A cannonball is shot horizontally off a 10.5 m high castle wall at 47.4 m/s. How far from the base of the wall does the cannonball land?

Gravity helps to widen the valley of the Colorado River through the Grand Canyon through the forces which increases the pressure thereby leading to it being eroded.

This is referred to as the force of attraction which occurs on objects which draws them toward the center of the planet.

Gravity acts downwards on all bodies on earth which is why the Colorado River erodes downward. This then results in the movement of materials from high to low areas.

This the leads to the continual widening of the valley of the Colorado River through the Grand Canyon and is therefore referred to as the most appropriate answer.

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Answer:

21.4 g/cm3

Explanation:

A third positive charge [tex]x = \frac{2\sqrt{2}a }{1+\sqrt{2} }[/tex] can be placed on the x-axis so that the net electric force on it is zero.

whilst -factor charges are in touch, there may be

[tex]F = k \frac{q_{1}q_{2} }{ r^{2} }[/tex]

Where

[tex]k = 9 * 10^{9} Nm^{2}C^{-1}[/tex] = the coulomb constant.

The charges' magnitudes are [tex]q_{1}[/tex] and [tex]q_{2}[/tex].

r is the separation of the charges.

Let,

The third charge equals Q at, x equals x from the source.

because there is no net force acting on the third charge.

Hence,

[tex]f_{1} + f_{2} = 0[/tex]

⇒ [tex]k\frac{(2q)Q}{x^{2} }-k\frac{qQ}{(2a-x)^{2} } = 0[/tex]

⇒ [tex]\frac{2}{x^{2} } - \frac{1}{(2a-x)^{2} } = 0[/tex]

⇒ [tex]\frac{2}{x^{2} } = \frac{1}{(2a-x)^{2} }[/tex]

⇒ [tex]\frac{\sqrt{2} }{x} = \frac{1}{2a-x}[/tex]

⇒ [tex]2\sqrt{2}a - \sqrt{2} = x[/tex]

⇒ [tex]x = \frac{2\sqrt{2}a }{1+\sqrt{2} }[/tex]

handiest when forces resulting from previous prices cancel every different out will the pressure on a third fee be 0.

at the same time as the pressure between  identical costs is repulsive and is interpreted as high-quality, the pressure between two opposing expenses is attracted and is interpreted as bad.

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80Sec or 1.33 min time taken by train to cross a bridge with a uniform speed of 36 kmph.

Given data,

length of bridge = 600m

length of train = 200m

Length of bridge + Length of train is the total distance travelled by train to cross the bridge.

So, 600+200 = 800m = 0.8km

Now, applying the formula for time,

[tex]time =\frac{distance}{speed}[/tex]

[tex]time = \frac{0.8}{36}[/tex]

time = 0.022hours

time in seconds= 0.022×60×60

time in seconds= 1.33×60

time in seconds= 80seconds

Therefore, 80Sec or 1.33 min time taken by train to cross a bridge with a uniform speed of 36 kmph.

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The magnitude of the acceleration attained by the tool will be [tex]0.2\frac{m}{s^{2} }[/tex]

It is given that the force is acting upon a tool that attains an acceleration. The tool has a certain mass. We know that Force is calculated by the product of mass and acceleration of the object which gives us the following equation:    =>  F = m*a, where F = Force, m = Mass of the object, and a = acceleration attained by the object.

Sp, F = 16N, M = 80 kg, and acceleration = a

Putting these values into the Formula to calculate Force we get :

                 => F = ma    => 16 = 80*a  => a = 16/80

                 => a = 0.2

Hence, we get Acceleration a = [tex]0.2\frac{m}{s^{2} }[/tex]

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The car will take 32.5 seconds to exceed the 65mph.

The speed of a car with a turbo engine can be modeled as a function of time using the parabolic equation

s(t) = 2t

We need to find the time taken by the car to exceed the 65 mph.

Put s(t) = 65 mph

65 = 2t

t = 32.5 seconds

The additional compressed air is then forced into the combustion chamber by a turbine that is powered by the exhaust gas of the turbocharged engine. On the other hand, a supercharged engine employs a mechanically-driven process. This kind of charger is often driven by a crankshaft-mounted belt.

In terms of performance and efficiency, a turbocharged engine is superior to a standard engine. The power output of a smaller capacity turbo engine is equivalent to that of a bigger capacity NA engine.

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Answer:

we will feel unstable on the skates. Because the recoil force pushes us forward, and affect our balance

Answer:

4. y = 2.38333t - 26.55 is the answer.

The magnitude of the resultant velocity of the soccer ball is: 25.059 m/s

The formula for projectile motion that we will use to solve this exercise is:

vf= √[v(x)² + v(y)²]

Where:

Information about the problem:

Applying the final velocity formula we have:

vf= √[v(x)² + v(y)²]

vf= √[(22 m/s)² + (12 m/s)²]

vf= √[484 m²/s² + 144 m²/s²]

vf= √[628 m²/s²]

vf= 25.059 m/s

The projectile motion is the motion whose trajectory describes a parabola having a horizontal and a vertical component of motion.

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Answer: 6 km

works on odyseyware

The answer would be  is 6 km

I will store carolina distance learning kit box in a refrigerator.

To increase their shelf life, they should be refrigerated as soon as they arrive. Keep the lyophilized cultures away from youngsters in a sealed, labeled plastic bag.

Bacteria must be suspended in a medium that supports their viability during freezing, water removal, and subsequent storage if they are to be preserved by lyophilization.

The vials should be put within a freeze-dryer chamber, and the chamber should be vacuumed as directed by the manufacturer. Give the culture enough time to fully lyophilize (dry out).

Water is removed from a product after it has been frozen, and it is then placed in a vacuum, allowing the product to convert directly from solid to vapor without going through a liquid phase. This process is known as lyophilization or freeze drying.

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The thickness of the single sheet of paper is 6.30 × 10-5 m

The thickness can be defined as the measure of the distance between the two surfaces of an object.

It is usually the smallest of three dimensions i.e., length, width, and thickness.

In order to obtain the practical (not the theoretical) thickness of a sheet of paper, the best way would be using a micrometer, dial caliper, or a paper thickness gauge. There is digital as well as analog models of these instruments that can be used while measuring the thickness.

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Answer:  Atoms cannot be created nor destroyed, and they are indestructible; they cannot be broken into smaller parts. This was based on the Law of Conservation

Explanation: hope this helps you a little!!

By applying the specified constant pressure, the system's work done to reduce its volume from start to final is 32 l atm.

Initial volume v1 = 17.0  l

final volume v2 = 9.0 l

Pressure P= 4.0 atm

When a gas expands, there is an amount of work that is done that is equal to the product of the gas's pressure and its volume change.

We apply the formula for work done by gas against a constant external pressure.

expression: Work done = -(P. d V)

Therefore substituting the values :

Work done = - P (v2 - v1)

= - 4.0 x (-8.0) l atm

= 32 l atm.

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An object has a 2 c charge. the object breaks into two pieces. one piece has a charge of -5 c is 7

Charge is the traveling longitudinal wave energy. Mass and charge are the indeed related and can be simplified to a single energy equation. To relate mass and charge, Coulombs can be explained as the wave amplitude, which is measured as a distance (meters).  If one assumes a substance in vacuum of space that has a physical property of kilograms, and moves as waves, then mass and charge can be described as their motion.  In EWT, this substance is referred to as the ether and its components as granules.

Let's call Q the initial charge of object, which is:

Q=2c

When it breaks, two pieces will have charge  and , and since the total charge must be conserved, the sum of these two charges must be equal to the initial charge of the object:

Q=Q1+Q2

We also know charge of one of the two pieces:

Q1=-5

So, by substituting Q and Q1 into the equation, we can find charge of the second piece, Q2:

Q2=Q-Q1=2-(-5)=+7

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The Grand Canyon is 884 m deep from the spot where I heard the echo

The formula for uniformly rectilinear motion (URM) and procedure we will use to solve this exercise is:

v = x /t

Where:

Information about the problem:

Notice that the echo is a sound that is produced when its wave hits an object (Grand Canyon) and returns to the place where it was emitted (person), that is to say that to calculate the time in which the echo arrived effectively to the bottom of the canyon we must divide it by 2.

t(canyon's bottom) = t(echo)/2

t(canyon's bottom)  = 5.2 s/2

t(canyon's bottom)  = 2.6 s

Applying the velocity formula, and isolating the distance, we get:

v = x /t(canyon's bottom)

x = v * t(canyon's bottom)

x = 340 m/s * 2.6 s

x = 884 m

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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The correct answer is true.

The algebraic sum of the inverses of the individual resistances is then the inverse of the equivalent resistance of two or more resistors linked in parallel.

The total or equivalent resistance, RT, is equal to half the value of one resistor if the two parallel resistances or impedances are equal and of the same value. That is equivalent to R/2, R/3, etc., for three parallel resistors of identical value.

The total resistance, RT, will always drop when more parallel resistors are added since the equivalent resistance is always smaller than the smallest resistor in the parallel network.

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The simple solution is to count all the integers that only have odd digits and subtract them from 900. Final solution: 900 – 125 = 775.

Odd and even numbers have opposite parities, therefore 13 is an example of an odd number. In particular, zero has an even parity. The parity of any pair of consecutive integers is opposite. The last digit of an integer stated in the decimal numeral system determines whether the value is even or odd. That example, an odd number is one where the last digit is one, three, five, seven, or nine; otherwise, an even number is one where the last digit is one, two, four, six, or eight.

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The point where the electric field is zero is situated at a distance of 0.056 meters or 5.6 centimeters from the 1.7 uC charge.

The electric field(E) due to a charge is given by the formula,

E = KQ/r^2

For a point where the electric field is zero, the magnitude of the field due to two charges should be equal so that they cancel each other

Hence, the field produced due to 1.7 uc at the point should be equal to the field produced by the 2.5 uc charge.

Let the distance of the point where the electric field is zero be x from the 1.7 uc.

So, the distance of the point where the field is zero will be (0.125 - x) from 2.5 uc.

K(1.7uc)/x^2 = K(2.5uc)/(0.125 - x)^2

Solving the above equation

x comes out to be 0.056 meters or 5.6 centimeters.

Hence, The point where the electric field is zero is situated at a distance of 0.056 meters or 5.6 centimeters from the 1.7 uC charge.

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The point where the electric field is zero is situated at a distance of 0.056 meters or 5.6 centimeters from the 1.7 uC charge.

The electric field(E) due to a charge is given by the formula,

E = KQ/r^2                                            equation 1

For a point where the electric field is zero, the magnitude of the field due to two charges should be equal so that they cancel each other

Hence, the field produced due to 1.7 uc at the point should be equal to the field produced by the 2.5 uc charge.

Let the distance of the point where the electric field is zero be x from the 1.7 uc.

So, the distance of the point where the field is zero will be (0.125 - x) from 2.5 uc.

Substitute the values of charges in equation1 and equate the equations for two different charges,

K(1.7uc)/x^2 = K(2.5uc)/(0.125 - x)^2

(1.7uc)(0.125 - x)^2 = (2.5uc) x^2

On simplifying the above equation

x = 0.056 meters or 5.6 centimeters.

Hence, the point where the electric field is zero is situated at a distance of 0.056 meters or 5.6 centimeters from the 1.7 uC charge.

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A ball hits a wall going 10 m/s, and bounces off going 8 m/s. the coefficient of restitution is

Given that

To find

So according the question

We have

                       u = 10 m/s.

                      v = 7 m/s.

Now, We have to find the coefficient of restitution

We know that,

         [tex]n = \frac{velocity \;\;of \; \;separation}{velocity \;of \;approach}[/tex]

So,

             [tex]n = \frac{8}{10}[/tex]

              n = 0.8

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1.15.42 Loudness of sound is the power emitted by the burper during his record burp.

Decibels: 112.4

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The angle of refraction in the glass is 30°.

i= 50°

u= 1.50

u1sini=u2sinr

⇒sinr =[tex]\frac{sin 50}{1.5\\}[/tex]

=0.50=1/2

so angle r = [tex]sin^{-1}[/tex](0.5) =30°

Then we have to calculate r final.

[tex]u_{glass}[/tex]sini= [tex]u_{air}[/tex] sinr

⇒ r = [tex]sin^{-1}[/tex] (1.5 x [tex]\frac{\sqrt{3} }{2}[/tex])

[tex]sin^{-1}[/tex](1.29) = 0.0225

Then the displacement can be calculated as follows:

T= thickness = 5cm

s= t (1- 1/u)

s= 2cm

Thus, all the values have been found out.

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Vacuum tubes enjoy numerous upper hands over semiconductor gadgets in applications between 300 MHz and 300 GHz.

A vacuum tube, electron tube, valve (English use), or cylinder (North America), is a gadget that controls electric flow stream in a high vacuum between terminals to which an electric potential distinction has been applied.

The sort known as a thermionic cylinder or thermionic valve uses thermionic emanation of electrons from a hot cathode for basic electronic capabilities like sign intensification and current correction. Non-thermionic sorts, for example, a vacuum phototube, notwithstanding, accomplish electron outflow through the photoelectric impact, and are utilized for such purposes as the discovery of light powers. In the two sorts, the electrons are advanced from the cathode to the anode by the electric field in the cylinder. Sound power speaker utilizing tubes, in activity. Red-orange sparkle is from warmed fibers. Delineation addressing a crude triode vacuum tube and the polarities of the run of the mill dc working possibilities. Not shown are the impedances (resistors or inductors) that would be remembered for series with the C and B voltage sources.

Every group of vacuum tubes (triodes, tetrodes, and their subordinates including magnetrons, klystrons, crossed field speakers, voyaging wave tubes and gyrotrons) have their own qualities as far as working recurrence, quick data transmission, top power, mean power, gain (enhancers), electrical proficiency, linearity, dependability and lifetime. This makes it simpler to choose the most reasonable vacuum tube for a given application.

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The muzzle velocity of the bullet is 510.3 m/s.

The projectile's speed when it exits the gun's muzzle is known as muzzle velocity.

The quality (burn speed, expansion) and quantity of the propellant, the mass of the projectile, and the length of the barrel all affect the muzzle velocity of conventional firearms. While a slower burning propellant can use a heavier projectile, it requires a longer barrel to burn completely.

Apply the kinematics equation,

v=u+at

Here v is the final velocity, u is the initial velocity, a is the acceleration and t is the time interval during which a body is under acceleration.

The muzzle velocity of a bullet is the velocity with which the bullet leaves contact with the barrel of the gun.

The muzzle velocity or the final velocity of the bullet will be

v=u+at

v=0+(6.3×[tex]10^{5}[/tex])(8.1×[tex]10^{-4}[/tex])
=50.3 m/s

Therefore, the muzzle velocity of the bullet is 510.3 m/s.

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Jorge was driving at 20m/s. He accelerated at a rate of 2m/s² for 10s.

So he travel ---m during this time.

Jorge was driving at 20m/s, so speed = 20 units

He accelerated at a rate of 2m/s² so acceleration = 2 units

Time taken by Jorge is 10 units.

We know by Newton's 2nd equation of motion that

S= ut + (1/2)*a*t*t

where S is distance, a is acceleration, u is initial velocity and t is time.

So S=?

Time t = 10

Acceleration a =2

Initial Velocity u = 20

Hence distance travelled by Jorge is S=300 m

Thus Jorge travelled 300m during this time  at speed 20m/s accelerated at a rate of 2m/s² for 10s.

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If a sample's absorbance reading is higher than 1.0 when being measured with a UV-vis spectrometer, it must be diluted in order to obtain a lower absorbance value.

The logarithm of light transmission (T) through a sample is known as absorbance. Transmission is the difference between the amount of light that passes through a sample and a blank in intensity (I) (Io). Thus, absorbance equals log (Io/I).

At an absorbance of 2, you are at 1%T, which denotes that the sample is blocking (absorbing) 99% of the light that is available. When you have an ABS of 3, you are at 0.1% T, which means that the sample is blocking (absorbing) 99.9% of the light that is available. These ranges fall outside of spectrometers' useful range.

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A business entrepreneur has a product or service for the business world, a Social one has ideas for social change, a Serial one has multiple startups and a Lifestyle one starts up their business due to their lifestyles.

A business entrepreneur starts new business with his own money. Some of the famous business entrepreneurs are Steve Jobs, Mark Zuckerberg and Bill Gates. A social entrepreneur develops solutions for social issues and directly addresses them. For example, microfinancing institutions provide banking services to low - income and unemployed people.

A serial entrepreneur can create ideas into successful businesses on a regular basis. They do not stop at one business. Elon Musk is a great example of a serial entrepreneur. A lifestyle entrepreneur creates business to change their lifestyle. A lifestyle entrepreneur does not necessarily make profits. Blogging and photography are some of the examples of lifestyle entrepreneurship.

Therefore,

1. Business Entrepreneur - Has an ideal, product or service for the business world

2. Social Entrepreneur - Has to innovative ideas for social change, solutions, etc.

3. Serial Entrepreneur - Has multiple startups do to new ideas.

4. Lifestyle Entrepreneur - Start up their business due to their lifestyles such as sports hobbies or passions

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Answer:

1. Business

2. Social

3. Serial

4. Lifestyle

The correct answer is 1.575 A.

a)

From Transformer turns ration

N_s/N_p =V_s/V_p

=>N_p =N_s × (V_p/V_s) =100 × (1.6 × 10^4/120)

N_P=1.33 × 10^4 Turns

b)

P_out =P_in

V_sI_s =V_PI_P

210 × 120 =(1.6 × 10^4)I_p

I_p=1.575 A

What is the working principle of an electric generator?

The generator is composed of a coil with many copper wires coiled around an iron core that is rectangular in shape. The armature is the term for this coil. This armature's purpose is to boost the magnetic flux. The armature revolves between two powerful permanent magnets that have been set. Here, the magnetic lines that are created are orthogonal to the axis of the armature. Two slip rings are further attached to the armature's arms. Two metallic brushes are also linked to the slip rings, which aid in moving current from the armature to the slip rings. These rings are employed for creating moveable contact. Last but not least, the current flows via a load resistance that is wired in parallel with and across the two slip rings.

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If you walk 3 km due east, then 2.5 km due south, then 11 km due west, then you are 9.34 km far from the starting point.

If you connect all the paths, it will make a triangle. If you join your current position with the start position, then you get the triangle ADE.

This question can be solved by using the application of Pythagoras theorem.

This theorem states that in a right-angled triangle, square of longest side is equal to the sum of the individual squares of the other two sides

Here, AD is the same as BC = 2.5km

and then EC = 11km and DC = AB = 3km

ED= EC-DC = 9 km

In the triangle ADE, according to Pythagoras theorem,

AE^2 = AD^2 + ED^2

so, AE = sqrt (9^2 + 2.5^2)

⇒ AE= sqrt (81 + 6.25)

⇒ AE = 9.34 km

Thus, you are about 9.34 km distance from your start point.

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Answer:

d = 102 m

Explanation:

distance = 36 m + 44 m + 22 m

Distance = 102 m