Answer:
7.3*10^7
Step-by-step explanation:
7
Write a Two-Column Proof
Given: m 8-125-
m/3-55°
Prove: pr
3/4
5/6
7/8
2
By two column proof, we get:
∠2 = 60°, ∠3 = 120°, ∠4 = 60°, ∠5 = 120°, ∠6 = 60°, ∠7 = 120° and ∠8 = 60
Two column Proof:
A two-column geometric proof consists of a list of statements and the reasons why we know these statements are true. The complaints are listed in the left column and the reasons for the complaint are listed in the right column.
According to the Question:
l II m and p is their transversal and 1 = 120°
∠1 + ∠2 = 180 °(Straight line)
120° + ∠2 = 180° > ∠2 = 180° - 120° = 60°
∠2 = 60°
But ∠1 = ∠3 (Vertically opposite angles)
∠3 = ∠1 = 120°
Similarly ∠4 = ∠2
By Vertically opposite angles,
∠4 = 60°
∠5 = ∠1 (Corresponding angles)
∠5 = 120°
Similarly, by corresponding angles:
∠6 = ∠2
∠6 = 60°
∠7 = ∠5 (Vertically opposite angles)
∠7 = 120°
And,
∠8 = ∠6 (Vertically opposite angles)
∠8 = 60°
Hence ∠2 = 60°, ∠3 = 120°, ∠4 = 60°, ∠5 = 120°, ∠6 = 60°, ∠7 = 120° and ∠8 = 60°
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1. Let g(x)=3x+4cos(1/2 x)a. What is the linear approximation to g(x) around x=0.b. Using the linear approximation, approximate 3(0.2) +4cos(0.1).2. A particle moves in such a way that at times t
Linear approximation to g(x) at x=0:
For this, we will require to compute g(0), g'(0), and use the formula g(x) ≈ g(0) + g'(0)x.
Let's first find g(0):
g(0) = 3(0) + 4cos(1/2(0)) = 4
Next, let's find g'(x):
g(x) = 3x + 4cos(1/2 x)
g'(x) = 3 - 2sin(1/2 x)
Evaluate g'(0):
g'(0) = 3 - 2sin(1/2(0)) = 3
So we have the linear approximation around x=0:
g(x) ≈ 4 + 3x.
Approximating 3(0.2) + 4cos(0.1) using linear approximation:
We will use the result from the first part:
g(x) ≈ 4 + 3x, so that g(0.2) ≈ 4 + 3(0.2) = 4.6
Now we will approximate 4cos(0.1) by using the linear approximation of cos(x) at x=0, which is:
cos(x) ≈ 1 - x
So that cos(0.1) ≈ 1 - 0.1 = 0.9
Now we use these approximations to approximate 3(0.2) + 4cos(0.1):
3(0.2) + 4cos(0.1) ≈ 3(0.2) + 4(0.9) = 1.8 + 3.6 = 5.4
The approximation is 5.4.
A particle moves in such a way that at times t, its velocity is given by v(t) = 4e^(t/4) - 4 (cm/s). What is the displacement of the particle during the first 2 seconds?
The velocity is given by v(t) = 4e^(t/4) - 4. This is a continuous function, so we can calculate the displacement by finding the antiderivative of the velocity function and evaluating it between the limits of 0 and 2.
We can also notice that the velocity function is the derivative of the displacement function, so the displacement function is simply the antiderivative of the velocity function: s(t) = ∫v(t) dt.
Let's compute the displacement for the first 2 seconds by evaluating the antiderivative between 0 and 2. We can use the formula for the antiderivative of an exponential function ∫e^x dx = e^x + C.
s(t) = ∫v(t) dt = 4e^(t/4) - 4t + C
The constant of integration is arbitrary and we will determine it by using the initial condition that s(0) = 0:
s(0) = 4e^(0/4) - 4(0) + C = 4 - 0 + C = 4 => C = 0
Now we have:
s(t) = 4e^(t/4) - 4t
The displacement for the first 2 seconds is:
s(2) - s(0) = (4e^(2/4) - 4(2)) - (4e^(0/4) - 4(0)) = (4e^(1/2) - 8) - 4 = 4
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How many different seating arrangement can a teacher make for a class of 30, if the classroom has 6 rows with 5 desks per row?
There are 126,749,601,088,000 different seating arrangements.
The number of different seating arrangements for a class of 30 students seated in a classroom with 6 rows of 5 desks each can be found by using the permutation formula.
To seat 30 students in 30 desks, there are 30 choices for the first seat, 29 choices for the second seat, 28 choices for the third seat, and so on until there is only 1 choice for the 30th seat. This can be expressed mathematically as:
30 × 29 × 28 × ... × 2 × 1
However, since the desks are arranged in rows, the order in which the students are seated within each row does not matter. So we need to divide the above expression by the number of ways in which 5 students can be arranged in a row. This can be calculated as:
5 × 4 × 3 × 2 × 1
So the total number of different seating arrangements is:
(30 × 29 × 28 × ... × 2 × 1) / (5 × 4 × 3 × 2 × 1)
which simplifies to 30! / (5!)^6
Using a calculator, this expression evaluates to:
126, 749, 601, 088, 000
Therefore, by Permutation formula there are 126,749,601,088,000 different seating arrangements that a teacher can make for a class of 30 seated in a classroom with 6 rows of 5 desks each.
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Reasoning One image of ABC is A'B'C'. How do the
x-coordinates of the vertices change? How do the y-coordinates of
the vertices change? What type of reflection is the image A'B'C'?
How do the x-coordinates of the vertices change?
A. The x-coordinates of the vertices change differently depending on where they are on the figure.
B. The x-coordinates of the vertices are the same distance away from the x-axis but in the opposite direction.
C. The x-coordinates of the vertices are unchanged in the image.
D. The x-coordinates of the vertices are the same distance away from the y-axis but in the opposite direction.
The x-coordinates of the vertices are at the same distance away from the x-axis but in the opposite direction of the triangle.
What is triangle ?A triangle is a geometric shape consisting of three straight sides and three angles. It is a polygon with three sides. Triangles are one of the simplest shapes in geometry, and they can be classified based on their side lengths and angle measures.
According to given information :
B. The x-coordinates of the vertices are the same distance away from the x-axis but in the opposite direction.
When an object is reflected across the x-axis, the x-coordinates of its vertices remain the same, but their signs are flipped.
So, if the original coordinates of the vertices of ABC are (x₁, y₁), (x₂, y₂), and (x₃, y₃), then the coordinates of the reflected image A'B'C' are (x₁, -y₁), (x₂, -y₂), and (x₃,-y₃).
The x-coordinates remain the same, but the y-coordinates change in sign.
Therefore, the x-coordinates of the vertices are the same distance away from the x-axis but in the opposite direction.
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What is the equation in the slope-intercept form of the line that passes through the point (0,-4) and (2,0)?
An equation in slope-intercept form of the line that passes through the point (0, -4) and (2, 0) is y = 2x - 4.
What is the point-slope form?In Mathematics, the point-slope form of any straight line can be calculated by using the following mathematical expression:
[tex]y - y_1 = \frac{(y_2- y_1)}{(x_2 - x_1)}(x - x_1)[/tex] or y - y₁ = m(x - x₁)
Where:
m represents the slope.x and y represent the points.At data point (0, -4), a linear equation of this line can be calculated in slope-intercept form as follows:
[tex]y - y_1 = \frac{(y_2- y_1)}{(x_2 - x_1)}(x - x_1)[/tex]
[tex]y - (-1) = \frac{(0- (-4))}{(2 - 0)}(x - 0)\\\\y +1 = \frac{(0+4)}{(2 - 0)}(x - 0)[/tex]
y + 4 = 2(x - 0)
y = 2x - 4
In this context, we can reasonably infer and logically deduce that a linear equation or function of the line with these the points (0, -4) and (2, 0) in slope-intercept form is y = 2x - 4.
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If 2a+b=7 and b+2c=23 what is the mean of a,b,c
Answer:To find the mean of a, b, and c, we first need to determine their individual values.
We can use the two given equations to solve for a, b, and c:
2a + b = 7 (equation 1)
b + 2c = 23 (equation 2)
Solving for b in equation 1, we get:
b = 7 - 2a
Substituting this value of b into equation 2, we get:
7 - 2a + 2c = 23
Simplifying this equation, we get:
2c - 2a = 16
Dividing both sides by 2, we get:
c - a = 8
Solving for c in terms of a, we get:
c = a + 8
Now, we can substitute this expression for c into equation 2 to solve for b:
b + 2c = 23
b + 2(a + 8) = 23
b + 2a + 16 = 23
b + 2a = 7
Substituting the value of b from equation 1 into this equation, we get:
7 - 2a + 2a = 7
Therefore, we have found that:
b = 7 - 2a
c = a + 8
To find the mean of a, b, and c, we can add these values together and divide by 3:
mean = (a + b + c) / 3
Substituting the expressions we found for b and c, we get:
mean = (a + (7 - 2a) + (a + 8)) / 3
Simplifying this equation, we get:
mean = (3a + 15) / 3
mean = a + 5
Therefore, the mean of a, b, and c is equal to a + 5. We do not have enough information to determine the specific values of a, b, and c, so we cannot determine the exact value of the mean.
Step-by-step explanation:
find the value of x. round to the nearest tenth!!!!!
Answer:
82.3 .
Step-by-step explanation:
We can use the trigonometric ratios ( SOH CAH TOA)
The opposite side is the side opposite the degree or 22.
We are looking for the adjacent which is the part, let's say, 'under' the angle.
It looks like the TOA ratio ( tan β) is the suitable ratio.
Tan 61 = x/22 ( opposite/adjacent= tan β)
Thus, x= 22tan 61
x = 82.34...
x≈ 82.3 (nearest tenth)
Hope this helps! :)
Find the sum of the numbers between, and including, 551-600.
Sn=
The sum of the numbers between, and including, 551-600 is 28,775.
How to calculate the sum of the numbers between, and including, 551-600.Using the formula:
Sn = n/2 * (a1 + an)
where
Sn is the sum of the numbers,
n is the number of terms,
a1 is the first term, and
an is the last term.
From the question,
n = 50 (since there are 50 numbers between 551 and 600, inclusive),
a1 = 551, and
an = 600.
So we have:
Sn = 50/2 * (551 + 600)
= 25 * 1151
= 28,775
Therefore, the sum of the numbers between and including 551-600 is 28,775.
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what's the answersssss????
Step-by-step explanation:
inversely proportional to x² means
y = k/x²
directly proportional would have meant
y = kx²
so, based on
y = k/x²
we need to find k out of the given data points, so that we can calculate autobahn data points.
let's start with x = 1
16 = k/1² = k
let's verify : x = 2
4 = 16/2² = 16/4 = 4 correct
x = 3
16/9 = 16/3² = 16/9 correct
x = 4
1 = 16/4² = 16/16 correct
a)
y = 16/x²
b)
y = 25
25 = 16/x²
25x² = 16
let's pull the square root on both sides
5x = 4
x = 4/5
FYI : x could have been also -4/5 (remember, any square root has a positive and negative number solution, as the square is the same). but the request was for the positive number.
Min must drive 814 mile to get to the mall. He has already traveled 34 mile. How many more miles must he drive to get to the mall?
Enter your answer as a mixed number in simplest form by filling in the boxes
If Min must drive 814 mile to get to the mall. He has already traveled 34 mile, To reach the mall, Min must travel an additional 780 miles.
To see why, you can subtract the distance Min has already traveled from the total distance he needs to travel:
Total distance = 814 miles
Distance traveled = 34 miles
Distance remaining = Total distance - Distance traveled
Distance remaining = 814 miles - 34 miles
Distance remaining = 780 miles
Therefore, Min must drive 780 more miles to get to the mall. Driving long distances can be a daunting task, especially if it involves traveling hundreds of miles. In the example given, Min needs to drive 814 miles to get to the mall. It's important to plan ahead for such a long journey to ensure safety and comfort. This includes checking the weather conditions, planning rest stops, and having enough food and water to stay hydrated and energized. It's also important to make sure the vehicle is in good condition and has enough fuel to make the journey. It's recommended to take breaks every couple of hours to rest and stretch your legs. By following these tips, Min can make the long drive to the mall safely and comfortably
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I need of assistance, Question stated in picture.
The perimeter of the given figure is 22.56 units respectively.
What do we mean by perimeter?A closed path that covers, encircles, or outlines a one-dimensional length or a two-dimensional shape is called a perimeter.
A circle's or an ellipse's circumference is referred to as its perimeter.
There are numerous uses in real life for perimeter calculations.
The distance around an object is called the perimeter. For instance, the yard of your home is fenced in.
The fence's length serves as the perimeter.
Your fence is 200 feet long if the yard is 50 feet by 50 feet.
So, the perimeter of the figure would be:
Semicircle + Semicircle = Circle
Now, the perimeter of the circle: r = 4/2 = 2
= 2πr
= 2*3.14*2
= 12.56
Perimeter = 12.56 + 5 + 5
Perimeter = 22.56 units
Therefore, the perimeter of the given figure is 22.56 units respectively.
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1
(ii) angle ACE,
Answer(a)(i) Angle BCA =
B
42°
(iii) angle CFE,
A, B, C, D, E and Fare points on the circumference of a circle centre O..
AE is a diameter of the circle.
BC is parallel to AE and angle CAE = 42°.
Giving a reason for each answer, find
(i) angle BCA,
(iv) angle CDE.
Answer(a)(ii) Angle ACE
Reason
Reason
Reason
*****
Answer(a)(iv) Angle CDE=
GGSkexanguru.com
**********
C
**********
E
*********▪▪▪▪▪▪
NOT TO
SCALE
May June 2012 Code 42
[2]
[2]
[2]
[2]
So, the probability that a randomly selected light bulb will last between 750 and 900 hours is 40.82%, or 0.4082 as a decimal.
What is Probability?Probability refers to the measure or quantification of the likelihood of an event or outcome occurring. It is a numerical value between 0 and 1, where 0 represents an impossible event (never occurring) and 1 represents a certain event (always occurring).
Probability can be calculated by dividing the number of favorable outcomes by the total number of possible outcomes. For example, if we flip a fair coin, the probability of getting heads is 0.5, because there is one favorable outcome (heads) out of two possible outcomes (heads or tails).
by the question.
Using the given mean and standard deviation, we can standardize the range of 750 to 900 hours as follows:
[tex]z1 = (750 - 750) / 75 = 0[/tex]
[tex]z2 = (900 - 750) / 75 = 1.33[/tex]
We can then use the 68-95-99.7 rule to find the probability that a randomly selected light bulb will last between 750 and 900 hours:
[tex]P(750 \leq X \leq 900) = P(0 \leq Z \leq 1.33)[/tex]
From the table of standard normal probabilities, we can find that the area to the left of 1.33 is 0.9082, and the area to the left of 0 is 0.5. Therefore:
[tex]P(0 \leq Z \leq 1.33) = 0.9082 - 0.5 = 0.4082[/tex]
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Your friend clAIMs that you can transform every rhombus into a square using a similarity transformation. Is your friend correct? explain your reasoning
Yοur friend is nοt cοrrect. Since a similarity transfοrmatiοn can οnly transfοrm οne shape intο anοther shape that is similar tο it.
Similarity transfοrmatiοn:
A similarity transfοrmatiοn is a type οf geοmetric transfοrmatiοn that preserves the shape οf a geοmetric figure, while pοssibly changing its size, οrientatiοn, and pοsitiοn in the plane οr in space.
Specifically, a similarity transfοrmatiοn is a cοmpοsitiοn οf a dilatiοn (οr a unifοrm scaling), fοllοwed by a rigid transfοrmatiοn (a rοtatiοn, reflectiοn, οr translatiοn).
Transfοrming rhοmbus intο a square using a similarity transfοrmatiοn:
A rhοmbus is a quadrilateral with all sides οf equal length, while a square is a special type οf rhοmbus with all angles equal tο 90°.
Althοugh a square is a rhοmbus, nοt every rhοmbus is a square, and it is nοt pοssible tο transfοrm every rhοmbus intο a square using a similarity transfοrmatiοn.
Tο transfοrm a rhοmbus intο a square, yοu wοuld need tο change the length οf at least οne οf its sides, which is nοt allοwed in a similarity transfοrmatiοn.
Instead, yοu wοuld need tο use οther types οf transfοrmatiοns, such as a shear οr a cοmbinatiοn οf rοtatiοns and translatiοns.
Therefοre,
Yοur friend is nοt cοrrect. Since a similarity transfοrmatiοn can οnly transfοrm οne shape intο anοther shape that is similar tο it.
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it takes 6 painters 4 1/2 hours to paint these classrooms .calculate how long 3 painters will take to compete the same job . is this direct or indirect proportion
Answer:
9 hours
Step-by-step explanation:
If someone returns an item for 15 dollars and buys a nother idem for 15 dollars
The net effect on someone's overall spending after returning an item for 15 dollars and buying another item for 15 dollars will depend on the store's return policy regarding returns and exchanges
If someone returns an item for 15 dollars and then buys another item for 15 dollars, the net effect on their overall spending will depend on the store's policy regarding returns and exchanges.
If the store offers a full refund for the returned item, the person will essentially receive back the 15 dollars they spent on the original item. If they then purchase a new item for 15 dollars, their overall spending will remain the same.
However, if the store charges a restocking fee or only offers store credit for returns, the person may not receive the full 15 dollars back. In that case, their overall spending would increase by the amount of the restocking fee or by the difference between the refunded amount and the original purchase price.
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The given question is incomplete, the complete question is:
If someone returns an item for 15 dollars and buys another item for 15 dollars, what will be the net effect ?
Comparing scales: In an experiment to determine whether there is a systematic difference between the weights obtained with two different scales, 10 rock specimens were weighed, in grams, on each scale. The following data were obtained:
Specimen Weight on Scale 1 Weight on Scale 2
1
12. 35
12. 51
2
15. 08
14. 99
3
9. 00
9. 10
4
11. 55
11. 47
5
24. 36
24. 35
6
9. 88
10. 00
7
15. 36
15. 55
8
7. 05
7. 04
9
13. 39
13. 57
Let μ1 represent the mean weight on Scale 1 and ud= μ1-μ2
Can you conclude that the mean weight on Scale 1 is less than the mean weight on Scale 2?
Use the a=0. 10 level of significance
We can conduct a hypothesis test to determine the scale 1's mean weight is less than the weight of scale 2.
H0: μ1 ≥ μ2 (the mean weight on Scale 1 is greater than or equal to the mean weight on Scale 2)
Ha: μ1 < μ2 (the mean weight on Scale 1 is less than the mean weight on Scale 2)
We will use a significance level of α = 0.10.
First, we calculate the sample means and the difference between the means:
Sample mean weight on Scale 1, μ1 = (12.35 + 15.08 + 9.00 + 11.55 + 24.36 + 9.88 + 15.36 + 7.05 + 13.39)/10 = 12.43
Sample mean weight on Scale 2, μ2 = (12.51 + 14.99 + 9.10 + 11.47 + 24.35 + 10.00 + 15.55 + 7.04 + 13.57)/10 = 13.15
Difference between the means, ud = μ1 - μ2 = -0.72
s.d.(ud) = sqrt((s1^2/n1) + (s2^2/n2))
s1 and s2 are sample standard deviations n1 n1 and n 2
s1 = sqrt(((12.35 - 12.43)^2 + (15.08 - 12.43)^2 + ... + (13.39 - 12.43)^2)/9) = 3.153
s2 = sqrt(((12.51 - 13.15)^2 + (14.99 - 13.15)^2 + ... + (13.57 - 13.15)^2)/9) = 2.114
n1 = n2 = 10
The test statistic can now be calculated as:
t = (ud - 0) / (s.d.(ud)/sqrt(n)) = (-0.72 - 0) / (1.109/sqrt(10)) = -2.05
Using a t-distribution table with 9 degrees of freedom and a one-sided test at α = 0.10, we find the critical value to be -1.383. As the calculated value so we will not consider null hypothesis.
The mean weight of scale 1 can be less than the scale 2 mean weight at 0.10 level.
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The angle � 1 θ 1 theta, start subscript, 1, end subscript is located in Quadrant IV IVstart text, I, V, end text, and sin ( � 1 ) = − 24 25 sin(θ 1 )=− 25 24
In both cases, the values given are outside the range of possible values for the sine function, so there is no solution to the equations.
What is angle?In mathematics, an angle is a geometric figure formed by two rays or line segments that share a common endpoint, called the vertex. The rays or line segments that form the angle are known as the sides of the angle. The size of an angle is typically measured in degrees or radians. In Euclidean geometry, angles are usually measured in degrees, with a full circle consisting of 360 degrees. One degree is equal to 1/360th of a full circle. Angles can be classified as acute, right, obtuse, straight, or reflex, depending on their size and shape.
Here,
1. It is not possible to find a value of θ that satisfies the equation sin θ = -24/25, because the sine function is defined as the ratio of the opposite side to the hypotenuse in a right triangle, and the ratio cannot be larger than 1 or smaller than -1. Therefore, there is no angle whose sine is equal to -24/25.
2. Similarly, it is not possible to find a value of θ that satisfies the equation sin θ = -25/24, because the sine function is defined as the ratio of the opposite side to the hypotenuse in a right triangle, and the ratio cannot be larger than 1 or smaller than -1. Therefore, there is no angle whose sine is equal to -25/24.
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Complete question:
Find the value of θ when:
1. sin θ=-24/25
2. sin θ=-25/24
Nora recorded the grade-level and instrument of everyone in the middle school School of Rock below.
Seventh Grade Students
Instrument # of Students
Guitar 13
Bass 12
Drums 14
Keyboard 5
Eighth Grade Students
Instrument # of Students
Guitar 6
Bass 8
Drums 4
Keyboard 11
Based on these results, express the probability that a seventh grader chosen at random will play the bass as a percent to the nearest whole number.
The probability that a seventh grader chosen at random will play the bass is approximately 27 percent.
To find the probability that a seventh grader chosen at random will play the bass, we need to calculate the total number of seventh graders who play the bass and divide it by the total number of seventh graders.
According to the data given, there are 12 seventh grade students who play the bass, and the total number of seventh grade students is:
Total number of seventh grade students = 13 + 12 + 14 + 5 = 44
Therefore, the probability that a seventh grader chosen at random will play the bass is:
Probability = Number of seventh graders who play bass / Total number of seventh grade students
Probability = 12 / 44
To express this probability as a percentage, we need to multiply it by 100:
Probability as a percentage = (12 / 44) x 100
Probability as a percentage = 27.3
Rounding this to the nearest whole number gives:
Probability as a percentage ≈ 27
Therefore, the probability that a seventh grader chosen at random will play the bass is approximately 27 percent.
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Answer:
Step-by-step explanation:
the actual answer is 68%
Write the equation of the line that passes through (5,-2) and is perpendicular to y=x-3.
Answer:
[tex]y\:=\:-\frac{3}{5}x\:+1[/tex]
Step-by-step explanation:
A shirt is on sale for 60% off. If the sale price is $16, what was the original price?
Answer:
$40
Step-by-step explanation:
We can represent the price of an item on sale for [tex]x\%[/tex] off as:
[tex]S=P \cdot \dfrac{100-x}{100}[/tex],
where P is the product's original price and S is the sale price.
Applying this to the problem at hand:
[tex]\$16=P \cdot \dfrac{100-60}{100}[/tex]
↓ simplifying the fraction
[tex]\$16=P \cdot \dfrac{2}{5}[/tex]
To solve for P in this equation (the original price), we have to multiply both sides of the equation by the reciprocal of its coefficient.
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Remember that any fraction multiplied by its reciprocal is 1:
[tex]\dfrac{2}{5} \cdot \dfrac{5}{2} = \dfrac{10}{10} = 1[/tex]
⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯
[tex]\dfrac{5}{2} \left( \$16\right)= \left(P \cdot \dfrac{2}{5}\right)\dfrac{5}{2}[/tex]
[tex]\boxed{\$40 = P}[/tex]
So, the original price of the shirt was $40.
Which graph represents the function f(x)=|x-2|+1?
Answer:
Step-by-step explanation:
The graph of the function f(x) = |x-2|+1 can be obtained by breaking the expression into two parts based on the definition of absolute value. When x is greater than or equal to 2, the expression evaluates to (x-2)+1 = x-1. When x is less than 2, the expression evaluates to -(x-2)+1 = 3-x.
Thus, we can write the function as:
f(x) = {x-1, x >= 2
{3-x, x < 2
The graph of the function f(x) looks like:
|
4 - | /\
| / \
3 - | / \
|/ \
2 - +--------\-------
0 1 2 3 4
Note that the graph has a corner point at (2, 1) where the two parts of the function meet. On the left side of the graph, the function is decreasing linearly from (2, 1) to (0, 3), while on the right side, the function is increasing linearly from (2, 1) to (4, 3).
A new restaurant in town is surveying residents to determine how much they typically pay for a meal out. Which of the following best describes a random sample
A. They go door-to-door in a nearby neighborhood.
B. They randomly select 50 residents of a local nursing home.
C. They call 200 randomly selected town residents.
D. They ask patrons if the price was reasonable.
The correct answer is (C) They call 200 randomly selected town residents.
Why are unbiased estimators preferred over biased estimators?
A. Unbiased estimators behave with reliable results, where as biased estimators are inconsistent.
B. Unbiased estimators require a greater sample size which gives greater accuracy over biased estimators.
C. Unbiased estimators retain original distribution of the same, where as biased estimators follow a normal distribution
D. Unbiased estimators follow the normal distribution, where as biased estimators follow original distribution
A. Unbiased estimators behave with reliable results, where as biased estimators are inconsistent.
Unbiased estimators are preferred over biased estimators because they provide accurate estimates of population parameters. An estimator is said to be unbiased if, on average, it gives an estimate that is equal to the true population parameter being estimated.
Biased estimators, on the other hand, have a tendency to systematically overestimate or underestimate the population parameter, which can lead to incorrect conclusions. While biased estimators may sometimes have lower variability or require smaller sample sizes, they cannot be relied upon to provide accurate estimates in the long run. Unbiased estimators, on the other hand, retain the original distribution of the data and are consistent, making them more reliable in providing accurate estimates of population parameters.
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Write the equation of the line passing through the points (0, 10) and (2, 14) in the form ax + y = c. What is the value of a?
Answer:
Step-by-step explanation:
To find the equation of the line passing through the points (0, 10) and (2, 14) in the form ax + y = c, we can use the point-slope form of the equation of a line:
y - y1 = m(x - x1)
where m is the slope of the line and (x1, y1) is a point on the line. We can use the point (0, 10) as our reference point, so x1 = 0 and y1 = 10. We need to find the slope of the line:
m = (y2 - y1)/(x2 - x1)
where (x2, y2) is the other point on the line. Using (0, 10) and (2, 14), we get:
m = (14 - 10)/(2 - 0) = 2
So the slope of the line is 2. Now we can use the point-slope form of the equation to find the equation of the line:
y - 10 = 2(x - 0)
Simplifying, we get:
y - 10 = 2x
Adding 10 to both sides, we get:
y = 2x + 10
This is the equation of the line in slope-intercept form. To write it in the form ax + y = c, we can rearrange the terms:
-2x + y = 10
Therefore, the value of a is -2.
The equation of the line passing through the points (0, 10) and (2, 14) in the form ax + y = c is 2x - y = -10. The value of a is 2.
Explanation:To find the equation of the line passing through the points (0, 10) and (2, 14), we need to use the slope-intercept form of the equation: y = mx + b. First, let's find the slope (m) using the formula: m = (y2 - y1) / (x2 - x1). Plugging in the coordinates, we get m = (14 - 10) / (2 - 0) = 2. Now, we can use one of the points and the slope to find the y-intercept (b). Let's use the point (0, 10). Since y = mx + b, we can rearrange the equation to solve for b: b = y - mx. Plugging in the values, we get b = 10 - (2 * 0) = 10. So the equation of the line is y = 2x + 10. In the form ax + y = c, we can rewrite the equation as 2x - y = -10. Therefore, the value of a is 2.
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A school principal of 110 students needs to determine what percent of students passed and did not pass a
statewide examination. Round to the nearest percent.
(a) If 80 students passed the exam, what percent passed the test?
(b) What percent did not pass the test?
Answer:
(a) The percent of students who passed the exam is:
Percent passed = (number of students who passed ÷ total number of students) × 100
Percent passed = (80 ÷ 110) × 100
Percent passed = 72.73%
Rounded to the nearest percent, 73% of the students passed the exam.
(b) The percent of students who did not pass the exam is:
Percent did not pass = 100% - percent passed
Percent did not pass = 100% - 72.73%
Percent did not pass = 27.27%
Rounded to the nearest percent, 27% of the students did not pass the exam.
Please help answer the linked question
Answer:3.5 ish
Step-by-step explanation:
Given that y = 9 cm and θ = 46°, work out x rounded to 1 DP.
Answer:
Step-by-step explanation:
[tex]sin\theta=\frac{x}{y}[/tex]
[tex]sin45=\frac{x}{9}[/tex]
[tex]x=9sin45[/tex]
[tex]=7.7cm[/tex] (to 1 decimal place)
two flower seeds are randomly selected from a package that contains 8 seeds for red flowers and 13 seeds for white flowers. (give your answer correct to three decimal places.) (a) what is the probability that both seeds will result in red flowers? (b) what is the probability that one of each color is selected? (c) what is the probability that both seeds are for white flowers?
If there are 8 red flower seeds and 13 white flower seeds in a package, (a) the probability of getting two red flowers is 0.114, (b) the probability of getting one of each color is 0.495, and (c) the probability of getting two white flowers is 0.371.
(a) The probability of selecting the first red seed is 8/21, and the probability of selecting the second red seed is 7/20 (since there are now 7 red seeds left out of 20 total). Therefore, the probability of selecting two red seeds is (8/21) * (7/20) = 0.114.
(b) The probability of selecting one red seed and one white seed can happen in two ways: either red-white or white-red. The probability of red-white is (8/21) * (13/20), and the probability of white-red is (13/21) * (8/20). So the total probability is (8/21) * (13/20) + (13/21) * (8/20) = 0.495.
(c) The probability of selecting the first white seed is 13/21, and the probability of selecting the second white seed is 12/20 (since there are now 12 white seeds left out of 20 total). Therefore, the probability of selecting two white seeds is (13/21) * (12/20) = 0.371.
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Suppose we haveX1,…,Xn ~ N(μ,σ2) with density,f(x)=\frac{1}{\sigma{\sqrt{2\pi}}}e^{\frac{-(x-\mu)^{2}}{2\sigma^{2}}}x\epsilon(-\propto,\propto)1) DoesS^{2}attain CRLB (Cramer-Rao Lower Bound) for\sigma^{^{2}}?2) Would the MLE for\sigma^{^{2}},\widehat{\sigma ^{2}}=\frac{1}{n}\sum_{i=1}^{n}(X_{i}-\bar{X})^{2}, be the UMVUE if attained by CRLB?Please show how you derived your answers.Unbiased estimator for\sigma^{^{2}},S^{2}=\frac{1}{n-1} \sum_{i=1}^{n}(X_{i}-\bar{X})^{2}, has varianceVar(S^{2})=\frac{2\sigma^{4}}{n-1}
Yes, the unbiased estimator for $\sigma^2$, $S^2 = \frac{1}{n-1}\sum_{i=1}^{n}(X_i-\bar{X})^{2}$, does attain the Cramer-Rao Lower Bound (CRLB) for $\sigma^2$. The CRLB for $\sigma^2$ is given by the equation $Var(\hat{\sigma^2})=\frac{2\sigma^4}{n-1}$.
The Maximum Likelihood Estimator (MLE) for $\sigma^2$ is given by $\hat{\sigma^2}=\frac{1}{n}\sum_{i=1}^{n}(X_{i}-\bar{X})^{2}$. If $S^2$ attains the CRLB, then the MLE $\hat{\sigma^2}$ is the Unbiased Minimum Variance Unbiased Estimator (UMVUE) of $\sigma^2$.
This can be shown by first noting that the density of $X_1,...,X_n$ is given by $f(x)=\frac{1}{\sigma{\sqrt{2\pi}}}e^{\frac{-(x-\mu)^{2}}{2\sigma^{2}}}$, $\forall x \epsilon (-\infty,\infty)$. Then, since $S^2$ is an unbiased estimator of $\sigma^2$ with variance $Var(S^2)=\frac{2\sigma^4}{n-1}$, it attains the CRLB for $\sigma^2$. Therefore, the MLE for $\sigma^2$, $\hat{\sigma^2}$, is the UMVUE for $\sigma^2$.
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Suppose we have a random sample X1, X2, ..., Xn from a normal distribution with mean and variance σ^2, and density function f(x) = (1/(σ√(2π))) * e^(-(x-μ)^2/(2σ^2)), where x is in the range of (-∞, ∞). We are interested in two questions:
Does the sample variance S^2 attain the Cramer-Rao lower bound (CRLB) for σ^2?
If the maximum likelihood estimator (MLE) for σ^2, denoted by \widehat{σ^2} = (1/n) * ∑(Xi- MEAN)^2, is attained by the CRLB, is it also the uniformly minimum variance unbiased estimator (UMVUE)?
It is known that the unbiased estimator for σ^2 is S^2 = (1/(n-1)) * ∑(Xi- MEAN)^2, and it has variance Var(S^2) = (2σ^4)/(n-1).
Anna is in charge of the alumni fundraiser for her alma mater. She is selling pre-sale tickets for $10 and at-the-door tickets for $20. The venue has the capacity to hold 400 people. The graph represents the number of tickets Anna needs to sell to offset her upfront costs and raise $5,000 for her school:
Graph with x axis labeled pre sale tickets and y axis labeled at the door tickets. There are two lines intersecting at three hundred comma one hundred.
How many at-the-door tickets must she sell to make her goal?
400
300
250
100
Answer: From the graph, we can see that the point where the two lines intersect is (300, 100). This means that Anna needs to sell 300 pre-sale tickets and 100 at-the-door tickets to reach her goal of raising $5,000.
Since each pre-sale ticket costs $10 and each at-the-door ticket costs $20, the total revenue from pre-sale tickets would be:
300 pre-sale tickets × $10/ticket = $3,000
To reach her goal of $5,000, Anna would need to earn an additional:
$5,000 - $3,000 = $2,000
To earn $2,000 from at-the-door tickets, she would need to sell:
$2,000 ÷ $20/ticket = 100 at-the-door tickets
Therefore, Anna would need to sell 100 at-the-door tickets to make her goal.
Step-by-step explanation: