To find the volume of the cone, we will use the formula below:
[tex]V=\frac{1}{3}\pi r^2h[/tex]where r is the radius and h is the height
From the question,
π = 3.14
r =7
h=17
substitute the values into the formula
[tex]V=\frac{1}{3}\times3.14\times7^2\times17[/tex][tex]V\approx871.87\text{ cubic centimeters}[/tex]
15. Find the volume of a rectangular prism with the following dimensions.a length of 11 cm, a width of 4.2 cm, and a height of 7.1 cm.3308.24 cm3328.02 cm322.3 cm346.2 cm
For this problem, we are given the dimensions of a rectangular prism and are asked to determine its volume.
The volume of a rectangular prism is given by the product of the three dimensions, therefore we have:
[tex]\begin{gathered} V=\text{ height}\cdot\text{ length}\cdot\text{ width}\\ \\ V=11\cdot4.2\cdot7.1=328.02\text{ cubic cm} \\ \end{gathered}[/tex]The correct answer is 328.02 cubic centimeters.
The endpoints of the line are (0, 5) and (6, 4). Find the slope of the line.
Solution:
Given the endpoints of the line;
[tex](0,5),(6,4)[/tex]The slope, m of the line is;
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \\ \text{ Where }x_1=0,y_1=5,x_2=6,y_2=4 \end{gathered}[/tex]Thus;
[tex]\begin{gathered} m=\frac{4-5}{6-6} \\ \\ m=-\frac{1}{6} \end{gathered}[/tex]CORRECT ANSWER:
[tex]-\frac{1}{6}[/tex]What is the scale factor for AXYZ to AUVW?O A1/1O B. 1/1/20OC. 2OD. 4371620A A837-105353X 6 Z12
SOLUTION:
We want to know the scale factor of the transformation from;
[tex]\Delta XYZ\rightarrow\Delta UVW[/tex]We do this by taking ratios of corresponding sides, they should be the same in either case;
Thus , the scale factor is;
[tex]\frac{20}{10}=\frac{12}{6}=\frac{16}{8}=2[/tex]Thus, the scale factor is 2.
The graph represents a quadratic function. Write an equation of the function in standard form.
A quadratic function in standard form with the given characteristics is (1/4) x² - 3x + 5.
Given that, the graph is passing through (2, 0), (10, 0) and (6, -4).
What is a quadratic function in standard form?The standard form of a quadratic equation is given as:
ax² + bx + c = 0 where a, b, c are real numbers and a ≠ 0.
Now, the equation passes through (2, 0)
y = ax² + bx + c
0 = 4a + 2b + c ----------------(1)
The equation passes through (6, -4)
y = ax² + bx + c
-4= 36a + 6b + c ----------------(2)
The equation passes through (10, 0)
y = ax² + bx + c
0 = 100a + 10b + c ----------------(3)
Using the Gauss elimination method to solve the system of equations we get,
a = 1/4, b = -3, and c = 5
The quadratic equation will be:
y = ax² + bx + c
y = (1/4) x² - 3x + 5
Therefore, a quadratic function in standard form with the given characteristics is (1/4) x² - 3x + 5.
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State the domain and range for each graph and then tell if the graph is a function(write yes or no)
For the point 1)
- The domain will be: (note that this is not an interval, it is a set of two points)
[tex]\mleft\lbrace-3,2\mright\rbrace[/tex]-The range is the set R of all real numbers (since the line extends to infinite)
-The first graph is NOT a function
For the point 2)
-The domain will be the interval
[tex](-5,5\rbrack[/tex]-The range is the interval:
[tex]\lbrack-2,2\rbrack[/tex]-The second graph is a function.
Please assist me. I have no idea how to start this equation
Part a
Remember that the linear equation in slope-intercept form is
y=mx+b
where
m is the slope or unit rate
b is the y-intercept or initial value
In this problem
the equation is of the form
C=m(n)+b
where
m=8.50
b=350
therefore
C=8.50n+350Part b
A reasonable domain for n (number of cups)
Remember that the number of cups cannot be a negative number
so
the domain is the interval [0, infinite)
but a reasonable domain could be [0, 500]
Find out the range
For n=0 -----> C=350
For n=500 ----> C=8.50(500)+350=2,100 ZAR
the range is the interval [350,2,100]
Part c
calculate the cost
For n=100 cups ----> C=8.50(100)+350=1,200 ZAR
For n=200 cups ----> C=8.50(200)+350=2,050 ZAR
For n=400 cups ---> C=8.50(400)+350=3,750 ZAR
Part d
Average cost
Divide the total cost by the number of cups
For 100 cups ------> 1,200/100=12 ZAR per cup
For 200 cups ----> 2,050/200=10.25 ZAR per cup
For 400 cups ----> 3,750/400=9.38 ZAR per cup
Part e
it is better to order more cups, to reduce the initial ZAR 350 cost.
Part f
In this problem we have the ordered pairs
(200, 2150) and (400, 3750)
Find out the slope m
m=(3750-2150)/(400-200)
m=8 ZAR per cup
Find out the linear equation
C=mn+b
we have
m=8
point (200,2150)
substitute and solve for b
2150=8(200)+b
b=2150-1600
b=550
therefore
The linear equation is
C=8n+550Part g
A reasonable domain could be [0, 600]
Find out the range
For n=0 ------> C=550
For n=600 ----> C=8(600)+550=5,350
The range is the interval [550,5350]
Part h
The gradient is the same as the slope
so
slope=8
that means ----> the cost of each cup is 8 ZAR
Part i
For n=600
C=8(600)+550=5,350 ZAR
Part j
we have the inequality
8n+550 < 8.50n+350
Solve for x
550-350 < 8.50n-8n
200 < 0.50n
400 < n
Rewrite
n > 400
For orders more than 400 cups is more effective to order from Cupomatic
Verify
For n=401
C=8n+550=8(401)+550=3,758 ZAR
C=8.50n+350=8.5(401)+350=3,758.5 ZAR
the cost is less in CUPOMATIC, is ok
the answer is
For orders more than 400 cups is more effective to order from CupomaticThe numbers of trading cards owned by 9 middle- school students are given below. ( note that these are already ordered from least to greatest.
Given the numbers:
355, 382, 383, 427, 500, 572, 601, 638, 669
Total numbers = 9
a) We find the mean:
[tex]\begin{gathered} mean=\frac{355+382+383+427+500+572+601+638+669}{9} \\ mean=\frac{4527}{9}=503 \end{gathered}[/tex]Change 669 to 606:
[tex]\begin{gathered} mean=\frac{355+382+382+427+500+572+601+638+606}{9} \\ mean=\frac{4464}{9}=496 \end{gathered}[/tex]Then:
[tex]\begin{gathered} mean=changed\text{ mean}-original\text{ mean} \\ mean=496-503=-7 \end{gathered}[/tex]Answer: It decreases by 7
b) We find median
Median: 355, 382, 383, 427, 500, 572, 601, 638, 669
Median = 500
669 changed to 606
Median: 355, 382, 383, 427, 500, 572, 601, 606, 638
Median = 500
Answer: It stays the same
The function f(x) is graphed below. what is true about the graph on the interval from x = y to x = ∞?* it is positive and increasing* it is positive and decreasing * it is negative and increasing* it is negative and decreasing
Looking at the graph, we will the following:
The portion ab is increasing
The portion bc is decreasing
The portion cd is decreasing
The portion de is increasing
The portion ef is increasing
The portion fg is decreasing
The portion beyond g is increasing
In the interval x = y to x = ∞, we will observe that the graph is positive & increasing
Hence, the first option is correct (it is positive and increasing)
Select the expressions that are equivalent to 7(7f)1. 49f2. 7(f+6f)3. f+144. f+49
ANSWER :
49f and 7(f + 6f)
EXPLANATION :
From the problem, we have :
[tex]7(7f)[/tex]When multiplied, it will be 49f
When breaking it down, 7f is equal to f + 6f. Then it will be 7(f + 6f)
The next options f + 14 and f + 49 has two terms, so it will not be equivalent to the given expression with one term.
So the only expressions that are equivalent to the given expression are 1 and 2
In a circle with radius 8, an angle measuring radians intercepts an arc. Find thelength of the arc in simplest form.
s = 28π/3
Explanation:The radius, r = 8
The angle, θ = 7π/6 radian
The length of the arc, s = rθ
s = 8 x 7π/6
s = 28π/3
Herb Garrett has an 80% methyl alcohol solution. He wishes to make a gallon of windshield washer solution by mixing his methyl alcohol solution with water. If 128 ounces or a gallon of windshield washer fluid contain 6% methyl alcohol, how much of the 80% methyl alcohol solution and how much water must be mixed? Express your answer in ounces.
First, calculate the total volume of alcohol in the gallon of windshield washer solution by calculating what is 6% of a gallon equal to. Since a gallon is equal to 128 ounces, then:
[tex]undefined[/tex]...........................
Solution
We have the following:
5!= 5*4*3*2= 20*3*2= 60*2= 120
Quadratic Factoring: Demonstrate solving some quadraticequations using the following methods: factoring, taking theroot, and completing the square.
The Solution:
Let's solve with the Factoring Method:
[tex]x^2-x-6=0[/tex][tex]\begin{gathered} x^2-3x+2x-6=0 \\ x(x-3)+2(x-3)=0 \\ (x+2)(x-3)=0 \end{gathered}[/tex][tex]\begin{gathered} x+2=0\text{ or }x-3=0 \\ x=-2\text{ or }x=3 \end{gathered}[/tex]Solving by the Completing the Square:
[tex]\begin{gathered} x^2-x=6 \\ x^2-x+(\frac{1}{2})^2=6+\frac{1}{4} \\ \\ (x-\frac{1}{2})^2=\frac{25}{4} \end{gathered}[/tex]Take the square root of both sides.
[tex]\begin{gathered} x-\frac{1}{2}=\sqrt{(\frac{25}{4})} \\ \\ x=\frac{1}{2}\pm\frac{5}{2}=\frac{1\pm5}{2} \end{gathered}[/tex][tex]\begin{gathered} x=\frac{1+5}{2}=\frac{6}{2}=3 \\ \\ \\ x=\frac{1-5}{2}=\frac{-4}{2}=-2 \end{gathered}[/tex]Therefore, the answers is:
[tex]x=-2\text{ or }x=3[/tex]Virginia is going to visit 5 cities this summer. She will choose from 8 different cities and the order in which she visits the cities does not matter. How many different city combinations are possible for the summer travelling?
For the function f(x) = x² + 2x - 24 solve the following.
f(x) = 0
For the function, f(x) =0, we have x = -6 and x =4
The given function is f(x) = x² + 2x - 24
For f(x) = 0
f(x) = x² + 2x - 24 =0
x² + 2x - 24 =0
Middle Term Splitting is a method to solve quadratic equations of the form ax² + bx +c, In middle-term splitting, we split the middle term into the factors of the constant terms, then we take common multiples from the terms and then convert the equation into factors, we equate each factor to zero and we get the desired results.
By splitting the middle term, we have:
x² + 6x -4x - 24 =0
x( x + 6) -4(x+6) =0
( x + 6 ) ( x - 4 ) = 0
( x + 6 ) = 0 and ( x - 4 ) = 0
x = -6 and x = 4
Hence, for f(x) =0, we have x = -6 and x =4
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State the domain of the function.{-2,0, 1, 2, 3, 4){-4,0, 1, 2, 6){0, 1,2,3)(-2,4)
D= {-2,0,1, 2,3,4}
1) Considering that the Domain is the set of entries of a function, on the x-axis, and examining that graph we can state
- The lowest value for that is given by x=-2
- The highest value for that is x= 4
- The points (-2,-4) (0,0), (1,1), (2,2), (3,1) and (4,6)
2) So, we can write the set, the Domain, after examining the options as:
D= {-2,0,1, 2,3,4}
Notice that we're considering the x-coordinates
3) So the answer is D= {-2,0,1, 2,3,4}
PLEASE HURRY AND HELP I NEED THIS TODAY
Solve k over negative 1.6 is greater than negative 5.3 for k.
k > −8.48
k < −6.9
k > −6.9
k < 8.48
Answer: [tex]k < 8.48[/tex]
Step-by-step explanation:
[tex]\frac{k}{-1.6} > -5.3\\\\k < (-5.3)(-1.6)\\\\k < 8.48[/tex]
1. Alice made the conjecture below.(a + b)2 = a + b2OWhich values of a and b are not counterexamples to the conjecture?a = 1, b = 1a = 0, b = 1aa = -1, b = 1a = -1, b = 2
the expression is
(a+b)^2=a+b^2
substitute a=1 and b=1
(1+1)^2 = 1+1^2
4=2
that is not possible. so these are the values of a and b that is not counterpart example to the conjecture.
now substitute a=0, b=1
(0+1)^2 = 0+1^2
1=1
so this is true for the above expression.
now for a=-1, b=1
(-1+1)^2 = -1+1^2
0=0
this is true.
now for a=-1, b=2
(-1+2)^2 = -1+2^2
1=3
that is not possible
so a=1, b=1 and a=1,b=2 is the values that not counterpart example to the conjecture.
How do I identify the horizontal and vertical asymptotes, find several points, and graph each function?Y=4/x+3 -2
Given:
[tex]y=\frac{4}{x+3}-2[/tex]Required:
To identify the horizontal and vertical asymptotes, and to point the graph.
Explanation:
Now the graph of the given function is
To find the horizontal asymptotes apply the limit
-12 -24 4bI need help can someone help .
To eliminate the coefficient divide each side by 3
Now solve the two step equation
3g - 5 = 17
3g = 17 + 5 = 22
then g= 22/3
Now solve 9 = 4a + 13
9 -13 = 4a
-4 = 4a then -1= a
a= -1
Jane is attending physical therapy after knee surgery. She walked 9 3/4 miles over 3 days. How many miles is this per day? (Simplify the answer and write it as a mixed number.)
She walked 3 1/4 miles per day.
Given,
Jane walked 9 3/4 miles in the course of 3 days.
If we calculate this mixed number into a fraction,
We get:
9 3/4 miles = {(9×4)+3} / 4 miles
=39/4 miles.
So, Jane walks 39/4 miles in 3 days.
Therefore, in one day she walked:
(39/4 ÷ 3) miles
= 13/4 miles per day
Let's now convert this fraction into a mixed number:
when 13 is divided by 4 we get the remainder as 1 and the quotient as 3.
So, a mixed number is given by:
quotient remainder/divisor
Hence 13/4 = 3 1/4.
So, Jane walked 3 1/4 miles per day.
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Solve the compound inequality. Graph the solution-7 *x+3<4-The solutions are(Type an inequality or a compound inequality. Sim
Answer:
[tex]-10\leqslant x<1[/tex]Explanation:
To solve compound inequalities, we do the same as in an equation or inequality: we need to do the same operation in all places.
We want to solve for x:
[tex]-7\leqslant x+3<4[/tex][tex]-7-3\leqslant x+3-3<4-3[/tex][tex]-10\leqslant x<1[/tex]And that's the answer
19. Translate the following statement into an algebraic statement: "Two more than seven times a number is fifteen" I
2+7x=15
Explanation
Step 1
Let
x represents the number
seven times a number = 7x
two more = +2 or 2+, you need to add 2
is = "="
Step 2
replace,
"Two more than seven times a number is fifteen"
[tex]2+7x=15[/tex]I hope this helps you
The problem is below, we know the man weighs 60, the cat weighs 10 but we’re having a hard time explaining how
Given data:
The weight of man and daughter = 90
The weight of man and cat is = 70
The weight of cat and daughter = 40 .
The man weights 60 kg.
then daughter weight = 90-60 = 30.
Thus the daughter weight is 30kg.
therefore the cat weight iwith daughter, 40-30 = 10 .
also with father, 70-60 = 10 .
Thus, the father weight is 60 kg.
The daughter weight is 30 kg and
The cat weight is 10 kg.
Suppose Yolanda places $9000 in an account that pays 8% interest compounded each year. Assume that no withdrawals are made from the account. Follow the instructions below. Do not do any rounding. (a) Find the amount in the account at the end of 1 year. $ (b) Find the amount in the account at the end of 2 years. $0 X S
Compound interest - The amount in the account at the end of 1st year is $9720 and The amount in the account at the end of 2nd years is $10497.6
What is compound interest?
The interest earned on savings that is calculated using both the initial principal and the interest accrued over time is known as compound interest. It is thought that Italy in the 17th century is where the concept of "interest on interest" or compound interest first appeared. It will accelerate the growth of a sum more quickly than simple interest, which is only calculated on the principal sum. Money multiplies more quickly thanks to compounding, and the more compounding periods there are, the higher the compound interest will be.
We are given that the principal amount is $9000
An the interest is 8%
Hence after 1 year the amount will be
[tex]A=9000(1+0.08)\\A=9000(1.08)\\A=9720\\[/tex]
After 1 year the amount becomes $9720
Now After 2 years we will get interest on $9720
Hence the amount after 2 years will be
[tex]B=9720(1+0.08)\\B=9720(1.08)\\B=10497.6[/tex]
Therefore the amount after 2 years is $10497.6
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A local dairy has three machines to fill half-gallon milk cartons. The machines can fill the daily quota in 3 hrs, 14 hrs, and 10.5 hrs, respectively. Find how long it takes to fill the daily quota if all three machines are running.
Answer
It will take 2 hours to fill the daily quota if all the machines are running.
Explanation
To find how long it takes to fill the daily quota if all the machines are running, we use the relation below:
Rate of machine 1 + Rate of machine 2 + Rate of machine 3 = Total rate of the machines
[tex]\begin{gathered} \Rightarrow\frac{1}{3}+\frac{1}{14}+\frac{1}{10.5}=\frac{1}{x} \\ \text{Where x is the }time\text{ it takes to fill the daily quota} \\ \frac{1}{3}+\frac{1}{14}+\frac{2}{21}=\frac{1}{x} \\ \text{Multiply all through by 42x} \\ 42x(\frac{1}{3})+42x(\frac{1}{14})+42x(\frac{2}{21})=42x(\frac{1}{x}) \\ 14x+3x+4x=42 \\ 21x=42 \\ x=\frac{42}{21} \\ x=2 \\ \text{Therefore it will take 2 hours to fill the daily quota} \end{gathered}[/tex]Evaluate 2(x - 4) + 3x - x^2 for x = 2.O A. -6O B. -2O C. 6O D. 2
C. 6
Explanation
To evaluate an algebraic expression means to find the value of the expression when the variable is replaced by a given number.so
Step 1
given
[tex]2(x-4)+3x-x^2[/tex]a)let
[tex]x=2[/tex]b) now, replace and calculate
[tex]\begin{gathered} 2(x-4)+3x-x^2 \\ 2(2-4)+3(2)-(2^2) \\ 2(-2)+6-4 \\ -4+6-4 \\ -4+6-4=6 \end{gathered}[/tex]therefore, the answer is
C. 6
I hope this helps you
I’m trying to make a study guide and need step by step explanation on how to solve this question please
Given:
The dimension of square shape floor is 200 feet by 200 feet.
The area of the square is calculated as,
[tex]\begin{gathered} A=side^2 \\ A=200^2=40000 \end{gathered}[/tex]Now, given that the 1/2 bottle will cover approximately 2000 quare feet.
It gives,
[tex]\begin{gathered} \frac{1}{2}\text{ bottle=2000 square f}ee\text{t} \\ 1\text{ bottle=4000 square fe}et \end{gathered}[/tex]So, the number of bottles required are,
[tex]\frac{A}{4000}=\frac{40000}{4000}=10\text{ bottles}[/tex]Answer: option B)
Find the vertical and horizontal lines that passes through the point (3,6).
We have to find the vertical and horizontal lines that passes through the point (3,6).
A vertical line will be defined as x = constant. If it passes trough a point (x,1,y1), the line will be defined as a x=x1, so the point (x1,y1) belongs to the line.
The same goes for horizontal lines, but in this case the line is defined as y = constant.
For a point (x1,y1), the horizontal line that pass through the point will be y = y1.
Then, for point (x,y)=(3,6), the vertical and horizontal lines as:
x=3 and y=6.
Answer:
Vertical line: x = 3
Horizontal line: y = 6.
Which of the following is the explicit formula for a compound interestgeometric sequence?
INFORMATION:
We have the following options
And we must select the one that represents the explicit formula for a compound interest geometric sequence
STEP BY STEP EXPLANATION:
To select the correct one, we need to know that:
[tex]P_n=P_1(1+i)^{(n-1)}[/tex]Finally, the correct one would be option A
ANSWER:
[tex]A.\text{ }P_n=P_1\cdot(1+i)^{n-1}[/tex]