A bridge AB is to be built across a river. The point C is located 62m from B, and angle A is 80 degrees, angle C is 60 degrees. How long is the bridge

A Bridge AB Is To Be Built Across A River. The Point C Is Located 62m From B, And Angle A Is 80 Degrees,

Answers

Answer 1

The points A, B, and C form a triangle.

From the given information in the question, the triangle ABC can be drawn to have the following parameters:

Recall the Sine Rule. Applied to the triangle above, the rule is stated as follows:

[tex]\frac{BC}{\sin A}=\frac{AC}{\sin B}=\frac{AB}{\sin C}[/tex]

The length of the bridge is AB. Given that the measures of angles A and C, and side BC are known, the following ratio is used to solve:

[tex]\frac{BC}{\sin A}=\frac{AB}{\sin C}[/tex]

Substituting known values, the length of AB is calculated as follows:

[tex]\begin{gathered} \frac{62}{\sin80}=\frac{AB}{\sin60} \\ AB=\frac{62\times\sin60}{\sin80} \\ AB=54.52 \end{gathered}[/tex]

The bridge is 54.52 m long.

A Bridge AB Is To Be Built Across A River. The Point C Is Located 62m From B, And Angle A Is 80 Degrees,

Related Questions

50 gramos de pechuga de un pollo contiene 10.4 g de proteínas, 0.5 g de carbohidratos y 1.6 g de grasas. Los valores medios de energía alimentaria de esas sustancias son de 4.0 kcal/g para las proteínas y los carbohidratos, y de 9.0 kcal/g para las grasas. a) Al jugar baloncesto, una persona representativa consume energía a una potencia de 420 kcal/h. ¿Cuánto tiempo debe jugar para “quemar” esa pechuga?

Answers

Tenemos lo siguiente:

Lo primero es calcular las kilocalorías para las proteínas y para los carbohidratos y grasas, de la siguiente día:

[tex]\begin{gathered} \text{Protenas} \\ 10.4\text{ g}\cdot4\frac{\text{ kcal}}{g}=41.6\text{kcal} \\ \text{Carbohidratos} \\ 0.5\text{ g}\cdot4\frac{\text{ kcal}}{g}=2\text{kcal} \\ \text{Grasas} \\ 1.6\text{ g}\cdot9\frac{\text{ kcal}}{g}=14.4\text{kcal} \end{gathered}[/tex]

Ahora sumamos todas las kilocalorías y nos queda lo siguiente:

[tex]41.6+2+14.4=58[/tex]

Es decir que en total en los 50 gramos de pechuga hay en total de 58 kilocalorías, ahora debemos calcular el tiempo dividiendo el numero de kilocalorías por la cantidad de consumo de kilocalorías al jugar baloncesto

[tex]\frac{58\text{ kcal}}{420\text{ kcal/h}}=0.138\text{ h}[/tex]

Es decir que debe jugar 0.138 horas o un total de:

[tex]0.138\text{ h}\cdot\frac{60\text{ min}}{1\text{ h}}=8.28\text{ min}[/tex]

Es decir que debe jugar 8.28 minutos

6 Equations of parallel and perpendicular lines VEB
The equation for line u can be written as y = -x + 1. Line v, which is perpendicular to line
u, includes the point (-3, 2). What is the equation of line v?
Write the equation in slope-intercept form. Write the numbers in the equation as simplified
proper fractions, improper fractions, or integers.

Answers

Answer:

  y = 4/9x +10/3

Step-by-step explanation:

You want the slope-intercept equation of the line through point (-3, 2) that is perpendicular to the line y = -9/4x +1.

Slope-intercept equation

The slope-intercept form of the equation for a line is ...

  y = mx + b . . . . . . m is the slope, b is the y-intercept

In order to write the desired equation, we need to know the desired slope and the y-intercept that makes the line go through the given point.

Slope

The slope of the perpendicular line is the opposite reciprocal of the slope of the given line. The given line equation is in slope-intercept form, so the coefficient of x is the slope of it: -9/4.

The slope of the perpendicular line is the opposite reciprocal of this:

  m = -1/(-9/4) = 4/9

Y-intercept

Solving the slope-intercept form equation for b, we find ...

  b = y - mx

Using the values of x and y for the given point, and the slope we just found, we have ...

  b = 2 -(4/9)(-3) = 2 +4/3 = 10/3

Desired equation

The slope-intercept equation for a line with slope 4/9 and y-intercept 2/3 is ...

  y = 4/9x +10/3

__

Additional comment

It can also be useful to start from the point-slope equation:

  y -k = m(x -h) . . . . . line with slope m through point (h, k)

Your line is ...

  y -2 = 4/9(x +3) . . . . . . use m=opposite reciprocal of -9/4; (h, k) = (-3, 2)

  y = 4/9x +(4/9)(3) +2 = 4/9x +10/3 . . . . . . add 2 and simplify

Find the time it would take for the general level of prices in the economy to double at an average annual inflation rate of 4%. The doubling time is aboutyears.

Answers

The doubling time for the general price levels in the eonomy given the average annual inflation rate is 18 years.

What is the doubling time?

Inflation is a period where the general price levels in an economy rise persistently. When there is an inflation, the prices of goods and services increase. Inflation can either be as a result of an increase in the cost of production or an increase in the demand of a good.

The rule of 72 can be used to determine the doubling time. The rule of 72 is a rule of thumb that determines the number of years it would take an investment to double given its rate of growth.

The rule of 72 = 72 / inflation rate

72 / 4 = 18 years

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Please show me how to solve this step by step im really confused

Answers

Given

[tex]-16t^2+v_0t+h_0[/tex]

initial velocity = 60 feet per second

initial height = 95 feet

Find

Maximum height attained by the ball

Explanation

we have given

[tex]\begin{gathered} h(t)=-16t^2+60t+95 \\ h^{\prime}(t)=-32t+60 \end{gathered}[/tex]

put h'(t) = 0

[tex]\begin{gathered} -32t+60=0 \\ -32t=-60 \\ t=\frac{60}{32}=1.875sec \end{gathered}[/tex]

to find the maximum height find the value of h(1.875)

[tex]\begin{gathered} h(1.875)=-16(1.875)^2+60(1.875)+95 \\ h(1.875)=-56.25+112.5+95 \\ h(1.875)=-56.25+207.5 \\ h(1.875)=151.25 \end{gathered}[/tex]

Final Answer

Therefore , the maximum height attained by the ball is 151.25 feet

Reba is playing on the slide. Over and over, she climbs the 9-foot ladder, goes down the slide, and walks 3 feet to get back to the ladder. How far does Reba travel each time she repeats this process? If necessary, round to the nearest tenth.

Answers

we have

then find c

[tex]\begin{gathered} c^2=3^2+9^2 \\ c^2=9+81 \\ c^2=90 \\ c=\sqrt[]{90} \\ c=3\sqrt[]{10} \end{gathered}[/tex]

therefore the distance is:

[tex]9+3\sqrt[]{10}+3=21.5[/tex]

answer: 21.5 ft

Charlene and Gary want to make perfume. In order to get the right balance of ingredients for their tastes they bought 2ounces of rose oil at $4.36 per ounce, 5 ounces of ginger essence for $2.15 per ounce, and 4 ounces of black currant essence for $2.27 per ounce. Determine the cost per ounce of the perfume.

Answers

First, lets calculate how much the expended in the perfume:

[tex]2\times(4.36)+5\times(2.15)_{}+4\times(2.27)=28.55[/tex]

So, for 11 ounces of perfume, they need $28.55, so the minimum that the perfume need to cost per ounce is:

[tex]\frac{28.55}{11}=2.5954\cong2.6[/tex]

So, about $2.6 per ounce of perfume.

Problem Solving: Fraction Division For exercises 1 and 2, write three problem situations for each division 56÷1/3 and 6/1/2÷1/2/3

Answers

56÷1/3

We have to model a problem where the solution is 56÷1/3.

So, we take something that is 56 and we have to divide it by 1/3rd.

So, we can say:

George had 56 large cakes.

Giving 1/3rd of each cake to each person is enough.

If George used all of the cake, how many person could he feed?


If X persons are admitted in a hospital during the last five years and Y persons
are recovered out of them during this period then find the average number of
persons admitted in one year.

Answers

The average number of persons admitted in one year is X/5.

What is average number?

Average By adding a collection of numbers, dividing by their count, and then summing the results, the arithmetic mean is determined.

If X persons are admitted in last 5 years in a hospital.

Then we get the average value of admitted persons are X/5 per year.

If Y persons are recovered in last 5 years in a hospital.

Then we get the average value of recovered persons are Y/5 per year.

Therefore, the average number of persons admitted in one year is X/5.

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Quadrilateral PQRS is plotted in the coordinate plane. The quadrilateral is dilated by a scale factor of 3/4. What are the new ordered pairs for P'Q'R'S'?

Answers

Explanation:

The first thing is to state the coordinates of Quadrilateral PQRS

P (5, 5), Q (3, 5), R (3, 1), S (5, 1)

Then we find the distance between two points using the distance formula

[tex]dis\tan ce\text{ = }\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}[/tex][tex]\begin{gathered} P(5,5),Q(3,5)\text{ = (x1, y1) and (x2, y2)} \\ \text{distance PQ = }\sqrt[]{(5-5)^2+(3-5)^2}\text{ = }\sqrt[]{0+(-2)^2}\text{ =}\sqrt[]{4} \\ \text{distance PQ = }2 \end{gathered}[/tex][tex]\begin{gathered} Q(3,5),R(3,1)\text{= (x1, y1) and (x2, y2)} \\ \text{distance QR = }\sqrt[]{(1-5)^2+(3-3)^2}\text{ = }\sqrt[]{(-4)^2+0}\text{ = }\sqrt[]{16} \\ \text{distance QR = 4} \end{gathered}[/tex]

It is a quadrilateral, meaning the two lengths are equal. Like wise the two widths are equal.

length PQ = length SR = 2

Length QR = length PS = 4

Scale factor = 3/4

Scale factor = corresponding side of new image/ corresponding side of original image

PQRS = original image, P'Q'R'S' = new image

3/4 = P'Q'/PQ

3/4 = P'Q'/2

P'Q' = 2(3/4) = 6/4 = 3/2

Since P'Q' = S'R'

S'R' = 3/2

3/4 = Q'R'/QR

3/4 = Q'R'/4

Q'R' = 3/4 (4) = 12/4 = 3

Since Q'R' = P'S

P (5, 5), Q (3, 5), R (3, 1), S (5, 1)

PQRS to P'Q'R'S' = 3/4(

P' = 3/4 (5, 5) = (15/4, 15/4)

Q' = 3/4 (3, 5) = (9/4, 15/4)

R' = 3/4 (3, 1) = (9/4, 3/4)

S' = 3/4 (5, 1)

What are the rotations that will carry this equilateral triangle onto itself?A. 90° counterclockwise rotation about its center PB. 270° counterclockwise rotation about its center PC. 120° counterclockwise rotation about its center PD. 240° clockwise rotation about its center PE. 225 clockwise rotation about its center PF. 200 counterclockwise rotation about its center Prights reserved

Answers

Given -

Equilateral Triangle

To Find -

The number of rotations that will carry this equilateral triangle onto itself =?

Step-by-Step Explanation -

We know that in an equilateral triangle each question is of 60°

So,

Since it is a three-sided symmetry So, a rotation of 120° will carry this equilateral triangle onto itself.

Final Answer:

C. 120° counterclockwise rotation about its center P

Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options. x < 5 –6x – 5 < 10 – x –6x + 15 < 10 – 5x A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right. A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.

Answers

The correct representations of the inequality -3(2x-5)<5(2-x) are -6x + 15 < 10 - 5x  and  "an open circle is at 5 and a bold line that starts at 5 and is pointing to the right" , the correct option is (c) and (d) .

In the question ;

it is given that

the inequality -3(2x-5)<5(2-x)

on solving this inequality further , we get

-3(2x-5)<5(2-x)

-6x+15<10-5x

which is option (c) .

Further solving

Subtracting 15 from both the sides of the inequality  , we get

-6x + 15 -15 < 10 -5x -15

-6x < -5 -5x

-6x +5x < -5

-x < -5

multiplying both sides by (-1) ,

we get

x > 5 .

x> 5 on number line means  an open circle is at 5 and a bold line starts at 5 and is pointing to the right .

Therefore , the correct representations of the inequality -3(2x-5)<5(2-x) are -6x + 15 < 10 - 5x  and  "an open circle is at 5 and a bold line that starts at 5 and is pointing to the right" , the correct option is (c) and (d) .

The given question is incomplete , the complete question is

Which are correct representations of the inequality -3(2x - 5) < 5(2 - x)? Select two options.

(a) x < 5

(b) –6x – 5 < 10 – x

(c) –6x + 15 < 10 – 5x

(d) A number line from negative 3 to 7 in increments of 1 , An open circle is at 5 and a bold line that starts at 5 and is pointing to the right.

(e) A number line from negative 7 to 3 in increments of 1,  An open circle is at negative 5 and a bold line that starts at negative 5 and is pointing to the left.

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-14.4 + x = -8.2what does x equal?I NEED ANSWERS ASAPi will give brainliest

Answers

the given expression is,

-14.4 + x = -8.2

x = 14.4 - 8.2

x = 6.2

thus, the answer is x = 6.2

Multiply.(2x + 4)(2x - 4)A. 4x2 + 16x- 16B. 4x2 - 16C. 4x2 - 16x - 16D. 4x2 + 16

Answers

We have to multiply the expression (2x + 4)(2x - 4):

[tex]\begin{gathered} \left(2x+4\right)\left(2x-4\right) \\ 2x\cdot2x+2x\cdot(-4)+4\cdot2x+4\cdot(-4) \\ 4x^2-8x+8x-16 \\ 4x^2+(8-8)x-16 \\ 4x^2-16 \end{gathered}[/tex]

The answer is:

B. 4x^2 - 16

Express the interval using inequality notation(1,6)

Answers

The interval (1, 6) contains all the real numbers between 1 and 6, not including any of the endpoints.

This can be written in inequality notation as:

x >1 AND x < 6

But there is a shorter way to write the interval by combining both inequalities:

1 < x < 6

May I please get help with this. For I have tried many times but still could not get the rotation correct

Answers

Let us write out the coordinates of the parent image given

Let us name the triangle ABC

[tex]\begin{gathered} A\rightarrow(1,5) \\ B\rightarrow(-3,2) \\ C\rightarrow(-5,4) \end{gathered}[/tex]

Therefore, the rule for the rotation 90 degrees counterclockwise about the origin is,

[tex]A(x,y)\rightarrow A^{\prime}(-y,x)[/tex]

Let us now obtain the coordinates of the transformed image

[tex]\begin{gathered} A(1,5)\rightarrow A^{\prime}(-5,1) \\ B(-3,2)\rightarrow B^{\prime}(-2,-3) \\ C(-5,4)\rightarrow C^{\prime}(-4,-5) \end{gathered}[/tex]

Hence, the coordinates of the transformed image are

[tex]\begin{gathered} A^{\prime}(-5,1) \\ B^{\prime}(-2,-3) \\ C^{\prime}(-4,-5) \end{gathered}[/tex]

Let us now plot the transformed image

Find the domain of the function. Write the domain in interval notation.

Answers

The domain of a function is the possible values of "t" that the given function can take.

Since the variable "t" is in the denominator, the denominator cannot be equal to zero because it would make the function undefined.

Hence, t - 4 must be greater than zero. For t - 4 to be greater than zero, the value of t must be greater than 4.

In addition, since the variable is inside the radical sign, then the function itself cannot be negative.

Hence, the domain of this function must be greater than 4. In interval notation, it is (4, ∞).

Kuta Software - Infinite Precalculus Angles and Angle Measure Find the measure of each angle.

Answers

Explanation:

We are to draw the angle that is equivalent to 5pi/4

First we need to convert the radian value to degree

Since pi rad = 180degrees

5pi/4 = x

Cross multiply

pi * x = 5pi/4 * 180

x = 5/4 * 180

x = 5 * 45

x = 225 degrees

This can also be written as 225 = 180 + 45

225degrees = 180 + pi/4

Note that 180degrees is an angle on a straight line. Find the digaram attached

The remaining angle which is pi/4 is the reason for the angle extensionon for the angle extension

5pi/4 = x

Cross multiply

pi * x = 5pi/4 * 180

x =

is H less than 9?[tex]h \leqslant 9[/tex]

Answers

3) The given inequality is

[tex]h\text{ }\leq\text{ 9}[/tex]

The inequality symbol is that of less than. Since it has an equal to sign attached, then, the meaning is h is less than or equal to 9. In words, h is at most 9, no more than 9.

Identify the type(s) of symmetry for the graph below.Select all that apply. aSymmetry with respect to the line \small \theta=\frac{\pi}{2} bSymmetry with respect to the polar axis cSymmetry with respect to the pole

Answers

The line θ=π/2 is the vertical line in the polar grid, the polar axis is the horizontal line and the pole is the center of coordinates. Now let's analyze the symmetries:

If the grpah is symmetric with respect to θ=π/2 then the graph at the left of this line has to be the mirrored image of the graph at the right side. This is the case of this graph so it does have symmetry with respect to θ=π/2.

For the polar axis is the same, the graph above the axis has to be the mirrored image of that below the axis. However in this case we have two "petals" above the polar axis and one below so the upper part is not the mirrored version of the lower part so it has no symmetry with respect to this axis.

For the pole we must rotate the graph 180°. If the graph remains unchanged then it is symmetric with respect to it. In this case if we rotate the graph 180° the lower petal ends up in the opposite direction so the graph changes after a 180° rotation and it has no symmetry with respect to the pole.

Then the only type of symmetry is with respect to the line θ=π/2 and the answer is option a.

please help me with this. four potential solutions.450, 780, 647, 354

Answers

So first of all let's take:

[tex]x_1=x\text{ and }x_2=y[/tex]

Then we get:

[tex]\begin{gathered} \text{Min}z=1.5x+2y \\ x+y\ge300 \\ 2x+y\ge400 \\ 2x+5y\leq750 \\ x,y\ge0 \end{gathered}[/tex]

The next step would be operate with the inequalities and the equation so we end up having only the term y at the left side of each:

[tex]\begin{gathered} \text{Min}z=1.5x+2y \\ 1.5x+2y=\text{Min}z \\ 2y=\text{Min}z-1.5x \\ y=\frac{\text{Min}z}{2}-0.75x \end{gathered}[/tex][tex]\begin{gathered} x+y\ge300 \\ y\ge300-x \end{gathered}[/tex][tex]\begin{gathered} 2x+y\ge400 \\ y\ge400-2x \end{gathered}[/tex][tex]\begin{gathered} 2x+5y\leq750 \\ y\leq150-\frac{2}{5}x \end{gathered}[/tex]

So now we have the following inequalities and equality:

[tex]\begin{gathered} y=\frac{\text{Min}z}{2}-0.75x \\ y\ge300-x \\ y\ge400-2x \\ y\leq150-\frac{2}{5}x \end{gathered}[/tex]

If we take the three inequalities and replace their symbols by "=' we'll have three equations of a line:

[tex]\begin{gathered} y=300-x \\ y=400-2x \\ y=150-\frac{2}{5}x \end{gathered}[/tex]

The following step is graphing these three lines and delimitating a zone in the grid that meets the inequalities:

Where the blue area is under the graph of y=150-(2/5)x which means that it meets:

[tex]y\leq150-\frac{2}{5}x[/tex]

And it is also above the x-axis, y=400-2x and y=300-x which means that it also meets:

[tex]\begin{gathered} x\ge0 \\ y\ge0 \\ y\ge400-2x \\ y\ge300-x \end{gathered}[/tex]

All of this means that the values of x and y that give us the correct minimum of z are given by the coordinates of a point inside the blue area. The next thing to do is take the four possible values for Min(z) and use them to graph four lines using this equation:

[tex]y=\frac{\text{Min}z}{2}-0.75x[/tex]

Then we have four equations of a line:

[tex]\begin{gathered} y=\frac{450}{2}-0.75x \\ y=\frac{780}{2}-0.75x \\ y=\frac{647}{2}-0.75x \\ y=\frac{354}{2}-0.75x \end{gathered}[/tex]

The line that has more points inside the blue area is the one made with the closest value to Min(z). Then we have the following graph:

As you can see there are two lines that have points inside the blue area. These are:

[tex]\begin{gathered} y=-\frac{3}{4}x+\frac{450}{2} \\ y=-\frac{3}{4}x+\frac{354}{2} \end{gathered}[/tex]

That where made using:

[tex]\begin{gathered} \text{Min }z=450 \\ \text{Min }z=354 \end{gathered}[/tex]

Taking a closer look you can see that the part of the orange line inside the blue area is larger than that of the red line. Then the value used to make the orange line would be a better aproximation for the Min z. The orange line is -(3/4)x+450/2 which means that the answer to this problem is the first option, 450.

Dr Taylor just started an experiment he will collect data for 5 days how many hours is this

Answers

In one day the total number of hours is 24 hours.

So, in 5 days the number of hours is,

[tex]24\times5=120\text{ hours}[/tex]

So, the required number of hours is 120 hours.

1 point Esther thinks she understands how to find the midpoint of a segment on a graph. "I always look for the middle of the line segment. But what should I do if the coordinates are not easy to graph?" she asks. Find the midpoint of KL if (2.125) and L(98, 15). *

Answers

[tex]\begin{gathered} \text{ Given two points, on a graph} \\ (x_1,y_1)\text{ and }(x_{2,}y_2)\text{ then the} \end{gathered}[/tex][tex]\begin{gathered} \text{coordinate of the mid-point }(x_m,y_m)\text{ is given by} \\ x_m=\frac{x_1+x_2}{2},y_m=\frac{y_1+y_2}{2} \end{gathered}[/tex]

In this case, we can write out the parameters

[tex]\begin{gathered} x_1=2,_{}y_1=125, \\ x_2=98,y_2=15 \end{gathered}[/tex]

Thus, substitute the coordinates in the mid-point formula and simplify

[tex]\begin{gathered} x_m=\frac{98+2}{2}=\frac{100}{2}=50 \\ y_m=\frac{125+15}{2}=\frac{140}{2}=70 \end{gathered}[/tex]

Hence, the coordinate of the mid-point is (50, 70)

Set up the system of equations:The cost of 4 bananas and 6 pears is $1.68. Nine bananas and 2 pears cost $1.48. Set up thesystem of equations to find the cost of each banana and pear.4B + 6P = 1.689B - 2P = 1.484B + 6P + 1.689B + 2P + 1.484B + 6P = 1.689B + 2P = 1484B = 6P + 1.689B = 2P + 148

Answers

Solution:

Let b represent the cost of 1 banana

Let p represent the cost of 1 pear

From the first statement, The cost of 4 bananas and 6 pears is $1.68

4b + 6p = 1.68 ----------------------------equation (1)

From the second statement, Nine bananas and 2 pears cost $1.48

9b + 2p = 1.48 -----------------------------equation (2)

Solve both equations simultaneously

4b + 6p = 1.68 ----------------------------equation (1)

9b + 2p = 1.48 -----------------------------equation (2)

Multiply equation (2) by 3 to eliminate p

27b + 6p = 4.44

4b + 6p = 1.68

Subtract both equatuions above

23b = 2.76

b = 2.76/23

b= 0.12

Substitute b = 0.12 into equation (1)

9b + 2p = 1.48

9(0.12) + 2p = 1.48

1.08 + 2p = 1.48

2p = 1.48 - 1.08

2p = 0.4

p = 0.4/2

p = 0.2

Hence, the cost of each banana is $0.12 while the cost of each pear is $0.2

The Hughes family and the Gonzalez family each used their sprinklers last summer. The Hughes family's sprinkler was used for 15 hours. The Gonzalez family's sprinkler was used for 35 hours. There was a combined total output of 1475 L of water. What was the water output rate for each sprinkler if the sum of the two rates was 65 L per hour?

Answers

Answer:

Hughes Family: 40 L/ hour
Gonzalez family: 25L/hour

Step-by-step explanation:

Let us use the following variables to denote the output rates for each sprinkler.

Let H = water output rate for the Hughes family

Let G = water output rate for the Gonzalez family

(I am using H ang G rather than the traditionally used X and Y to easily identify which rate belongs to which family)

The general equation for the volume of water outputted, V,  in time h hours at a rate of r per hour is
V = r x h

Given r

Using this fact
Water Output for Hughes family at rate H for 15 hours = 15H

Water Output for Gonzalez family at rate G for 35 hours = 35 G

The total of both outputs = 1475

That gives us one equation
15H + 35G = 1475    [1]

We are given the combined rate as 65 L per hour
Sum of the two rates = combined rate

H + G = 65   [2]

Let's write down these two equations and solve for H and G
15H + 35G = 1475    [1]
   H +     G =     65   [2]
Multiply equation [2] by 15 to make the H terms equal
15H + 15G = 975     [3]
Subtract [3] from [1] to eliminate the H terms
       15H + 35G =  1475
         -          -           -
        15H  + 15G =   975
--------------------------------------
           0H + 20G =  500
---------------------------------------So we get
20G = 500
G = 500/20 = 25 liters/hour
Plug this value of G into equation [2] to get
H + 20 = 65
H = 65 - 25
H = 40 liters/hour
Water output rates  are as follows:
Hughes Family: 40 L/ hour
Gonzalez family: 25L/hour

2-x+ 3-X-4
where a and b are integers.
Work out the value of a and the value of b.
can be written as a single fraction in the form
ax+b
x²-16

Answers

Answer:

2-×+3-×-4=0

Step-by-step explanation:

×=1\2

0.5,2`1

I got 4089 for the answer but it was incorrect

Answers

Let A be the event "person under 18" and B be the event "employed part-time". So, we need to find the following probability

[tex]P(A\text{ or B) =P(A}\cup B)[/tex]

which is given by

[tex]P(A\text{ or B) =P(A}\cup B)=P(A)+P(B)-P(A\cap B)[/tex]

Since the total number od people in the table is equal to n=4089, we have that

[tex]P(A)=\frac{28+174+395}{4089}=\frac{597}{4089}[/tex]

and

[tex]P(B)=\frac{174+194+71+179+173}{4089}=\frac{791}{{4089}}[/tex]

and

[tex]P(A\cap B)=\frac{174}{4089}[/tex]

we have that

[tex]P(A\text{ or B) =}\frac{597}{4089}+\frac{791}{{4089}}-\frac{174}{4089}[/tex]

which gives

[tex]P(A\text{ or B) =}\frac{597+791-174}{4089}=\frac{1214}{4089}=0.29689[/tex]

Therefore, the answer the searched probability is: 0.296

7 x 5f = 7070

HELPPPP PLEASE

Answers

f = 202

Step-by-step explanation:

[tex]7 \times 5f = 7070[/tex]

[tex]5f = \frac{7070}{7} [/tex]

[tex]5f = 1010[/tex]

[tex]f = \frac{1010}{5} [/tex]

[tex]f = 202[/tex]

Verification to check the given answer is correct, then put the value of f in the given question.

[tex]7 \times 5(202) = 7070[/tex]

[tex]35(202) = 7070[/tex]

[tex]7070 = 7070[/tex]

L.H.S. = R.H.S

[tex]{ \green { \boxed{ \red{ \sf{f = 202}}}}}[/tex]

Step-by-step explanation:

The given Eqⁿ is, [tex]{ \purple{ \sf{7 \times 5f = 7070}}}[/tex]

We need to find the value of f. So, let us cancel the numbers one by one.

First, let us cancel 7 by dividing both the sides by 7 in the given Eqⁿ.

[tex]{ \purple{ \sf \frac{ \cancel7 \times 5f}{ \cancel7}}} = { \purple{ \sf{ \frac{ \cancel{7070} ^{ \green{ \tt{1010}}} }{ \cancel 7_{ \green{ \tt{1}}}}}}}[/tex]

[tex]{ \purple{ \sf{5f = 1010}}}[/tex]

Now, let us cancel 5 by dividing both the sides by 5. then,

[tex]{ \purple{ \sf{ \frac{ \cancel5}{ \cancel5}f}}} = { \purple{ \sf{ \frac{ \cancel{1010^{ \red{ \tt{ \: \:202}}}}}{ \cancel 5_{ \red{ \tt{1}}}}}}}[/tex]

[tex]{ \boxed{ \blue{ \sf{f = 202}}}}[/tex]

Suppose you want to have $ 749,791 for retirement in 13 years. Your account earns 9.5 % interest monthly. How much interest will you earn?$_________ (Round to the nearest DOLLAR)

Answers

ANSWER

$530,663

EXPLANATION

The amount the account will have in t years is given by,

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

Where n = 12, t = 13 years, r = 0.095 and A = 749,791. We have to find P,

[tex]P=\frac{A}{(1+\frac{r}{n})^{nt}}[/tex]

Replace with the values and solve,

[tex]P=\frac{749,791}{(1+\frac{0.095}{12})^{12\cdot13}}\approx219,128[/tex]

The interest earned is the difference between the initial deposit P and the final amount A,

[tex]i=A-P=749,791-219,128=530,663[/tex]

Hence, the interest earned would be $530,663.

Bill Jensen deposits $8500 with Bank of America in an investment paying 5% compounded semiannually. Find the interest in 6 years

Answers

Amount deposited = $8500

Rate = 5%

time for interest = 6years

Compounded semiannually

The formula for semiannually is

[tex]A=P(1+\frac{r}{100n})^{nt}[/tex]

From the given information

P = $8500

r = 5

t = 6

Since the investment was compounded semiannually then

n = 2

Substitute the values into the formula

This gives

[tex]A=8500(1+\frac{5}{100\times2})^{6\times2}[/tex]

Solve for A

[tex]\begin{gathered} A=8500(1+0.025)^{12} \\ A=8500(1.025)^{12} \\ A=11431.56 \end{gathered}[/tex]

To find the interest

Recall

[tex]I=A-P[/tex]

Where I, is the interest

Hence

[tex]\begin{gathered} I=\text{\$}11431.56-\text{\$}8500 \\ I=\text{\$}2931.56 \end{gathered}[/tex]

Nguyen deposited $35 in a bank account earning 14% interest, compounded annually. How much interest will he earn in 72 months?

Answers

Given:

a.) Nguyen deposited $35 in a bank account.

b.) It earns 14% interest.

To be able to determine how much interest will he earn in 72 months, the following formula will be used for Compound Interest:

[tex]\text{ Interest Earned = P(1 + }\frac{\frac{r}{100}}{n})^{nt}\text{ - P}[/tex]

Where,

P = Principal amount

r = Interest rate

n = No. of times the interest is compounded = annually = 1

t = Time in years = 72 months = 72/12 = 6 Years

We get,

[tex]\text{ Intereset Earned = (35)(1 + }\frac{\frac{14}{100}}{1})^{(1)(6)}\text{ - 35}[/tex][tex]\text{ = (35)(1 + }0.14)^6\text{ - 35}[/tex][tex]\text{ = (35)(}1.14)^6\text{ - 35}[/tex][tex]\text{ = (35)(}2.19497262394)^{}\text{ - 35}[/tex][tex]\text{ = 76.82404183776 - 35}[/tex][tex]\text{ = 41.82404183776 }\approx\text{ 41.82}[/tex][tex]\text{ Interest Earned = \$41.82}[/tex]

Therefore, the interest he will be earning is $41.82

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