Write a program to input 6 numbers. After each number is input, print the biggest of the numbers entered so far.
Answers
Answer:
num1 = int(input("Enter a number: " ))
print("Largest: " + str(num1))
# num 2 #
num2 = int(input("Enter a number: "))
if num2 > num1:
print("Largest: " + str(num2))
else:
print("Largest: " + str(num1))
# num 3 #
num3 = int(input("Enter a number: "))
print("Largest: " + str(max(num1, num2, num3)))
# num 4 #
num4 = int(input("Enter a number: "))
print("Largest: " + str(max(num1, num2, num3, num4)))
# num 5 #
num5 = int(input("Enter a number: "))
print("Largest: " + str(max(num1, num2, num3, num4, num5)))
# num 6 #
num6 = int(input("Enter a number: "))
print("Largest: " + str(max(num1, num2, num3, num4, num5, num6)))
Explanation:
In this exercise, using the knowledge of computational language in python, we have that this code will be written as:
The code is in the attached image.
We can write the python as:
num1 = int(input("Enter a number: " ))
print("Largest: " + str(num1))
num2 = int(input("Enter a number: "))
if num2 > num1:
print("Largest: " + str(num2))
else:
print("Largest: " + str(num1))
num3 = int(input("Enter a number: "))
print("Largest: " + str(max(num1, num2, num3)))
num4 = int(input("Enter a number: "))
print("Largest: " + str(max(num1, num2, num3, num4)))
num5 = int(input("Enter a number: "))
print("Largest: " + str(max(num1, num2, num3, num4, num5)))
num6 = int(input("Enter a number: "))
print("Largest: " + str(max(num1, num2, num3, num4, num5, num6)))
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Answer:
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Answer:
Unlike proprietary software, open-source software promotes creative work and gives users full access to the source code. If you want to customize a specific program, you can simply ask a developer to do it (assuming that you have a license, which is required in most cases).
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Answer:
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Answer:
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Answer:
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Answer:
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Answers
Compaction often gives solutions to the issues regarding external fragmentation.
One technique for overcoming external fragmentation in dynamic partitioning is
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The reason why this technique of overcoming external fragmentation may be inefficient is because:
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Answers
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Answer : B. Define Range
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Answers
Answer:
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Explanation:
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Answer:
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Explanation:
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Answer:
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Explanation:
hope it helps
Answer:
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Explanation:
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Answer:
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Answer:
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Explanation:
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Answer:
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