7. [-/1 Points]DETAILS MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER
The length of time it takes to find a parking space at 9 A.M. follows a normal distribution with a mean of 5 minutes and a standard deviation of 3 minutes.
Eighty percent of the time, it takes more than how many minutes to find a parking space? (Round your answer to two decimal places.)
min
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The requried, for a given proportional relationship when x = 9 and z = 10, y is equal to 0.72.

If y varies directly with x and inversely with the square of z, we can write the following proportion:

y ∝ x / z²

To solve for k, we can use the initial condition:

y = k (x / z²)

When x = 4 and z = 2, y = 8. Substituting these values into the equation, we get:

8 = k (4 / 2²)

k = 8

So, the equation for the variation is:

y = 8 (x / z²)

To find y when x = 9 and z = 10, we substitute these values into the equation:

y = 8 (9 / 10²)

y = 0.72

Therefore, when x = 9 and z = 10, y is equal to 0.72.

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The value of the expression is 295.

We can simplify the expression by grouping the terms that have the same value:

26 + (25 + 25) + (24 + 24) - (23 + 23) - (22 + 22) - (21 + 21) - (20 + 20) + (19 + 19) + (18 + 18) + 17 - (16 + 16) + (15 + 15) + (14)

= 26 + 50 + 48 - 46 - 44 - 42 - 40 + 38 + 36 + 17 - 32 + 30 + 14

= 295

The given expression involves a series of numbers where some of them are added and some of them are subtracted. To simplify this expression, we need to group the terms that have the same value. We can see that the expression has pairs of numbers that add up to the same value, such as (25 + 25), (24 + 24), and so on. We can combine these pairs and simplify the expression further.

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Answer:

what

Step-by-step explanation:

Answer: 0.3%

Step-by-step explanation:

Answer:112.475

Step-by-step explanation:

The sum of the polynomial is solved to be

A. 5x^5 + 7x^3 + 7x^2 + 25x

To find the sum of the given polynomials, we simply add the like terms. Like terms in this case are terms with the same degree of x.

The given polynomials are:

(9x^5 + 7x^3 + 21x) and

(-4x^5 + 7x^2 + 4x)

Adding the like terms:

9x^5 + (-4x^5) = 5x^5

7x^3 + 0 = 7x^3

0 + 7x^2 = 7x^2

21x + 4x = 25x

Putting it all together, we get:

(9x^5 + 7x^3 + 21x) + (-4x^5 + 7x^2 + 4x) = 5x^5 + 7x^3 + 7x^2 + 25x

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Answer:

Bellow

Step-by-step explanation:

(2x³ + 4x³ - ) - (-7x² + x -5)

= 6x³ + 7x² - x + 5

(-6y² + 2y - 2) - (y² - 3y +10)

= -6y² + 2y - 2 - y² + 3y - 10

= -7y² + 5y - 12

(5x² -4x +11) + (-12x² +4x -1)

= -7x² + 0x + 10

= -7x² + 10

(10x² -5x +3) - (8x² + 6x + 4)

= 10x² - 5x + 3 - 8x² - 6x - 4

= 2x² - 11x - 1

I hope this helps!

The expressions are s

6x³ + 7x² - x + 5

-7y² + 5y - 12

-7x² - 8x + 10

2x² - 11x -1

Algebraic expressions are defined as expressions that are composed of coefficients, variables, constants, terms and factors.

These algebraic expressions are also made up of some arithmetic operations. These operations are;

From the information given, we have that;

1. (2x3 + 4x3 - ) - (-7x2 + x -5)

expand the bracket

6x³ + 7x² - x + 5

2. (-6y2 + 2y - 2) - (y2 - 3y +10)

expand the bracket

-6y² + 2y -2 - y² + 3y - 10

collect the like terms

-7y² + 5y - 12

3. (5x2 -4x +11) + (-12x2 +4x -1)

expand the bracket

5x² - 4x + 11 - 12x² - 4x - 1

-7x² - 8x + 10

4. (10x2 -5x +3) - (8x2 + 6x + 4)

expand the bracket

2x² - 11x -1

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The system of equations using the backslash operator \, which performs Gaussian elimination with partial pivoting to obtain the solution x. Finally, we display the values of x, y, and z using the disp function.

Here's a MATLAB program that solves the given system of equations using the provided values of R1, R2, and R3 from the file quiz2.mat:

% Load the data from quiz2.mat

load('quiz2.mat');

% Define the coefficient matrix and the right-hand side vector

A = [2 1 -1; -3 -1 2; -2 1 2];

b = [R1; R2; R3];

% Solve the system of equations using the backslash operator

x = A \ b;

% Display the solution

disp(['x = ' num2str(x(1))]);

disp(['y = ' num2str(x(2))]);

disp(['z = ' num2str(x(3))]);

In this program, we first load the values of R1, R2, and R3 from the file quiz2.mat using the load function. We then define the coefficient matrix A and the right-hand side vector b using the given system of equations.

We solve the system of equations using the backslash operator \, which performs Gaussian elimination with partial pivoting to obtain the solution x. Finally, we display the values of x, y, and z using the disp function.

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Therefore, the original purchased price of the medium pizza without a coupon is $10.31.

A coupon is a ticket or document that may be used in marketing to obtain a financial discount or refund when making a purchase of a good.  Customers receive a discount on their initial purchase thanks to the First Order Coupon. The first order coupon sales rule may be configured by admin in the admin area.

It aids in improving conversion rates. Frequently, yearly percentages are used to describe coupon payments. For instance, a bond with a $1,000 face value and an annual payment of $30 is said to have a 3% coupon. If the friend purchased a medium pizza for $10.31 with a 30% off coupon, then the price of the pizza after the discount is:

= 10.31 - 0.30(10.31)

= 10.31 - 3.09

= $7.22

So the price of the medium pizza without a coupon is $7.22 / (1 - 0.30) = $10.31.

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Answer:

Speed= distance/ time

Speed= (2/3)/(3/4) = 0.88 miles/hr

The expected value of a $4 bet on the state's lottery is -$0.84 and the expected value of a $4 bet on the casino game is -1.7¢ (which is equivalent to -$0.017), the state's lottery is a better bet in terms of producing a higher expected value.

a. There are 10 possible choices for each of the three digits, so the total number of different selections is 10 x 10 x 10 = 1000.

b. Since there is only one winning combination out of the 1000 possible selections, the probability of winning is 1/1000.

c. If you win, your net profit would be $500 - $4 = $496.

d. The expected value is the sum of the products of each possible outcome and its probability. In this case, the expected value is (1/1000) x $500 + (999/1000) x (-$4) = -$0.84.

e. Since the expected value of a $4 bet on the state's lottery is -$0.84 and the expected value of a $4 bet on the casino game is -1.7¢ (which is equivalent to -$0.017), the state's lottery is a better bet in terms of producing a higher expected value.

This is because the expected loss for the state's lottery is smaller than the expected loss for the casino game.

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The resulting average cost of a gaming system is approximately $678.58.

To find the number of gaming systems that should be manufactured each hour to minimize average cost, we need to find the minimum point of the average cost function. The average cost function is given by:

A(x) = C(x)/x

where C(x) is the cost function.

To find the minimum point of A(x), we can differentiate it with respect to x and set it equal to zero:

A'(x) = [C'(x)x - C(x)]/[tex]x^2[/tex] = 0

Solving for x, we get:

C'(x)x - C(x) = 0

340 + 0.001x = C(x)/x

Substituting the cost function C(x) = 1,152,000 + 340x + 0.0005x^2, we get:

340 + 0.001x = (1,152,000 + 340x + 0.0005[tex]x^2[/tex])/x

Multiplying both sides by x, we get:

340x + [tex]x^2[/tex]/2000 = 1,152,000/x

Multiplying both sides by 2000x, we get:

340[tex]x^2[/tex] + [tex]x^3[/tex] = 2,304,000

Dividing both sides by [tex]x^2[/tex], we get:

[tex]x^2[/tex] + 340x - 2,304,000/[tex]x^2[/tex] = 0

Let y =[tex]x^2,[/tex] then the equation becomes:

[tex]y^2[/tex] + 340y - 2,304,000 = 0

Solving for y using the quadratic formula, we get:

y = (-340 ± √([tex]340^2[/tex] + 4*2,304,000))/2

y ≈ 3,177.56 or y ≈ -6,517.56

Since y =[tex]x^2[/tex], we take the positive root:

[tex]x^2[/tex] ≈ 3,177.56

x ≈ 56.37

Therefore, the optimal number of gaming systems that should be manufactured each hour to minimize average cost is approximately 56.37.

To find the resulting average cost of a gaming system, we plug this value into the average cost function:

A(56.37) = C(56.37)/56.37 ≈ $678.58

Therefore, the resulting average cost of a gaming system is approximately $678.58.

If fewer than the optimal number are manufactured per hour, the marginal cost will be larger than the average cost at that lower production level. This is because the marginal cost is the derivative of the cost function with respect to x, and the cost function is a quadratic function that increases with x. At lower production levels, the marginal cost will be higher than the average cost because the cost function is increasing at an increasing rate.

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a) there are 32 possible subsets of C.

b)The cardinality of set M is the sum of these numbers, which is 781.

C) there are an infinite number of possible strings, the cardinality of set K, which contains all possible strings using letters from C, is also infinite.

a) The cardinality of set C is 5, as there are 5 distinct elements in the set. The cardinality of the power set of C, denoted as P(C), is 2^5 = 32, as there are 32 possible subsets of C.

b) A tree showing all possible strings of letters of length 5 or less starting with the letter z would look like:

z

├── v

│   ├── v

│   ├── w

│   ├── x

│   └── y

├── w

│   ├── v

│   ├── w

│   ├── x

│   └── y

├── x

│   ├── v

│   ├── w

│   ├── x

│   └── y

├── y

│   ├── v

│   ├── w

│   ├── x

│   └── y

└── z

   ├── v

   ├── w

   ├── x

   └── y

The cardinality of set M, which contains all possible strings of length 5 or less with letters from C, is equal to the sum of the cardinalities of all sets of strings of each length. Thus,

Set of strings Number of strings

Length 1 1

Length 2 5

Length 3 5^2 = 25

Length 4 5^3 = 125

Length 5 5^4 = 625

The cardinality of set M is the sum of these numbers, which is 1 + 5 + 25 + 125 + 625 = 781.

c) A tree showing all possible strings of any length would have an infinite number of branches. Each node in the tree would represent a different string, and the branches emanating from each node would represent the next letter that could be added to the string. Since there are an infinite number of possible strings, the cardinality of set K, which contains all possible strings using letters from C, is also infinite.

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A) tan(2θ) = 5/12

B) cos(2θ) = -31

C) tan(θ/2) = ±(6/5)√6 - 3i/5

Given tanθ = -5 and 3x < θ < 5x/2. We need to find:

A) tan(2θ)

B) cos(2θ)

C) tan(θ/2)

First, we can find the value of θ using the given inequality:

3x < θ < 5x/2

Multiplying all terms by 2, we get:

6x < 2θ < 5x

Dividing all terms by 2, we get:

3x < θ < 5x/2

Since we are given that tanθ = -5, we know that θ is in the third quadrant. In the third quadrant, tanθ is negative and sinθ is negative, while cosθ is positive.

Using the Pythagorean identity, we can find the value of cosθ:

[tex]cos^2θ + sin^2θ = 1[/tex]

[tex]cos^2θ + (-5)^2 = 1[/tex]

[tex]cos^2θ = 1 - 25[/tex]

cosθ = √(1 - 25) = √(-24) = 2i√6/6 (taking the positive root since cosθ is positive in the third quadrant)

Now, we can use the double angle identities to find A) and B):

A) tan(2θ) = 2tanθ/(1-tan^2θ)

= 2(-5)/(1-(-5)^2)

= 10/24

= 5/12

B) cos(2θ) = [tex]cos^2θ - sin^2θ[/tex]

= (2i√[tex]6/6)^2[/tex] - (-[tex]5)^2[/tex]

= -6/3 - 25

= -31

Finally, we can use the half-angle identity to find C):

C) tan(θ/2) = ±√((1-cosθ)/1+cosθ))

= ±√((1-2i√6/6)/(1+2i√6/6))

= ±√((1-2i√[tex]6/6)^2[/tex]/(1-24/36))

= ±√((1-2i√6/[tex]6)^2[/tex]/(5/36))

= ±(6/5)√6 - 3i/5

Therefore, the exact values are:

A) tan(2θ) = 5/12

B) cos(2θ) = -31

C) tan(θ/2) = ±(6/5)√6 - 3i/5

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Answer:

Opens downward and is thinner than the parent function.

The a value is negative remember I told you ax^2+bx+x=0

if the a value is negative it opens down, but if it's positive it opens up.

This graph is also stretched because a is greater than 1.

The value of x and y are 27 and 47 unit.

We are given the hexagon shape which we need to find the angles.

5x -1 + 4x + 2 + 5x + 6 + 2x - 2 + 3x + 5 + x - 10 = 540

Combine the like terms;

5x -1 + 4x + 2 + 5x + 6 + 2x - 2 + 3x + 5 + x - 10 = 540

9x + 7x + 4x = 540

20x = 540

x = 27

Now solve for y;

3x + 5 + 2y = 180

3(27) + 5 + 2y = 180

2y = 180 - 5 - 81

2y = 94

y = 47

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The surface area of this cube is 384 sq ft.

To find the surface area of this cube:

You can follow these steps:

STEP 1: Identify the number of faces on the cube: A cube has 6 faces.
STEP 2: Determine the area of each face: Each face measures 64 sq ft.
STEP 3: Calculate the surface area: Multiply the area of each face by the total number of faces.

Surface area = (Area of each face) x (Total number of faces)
Surface area = (64 sq ft) x (6)
Surface area = 384 sq ft

The surface area of this cube is 384 sq ft.

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The Q(Q) = {(a,b,c,√2a+b+c) | a,b,c ∈ Q} ∪ {(-a,b,c,-√2a+b+c) | a,b,c ∈ Q}, where Q is the  cubic.

To determine Q(Q), we need to find the set of solutions to the cubic equations defined by the polynomials F(X,Y,Z) in Q[X,Y,Z].

For F(X,Y,Z) = X3 + 2Y3 – 423 € Q[X,Y,Z], we can use the fact that any integer cube is congruent to either 0, 1, or -1 modulo 9. Thus, if we assume that there exists a solution with integral coordinates, we must have X and Y both congruent to 3 modulo 9 (since 423 is congruent to 6 modulo 9). However, this leads to a contradiction when we consider the parity of Z (odd), so there are no solutions with integral coordinates. Therefore, Q(Q) = {}.

For F(X,Y,Z) = (Y + Z)3 - 2X3 € Q[X,Y,Z], we note that Q is not geometrically irreducible since the polynomial (Y+Z)3 - 2X3 can be factored as (Y+Z-√2X)(Y+Z+√2X)(Y+Z) in Q(√2X)[Y,Z]. Thus, we need to study the Galois action on the irreducible components.

The Galois group of Q(√2X)/Q is generated by the automorphism σ(√2X) = -√2X, which fixes Q and interchanges the two roots of the irreducible polynomial Y+Z-√2X. Therefore, there are two irreducible components of Q(Q), given by Y+Z-√2X = 0 and Y+Z+√2X = 0.

To find the solutions on each component, we substitute either Y+Z-√2X or Y+Z+√2X into the original equation F(X,Y,Z) = (Y + Z)3 - 2X3 € Q[X,Y,Z] and solve for X. We obtain:

- For Y+Z-√2X = 0, we have X = (Y+Z)√2/∛2. Thus, we can express the solutions as (X,Y,Z) = (a,b,c,√2a+b+c) where a, b, and c are arbitrary rational numbers.
- For Y+Z+√2X = 0, we have X = -(Y+Z)√2/∛2. Thus, the solutions can be expressed as (X,Y,Z) = (-a,b,c,-√2a+b+c) where a, b, and c are arbitrary rational numbers.

Therefore, Q(Q) = {(a,b,c,√2a+b+c) | a,b,c ∈ Q} ∪ {(-a,b,c,-√2a+b+c) | a,b,c ∈ Q}.

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d. random and estimated. The number of tickets in the box labeled 1 represents the number of customers in the population who are satisfied with their internet service provider.

This quantity is not fixed or known, as we are using a sample to estimate the proportion of the population who are satisfied. The tickets in the box are randomly selected from the population, and the number in the box is estimated based on the proportion of satisfied customers in the sample. Therefore, the quantity is both random and estimated. we can calculate the sample proportion and construct a confidence interval to estimate the true proportion of satisfied customers in the population.

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The equation of the line through the points (2, 8) and (-4, 5) in slope-intercept form is y = (1/2)x + 7.

To determine the equation of the line through the points (2, 8) and (-4, 5) and express it in slope-intercept form, follow these steps:

1. Calculate the slope (m) of the line using the formula: m = (y2 - y1) / (x2 - x1)
  In our case, (x1, y1) = (2, 8) and (x2, y2) = (-4, 5).
  m = (5 - 8) / (-4 - 2) = (-3) / (-6) = 1/2

2. Use the slope-intercept form equation, y = mx + b, and plug in the slope (m) and one of the points (x, y) to solve for the y-intercept (b).
  Let's use the point (2, 8).
  8 = (1/2) * 2 + b
  8 = 1 + b
  b = 7

3. Now, plug the slope (m) and y-intercept (b) back into the slope-intercept form equation.
  y = mx + b
  y = (1/2)x + 7

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Note that the graph that best shows the estimates of the survey rounded to the nearest 500  is Graph D. See the attached image.

If we have a total of 10,000 people, and 240 people respond to a survey.

If 180 of them own cars and 60 don't, then the ratio of the respondent to the total population is:

Those that own car = (180/240) * 10,000

= 7,500  people

Those that don't own a car = (60/240) * 10,000

= 2,500 people

This is what is depicted in Graph D, hence option D is the correct answer.

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Approximate value is 7.5245.

To find the value of the expression (3x + 2x² + 3 sin(x)) and evaluate it at x = 1 using trigonometry, follow these steps:

Step 1: Substitute x = 1 into the expression:
(3(1) + 2(1)² + 3 sin(1))

Step 2: Simplify the expression:
(3 + 2 + 3 sin(1))

Step 3: Evaluate sin(1) (Note that x=1 is in radians):
sin(1) ≈ 0.8415

Step 4: Substitute the value of sin(1) back into the expression:
(3 + 2 + 3(0.8415))

Step 5: Calculate the final value:
3 + 2 + 3(0.8415) ≈ 5 + 2.5245 = 7.5245

So, the value of the expression (3x + 2x² + 3 sin(x)) evaluated at x = 1 is approximately 7.5245. The given options do not include this value, so the correct answer is d. None.

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The rank correlation is 1, this means that the two variables being compared are monotonically related, even if their relationship is not linear.

Given the data

X, ...rankX.....Y.....rankY......d=rx-ry........d²

4.........4...........-5......4................0..............0

53.......3.........-1........3................0...............0

86.......2.........13.......2................0................0

162......1..........16.......1.................0...............0

Then, using the rank correlation formula

p = 1 — 6•Σd² / n(n²—1)

p = 1 - 6• 0 / 4(4²-1)

p = 1 - 0

p = 1

So, the rank correlation is 1, this means that the two variables being compared are monotonically related, even if their relationship is not linear.

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Full Question: Use the table of values to calculate the linear correlation coefficient r.

X Y

4 -5

53 -1

86 13

162 16

Answer:41.5

Step-by-step explanation:

By arranging the data from smallest to largest, like this:

40, 41, 42, 45, we can take the average of the two middle values divided by 2 to find the median. This is done with an equation like this:

(41+42)/2

Which comes out to be 41.5.

The time that it takes for the coconut to land on the net is given as follows:

t = 2.1 seconds.

The quadratic function giving the height of the coconut after t seconds is defined as follows:

h(t) = -4.9t² + S.

In which S represents the height of the canopy.

Ellie uses a pole pruner to release a bunch of coconuts from a canopy 24 meters above the ground, hence the value of S is given as follows:

S = 24.

Thus the function is:

h(t) = -4.9t² + 24.

The coconuts hit the net when h(t) = 1.5, hence the time is obtained as follows:

1.5 = -4.9t² + 24

4.9t² = 22.5

t = sqrt(22.5/4.9)

t = 2.1 seconds.

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The rule for the transformation formed by the translation 8 units right and 5 units down followed by a 180 degree rotation is (x, y) changes to (-x - 8, 5 - y).

Consider a point (x, y).

When this point is translated such that it is translated 8 units right and 5 units down, then the point becomes,

(x, y) changes to (x + 8, y - 5).

This point is rotated 180 degrees.

When a point (x, y) is rotated 180 degrees, then the point becomes (-x, -y).

So, (x + 8, y - 5) changes to (-x - 8, -y + 5) = (-x - 8, 5 - y).

Hence the rule for the given transformation is (-x - 8, 5 - y).

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The policyholder is insured for $238,000, and the actual cash value of the damages is $110,000. Therefore, the insurer will pay the actual cash value, which is $110,000, so option A is correct.

The claim payment for a flood policy is based on the replacement cost value (RCV) of the property and the actual cash value (ACV) of the damage. The RCV represents the cost to replace the damaged property with new property of like kind and quality, while the ACV represents the RCV less depreciation.

Even though the duplex's replacement cost is $240,000, it is insured for $238,000 in this case. The cash value of the flood damage is $110000. Since the policyholder is only covered for a portion of the replacement cost, the claim payment will be determined by the damage's $110,000 actual cash value. Therefore, the answer is A.

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Geometric shapes are defined as shapes that have a clear and defined outline, uniformity in their angles, and consistent measurements. Examples of geometric shapes include squares, triangles, and stars. These shapes are typically man-made and are commonly found in architecture and design.

On the other hand, organic shapes are irregular and asymmetrical in nature, often resembling forms found in nature. Examples of organic shapes include leaves, hands, and clouds. These shapes are often found in art and can evoke a sense of movement and fluidity.
When teaching shapes to a kindergarten class, it is important to differentiate between geometric and organic shapes to help children understand the unique characteristics of each. This can help develop their cognitive and spatial skills and encourage creativity in their art and design projects.

Overall, the distinction between geometric and organic shapes is an important concept to introduce to young children, as it lays the foundation for future learning in math and design. By teaching them the differences between these two types of shapes, we can help them develop a deeper understanding of the world around them.

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