6930553.9
1) Let's rewrite and solve the expression, note that since Multiplication and Division are on the same level of priority according to PEMDAS acronym for the order of operations:
[tex]\begin{gathered} 957.55\times8042\times\frac{6}{4}\times6= \\ 957.55\times8042\times\frac{3}{2}\times6= \\ 957.55\times8042\times\frac{3}{1}\times3= \\ 69305553.90= \end{gathered}[/tex]Notice that we simplified 6/4 to 3/2 and then 6 by 2. In addition to this, note that the 2 decimal places were kept, we can write 69305553.90 or simply 69305553.9
2) Hence, the answer is = 6930553.9
4(3c+3)-3c+1=3(3c+5)-2
The given equation is,
[tex]4(3c+3)-3c+1=3(3c+5)-2[/tex]The above equation can be simplified as follow,
[tex]undefined[/tex]URGENT!! ILL GIVE
BRAINLIEST!!!!! AND 100
POINTS!!!!!
The transformation of the map is given as; translation of 1 unit to the right and rotated 180 degree counterclockwise about origin.
What is termed as the translation?In geometry, translation refers to a function which moves an object a specified distance. The element is not otherwise altered. It is not rotated, mirrored, or resized.Each point of the element must be relocated within the same direction and at the same distance during a translation.When performing a translation, this same initial object is referred to as the pre-image, and the element after the translation is referred to as the image.For the given question;
The graph of the triangle is given,
The triangle is first translated to the 1 unit to its right such that vertex of the triangles lies on the y -axis.
Now, the triangle is rotated about origin in counter clock wise direction about 180 degrees.
Thus, the final image is shown by red triangle.
To know more about the translation, here
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What is the value of the expression below when w = 3?5W^2 – 5W – 8
According to the given data we have the following expression:
5W^2 – 5W – 8
In order to calculate the value of the expression above when w=3 we would need to substitute the w with 3 and then calculate the expression.
So, if w=3 then:
5(3)^2 -5(3) -8
=45 - 15 -8
=22
The value of 5W^2 – 5W – 8 when w = 3 would be 22
The state of California charges homeowners approximately $1,200 per year in property taxes for every $100,000 a person's home is worth. If Mr. Cohen's home in Studio City, CA is worth $1,600,000, how much does he have to pay in property taxes per year? Set up a pair of equivalent ratios and then use your knowledge of cross products to solve. You may use calculator.
We have the next information
1,200 ----- 100,000
x ----- 1,600,000
x is the missing quantity
x can be calculated in this way
[tex]x=\frac{1,600,000\cdot1200}{100,000}=19200[/tex]Mr. Cohen has to pay per year $19,200 taxes per year
y= -2x - 7x - y = -8
Given the system of equations:
[tex]\begin{gathered} y=-2x-7\rightarrow(1) \\ x-y=-8\rightarrow(2) \end{gathered}[/tex]we will find the solution to the system by graphing
To draw the lines, we need to know two points on each line
so, substitute with two values of x and calculate the corresponding value of y
For line (1): y = -2x - 7
[tex]\begin{gathered} x=0\rightarrow y=-2\cdot0-7=-7 \\ x=1\rightarrow y=-2\cdot1-7=-9 \end{gathered}[/tex]so, line (1) passes through the points ( 0, -7) and ( 1, -9)
For line (2): x - y = -8
y = x + 8
[tex]\begin{gathered} x=0\rightarrow y=8 \\ x=1\rightarrow y=1+8=9 \end{gathered}[/tex]So, line 2 passes through the points ( 0, 8) and ( 1, 9)
The graph of the line will be as shown in the following picture
As shown in the figure:
Line (1) is the blue line
Line (2) is the red line
The point of intersection = ( -5, 3)
So, the solution is point ( -5, 3)
2) A humane society claims that 30% of U.S. households own a cat. In a random sample of 210 U.S. households, 80 say they own a cat. Is there enough evidence to show this percent has changed? Use a level of significance of 0.05.
ANSWER:
There is enough evidence to reject the humane society claims
STEP-BY-STEP EXPLANATION:
Given:
p = 0.3
q = 1 - p = 1 - 0.3 = 0.7
n = 210
x = 80
Therefore:
[tex]\hat{p}=\frac{x}{n}=\frac{80}{210}=0.381[/tex]The critical values are:
[tex]Z_0=\pm1.96\text{ due }\alpha=0.05[/tex]The test statistic is:
[tex]\begin{gathered} Z=\frac{\hat{p}-p}{\sqrt[]{\frac{pq}{n}}} \\ \text{ replacing:} \\ Z=\frac{0.381-0.3}{\sqrt{\frac{0.3\cdot0.7}{210}}} \\ Z=2.56 \end{gathered}[/tex]Observe that
Z < 1.96
Therefore, reject the null hypothesis
There is enough evidence to reject the humane society claims
ANSWER:
There is enough evidence to reject the humane society claims
STEP-BY-STEP EXPLANATION:
Given:
p = 0.3
q = 1 - p = 1 - 0.3 = 0.7
n = 210
x = 80
Therefore:
[tex]\hat{p}=\frac{x}{n}=\frac{80}{210}=0.381[/tex]The critical values are:
[tex]Z_0=\pm1.96\text{ due }\alpha=0.05[/tex]The test statistic is:
[tex]\begin{gathered} Z=\frac{\hat{p}-p}{\sqrt[]{\frac{pq}{n}}} \\ \text{ replacing:} \\ Z=\frac{0.381-0.3}{\sqrt{\frac{0.3\cdot0.7}{210}}} \\ Z=2.56 \end{gathered}[/tex]Observe that
Z < 1.96
Therefore, reject the null hypothesis
There is enough evidence to reject the humane society claims
What is period of the function, give the exact value
Solution
Step 1:
Find the midline
[tex]\begin{gathered} Midline\text{ = }\frac{maximum\text{ + minimum}}{2} \\ Maximum\text{ = 11.4} \\ minimum\text{ = -5.5} \\ midline\text{ = }\frac{11.4\text{ + \lparen-5.5\rparen}}{2} \\ midline\text{ = }\frac{5.9}{2} \\ midline\text{ = 2.95} \end{gathered}[/tex]Step 2:
Find the amplitude
[tex]\begin{gathered} Amplitude\text{ = }\frac{maximum\text{ - minimum}}{2} \\ Amplitude\text{ = }\frac{11.4\text{ - \lparen-5.5\rparen}}{2} \\ Amplitude\text{ = 8.45} \end{gathered}[/tex]Step 3:
Period:
To find the period, use the values of x.
[tex]\begin{gathered} Period\text{ = 2\lparen11.4 + 5.5\rparen} \\ Period\text{ = 2 }\times\text{ 16.9} \\ period\text{ = 33.8} \end{gathered}[/tex]Final answer
Period = 33.8
The Neckware association of America reported that 3% of ties sold in the United States are bow ties. If 4 customers who purchased a tie randomly selected,find the probability that at least 1 purchased a bow tie
Pr (people with bow ties) = 3% = 0.03
p = 0.03
Pr (people without bow tie) = 1 - 0.03 = 0.97
q = 0.97
n = 4 customers
[tex]Pr(at\text{ least 1 purchased a bow tie) = 1 - Pr(none purchased a bow tie)}[/tex]To find the probability that at least 1 purchased a bow tie, we will use a binomial probability formula:
[tex]p(x=^{}X)=^nC_xp^xq^{n\text{ - x}}[/tex][tex]\begin{gathered} \text{Pr(none purchased a bow tie) = p(x = 0)} \\ \text{p(x = 0) = }^4C_0\times p^0\times q^{4\text{ - }0} \\ \text{p(x = 0) = 1 }\times\text{ 1}\times q^4=(0.97)^4 \\ \text{p(x = 0) = }0.8853 \\ \\ \text{Pr(none purchased a bow tie) = }0.8853 \end{gathered}[/tex][tex]\begin{gathered} Pr(at\text{ least 1 purchased a bow tie) = 1 - 0.8853} \\ Pr(at\text{ least 1 purchased a bow tie) = 0.1147} \end{gathered}[/tex]Fred takes out a mortgage for $60,000 at 7% for 20 years. What are his monttpayment, the total amount paid, and the cost of the mortgage?
We will have the following:
First, we determine the monthly rate:
[tex]r_m=\frac{0.07}{12}=\frac{7}{1200}[/tex]Now, we determine the monthly payment:
[tex]\begin{gathered} A=P\frac{(1+r_m)^n}{(1+r_m)^n-1} \\ \\ \Rightarrow A=60000\frac{(1+(7/1200))^{^{240}}}{(1+(7/1200))^{240}-1}\Rightarrow A\approx465.18 \end{gathered}[/tex]So, the monthly payment will be approximately $465.18.
The total amount paid will be:
[tex]\begin{gathered} X=A\ast n\ast t \\ \\ \Rightarrow X=(465.18)(12)(20)\Rightarrow X\approx111643.2 \end{gathered}[/tex]So, the total payment will be approximately $111 643.2.
The cost of the mortgage is:
[tex]c=111643.2-60000\Rightarrow c\approx51643.2[/tex]So, the cost of the mortgage is approximately $51 643.2.
leon wrote an expression that is equivalent to (30+6)÷12 witch expression could be the one leon wrote
ANSWER
(3 · 3 · 2 · 2) ÷ (3 · 2 · 2)
EXPLANATION
The given expression is also equivalent to 36 ÷ 12 - because 30 + 6 = 36.
In the equivalent expression we have:
[tex]\begin{gathered} 3\cdot3\cdot2\cdot2=36 \\ 3\cdot2\cdot2=12 \end{gathered}[/tex]Therefore it's 36 ÷ 12 too
I don't understand this. Proving and applying ASA and Salad congruence
Given two triangles, we can say that they are congruent by the SAS postulate (Side Angle Side) if both triangles have two congruent sides and the angle that they form is also congruent
In this case, we have that triangle IHG and DFE have already two congruent sides, then, to make them congruent, the angle that they each form (angle IHG and angle DEF) must be congruent so we can use the SAS postulate
oblem 9If 8 x 17 = 136, then 17 isI % of 136if 44 x 8 = 352, then 44 is% of 352
Let 'x' represents the missing number
a) x % of 136 = 17
[tex]\begin{gathered} \text{where, }x\text{ \% =}\frac{\text{x}}{100} \\ \frac{x}{100}of136=17 \\ \frac{x}{100}\times136=17 \\ \frac{136x}{100}=17 \\ 1.36x=17 \end{gathered}[/tex]Divide both sides by 1.36
[tex]\begin{gathered} \frac{1.36x}{1.36}=\frac{17}{1.36} \\ x=\frac{25}{2}=12.5 \\ \therefore x=12.5 \end{gathered}[/tex]Hence, 17 is 12.5% of 136.
b) x% of 352 = 44
[tex]\begin{gathered} \text{where, x\%=}\frac{\text{x}}{100} \\ \frac{x}{100}\times352=44 \\ \frac{352x}{100}=44 \\ 3.52x=44 \end{gathered}[/tex]Divide both sides by 3.52
[tex]\begin{gathered} \frac{3.52x}{3.52}=\frac{44}{3.52} \\ x=12.5 \\ \therefore x=12.5 \end{gathered}[/tex]Hence, 44 is 12.5% of 352.
Why is it incorrect to write {∅} to denote a set with no elements?
Answer:
It's incorrect because {∅} is saying that the set contains empty sets, which is not the same as saying the set is empty (which can be denoted by { } or ∅
Step-by-step explanation: It's all in the answer.
The graph shows the first four ordered pairs formed by the corresponding terms of two patterns. Which ordered pair would be the fifth point on this graph? (4,12) (12,4) (12,8) (10, 4) Q1 6 7 8 9 10 11 12
As shown in the graph:
There are four points:
(0,0) , (3, 1) , ( 6, 2) and ( 9, 3)
The points represent a proportion relation between x and y
The relation will be:
[tex]y=\frac{1}{3}x[/tex]So, the fifth point will be: ( 12, 4)
What is the solution to the equation?
-6 = x/8
Enter your answer in the box.
X =
Answer:
-48
Step-by-step explanation:
First, you multiple the fraction by the denominator, which is 8. You multiple both sides of the equation by 8. -6*8=-48. x/8 * 8 = x. In conclusion, -48 = x or x = -48.
Two right rectangular prisms are shown below. 2 inches 5 Inches 9 inches inches 7 NI inches inches Prism I Prism II If each prism is packed with small cubes of side length 1 inch, how many more cubes are in Prism Il than in Prism I? O 42 cubes О 210 cubes O 510 cubes O 720 cubes
The number of small cubes in the prism I can be determined as,
[tex]\begin{gathered} N_1=\frac{Volume\text{ of prism I}}{Volume\text{ of one small cube}} \\ =\frac{\frac{7}{4}\text{ in}\times\frac{5}{4}\text{ in}\times\frac{3}{2}\text{ in}}{\frac{1}{4}\text{ in}\times\frac{1}{4}\text{ in}\times\frac{1}{4}\text{ in}} \\ =210 \end{gathered}[/tex]The number of cubes in the prism II can be determined as,
[tex]\begin{gathered} N_2=\frac{2\text{ in}\times\frac{5}{2}\text{ in}\times\frac{9}{4}in}{\frac{1}{4}in\times\frac{1}{4}in\times\frac{1}{4}in} \\ N_2=720 \end{gathered}[/tex]The difference in the number of cubes is,
[tex]\begin{gathered} N_2-N_1=720-210 \\ =510 \end{gathered}[/tex]Thus, Prism II has 510 more cubes than Prism I.
Thus, option (c) is the correct solution.
Find the due date of a note dated October 24, 2018 for 2 months.
2 months after october 24th 2018 will be:
24th December 2018 which was a monday.
Add 3 days of grace period will give the due date to be 27th December 2018.
A survey team is trying to estimate the height of a mountain above a level plain. From one point on the plain, the team observes that the angle of elevation to the top of the mountain is 32o. From a point 2,000 feet closer to the mountain along the plain, the team finds that the angle of elevation is 35o. How tall (in feet) is the mountain? Round to two decimal places.
___________
To calculate the angle of elevation, just measure the angle formed by the line of sight and the level plain. The elevation of the peak is 10406.58 feet at its highest point.
This is further explained below.
What is the height of the mountain?Where
<A=30
AB=2000
<A B C=180-33
<A B C=147
<B C A=180-<A-<A B C
< B C A=180-30-147
<BCA=3
To begin, the side length BC may be calculated by using the following formula:
[tex]\frac{B C}{\sin A}=\frac{A B}{\sin C}[/tex]
So, we have:
B C=sin A *(A B/sin C)
B C=sin (30) *2000/sin (3)
B C=19107.3
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The same set of data has been fit using two different functions. The following images show the residual plots of each function.
We have the residuals of each function graphed.
They represent the distance, taking into account the sign, of each data point to the line of best fit.
A good fit will have residuals that are close to the x-axis. Also, the distribution for the residuals should not have too much spread, meaning that all the points should have approximately the same residual in ideal conditions.
In this case, we see that Function A has most residuals around the horizontal axis. Except for one of the points, that may be considered an outliert.
In the case of Function B there is a clear pattern (a quadratic relation between x and the residual) that shows that the degree of the best fit function is not the adequate (maybe two degrees lower than what should be).
This results in residuals that have a wide spread depending on the value of x.
Then, we can conclude that Function A has a better fit because the points are clustered around the x-axis.
Answer: Function A has a better fit because the points are clustered around the x-axis [Third option]
coupon A 45% off of a $73 jacket coupon B $30 rebate on a $73 Jacket
To be able to determine which among the coupon gives a lower price, let's determine what is 45% of $73 so that we could compare it with the $30 rebate. The highest amount among the two coupons will give you a lower price.
Let's determinte the 45% of 73:
[tex]\text{73 x }\frac{45\text{\%}}{100\text{\%}}\text{ }\rightarrow\text{ 73 x 0.45}[/tex][tex]\text{ = \$32.85}[/tex]Coupon A gives you $32.85 dollar off of a $73 Jacket.
Coupon A will give you a lower price compared to Coupon B. The price of the jacket will be $2.85 lesser than using Coupon B.
While waiting for the school bus, Michiko records the colors, of all cars passing through an intersection. Thetable shows the results, Estimate the probability that the next car through the intersection will be red. Exgressyour answer as a percent. If necessary, round your anewer to the nearest tenth
Given the following question:
Estimate the probability that the next car will be red.
11, 24, 16, 9
[tex]\begin{gathered} 11\text{ + 24}=35 \\ 35\text{ + 16 = 51} \\ 51\text{ + 9 = }60 \\ 60=100\text{per} \end{gathered}[/tex][tex]p=\frac{11}{60}[/tex][tex]\frac{11}{60}\times100=18.333333[/tex][tex]\begin{gathered} 18.333333 \\ 3\text{ < 5} \\ 18.3 \end{gathered}[/tex]18.3% or the first option.
Solve the problems. Simon is organizing his 36 toy cars into equal-sized piles. Which list shows all of the possible numbers of cars that could be in each pile? A 2. 3,4,6 B 1, 2, 3, 4,6 C 2, 3, 4, 6, 9, 12, 18 D 1, 2, 3, 4, 6, 9, 12, 18, 36
Consider that the total available toy cars is 36.
The factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36.
So Simon can make 1 pile of 36 toy cars, 2 piles of 18 cars each, 3 piles of 12 cars each, 4 piles of 9 cars each, 6 piles of 6 cars each, 9 piles of 4 cars each, 12 piles of 3 cars each, 18 piles of 2 cars each, and 36 piles of 1 car each.
Thus, the possible number of cars that could be in each pile are 1,2, 3, 4, 6, 9, 12, 18, 36.
Therefore, option D is the correct choice.
Suppose that a regression line for some data transformed with logarithmspredicts that when x equals 4, log(y) will equal 2.671. What does theregression line predict y will equal when x equals 4?
Explanation:
The information that we have is that when the value of x is 4
[tex]x=4[/tex]The logarithm of y is 2.671
[tex]log(y)=2.671[/tex]The question is:
What does the regression line predict y will equal when x =4?
That means we need to solve for y in
[tex]log(y)=2.671[/tex]To find the predicted y-value.
To solve for y, we make 10 the base of the two sides of the equation as shown in the following expression:
[tex]10^{log(y)}=10^{2.671}[/tex]Due to the properties of logarithms, on the left side, we will be left only with 'y'
[tex]y=10^{2.671}[/tex]And finally, solving the operations on the right-hand side, the result is:
[tex]y=468.813[/tex]Answer:
[tex]y=468.813[/tex]Determine the value(s) of x at which the function is discontinuous. Describe the discontinuity as removale or non-removable.
Answer with explanation: To find the values of x where the f(x) is discontinuous, we have to set the denominator equal to zero, doing this gives:
[tex]\begin{gathered} f(x)=\frac{x^2+10+9}{x^2-81}\Rightarrow x^2-81=0 \\ x=\sqrt[]{81}=9 \\ x=9 \end{gathered}[/tex]The f(x) is discontinuous at x = 9, following graph confirms it:
In conclusion, discontinuity is non-removable.
In the diagram below, if the measure of < C = 45 °, and side AB = 6.8, then side BC = _____.
Solution
Since
[tex]\begin{gathered} \tan45=\frac{6.8}{BC} \\ \\ \Rightarrow BC=\frac{6.8}{\tan45}=6.8\text{ since}\tan45=1 \end{gathered}[/tex]The correct option is A.
A gamer spinner, circle O, is divided into 3 regions as shown. RP is a diameter. what is the area of the shaded sector ROS if RP=8 in a m
we get that the radius is 4 and the angle is 135° which is radians 3/4 pi
so the area is
[tex]A=\frac{\pi}{2}\cdot4^2-\frac{\pi}{8}\cdot4^2=8\pi-2\pi=6\pi\approx18.85[/tex]Do 9 and 10 keep it 9th grade if you can Question 9-10
Given the formula for the volume of a cylinder:
[tex]V=\pi r^2h[/tex]You know that "r" is the radius of the cylinder and "h" is the height.
a. In order to solve the formula for "h", you can divide both sides of the formula by:
[tex]\pi r^2[/tex]As follows:
[tex]\frac{V}{\pi r^2}=\frac{\pi r^2h}{\pi r^2}[/tex][tex]h=\frac{V}{\pi r^2}[/tex]b. Having a cylindrical swimming pool, you know that:
[tex]\begin{gathered} r=12\text{ }ft \\ V=1810\text{ }ft^3 \end{gathered}[/tex]And, for this case:
[tex]\pi\approx3.14[/tex]Therefore, you can substitute values into the formula for the height of a cylinder found in Part "a" and evaluate:
[tex]\frac{V}{\pi r^2}=\frac{\pi r^2h}{\pi r^2}[/tex][tex]h=\frac{1810\text{ }ft^3}{(3.14)(12\text{ }ft)^2}[/tex][tex]h=\frac{1810\text{ }ft^3}{452.16\text{ }ft^2}[/tex][tex]h\approx4\text{ }ft[/tex]Hence, the answers are:
a.
[tex]h=\frac{V}{\pi r^2}[/tex]b.
[tex]h\approx4\text{ }ft[/tex](1 point) A variable of a population has a mean of I = 250 and a standard deviation of o = 49.
Solution
Question 1a:
- The population mean and sample mean are approximately the same in theory. The only difference is that the distribution of the sample will be wider due to a larger uncertainty caused by having less data to work with.
- Thus, we have:
[tex]\begin{gathered} \text{ Sample Mean:} \\ 250 \\ \\ \text{ Standard Deviation:} \\ \frac{\sigma}{\sqrt{n}}=\frac{49}{\sqrt{49}}=\frac{49}{7}=7 \\ \end{gathered}[/tex]Question 1b:
- The assumption is that the distribution is a normal distribution (OPTION C)
Question 1c:
Yes, the sampling distribution of the sample mean is always normal (OPTION B). This is in accordance with the central limit theorem.
a rectangular Garden has a length of 10 m and a width of 8 meters fill in the Box to show the perimeter and the area of the garden
Explanation
Step 1
Area,To find the area of a rectangle, multiply its height by its width
then
[tex]\text{Area}_{rec\tan gle}=length\cdot width[/tex]Let
length=10 m
width=8 m
replace,
[tex]\begin{gathered} \text{Area}_{rec\tan gle}=length\cdot width \\ \text{Area}_{rec\tan gle}=10\text{ m }\cdot\text{ 8 m} \\ \text{Area}_{rec\tan gle}=80m^2 \end{gathered}[/tex]Step 2
find the perimeter:
Perimeter is the distance around the outside of a shape,so for the garden the perimeter is
[tex]\text{Perimeter}_{rec\tan gle}=2(length+width)[/tex]replace,
[tex]\begin{gathered} \text{Perimeter}_{\text{garden}}=2(10m+8m) \\ \text{Perimeter}_{\text{garden}}=2(18\text{ m)} \\ \text{Perimeter}_{\text{garden}}=36\text{ m} \end{gathered}[/tex]I hope this helps you
use the quadratic formula to find both solitions to the quadratic equation given below x^2+6×=16
Answer:
x1=4
x2=-8
Step-by-step explanation:
x^2+6x-16=0
a=1 b=6 c=-16
D=b^2 - 4ab= 36+64=100
D>0, 2 sqrt
x1= -b+sqrt{D} /2= -6+10/2= 4
x2= -b-sqrt{D} /2= -6-10/2= -8
(That's what we were taught!)