Answers
Organism – Squid
Number of chromosomes after meiosis: 26
Number of chromosomes in the body cells: 52
Number of chromosomes in gametes: 26
Number of chromosomes after mitosis: 52
Organism – Sunflower
Number of chromosomes after meiosis: 19
Number of chromosomes in the body cells: 38
Number of chromosomes in gametes: 19
Number of chromosomes after mitosis: 38
Organism – Pea plant
Number of chromosomes after meiosis: 7
Number of chromosomes in the body cells: 14
Number of chromosomes in gametes: 7
Number of chromosomes after mitosis: 14
Organism – Cow
Number of chromosomes after meiosis: 30
Number of chromosomes in the body cells: 60
Number of chromosomes in gametes: 30
Number of chromosomes after mitosis: 60
Chromosome are made up of genetic material called DNA and it looks like a thread. It is present in the inside of nucleus of a cell.
During meiosis number of chromosomes would be reduced to half whereas in mitosis number of chromosomes remains the same.
The number of chromosomes in body cells is the chromosomal number of an organism and in gametes it would be reduced to half.
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Related Questions
Perform the followingmathematical operation, andreport the answer to thecorrect number of significantfigures.
Answers
To find out how many significant numbers there are in a number we can rely on a few rules:
1. Non-zero digits are always significant
2. Any zeros between non-zero digits are significant
3. Final zeros or trailing zeros are significant if they come after the non-zero numbers in a decimal number situation
Example: .500 and .632000
In this question, we have:
0.0016/0.849 = 0.0019, this is the correct value with the correct number of significant figures
Howmany Mol MnO3areproducedwhen 4.30 kg of O2completelyreactsaccordingtothebalancedchemicalreaction:2Mn(s)+3O₂(g)→2MnO₃(s)Answer as equation
Answers
Answer:
89.58 moles of MnO3 are produced.
Explanation:
1st) From the balanced reaction we know that the relation between O2 and MnO3 is that 3 moles of O2 produces 2 moles of MnO3.
2nd) To build the equation, we must build a path from the given value of 4.30kg of O2 to moles of MnO3. So, it is important to figure out the relations that we need to build the equation.
The order to build the equation is:
• Start with, the given value of ,4.30kg of O2,.
,• We need to convert kg to grams, so we need the realtion between kg and g: ,1kg=1000g,.
,• To convert the grams of oxygen to moles, we need to use the molar mass of O2: ,32g/1mol,.
,• We need to use the relation between O2 and MnO3 from the balanced equation: ,3 moles of O2, produces, 2 moles of MnO3,.
[tex]4.30kg\text{ O}_2*\frac{1000g}{1kg}*\frac{1mol\text{ O}_2}{32g\text{ O}_2}*\frac{2moles\text{ MnO}_3}{3moles\text{ O}_2}=89.58moles\text{ MnO}_3[/tex]So, 89.58 moles of MnO3 are produced.
Andrew wants to become a certified forensic pathologist. What is MOST likely to be true about his path to achieve this goal?
A.
It is fairly easy and doesn’t take a long time.
B.
There is no required residency or clinical fellowship.
C.
It requires a medical degree like a regular doctor.
D.
There are no schools that are currently offering this training.
Answers
Answer:
A
Explanation:
it is easy and doesn't take a long time
Calculate the volume of 0.875 mol/dm3 NaOH solution needed to make up a 100.0 ml of a diluted solution with a concentration of 0.235 mol/dm3 NaOH.
Answers
The volume of 0.875 mol/dm³ NaOH solution needed to make up a 100.0 ml of a diluted solution with a concentration of 0.235 mol/dm³ NaOH is 73.15 mL.
Given that :
molarity M1 = 0.875 mol/ dm³
M2 = 0.235 mol/ dm³
volume V2 = 100mL
using the formula , we get
M1 V1 = M2 V2
substituting the values in the formula we get :
0.875 × V1 = 0.235 × 100 mL
V1 = 26.857 mL
the volume added = V2 - V1 = 100 mL - 26.85 = 73.15
Thus, The volume of 0.875 mol/dm³ NaOH solution needed to make up a 100.0 ml of a diluted solution with a concentration of 0.235 mol/dm³ NaOH is 73.15 mL.
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11.A substance that is corrosive and that conducts electricity in water can be classified as which of the following?Select one:a. An acid only.b. A base only.c. Either an acid or a base.d. Neither an acid or a base.
Answers
Answer
acids and bases are both corrosive furthermore both will conduct electricity depending on the strength of the acid or base
C is the correct option
If the volume is 15 and the mass of water is 14.9 what is the density
Answers
Answer:
0.9933
(Text Text Text)
I dont understand how to find the one with smallest atomic radiusa. Calciumb. Cobaltc. potassiumd NickelI think its last one but why
Answers
Answer:
d. Nickel
Explanation:
The atomic radius is a periodic property, that is, we can see how it varies in the Periodic Table of Elements.
Atomic radius increases by a column (group) from top to bottom, and increases by a row (period) from right to left.
We can see the variation of atomic radius and the location of the given atoms in the following drawing:
Since K (potassium), Ca (calcium), Co (cobalt) and Ni (nickel) are located in the same row (period), to identify which one has the smallest atomic radius, we have to analyze the increase in horizontal atomic radius.
So, the Ni atom has the smallest atomic radius (because it is located more to the right compared to the other atoms in the same row) and K atom has the largest atomic radius.
HELP ASAP PLEASE. A legend is a traditional story that explains something in real life. Sometimes they are accepted as true, but sometimes they are fantastical and just plain fun. There are many legends that surround the North Star explaining its creation as well as why it is stationary.
Take some time to research some of the legends of the North Star. After you have had a chance to read several of them, create your own fantastical story of the North Star. It can be how it came to be or explain why it is stationary.
Answers
A legend of the North star goes as follows:
Once upon a time, when God was creating the universe, the curious star Tam once he learned that God was humans on earth, he began visiting humans. He became fond of one human. But each time he had to return to the sky, the human could not see him again. Therefore, he decided to remain stationary so that the human can always locate him.What is the North Star?The North star is a star that sits directly above the North pole of the earth. It is also known as Polaris.
The North star is especially significant in that the North star is an ever-present star in the skies. It neither rises nor sets unlike other stars in the skies.
Because of this special feature of the North star, it serves as a guiding beacon in the skies for travelers. Also, several legends have been told about the North star.
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What is the enthalpy change for the following reaction: C3H8(g) + 5O2 (g) --> 3CO2 (g) + 4H2O (l)ΔHof C3H8 (g) = -103.8 kJΔHof CO2 (g) = -393.5 kJΔHof H20 (l) = -285.8 kJ
Answers
The answer is -2219.9 kJ/mol
What volume of Cl2 gas, measured at 688 torr and 36 °C, is required to form 22 g of NaCl?Express your answer using two significant figures.
Answers
ANSWER
Volume of the gas 5.3L
EXPLANATION;
Given that
The pressure of the chlorine gas is 688 torr
The temperature of the chlorine gas is 36 degrees Celcius
The mass of NaCl is 22 grams
Follow the steps below to find the volume of chlorine gas
Step 1; Write a balanced equation for the reaction
[tex]\text{ 2Na + Cl}_2\text{ }\rightarrow\text{ 2NaCl}[/tex]In the above reaction, 2 moles of Na react with 1 mole of chlorine to form 2 moles of NaCl
Step 2; Find the number of moles of NaCl using the below formula
[tex]\text{ mole = }\frac{\text{ mass}}{\text{ molar mass}}[/tex]Recall, that the molar mass of NaCl is 58.44 g/mol
[tex]\begin{gathered} \text{ mole = }\frac{22}{\text{ 58.44}} \\ \text{ moles = 0.376 mole} \end{gathered}[/tex]Step 3; Find the number of moles of Cl2 using a stoichiometry ratio
Let x represents the number of moles of Cl2
[tex]\begin{gathered} 1\text{ mole Cl}_2\text{ }\rightarrow\text{ 2 moles NaCl} \\ \text{ x moles Cl}_2\rightarrow\text{ 0.376 moles NaCl} \\ \text{ cross multiply} \\ \text{ x moles Cl}_2\text{ }\times2\text{ moles NaCl }=\text{ 1 mole Cl}_2\text{ }\times\text{ 0.376 mole NaCl} \\ \text{ Isolate x} \\ \text{ x = }\frac{\text{ 1 mole Cl}_2\times0.376moles\cancel{NaCl}}{2moles\cancel{NaCl}} \\ \\ \text{ x = }\frac{1\text{ }\times\text{ 0.376}}{2} \\ x\text{ = }\frac{0.376}{2} \\ \text{ x = 0.188 mol} \end{gathered}[/tex]The number of moles of Cl2 is 0.188 mol
Step 4; Find the volume of the gas using the ideal gas equation
[tex]\text{ PV = nRT}[/tex]Convert the temperature to degree kelvin
[tex]\begin{gathered} \text{ t = 36}\degree C \\ \text{ T = 36 + 273.15} \\ \text{ T = 309.15 K} \end{gathered}[/tex]Step 5; Find the volume of the gas
[tex]\begin{gathered} \text{ PV = nRT} \\ \text{ Recall, that R = 62.363 L. torr mol}^{-1}K^{-1} \\ \text{ 688}\times\text{ V =}^{\text{ }}0.188\text{ x 62.636 }\times\text{ 309.15} \\ \text{ 688 V = 3624. 500} \\ V\text{ = }\frac{\text{ 3645, 500}}{688} \\ \text{ v = 5.3 L} \end{gathered}[/tex]Therefore, volume of the gas 5.3L
What is a molecular equation and what is this question asking please help?
Answers
In this question, we have a reaction between silver nitrate and potassium chloride, which will have the following chemical formula and also the following product:
AgNO3 (aq) + KCl (aq) --> AgCl (s) + KNO3 (aq)
Now we need to identify the ions that are components of the precipitate that was formed in this reaction
A precipitate is a product of a reaction that is not soluble in water in the conditions given in the reaction, therefore the precipitate will be a solid product of the reaction. The solid of the reaction is AgCl, therefore this is the precipitate
Now the ions that compose AgCl are Ag+ and Cl-, the answer will be the 3rd option
a sample of argon has a volume of 4.95 L and the pressure is 0.92 atm if the final temperature is 30 C the final volume is 5.7 L and the final pressure is .092 atm what was the initial temperature of the argon
Answers
The initial temperature of the argon is 2678 K
Given that,
Initial volume (V1) = 4.95 L
Initial pressure (P1) = 0.92 atm
Final temperature (T2) = 30 C = 303.15 K
Final volume (V2) = 5.7 L
Final pressure (P2) = 0.092 atm
We need to find the Initial temperature of the argon represented as T1
We Know that, In ideal gas law: PV = nRT
It can be written as, P1V1 / T1 = P2V2 / T2
(0.92 * 4.95) / T1 = (0.092 * 5.7) / 303.15
4.554 / T1 = 0.5244 / 303.15
4.554 / T1 = 0.0017
T1 = 4.554 / 0.0017
T1 = 2678 K
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need help on chem homework
What is the relationship between n, ℓ, and the total number of nodes?
The number of planar nodes = ℓ.
The number of spherical nodes = n - ℓ - 1.
Answers
The relationship between the number nodes, the energy level n and the azimuthal quantum number l is (n-l -1) + l. Thus the total number of nodes is n-1.
What is node?Node is the region or point in the orbital where the probability of finding an electron is zero. Electrons are revolving around circular paths of fixed energy levels.
The principal quantum number n represents the number of main shells or the energy level of the electrons. Whereas, azimuthal quantum number represents the number of orbitals denoted as l.
The point where there is a probability of finding an electron is called antinode. The total node in an orbital is the sum of number of planar nodes and number of spherical nodes.
Thus total number of nodes = (n-l-1) + l
= n - 1.
Therefore, the total number of nodes is n-1. For example for n=3 level there will be two nodes.
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What is the concentration of A pill weighing 325mg containing 22mg Mg
Answers
Step 1 - Understanding percentual concentration
To express the concentration of a substance as a percentual concentration, we just need to divide its mass by the total mass:
[tex]concentration\text{ in \% = }\frac{m_{substance}}{m_{total}}\times100[/tex]Step 2 - Calculating the concentration in the pill
We want to calculate the concentration of Mg in the pill. Therefore, we'll divide its mass by the total mass of the pill:
[tex]concentration\text{ of Mg =}\frac{22mg}{325mg}\times100=6.8\text{ \%}[/tex]Answer: the concentration of Mg in the pill is 6.8%
What is the specific heat capacity of methanol (C) if it takes 7,490 joules of energy to heat 50.0 grams from 10.0 0C to 80.0 0C?
Answers
The formula for calculating the amount of heat energy absorbed is given as:
[tex]Q=mc\triangle t[/tex]Given the following
• mass m = 50.0g
,• Heat energy Q = 7490 Joules
,• change in temperature = 80 -10= 70 degrees celsius
Substitute
[tex]\begin{gathered} 7490=50\times c\times70 \\ c=\frac{7490}{3500} \\ c=2.14J\text{/}g^oC \end{gathered}[/tex]Hence the specific heat capacity of methanol is 2.14J/gC
A student finds two green powders that look the same. He wants to figure out if the two powders are the same or different substances. Which of the following is
the best method to use?
I temperature of each powder
Mix the two green powders together and then test the properties.
Answers
A student finds two green powders that look the same he wants to figure out if the two powders are the same or different substances then mix the two green powders together and then test the properties
A powder is a dry bulk solid composed of many very fine particles that may flow freely when shaken or tilted and to figure out unknown two mixture powder are same or different then student want to mix the two green powders together and then test the properties because of properties student the two unknown powder are to be determined
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Read each question carefully and choose the letter of the best answer.
Answers
This element is nonmetal and appears in the periodic table.
The number that represents the position of the elements is called, the atomic number, it also represents the number of protons = numbers of electrons an atom has.
Answer: D. the atomic number
I keep getting 37.5 KPA but apparently that isn't the answer can anyone help?
Answers
ANSWER
The pressure of the gas is 281.25 mmHg
EXPLANATION
Given that;
The initial pressure of the gas is 75 mmHg
The intial temperature of the gas is 80K
The final temperature of the gas is 27 degrees Celcius
Follow the steps below to find the final pressure of the gas
Step 1; Convert the final temperature to degrees kelvin
[tex]\text{ T K = t}\degree C\text{ + 273.15}[/tex][tex]\begin{gathered} \text{ T K = 27 + 273.15} \\ \text{ T K = 300.15K} \end{gathered}[/tex]Step 2; Apply the Gay Lussac's law
[tex]\text{ }\frac{\text{ P1}}{\text{ T1}}\text{ = }\frac{\text{ P2}}{\text{ T2}}[/tex][tex]\begin{gathered} \text{ }\frac{\text{ 75}}{\text{ 80}}\text{ = }\frac{\text{ P2}}{\text{ 300.15}} \\ \text{ cross multiply} \\ \text{ 75 }\times\text{ 300.15 = P2 }\times\text{ 80} \\ 22511.25\text{ = 80 P2} \\ \text{ Divide both sides by 80} \\ \text{ P2 = }\frac{\text{ 22511.25}}{\text{ 80}} \\ \text{ P2 = 281.25mmHg} \end{gathered}[/tex]Write the two half-reactions that occur in this electroplating process. Be sure to include the states of the elements or ions.
Answers
Answer:
Explanation:
As the cell has a copper strip like the anode and a coin or nail (we can consider this like it is nickel) like the cathode, we can write both half-reactions:
• Copper half-reaction,:
[tex]Cu_{(s)}\leftrightarrows Cu_{(aq)}^{2+}+2e^-[/tex]In the copper anode, the oxidation reaction takes place. This is the positive terminal.
• Nickel half-reaction,:
[tex]Ni_{(aq)}^{2+}+2e^-\leftrightarrows Ni_{(s)}[/tex]In the nickel cathode, the reduction reaction takes place. This is the negative terminal.
The direction of the electron flow always go from the anode to the cathode.
Calculate the enthalpy of combustion (kJ/mol) of methyl linoleate (C₁₉H₃₄O₂), an important component of many biodiesel fuels made from corn oil and methanol, given the following standard enthalpies of formation: CO₂(g) = -393.5 kJ/mol H₂O(l) = -285.8 kJ/mol C₁₉H₃₄O₂(l) = -645.7 kJ/mol
Answers
Answer:
Explanation: 2 C19H34O2(l) + 53 O2(g) ==> 38 CO2(g) + 34 H2O(l) ... balanced equation
∆Hcombustion
∆H = ∑∆Hf products - ∑∆Hf reactants
∆H = [(38 x -393.5) + (34 x -285.8)] - (2 x -645.7) = (-14,953 + -9717) - (-1291)
∆H = -24,670 + 1291
∆H = 25,961 kJ
(be sure to check the math)
Two different signs that indicate a chemical action has occurred. What time is showing in the picture on the left what sign is showing on the picture in the right?
Answers
The reaction that occurs on the left is called a single displacemt reaction
find the natural logarithm of7.56
Answers
In a graph:
9 mol of A how many moles of C are formed upon complete reaction of
Answers
Answer:
C = 9 mol
Explanation:
Reaction: A + 2B ---> C
We want to find the moles of C.
Given: moles of A = 9 mol.
To solve this problem we will need to use stoichiometry.
A is the limiting reagent because it has a coefficient of 1 and B has a coefficient of 2.
The molar ratio between A and C is 1:1 therefore for every 9 moles of A that react, 9 moles of C will be produced.
0.650 moles of O₂(g) are added to 1.00 L flask and the internal pressure ismeasured at 20.00 atm. What is the temperature of the gas under theseconditions (in *C)? ________ °C?
Answers
1) List the known and unknown quantities.
Sample: O2
Amount of substance: 0.650 mol O2.
Volume: 1.00 L.
Pressure: 20.00 atm.
Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1)
Temperature: unknown.
2) Set the equation.
Ideal gas law.
[tex]PV=nRT[/tex]3) Plug in the known quantities and solve for T.
[tex](20.00\text{ }atm)(1.00\text{ }L)=(0.650\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})(T)[/tex][tex]T=\frac{(20.00atm)(1.00L)}{(0.650\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})}[/tex][tex]T=374.97\text{ }K[/tex]4) Convert K to ºC.
[tex]ºC=K-273.15[/tex][tex]ºC=374.94-273.15[/tex][tex]ºC=101.81\text{ }ºC[/tex]The temperature of the gas under these conditions is 101.81ºC.
.
Terrance found a small hair on the victim’s shirt. What type of evidence does this BEST represent?
A.
trace evidence
B.
biological evidence
C.
ammunitions evidence
D.
impression evidence
Answers
Answer:
Biological evidence, since it was a hair, which forms part of the human
Match each colored row or group on the table to the family of elements it represents.Green (2nd column)Red (1st column)Purple (two rows below the rest of table)Blue (3rd to 12th columns)?Alkali metals?Alkaline earth metals?Transition metals?Lanthanides and actinides
Answers
Green column - Alkaline earth metals
Red column - Alkali metals
Purple column - Lanthanides and actinides
Blue column - Transition metals
Explanations:
The red block are made up of group 1 elements and these elements are known as Alkali metals.
The green column are the group 2 elements in the periodic table and are known as the Alkali earth metals.
For the blue columns, they are element from group 3 to 10 and they are known as the transition metals.
For the purple column, they are Lanthanides and actinides
Propane (C3H8) is a component of natural gas and is used in domestic cooking and heating. It burns according to the following reaction:
C3H8 + O2 → CO2 + H2O
a. Balance the equation representing the combustion of propane in air.
b. How many grams of carbon dioxide can be produced by burning 20.0 pounds of propane, the typical size of a BBG grill propane tank?
Assume that oxygen is the excess reagent in this reaction.
Answers
A. The balanced equation for the reaction is given as
C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O
B. The mass (in grams) of carbon dioxide that can be produced by burning 20.0 pounds of propane is 27216.49 g
A. Balance equation
The balanced equation for the combustion of propane is:
C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O
B. How to determin the mass (in grams) of CO₂ produced
The mass (in grams) of CO₂ produced from the reaction can be obtained as follow:
Molar mass of C₃H₈ = (12 × 3) +(8 × 1) = 44 g/molMass of C₃H₈ from the balanced equation = 44 × 1 = 44 g = 44 / 453.592 = 0.097 poundMolar mass of CO₂ = 12 + (16 × 2) = 44 g/molMass of CO₂ from the balanced equation = 3 × 44 = 132 gFrom the balanced equation above,
0.097 pound of C₃H₈ reacted to produce 132 g of CO₂
Therefore,
20 pound of C₃H₈ will react to produce = (20 × 132) / 0.097 = 27216.49 g of CO₂
Thus, the mass of CO₂ produced is 27216.49 g
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Select the structure that correspondsto the molecule name:ethylmethylamineA.NHB. CH3CH₂NHCH3C. both
Answers
Ethylmethylamine is a secondary amine, that has one ethyl group attached to the amine group and one methyl group, which is a also attached to the amine group.
It is represented by:
Nevertheless it can be represented by CH3CH2NHCH3.
It means that the correct answer is c. Both.
determine the mass (in grams) of c4h10 that is required to produce 14.7 g co2
Answers
According to the stoichiometry, 4.85 g of propane is required to produce 14.7 g carbon dioxide.
What is stoichiometry?
It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.
Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.
In the given problem as per balanced equation of combustion of propane 2 molecules of propane produce 8 molecules of carbon dioxide.That is, 116.24 g of propane produces 352.08 g of carbon dioxide.
∴14.7 g of carbon dioxide is produced by, 14.7×116.24/352.08=4.85 g of propane.
Thus, 4.85 g of propane is required to produce 14.7 g of carbon dioxide.
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In the following equation, how many grams of CO2 are produced if 2 moles of O2 react completely with methane (CH4)? CH4 + 2O2 -> CO2 + 2H2OHELPFUL INFO: molar mass of CO2=44g/mol, molar mass of O2=32g/mol, molar mass of CH4=16g/mol, and molar mass of water = 18g/mol
Answers
Step 1 - "Reading" the equation
The given chemical equation is:
[tex]CH_{4(g)}+2O_{2(g)}\to CO_{2(g)}+2H_2O_{(l)}[/tex]The bigger numbers, those that come before the formulas of the substances, indicate the quantity in moles of each substance required in this rection.
We can "read" this reaction thus as :
one mole of CH4 reacts with 2 moles of O2 thus producing one mole of CO2 and two moles of H2O
As the exercise is specifically asking about the proportion between O2 and CO2, we can further simplify this statement to:
two moles of O2 produce one mole of CO2
Step 2 - Obtaining the "recipe" for the reaction
In order to obtain a relation in grams, we need to multiply the number of moles of each substance by its respective molar mass. Let's remember that:
two moles of O2 produce one mole of CO2
Therefore, converting to grams (molar masses: 32 g/mol for O2; 44 g/mol for CO2)
[tex]\begin{gathered} O_2\to2\text{ moles }\times32\text{ g/mole = 64g} \\ CO2\to1\text{ mole }\times44\text{ g/mole = 44g} \end{gathered}[/tex]We have now obtained the "recipe" for this reaction:
64g of O2 produce 44g of CO2
Pretty much as we would with a cake recipe, we can use this to predict how much CO2 is formed.
Since the reaction of two moles of O2 is exactly what we have already calculated, 44g of CO2 would be formed in this reaction.