can be predicted linearly from the others using a high degree of accuracy when there is a phenomenon known as multicollinearity (also known as collinearity). In this case, minor adjustments to the model or the data may cause the multiple regression's coefficient estimates to fluctuate unpredictably. Multicollinearity only impacts calculations pertaining to specific predictors; it has no impact on the predictive capability or reliability of the model as a whole, at least within the sample data set. In other words, a multivariate regression model with collinear predictors can show how well the complete set of predictors predicts the outcome variable, but it could not provide accurate information about any particular predictor or which predictors are redundant in relation to others.

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The possible triples are: (3, 3, 3), (4, 2, 4) as seen by counting theorem.

Now, by the counting principle,

Hence, the possible triples are: (3, 3, 3), (4, 2, 4).

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Answer:

2,200,000=2.2x10^6

Step-by-step explanation:

Answer:

The Last box. (y=1/2x-4)

Step-by-step explanation:

The formula is y=mx+b
b is the interception point on the y axis.
So the -4 is where the line crosses on the y axis.
mx is how many spaces it goes up or down.
If you look the box goes up or down twice then left or right once.

So that's your answer, hope this helps.