Write the two half-reactions that occur in this electroplating process. Be sure to include the states of the elements or ions.

Answer:

Linear (180 degrees)

Explanation:

Whenever you have a triple bond between two atoms, their shape is linear. This is because the density of the triple bond between them is heavy, causing the other things attached to the atom to be as far away as possible, creating a linear structure.

1) Subatomic particles. Atoms are made up of smaller parts called subatomic particles. Proton, neutron, and electron are some of them.

Electron: 9.11*10^-31 kg.

Proton: 1.672 18*10^-27 kg.

Neutron: 1.674 93*10^27 kg.

The lightest subatomic particle is the electron, then comes the protons, and finally the electron.

The number of blocks that can be lifted through this height is 11563 blocks.

We know that we define the term energy as the ability to do work, Now we have to consider the fact that we are told that one serving provides 185 kcal. Then we are told that  all of this energy is used to lift 1.0-kg blocks through a distance of  7.0 meters.

Given that the energy exerted in lifting each block is;

mgh

m = mass of the block

g = acceleration due to gravity

h = height lifted through

E = 1.0-kg * 9.8 m/s^2 * 7.0 meters = 68.6 J or 0.016 kcal

The number of blocks that can be lifted =  185 kcal/ 0.016 kcal

= 11563 blocks

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The balanced chemical equation for 0.1 M barium nitrate and 0.1 M sodium sulfate is -

2 Ba(NO₃)₂ + 2 Na₂SO₄   →   2 Ba(SO₄) + 2 NaNO₃

Balanced chemical equation are the equations having equal amount of reactants and the products formed. The reactants are placed on the left and products are placed on right forming a balanced chemical equation.

When 0.1 M barium nitrate reacts with the 0.1 M sodium sulfate, it gives an insoluble salt of barium sulfate and soluble salt of sodium nitrate as the product. This reaction is a type of precipitation reaction as precipitate is formed in the reaction. It is a double displacement reaction because the sulfate ions replace the nitrate ions to give the product.

Barium sulfate is known to be the most insoluble compound. It is formed as a precipitate.

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Answer:

d. Nickel

Explanation:

The atomic radius is a periodic property, that is, we can see how it varies in the Periodic Table of Elements.

Atomic radius increases by a column (group) from top to bottom, and increases by a row (period) from right to left.

We can see the variation of atomic radius and the location of the given atoms in the following drawing:

Since K (potassium), Ca (calcium), Co (cobalt) and Ni (nickel) are located in the same row (period), to identify which one has the smallest atomic radius, we have to analyze the increase in horizontal atomic radius.

So, the Ni atom has the smallest atomic radius (because it is located more to the right compared to the other atoms in the same row) and K atom has the largest atomic radius.

Answer:

B. The percent yield is 55.9%.

Explanation:

From the balanced reaction we know that 2 moles of FePO4 produce 1 mole of Fe2(SO4)3.

1st) It necessary to convert moles into grams, using the molar mass of FePO4 (151g/mol) and the molar mass of Fe2(SO4)3 (400g/mol):

- FePO4 conversion:

- Fe2(SO4)3 conversion:

In this case, it is not necessary the conversion, because there is 1 mole, so it is equal to 400g.

Now we know that 302g of FePO4 produce 400g of Fe2(SO4)3.

2nd) Now we have to calculate the Theoretical yield of Iron (III) sulfate, that is, the amount of Iron (III) sulfate that we must produce from 25g of Iron (III) phosphate:

So, the Theoretical yield is 33.11g.

3rd) Finally, we can calculate the Percent yield using the Theoretical yield (33.11g) and the Actual yield (18.5g):

So, the percent yield is 55.9%.

The concentration of the 25ml of original HNO₃ solution that was neutralized with 31.4 mL of 0.250 M Ba(OH)₂ is 0.628 M HNO3

The neutralization reaction involved with HNO₃ and Ba(OH)2 is

Ba(OH)₂ + 2HNO₃---> Ba(NO₃) + 2H₂O.

From the balanced equation of the reaction, we can say that to neutralize barium hydroxide (Ba(OH)₂) we would require 2 moles of Nitric acid (HNO₃)

By multiplying concentration of barium hydroxide by volume its volume, and then multiplying by 2 as twice is required we would get the moles of HNO3 that is equivalent to 2 moles based on the values

Moles of HNO₃ = 2 (0.0314 * 0.250) = 0.0157 moles

Concentration of the original HNO₃ solution = 0.0157 moles / 0.025 L = 0.628 M HNO₃

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Answer:

b d my good mannnnnnnnnnnn

The number of photons having a wavelength of 16.0 um required to produce 2.3KJ of energy is 1.85 x 10¹⁹

Photons are defined as a basic particle that is both the force carrier for the electromagnetic force and a quantum of the electromagnetic field, which includes electromagnetic radiation like light and radio waves.

It can also be defined as a discrete bundle of electromagnetic energy is what is known as a light particle.

Energy = 2.3 KJ

Wavelength = 16.0 x 10⁶ m

Energy = hc / ∧

            = 6.63 x 10²⁴ x 3 x 10³ / 16.0 x 10⁶

            = 1.24 x 10¹⁹ J

Number of photons used = 2.3 KJ / 1.24 x10¹⁹

                                          = 1.85 x 10¹⁹

Thus, the number of photons having a wavelength of 16.0 um required to produce 2.3KJ of energy is 1.85 x 10¹⁹

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The amount of heat energy that must be inputted into the reaction to make 58.9 grams of C₆H₁₂O₆ is 968.574 KJ

We'll begin by obtainig the number of mole of 58.9 grams of C₆H₁₂O₆. This can bbe obtained as follow:

Mole = mass/ molar mass

Mole of C₆H₁₂O₆ = 58.9 / 180

Mole of C₆H₁₂O₆ = 0.327 mole

Finally, we shall determine thhe heat energy needed.

The balanced equation for the reaction is given below:

6CO₂(g) + 6H₂O(g) → C₆H₁₂O₆(g) + 6O₂(g) ΔH = +2962 KJ/mol

From the balanced equation for above,

1 moles of C₆H₁₂O₆ was produced by 2962 KJ of heat energy.

Therefore,

0.327 mole of C₆H₁₂O₆ will be produce by = (0.327 × 2962) / 1 mole = 968.574 KJ of heat energy

Thus, 968.574 KJ of heat energy is needed for the reaction

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The reaction that occurs on the left is called a single displacemt reaction

Explanation:

First, let's write the formulas:

Potassium chlorate: KClO3

Oxygen: O2

Potassium chloride: KCl

So the reaction will be:

KClO3 -> O2 + KCl

Now let's balance it.

To balance the equation it is necessary to have the same number of atoms of each element on both sides of the equation (reactant side and product side). Let's count the number of atoms of each element for the unbalanced equation: KClO3 -> O2 + KCl

Reactant side:

K - 1

Cl - 1

O - 3

Product side:

O - 2

K - 1

Cl - 1

As you can see, oxygen number of atoms is not equal on both sides of the equation. Let's balance it by changing the stoichiometric coefficient.

2KClO3 → 2KCl + 3O2

Let's count the number of atoms of each element for the balanced equation.

Reactant side:

K - 2

Cl - 2

O - 6

Product side:

K - 2

Cl - 2

O - 6

Now the equation is balanced.

Answer: 2KClO3 → 2KCl + 3O2

Coefficients are: 2, 2 and 3.

Answer:

89.58 moles of MnO3 are produced.

Explanation:

1st) From the balanced reaction we know that the relation between O2 and MnO3 is that 3 moles of O2 produces 2 moles of MnO3.

2nd) To build the equation, we must build a path from the given value of 4.30kg of O2 to moles of MnO3. So, it is important to figure out the relations that we need to build the equation.

The order to build the equation is:

• Start with, the given value of ,4.30kg of O2,.

• We need to convert kg to grams, so we need the realtion between kg and g: ,1kg=1000g,.

• To convert the grams of oxygen to moles, we need to use the molar mass of O2: ,32g/1mol,.

• We need to use the relation between O2 and MnO3 from the balanced equation: ,3 moles of O2, produces, 2 moles of MnO3,.

So, 89.58 moles of MnO3 are produced.

A. The balanced equation for the reaction is given as

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

B. The mass (in grams) of carbon dioxide that can be produced by burning 20.0 pounds of propane is 27216.49 g

A. Balance equation

The balanced equation for the combustion of propane is:

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

B. How to determin the mass (in grams) of CO₂ produced

The mass (in grams) of CO₂ produced from the reaction can be obtained as follow:

From the balanced equation above,

0.097 pound of C₃H₈ reacted to produce 132 g of CO₂

Therefore,

20 pound of C₃H₈ will react to produce = (20 × 132) / 0.097 = 27216.49 g of CO₂

Thus, the mass of CO₂ produced is 27216.49 g

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The International System of Units uses the mole (symbol: mol) as the unit of substance amount.

In 5.67 moles of CO2 there exists 249.48 grams of CO2.

Start by dividing the number of atoms by the atomic weight of each component of the compound to convert grams to moles. After that, tally up all of your responses to determine the compound's molar mass. The final step is to calculate the number of moles by dividing the number of grams of the compound by its molar mass.

The International System of Units uses the mole (symbol: mol) as the unit of substance amount. How many elementary entities of a particular substance are present in an object or sample is determined by the quantity of that substance.

Let the equation be

Mass = relative atomic mass × mole number

substitute the values in the above equation, we get

= 5.67 × (12 + 16 + 16)  

= 249.48 g

Therefore, there exists 249.48 grams of CO2 are in 5.67 moles of CO2.

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Answer:

Biological evidence, since it was a hair, which forms part of the human

Step 1 - "Reading" the equation

The given chemical equation is:

The bigger numbers, those that come before the formulas of the substances, indicate the quantity in moles of each substance required in this rection.

We can "read" this reaction thus as :

one mole of CH4 reacts with 2 moles of O2 thus producing one mole of CO2 and two moles of H2O

As the exercise is specifically asking about the proportion between O2 and CO2, we can further simplify this statement to:

two moles of O2 produce one mole of CO2

Step 2 - Obtaining the "recipe" for the reaction

In order to obtain a relation in grams, we need to multiply the number of moles of each substance by its respective molar mass. Let's remember that:

two moles of O2 produce one mole of CO2

Therefore, converting to grams (molar masses: 32 g/mol for O2; 44 g/mol for CO2)

We have now obtained the "recipe" for this reaction:

64g of O2 produce 44g of CO2

Pretty much as we would with a cake recipe, we can use this to predict how much CO2 is formed.

Since the reaction of two moles of O2 is exactly what we have already calculated, 44g of CO2 would be formed in this reaction.

1) List the known and unknown quantities.

Sample: O2

Amount of substance: 0.650 mol O2.

Volume: 1.00 L.

Pressure: 20.00 atm.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1)

Temperature: unknown.

2) Set the equation.

Ideal gas law.

3) Plug in the known quantities and solve for T.

4) Convert K to ºC.

The temperature of the gas under these conditions is 101.81ºC.

.

ANSWER

Volume of the gas 5.3L

EXPLANATION;

Given that

The pressure of the chlorine gas is 688 torr

The temperature of the chlorine gas is 36 degrees Celcius

The mass of NaCl is 22 grams

Follow the steps below to find the volume of chlorine gas

Step 1; Write a balanced equation for the reaction

In the above reaction, 2 moles of Na react with 1 mole of chlorine to form 2 moles of NaCl

Step 2; Find the number of moles of NaCl using the below formula

Recall, that the molar mass of NaCl is 58.44 g/mol

Step 3; Find the number of moles of Cl2 using a stoichiometry ratio

Let x represents the number of moles of Cl2

The number of moles of Cl2 is 0.188 mol

Step 4; Find the volume of the gas using the ideal gas equation

Convert the temperature to degree kelvin

Step 5; Find the volume of the gas

Therefore, volume of the gas 5.3L

The relationship between the number nodes,  the energy level n and the azimuthal quantum number l is (n-l -1) + l. Thus the total number of nodes is n-1.

Node is the region or point in the orbital where the probability of finding an electron is zero. Electrons are revolving around circular paths of fixed energy levels.

The principal quantum number n represents the number of main shells or the energy level of the electrons. Whereas, azimuthal quantum number represents the number of orbitals denoted as l.

The point where there is a probability of finding an electron is called antinode. The total node in an orbital is the sum of number of planar nodes and number of spherical nodes.

Thus total number of nodes =  (n-l-1) + l

                                               = n - 1.

Therefore, the total number of nodes is n-1. For example for n=3 level there will be two nodes.

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Answer:

Explanation: 2 C19H34O2(l) + 53 O2(g) ==> 38 CO2(g) + 34 H2O(l) ... balanced equation

∆Hcombustion

∆H = ∑∆Hf products - ∑∆Hf reactants

∆H = [(38 x -393.5) + (34 x -285.8)] - (2 x -645.7) = (-14,953 + -9717) - (-1291)

∆H = -24,670 + 1291

∆H = 25,961 kJ

(be sure to check the math)

The initial temperature of the argon is 2678 K

Given that,

Initial volume (V1) = 4.95 L

Initial pressure (P1) = 0.92 atm

Final temperature (T2) = 30 C = 303.15 K

Final volume (V2) = 5.7 L

Final pressure (P2) = 0.092 atm

We need to find the Initial temperature of the argon represented as T1

We Know that, In ideal gas law: PV = nRT

It can be written as, P1V1 / T1 = P2V2 / T2

(0.92 * 4.95) / T1 = (0.092 * 5.7) / 303.15

4.554 / T1 = 0.5244 / 303.15

4.554 / T1 = 0.0017

T1 = 4.554 / 0.0017

T1 = 2678 K

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Answer:

Al 3+

Na+

Mg2+

F-

Explanation:

The element with the given electron that isn't an ion is Neon. It has 10 electrons in total.

Looking at the periodic table attached will help to see how the elements below are related to the one circled in red (Ne).

Al 3+ lacks 3 (because it has a 3+ charge) of its normal electrons so it has 10 and will have the same electron configuration as shown.

Na+ lacks one electron so it will also have 10 electrons instead of its normal 11.

Mg 2+ lacks two electrons so it will also have 10 total electrons.

F- has gained an extra electron so it now has 10 instead of 9.

Al3+, Na+, F-, and Mg2+ will have the given electronic configuration.

The electronic configuration given in the question is:

2p6, 2s2, 1s2

If it was a stable atom, the answer would have been Neon.

And if that would have been negative ion or anion (to be precise),

the answer would have been either F- or O2-.

But in the case of positive ions or we can say cations,

Al3+, Na+, and Mg2+ have the given electronic configurations.

Because the atom of Aluminum loses three electrons to achieve another state which is responsible for the formation of Al3+.

Similarly,

The atoms of Sodium and Magnesium also lose one and two electrons respectively to form Na+ and Mg2+.

So, we can conclude that Al3+, Na+, F- and Mg2+ will have the given electronic configuration.

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A student finds two green powders that look the same he wants to figure out if the two powders are the same or different substances then mix the two green powders together and then test the properties

A powder is a dry bulk solid composed of many very fine particles that may flow freely when shaken or tilted and to figure out unknown two mixture powder are same or different then student want to mix the two green powders together and then test the properties because of properties student the two unknown powder are to be determined

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Isotopes of certain __radioactive__ elements that spontaneously emit __radiation__ and _rays___ from the __nuclei____

Any of multiple species of the same chemical element with differing masses whose nuclei are unstable and spontaneously produce radiation in the form of alpha, beta, and gamma rays are known as radioactive isotopes, also known as radioisotopes, radionuclides, or radioactive nuclides.

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The volume of carbon dioxide (in L) that can be made from the 2.00 g of the antacid is 5.09 L

We'll beging by obtaining the mole of CO₂ produced. This can be obtained as follow:

CaCO₃ (s) + 2 HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)

From the balanced equation above,

1 mole CaCO₃ reacted to produce 1 mole of CO₂.

Therefore,

0.02 mole CaCO₃ will also react to produce 0.02 mole of CO₂.

Finally, we shall determine the volume of the CO₂ produced. Details below.

PV = nRT

1 × V = 0.02 × 0.0821 × 310

V = 5.09 L

Thus, the volume obtained is 5.09 L

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According to the stoichiometry, 4.85 g of propane is required to produce 14.7 g carbon dioxide.

It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.

In the given problem as per balanced equation of combustion of propane 2 molecules of propane produce  8 molecules of carbon dioxide.That is, 116.24 g of propane produces 352.08 g of carbon dioxide.

∴14.7 g of carbon dioxide is produced by, 14.7×116.24/352.08=4.85 g of propane.

Thus, 4.85 g of propane is required to produce 14.7 g of carbon dioxide.

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The general molecular equation is; [tex]Ba(CH3COO)_{2} (aq) + Na_{3} PO_{4} ------ > Ba_{3} (PO_{4})_{2} (s)+ Na(CH3COO)_{2} (aq)[/tex] while the net ionic equation is; [tex]2PO_{4} }^{3-} (aq) + 3Ba^{2+ } (aq) ------- > Ba_{3} (PO_{4})_{2} (s)[/tex]

We can define the term reaction as the interaction that occurs between the reactants and helps us to be able to get a product as shown. Now we have a case in which we are asked to write the molecular, ionic and net ionic equation, with the phases of matter for the reaction between Barium acetate + Sodium phosphate --> Barium phosphate + Sodium acetate.

The task now is to make use of the ideas that we have from the question to be able to determine both the molecular reaction equation as well as the net ionic equation as required.

Let us no take the reaction individually. We can write the molecular reaction as;

[tex]Ba(CH3COO)_{2} (aq) + Na_{3} PO_{4} ------ > Ba_{3} (PO_{4})_{2} (s)+ Na(CH3COO)_{2} (aq)[/tex]

After we have written the molecular reaction equation, then we can identify the spectator ions as  acetate ion and the sodium ion as we can see from the balanced reaction equation.

The net ionic equation therefore is;

[tex]2PO_{4} }^{3-} (aq) + 3Ba^{2+ } (aq) ------- > Ba_{3} (PO_{4})_{2} (s)[/tex]

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The molecular formula for the compound that contains 4.90 g N and 11.2 g O is N₂O₄

We'll begin by obtaining the empirical formula for the compound. This is illustrated below:

Divide by their molar mass

N = 4.9 / 14 = 0.35

O = 11.2 / 16 = 0.7

Divide by the smallest

N = 0.35 / 0.35 = 1

O = 0.7 / 0.35 = 2

Thus, the empirical formula of the compound is NO₂

Finally, we shall determine the molecula formula. Details below

Molecular formula = empirical × n = molar mass

[NO₂]ₙ = 92

[14 + (16×2)]ₙ = 92

46n = 92

Divide both side by 46

n = 92 / 46

n = 2

Molecular formula = [NO₂]ₙ

Molecular formula = [NO₂]₂

Molecular formula = N₂O₄

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Complete question:

Find the molecular formula for a compound that contains 4.90 g N and 11.2 g O. The molar mass of the compound is 92.0 g/mol.