Write an equation of the line that passes through the point (6,2) and is perpendicular to the line y=3x+3

Answer:

62•4=248

[tex]63^{4} =2^{24}[/tex]

Step-by-step explanation:

I didn't know which one you needed so here's both.

Find slope of line (m)

[tex]\\ \sf\longmapsto m=\dfrac{2-0}{1-0}[/tex]

[tex]\\ \sf\longmapsto m=2[/tex]

Putting in y=mx+b

[tex]\\ \sf\longmapsto y=mx+b[/tex]

[tex]\\ \sf\longmapsto 2=2(1)+b[/tex]

[tex]\\ \sf\longmapsto 2=2+b[/tex]

[tex]\\ \sf\longmapsto b=2-2=0[/tex]

Equation of the line

[tex]\\ \sf\longmapsto y=2x[/tex]

Answer:

Step-by-step explanation:

The line passes through the origin and holds the point A(1, 2).

This is a proportional relationship:

Considering the coordinates of the point A:

The line is:

Answer:

144 students

Step-by-step explanation:

12/28=3/7

3/7*336=144

Unit rate is the quantity of an amount of something at a rate of one of another quantity.

If out of 28 students, 12 students packed their lunch.

The number of students who packed their lunch out of 336 students is 144 students.

It is the quantity of an amount of something at a rate of one of another quantity.

Example:

3 miles in 3 hours.

1 mile in one hour.

We have,

In a class of 28 students, 12 students packed their lunch.

We can write this as:

28 students = 12 students packed lunch ______(1)

We have to make 28 students into 336 students.

This can be done by multiplying 12 on both sides of the equation (1)

Multiply 12 on both sides.

12 x 28 students = 12 x 12 students packed lunch

336 students = 144 students packed lunch

Thus,

The number of students who packed their lunch out of 336 students is 144 students.

Learn more about unit rates here:

https://brainly.com/question/11258929

#SPJ5

Answer:

-4/45

Step-by-step explanation:

[tex]\dfrac{-6}{35}*\dfrac{14}{27}=\dfrac{-6}{5}*\dfrac{2}{27}[/tex]

14 and 35 are given by 7th table.

               [tex]= \dfrac{-2}{5}*\dfrac{2}{9}[/tex]      

Now , 6 and 27 are given by 3rd table

                [tex]=\dfrac{-4}{45}[/tex]

Answer:

-4/45

Step-by-step explanation:

2.03 Quiz: Multiply Signed Fractions

Answer:

66 (lmk if i'm wrong)

Step-by-step explanation:

9x6 + (16-4)

54 +12

66

Answer:

0.1714

Step-by-step explanation:

just substract 9.6 from 66/7 which will give u the other rational number.

then add both the rational numbers to check ur answer.

66/7 + 0.1714 = 9.6

Answer:

reciprocal of 4 = 1/4

Step-by-step explanation:

By definition, a reciprocal of a/b = b/a.

Since 4 is the same as 4/1, then it's reciprocal must be 1/4.

Answer:

1/4

Step-by-step explanation:

because 4 = 4/1

reciprocal means to flip it upside down 4/1 = 1/4

Answer:

the answer is d (the last one)

Step-by-step explanation:

2.25 * 2 = 4.5

+

7.25 * 3 = 21.75

= 26.25

he needs 35, so it's not enough

Answer:

-65 is the right answerrr

Answer:

hope i helped...if anythng not understood please write in the comments

Answer:

x=19/10

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

1/5(x+0.5)+5.24=3/2x +x+7/10(x+2.2)

(1/5)(x)+(1/5)(0.5)+5.24=3/2x+(7/10)(x)+(7/10)(2.2)(Distribute)

1/5x+0.1+5.24=3/2x+7/10x+1.54

(1/5x)+(0.1+5.24)=(3/2x+7/10x)+(1.54)(Combine Like Terms)

1/5x+5.34=11/5x+1.54

Step 2: Subtract 11/5x from both sides.

1/5x+5.34−11/5x=11/5x+1.54−11/5x

−2x+5.34=1.54

Step 3: Subtract 5.34 from both sides.

−2x+5.34−5.34=1.54−5.34

−2x=

−19/5

Step 4: Divide both sides by -2.

−2x=−19/5

x= 19/10

Answer:

x= 19/10

Answer:

2.01

Step-by-step explanation:

Answer:

 Equivalent ratio of 9:1 is 18:2.

Mark me as the brainlist

Answer:

18:2 is equivalent

pretty sure

Answer:

Step-by-step explanation:

-(8/11)/(-3/5) = -(8/11)*(-5/3)

-(8/11)*(-5/3) = 40/33  [ or 1 7/33]

I can't interpret the rest of the question.  I see:

"Add 2/5 + 3/6 + 1/4 0 1 11/60 O 13/20 o 17/20 1 13/60"

Using the inverse function, it is found that the equation is:

[tex]P(t) = \frac{e^{0.1t}}{50} + 20[/tex]

It's initial value is 20.

---------------------------

We want to find the inverse of:

[tex]y = P^{-1}(t) = 10\ln{50t - 1000}[/tex]

To do this, we exchange y and t, and isolate y.

Then:

[tex]10\ln{50y - 1000} = t[/tex]

[tex]\ln{50y - 1000} = \frac{t}{10}[/tex]

[tex]e^{\ln{50y - 1000}} = e^{0.1t}[/tex]

[tex]50y - 1000 = e^{0.1t}[/tex]

[tex]50y = e^{0.1t} + 1000[/tex]

[tex]y = \frac{e^{0.1t} + 1000}{50}[/tex]

[tex]y = \frac{e^{0.1t}}{50} + \frac{1000}{50}[/tex]

[tex]P(t) = \frac{e^{0.1t}}{50} + 20[/tex]

It's initial value is:

[tex]P(0) = \frac{e^{0.1(0)}}{50} + 20 = 0.02 + 20 = 20.02[/tex]

Rounding, 20.

A similar problem is given at https://brainly.com/question/23950969

Answer:

P = 1/50e^0.1t + 20

Step-by-step explanation:

Answer:

the answer is------------ 1/4.4.4

Answer:

To find 3,500 by near to 3,550

Step-by-step explanation:

the nearest number of 3,500 is 3,500

Answer: 500km I believe

Step-by-step explanation:

hope this helps :)

Answer:

I think that the answer is 850

Step-by-step explanation:

find out how many km traveled 0.5 hours, then multiply by 12

Answer:

D) X-12

Step-by-step explanation:

imagine that X = 2 or any number less than 12

A) 12 - X = 12 - 2 = 10

B) 12X = 12 ×2 = 24

C) X + 12 = 2 + 12 = 14

D) X - 12 = 2 - 12 = -10

So, the smallest number is (D)

Hope it's help.

Answer:

5790

Step-by-step explanation:

Hope this helps! Pls give brainliest!

Answer:

5790

Step-by-step explanation:

0.579 × [tex]10^{4}[/tex]

Calculate 10 to the power of 4 and get 10000.

0.579 × 10000

Multiply 0.579 and 10000 to get 5790

5790

Hello!

Answer:

g = 9

Step-by-step explanation:

(g+1)^2

Plug in 2 for g: (2+1)^2

Add 2 and 1: (3)^2

Simplify: (3 x 3)= 9

Hope this helps.

Step-by-step explanation:

[tex]1) \: \: - x + 2y + 2z = - 4 \\ 2z = - 4 + x - 2y \\ z = \frac{ - 4 + x - 2y}{2} \\ \\ 2) \: \: 4x + y - 3z = 13 \\ - 3z = 13 - 4x - y \\ z = \frac{13 - 4x - y}{ - 3} \\ \\ 3) \: \: x - 5y + z = - 23 \\ z = - 23 - x + 5y \\ [/tex]

Answer:

6xy + 2x

Step-by-step explanation:

Simplify the expression.8xy-(x+2xy)+3x​

Answer:

d

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

got

submited

showed

arrived

already filled

Step-by-step explanation:

If you're like me and don't remember hyperbolic identities (especially involving inverse functions) off the top of your head, recall the definitions of the hyperbolic cosine and sine:

[tex]\cosh(x) = \dfrac{e^x + e^{-x}}2 \\\\ \sinh(x) = \dfrac{e^x - e^{-x}}2[/tex]

Then differentiating yields

[tex]\dfrac{\mathrm d(\cosh(x))}{\mathrm dx} = \dfrac{e^x-e^{-x}}2 = \sinh(x) \\\\ \dfrac{\mathrm d(\sinh(x))}{\mathrm dx} = \dfrac{e^x+e^{-x}}2 = \cosh(x)[/tex]

so that by the chain rule, if

[tex]y = \cosh\left(4\tanh^{-1}(x)\right)[/tex]

then

[tex]\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\mathrm d\left(\cosh\left(4\tanh^{-1}(x)\right)\right)}{\mathrm dx} = \sinh\left(4\tanh^{-1}(x)\right) \dfrac{\mathrm d\left(4\tanh^{-1}(x)\right)}{\mathrm dx}[/tex]

Now, let [tex]z=4\tanh^{-1}(x)[/tex], so that (•) [tex]\tanh\left(\frac z4\right) = x[/tex].

Recall that

[tex]\tanh(x) = \dfrac{\sinh(x)}{\cosh(x)} = \dfrac{e^x-e^{-x}}{e^x+e^{-x}}[/tex]

and so the derivative of tanh(x) is

[tex]\dfrac{\mathrm d(\tanh(x))}{\mathrm dx} = \dfrac{(e^x+e^{-x})(e^x+e^{-x})-(e^x-e^{-x})(e^x-e^{-x})}{(e^x+e^{-x})^2} \\\\ = \dfrac{4\cosh^2(x)-4\sinh^2(x)}{4\cosh^2(x)} \\\\ = 1-\tanh^2(x) = \mathrm{sech}^2(x)[/tex]

where the last equality follows from the hyperbolic Pythagorean identity,

[tex]\cosh^2(x)-\sinh^2(x) = 1 \implies 1-\tanh^2(x) = \mathrm{sech}^2(x)[/tex]

Differentiating both sides of (•) implicitly with respect to x gives

[tex]\dfrac{\mathrm d\left(\tanh\left(\frac z4\right)\right)}{\mathrm dx} = \dfrac{\mathrm d(x)}{\mathrm dx} \\\\ \mathrm{sech}^2\left(\dfrac z4\right)\dfrac{\mathrm d\left(\frac z4\right)}{\mathrm dx} = 1 \\\\ \dfrac14 \mathrm{sech}^2\left(\dfrac z4\right) \dfrac{\mathrm dz}{\mathrm dx} = 1 \\\\ \dfrac{\mathrm dz}{\mathrm dx} = 4\cosh^2\left(\dfrac z4\right) \\\\ \dfrac{\mathrm dz}{\mathrm dx} = 4\cosh^2\left(\tanh^{-1}(x)\right)[/tex]

So, the derivative we want is the somewhat messy expression

[tex]\boxed{\dfrac{\mathrm dy}{\mathrm dx} = 4\sinh\left(4\tanh^{-1}(x)\right) \cosh^2\left(\tanh^{-1}(x)\right)}[/tex]

and while this could be simplified into a rational expression of x, I would argue for leaving the solution in this form considering how y is given in this form from the start.

In case you are interested, we have

[tex]\cosh\left(\tanh^{-1}(x)\right) = \dfrac1{\sqrt{1-x^2}}[/tex]

and you can instead work on differentiating that; you would end up with

[tex]\dfrac{\mathrm dy}{\mathrm dx} = -\dfrac{16x^3+16x}{(x^2-1)^3}[/tex]