A 2.0-kg block slides on a rough horizontal surface. A force (magnitude P = 4.0 N) acting parallel to the surface is applied to the block. The magnitude of the block's acceleration is 1.2 m/s2. If P is increased to 5.0 N, determine the magnitude of the block's

Answers

Answer 1

When the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

Frictional force between the block and the horizontal surface

The frictional force between the block and the horizontal surface is determined by applying Newton's law;

∑F = ma

F - Ff = ma

Ff = F - ma

Ff = 4 - 2(1.2)

Ff = 4 - 2.4

Ff = 1.6 N

When the applied force increases to 5 N, the magnitude of the block's acceleration is calculated as follows;

F - Ff = ma

5 - 1.6 = 2a

3.4 = 2a

a = 3.4/2

a = 1.7 m/s²

Thus, when the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

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Related Questions

I need help with my earth and space science, ASAP! can someone please help?

Answers

Answer:

from what i got it is B

Hope This Helps

Once you have possession of the disk, you can run only 5 steps before you have to pass it to a teammate.

true
false

Answers

Answer:

If this is for Ultimate Frisbee, then FALSE

Explanation:

According to the rules, "In order for the disc to go from one player to another, it must at some time be in the air. No player may walk, run, or take steps in possession of the disc. The momentum of the receiver, however, must be taken into consideration." (crec.unl.edu) This means that if the player is already moving, they may take a maximum of two steps to come to a stop. (www.csun.edu).

.

.

.

Hope that helps?

1- Show that the equation d=vt2
dimensionally correct or not?

Answers

- Show that the equation d=vt2 dimensionally correct or not? ... nalsn7 is waiting for your help. Add your answer and earn points.

Which of the following scenarios will generate electricity using electromagnetic induction?
A. a highly conductive meatal moving within magnetic field

B. a changing magnetic field surrounded by plastic wires

C. electricity Being applied to a magnet

Answers

Answer:

A   generates electricity, the others do not

Explanation:

can i get some help please

Answers

Answer:

B. They reproduce

Explanation:

Both arent made up of one cell, and both arent made up of mutliple cells. Only some unicellular and multicellular organisms are infectious.

Answer:

Your answer would be:
B.) They reproduce.

Unicellular organisms are made up of only one cell that carries out all of the functions needed by the organism, while multicellular organisms use many different cells to function. Multicellular organisms are composed of more than one cell, with groups of cells differentiating to take on specialized functions.

Unicellular organisms are made up of only one cell that carries out all of the functions needed by the organism. Multicellular organisms use many different cells to function.


Unicellular organisms are single-celled.

Multicellular organisms are multi-celled.
However, both reproduce.




Explanation:

Have a great rest of your day
#TheWizzer

is this right lol i think it is but im not so sure XD

Answers

[tex]\bold{Heya!}[/tex]

Yup. your answer is correct!

→ EXPLANATION :-

1. just put the numbers in order [tex]^1^6^, ^1^8^,^2^3^,^2^4^,^2^9^,^3^0[/tex]

2. Cross off high/low pairs, we left with the numbers :-

        [tex]23,24.[/tex]

3. Add the leftover numbers.

        [tex]23 \: + 24 = 47.[/tex]

Divide the sum of 2.

        [tex]\frac{47}{2} = 23.5[/tex]

Hopefully This Helps ! ~

#LearnWithBrainly

[tex]\underline{Answer :}[/tex]

Jaceysan ~

Answer:

GIVE HIM BRAINLEST

what is the centripetal acceleration of an air plug on a car tire 250 rpm raduius of 0.45 m

Answers

The magnitude of the centripetal acceleration of the air plug on a car tire is 308.43 m/s².

What is centripetal acceleration?

Centripetal acceleration of an object is the rate of change of object's velocity with time, and it is directed inwards.

The magnitude of the centripetal acceleration of the air plug on a car tire is calculated as follows;

ac = ω²r

where;

ω angular speed (rad/s)r is radius of the tireAngular speed in radian per second

[tex]\omega = 250 \ \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1 \min}{60 \ s} \\\\\omega = 26.18 \ rad/s[/tex]

ac = (26.18)² x 0.45

ac = 308.43 m/s²

Thus, the magnitude of the centripetal acceleration of the air plug on a car tire is 308.43 m/s².

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All forces on the bullets cancel so that the net force on a bullet is zero, which means the bullet has zero acceleration and is in a state known as?

a. collision
b. equilibrium
c. momentum
d. parallel vectors

Answers

Answer:

its b equilibrium

Explanation:

trust

Select all the correct answers.
A worker is holding a filled gas cylinder still. Which two sentences are true about the energy of the filled gas cylinder?
it has no energy because it's being held still
It has gravitational potential energy because of its height.
its atoms and molecules have thermal energy
It has motion energy because it will fall if let go
its kinetic energy is being converted to potential energy
ghts reserved

Answers

it has no energy because its being held still

it has motion energy because it will fall if let go

A constant force of 10N is applied to a 2−kg crate on a rough surface that is sitting on it. The crate undergoes a frictional force against the force that moves it over the surface. (a) Assuming the coefficient of friction is \mu_k=0.24μ k​ =0.24, find the magnitude of the friction force opposes the motion?(b) What is the net force on the

WITH EXPLANATION PLEASE.

Answers

Answer:

Explanation:

The kinetic friction between crate and the surface can be calculated as follows: [tex]f_{k}=\mu_{k}N=\mu_{k}mg=(0.24)(2)(10)=4.8 N[/tex]

Assume that the direction of the 10 N constant force is on the right, the kinetic friction will go the left, then:

[tex]\sum F=F_{net}=F-f_{k}=10-4.8=5.2 N[/tex]

A constant force of 10 N is applied to a crate of mass 2 kg on a rough surface, then the net force on the crate is 5.2 N

What is friction?

Friction is the resistance to a thing sliding or rolling over another solid object. Although frictional forces can be helpful, such as the traction required to walk without sliding, they also provide a significant level of resistance to motion.

The forces of attraction, also called as adhesion, between both the contact zones of the surfaces, that are always microscopically uneven, seem to be the main contributor to friction among metals.

These "welded" joints are sheared, and friction is created by the irregularities of a harder surface scuffing down against the softer surface.

From the given data in the question,

Firstly, calculate the friction between the crate and the surface,

[tex]f_k\\[/tex] = [tex]\mu_k[/tex]mg

= (0.24)(2)(10)

= 4.8 N

Now, let's calculate the net force,

ΣF = F(N) = F - [tex]f_k[/tex]

= 10 - 7.8

= 5.2 N

Therefore, the net force will be equal to 5.2 N.

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Give Reason during change of state,the temperature remains constant

Answers

Answer:

the substance has lost or gained an ion

Explanation:

I say substance be cause I'm referring to the item are the same are similar to the substances that make up make matter like the ones on the periodic table!

A particle (q = +5.0 µC) is released from rest when it is 2.0 m from a charged particle which is held at
rest. After the positively charged particle has moved 1.0 m toward the fixed particle, it has a kinetic
energy of 50 mJ. What is the charge on the fixed particle?
a. –2.2 µC
b. +6.7 µC
c. –2.7 µC
d. +8.0 µC
e. –1.1 µC

Answers

The answer to your question is A. Have a great day

The kinetic energy of the charged particle is equal to the work done to bring it from the distance of 1 m. Hence, the total electric force here is 0.025 N. Therefore, the charge on the fixed particle is  approximately + 6.7 µC.

What is Coulomb's law ?

According Coulomb's law the electrostatic force between two charges is given by ,

F =  k q1 q2 /r²

Where q1 and q2 be the charges and r be the distance between them, k be the constant equal to 8 × 10⁹ N m²/C².

Given q1 = + 5  µC

r = 1 m.

the kinetic energy in bringing the charge of  5 µC from 2 m is given 50 mJ.

then F = 0.05 J/2 m = 0.025 N

Then q2 = F r²/ (q1 K)

q2  = 0.025 N / ( + 5  µC × 8 × 10⁹ N m²/C²)

      =  6 µC.

Therefore, option b is the approximate charge of the fixed particle.

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The diagram below show the earth and the sun, as well as four different possible positions for the moon (Z, W, X, and Y). Where will the moon be during a SOLAR eclipse as seen from Earth?

Z

W

X

Y​

Answers

Answer:

the moon will be in between the sun and the moon covering the earth view of the sun

What do radio waves, microwaves, light, and X-rays have in common

Answers

Answer:

They are all electromagnetic waves, electric and magnetic fields that oscillate together, perpendicular to each other

Relative gravitational potential energy depends on gravity, mass, and height measured from the ____.

Answers

Answer:

We dont have a understandable Ansewer for this

Explanation:

In the image, not to scale, which phase of the moon would you observe from earth?​

Answers

Answer:

The "new" moon phase is being shown because the moon shown is directly between the sun and earth and is not visible from the earth because of the brightess of the sun.

4. A swimming pool has dimensions 30 meters by 10 meters and a flat bottom. When the pool is filled to a depth of 2 meters with fresh water, what is the total force due to the water on the bottom?

Answers

Answer:

The force exerted by fresh water at the bottom is [tex]5.88*10^6Nm^2[/tex]

All my work is shown in the Picture*

~BrainlyMaster21 - Helping Students~

a current of 180 mini amphere passes through a conductor for 5minute calculate the quantity of electricity transported​

Answers

Answer:

Explanation:

You can calculate the total electric charge that passes through the conductor as [tex]q=It=(180\times 10^{-3})(5\times 60)= 54 C[/tex]. It means that the number of electron that passes through the conductor is:

[tex]n=\frac{q}{e}=\frac{54}{1.6\times 10^{-19}}=33.75\times 10^{19}[/tex]

- A teenage male is removing clothes from the dryer and is having difficulty because the items are
sticking together.
-What force is causing the clothes to stick together?
-What two factors in the dryer operation has produced this situation?
-What will misting the clothes with a light spray of water do?

Answers

We can confirm that the clothes are sticking together due to static forces created by the heat and friction of the dryer.

How will water help with this situation?

The clothes are stuck together due to static forces that arise when these materials are heated and the friction from the dryer cycle. Adding a light spray of water can help with this situation given that water is a strong conductor of electricity, which will help to dispel the charges that hold the clothes together.

Therefore, we can confirm that clothes are sticking together due to static forces created by the heat and friction of the dryer, which a light spray of water can help to dispel and separate the clothes.

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An example of a natural electric field is thunder or lightning

Answers

An example of natural electric field is Lightning

Answer:

Lightning

Explanation:

Lightning during a thunderstorm is an example of electrical energy. It is the visible discharge of atmospheric electricity. As lightning heats the air, it creates a shock wave that causes the sound of thunder.

hope this helps :)

The denizens of a distant planet live under an atmosphere made predominantly of CO2 which is a dispersive medium while attending a concert which of the following would be true for a spectator seated in the back of a large amphitheater?
I. They would hear the low notes and high notes at different times
II. They would hear the low notes and high notes at the same time

Answers

Since the frequency of sound in a medium is constant, therefore, the concert-goers would hear the low notes and high notes at the same time.

What is a dispersive medium?

A dispersive medium is a medium which spreads out or disperses a substance passing through it.

Since CO2 is a dispersive medium, it means sound waves passing through it would be dispersed based on wavelength.

The note of a sound depends on its frequency, the higher the frequency, the higher the note.

Frequency of sound is constant, therefore, the concert-goers would hear the low notes and high notes at the same time.

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The force of a hammer drives a nail into wood. This is an example of. A. An unbalanced force. B. Gravitational force. C. Friction. D. Balanced forces​

Answers

B gravitational force sorry if I’m wrong!

Answer:

What i got was A. An unbalanced force.

Hope This Helps

Help please!

An object of mass m is oscillating with a period T. The position x of the object as a function of time is given by the equation x(t)=Acosωt . The maximum net force exerted on the object while it is oscillating has a magnitude F. Which of the following expressions is correct for the maximum speed of the object during its motion?

Answers

The correct expression for the maximum speed of the object during its motion is [tex]\frac{FT}{m}[/tex].

Maximum speed of the object

The maximum speed of the object is determined using the following formulas;

v(max) = Aω

where;

A is the amplitude of the motionω is angular speed

The maximum speed of the object can also be obtained from the maximum net force on the object,

F = ma

where;

F is the maximum net forcea is the accelerationm is mass of the object

F = m(v/t)

mv = Ft

v = Ft/m

Thus, the correct expression for the maximum speed of the object during its motion is [tex]\frac{FT}{m}[/tex].

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Answer:

[tex]\frac{FT^{2} }{4\pi ^{2} }[/tex]

Explanation:

I just finished the AP Physics Exam and the other answer got the question wrong.

student asserted that a suitable unit of specific heat capacity is m²/s²°c .is he correct ? why or why not​

Answers

Answer:

Socratic app

Explanation:

it will help you

(a) Calculate the capacitance of a parallel-plate capacitor whose plates are 30. cm x 5.0 cm and are separated by a 3.0-mm air gap. (b) What is the charge on each plate if a 6-V battery is connected across the two plates? (c) What is the electric field between the plates? (d) Estimate the area of the plates needed to achieve a capacitance of 5F, given the same air gap d.​

Answers

The answers to your questions are as written below

A) capacitance of a parallel plate capacitor = 442.5 * 10⁻¹³ F

B) The charge on each plate is = 2655 * 10⁻¹³ C

C) The electric field between the plates is ; 2 * 10³ N/C

D) The estimated area of the plates is ; 1.695 * 10⁹ m²

A) Calculate the capacitance of a parallel plate capacitor

Plate dimension = 30 cm * 5 cm

Air gap ( d )  = 3 mm = 3 * 10⁻³ m

First step : calculate the area of the plate

Area of plate = 30 * 10⁻²m  *  5 * 10⁻² m

                      = 150 * 10⁻⁴ m²

Next step : determine the capacitance

Capacitance = ε₀A / d

                     = ( 8.85 * 10⁻¹² *  150 * 10⁻⁴ ) / 3 * 10⁻³

                     = 442.5 * 10⁻¹³ F

B) Calculate the charge on each plate if a 6-V battery is connected

charge on each plate can be calculated with the formula below

Q = CV

   =  442.5 * 10⁻¹³  * 6

   = 2655 * 10⁻¹³ C

C) Determine the electric field between the plates

Electric field between plates ( E ) = V / d

                                                       = 6 / 3 * 10⁻³

                                                       = 2 * 10³ N/C

D) Estimate the area of the plates

Required capacitance = 5 F

Air gap ( d ) =  3 * 10⁻³ m

applying the equation below

C = ε₀A / d -----

5 = ( 8.85 * 10⁻¹²  * A ) / 3 * 10⁻³

Therefore A :

A = ( 5 * 3 * 10⁻³ ) /  8.85 * 10⁻¹²  

   = 15 * 10⁻³ / 8.85 * 10⁻¹²

   = 1.695 * 10⁹ m²

Hence we can conclude that the answers to your questions are as written above.

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Calculate the capacitance of capacitor having 5V voltage and energy of 40J.

Answers

The answer to the question is 8

Microphones are used to convert sound vibrations to electrical signals. In one kind of microphone, sound waves move a coil of wire up and down in a magnetic field, as shown in (Figure 1). The coil shown has a diameter of 1.4 cm and has 100 turns; the 0.010 T magnetic field points radially out from the north pole to the south.

If the microphone's emf at some instant is 10 mV , what is the speed of the coil?

Answers

The speed of coil of the microphone is 0.227 m/s

What is a Microphones?

A microphone is a device used to transmit sound energy through electrical energy. it makes use of magnetic fields whose strength is measures in Tesla

Given data

D = 1.4cm = 0.014m

N = 100

B = 0.010T

emf = 10mV

speed = dx / dt = ?

solution

emf = N dΦ / dt

Φ = BA

A =  2 pi R x

R = D / 2 = 0.014 / 2 = 0.007

emf = N d ( B 2 pi R x ) / dt

emf = N B 2 pi R dx / dt

and dx / dt = speed

speed = emf / N B 2 pi R

speed = 10 * 10 ^ -3 / ( 100 * 0.010 * 2 * 3.142 * 0.007)

speed = 10 * 10 ^ -3 / ( 0.043988 )

speed = 0.227 m/s

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ε = vLB

v - velocity = ?

ε - emf = 10mV = 0.01V

B - magnetic field = 0.010 T

L - length of wire = find

Find L

N - turns of wire = 100

d = diameter = 1.4 cm = 0.014 m

L = circumference of 1 turn of wire * # of turns of wire

L = 2πr * N

L = πdN

L = π * 0.014 m * 100

L = 1.4π m

Return to main equation

ε = vLB

[tex]v = \frac{\epsilon}{LB}[/tex]

[tex]v = \frac{0.01}{(1.4\pi)*(0.010)}[/tex]

v = 0.227 m/s

A system of four capacitors is connected across a 90-V voltage source as shown in the figure.
(a) What is the potential difference across the plates of the 6.0-µF capacitor? (b) What is the charge on the 2.0-µF capacitor?​

Answers

For a system of four capacitors is connected across a 90-V voltage source, the potential difference across the plates of the 6.0-µF and 2uF capacitors  is mathematically given as

a) vd=30v

b) Q=119.7uc

What is the potential difference across the plates of the 6.0-µF and 2uF capacitors?

Generally, the equation for the charge across 6uf  is mathematically given as

Q=C6Vd

Where

1/c36=1/3+1/6

c36=2

Q3=2*90

Q3=180

Therefore

vd=180/6

vd=30v

In conclusion

1/c24=1/2+1/4

C24=1.33uf

Q2=1.33*90

Q=119.7uc

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8. A turtle crawls along a straight line, which we will call the x-axis with the positive direction to the right. The equation for the turtle's position as a function of time is x(t) = 5.0 cm + (4.00 cm/s) - (0.625 cm/s2)t2. (a) Find the turtle's initial velocity, initial position, and initial acceleration. (b) At what time is the velocity of the turtle zero? (c) How long after starting does it take the turtle to return to its starting point? (d) At what times t is the turtle a distance of 30.00 cm from its starting point? What is the velocity at each of these times?​

Answers

(a) The turtle's initial velocity is 4 m/s, initial position of the turtle is 5 cm, and initial acceleration is -1.25 m/s².

(b) The time when the velocity of the turtle is zero is 3.2 s.

(c) The time taken for the turtle to return to its starting point is 6.4 s.

(d) The time taken for the turtle to travel 30 cm is 0.08 s.

Initial velocity of the turtle

The initial velocity of the turtle is calculated as follows;

[tex]v = \frac{dx}{dt} \\\\x = 5 + 4t -0.625t^2\\\\v(t) = 4 - 1.25t\\\\v(0) = 4-0\\\\v(0) = 4 \ m/s[/tex]

Initial acceleration of the turtle

The initial acceleration of the turtle is calculated as follows;

[tex]a = \frac{dv}{dt} \\\\v(t) = 4 - 1.25t\\\\a = -1.25\ m/s^2[/tex]

Initial position of the turtle

x(t) = 5 + 4t - 0.625t²

x(0) = 5 cm

Time when the velocity becomes zero

v(t) = 4 - 1.25t

0 = 4 - 1.25t

1.25t = 4

t = 4/1.25

t = 3.2 s

Time taken to return to starting point

The total distance traveled is calculated as follows

v² = u² + 2ad

0 = (4)² + 2(-1.25)d

0 = 16 - 2.5d

2.5d = 16

d = 16/2.5

d = 6.4 m

Time to travel the given distance;

d = ut + ¹/₂at²

6.4 = (4)t + ¹/₂(-1.25)t²

6.4 = 4t - 0.625t²

0.625t² - 4t + 6.4 = 0

solve the quadratic equation using formula method;

t = 3.2 s

The time travel the distance two times, = 2 x 3.2 s = 6.4 s

Time taken for the turtle to travel 30 cm

d = ut + ¹/₂at²

0.3 = (4)t + ¹/₂(-1.25)t²

0.3 = 4t - 0.625t²

0.625t² - 4t + 0.3 = 0

solve the quadratic equation using formula method;

t = 0.08 s

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I will give brainlisted for the correct answer!

Answers

there are no measurements to work with. you'll need to measure the indicated lines with a ruler (most likely in cm) in order to obtain data to use!
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