Answer:
3.7 m
Explanation:
ASSUMING this means extra distance beyond where the cannonball would land WITHOUT the wind assistance but in general ignoring air resistance. Hmmmmmm...tricky
The ball drops from vertical rest to ASSUMED horizontal ground 15 m below in a time of
t = √ (2h/g) = √(2(15)/9.8) = 1.75 s
Without the tail wind, the ball travels horizontally
d = vt = 68(1.75) = 119 m
The tailwind exerts a constant acceleration on the ball of
a = F/m = 12/5.0 = 2.4 m/s²
The average horizontal velocity during the flight is
v(avg) = (68 + (68 + 2.4(1.75)) / 2 = 70.1 m/s
so the distance with tailwind is
d = v(avg)t = 70.1(1.75) = 122.675 m
The extra distance is 122.675 - 119 = 3.675 = 3.7 m
A spring scale is used to measure the weight of various objects. When a 100 g empty glass bottle is placed on the scale, the spring stretches down 1.8 cm. How much water should be poured into the glass bottle to stretch the spring down by 2.7 cm?
A: 44 mL
B: 50 mL
C: 33 mL
D: 150 mL
50 mL of water have to poured to the glass bottle of 100 g to increase the stretching of the spring from 1.8 cm to 2.7 cm.
What is spring stretching?A spring can hang when it loads a weight. The stretching of spring is the change in length of the spring end from its initial length. Spring balance works with the principle of Hooks law.
The stretching is made by the elasticity of the spring which make it in a wave like motion.
Given that the glass bottle with 100 g weight when loaded on the spring scale, it will stretch down to 1.8 cm. Then the weight required to make a stretch of 2.7 cm is calculated as follows:
weight required = (100 g × 1.8 cm) /2.7 cm
= 150 g.
A total of 150 g is needed to stretch into 2.7 cm. Thus we have to add 50 g of water to the glass weighing 100 g . 50 g is equivalent to 50 ml, since density of water is 1 g/L.
Hence, 50 ml of water should be poured to the glass.
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A racecar begins at rest and accelerates to 25 m/s at a rate of 6.25 m/s2. What distance does the racecar cover?
a.
2 m
b.
156 m
c.
4 m
d.
50 m
Answer:
d.
50 m
Explanation:
v² = u² + 2as
s = (v² - u²) / 2a
s =(25² - 0²) / (2(6.25))
s = 50 m
Which of the following types of stars is hottest?
A
B
C
D
Answer:
graph b
Explanation:
the force of gravity on Mars is 3.7 m/s^2. what is the force of gravity on Earth?
bus travels 6 km east and then 8 km south. What is the displacement?
Answer:
d = √(6² + 8²) = 10 km
Explanation:
displacement is a vector and subject to vector addition.
You had an amazing race. You finished the 300kms race in 1hr 40 minutes. What is the average velocity?
Average Velocity
Level : JHSv = s/t
v = 300 km/(1 hour + 40/60 hour)
v = 300 km/(1.66 hour)
v = 180 km/hour
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a ball thrown horizontally with the velocity of 20 m\s from a 20 m building .what is the time
Answer:2.02s
Explanation:
At the y component, the tract of the ball is free falling body. The initial velocity at y component is 0 m/s.
Height = 1/2 * g * t^2
20 = 1/2 * 9.8 * t^2
t = (20 * 2 / 9.8)^1/2, t = 2.02s
6. During an impact time casting 5 x 10-45 a gulf club exerts an average impar
force of 5000N on the ball. What linear impulse is delivered to the ball as a result?
Answer:
2.5 × 10-⁴¹ Ns
Explanation:
Impulse
I = F × t
I = 5000 N × 5 × 10-⁴⁵ s
I = 25 × 10-⁴² Ns
I = 2.5 × 10-⁴¹ Ns
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Help on these two thanks
Answer:
8. Friction
9. Net force
Explanation:
Hope this helps you. Have a nice day. :)
Please help as soon as possible! I will give Brainliest! I just need to know the answers to this diagram.
A 5.7 kg block slides along a horizontal surface toward a horizontally mounted spring with a spring constant of 150 N/m. At one instant, the block is 5.0 m from the end of the spring and has a speed of 12.0 m/s. If the surface is frictionless, what is the maximum compression of the spring
Hi there!
We can use the conservation of energy:
Ei = Ef
The initial energy involves kinetic energy while the final energy involves maximum elastic potential energy, so:
1/2mv² = 1/2kx²
We can cancel out the 1/2s for ease of solving:
mv² = kx²
Plug in given values to solve for x:
√(mv²/k) = x
√(5.7)(12²)/(150)) = x
x = 2.339 m
A 55-kg person lands on firm ground after jumping from a height of 2.8 m.
Explanation:
What are you searching for?
Potential energy?
Answer:
3018.4
Explanation:
So this velocity just before reaching the ground, the final equals square root of two times G times H. So gs 9.8 m per second squared H is 2.8 m. So it gives the velocity of 7.41 m per second squared. That's the velocity right before touching the ground. So to find the impulse required to come to rest here, we just do mass times the velocity minus zero. So zero is the final momentum, final velocity zero. So that makes the final momentum zero. So we multiply the mass with the velocity before touching the ground and after. And subject zero. That's the momentum after touching the ground. So we multiply mass 55 kg. At 7.41 velocity we got 407.45. kilograms meters per second of impulse. we know that the force will be larger for stiff stiff flex compared to bend flex. Because the stiff flex. Bring the object to rest in a short amount of time and distance. So in part C, that's calculate for stiff flex. The stopping distance, Delta Y. Is 0.1 m. This one centimeter. So we can calculate the acceleration of the body when it comes to rest. From the moment it touches the ground. equals v squared over two times Delta Y. So we use the square is 54.88. The 7.41 square divided by two times 0.01 gives us an explosion of 2744 m/s square. So you multiply this acceleration by the mass to get the force so force equals mass times acceleration gives us a large force, 159 20 newtons. Then for bent legs, repeat the same process with a different delta Y, delta Y of 200.5 m. So that's 50 centimeters and calculate acceleration the same process. Just use a different value of delta Y. And we get as much smaller acceleration 54.88 m per second square. And the force experience would just be mass times acceleration. That gives us 3018.4 newton's a lot smaller than for stiff flex.
How much force (in Newtons) is needed to accelerate a 160 kg object at a rate of 4 m/s2?
A. 15
B. 40
C. 640
D. .025
Answer:
C. 640
Explanation:
The minimum force would occur in a frictionless environment and act parallel to any abutting surface.
F = ma = 160(4) = 640 N
how do sound waves behave as a solid
a. they travel faster in a solid than other mediums
b. they travel slower in a solid than other solids
c. they stop when they hit a solid
d.sound waves behave the same in any medium
Answer:
A. They travel faster in a solid than other mediums
Explanation:
Sound waves travel faster in solids because the density of solids is higher than that of liquids which means that the particles are closer together and sound can be transmitted more easily.
In the free-body diagram, what is the net force? (Hint-Trig.- SOH-CAH-TOA)
a. 35 N right
b. 28 N right
c. 75 N
If 1 light year = 9.46x 1015.
m and 1 mile = 1.6 km, how many miles are in a light year? You
Answer:
5 912 500 000 000 = 5.91x10^12 miles
Explanation:
The first thing we need to do is convert the light year distance to kilometres, since we have the kilometre to mile conversion. There are 1000m in a kilometre, so we need to divide the light year value that we have by 1000, giving us 9.46x10^12 km for 1 light year.
Now that we have our value in kilometres, we simply need to divide it by 1.6 to get it in miles. Doing so gives us 5 912 500 000 000 miles, or 5.91x10^12 miles.
Hope that made sense, and let me know if you have any further questions!
please answer me!!! asappp
Answer:
omg this is hard
Explanation:
Yes it is lol
Anne pushed a cart by 12 N. How far did the cart move if the work done was 9 J?
[tex]\\ \sf\longmapsto W=Fd[/tex]
[tex]\\ \sf\longmapsto d=\dfrac{W}{F}[/tex]
[tex]\\ \sf\longmapsto d=\dfrac{9}{12}=0.72m[/tex]
Answer:
Anne pushed a cart by 12 N.
● Force = 12 N
Work done is 9 J
● Work = 9 J
=> Work = Force × distance
[tex]=> distance = \frac{work}{force} [/tex]
[tex]=> distance = \frac{9}{2} [/tex]
[tex]=> distance = 0.72m[/tex]
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Write down the units for the following physical quantities:
a. Velocity
b. Acceleration
c. Momentum
d. Force
e. Power
f. Energy
g. Pressure
Why is mass not included in the calculated height equation ?
Answer:
You can't use energy conservation when mass is removed. This has required energy that you are not taking into account.
Answer:
because some time it dose not need to be i equation becasue it is not need
Explanation:
Imagine that you are immersed under a beautiful cosmic meteor shower. Which
instrument would BEST help you view the largest portion of the sky?
refracting telescope
binoculars
sextant
compound telescope
Answer:
binoculars
Explanation: I am taking astronomy
Answer: B) binoculars just took the test
Explanation:
How much protein would be consumed with a 3-ounce serving of
this food?
A. 0g
B. 5g
C. 10g
D.15g
Please Help me
Answer:
15kg
(i actually did this)
Explanation:
k12
hope this helped!
i hope you ace it!
Answer: B) 5g
I took the 4.11 Unit Test: Nutrition quiz.
A plane is traveling with an air velocity of 720 kilometers/hour due east. It experiences a headwind of 16 kilometers/hour. Find the resultant velocity and direction of the plane with respect to the ground.
i need working steps and answers
Explanation:
I will definitely explain you if you follow me please
When you view the pendulum’s swing, it shows that at the very top of the swing KE = 0. What does that tell you about the pendulum’s motion at that point?
it tells you that it has a lot of force
Answer:
Since I couldn't find the other answers to the same question, I wrote the wrong answer to help ya'll get the sample response. So here's from Edge
Explanation:
Sample Response: If KE = 0, the pendulum is not moving. At the top of the swing, the pendulum must stop for a brief moment.
on earth what is the weight of a large screen tv thas has amass of 75 kg
Answer:
Explanation:
F = mg
F = 75(9.8)
F = 735 N
hi i think it 573 udaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
Answer:
ummm I didn't understand the question
Is the answer 0.055 seconds? (Only problem 13)
Answer:
155÷8.5
=18.235294117647
Độ hấp thụ của dung dịch có độ truyền qua 30% ở bước sóng 640nm là bao nhiêu?
Which of the following is an example of an acceptable time to ignore the rules and etiquette of a sport?
A.
when no one else notices
B.
when nobody really gets hurt
C.
when the outcome of the game isn't affected
D.
it's never acceptable to ignore rules and etiquette
Answer:
D-it's never acceptable to ignore rules and etiquette
Explanation:
We should know that it's never acceptable to ignore rules and etiquette.
What are the rules of etiquette in sports?The rules of etiquette in sports are the rules of the sports that have been document by the various sports federations.
We should know that it's never acceptable to ignore rules and etiquette. These will make the the sports a lawless act and full of chaos.
Learn more about etiquette in sports:https://brainly.com/question/979191
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