write a quadratic function f whose only zero is 11

the measure of angle c is 120

Answer:

C = M = 120

i hope this helps

Answer:

x = 7

y = -2

Step-by-step explanation:

Equation 1:  2x + y = 12

Equation 2:  x - y = 9

Rewrite Equation 2 to make x the subject:

⇒ x = 9 + y

Substitute this into Equation 1 and solve for y:

⇒ 2(9 + y) + y = 12

⇒ 18 + 2y + y = 12

⇒ 18 + 3y = 12

⇒ 3y = -6

⇒ y = -2

Substitute found value of y into the rewritten Equation 2 and solve for x:

⇒ x = 9 + (-2)

⇒ x = 7

Step-by-step explanation:

2x + y = 12 equ 1

x - y = 9 equ 2

from equ 2 make x the subject

x - y = 9

x = 9 + y equ 3

substitute equ 3 to equ 1

2x + y = 12

2(9 + y ) + y = 12

18 + 2y + y = 12

3y = - 6

y = -2

substitute y = -2 into equ 3

x = 9 + (-2)

x = 9 - 2 = 7

(x, y) = (7, -2)

let's prove and see if we are correct

2x + y = 12

input the values of (x, y) = ( 7, -2) into the question

2(7) + (-2) = 12

14 - 2 = 12

12 = 12

for the second equation

x - y = 9

Input the values of (x, y) = ( 7, -2) into the question

7 - (-2) = 9

7 + 2 = 9

9 = 9

Digram:-

[tex] \\ [/tex]

[tex]\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\put(5,1){\vector(1,0){4}}\put(5,1){\vector(-1,0){4}}\put(5,1){\vector(1,1){3}}\put(2,2){$\underline{\boxed{\large\sf a + b = 180^{\circ}}$}}\put(4.5,1.3){$\sf a^{\circ}$}\put(5.7,1.3){$\sf b^{\circ}$}\end{picture}[/tex]

[tex] \\ [/tex]

STEP :-

[tex] \dashrightarrow \tt(4q - 1) {}^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]

{Linear pair}

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \tt(4q - 1) {}^{ \circ}= 18 {0}^{ \circ} - {117}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt(4q - 1) {}^{ \circ}=63^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt4q - 1{}^{ \circ}=63^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt4q =63^{ \circ} + 1{}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt4q =64{}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt \: q = \dfrac{64}{4}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt \: q = \dfrac{16 \times 4}{4}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt \: q = \dfrac{16 \times \cancel4}{\cancel4}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt \: q = \dfrac{16}{1}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \bf q = 16 \degree[/tex]

[tex] \\ \\ [/tex]

Verification:

[tex] \\ [/tex]

[tex] \dashrightarrow \tt(4 \times 16- 1) {}^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt(64- 1) {}^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt63^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt180^{ \circ} = 18 {0}^{ \circ} [/tex]

[tex] \\ [/tex]

LHS = RHS

HENCE VERIFIED!

Answer:

Value of [tex]\sf\purple{q\: = \:16.}[/tex]

Step-by-step explanation:

[tex]\rightarrow[/tex]As we know that,

Sum all angles that lie on a straight line = [tex]\sf\blue{180°}[/tex]

So,

[tex]\rightarrow[/tex] [tex]\sf{(4q-1)°+ 117°\: = \:180°}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{(4q-1)\: = \:180-117}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{(4q-1)\: = \:63}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{4q\: = \:63+1}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{q\: = \:\frac{64}{4}}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{q\: = \:16}[/tex]

Thus, [tex]\sf\purple{q\: = \:16.}[/tex]

_________________________________

Hope it helps you:)

Answer:

5/9

Step-by-step explanation:

What we have here is the reciprocal of (9/5).  Inverting (9/5) results in (5/9), which is the desired result.

Answer:

x = 148⁰

Step-by-step explanation:

180⁰-32⁰= 148⁰

so 32⁰ angle is parallell to c angle so that means x equals to 148⁰

p and x are parallels

Answer: The answer should be the 2nd one

Step-by-step explanation:

Answer:

x=-3/7;x=-5/7

Step-by-step explanation:

Answer:

I think you meant cm, not em. So the answer is 6 cm.

Step-by-step explanation:

18cm x 6cm = 108 cm

Step-by-step explanation:

please mark me as brainlest

Answer:

[tex]\sf -\dfrac{1}{36}[/tex]

Explanation:

[tex]\rightarrow \sf -\dfrac{7}{9} -(-\dfrac{5}{12} )+\dfrac{1}{3}[/tex]

remove parenthesis

[tex]\rightarrow \sf -\dfrac{7}{9} +\dfrac{5}{12} +\dfrac{1}{3}[/tex]

all the denominators has a common multiple of 108

[tex]\rightarrow \sf -\dfrac{7(12)}{108} +\dfrac{5(9)}{108} +\dfrac{1(36)}{108}[/tex]

simplify

[tex]\rightarrow \sf \dfrac{-84}{108} +\dfrac{45}{108} +\dfrac{36}{108}[/tex]

join the fractions

[tex]\rightarrow \sf \dfrac{-84+45+36}{108}[/tex]

simplify

[tex]\rightarrow \sf \dfrac{-3}{108}[/tex]

simplify

[tex]\rightarrow \sf -\dfrac{1}{108}[/tex]

Answer:

B

Step-by-step explanation:

Let's add some numbers together and divide by the numbers of numbers. The answer should be among these.

4 + 5 + -4 + -3 = 2

4/2 = 2.

-17 + -4 + 4 + 5 = -12

-12/4 = -3.

The answer is B.

Answer:

g is 37

Step-by-step explanation:

supplementary means two angles that add up to 180°

180-143=37

Answer:

I don't know the exact answer but, I had a problem like this the other day. This is how to find it out. I am just in a rush so I have to go if not I would help you figure it out.

Step-by-step explanation:

Write the equation of each circle.

1. center at (9, 0), radius 5

SOLUTION:  

ANSWER:  

2. center at (3, 1), diameter 14

SOLUTION:  

Since the radius is half the diameter, r = (14) or 7.

ANSWER:  

3. center at origin, passes through (2,2)

AnswerAnswerAnswerAnswer:

the answer is  D h(x) = 1/4 x

Step-by-step explanation:

Have a great day!

A brainliest would help!

Answer:

option c

Step-by-step explanation:

Let the sides of the right angled triangle = x , (x +1) , (x +2)

Perimeter = 12 feet

x + x +1 + x + 2 = 12

x +x + x + 1+2 = 12

Combine like terms

3x+  3 = 12

Subtract 3 from both sides

3x = 12- 3

3x = 9

Divide both sides by 3

x = 9/3

x = 3

x + 1 = 3 + 1 = 4

x + 2 = 3 + 2 = 5

The sides of the triangle are 3 , 4 ,5

The biggest side will be the hypotenuse.

So, hypotenuse = 5 ft. other legs are 3 and 4

[tex]\text {Sin \ $\theta$ = $\dfrac{opposite \ side \ of \ \theta}{hypotenuse}$ } \\\\\\ = \dfrac{4}{5}\\\\\\Sin \ \theta = 0.8\\\\\theta = Sin^{-1} \ 0.8\\\\\theta = 53.13 \ ^\circ[/tex]

another angle = 180 - [ 90 + 53.13]

                        = 180 - 143.13

                         = 36.87°

Answer:

Step-by-step explanation:

when  3(2x^2+4x+7)−(x^2−8x+11) is solved you get

5x^2 + 20x + 10.

the x term is

−

2

+

√

2

,

0

)

,

(

−

2

−

√

2

,

0

)

[tex]3(2x^2+4x+7)-(x^2-8x+11)\\\\=6x^2 +12x + 21 -x^2+8x -11\\\\=5x^2+20x +10\\\\\text{The coefficient of the x term is 20}[/tex]

Step-by-step explanation:

Let the larger no be = a

Difference of the numbers = a - 32

As per the question;

(a + 32) = 5(a - 32)

⇒ a + 32 = 5a - 160

⇒ 128 = 4a

⇒ a = 32

∴ The larger no is 32.

Answer: the answer is not in the multiple choice.

area = 60 in^2

Step-by-step explanation:

Answer:

20 inches²

Step-by-step explanation:

perimeter = 8 + 3 + 5 + 4

= 20 inches²

Answer:

  n = 6

Step-by-step explanation:

To find the exponent of 10, you can write the equivalent multiplier in standard form, then identify the place value of the 1 in the multiplier.

  0.000689 = 689 × 0.000001

The 1 is in the 6th place to the right of the decimal point. The place value of digits in that place is 10^-6

  0.000689 =689 × 10^n = 689 ×10^-6

  n = -6

_____

In the attached, your number would fill in the blanks to the right of the decimal point. The least-significant digit (9) would have a value of 9×10^-6.

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Let the blank is x, solve the equation for x:

Let that be x

D or A not sure

The Twenty-fourth Amendment (Amendment XXIV) of the United States Constitution prohibits both Congress and the states from conditioning the right to vote in federal elections on payment of a poll tax or other types of tax.

Answer:

(D) they do not pay their taxes ​

Step-by-step explanation:

I got it correct on an exam I did.

Here's li[tex]^{}[/tex]nk to the answer:

bit.[tex]^{}[/tex]ly/3HH[tex]^{}[/tex]Mdaf

Answer:

x=1.5 and x= -1.5

Step-by-step explanation:

thats where the graph crosses the x axis (which basically is y=0)

Answer:

Step-by-step explanation:

x² - 2 = y

x² - 2 = 0

x² = 2

x = √2

x = ±1.4

Answer:

A Translation 2 units left and 1 unit down

Step-by-step explanation:

The balance after one year if you deposit one $50 envelope each month, all year is  $613.95.

The balance after 1 year can be determined using this formula:

Amount deposited monthly x annuity factor

Annuity factor = {[(1+r)^n] - 1} / r

Where:

Annuity factor = 1.004167^12 - 1 / 0.00417 = 12.279082

Balance = 12.279082 x 50 = $613.95

To learn more about annuities, please check: https://brainly.com/question/24108530

Answer:

  821.20

Step-by-step explanation:

The tax is added to the listed price in order to find the total cost. The tax is computed by multiplying the listed price by the tax rate.

  tax = 749.95 × 0.095 = 71.25 . . . . . (rounded up from 74.24525)

  total cost = listed price + tax = 749.95 +71.25 = 821.20

The total cost of the bicycle with sales tax included is 821.20.

Answer:

$821.20 (nearest cent)

Step-by-step explanation:

If a sales tax of 9.5% is applied,
the final cost of the bicycle = 100% + 9.5% = 109.5% of its listed price

Convert 109.5% into a decimal:

109.5% = 109.5/100 = 1.095

So 109.5% of $749.95 = 1.095 × 749.95

                                     = $821.20 (nearest cent)

Answer:

See below for answers and explanations

Step-by-step explanation:

Problem 1

To convert from polar to Cartesian coordinates, recall that [tex](x,y)=(r\:cos\theta,r\:sin\theta)[/tex], thus, [tex](x,y)=(6\:cos\frac{5\pi}{6},6sin\frac{5\pi}{6})=(6(-\frac{\sqrt{3}}{2}),6(\frac{1}{2}))=(-3\sqrt{3},3)[/tex]

Therefore, C is the correct answer

Problem 2

Convert from polar to Cartesian coordinates:

[tex](x,y)=(-5\:cos\frac{2\pi}{3},-5\:sin\frac{2\pi}{3})=(-5(-\frac{1}{2}),-5(\frac{\sqrt{3}}{2}))=(\frac{5}{2},\frac{-5\sqrt{3}}{2})[/tex]

Therefore, U is the correct answer

Problem 3

Since [tex]r=\sqrt{x^2+y^2}[/tex], then [tex]r^2=x^2+y^2[/tex]. Don't also forget to use the substitution [tex]x=r\:cos\theta[/tex]:

[tex]x^2+y^2-7x=0\\\\r^2-7rcos\theta=0\\\\r(r-7cos\theta)=0\\\\r-7cos\theta=0\\\\r=7cos\theta[/tex]

Therefore, B is the correct answer

Problem 4

[tex]r=(tan\theta)(sec\theta)\\\\r=(\frac{sin\theta}{cos\theta})(\frac{1}{cos\theta})\\ \\\frac{r^2}{r}=(\frac{rsin\theta}{rcos\theta})(\frac{r}{rcos\theta})\\ \\\frac{x^2+y^2}{\sqrt{x^2+y^2}}=(\frac{y}{x})(\frac{\sqrt{x^2+y^2}}{x})\\ \\x^2+y^2=\frac{y(x^2+y^2)}{x^2}\\ \\1=\frac{y}{x^2}\\\\x^2=y[/tex]

Therefore, A is the correct answer