D=44.13, Horizontal velocity is unimportant. The time it takes the cannon ball to fall to the ground is the key to determining the height of the cliff. where that cannon is present.
The speed of any projectile travelling along a Horizontal velocity is known as the horizontal velocity. When a particle or object is launched into the air at an angle other than 90 degrees, it moves along the trajectory path and changes the shape of the curve to a parabolic one.
the speed at which velocity changes over time. Due to its magnitude and direction, acceleration is a vector quantity. The first derivative of velocity with respect to time or the second derivative of position with respect to time are further examples. This is called acceleration.
Distance to the ground is d = 1/2gt^2,
where g is the acceleration rate of gravity (9.80665 m/s^2)
and t = 3 secs.
d = .5×9.80665×9 = 44.13 m.
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Answer: D=44.13, Vertical velocity is not significant. The height of the cliff can be calculated using the time it takes the cannonball to hit the earth. where there is that gun.
Explanation: The horizontal velocity is the rate at which any projectile is moving along a plane. A particle or object that is propelled into the air at an angle other than 90 degrees goes along the trajectory line and transforms the curve's shape into a parabolic one.
the rate of change of velocity over time. Acceleration is a vector number because of its size and directional characteristics. Additional examples are the second derivative of location with respect to time or the first derivative of velocity with respect to time. Here is
Distance to the ground is d = 1/2gt^2,
where g is the acceleration rate of gravity (9.80665 m/s^2)
and t = 3 secs.
d = .5×9.80665×9 = 44.13 m
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scientists are testing a transparent material whose index of refraction for visible light varies with wavelength as , where is in nm. if a 295-nm-thick coating is placed on glass for what visible wavelengths will the reflected light have maximum constructive interference?
The wavelength of the reflected light will have a range from 360 nanometers to 700 nanometers.
Constructive Interference may be defined as the process which occurs when the maxima of any two waves add up and the amplitude of the resulting wave will be equal to the sum of the two individual waves. According to the question thickness of coating, d = 295 nm and wavelength varies as n = [(30nm) ^1/2]/λ^1/2.
Also, the wavelength will be expressed as
λ = 2nd/M where M = 1,2,3......
λ = 2d[(30nm)^1/2]/Mλ^1/2
λ^3/2 = (d60nm^1/2)/M
λ = ∛d² 3600 nm/M
Now, if M = 1 then,
λ = ∛295² 3600nm/1 = 679.18 nm
Now, if M = 2 then,
λ = ∛295² 3600nm/2 = 679.18 nm
Now, if M = 3 then,
λ = ∛295² 3600nm/3 = 326.51 nm
So, the range is approximately 360 nm to 700 nm.
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Complete Question:
Scientists are testing a transparent material whose index of refraction for visible light varies with wavelength as n = 30.0 nm1/2 /l1/2, where l is in nm. If a 295-nm-thick coating is placed on glass 1n = 1.502 for what visible wavelengths will the reflected light have maximum constructive interference?
A student placed two magnets 5cm apart for a lab experiment. after completing two trials of the experiment, she leaves. when she returned, she noticed her magnets were moved just a little but decided to continue working with them anyway. after trying her 3rd trial of the lab, her magnets did not work. what happened?
The third trial of the lab experiment did not work out because in most probability the magnets lost their magnetic properties or got demagnetized.
Demagnetization is the phenomenon by which magnets lose their magnetic property or are weakened. We see that the magnets moved just a little after she left them after the first two trials of her experiment. It is possible that because the magnets moved a little they repelled each other and this only happens when like poles face each other.
The demagnetizing field of one magnet will affect the other and vice versa because their magnetic fields are opposite in direction. Consequently, magnetic field strength weakens gradually. Thus the magnets did not work after the 3rd trial.
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Two ice skaters stand facing each other at rest on a frozen pond. They push off against one another and the 49 kg skater acquires a speed of 2. 10 m/s. If the other skater acquires a speed of 3. 81 m/s, what is her mass in kilograms?
Her mass is approximately equal to 27 kilograms.
How do you prove that?First of all, you need to understand that momentum is a conserved quantity and the solution to this problem involves elastic collision.
Momentum can be defined as p = mv where p is momentum, m is mass, and v is velocity. Just like energy, momentum is a physical quantity that is conserved in an isolated system. Momentum is conserved as a result of Newton's third law, which states that [tex]F_A=-F_B[/tex].
You are given that the ice skaters bounce off each other, meaning the collision is elastic. Remember that in an elastic collision, m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂ where
m₁ is the mass of the first body, m₂ is the mass of the second body,u₁ is the initial velocity of m₁,u₂ is the initial velocity of m₂,v₁ is the final velocity of m₁, andv₂ is the final velocity of m₂.Suppose that m₁ = 49 kg, m₂ = x, u₁ and u₂ = 0 m/s, v₁ = 2.1 m/s, and v₂ = 3.81 m/s. Then the mass of the other ice skater is as follows:
49 · 0 + x · 0 = 49 · 2.1 + x · 3.81
0 = 102.9 + 3.81x
3.81x + 102.9 = 0
3.81x = -102.9
x ≈ -27
Since a mass value can't be negative, the absolute value of x is 27. Therefore, it's her actual mass in kilograms.
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a 68.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. he then drops through a height of 1.56 m, and ends with a speed of 8.51 m/s. how much nonconservative work (in kj) was done on the boy?
The non-conservative work done on the boy is 1.337 kJ
Given that,
Mass of boy, m = 68.1 kg
Initial speed of boy, u = 1,60 m/s
The boy then drops through a height of 1.56 m
Final speed of boy, v = 8.51 m/s
Now, we have to find the non-conservative work was done on the boy.
The Work done by the non-conservative forces is equal to the sum of total change in kinetic energy and total change in potential energy.
[tex]W=\frac{1}{2}m (v^{2}-u^{2})+(0-mgh)[/tex]
[tex]W=\frac{1}{2}m (v^{2}-u^{2})-mgh[/tex]
[tex]W=\frac{1}{2}(68.1) ((8.51)^{2}-(1.60)^{2})-68.1*9.8*1.56[/tex]
W = 1337.62 Joules
or
W = 1.337 kJ
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A bird flies at 10m * s ^ - 1 for 3s, 15m * s ^ - 1 for 3s, and 20m * s ^ - 1 for 4 Calculate the birds's average speed. A 4.5m * s ^ - 1 B 15m * s ^ - 1 C 15.5m * s ^ - 1 D 51.7m * s ^ - 1
The bird's average speed when he flies 10 m/s for 3 s, 15 m/s for 3s and 20 m/s for 4 s is 15.5 m/s. The right option is C 15.5 m/s
What is average speed?Average speed can be defined as the ratio of the total distance to the total time traveled by an object.
To calculate the average speed of the bird, we use the formula below.
Formula:
S = Total distance/total timeS = s₁t₁+s₂t₂+s₃t₃/(t₁+t₂+t₃)............. Equation 1From the question,
Givne:
s₁ = 10 m/st₁ = 3 ss₂ = 15 m/st₂ = 3 ss₃ = 20 m/st₃ = 4 s
Substitute these values into equation 1
S = [(10×3)+(15×3)+(20×4)]/(3+3+4)S = (30+45+80)/10S = 155/10S = 15.5 m/sHence, the average velocity of the bird is 15.5 m/s.
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a zoologist standing on a cliff aims a tranquilizer gun at a monkey hanging from a distant tree branch. th ebarrel fo the gun is horizontla. just as the zoologigtist pulls the trigger, the monkey lets go and begins to fall. will the dark hit the monkey? neglect air resistance
The Monkey captured Bryce's spirit inside a circle of salt inside a McDonald's bathroom stall and left after escaping from Lady Bullseye. After several weeks, he finally came back and set him free.
When injected, tranquilizer-filled darts fired by tranquilizer guns temporarily sedate a person or an animal so that they can be handled (or captured) safely. The tranquilizer may be a paralytic, sedative, or anesthetic. There is a long history of using tranquilizer weapons to capture wildlife without harm. The most frequent sensations are relaxation and sleepiness. Negative feelings, stress, or anxiety might also gradually fade away once the sedative starts to work. Your entire body could experience tingling, especially in your arms, legs, hands, and feet.
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a cliff diver steps off a cliff and hits the water 2.2 seconds later. How high was the cliff?
The height of the cliff is 24.2 m.
Let:
'h' be the height of the cliff'u' be the initial velocity of diver; u = 0m/s'+'ve been the annotation for the Downward directiona = 10m/s^2 be the approximation of acceleration due to gravityUsing the Second Equation of Motion:
[tex]h = ut + 1/2 at^{2} \\h = 0 + 1/2 (10)(2.2)^{2} \\h = 0 + 5(2.2)^{2} \\h = 5(4.84)\\h = 24.2m[/tex]
The Second Equation of Motion establishes a relationship between displacement and time. It can be used to calculate the displacement and time, in different conditions.
The cliff was 24.2m high above the water surface, into which the cliff diver dived.
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a 20kg is pulled along a horizontal surface by a fp of 50.on applied at 25 degrees angle above the horizontal. consider friction, and assume a coefficient of kinetic friction of 0.20. calculate the acceleration
The net acceleration of the block is about -2.04m/s².
The mass of the block is 20Kg. The force applied is 50 N and the angle at which the force is applied is 25°. The coefficient of friction is 0.20.
When the block will be pulled along horizontal by applying Force fat an angle A, then there will be two components of force one along vertical fsinA and one along horizontal fcosA.
The friction will be in opposite direction,
So, we can say, the net Force F on the block is,
F = Fr - fcosA
Ma = uN -fcosA
Where,
a is the acceleration of the block,
M is the mass of the block,
N is the normal force,
f is the applied force and,
u is the coefficient of friction.
Putting all the values,
20(a) = 0.2(50)sin(25°) - 50cos(25°)
20a = 0.2(0.42)(50)-50(0.9)
20a = 4.2 - 45
20a = 40.8
a = -2.04m/s².
The net acceleration of the block is -2.04m/s².
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In a resonance a turning fork of frequency 330hz produced the first loud sound when water level in a pipe was 17.8cm from the open-end ant the second at 57.3cm. calculate the wavelength of the sound, speed of sound in air, water level of the next resonant length ?
The wavelength, the speed of sound and the water level of the next resonant length (the fifth harmonics) are as follows;
The calculated wavelength of the sound from the tuning fork is 0.79 metersThe speed of the sound is 260.7 m/sThe water level of the fifth harmonics is 96.8 cmWhat is an harmonics of a sound wave?An harmonics are waves with a frequency that is an integer multiple of the fundamental frequency.
The given frequency of the sound wave, f = 330 hz
The first water level that gives the first loud sound, l₁ = 17.8 cm
The water level from the open end at the second loud sound, l₂ = 57.3 cm
First part;
The first harmonics that gives the fundamental frequency for the pipe is expressed as follows;
[tex]\dfrac{\lambda}{4} = l_1+e[/tex]
Where;
e = The distance to the antinode of the wave above the top of the pipe
The third harmonics is given by the formula
[tex]\dfrac{3\cdot \lambda}{4} = l_2+e[/tex]
[tex]\dfrac{3\cdot \lambda}{4}- \dfrac{\lambda}{4} = \dfrac{\lambda}{2} = (l_2+e) - (l_1+e) = l_2 - l_1[/tex]
[tex]\dfrac{\lambda}{2} = l_2 - l_1[/tex]
λ = 2 × (l₂ - l₁)
λ = 2 × (57.3 - 17.8) = 79
The wavelength of the wave, λ = 79 centimeters = 0.79 meters
Second part;
Speed of sound, v = f × λ
Therefore; v = 330 Hz × 0.79 m = 260.7 m/s
The speed of sound in air, v = 260.7 m/sThird part;
[tex]\dfrac{\lambda}{4} = l_1+e[/tex]
[tex]\dfrac{3\cdot \lambda}{4} = l_2+e[/tex]
Which gives; 3·(l₁ + e) = l₂ + e
3·l₁ + 3·e = l₂ + e
3·e - e = l₂ - 3·l₁
2·e = l₂ - 3·l₁
Therefore, 2·e = 57.3 - 3 × 17.8 = 2.9
e = 3.9 ÷ 2 = 1.95The water level for the next resonant length, which is the fifth harmonics, is given by the formula;
[tex]\dfrac{5\cdot \lambda}{4} = l_3+e[/tex]
Which gives;
[tex]l_3 = \dfrac{5\cdot \lambda}{4} - e[/tex]
Therefore;
[tex]l_3 = \dfrac{5\times 79 }{4} - 1.95 = 96.8[/tex]
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Both speed and velocity measure how fast something is moving. However, since speed is not a _________ it does not require a(n) ___________ .
Responses
A scalar, directionscalar, direction
B quantity, unitquantity, unit
C magnitude, unitmagnitude, unit
D vector, direction
a baseball player exerts a force of 100n on a ball for a distance of 0.5m as he throws it. if the ball has a mass of 0.15kg, what is its velocity as it leaves his hand?
This equation shows how the number of biscuits Olivia can bake is related to the amount of flour she has.
c = 15f
The variable f represents the number of scoops of flour Olivia has, and the variable c represents the number of biscuits she can bake. With 1 scoop of flour, how many biscuits can Olivia bake?
With 1 scoop of flour, Olivia can bake 15 biscuits if the the equation that shows the relation between number of biscuits and amount of flour is c = 15f.
c = 15 f
c = Number of biscuits
f = Number of scoops of flour
f = 1
c = 15 * 1
c = 15
This equation shows that number of biscuits that can be made is 15 times the number of scoops of flour. So if the number of scoops of flour is 1, the number of biscuits that can be made is 15.
Therefore, with 1 scoop of flour, Olivia can bake 15 biscuits
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Exciting the electrons in an iron increases the energy in the iron atom which can cause heating how might a magnetic field be used to excite electrons in atoms
Magnetic fields can be used to excite electrons in atoms because a magnetic field can pull or push electrons.
What is the effect of magnetic field on electron?Magnetic fields pull and push electrons which leads to the excitation of electrons. Metals have electrons that are loosely held together. Moving a magnet around a coil of wire around a magnet pushes the electrons in the wire that creates an electrical current. The magnetic force will not change the speed of an electron because the magnetic force is always perpendicular to the speed. Current in these coils causes the deflection of the electrons that is perpendicular to the magnetic field which is to the direction of the electrons.
So we can conclude that magnetic fields can pull or push electrons so that a magnetic field can be used to excite electrons.
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a 5.25-g bullet is fired into a 360-g block of wood suspended as a ballistic pendulum. the combined mass swings up to a height of 8.75 cm. what was the magnitude of the momentum of the combined mass immediately after the collision?
magnitude of the momentum of the combined mass immediately after the collision p = 0. 478 (kg. m/sec)
Mass of bullet : m = 5. 25 (g) = 0. 00525 (kg)
Mass of block : M = 360 (g) = 0. 360 (kg)
Height : h = 8. 75 (m) = 0. 0875 (m)
Here we need to find the momentum :
Now,
As we know that,
The conservation of energy :
Now,
Kinetic energy = Potential energy
= 1/2( m + M)v² = (m+M)gh (m,M is mass of bullet and block)
Now,
v = [tex]\sqrt{2gh}[/tex]
Now,
Momentum can be defined as :
Here,
p = (m+ M) [tex]\sqrt{2gh}[/tex]. . . eqn 1
Putting the values in eqn 1 :
We get,
p = 0.478 (kg. m/sec)
Hence, the momentum : p = 0. 478 (kg. m/sec)
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Hello! I am currently trying to answer this question. Could you provide the steps to help me solve it?
Given:
The length of the pipe is L.
The third harmonic has teh wavelength,
[tex]\frac{2L}{3}[/tex]To find:
The type of the pipe
Explanation:
The wavelength of the harmonics for a pipe closed at one end is,
[tex]\lambda=\frac{4L}{2n-1}[/tex]The wavelength of the harmonics for a pipe open at both the ends is,
[tex]\lambda=\frac{2L}{n}[/tex]Here,
[tex]n=1,\text{ 2, ......}[/tex]The given wavelength is,
[tex]\frac{2L}{3}[/tex]which resembles the form,
[tex]\frac{2L}{n}[/tex]Hence, the pipe is open at the other end.
an apple drops from a tree and hits the ground in 1.4 s how far does it fall?
It falls 9.8m far for the apple to drop from tree in 1.4sec.
Apple fall time t = 1.4 s
The free fall distance in time t is given by
d = 1/2at²
where a = g = 10 m/s² = free fall acceleration
calculation:
Using the above formula and the values given, the distance the apple will fall free in 1.4 seconds is
d = 1/2(10)(1.4)²
= 9.8 m
Therefore the distance um the apple will fall is 9.8 m.
Isaac Newton formulated gravitational theory in 1665 or 1666 after watching an apple fall. An apple falling from a tree is an example of Straight-line motion because gravity causes it to fall vertically in a straight line.
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a site was measured to have an average wind velocity of 5.2 m/s at 13m above ground. if the surface roughness exponent is assumed to be 0.23, what will the predicted wind velocity be at 32m above ground?
The wind velocity at 32 m above the ground is 6.39m/s when the roughness exponent of the surface is 0.23
Given in the problem is
Wind velocity at 13m above the ground v1 =5.2 m/s
Height initially h1 = 13m
height at which wind velocity is to be predicted h2= 32m
surface roughness exponent α = 0.23
Let velocity to be predicted be v2
We know that from the formula
v2= v1*(h2/h1)^α
⇒v2= 5.2 * (32/13)^ 0.23 = 6.39 m/s
Thus the wind velocity at 32m above the ground is 6.39m/s
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at the spinal tap concert in deware fieldhouse, nigel turns his guitar amp up to 11, blowing out the inductor on the subwoofer. what value of inductor would you grab from the lab if the speaker resistance is 4ohms and only frequencies below 250hz are desired? the speaker is a resistor.
The load a speaker provides on an amplifier is referred to as speaker impedance. That is, in fact, the result of speaker impedance.
Speaker impedance is defined as the "resistance" a speaker provides to the current delivered by an amplifier in technical terms.
The resistance is known as impedance because an amp's output current is AC (as opposed to DC, like from a battery), not DC. To be completely technical, impedance is the result of adding any reactance present in an AC circuit to DC resistance.
Just keep in mind that speaker impedance impacts how much current is drawn from the amplifier without getting too technical.
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10. Unless a light ray comes into contact with a surface or enters a different material, it travels in a
Unless a light ray comes into contact with a surface or enters a different material, it travels in a straight line.
When light enters a medium with a different speed or transitions from a fast to a slow medium, refraction occurs. According to Snell's law, if a light ray is incident ordinarily on the surfaces, then deviating from the normal will always lengthen the travel time.
Theoretically, sine (angle of incidence)*index of refraction of the incident media = sine (angle of refraction)*index of refraction of the refractive medium
Sine (0)=0 because the angle of incidence is 0 degrees.
As a result, the light ray will travel straight.
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If Earth's circumference at the
equator is 40,070 km, what is the
speed of the stationary satellite
GOES above the equator in km/
hour? (Use the formula: Speed =
Distance/Time)
The stationary satellite crosses the equator at a speed of 1180 kilometres per hour.
How does speed at the equator get calculated?At the equator, where the Earth's circumference is 40,070 kilometres and the day lasts for 24 hours, the speed is 1670 kilometres per hour (1037 miles per hour). This slows down by the latitude's cosine, so at a latitude of 45 degrees, cos(45) =. 707, and the speed is. 707 x 1670 = 1180 kilometres per hour.
How fast would a student travelling at the equator while seated on Earth's surface?
The daily motion felt on our earth is brought on by this spinning. You would move at almost 1,000 miles per hour (1,600 km/hr) if you were standing on the equator of the Earth, but your pace would slow down if you started moving in the direction of the North or South Poles.
A latitude of 45 degrees, cos(45) =. 707, and the speed is. 707 x 1670 = 1180 kilometres per hour.
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a horizontal rifle is fired at a bull's-eye. the muzzle speed of the bullet is 655 m/s. the gun is pointed directly at the center of the bull's-eye, but the bullet strikes the target 0.029 m below the center. what is the horizontal distance between the end of the rifle and the bull's-eye?
The horizontal distance between the end of the rifle and the eye of the bull is equal to 50.35 m.
What are the equations of motion?The equations of motion can be described as the equations which set up the relationship between the velocity of the object, the acceleration, time, and distance of the moving object.
Consider that a vector r, which describes the position of the bullet when it reaches the target, is composed of [tex]r_x[/tex] and [tex]r_y[/tex]
[tex]r = (r_x, r_y)[/tex]
Given that [tex]r_y[/tex] is -0.029 m (the reference is located at the end of the rifle),
r =([tex]r_x[/tex], -0.029 m)
The vertical position of the bullet at time 't' can be written in form of an equation as follows:
[tex]y = (y_o +v_oy) t + \frac{1}{2} g t^2[/tex]
The vertical component of the speed at t = 0 is 0, then, acceleration, v₀y = 0 and y₀ = 0.
Then, we can find the time for the vertical position (y) of bullet -0.029 m:
-0.029 m =(0)t - (1/2) · (9.8 m/s²) · t²
t = 0.077 sec
The equation for the horizontal position can be written as:
x = x₀ + (v₀x) · t
Since the origin of the reference system is located at the bullet starts its trajectory, x₀ = 0.
x = (v₀x) · t
x = (655) × 0.077 = 50.35m
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Someone is standing on a trampoline. They have a mass of 65kg and each of their feet a 25cm x 10cm, what is the pressure exerted by both on the trampoline?
The pressure exerted by both on the trampoline is 25,480 N/m².
What is the pressure exerted?The pressure exerted by both on the trampoline is the force per unit area which is calculated as follows;
P = F/A
where;
F is the force applied by their weight A is the area of their feetP is the pressure exertedSubstitute the given parameters and solve for the pressure exerted.
P = (mg)/A
A = 0.25 m x 0.1 m
A = 0.025 m²
P = (65 x 9.8) / (0.025)
P = 25,480 N/m²
Thus, the pressure exerted at any given surface depends on the applied force and the area of the given surface.
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similar to the case in the experiment you use two rubber bands, side to side first, to hold a weight of 3 reference objects. then, as in the experiment, the bands are pulled apart in their free ends until they form an angle of 30 degrees with respect to the horizontal. what are the deformations observed in these bands? ...
Three units deformations observed in these bands.
What forces do a rubber band encounter?Elastic force is the force that permits some materials to regain their former shape after being stretched or crushed. Thus, a stretched rubber band is subject to an elastic force.
The rubber band experiment uses a straightforward rubber band to show entropic force and a refrigeration cycle. The rubber band experiment involves stretching and then releasing a rubber band while measuring its temperature.
Always acting in the opposite direction of motion is friction. This indicates that if friction is there, it cancels out some of the force driving the motion (if the object is being accelerated). This results in a decreased acceleration and a smaller net force.
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What is the main reason sea level is rising?
A: Ice Melting
B: Thermal Expansion
The main reason for the sea level rise is the melting of the ice, as the icebergs are melting due to the increase in the average temperature of the earth, therefore the correct answer is option A.
What is thermal energy?It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.
Thermal expansion is unrelated to the sea level rising.
Since icebergs are melting due to an increase in the earth's average temperature, melting ice is the primary cause of sea level rise, therefore the correct answer is option A.
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What is the magnitude of the force that must be applied for the system below to be balanced?
Answer:
20 N
Explanation:
logically it'd be 20 N due to the fact that it's a rectangular shape. You pretty much look at the counterpart and copy and paste it to the other side.
Ida Haitarun is captain of the Varsity cross country team. During the after-school practice on Tuesday, he led the team on the following run from school to a nearby park. From the road, he ran at a 20 degree angle North of East for 8 miles. Determine how far east and how far north they are from where they started.
The displacement of the team is 2.74 miles due east and 7.52 miles due north from where they started.
What is the eastward displacement of the team?
The eastward displacement of Ida Haitarun and his team during the cross country race is calculated by forming a right triangle from the displacement of the team.
The angle of inclination of the displacement is calculated as follows;
θ = 90⁰ - 20⁰ = 70⁰ (above the horizontal)
The eastward displacement is the base of the triangle and it is calculated as follows;
cos θ = base / hypotenuse side
cos 70 = base / 8 miles
base = (8 miles) x (cos 70)
base = 2.74 miles
The northward displacement is calculated as follows;
sin θ = height / hypotenuse side
sin 70 = height / 8 miles
height = (8 miles) x (sin 70)
height = 7.52 miles
Thus, the team is 2.74 miles due east and 7.52 miles due north from where they started.
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PLEASE HELP ME!
What holds the protons together in the nucleus?
A. electrons
B. anions
C. cations
D. neutrons
Answer:
neutrons.........................
a box of books with mass 40 kg rests on the level floor of the campus bookstore. the floor is freshly waxed and has negligible friction. a bookstore worker applies a constant horizontal force with magnitude 25 n to the box. what is the magnitude of the acceleration of the box?
The magnitude of the acceleration of the box is = 0.625 m/s²
Friction is the pressure resisting the relative movement of strong surfaces, fluid layers, and material elements sliding in opposition to each other. There are numerous kinds of friction: Dry friction is a pressure that opposes the relative lateral motion of strong surfaces in touch.
Pressure is a power that could exchange the movement of an object. A pressure can reason an item with mass to alternate its speed, i.e., to boost up. pressure also can be defined intuitively as a push or a pull. A force has each magnitude and course, making it a vector amount.
Acceleration is the price of trade of the rate of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by way of the orientation of the net force performing on that object.
Force = mass × acceleration
acceleration = force / mass
= 25 / 40
= 0.625 m/s²
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a car is traveling at 100 mph down the highway. at some time the driver sees an obstruction in the road and slams on the brakes skidding to a halt reducing its kinetic energy to zero. what happened to the kinetic energy of the car?
The kinetic energy is changed to thermal energy by brake friction and turns to zero.
We need to know about kinetic energy to solve this problem. Kinetic energy is the energy from a moving object. It can be determined as
KE = 1/2 . m . v²
where KE is kinetic energy, m is mass and v is speed.
From the question above, we know that
v1 = 100 mph
KE2 = 0 joule
When the car moves at 100 mph, the car has kinetic energy. But on the way when the driver brakes the car, the kinetic energy is changed to thermal energy by brake friction. Hence, the kinetic energy is reduced every time and finally turns to zero.
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In 1993 itleana salvador at italy walked 30 km under 12 min suppose that during 115m at her walk she steadly increased her speed from 42m/s to 5m/s how long does it increase took
When acceleration is constant, we may connect displacement to time and velocity, two of the other three parameters that describe motion, using the following three equations: d = ( 1 2 ) ( 1 2 ) (v f + v I (t) (Equation 1) D = v I t + a t + 1 2 (Equation 2) V I 2 + 2 a d = v f 2 (Equation 3).
Defining displacement If acceleration is constant, then?Displacement is directly proportional to the square of the length of the linear motion when acceleration is constant and beginning velocity is zero.
Solution:-
vi =+245km/h
aavg = -3.0m/s2
vf =vi -(0.200)vi
vi =(245km/h)(1h/3600s)(103m/1km)= +68.1m/s
vf =(1.000-0.200)vi =(0.800)(68.1m/s)=+54.5m/s
Δt=vf -vi /aavg
= 54.5m/s - 68.1m/s / -3.0m/s2
=-13.6m/s /-3.0 m/s2
= 4.5s
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