3.(a) Draw the following five-carbon hydrocarbons:•Pentane•Pentene•Pentyne(e)Classify each molecule and explain the differences between them. (Classes of organic molecules include alkanes, alkenes, alkynes, alcohols, carboxylic acids, aldehydes, ketones, esters, ethers, amines, and amides.)

Answer:

Explanation:

Here, we want to get the functional group is found in amino acids

In the amino acids, we can get amines, carboxylic acid groups, and the carbon chain

Looking at the options, we can see that the amine group is the right option here as the other two are not available

The oxidation number of O is usually -2 and in this case it is.

Our ion is ReO₄⁻. It has a total charge of -1. The charge of the four atoms of O is -8. With this information we can write an equation. X will represent the oxidation state of Re.

Total charge = Oxidation state of Re + 4 * Oxidation state of O

- 1 = x + 4 * (-2)

- 1 = x - 8

-1 + 8 = x

x = +7

So the oxidation state of Re is +7.

The elements with the same number of energy levels are the ones that belong to the same period of the periodic table.

Copper and Zinc both belong to the 4th period of the periodic table.

Nickel belongs to the 4th period and palladium to the 5th period.

Lithium belongs to the 2nd period and Magnesium to the 3rd period.

It means that the correct answer is Copper and Zinc, they belong to the same period,

87.77 ml will provide the recommended daily allowance of vitamin C.

- To calculate the milliliters of vegetable juice that will provide 100% of the recommended daily allowance of vitamin C, we can use a mathematical Rule of Three:

So, 87.77 ml will provide the recommended daily allowance of vitamin C.

[tex]2K_(s) + Cl_2_(g)[/tex] ⇒ [tex]2KCl_(aq)[/tex]

Type of Reaction: Synthesis

What is a synthesis reaction?

When 2 or more substances react to form a single compound.

The set of quantum numbers (3, 3, -3, -1/2), and  (2, 1, 2, +1/2) are not possible. Therefore, options c and e are correct.

The set of numbers that can describe the position and energy of the electron. We have four quantum numbers principal, azimuthal, magnetic, and spin quantum numbers.

Principal quantum numbers (n) tell about the principal electron shell of the atom and the most probable distance between the electrons and the nucleus. The azimuthal quantum number (l) tells about the shape of an orbital in which an electron is present. It has values equal to l = n - 1.

The magnetic quantum number tells about the total number of orbitals in a subshell and the orientation of these orbitals.  The value of m lies in between -l to +l. The value of the spin quantum number describes the direction of spin of an electron and it has only two values +½ and -½.

In option c, the principle (n) and azimuthal (l) quantum number has the same value but when n = 3 the possible values of l are 2, 1, 0. In option d, the magnetic quantum number has the value of 2 while l has 1 which is not possible because when l= 1 the values of m can be  +1, 0, and -1.

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To read the measuring cylinder we first count the number of smaller divisions between the marked interval. In this case it is 10 intervals. The marked intervals are 60 and 80, therefore between these values we have 20. We will now divide the 20 by the 10 intervalswhich is equal to 2. Now each interval has a numerical value of 2. We read from the bottom of the meniscus. The meniscus is ttouching the 5th line and so we say 5 x 2=10, we add this to 60.

Answer: 60+10= 70,

Step 1

The reaction must be written, completed, and balanced:

2 NaOH + H2SO4 => Na2SO4 + H2O

-----------

Step 2

Information provided:

Mass of NaOH = 40.0 g

Mass of H2SO4 = 60.0 g

--

Information needed:

The molar masses:

NaOH) 40.0 g/mol approx.

H2SO4) 98.0 g/mol approx.

-----------

Step 3

The limiting reactant?

By stoichiometry:

1 mole NaOH = 40.0 g

1 mole H2SO4 = 98.0 g

2 NaOH + H2SO4 => Na2SO4 + H2O

2 x 40.0 g NaOH ----------- 98.0 g H2SO4

40.0 g NaOH ----------- X

X = 40.0 g NaOH x 98.0 g H2SO4/2 x 40.0 g NaOH = 49.0 g H2SO4

For 40.0 g of NaOH, 49.0 g of H2SO4 is needed but is provided 60.0 g of H2SO4. Therefore, the excess is the H2SO4, and the limiting reactant is the NaOH.

Answer: the limiting reactant is NaOH

We will reconstruct the model in the following manner :

From the above diagram we can see that :

• number of Carbon atom = 3

• number of hydrogen atom = 8

• rewrite this in an alphabetical order, you get :

Answer

The specific heat of the glass = 0.7366 J/g°C

Explanation

Given:

Mass of the glass sample, m = 9.3 g

Quantity of heat given off, Q = 87 J

Change in temperature, ΔT = 12.7 °C

What to find:

The specific heat, c of the glass.

Step-by-step solution:

The specific heat, c of the glass can be calculated using the given formula below.

Putting the values of the given parameters into the formula, we have;

Therefore, the specific heat of the glass is 0.7366 J/g°C

Answer:

Explanation:

Here, we want to get the maximum volume of solution that can be produced

Given:

Molarity = 1.8 M

Number of Moles = 0.9 moles

Find:

Volume

Equation Used:

Number of moles = molarity * volume

Answer:

To convert this to mL, we multiply the volume by 1000 since 1 L = 1000 mL

Thus, we have it that:

We start by counting the number of atoms of each element on each side of the reaction.

Now we balance the reaction by trial and error, starting with chlorine. We have 2 chlorine atoms in the reactants and 3 clear atoms in the products, so to balance we cross the coefficients placing 3 on the reactant side and two on the product side in the respective molecules:

Now we continue with the oxygens, we have 3 oxygens on the reactant side and 1 on the products, so we put the coefficient 3 on the products side in front of the respective molecule:

We now have the balanced equation. We have 3 Mg atoms, 6 Cl atoms, 2 Cr atoms, and 3 O atoms on each side of the reaction.

Answer

101.3 mL

Explanation

Given:

The initial temperature, T₁ = 148.5 °C = (148.5°C + 273) = 421.5 K

The initial volume, V₁ = 241.8 mL

Final temperature, T₂ = -96.4 °C = (-96.4°C + 273) = 176.6 K

What to find:

The final volume of the gas.

Step-by-step solution:

The final volume, V₂ of the gas can be calculated using Charle's law formula.

The final volume of the gas is 101.3 mL

Co-60 is used medically for radiation therapy as implants and as an external source of radiation exposure the half-life of Co-60 is 5, 272 years 2.000 mg sample will remain after 21, 088 years is 0.0625 gm left

Radiation therapy is the cancer treatment that uses high doses of radiation to kill cancer cell and shrink tumor

Here given data is Co-60 is 5, 272 years and we have to find the number of half lives in 21, 088 years = ?

21, 088/5, 272 = 4 half lives

(1/2)⁵   = 1/32 nd  of the original will be left

1/32×2.000mg = 0.0625 gm left

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Answer:

80g

Explanation:

The law of conservation of matter states that matter cannot be created nor destroyed. Basically, whatever mass you have at the beginning of a reaction, should be the same as at the end of the reaction on the product side.

Since here it lets you know that a total of 100g (30g + 70g) were produced on the product side, that means that we started off with 100g in our reactant side.

We have given that one material is 20g on our reactant side but we need the mass of the other. To find the mass of the other material, simply subtract 20g from the total mass created on the product side.

100g - 20g = 80g

The 80g would be the missing amount from the reactant side that isn't stated.

0.167L

In order to know how much L of the 3M NaOH solution would you need, we will simply set up an equal proportion solution expressed as;

C1 and C2 are the concentration of the solutions

V1 and V2 are the volumes of the solutions

Given the following parameters;

C1 = 1M

V1 = 500mL

C2 = 3M

V2 = ?

Substitute the given parameters into the formula above to get the required litre of solution needed.

Divide both sides by 3:

Converting to litres

Since 1mL = 0.001L

166.67mL = x

Cross multiply

Hence the amount of L of the 3M NaOH solution would you need is 0.167L

The first thing will be to finish the reaction that happens in the experiment to the reactional HCl and sodium bicarbonate (NaHCO3). The balanced reaction is the following:

Now, we must determine which is the limiting reactant. To do this we are going to convert all the data they give us to moles.

For HCl we are given the molarity, so the moles will be:

Now the moles of sodium bicarbonate are found using its molar mass:

By stoichiometry, we have that one mole of NaHCO3 reacts with one mole of HCl. We have more moles of NaHCO3 than HCl. Therefore, HCl will be the limiting reactant.

So the reaction will occur according to the number of moles of HCl. Now the ratio between HCl and CO2 gas formed is 1 to 1. For one mole of HCl that reacts, 1 mole of CO2 will be formed.

so, the number

In order to answer this question we will use the molar mass of Chromium, which is 52 g/mol, that means that in every 1 mol of Cr, we will have 52 grams of it:

52 g = 1 mol

260 g = x moles

52x = 260

x = 5 moles of Chromium

3.01×10²³molecules.

The formula for the number of molecules of a compound given the number of moles is expressed as:

Get the moles of ethane gas using the formula:

Determine the required number of molecules of ethane

Hence the molecule of ethane gas that is in 15 grams of the compound is 3.01×10²³molecules.

(1)

The molecule NH4NO3 is ammonium nitrate, which makes a redox reaction.

It produces N2, O2, and H2O, which are nitrogen, oxygen, and water.

The ions are 2NH4+ and 2NO3-.

2 molecules of N2, 4 molecules of H2O, and 1 molecule of O2.

(2)

There are 2 moles of NH4NO3, 2 moles of N2, 4 moles of H2O, and 1 mole of O2.

(3)

The molar mass of NH4NO3 is 80.043 grams per mole, but there are 2 moles of it, so there are 160.09 grams of NH4NO3.

There are 56.03 grams of N2 because there are 2 moles of it. (1 mole N2 = 28.0134 g/mol).

There are 72.06 grams of H2O because there are 4 moles of it (1 mole H2O = 18.02 g/mol).

There are 31.998 grams of O2 because there's just 1 mole of it.

(4)

The formula units of NH4NO3 is 1.204x10^24, which is equivalent to 2 moles.

Nitrogen has the same formula units because there are 2 moles of it, so it's 1.204x10^24.

Water has 2.409x10^24 because there are moles of it.

Oxygen has 6.022x10^23 because there's just 1 mole, inis Avogadro's Number.

1) A precipitate called [tex]Fe(OH)_{2}[/tex]

2) A precipitate is formed called [tex]Mg(CH_{3} COO)_{2}[/tex]

The term precipitate is used to describe the product that is formed when there is a reaction between two aqueous phase reactants that leads to the formation of a solid product from the reaction as we can see from the image that is attached.

we now have to look at the reactions as we can see them in the mage that is attached. We must note that we can only say that a precipitate has been formed if the product is solid after we have mixed the aqueous phase reactants.

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Answer:

60.0 mL of 0.322 M potassium iodide are combined with 20.0 mL of 0.530 M lead (II) nitrate.

How many grams of lead (II) iodide will precipitate? (you must write your own reaction)

Explanation:

Answer: C4H10O2

Explanation:

At first find the percentage composition, in 1.67 g compound what percentage of Carbon, Hydrogen and Oxygen are there. Then from those percentages through unitary method find out how much Carbon, Hydrogen and Oxygen would be there in 90.1 g of compound. From those amounts finds their mole number, as in divide the obtained amount by their gram equivalent mass. The numbers you obtain are the corresponding number of Carbon Hydrogen and Oxygen in one molecule of the compound. Hope this helps

The limiting reactant, given that 5.0 moles of CH₄ and 1.0 mole of O₂ are in the reactor is O₂

We'll begin by obtainig the balanced equation for the reaction. This is given below:

CH₄ + 2O₂ —> CO₂ + 2H₂O

The limiting reactant for the reaciont can be obtained as illustrated below:

From the balanced equation above,

1 mole of CH₄ reacted with 2 moles of O₂

Therefore,

5 moles of CH₄ will react with = 5 × 2 = 10 moles of O₂

From the above illustration, we can see that a higher amount of O₂ is needed to react completely with 5 moles of CH₄.

Thus, we can conclude that O₂ is the limiting reactant.

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Answer: 43.38 number of atoms

Explanation: If you look at this formula, then this one molecule contains six oxygen atoms. That means number of moles of oxygen atoms. That is six times the number of moles and of calcium nitrate, That is six, multiply 7.23, which comes out to be 43.38 moles of oxygen atom.

Answer:

Explanation:

Here, we want to calculate the density of the gas at STP

We use a modification of the general gas law as follows

Mathematically:

where:

P1 is the initial pressure which is 0.95 atm

D1 is the initial density which is 0.066 g/l

T1 is the initial temperature in Kelvin (we add the temperature in Celsius with 273 K : 32 + 273 = 305 K)

P2 is the pressure at STP which is 1 atm

D2 is the density that we want to calculate

T2 is the temperature at STP which is 273 K

Substituting the values, we have it that:

The frequency of the green light from a traffic signal is 5.76 * 10¹⁴ Hz

The frequency of the light is 1.85 * 10¹⁶ Hz

The frequency of the light is 4.84 * 10¹⁴ Hz

The energy of the photons is 1.172 * 10⁻³ J

The energy of the photons is 4.34 * 10⁻² J

The frequency of light can be found given the wavelength from the formula below:

8. The frequency of the green light from a traffic signal is calculated below:

velocity of light = 3.0 * 10⁸ m/s

wavelength = 5.2 x 10⁻⁷ m

Frequency = 3.0 * 10⁸ / 5.2 x 10⁻⁷

frequency = 5.76 * 10¹⁴ Hz

9. The frequency of the light is calculated below:

velocity of light = 3.0 * 10⁸ m/s

wavelength = 16.23 x 10⁻⁹ m

Frequency = 3.0 * 10⁸ / 16.23 x 10⁻⁹

frequency = 1.85 * 10¹⁶ Hz

10. The frequency of the light is calculated below:

velocity of light = 3.0 * 10⁸ m/s

wavelength = 6.2 x 10⁻⁷ m

Frequency = 3.0 * 10⁸ / 6.2 x 10⁻⁷

frequency = 4.84 * 10¹⁴ Hz

11. The energy of one of the photons will be calculated as follows:

E = hf

E = hc/λ

Energy of the photons =  2.3 x 10¹¹ x hc/λ

h = 6.626 * 10⁻³⁴Js

λ = 3.9 x 10⁻¹² m

c = 3.0 * 10⁸ m/s

E =   2.3 x 10¹¹ x 6.626 * 10⁻³⁴ * 3.0 * 10⁸ / 3.9 x 10⁻¹²

E = 1.172 * 10⁻³ J

12. The energy of one of the photons will be calculated as follows:

E = hf

E = hc/λ

Energy of the photons =  9.4 x 10¹⁶ x hc/λ

h = 6.626 * 10⁻³⁴Js

λ = 4.3 x 10⁻⁷ m

c = 3.0 * 10⁸ m/s

E =   9.4 x 10¹⁶ x 6.626 * 10⁻³⁴ * 3.0 * 10⁸ / 4.3 x 10⁻⁷

E = 4.34 * 10⁻² J

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Answer

B. The bonds in the compound are covalent

Explanation

The carbon, oxygen, and hydrogen that combine in a specific ratio to form the sugar are nonmetals. From what was learned about elements and the periodic table, nonmetals form covalent bonds among themselves to form compounds.

So what is true about the bonding in sugar is:

B. The bonds in the compound are covalent.