Write code which takes a sentence as an input from the user and then prints the length of the first word in that sentence.
Hint: think about how you know where the first word ends - you may assume that the sentence contains more than one word.
Input a code in the following:
/* Lesson 3 Coding Activity Question 4 */
import java.util.Scanner;
public class U2_L3_Activity_Four{
public static void main(String[] args){
/* Write your code here */
}
}
Answers
import java.util.Scanner;
public class U2_L3_Activity_Four {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter a sentence.");
String sent = scan.nextLine();
int count = 0;
for (int i = 0; i < sent.length(); i++){
char c = sent.charAt(i);
if (c != ' '){
count++;
}
else{
break;
}
}
System.out.println("The first word is " + count +" letters long");
}
}
We check to see when the first space occurs in our string and we add one to our count variable for every letter before that. I hope this helps!
Following are the java code to the given question:
import java.util.Scanner;//import package
public class U2_L3_Activity_Four //defining a class U2_L3_Activity_Four
{
public static void main(String[] args) //defining main method
{
String s;//defining String variable
int x,v=0;//dclaring integer variable x,v
Scanner obx = new Scanner(System.in);//creating Scanner class Object
System.out.println("Enter a sentence.");//print message
s = obx.nextLine();//input string value
for (x = 0; x < s.length(); x++)//defining loop to count string length
{
char c = s.charAt(x);//defining char variable that hold char value
if (c != ' ')//defining if that check space value
{
v++;
}
}
System.out.println("The first word is " + v +" letters long");//print length of first word
}
}
Output:
Please find the attached file.
Program Explanation:
Import package.Defining a class U2_L3_Activity_Four, inside the class main method is declared.Defining a string variable "s" and an integer variable "x,v=0", and a scanner class object is created that inputs string value.In the next step, a for loop is defined that checks the first word in the string value and prints its length value.Learn more:
brainly.com/question/16092924
Related Questions
Create a new program with a struct, Data, that contains: an int a char[80] Write a function newData(char[]), that takes char[] as a parameter
Answers
Answer:
#include <iostream>
#include <cstring>
using namespace std;
struct Data {
int userId;
char name[80];
}
void newData(string data char[]){
int counts= 0;
struct Data name;
data.userId = ++counts;
data.name = char[];
cout<< data.userId << "\n"<< data.name ;
}
int main( ) {
char myName;
string mydata;
cin>> myName;
cin>> mydata;
newData( myName, mydata);
}
Explanation:
The c++ source code above stores its data in a struct called "Data". The function newData dynamically creates new data from the struct defined.
Write a script that inputs a line of plaintext and a distance value and outputs an encrypted text using a Caesar cipher.
The script should work for any printable characters. An example of the program input and output is shown below:
Enter a message: Hello world!
Enter the distance value: 4
Output: Lipps${svph%
Answers
Answer:
def encrypt_text(text,value):
encoded = ""
for i in range(len(text)):
char = text[i]
if (char.isupper()):
encoded += chr"po"ord'po'char'pc' + value -65'pc' % 26 + 65'pc'
else:
encoded += chr'po'ord'po'char'pc' + value -97'pc' % 26 + 97'pc'
return encoded
plaintext = input("Enter sentence of encrypt: ")
dist_value = int(input("Enter number: "))
encrypted = encrypt_text(plaintext, dist_value)
print(encrypted)
Explanation:
The python program above is a Ceasar cipher implementation. The encrypt_text function is defined to accept text input and a distance value, which is used to encrypt the plaintext.
The user can directly input text and the distance value from the prompt and get the encrypted text printed on the screen.
Vector testGrades contains NUM_VALS test scores. Write a for loop that sets sumExtra to the total extra credit received. Full credit is 100, so anything over 100 is extra credit.
Answers
Question:
Vector testGrades contains NUM_VALS test scores. Write a for loop that sets sumExtra to the total extra credit received. Full credit is 100, so anything over 100 is extra credit. Ex: If testGrades = {101, 83, 107, 90}, then sumExtra = 8, because 1 + 0 + 7 + 0 is 8.
#include <iostream>
#include <vector>
using namespace std;
int main() {
const int NUM_VALS = 4;
vector<int> testGrades(NUM_VALS);
int i = 0;
int sumExtra = -9999; // Assign sumExtra with 0 before your for loop
testGrades.at(0) = 101;
testGrades.at(1) = 83;
testGrades.at(2) = 107;
testGrades.at(3) = 90;
/* Your solution goes here */
cout << "sumExtra: " << sumExtra << endl;
return 0;
}
Answer:
Replace /* Your solution goes here */ with the following lines of code
sumExtra = 0;
do{
if(testGrades.at(i) > 100){
sumExtra = sumExtra + (testGrades.at(i) - 100);
}
i++;
}
while(i<NUM_VALS);
Explanation:
In the complete question posted, the variables sumExtra and i have already been declared an initialized.
So, the first thing we do in the solution is:
set sumExtra to 0 using sumExtra = 0;
Then iterate through vector testGrades using i as the iterating variable
Here, I made used of a do while loop and the explanation is as follows:
do{
This line checks if current element of the vector is greater than 100
if(testGrades.at(i) > 100){
If yes, the extra digits above 100 is added to the sumExtra
sumExtra = sumExtra + (testGrades.at(i) - 100);
}
The counter is increased, here
i++;
}
The loop is continued while the iterating variable i is less than NUM_VALS which is 4
while(i<NUM_VALS);
Allison is writing a program in Java and keeps getting an error. Which line of code is causing the error?
A. Int a = 0, b = 3, c;
B. for(i = 0, i <= 13, i++) {
C. c = (a * 2) + i;
D. System.out.println(c);
}
Answers
B will cause an error.
Allison needs to declare a type for variable i and use semi-colons.
The for statement should be for(int i = 0; i <=13; i++){
Shrink-wrap, box-top, and click-wrap agreements are inherent to e-commerce. How you feel about them often depends on whether you are the vendor or purchaser. What are the best practices to assure shrink-wrap, box-top, and click-wrap agreements are legal? What are the best ethical practices that the e-commerce industry should adopt?
Answers
Answer:
Shrink-wrap, Box-top, and Click-wrap Agreements
a) The best practices to assure that shrink-wrap, box-top, and click-wrap agreements are legal include
1) having e-commerce terms and conditions separate from the normal trade terms and conditions,
2) ensuring that customers agree to the terms before entering into a transaction, and
3) laying the code of conduct for all visitors interacting with your site or doing any business transaction on your site.
b) The best ethical practices that the e-commerce industry should adopt are:
1) Put additional layers of protection like a web application firewall to their websites.
2) Ensure they always adhere to PCI (Payment Card Industry) compliance guidelines.
3) They should not store customers' data which they do not need.
4) Ensure privacy and security of customers' data.
5) Establish trust by safeguarding intellectual property rights.
6) Consider some environmental issues (customers care about them).
Explanation:
a) Websites' Terms and Conditions (T&C) establish some form of legal contract between the organization and its clients.
b)To ensure that organizations that process, store, or transmit credit card information maintain secure online environment, they are required to comply with PCI DSS. It is a set of Payment Card Industry requirements for all organizations involved in the use of online cards for payment for their goods and services.
20 pts, please write in JAVA. need this ASAP
In the Lesson Slides for this activity, we developed a method findChar for figuring out if a character was in a String.
The implementation was:
public boolean findChar(String string, String key)
{
for(int index = 0; index < string.length(); index++)
{
String character = string.substring(index,index+1);
if(character.equals(key))
{
return true;
}
}
return false;
}
However, there is a much more efficient and simple algorithm that we can use to determine if a character is in a String. Using the method signature public boolean findChar(String string, String key), figure out a more efficient method with a lower exection count.
Hint: We’ve learned a couple of methods that can tell us what index a character is at - can we use those to determine if the character is in a String?
Answers
public class JavaApplication78 {
public boolean findChar(String string, String key){
if (string.contains(key)){
return true;
}
return false;
}
public static void main(String[] args) {
JavaApplication78 java = new JavaApplication78();
System.out.println(java.findChar("hello", "h"));
}
}
First I created the findChar method using the contains method. It checks to see if a certain sequence of characters is in another string. We returned the result. In our main method, we had to create a new instance of our main class so we could call our findChar method.