During the spring, Mr. Salina's grass grows at a rate of 1.5 inches per week. During a rainy stretch in the summer, his grass grew a total of 8 inches in 4 weeks.
Based on the growth rate of Mr. Salina's grass per week in the summer, and in spring, the relationship is not proportional.
How are relationships proportional?When relationships are said to be proportional, it means that they increase or decrease by the same rate.
In the spring, Mr. Salina's grass grows at a rate of 1.5 inches per week.
In the rainy stretch of summer, this rate goes to:
= Total number of inches / Number of weeks
= 8 / 4
= 2 inches per week
This means that the relationship is not proportional and one rate is higher than the other.
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The radius of a circle is 8 inches. What is the area?Give the exact answer in simplest form. _____ square inches. (pi, fraction)
Given:
Radius of circle is 8 inches.
The objective is to find the area of the circle.
The formula to find the area of the circle is,
[tex]\begin{gathered} A=\pi r^2 \\ =\pi\times8\times8 \\ =64\pi \\ =201in^2 \end{gathered}[/tex]Hence, the area of the circle is 201 square inches.
The line 3x + 4y - 7 = 0 is parallel to the line k . x + 12y + 3 = 0. What is the value of k?
The function is solved below
What is a function?
The function is instantly given a name, such as a, in functional notation, and its description is supplied by what it does to the input x, using a formula in terms of x. Instead of sine, put sine x. (x). Leonhard Euler invented functional notation in 1734. Some commonly used functions are represented with a symbol made up of many letters (usually two or three, generally an abbreviation of their name). In this scenario, a roman font is typically used, such as "sine" for the sine function, rather than an italic font for single-letter symbols. A function is also known as a map or a mapping, however some writers distinguish between "map" and "function."
The function can be written as
3x+4y-7 = 0
or, y = (-3/4)x + 7/4
so, slope = -3/4
and other function is
kx+12y+3 = 0
or, y = (-k/12)x - 1/4
so, slope = -x/12
Given the lines are parallel, so slopes are equal
i.e., -3/4 = -k/12
or, k = (3/4)12 = 9
Hence, the value of k is 9.
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There is one male snake, and the rest are female. She needs one vitamin pill for every female snake. How many vitamin pills does she need if the number of snakes is: a. 10b. 6C. X
We are told that there is one male snake, and the rest are female.
She needs one vitamin pill for every female snake.
1. If there are 10 snakes, this means that if one is male, the number of female snakes are:
[tex]10-1=9\text{ females}[/tex]Sine one vitamin pill is needed for each female snake, she would need 9 vitamin pills.
2. If there are 6 snakes, this means that if one is male, the number of female snakes are:
[tex]6-1=5\text{ females}[/tex]Sine one vitamin pill is needed for each female snake, she would need 5 vitamin pills.
3. If there are X snakes, this means that if one is male, the number of female snakes are:
[tex]X-1=(X-1)\text{ females}[/tex]Sine one vitamin pill is needed for each female snake, she would need (X-1) vitamin pills.
im not sure the steps to this math problem, from step one to step three
The equation of the second line is written in standard form. To know the slope of this line, we can rewrite its equation in slope-intercept form by solving for y.
[tex]\begin{gathered} ax+by=c\Rightarrow\text{ Standard form} \\ y=mx+b\Rightarrow\text{ Slope-intercept form} \\ \text{ Where m is the slope and b is the y-intercept} \end{gathered}[/tex]Then, we have:
[tex]\begin{gathered} 4x-5y=-10 \\ \text{ Subtract 4x from both sides of the equation} \\ 4x-5y-4x=-10-4x \\ -5y=-10-4x \\ \text{Divide by -5 from both sides of the equation} \\ \frac{-5y}{-5}=\frac{-10-4x}{-5} \\ y=\frac{-10}{-5}-\frac{4x}{-5} \\ y=2+\frac{4}{5}x \\ \text{ Reorganize} \\ y=\frac{4}{5}x+2 \\ \text{ Then} \\ $$\boldsymbol{m=\frac{4}{5}}$$ \end{gathered}[/tex]Now, two lines are perpendicular if their slopes satisfy the following equation:
[tex]\begin{gathered} m_1=-\frac{1}{m_2} \\ \text{ Where }m_1\text{ is the slope of the first equation and} \\ m_2\text{ is the slope of the second equation} \end{gathered}[/tex]In this case, we have:
[tex]\begin{gathered} m_2=\frac{4}{5} \\ m_1=-\frac{1}{\frac{4}{5}_{}} \\ m_1=-\frac{\frac{1}{1}}{\frac{4}{5}_{}} \\ m_1=-\frac{1\cdot5}{1\cdot4} \\ $$\boldsymbol{m}_{\boldsymbol{1}}\boldsymbol{=-\frac{5}{4}}$$ \end{gathered}[/tex]Step 2Since we already have a point on the line and its slope, then we can use the point-slope formula:
[tex]\begin{gathered} y-y_1=m(x-x_1)\Rightarrow\text{ Point-slope formula} \\ \text{ Where } \\ m\text{ is the slope and} \\ (x_1,y_1)\text{ is a point through which the line passes} \end{gathered}[/tex]Then, we have:
[tex]\begin{gathered} (x_1,y_1)=(6,3) \\ m=-\frac{5}{4} \\ y-3=-\frac{5}{4}(x-6) \\ \text{ Apply the distributive property} \\ y-3=-\frac{5}{4}\cdot x-\frac{5}{4}\cdot-6 \\ y-3=-\frac{5}{4}x+\frac{5}{4}\cdot6 \\ y-3=-\frac{5}{4}x+\frac{30}{4} \\ \text{ Add 3 from both sides of the equation} \\ y-3+3=-\frac{5}{4}x+\frac{30}{4}+3 \\ y=-\frac{5}{4}x+\frac{30}{4}+\frac{12}{4} \\ y=-\frac{5}{4}x+\frac{30+12}{4} \\ y=-\frac{5}{4}x+\frac{42}{4} \\ \text{ Simplify} \\ y=-\frac{5}{4}x+\frac{21\cdot2}{2\cdot2} \\ y=-\frac{5}{4}x+\frac{21}{2} \end{gathered}[/tex]Step 3Therefore, the equation of the line that passes through the point (6,3) that is perpendicular to the line 4x - 5y = -10 is
[tex]$$\boldsymbol{y=-\frac{5}{4}x+\frac{21}{2}}$$[/tex]How is the input force different from the output force?
Responses
The input force is all of the energy applied to the situation, and the output force is the result.
The input force is all of the energy applied to the situation, and the output force is the result.
The input force is applied to the problem, and the output force is the movement that results.
The input force is applied to the problem, and the output force is the movement that results.
The output force is applied to the simple machine, and the input force is the force the simple machine applies to an object.
The output force is applied to the simple machine, and the input force is the force the simple machine applies to an object.
The input force is applied to the simple machine, and the output force is the force the simple machine applies to an object.
The input force is applied to the simple machine, and the output force is the force the simple machine applies to an object.
The input force different from the output force is D. The input force is applied to the simple machine, and the output force is the force the simple machine applies to an object."
What is a simple machine?A simple machine is a mechanical device that alters the magnitude or direction of a force. In general, they are the most basic systems that exploit mechanical advantage to multiply force.
A simple machine is a mechanical device that adjusts the direction or amplitude of a force. According to Newton's third law, if object A exerts a force on object B, object B will exert a force of same size and opposite direction on object A.
In that situation, the input force is done by object A, and the output force is done by object B as a reaction.
With this in mind, we can see that the proper answer is: "The input force is applied to the simple machine, and the output force is the force applied to an item."
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Solve the given quadratic inequality. Write the answer in interval notation.
A random variable X follows a normal distribution with a mean of 150 and a standard deviation of sigma. If we know that P(120 < X < 180) = 0.95, then, according to the 68-95-99.7 rule, the value of sigma is approximately:
a.
20
b.
15
c.
40
d.
30
e.
60
The value of sigma according to the 68-95-99.7 rule is 15.
What is the 68-95-99.7 rule?This is the informal term that is used in statistics to remember the percentage of values that are in the interval of a distribution in statistics.
We have the mean = 150
the interval is given as P(120 < X < 180)
based on this rule, 95 percent of the data lies in the u - 20 and u + 20 region
Such that we would have
u - 2α < x < u + 2α = 0.95
we have
u - 2α = 120
150 - 2α = 120
2α = 150 - 120
2α = 30
divide through by 2
α = 15
Sigma is given as 15
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Please see the picture below,PART BUse the real zeros to factor f
Explanation:
The polynomial is given below as
[tex]f(x)=x^4+2x^3-7x^2-8x+12[/tex]Given in the question above the real zeros are gotten below as
[tex]x=-3,-2,1,2[/tex]Concept:
To figure out the factor form of the polynoimial, we will equate each zero to x below as
[tex]\begin{gathered} x=c \\ (x-c) \end{gathered}[/tex]Therefore,
The factored form of the polynomial will be
[tex]\begin{gathered} f(x)=x^{4}+2x^{3}-7x^{2}-8x+12 \\ x=-3,x=-2,x=1,x=2 \\ f(x)=(x+3)(x+2)(x-1)(x-2) \end{gathered}[/tex]Hence,
Using the real zeros of f(x) , the factored form of the polynomial is
[tex]\Rightarrow f(x)=(x+3)(x+2)(x-1)(x-2)[/tex]For which value(s) of x will the rational expression below equal zero? Che all that apply. (x - 5)(x+2) x + 1 A.-5 B. 2 c. 1 1 D. -1 E. 5 F. -2
The rational expression we have is:
[tex]\frac{(x-5)(x+2)}{x+1}[/tex]For a rational expression to be equal to 0, the numerator of the expression has to be equal to 0.
The numerator is: (x-5)(x+2)
That has to be equal to 0:
[tex](x-5)(x+2)=0[/tex]Here, we apply the zero product property, which tells us that if a product is equal to 0, one of the two elements, or the two elements, are equal to 0:
[tex]\begin{gathered} x-5=0 \\ x+2=0 \end{gathered}[/tex]We solve the two equations, and get the two values that will make the rational equation equal to 0:
[tex]\begin{gathered} x=5 \\ x=-2 \end{gathered}[/tex]Answer:
E. 5
F. -2
Given the formula for the nth term, state the first 5 terms of each sequence.t1= 800, tn= -0.25tn-1
In this case, we'll have to carry out several steps to find the solution.
Step 01:
data:
t1 = 800
tn = - 0.25 tn-1
Step 02:
sequence:
t1 = 800
t2 = -0.25 (800) = - 200
t3 = -0.25 (-200) = 50
t4 = -0.25 (50) = -12.5
t5 = - 0.25 (-12.5) = 3.125
The answer is:
t1 = 800
t2 = - 200
t3 = 50
t4 = -12.5
t5 = 3.125
Cobalt-60 has a half-life of about 5 years. After 20 years, how many grams of a2,076 gram sample will remain? Round to the hundredths place, if answer doesn'thave a tenths place then use a zero so the answer does.
Solution:
The formula for half-life is given below as
[tex]N(t)=N_0(\frac{1}{2})^{\frac{t}{\frac{t1}{2}}}[/tex]Where the given values are
[tex]\begin{gathered} N_0=2076g \\ t=20years \\ t^{\frac{1}{2}}=5years \end{gathered}[/tex]By substituting the values, we will have
[tex]\begin{gathered} N(t)=N_{0}(\frac{1}{2})^{\frac{t}{\frac{t\times1}{2}}} \\ N(t)=2076\times(\frac{1}{2})^{\frac{20}{5}} \\ N(t)=2076\times(\frac{1}{2})^4 \\ N(t)=\frac{2076}{16} \\ N(t)=129.75g \end{gathered}[/tex]Hence,
The final answer is
[tex]\Rightarrow129.75g[/tex]Pls help me with this I will give brainless thank u <3
15.sum,neg
16.sum,neg
17.diff,neg
18.sum,neg
19.sum,pos
20.neg
21.pos
22.neg
23.pos
24.neg
Consider the following system of equations.ſ x - 4y = -34x - 2y = -12Step 2 of 2: Determine if the point (3, 1) lies on both of the lines in the system of equations by substituting theordered pair into both equations.
Given:
x - 4y = -3
4x - 2y = -12
To determine if the point (3, 1) lies on both of the lines in the system of equations:
Substitute (3, 1) in the first equation, we get
3 - 4(1) = -3
3 - 4 =-3
-1 = -3
But,
[tex]-1\ne-3[/tex]Substitute (3, 1) in the second equation, we get
4(3) - 2(1) = -12
12 - 2 = -12
10 = -12
But,
[tex]10\ne-12[/tex]Hence, the answer is, No.
The point (3, 1) does not lie on both of the lines in the system of equations.
Assume your salary is $24,000 per year and $50 for each computer you sell. What function represents your total pay for one year? Be sure to indicate any domain restrictions.
Let x represent the total amount of computers you sell in one year.
Since you get $50 for each computer, then, you would get 50x for x computers.
Additionally, your base salary is $24,000. Then, add 50x and 24,000 to find your total salary in a year.
If f(x) is a function that represents your salary depending on the amount of computers you sell, then:
[tex]f(x)=50x+24000[/tex]Notice that the amount of computers that you sell cannot be a negative number. Then, you must take into account the following restriction:
[tex]x\ge0[/tex]Therefore, the answer is:
[tex]f(x)=50x+24000\text{ for }x\ge0[/tex]At Joe's Café 1 cup of coffee and 3 doughnuts cost $7.54, and 2 cups of coffee and 2 doughnuts cost $8.32. What is thecost of 1 cup of coffee?
To answer this question, we can proceed as follows:
1. Let x be the cost of a cup of coffee.
2. Let y be the cost of a doughnut.
Then, we can express the question, algebraically, as follows:
[tex]\begin{cases}x+3y=7.54 \\ 2x+2y=8.32\end{cases}[/tex]Now, we can solve this linear equation system by
How do I graph a line with a equation in slope intercept form?An example is y=-3x+3, how do I graph this?
we have
y=-3x+3
to graph a line we need at least two points
so
Find out the intercepts
y-intercept (value of y when the value of x is zero)
For x=0
y=-3(0)+3
y=3
y-intercept is (0,3)
x-intercept (value of x when the value of y is zero)
For y=0
0=-3x+3
3x=3
x=1
x-intercept is (1,0)
therefore
Plot the points (0,3) and (1,0)
and join them to graph the line
see the attached figure to better understand the problem
A cat is stuck in the tree and the fire department needs a ladder to rescue the cat. The fire truck available has a 95-foot ladder, which starts 8 feet above ground. Unfortunately, the fire truck must park 75 feet away from the tree. If the cat is 60 feet up the tree, does the cat get rescued? If not, what ladder length is need to allow the cat to be rescued?
SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Draw the given scenario
STEP 2: Describe how to answer the question
The question forms a right angle triangle. where the height of the cat on the tree is the opposite side of the triangle. The distance between the cat and the tree is the adjacent side of the triangle .
Recall the 95 foot ladder can only start 8 feet above the ground .The diagram is represented above:
The ladder height should be the hypotenuse of the triangle.
using Pythagoras's theorem,
[tex]hypotenuse^2=opposite^2+adjacent^2[/tex]STEP 3: Write the given sides
[tex]\begin{gathered} adjacent=75fto \\ opposite=52ft \\ hypotenuse=x\text{ ft} \end{gathered}[/tex]STEP 4: find x
[tex]\begin{gathered} x^2=75^2+52^2 \\ x^2=5625+2704 \\ x^2=8329 \\ x=\sqrt{8329}=91.26335519 \\ x\approx91.26ft \end{gathered}[/tex]The expected length of the ladder should be approximately 91.26ft. Since the ladder is 95 foot, therefore the cat will be rescued with the given ladder.
32. Challenging. Read this one very carefully. Carla runs a small business where she makes artificial flower arrangements. A customer has placed a large order for 100 identical arrangements. Carla has made a list of supplies that she needs to make the entire order. Each arrangement needs a plastic molding. It will cost Carla $3.25 for each plastic molding. She also needs 4 packages of colored netting, which sell for $15.00 each. However, the company she orders from has a special on the netting packages. If you buy 3 packages of netting, you get a package for free. Polyester fabric is another item she will need. She needs 180 square feet of polyester fabric that sells for $5.20 per square yard. Lastly she needs artificial stems. She will need 6 stems per arrangement and they are sold in packs of 10. The cost for one pack of artificial stems is $2.50. if Carla sells each arrangement for $20.00,How much money will Carla make off the order once she subtracts her expenses for the supplies.
Substract expenses
Carlas expenses are
1. 100 Arrangements
2. Plastic molding PM = 3.25
3. Colored netting CN = 15
4. Four packages netting = 3 packages
5. 180 feet2 ,. 1 yard2=5.20
6. 10 stems = 2.5x10 = $25
7. Arrangement price AP = 20.00
Then substract
20 minus 3.25 = 16.75
16.75 x100= $1675
4. 4 packages nettingx 15 = $60 - $15 = $45
5. Now
In 180 feet2 ,there are 60 yards2
then polyester price is 60x5.2= $312
6. She needs 100x6= 600 stems
600/10 = 60 packs
60 packs x 2.50= $150
Then answer is
Carla's money = 1675 - 45 - 312 - 150 = $1168 dollars
Need help with a math word problem for homework. Thank you in advance
Given:
A client is making a 10-lb bag of trail mix
The chocolates cost $4 per pound and mixed nuts cost $7 per pound
the client has a budget of $6.1 per pound
We will use the variables c and n to represent the number of pounds for chocolates and nuts
So, we have the following system of equations:
[tex]\begin{gathered} c+n=10\rightarrow(1) \\ 4c+7n=6.1\cdot10\rightarrow(2) \end{gathered}[/tex]Solving the system by substitution method
From equation (1)
[tex]c=10-n\rightarrow(3)[/tex]substitute with (c) from equation (3) into equation (2)
[tex]\begin{gathered} 4(10-n)+7n=6.1\cdot10 \\ \end{gathered}[/tex]solve the equation to find (n)
[tex]\begin{gathered} 4\cdot10-4n+7n=6.1\cdot10 \\ -4n+7n=6.1\cdot10-4\cdot10 \\ 3n=21 \\ n=\frac{21}{3}=7 \end{gathered}[/tex]Substitute with (n) into equation (3) to find (c)
[tex]c=10-7=3[/tex]so, the answer will be:
The number of pounds of chocolates = c = 3 pounds
The number of pounds of nuts = n = 7 pounds
find the value of XA. 11√ 41inB. 11 inC. 33 inD. 35 in
From the diagram provided, we have a right angled triangle with the hypotenuse (side facing the right angle) given as 55, while one of the other two sides is given as 44.
We shall apply the pythagoras' theorem as follows;
[tex]c^2=a^2+b^2[/tex]Where,
c = hypotenuse,
a and b = the other sides.
Therefore, we'll now have;
[tex]\begin{gathered} c^2=a^2+b^2 \\ 55^2=44^2+c^2 \\ 3025=1936+c^2 \end{gathered}[/tex]Next step, we'll subtract 1936 from both sides of the equation;
[tex]\begin{gathered} 3025-1936=1936-1936+c^2 \\ 1089=c^2 \end{gathered}[/tex]Add the square root sign to both sides of the equation;
[tex]\begin{gathered} \sqrt[]{1089}=\sqrt[]{c^2} \\ 33=c \end{gathered}[/tex]ANSWER
Therefore, the correct answer is option C, that is 33 inches.
I was wondering if you could help me with this problem. I am not sure where to start solving it. Thank you.
As shown at the graph, we need to find x and y
The angles (x+1) and (2y+1) are vertical
so, x + 1 = 2y + 1
so,
x = 2y eq.(1)
And the sum of the angles (x+1) , (3x + 4y) and (71 - 3y) are 180
So,
(x+1) + (3x + 4y) + (71-3y) = 180
x + 1 + 3x + 4y + 71 - 3y = 180
4x + y = 180 - 1 - 71
4x + y = 108
Substitute with x from eq (1) with 2y
4 * 2y + y = 108
8y + y = 108
9y = 108
y = 108/9 = 12
x = 2y = 2 * 12 = 24
So, x = 24 and y = 12
How many and what type of solution(s) does the equation have?6p2 = 8p + 32 rational solutions1 rational solutionNo real solutions2 irrational solutions
We are going to solve the question using the quadratic formula
[tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{(b^2}-4ac)}{2a} \\ \text{where the quadratic equation is ax}^2+bx+c=0 \end{gathered}[/tex]The quadratic equation given is
[tex]\begin{gathered} 6p^2=8p+3 \\ 6p^2-8p-3=0 \\ \text{where a=6} \\ b=-8 \\ c=-3 \end{gathered}[/tex]By substitution we will have,
[tex]\begin{gathered} p=\frac{-(-8)\pm\sqrt[]{(-8)^2}-(4\times6\times-3)}{2\times6} \\ p=\frac{8\pm\sqrt[]{64+72}}{12} \\ p=\frac{8\pm\sqrt[]{136}}{12} \\ p=\frac{8\pm\sqrt[]{4\times34}}{12} \\ p=\frac{8\pm2\sqrt[]{34}}{12} \\ p=\frac{2(4\pm\sqrt[]{34)}}{12} \\ p=\frac{4\pm\sqrt[]{34}}{6} \\ p=\frac{4+\sqrt[]{34}}{6}\text{ or p=}\frac{4-\sqrt[]{34}}{6} \end{gathered}[/tex]Therefore,
With the roots gotten from the quadratic equation, we can therefore deduce that the solutions to the equation 6p²=8p+3 will give 2 irrational roots.
The correct answer is OPTION D
Equipment was purchased for $50,000. The equipment is expected to be used 15,000 hours over its useful life and has a residual value of $10,000. In the first two years of operation, the equipment was used for 2,700 hours and 3,300 hours, respectively. Using the activity-based method, what is the equipment’s accumulated depreciation at the end of the second year?
The equipment’s accumulated depreciation at the end of the second year is $16,000.
What is the accumulated depreciation?Depreciation is the process used in expensing the cost of an asset. The activity based method allocates the depreciation expense using the number of hours the asset was used. Accumulated depreciation is the sum of the depreciation over a period of time.
Depreciation expense using the activity based method = (cost of the asset - residual value) x (number of hours used in a year / total number of hours)
Depreciation expense in year 1 = ($50,000 - $10,000) x (2,700 / 15,000)
$40,000 x 0.18 = $7,200
Depreciation expense in year 2 = ($50,000 - $10,000) x (3,300 / 15,000)
$40,000 x 0.22 = $8,800
Accumulated depreciation = $8,800 + $7,200 = $16,000
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NO LINKS!! Show all work where necessary to get full credit Part 2
21. Circle R
A circle is named using its center.22. RV
A radius connects the center to a point on the circle.23. ZV
A chord connects two points on the circle.24. TX
A diameter passes through the center of the circle and connects two points on the circle.25. RV
See 22 and 24.26. 4 feet
The diameter is twice the radius, 2(2)=4.Answer:
21. R
22. RU
23. VZ
24. BE
25. RU
26. 4 feet
Step-by-step explanation:
Question 21
A circle is named by its center.
Therefore the name of the given circle is R.
Question 22
The radius of a circle is a straight line segment from the center to the circumference.
Therefore, the radii of the given circle are:
RZ, RT, RU, RV, RW and RX.Question 23
A chord is a straight line segment joining two points on the circumference of the circle.
Therefore, the chords of the given circle are:
WZ, TX and VZ.Question 24
The diameter of a circle is the width of the circle at its widest part. It is a straight line segment that passes through the center of the circle and whose endpoints lie on the circumference.
Therefore, the diameters of the given circle are:
TX and WZ.Question 25
As the diameters are TX and WZ, they contain the radii RZ, RT, RW and RX.
Therefore, the radii that are not contained in the diameter is:
RU and RV.Question 26
The diameter is twice the length of the radius.
Therefore, if the radius of the circle is 2 feet:
⇒ Diameter = 2 × 2 = 4 feet.
if (11,13) is an ordered pair of the function F(x), which of the following is an ordered pair of the inverse of F(x)
Given:
There are given that the ordered pair is:
[tex](11,13)[/tex]Explanation:
According to the question:
We need to find the inverse of the given ordered pair.
Then,
To find the inverse of the given relation, we need to switch the x and y-coordinates.
Then,
The inverse is:
[tex](11,13)\rightarrow(13,11)[/tex]Final answer:
Hence, the correct option is C.
In an art classroom, 8 students can sit around 1 table, and 48 students can sit around 6 tables. What is the relationship between the number of students to tables? (Do not reduce the ratios to their lowest terms.)
Answer: 8/1 = 6/48
Step-by-step explanation: um thats the answer bye
The relationship between the number of students to tables or the ratio of students to number of tables is 8 to 1.
According to question,
We have the following information:
In an art classroom, 8 students can sit around 1 table, and 48 students can sit around 6 tables.
Now, we will find the relationship between the number of students and the number of tables or in simple words, ratio.
So, we have:
8 students = 1 table
48 students = 6 tables
It can be rewritten by dividing both the sides by 6 as 8 students to 1 table.
It means that there are 8 students for 1 table.
Hence, the relationship between the number of students to the number of tables is 8 to 1.
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Matthew filled two 20 oz. water bottles before he left home. At the end of the day, he has less than 8 oz. left. Write an inequality to determine how much water, z, Matthew drank.
Given data:
The expression for the inequality is,
[tex]\begin{gathered} 2(20)-z<8 \\ 40-z<8 \end{gathered}[/tex]Thus, the second inequality is correct.
Give the digits in the ones place and the hundredths place.
12.86
Please help ASAP
Find a if (10-a )×2 +(2a×2)+(4a+7)=48
First step: Simplify everything
[tex]2(10-a) + 4a + 4a+7 = 48[/tex]
Next: Distribute required values
[tex]20-2a+4a+4a+7=48[/tex]
Next: Time to add like terms
[tex]6a = 21[/tex]
Final Step: Divide 6 on both sides to isolate variable
[tex]a = \frac{21}{6}[/tex]
Thus, the value "a" = [tex]\frac{21}{6}[/tex]
Hope this helps :)