3. In a figure a small square is cutting out from the largesquare. The area of the remaining part is 91 cm². The sum of Sides equal to 52cm.
(a). If the side of large square is x and the side of smallest square is y then find the area of the remaining part?
(b). Find the sides of the smallest square?
(c). Find the areas of the two squares?​

Step-by-step explanation:

[tex]\large\underline{\sf{Solution-}}[/tex]

Given that,

Further given that,

It means

We know,

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ Perimeter_{[square]} \: = \: 4 \times side \: }}}[/tex]

So, using this, we have

[tex]\rm :\longmapsto\:4x + 4y = 52[/tex]

[tex]\rm :\longmapsto\:4(x + y) = 52[/tex]

[tex]\rm\implies \:\boxed{\tt{ x + y = 13}} - - - - (1)[/tex]

Now, Further given that,

If square EFGH is cutting out from square ABCD, the area of remaining part is 91 square cm.

It means

[tex]\rm :\longmapsto\:Area_{[ABCD]} - Area_{[EFGH]} = 91[/tex]

We know,

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ Area_{[square]} = 4 \times side}}}[/tex]

So, using this, we get

[tex]\rm :\longmapsto\: {x}^{2} - {y}^{2} = 91[/tex]

can be further rewritten as using algebraic Identity,

[tex]\rm :\longmapsto\:(x + y)(x - y) = 91[/tex]

[tex]\rm :\longmapsto\:13(x - y) = 91[/tex]

[tex]\red{ \bigg\{  \sf \: \because \: using \: equation \: (1) \bigg\}}[/tex]

[tex]\rm\implies \:\boxed{\tt{ x - y = 7}} - - - - (2)[/tex]

On adding equation (1) and (2), we get

[tex]\rm :\longmapsto\:2x = 13 + 7[/tex]

[tex]\rm :\longmapsto\:2x = 20[/tex]

[tex]\rm\implies \:\boxed{ \: \bf \: \: x \: = \: 10 \:cm \: \: }[/tex]

On substituting the value of x in equation (1), we have

[tex]\rm :\longmapsto\:10 + y = 13[/tex]

[tex]\rm :\longmapsto\:y = 13 - 10[/tex]

[tex]\rm\implies \:\boxed{ \: \bf \: \: y \: = \: 3 \:cm \: \: }[/tex]

So,

[tex]\rm\implies \:\boxed{Side_{[square \: EFGH]} = y \: = 3 \: cm}[/tex]

and

[tex]\rm\implies \:\boxed{Side_{[square \: ABCD]} = x \: = 10 \: cm}[/tex]

Also,

[tex]\rm :\longmapsto\:\boxed{Area_{[square \: ABCD]} = {10}^{2} = 100 \: {cm}^{2} }[/tex]

[tex]\rm :\longmapsto\:\boxed{Area_{[squareEFGH] }\: = {3}^{2} = 9 \: {cm}^{2} }[/tex]

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[tex]\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}[/tex]

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