A gas has a mass of 3.82 g and occupies a volume of 0.854 L. The temperature in the laboratory is 302 K, and the air pressure is 1.04 atm. calculate the molar mass of the gas.

1) 93.4 g/ mol
2) 72.3 g/ mol
3) 107 g/ mol
4) 35.8 g/mol

The number of moles of air present is 0.056 mole

The ideal gas is one in which molecules do not attract or repel each other.Many gases like oxygen,nitrogen, carbon di oxide can be treated as the ideal gases as particular temperature and pressure.The real gases at high temperature and lower pressure can be treated as ideal gases.

The given data in the question is

Volume = 1.35 L

Pressure (P) = 750 torr

Temperature (T) = 17 °C = 17 + 273 = 290 K

Gas constant (R) = 62.396 L•torr/mol•K

The number of moles (n) =?

How to determine the number of moles:

The number of moles present can be obtained by using the ideal gas equation as illustrated below:

[tex]PV=nRT[/tex]

Divide both sides by RT

[tex]n=\dfrac{PV}{RT}[/tex]

[tex]n=\dfrac{(750\times 1.350}{62.396\times 290)}[/tex]

[tex]n=0.056\ moles[/tex]

Hence, the number of moles of air present is 0.056 mole

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Answer:

answer in picture

Explanation:

Answer:

Yes

Explanation:

The process of respiration and burning are similar in the following ways: Both respiration and burning require oxygen. Energy is released during both respiration and burning. The products produced (carbon dioxide and water) are the same for both respiration and burning.

Answer:

Yes

Both Respiration and Burning uses oxygen. Both Respiration and Burning produces energy. Both Respiration and Burning gives out carbon dioxide as the end product. The overall chemical reactions of both Respiration and Burning are the same.

Explanation:

Please mark me brainliest if correct

Answer:

the ice cube feels cold  

Explanation:

heat transfer is like how the sun gives us and the radiation of it put heat transfer but we dont have radiation

Entropy is the degree of disorder of a system. The entropy of b is 168.95  j/mol ･k.

The term entropy refers to the degree of disorder in a system. We have to know that the change in entropy of a system is the entropy of the product minus the entropy of the reactants.

Hence;

-277. 1 = [2(b) - 3(205. 0)

-277. 1  = 2b - 615

b= -277. 1 + 615/2

= 168.95  j/mol ･k

The entropy of b is 168.95  j/mol ･k.

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Answer:

B . Water molecules can collide with other particles more than neon atoms can.

Answer:

The number of carbon atoms is twice the number of magnesium atoms

Answer:

According to the kinetic theory of gases, in an ideal gas between two successive collisions, a gas molecule travels in a straight line.

C. Walking on wet floors shows that Friction is undesirable

Answer:

7. H

8. F

9. G.

10. D

11. A

12. E

13. B

14. C

Answer:

D.) 4

Explanation:

Al + 3 O₂ --> 2 Al₂O₃

In the equation, there are:

Reactants: 1 Al and 6 O

Products: 4 Al and 6 O

To determine how many atoms there are of each, you multiply the coefficients by the subscripts attached to the atoms. While the question doesn't ask, as you can see, the oxygen atoms are balanced because there is an equal amount on both sides. To balance the aluminum atoms, you can get 4 aluminum atoms on the reactants side by using a coefficient of 4.

The new equation would look this this:

4 Al + 3 O₂ --> 2 Al₂O₃

There are now:

Reactants: 4 Al and 6 O

Products: 4 Al and 6 O

After subtracting the volume needed from the volume dispensed, we got a remainder of 35ml

Given Data

Let us compute the amount of excess hexane/ the volume that will remain

Remainder = The difference in volume dispensed and the volume needed

Remainder = 40-5

Remainder = 35 ml

The remainder is 35ml

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If you dispense 40 ml of hexane, but it turns out you only need 5 ml, then we should have 35 mL of remained hexane.

Remaining volume of any liquid will be calucted as:

Remaining Volume = Total volume - Used volume

Given that, total volume of hexane = 40 mL

Used volume of hexane = 5 mL

On putting values in above equation, we get

Remaining volume = 40 - 5 = 35 mL

Hence required value of remaining volume is 3 mL.

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Answer:

chemical change i think

Explanation:

As the drops of vinegar fall through the oil to the bottom of the bottle, it reacts with the baking soda to make carbon dioxide gas. These bubbles attach themselves to the colored vinegar and cause them to float to the surface. When the bubbles pop, the color sinks back to the bottom of the bottle.

Moles are an estimation of the smallest unit of the molecules and the atoms in a sample. The moles of ammonium nitrate in a sample are 0.5010 moles.

Moles are calculated by dividing the mass of the substance in gm by that of the molar mass in gram per mole.  

Given.

Mass of ammonium nitrate = 40.10 gm

The molar mass of ammonium nitrate = 80. 0432 g/mol

Moles of ammonium nitrate are calculated as:

[tex]\begin{aligned}\rm moles &= \rm \dfrac{mass}{molar\; mass}\\\\&= \dfrac{40.10}{80.0432}\\\\&= 0.5010 \;\rm mol\end{aligned}[/tex]

Therefore, moles of ammonium nitrate present is option d. 0.5010 moles.

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Answer:

isobars

Explanation:

How?

So they are isobars

The reaction which shows the bronsted-lowry acid reacting is HCl + H₂O → H₃O⁺ + Cl⁻.

According to the Bronsted-Lowry theory, the species which donates H⁺ ion to the solution is known as Bronsted-Lowry acid and which accepts H⁺ ion is known as Bronsted-Lowry base.

Among the given reactions, only the reaction which is showing Bronsted-Lowry acid is:

HCl + H₂O → H₃O⁺ + Cl⁻

Here HCl is a Bronsted-Lowry acid as it gives H⁺ ion in the aqueous solution.

Hence, option (3) is correct.

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Answer:

you are not posted question

For an unknown using the retention times 1. 6 min for ch4, 12. 8 min for octane, 15. 4 min for the unknown, and 19. 6 min for nonane, the kovats retention index is mathematically given as

I = 807.857

Generally, the equation for the Kovats index(i)  is mathematically given as

[tex]I= \frac{100[n + (N - n) x (Log tr (unknown) - logtr (n))}{ logtr(N) - logtr(n))]}[/tex]

Therefore

[tex]I= \frac{100[ 1+8*(log(14.7) -log (1.5)}{log (19.8) - log (1.5)) 0]}[/tex]

I = 100[ 1+8*(0.991/1.12)]

I = 807.857

In conclusion, Kovats retention index

I = 807.857

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Kovats retention index is a system that converts the retention time into the independent constants of the system. The Kovats retention index for the unknown is 807.857.

The Kovats retention index (I) is the system used in analytical techniques like gas chromatography for the conversion of the retention time.  It is given mathematically as:

[tex]\rm I = \rm \dfrac{100[n+(N-n)x(Logtr(unknown)-logtr(n))}{Logtr(N)-Logtr(n)]}[/tex]

Substituting values and solving further,

[tex]\begin{aligned} \rm I &= \rm \dfrac{100[1+8 \times (Log(14.7) - log (1.5))}{(log (19.8) - log (1.5))0}\\\\&= 100 [ 1 + 8 (\dfrac{0.991}{1.12})]\\\\&= 807.857\end{aligned}[/tex]

Therefore, the Kovats retention index for an unknown is 807.857.

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Answer:

Enthalpy

Explanation:

The term entropy is used to express the particle scattering of a system.The term joule is a unit of energy.

ANSWER:

Physical chemistry is the branch of chemistry that deals with the physical structure of chemical compounds, the way they react with other matter and the bonds that hold their atoms together. An example of physical chemistry is nitric acid eating through wood.

Answer:

[tex]\huge\boxed{\sf n = 7.36 \ mol}[/tex]

Explanation:

Given Data:

Volume = v = 42.19 L

Pressure = P = 428.792 kPa = 4.23 atm

Temperature = 27.871 °C + 273 = 300.871 K

R = the gas constant = 0.08206 L atm K⁻¹mol⁻¹

Required:

No. of moles = n = ?

Formula:

nRT = Pv

Solution:

Rearranging formula

[tex]\displaystyle n = \frac{Pv}{RT} \\\\n = \frac{(4.23)(42.19)}{(0.08206)(300.871)} \\\\n = \frac{181.467}{24.69} \\\\n = 7.36 \ mol\\\\\rule[225]{225}{2}[/tex]

Answer:

9   I believe

Explanation:

The answers to your questions are as follows

A) The number of aluminium ions present = 1.62 * 10²³ ions

B) The number of chloride ions present = 9.86 * 10²³  ions

C) The mass of one unit of aluminium chloride = 133.34 grams

Given data :

mass of aluminium chloride = 37.2 g

molar mass of aluminium chloride = 133.34 g/mol

note : I mole of a molecule has 6 * 10²³ molecules  

Number of moles = mass / molar mass = 0.27 moles

A) aluminium ions present

moles of AlCl₃ * 6 * 10²³

= 0.27 * 6 * 10²³   = 1.62 * 10²³ ions

B) Chloride ions present

moles of AlCl₃ * 6 * 10²³  * 3

= 0.27 * 6 * 10²³ * 3

= 4.86 * 10²³ ions

C) The mass of one formula unit of aluminium chloride = 133.34 grams

Hence we can conclude that the answers to your question are as listed above.

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Considering the ideal gas law,  there are 279.42 moles of acetylene in the tank.

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:

P×V = n×R×T

In this case, you know:

Replacing in the ideal gas law:

17.4192 atm× 390 L = n×0.082 [tex]\frac{atmL}{molK}[/tex]× 296.5 K

Solving:

[tex]n=\frac{17.4192 atmx 390 L}{0.082 \frac{atmL}{molK}x296.5 L}[/tex]

n= 279.42 moles

Finally, there are 279.42 moles of acetylene in the tank.

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Answer:

These clouds extend through the lower and mid-layers of the troposphere bringing rain to the surface below.

Explanation:

The bases of clouds in the middle level of the troposphere, given the prefix “alto,”

Answer:

khate ko ban randi ko ban

Answer:

Mendeleev left some gaps in his periodic table because he believed that in future more elements will be discovered.

Explanation:

"Mendeleev left gaps in his table to place elements not known at the time. By looking at the chemical properties and physical properties of the elements next to a gap, he could also predict the properties of these undiscovered elements."

The partial stress of H2 is 737.47 mmHg Let's observe the Ideal Gas Law to find out the whole mols.

We count on that the closed vessel has 1L of volume

These are the whole moles. Now we are able to know the moles of water vapor, to discover the molar fraction of it.

Mole fraction is a unit of concentration, described to be identical to the variety of moles of an issue divided through the whole variety of moles of a solution. Because it's miles a ratio, mole fraction is a unitless expression.

Thus it is clear that the partial pressure of H2 is 737,47 mmHg.

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