The coefficient of kinetic friction between the box and the floor, μ = 0.1 m/2.
Equation :To find out the coefficient of kinetic friction between the box and the floor we will the formula,
μ = F/N
where,
F is friction force
N is normal force
So by question given is mass and acceleration we have to calculate friction force,
So to find F we use,
F = ma
F = 10 x 0.75 m/2
F = 7.5 m/2
By using formula of coefficient of kinetic friction,
μ = F/N
μ = 7.5 / 75
μ = 0.1 m/2
Coefficient of kinetic friction :The kinetic friction coefficient (F) is the ratio of the kinetic friction force (F) between both the surfaces in contact during motion to the normal force Ff/N. The static and kinetic coefficients of friction are both affected by the surfaces in contact. Their values are determined through experimentation.
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Two point charges Q₁ = +6.00 nC and Q₂ = -2.00 nC are separated by 45.0 cm.
(a) What is the electric potential at a point midway between the charges?
V
(b) What is the potential energy of the pair of charges?
J
What is the significance of the algebraic sign of your answer?
Positive work must be done to separate the charges.
Negative work must be done to separate the charges.
Answer:
(a) The electric potential at a point midway between the charges is 160 V.
(b) The potential energy of the pair of charges is -2.4x10⁻⁷ J.
What is electrical potential energy?
The effort necessary to assemble a system of point charges by bringing them close together, as in the system from an infinite distance, is defined as the electric potential energy of the system. Alternatively, the electric potential energy of any given charge or system of charges is defined as the total work performed by an external agent in moving the charge or system of charges from infinity to the current configuration without acceleration.
Explanation:
The electric potential at a point between two point charges Q₁ = +6.00nC and Q₂ = -2.00 nC separated by 45.0 cm is found to be 160 V and the potential energy of the pair of charges is -2.4 x 10⁻⁷ J.
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How many acres are in 1 square mile? One acre is equal to 43,560 ft2.
Answer:
There are 640 acres in 1 square mile I think
If you were a member of Congress, what legislation would you introduce if acid rain from a coal
There are many reasons. The easiest solution is because the rain that we remember acidic has a low pH; it has a better amount of hydrogen ions.
Acid rain manipulation implies three adjustments a notably extra complicated and cumbersome regulatory program beneath the Clean Air Act, new emission manipulation prices for initial rollback requirements and next offsets, and on account of these, new impediments to utility and commercial plant creation, expansion, and modernization.
The Acid Rain application (ARP) has brought widespread discounts in sulfur dioxide (SO2) and nitrogen oxide (NOX) emissions from fossil fuel-fired strength flora, full-size environmental and human fitness blessings, and a ways lower-than-anticipated prices.
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the magnitude of B-3A
Answer:
the magnitude of b 3A
Explanation:
2b 1 a
3. Describe what black holes are?
Answer: a place in space where gravity pulls so much that even light can not get out.
Answer:
black holes are holes that can suck this world with its high gravity
At Boston's Fenway Park, it is 310 feet (94.5 m) from homeplate to the left field wall The Green Monster which is 30 feet (9.2 m) high. If a batter hits a baseball at an initial height of 0.9 m, given the following velocities, does it clear the wall, hit the wall, or fall short?
If the velocity of x direction is 25 m/s
If the velocity of y direction is 20.5 m/s
Find the maximum height
Baseball will hit the wall due to less height from the The Green Monster wall.
from the data, we have in
velocity of x direction is 25 m/s
velocity of y direction is 20.5 m/s
now, the horizontally:
velocity=distance/time
time=distance/velocity
time=94.5/25
t=3.76sec
now for vertically: we will apply kinematics equation
s=ut+[tex]\frac{at^2}{2}[/tex]
now putting the values,
s=77.08-69.27
s=7.80m
now,
the initial height from baseball hit=0.9m
now, total height=0.9+7.80
s=8.7
8.7 m is less than wall height
so it will hit the wall
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Aliens are bombarding the Earth with asteroids from an orbit of 100km. If they launch the
asteroid with a speed of 100.0m/s, how long do the earthlings have to evacuate their city?
Distance is the overall motion of an object with no regard to its path. we can define distance as how much floor an item has included no matter it's beginning or ending point.
Given,
Distance = 100km
=100000
Speed =100m/sec
Distance=speed × time
Time= [tex]\frac{distance}{speed}[/tex]
Time =100000/100
time =1000 sec
Distance is a numerical or on occasion qualitative size of how far apart items or factors are. In physics or regular usage, the space might also check with a physical length or an estimation primarily based on other standards.
Displacement is described because of the alternate the function of an item. it's miles a vector amount and has a course and value. it's miles represented as an arrow that points from the beginning role to the very last function. as an example- If an item moves from A role to B, then the item's function modifications.
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Reacting quickly to avoid being struck, the diner moves 2.00 m horizontally directly toward the waiter opening the champagne bottle. Determine the horizontal distance, d in meters, between the waiter and the diner at the time the cork reaches where the diner had previously been sitting.
The horizontal distance d in meters between the waiter and the diner at the time the cork reaches where the diner had previously been sitting is 9.7 m
What is distance?The term distance refers to the quantity of length between two points. it is usually measured in meters but has other units.
Given data
u = 15.6
∅ = 78.5 deg
g = 9.81
solving for time tt = 2 * u * sin ∅ / g
t = 2 * 15.6 * sin 78.5 / 9.81
t = 30.57 / 9.81
t = 3.12 s
Solving for horizontal distance, d in metersd = u * co ∅ * t
d = 15.6 * cos 78.5 * 3.12
d = 9.7 m
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complete question
The cork from a champagne bottle slips through the hands of a waiter opening it, moving with an initial velocity v0 = 15.6 m/s at an angle θ = 78.5° above horizontal. A diner is sitting a horizontal distance d away when this happens. Assume the cork leaves the waiter’s hands at the same vertical level as the diner and that the cork falls back to this vertical level when it reaches the diner. Use a Cartesian coordinate system with the origin at the cork's initial position.
Calculate the time, td in seconds, for the cork to reach the diner.
Reacting quickly to avoid being struck, the diner moves 2.00 m horizontally directly toward the waiter opening the champagne bottle. Determine the horizontal distance, d in meters, between the waiter and the diner at the time the cork reaches where the diner had previously been sitting.
the velocity (v) of dimension of a, b and c.
According to the given statement The dimension of a, b and c is LT⁻² , L and T.
What do we mean by dimension?She took exact measurements of the room's length, width, height, and depth in one direction (for example, the distance between the ceiling and the floor of a room). The space was unexpectedly small in all three of its dimensions. Dimensions include length, breadth, and height. One dimension is that of a line, two dimensions are those of a square, and three dimensions are those of a cube (3D).
Briefing:According to the principle of dimensional homogenity
Dimension of v = dimension of at = dimension of b/t+c
Dimension of a = [tex]\frac{[\mathrm{v}]}{[\mathrm{t}]}=\frac{\mathrm{LT}^{-2}}{\mathrm{~T}}=\left[\mathrm{LT}^{-2}\right][/tex]
Dimension of b = [v][t]=[LT −1 T]=[L]
Dimension of c = [t]=[T]
According to the given statement The dimension of a, b and c is LT⁻² , L and T.
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A skateboarder initially traveling at 1.8 m/s accelerates at a rate of 1.5 m/s² for 2.5 s. How far does the skateboarder go in this time?
The skateboarder will travel a distance of 9.19 m
We know that,
a = ( v - u ) / t
Δv = ( v + u ) / 2 ( If acceleration is constant )
Δv = d / t
where,
a = Acceleration
v= Final velocity
u = Initial velocity
t = Time taken
d = Displacement
Δv = Average velocity
Given that,
u = 1.8 m / s
a = 1.5 m / s²
t = 2.5 s
a = ( v - u ) / t
1.5 = ( v - 1.8 ) / 2.5
v = 3.75 + 1.8
v = 5.55 m / s
Δv = ( 5.55 + 1.8 ) / 2
Δv = 3.675 m / s
d = Δv * t = 3.675 * 2.5
d = 9.19 m
If the initial and final velocity is known, average velocity can be calculated by taking the average value of initial and final velocity, if the acceleration is constant.
Therefore, the skateboarder will travel a distance of 9.19 m
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A bike accelerates from 0 m/s to 15 m/s over the span of 5 seconds. How fast is the bike
traveling after 2.5 seconds?
The bike is travelling at 22.5 m/s after 2.5 s
What is acceleration?This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the time How to determine the acceleration Initial velocity (u) = 0 m/sFinal velocity (v) = 15 m/sTime (t) = 5 sAcceleration (a) =?a = (v – u) / t
a = (15 – 0) / 5
a = 3 m/s²
How to determine the final velocity in the first 2.5 s Initial velocity (u) = 15 m/sAcceleration (a) = 3 m/s²Time (t) = 2.5 s Final velocity (v) = ?a = (v – u) / t
3 = (v – 15) / 2.5
Cross multiply
v – 15 = 3 × 2.5
v – 15 = 7.5
Collect like terms
v = 7.5 + 15
v = 22.5 m/s
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how much would i weigh on the star methuselah i weigh 100 pounds
Your weigh on the star methuselah is 38 pounds.
For example, if you weigh 100 pounds on Earth, you would weigh only 38 pounds on Mercury. That's because Mercury weighs less than Earth, and therefore its gravity would pull less on your body.
The element mercury has the atomic number 80 and the symbol Hg. Formerly called hydrargyrum from the Greek words Hydor (water) and Argyros, it's also known as quicksilver (silver). the sole other metallic element that is known to be liquid at standard circumstances for temperature and pressure is the halogen bromine, while metals like cesium, gallium, and rubidium melt just above temperature. Mercury may be a heavy, silvery d-block element.
Worldwide deposits of mercury, primarily as cinnabar, are found (mercuric sulfide). Grinding either synthetic mercuric sulfide or natural cinnabar yields the red color vermilion.
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Number of Humans
(Billions)
The World's Population Growth
7.0-
6.0
5.0-
4.0
3.0
2.0-
1.0-
0
1000
1200
+
1400
1600
1800
2000
Answer: The world population increased from 1 billion in 1800 to around 8 billion today. The world population growth rate declined from around 2% per year 50
Explanation:
A fishing boat leaves a marina with a constant speed of 3.4 m/s. A speedboat leaves the marina 12 s later with an initial speed of 2.8 m/s and an acceleration of 1.7 m/s2. Let the time the speedboat leaves the marina be t = 0 and let the direction of travel of both boats be the positive x direction.
Write position-time equations for fishing boat.
Express your answer in terms of t .
When does the speedboat catch up with the fishing boat?
(a) The position-time equations for fishing boat is x = 3.4t + 40.8
(b) The time taken for the speedboat to catch up with the fishing boat is 7.1 seconds.
Position-time equations for fishing boat
The position-time equations for fishing boat will be obtained by applying the principle of relative velocity as follows;
Let the time when the speedboat catches up = t
let the total time spent by fishing boat = t + 12
Distance traveled by the fishingx = 3.4(t + 12)
x = 3.4t + 40.8
Distance between between the fishing boat and speed boatfishing boat is moving at a constant speed = 3.4 m/s
speed boat started moving 12 seconds later,
distance between the boats = 3.4 m/s x 12 s = 40.8 m
final velocity of the speedboatv = u + at
v = 2.8 + 1.7t
set up the following equation to determine the time when the two boats meet.
vt - x = 40.8
t(2.8 + 1.7t) - (3.4t + 40.8) = 40.8
2.8t + 1.7t² - 3.4t - 40.8 = 40.8
1.7t² - 0.6t - 81.6 = 0
solve the quadratic equation using formula method as shown below;
a = 1.7, b = -0.6, c = -81.6
t = 7.1 seconds
Thus, the time taken for the speedboat to catch up with the fishing boat is 7.1 seconds.
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If one oscillation has 3.0 times the energy of a second one of equal frequency and mass, what is the ratio of their amplitudes?
The ratio of their amplitudes is 3.
The relation between energy and amplitude is as follows:
[tex]E_{1} = \frac{1}{2} KA_{1} ^{2}[/tex]
[tex]E_{2} =\frac{1}{2} KA_{2} ^{2}[/tex]
As, we know , one oscillation has 3.0 times the energy of a second one of equal frequency and mass i.e.,
[tex]E_{1} = 3E_{2}[/tex]
So, [tex]\frac{1}{2} KA_{1} ^{2} = 3(\frac{1}{2}KA_{2} ^{2} )[/tex]
[tex]A_{1} ^{2} = 3A_{2} ^{2}[/tex]
[tex]\frac{A_{1}^{2} }{A_{2}^{2} } = 3[/tex]
Therefore, the ratio of their amplitudes is 3.
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A race car traveling at 33 m/s accelerates at a rate of 0.8 m/s2 for 20 s. What is the final speed of the race car?
A. 42.4 m/s
B. 61.3 m/s
C. 49.0 m/s
D. 10.4 m/s
The final speed of the race car, given the data is 49 m/s (Option C)
What is acceleration?The acceleration of an object is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the timeWith the above formula, we can determine the final velocity of the car. Details below:
How to determine the final velocity of the car Initial velocity (u) = 33 m/sAcceleration (a) = 0.8 m/s²Time (t) =20 s Final velocity (v) = ?a = (v – u) / t
0.8 = (v – 33) / 20
Cross multiply
v – 33 = 0.8 × 20
v – 33 = 16
Collect like terms
v = 16 + 33
v = 49 m/s
Thus, the final velocity of the car is 49 m/s (Option C)
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jasmine broke the antenna k. her radio receiver how will this most likely affect jasmine radio?
Answer:An antenna is an array of conductors, that is connected to the receiver or transmitter.
It transmits and receives radio waves in the horizontal directions or in a particular direction.
It may include a parasitic elements, and reflectors that can serve to direct the radio waves into a beam like pattern or some other patter.
Explanation:
It will not capture modulated radio waves.
A river is moving east at vWE = 2.29 m/s. A boat starts from the dock heading θ = 39.3 degrees north of west at vBW = 7.18 m/s, relative to the water. The river is w = 1130 m wide.
What is the speed of the boat, in m/s, with respect to Earth?
Answer:
The speed of the boat, in m/s, with respect to Earth, is vBE = 7.52 m/s.
Explanation:
vBE = vBW + vWE
vBE = 7.18 m/s + 2.29 m/s
vBE = 7.52 m/s
A person weighs 1,913 N on earth. They are taken to a planet where the gravity is 0.6 times the gravity of earth. What is their new weight?
Answer: gravity of earth = 9.8 n/s , new weight of the body on other planet = mg = 1.913 ×6×9.8=112..5
Explanation:
Q. If the amplitude of the two
waves are 3 units and unit
respectively. Show by the
principle of superposition
that the ratio of the
amplitudes Of the stationary
wave at an antinode and
node is 2:1
That would be the proportion between the difference and the total of the two amplitudes (when they are in phase, or as they say, "add coherently") (when they are out of phase or "add destructively").
What is a wave's amplitude?The amplitude of a wave is the maximum displacement of a particle on the medium from its rest point. The distance between the rest and the crest can be thought of as the amplitude. Measuring the amplitude from the rest position to the trough position is another method of determining it.
How can amplitude be determined?The height between the center line and the peak is known as the amplitude (or to the trough). Alternatively, we might multiply the height from highest to lowest places by 2.
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Two small objects A and B are fixed in place and separated by a distance of 3.00 cm in a vacuum. Object A has a
charge of +2.00 С and object B has a charge of -2.00 C. How many electrons must be removed from object A and
placed on object B to make the electrostatic force into an attractive force with a magnitude of 68.0 N.
The number of electrons that must be removed from object A and placed on object B is 1.24 * [tex]10^{19}[/tex]
We know that,
E = k [tex]q_{1}[/tex] [tex]q_{2}[/tex] / r²
where,
E = Electrostatic force
k = Coulomb's constant
[tex]q_{1}[/tex], [tex]q_{2}[/tex] = Point charges
r = Distance between two charges
Given that,
[tex]q_{1}[/tex] = 2 + ne C
[tex]q_{2}[/tex] = - 2 - ne C
r = 3 cm
k = 9 * [tex]10^{9}[/tex] N m² / C²
E = - 68 N ( Since it is attractive )
- 68 = 9 * [tex]10^{9}[/tex] ( 2 - ne ) ( - 2 + ne ) / ( 3 * [tex]10^{-2}[/tex] )²
68 * [tex]10^{-4}[/tex] / 3 * [tex]10^{9}[/tex] = ( 2 - ne )²
2.27 * [tex]10^{-12}[/tex] = ( 2 - ne )²
1.5 * [tex]10^{-6}[/tex] = 2 - ne
ne = 1.98
n = 1.98 / 1.6 * [tex]10^{-19}[/tex] = 1.24 * [tex]10^{19}[/tex]
The given problem is an electrostatic attractive force because the two point charges are unlike charges. If the charges are like, then the electrostatic force will be repulsive.
Therefore, the number of electrons that must be removed from object A and placed on object B is 1.24 * [tex]10^{19}[/tex]
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A circuit is wired with a power supply, a resistor and an ammeter (for measuring current). The ammeter reads a current of 24 mA (milliAmps). Determine the new current if the voltage of the power supply was ...increased by a factor of 3 and the resistance was held constant
If the voltage of the power supply is increased by a factor of 3 and the resistance was held constant, the new current will be 0.008 A or 8 mA
What is Power ?Power is the rate at which work is done. Electrical power is measured in Watt.
Given that a circuit is wired with a power supply, a resistor and an ammeter (for measuring current). The ammeter reads a current of 24 mA Determine the new current if the voltage of the power supply was increased by a factor of 3 and the resistance was held constant
Let the
initial voltage = VNew voltage = 3VResistance = RInitial current = 24 mANew current = ?From the power formula, power will always be constant. That is, initial power will be the same with new power
Since P = IV
24/1000 V = I × 3V
0.024V = 3IV
V cancels out
3I = 0.024
I = 0.024/3
I = 0.008 A
Therefore, the new current will be 0.008 A.
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Study Island!!!!!
The average annual snowfall values for four different cities are shown in the table below.
which of the following conclusions could be made from this data?
A. It snows more in Green Bay than in Buffalo on average.
B. It snows less in Green Bay than in Kalamazoo on average.
C. It snows more in Kalamazoo than in Buffalo on average.
D. It snows less in Buffalo than in Bristol on average.
Based on the data attached, the option of the conclusion that could be made from this data is option B. It snows less in Green Bay than in Kalamazoo on average.
.
What snow implies?The term snows is known to be a kind of a small white crystals of ice that is known to be formed as a result of direct water vapor of the air.
It is known to be a measure or a mass of snowflakes that is said to have fallen to earth.
Therefore, from the data, one can see that the snow fell a lot in Buffalo and from it one can also see that Kalamazoo has almost times 2 of the snow in Green Bay.
Therefore, Based on the data attached, the option of the conclusion that could be made from this data is option B. It snows less in Green Bay than in Kalamazoo on average.
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What is the amperage of a current flowing through a wire that has a resistance of 30 ohms if the voltage is 90 volts?
12 ohms
2700 amps
3 amps
4 volts
A bicycle was traveling at 7.6 m/s when it decided to accelerate at a rate of 4.2 m/s² over 89 m. What was its final velocity?
The final velocity of the bicycle with initial velocity 7.6m/s and acceleration 4.2 m/s² is 28.4 m/s.
What is Velocity?
velocity is defined as the displacement per unit time.
What is Acceleration?
Acceleration is defined as the rate of change of velocity per unit time
i.e.
acceleration = (final velocity (v)-initial velocity)/time taken (t)
given:
initial velocity of the bicycle (u) = 7.6m/s
acceleration of the bicycle (a)=4.2m/s²
displacement of the bicycle=89m
using newtons third law of motion :
v²-u²=2×a×s
using the given value in question we get
v² = (7.6)²+2×4.2×89
v=28.4 m/s
the final velocity of the bicycle with initial velocity 7.6m/s and acceleration 4.2 m/s² is 28.4 m/s.
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Many traffic lights charge when a car roll up intersection. How does the light sense the presence of car? Describe briefly.
Answer:
There are a few ways that traffic lights can sense the presence of a car. One way is by using inductive loops that are installed on the road. These loops detect changes in the magnetic field caused by a car passing over them. Another way is by using infrared sensors that detect the heat signature of a car.
Explanation:
Hope this helps!
Didn't mean the first rating. It wouldn't allow me to change it. D is correct. Thank you :)
Answer:
ok
Explanation:
je cuene8snw72me8rntirn3ue 2 eje eue due rbd
1. Brittney Vargas undergoes 2 displacements while playing field hockey. First, she goes
26.5 m, West. She then turns and goes 18.7 m, South. What is Brittney's resultant
displacement? (Magnitude and direction!!!)
The resultant displacement is 32.4 m due west of south.
What is the displacement?The term displacement has to do with the change in the position of a body in a particular direction. Displacement is a vector quantity. We have to find the resultant displacement algebraically;
Hence;
Resultant displacement = √((26.5)^2 + 18.7)^2
Resultant displacement = 32.4 m due west of south
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what is the velocity of a car that traveled a total of 75 km north in 1.5 hours
Answer:
Velocity is distance + direction / time
so your answer is
75 km north / 1.5 hours
75/1.5 km north/ hours =
50 km / hours north
An object is moving forward along a straight path. Find the object’s position relative to it’s starting point if it moves 12.8 cm/s for 0.5 min.
The distance traveled by the object from its initial position is 384 cm.
Distance is the sum of an object's movements, regardless of direction. Without respect to the object's starting or finishing positions, distance can be defined as the amount of space it has traveled.
An object is moving in a straight path.
The speed of the object from its initial position is 12.8 cm/s.
The object is moving for 05 minutes.
Then, t = 0.5 min = 0.5 × 60 = 30 seconds.
Now, the speed of an object is the distance of the object per unit time.
Therefore,
s = d / t
d = s × t
d = ( 12.8 cm/s ) × ( 30 s )
d = 384 cm
Hence, the object's position from its initial position is 384 cm.
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