A car travels 15m east, then 5 m north, then 15m west. What is the car's
displacement?

Answers

Answer 1

Answer:

5m north

Explanation:

The displacement of an object is its deviation from it initial position.

given that the initial position is

15m east and it moves 5m north

then 15m west

displacement is = 15+5-15

displacement is= 5m north

kindly see attached a rough sketch for your reference.

should you need further clarification let me know.

A Car Travels 15m East, Then 5 M North, Then 15m West. What Is The Car'sdisplacement?

Related Questions

A biker accelerates from rest to 10 m/s in 5 seconds. What is the biker's
acceleration? Calculate for the missing variable
Your answer

Answers

Answer:

It starts from rest so Vi=0

Vf=10 m/s

t=5 seconds

Explanation:

a=Vf-Vi/t

a=10-0/5

a=10/5

a=2m/s^s

In general, which factor is NOT critical when beginning an exercise program? A. using appropriate protective equipment during exercise B. finding friends who like to exercise the same way you do C. seeing your doctor for a physical assessment prior to beginning exercise D. choosing clothing that is designed to match your exercise program Please select the best answer from the choices provided.
O A
О В
O C
PLEASE HELP!!! ​

Answers

Answer:

B. I looked it up I hope it's right

Explanation:

i hope this helps.

Answer:

its obviously C

Explanation:

i smart like dat

What is the average speed of a motorcycle that goes 90 meters in 5 seconds?

Answers

Answer:18 m/s

Explanation:

Take=speed=distance /time

A Force of 20N displaces a body about 45m how much work is done?​

Answers

Answer:

159 ofc

Explanation:

159 is how much work is done to the body.

if the coefficient of friction is root 3 the angle of friction is ​

Answers

Explanation:

The coefficient of friction = tanθ,

 the angle would be 30∘

Answer:

Tan¯¹ /3=60 degree

Explanation:

you know coefficient is friction is equal to tan 0 equal to square root of 3 is equal to tan of civil 20 skills equal to 60 degree

_________________ are labels for ranges of weight that are greater than what is generally considered healthy for a given height.
A. Overweight and obesity
B. Overweight and morbidity
C. Obesity and diabetes
D. Obesity and heft

Answers

Answer: A. Overweight and obesity

Explanation:

Overweight and obesity are labeled for ranges of weight that are greater than what is generally considered healthy for a given height. Hence, option A is correct.

What are Overweight and obesity?

Overweight and obesity are calculated by Body Mass Index (BMI). BMI is a person's weight in kilograms divided by the square of height in meters. The healthy adult human BMI ranges from 18.5 to 25.

If BMI is less than 18.5, it falls within the underweight range. If the BMI ranges from 25.0 to 29.9, it falls within the overweight range. If the BMI is greater than 30, it comes under the obesity range. A high BMI indicates high fatness.

Obesity and overweight are determined as an abnormal growth or excessive fat accumulation in the healthy range. It is caused by an energy imbalance between calories consumed and calories expended.

Obesity and Being overweight can cause certain diseases and health issues. It increases the risk of high blood pressure, heart disease, diabetes, and stroke.

It is important to maintain a healthy range BMI. Obesity and overweight are reduced by making the choice of healthier foods and regular physical activities like yoga and exercise.

Hence, The correct option is A) Overweight and Obesity.

Learn more about Obesity, Overweight, and BMI:

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Which phrase is not an example of intracellular communication?
A. molecular movement within a cell
B. reaction to pheromones
C.molecule in a cell changes function of cell
D. control of cell division​

Answers

Answer:

The answer is C

Explanation:

I ave K12 and i just finished it.

The phrase which is not an example of intracellular communication is :

C) Molecule in a cell changes function of cell.

"Intracellular communication"

The phrase which is not an example of intracellular communication is the molecule in a cell changes function of cell.

The intracellular communication could be a sort of communication which takes put inside a cell or interior a cell.

The intracellular speaks to inside a cell, subsequently, the development of the particle inside a cell may be with cytoplasmic gushing, cargo vesicle transport or any other instrument will speak to the intracellular communication.

Thus, the correct answer is C.

Learn more about "Intracellular communication":

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What happens to the acceleration of an object if the net force on it increases?
OA. The acceleration increases.
OB.
The acceleration decreases.
O C.
The acceleration becomes zero.
OD.
The acceleration remains the same.

Answers

Answer:

A

Explanation:

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased

Help me I need this now

Answers

Answer:

If the height of the ramp is changed at a different height then the  speed of the car will change.

A car accelerates from rest at 7.55 m/s2 for 4.25 s.
Determine the final velocity of the car.
And calculate the cars displacement.

Answers

Explanation:

This problem is on the motion of a car.

given data.

acceleration a=7.55m/s

time t= 4.25 sec

1. Determine the final velocity of the car.

we know that

acceleration= velocity/time

substituting our given data we have

7.55= v/4.25

v=7.55*4.25

v=32.08m/s

2.  calculate the cars displacement.

we also know that

velocity= distance/time

distance= velocity*time

distance= 32.04*4.25

distance= 136.37m

An object example to decrease pressure.

Answers

Answer:

To reduce pressure - decrease the force or increase the area the force acts on. If you were standing on a frozen lake and the ice started to crack you could lie down to increase the area in contact with the ice. The same force (your weight) would apply, spread over a larger area, so the pressure would reduce.

Answer:

You can use the following things

Explanation:

Rubber ball - A rubber ball can decrease pressure if you throw it against the wall and catch it.

Rubber squeezy toy - If you squeeze this in your hands also you can decrease pressure.

Hope this helps....

Have a nice day!!!!

An object is projected with initial speed v0 from the edge of the roof of a building that has height H. The initial velocity of the object makes an angle α0 with the horizontal. Neglect air resistance. If α0 is 90∘, so that the object is thrown straight up (but misses the roof on the way down), what is the speed v of the object just before it strikes the ground?

Answers

Answer:

Explanation:

Initial velocity u = V₀ in upward direction so it will be negative

u = - V₀

Displacement s = H . It is downwards so it will be positive

Acceleration = g ( positive as it is also downwards )

Using the formula

v² = u² + 2 g s

v² = (- V₀ )² + 2 g H

= V₀² + 2 g H .

v = √ ( V₀² + 2 g H )

what are muons in cosmology ​

Answers

Answer:

Explanation:

Muons in the atmosphere, a component of cosmic rays. Atmospheric muons are an essential component of cosmic ray showers. When a high energy primary particle coming from space collides with a nucleus of the upper atmosphere, it generates a spray of particles which later interact in their turn.

Erica forgot to put gas in her car (again) for two weeks. The graph below shows the last few seconds of her car being stalled along Elkins Drive st 7:23 am Friday. During the time shown, what was the acceleration of her car?
a 54 m
b 108 m/s
c 3 m/s^2
D -3 m/s^2

Answers

Answer:

Option (D) : - 3 m/s^2

Explanation:

Acceleration = Slope of v-t graph

= 18/6

= - 3 m/s^2 (-ive since the car is decelerating )

Multiple Choice
Which of the following was not required by the Massachusetts Education Law of 1642?
O
Children were to be educated in basic religious principles and the laws of the commonwealth.
O Children were to be able to read and write.
O Children of servants were included in the law as recipients of said education.
Children were to be sent to designated schoolmasters for their learning.

Answers

Answer:

What was not required by the Massachusetts Education law of 1642 is;

Children were to be sent to designated schoolmaster for their learning

Explanation:

The Law of 1642 required that parents and master see to it that their children knew the principles of religion and the capital laws of the commonwealth.

The important aspects of the 1642 Law includes;

1) The responsibility for the basic education and literacy of a child are those of the parents and masters of child apprentices

2) Reading and writing competency of all children and servants are a requirement

3) It is the duty of the government, where a parent or master are unable to meet their tutoring responsibility, to see that a child is placed where the basic educational requirement will be met.

The role of a schoolmaster or the setting of a formal school were yet to be formed as at that time.

Answer:

The correct answer is Children were to be sent to designated schoolmasters for their learning

The responsibility of educating children was on parents and apprenticeship masters, not on designated teachers or schoolmasters. However, the law did allow the government to step in if the supervising adults failed in their responsibilities.

Explanation:

A force of 200N is creating a pressure of 50Pa on a surface. Calculate the area of the surface.

Answers

Answer:

4kg

Explanation:

pressure=50pa

force=200N

Area=?

now,

pressure=force/area

50=200/area

area=200/50

area=4kg

The pressure is the forces acting on a given area. Hence, the area of the surface with a pressure of 50 Pa by a force of 200 N is 4 m².

What is force?

Force is an external agent acting on a object to deform it or to change its state form motion or rest. Force is a vector quantity and it is characterised by its magnitude and direction. The unit of force is Newton (N).

Pressure is the force applied on unit area. Thus, as the force increases, pressure increases. Pressure can have the units in atm, pa, N/m² etc.

Pressure = Force / area.

Given that force = 200 N

pressure = 50 Pa = 50 N/m²

Therefore, area =  force/pressure

                          = 200 N / 50 Pa

                          = 4 m²

Therefore, the area of the surface is 4 m².

To find more on pressure, refer here:

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Sarah throws a ball directly upward at the edge of a cliff with a starting velocity of 3.0 m/s
It lands on the ground with a final speed of 6.0 m/s
How long is the ball in the air?
Round the answer to two significant digits

Answers

Answer:

The correct answer is t = 0.92s

Explanation:

Initial velocity v​0 = 3.0 m/s

Displacement Δy = ?

Acceleration a = -9.8m/s2

Final velocity v = -6.0m/s

Time t=? Target unknown

We can use the kinematic formula missing Δy to solve for the target unknown t:

V=v0+at

We can rearrange the equation to solve to t:

V-v0=at

t= v-v0/a

Substituting the known value into the kinematic formula gives:

t= (-6.0m/s)-(3.0m/s)

————————————

-9.8m/s2

= -9m/s

—————-

-9.8m/s2

=0.92s

Sarah throws a ball directly upward at the edge of a cliff with a starting velocity of 3.0 m/s.  It lands on the ground with a final speed of 6.0 m/s.

How long is the ball in the air?

Answer: 0.92

Matter is all around us and is made of atoms. How are atoms of different elements different from each other? How do these differences relate to their properties?

Answers

Answer:

it all depends on the protons and the neutrons of that element.

Find the velocity of a ball traveling 5 meters for 20 seconds.
Formula:
Substitute:
Solution:

Answers

Answer:

The answer is

0.25 m/s

Explanation:

The velocity of w given body given the distance and time taken can be found by using the formula

[tex]velocity = \frac{distance}{time} \\ [/tex]

From the question

distance = 5 m

time = 20 s

The velocity of the ball is

[tex]velocity = \frac{5}{20} = \frac{1}{4} \\ [/tex]

We have the final answer as

0.25 m/s

Hope this helps you

Formula: v = d/t

v = velocity

d = distance

t = time

We are given the distance (5 meters) and the time (20 seconds). Solve with these given values.

v = 5/20

v = 1/4 m/s

Best of Luck!

What is the mode of 3, 9, 11, 11, 3, 6, 2, 2, 11?
0
11
2
5,5

Answers

Answer:11

Explanation: because is the number that repeted 2 times

The answer is 11 its in the number set 3 times

What other angle would give the same range at 19 degrees?

Answers

Answer:

I think it is acute angle.

Explanation:

Because it is an angle between 0° and 90°. Hope this answer wil help you.

Answer: acute angle
Hope this helps :)

HELP ME PLZ ASAP ITS DUE ON MONDAY​

Answers

Answer:

the answer in the paper

Answer:

5a. 11m, 5b. 16m, 5c. 9m, 5d. 7m        6a. 3m, 6b. 0m, 6c. 2m, 6d. 5m

Explanation:

I hope this helped and plz make brainliest!

us
Is this an example of a theory or law? Planets orbit the sun
elliptically.
Theory
Law

Answers

The answer to your question is law.

How does the “Sum of Forces” help you?
pls helppppppppppppppp

Answers

The purpose of adding force vectors is to determine the net force acting upon an object.

Explanation:

maaf kalau saya salah pada jawaban anda

Explain the haudralic break system​

Answers

Answer:

A hydraulic braking system transmits brake-pedal force to the wheel brakes through pressurized fluid.

Explanation:

TEST
16. What is the average velocity of Mulan as
she covers 20 min 3.5 s to meet her
matchmaker?
0.175 m/s
10 m/s
70 m/s
5.71 m/s
CLEAR ALL

Answers

Yes yes sir yes I’ll dm is the day I get that I wanna go home and get my
R =8-0 jevzfh z9834vdjn t the Danzig

4.46 x 1010 /6.52x 10-8 =

Answers

Answer:

690.8895705521 × 10^8 is the perfect answer of your question.

A 95kg clock initially at rest on a horizontal floor requires a 560N horizontal force to set it in motion. After the clock is in motion, in horizontal force of 650N

Answers

Complete Question

A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.

Answer:

The value for static friction is [tex]\mu_s = 0.60[/tex]

The value for static friction is [tex]\mu_k = 0.70[/tex]

Explanation:

From the question we are told that

The mass of the clock is [tex]m = 95 \ kg[/tex]

The first horizontal force is [tex]F _s = 560 \ N[/tex]

    The second horizontal force is    [tex]F _k  =  650  \  N[/tex]

Generally the static frictional force is equal to the first  horizontal force

So

     [tex]F _s  =  m  *  g  *  \mu_s[/tex]

=>   [tex]560  =  95  *  9.8  *  \mu_s[/tex]

=>    [tex]\mu_s =  0.60[/tex]

Generally the kinetic frictional force is equal to the second horizontal force

So

      [tex]F _k  =  m  *  g  *  \mu_k[/tex]

      [tex]650 =  95  *  9.8  *  \mu_k[/tex]

     [tex]\mu_k =  0.70[/tex]

A cyclist must travel 800 kilometers. How many days will the trip take if the cyclist travels at an average speed of 16 km/h

Answers

Answer:

2 days 2 hours or 50 hours

Explanation:

800/16=50

PLEASE HELP ASAP!!!!

Answers

T1 = 2×W / squrt (3) +1

T2 = squrt(6) ×W/ squrt (3) +1

Here, T1 is along A.

T2 is along B

W = 250N.

Yo can directly use above formula to find solution.

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