1. Ethan is dragging a bag of grass from the garage to the street on the evening before garbage pick-up day. The diagram at the right is a free-body diagram. It uses arrows to represent the forces acting upon the bag. Each force is labeled according to type. The magnitude of the force is represented by the size of the arrow. Use the free body diagram to determine the net force acting upon the bag. The values of the individual forces are:

Fgrav = Fnorm = 60.5 N
Fapp = 40.2 N
Ffrict = 5.7 N.

The acceleration is approximately 4 m/s². Therefore, the correct answer is:

A. 4 m/s²

To determine the acceleration from the graph, we need to look at how the velocity changes over time. Acceleration is defined as the rate of change of velocity with respect to time. In other words, it is the slope of the velocity-time graph.

Looking at the graph, we can see that the velocity changes from 0 m/s to 4 m/s over a time interval of 2 seconds. To calculate the acceleration, we use the formula:

Acceleration (a) = Change in velocity / Change in time

Acceleration (a) = (4 m/s - 0 m/s) / (2 s) = 4 m/s²

So, the acceleration is approximately 4 m/s². Therefore, the correct answer is:

A. 4 m/s²

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Answer:

7 feet because 2 feet and 5 feet make seven.

Answer:

6.66666 sec/m or 6 2/3 sec/m

Answer:

6.67 meters per second

Explanation:

120/18=6.67 meters per second

Answer:

22.9km

Explanation:

If the mountain is 1.00 km higher in elevation than your position and the angle measured from your position to the top of a mountain is 2.50∘.then you would have been 22.9 km far away from the mountain

A right-angled triangle's side ratios are the easiest way to express a function of an arc or angle, such as the sine, cosine, tangent, cotangent, secant, or cosecant. These functions are known as trigonometric functions.

As given in the problem you measure the angle from your position to the top of a mountain to be 2.50∘. If the mountain is 1.00 km higher in elevation than your position,

By using the tangent trigonometric function for the right triangle

tanθ = height /distance

tan 2.5° = 1000 m /distance

distance =1000 m /tan 2.5°

              =22903 m

              =22.9 km

Thus, the mountain is 22.9 km far away from your position

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Answer:

put an X on the second one, the third one, the forth one, and the last one

Explanation:

can i get braineist pls

Answer:

Explanation: actually for moving it in an CONSTANT velocity u need a zero accleration

F-f=ma,a=0 hence F=f=Nα=mgα=1,495.63 N

Answer:

The cosmic microwave background (CMB) is thought to be leftover radiation from the Big Bang or the time when the universe began. As the theory goes, when the universe was born it underwent rapid inflation and expansion. ... Which means its radiation is most visible in the microwave part of the electromagnetic spectrum.

Explanation:

Hope this helps.

Answer:

C

Explanation:

Answer:

We want to find at what angle a projectile is launched given that at the highest point, the speed is 6m/s.

The launch angle of the projectile is 60°.

Remember that the only acceleration will appear on the vertical axis, and this is the gravitational acceleration, this means that on the horizontal axis we will have a constant speed.

Also remember that when an object is on its highest point, the vertical velocity is equal to zero, then it only has horizontal velocity (which we know it is a constant).

Then we can conclude that the horizontal velocity is equal to 6m/s.

If the angle is measured from the horizontal axis, we will have that the horizontal velocity is a projection on the x-axis of the initial speed, this is:

12m/s*cos(θ) = 6m/s

Now we can solve this for theta.

cos(θ) = (6m/s)/(12 m/s) = 1/2

θ = Acos(1/2) = 60°

The launch angle of the projectile is 60°.

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Answer:

The acceleration of the car was one meter per second squared.

Explanation:

We can use one of the kinematic equations:

[tex]\displaystyle v_f = v_i + at[/tex]

Where v_f is the final velocity, v_i is the initial velocity, a is the acceleration, and t is the time (in seconds).

The final velocity is 40 m/s, the initial velocity is 35 m/s, and the time is 5 s. Substitute and solve for a:

[tex]\displaystyle \begin{aligned}(40 \text{ m/s}) &= (35 \text{ m/s}) + a(5\text{ s}) \\ \\ 5 \text{ m/s} &= a(5\text{ s}) \\ \\ a &= 1\text{ m/s$^2$} \end{aligned}[/tex]

In conclusion, the acceleration of the car was one meter per second squared.

Find the distance traveled by a car that travels with an average speed of 110 km/h for 3.5 h

To solve for distance:

d = v t

d = 110 × 3.5

d = 385 km

How long does it take a baseball moving with an average speed of 35 m/s to travel 18 m?

To solve for time:

t = d/v

t = 18 / 35

t = 0.514286

t = 0.5 s

What is the average speed of a car that travels 870 km in 14.5 h?

To solve for average speed:

v = d/t

v = 870 / 14.5

v = 60 km/h

Answer:The net force acting on the car is 3×103 Newtons

Explanation:

Answer:

0.1 miles

Explanation:

1mile/10 minutes

to get some miles/1 minute:

since you divided the 10 minutes to get 1 minute you also divide the 1 mile by 10 to get the number of miles per minutes

ei 1/10 = 0.1 miles

Answer:

95

Explanation:

Answer:

See Below

Explanation:

It is a change in the distribution of electric charge on one object because of  the influence a nearby object that has an electric charge.  So if an object with a negative charge is brought near to a neutral object, the neutral object will alter itself so that one side becomes more positive and the other side becomes more negative.

Electrostatic induction occurs whenever any object is placed in an electric field.

Answer:

c

Explanation:

ytkjsgxhxkvgakavsvdjddhdbiwbe vs

The pressure due to water at the bottom of the tank  is 200000 Pascal.

It is the ratio between the force being applied and the surface area being applied to. The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure.

Given parameters:

Depth of the tank = 25 meter.

Depth of water in the tank: d = 25×4/5 meter = 20 meter.

Density of water: ρ = 1000 kg/m³.

Acceleration due to gravity: g = 10 m/s².

Hence, the pressure due to water at the bottom of the tank

= depth of water (d) × density of water (ρ) × acceleration of the gravity (g)

=  20 meter × 1000 kg/m³ × 10 m/s²

= 200000 Newton/meter²

=200000 Pascal.

Hence, the pressure due to water at the bottom of the tank  is 200000 Pascal.

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Answer:  15.9 m/s

Explanation:

KE = 1/2(mv^2)

190,000J = 1/2(3000kg)*v^2

1 J = 1 kg*m^2/s^2

190,000 kg*m^2/s^2 = 1/2(3000kg)*v^2

v^2 = (190,000 kg*m^2/s^2)/(1/2(3000kg))

v^2 = (190,000 kg*m^2/s^2)/(1500kg))

v^2 = 126.6667 m^2/s^2

v = 11.25 mm/s velocity of 3000kg vehicle

With the same kinetic energy, a vehicle of 1500kg would have a different velocity:

190,000 kg*m^2/s^2 = 1/2(1500kg)*v^2

190,000 kg*m^2/s^2 =(750kg)*v^2

v^2 = 253.33 m^2/s^2

v = 15.9 m/s

We have that  the final velocity of a ball thrown downward at 10 m/s after 2 seconds is

V=29.6m/s

From the question we are told

What is the final velocity of a ball thrown downward at 10 m/s after 2 seconds?

Where

Generally the Newton's equation for Motion   is mathematically given as

[tex]V=U+at\\\\V=U+gt\\\\V=10+9.8*2\\\\V=29.6m/s[/tex]

Therefore

the final velocity of a ball thrown downward at 10 m/s after 2 seconds is

V=29.6m/s

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Answer:

Virchow

Explanation:

Rudolf Virchow

Answer:

It is Rudolf Virchow! Hope this help and if I could get brainliest that would be much appreciated.

Explanation:

Answer:

Explanation:

A classic projectile motion question. Horizontal motion does not matter whatsoever in the context of this equation as we are looking at the vertical component of velocity only. Since the question states that it is fired horizontally, there is no vertical component of velocity. Thus, v0y = 0.

Assuming the projectile is on the Earth, we can use the free-fall acceleration, 9.8 m/s^2.

The question gives us Δy, which is 37.3m.

Using the second kinematics equation, Δy = v0t + (at^2)/2, we can substitute in the values.

37.3 = 0 + 0.5(9.8)t^2

37.3 = 4.9t^2

7.61224489796 = t^2

t = 2.75902970226 seconds.

Answer:

Displacement = 8.4m

Explanation:

Hope that this is helpful.

Have a great day.

[tex]v = 60.7m {s}^{ - 1} \: u \: = 5.26m {s}^{ - 1 } \: t = 15s \: \: \: \: \: \\ a \: = \frac{v - u}{t} \\ a \: = \frac{60 .7- 5.26}{15} \\ a = 3.7m {s}^{ - 28} \\ {v}^{2} = {u}^{2} + 2as \\ {60.7}^{2} = {5.26}^{2} + 2 \times 3.7 \times s \\ 60.7 =27 .7 + 2 \times 3.7s \\60.7 = 29.7 \times 3.7s \\ 60.7 - 29.7 = 3.7s \\ 31 = 3.7s \\ \frac{31}{3.7} = \frac{3.7s}{3.7} \\ s = 8.4m[/tex]

Answer:

Salt is an ionic compound, consisting of a crystal, lattice structure of the two ions Na+ and Cl-. Salt water is full of sodium chloride molecules. ... The chlorine has one extra electron and its outer electron shell is complete, so like sodium it too cannot bond with other atoms.

Have a good day! <3Miss Hawaii

Answer:

Something like table salt (NaCl) is a compound because it is made from more than one kind of element (sodium and chlorine), but it is not a molecule because the bond that holds NaCl together is an ionic bond.

Answer:

I can't see the pic so I cannot ans

Answer:

1.0147 rounded to the nearest thousandths place is 1.015

Answer:

1.015

Explanation:

If you put the number in place value, you have 1 in the ones place, 0 in the tenths place, 1 in the hundreds place, 4 in the thousandths place, and 7 in the ten thousandths place. In order to know how to round 4, you must look at the number directly after it. Since 7 is greater than five, round up to ten. This increases 4 by 1 which would give you the answer 1.015.

Answer:

in a direction parallel to the direction that the wave moves

Explanation:

Answer:

parallel to the direction....

Answer:

If the work done by a resistive force is W then

W = F d = m a d where a is the acceleration of the object and d the distance traveled during this acceleration,

The object started with potential energy E = m g h

m g h = m a d

d = g h / a    where d is the distance traveled