Work out 2 and 1/2 x 1 and 4/5
Give your answer as a mixed number in its simplest form

the cost of a VCR that sold for $1,389.88 in 1981 would be $3,686.12 in today's dollars, adjusted for inflation.

To calculate the cost of a VCR in today's dollars based on its cost in 1981, we need to adjust for inflation using the Consumer Price Index (CPI).

We need to find the CPI for the year 1981 and the current year. For example, let's say the CPI for 1981 is 98.3 and the CPI for the current year is 260.5.

Inflation rate = (Current year CPI / 1981 CPI) x 100

Inflation rate = (260.5 / 98.3) x 100

Inflation rate = 265.17

This means that the general price level has increased by 265.17% since 1981.

To find the cost of the VCR in today's dollars, we multiply its cost in 1981 by the inflation rate:

Cost in today's dollars = Cost in 1981 x (Inflation rate / 100)

Cost in today's dollars = $1,389.88 x (265.17 / 100)

Cost in today's dollars = $3,686.12 (rounded to the nearest cent)

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The value of x from the given expression (3^1/2 ) ( 3^1/2 ) = 3^6 can be expressed as 6.

A formula that expresses the connection between two expressions on each side of a sign. Typically, it has a single variable and an equal sign. Like this: 2x - 4 Equals 2. In the above example, the variable x exists.

Given that (3^1/2 ) ( 3^1/2 ) = 3^6

then 3^(x/2+ x/2) = 3 ^6

x/2+ x/2 = 6

Then the lcm , we have

x+x/2 = 6

2x/2 = 6

2x = 12

x = 12/2 = 6

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If an art teacher has 4 1/8 gallons of paint to pour into containers, the art teacher can fill 11 containers with the 4 1/8 gallons of paint they have.

To solve the problem, we need to divide the total amount of paint by the capacity of each container.

First, we need to convert 4 1/8 gallons to an improper fraction. To do this, we multiply the whole number by the denominator and add the numerator, then put the result over the denominator:

4 1/8 = (4 x 8 + 1)/8 = 33/8

Next, we divide the total amount of paint by the capacity of each container:

33/8 ÷ 3/8 = 33/8 x 8/3 = 11

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Complete question is:

An art teacher has 4 1/8 gallons of paint to pour into containers. If each container holds 3/8 ​ gallon, how many containers can they fill?

P(X≥2) = 1 - 0.389 - 0.409= 0.202. The probability that at least 2 patients will die out of next 10 patients is 0.202.

The death rate from Covid19 in a certain country is 6%. The probability that at least 2 patients will die out of next 10 patients can be found using binomial distribution. What is binomial distribution? Binomial distribution is a probability distribution that deals with the number of successes or failures in a given number of trials. A binomial distribution model is characterized by the following conditions: There are only two outcomes of the trials, either success or failure. The probability of success is constant throughout the trials.

The trials are independent of each other. The formula for the probability of binomial distribution is as follows: P(X=k) = (n C k) × p^k × (1-p)^(n-k)Where P(X=k) is the probability of k successes out of n trials. n C k represents the number of ways of selecting k items out of n items. p is the probability of success.1-p is the probability of failure. Using the above formula, the probability that at least 2 patients will die out of next 10 patients is: P(X≥2) = 1 - P(X=0) - P(X=1)P(X=0) = (10 C 0) × 0.06^0 × (1-0.06)^(10-0)= 0.389P(X=1) = (10 C 1) × 0.06^1 × (1-0.06)^(10-1)= 0.409Therefore,P(X≥2) = 1 - 0.389 - 0.409= 0.202The probability that at least 2 patients will die out of next 10 patients is 0.202.

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The values of x make the quadratic equation (x-2)² =2 is 2 + √2.

To find the values of x that make the quadratic equation (x-2)² = 2 true, we need to solve for x.

First, we can take the square root of both sides of the equation:

x - 2 = ±√2

Next, we can add 2 to both sides of the equation:

x = 2 ± √2

Therefore, the two solutions for x are:

x = 2 + √2

x = 2 - √2

These are the two values of x that make the quadratic equation (x-2)^2 = 2 true.

To check these solutions, we can substitute each value back into the original equation:

[(2 + √2) - 2]² = 2

Simplifying:

√2² = 2

2 = 2

This solution works. Now let's check the other solution:

[(2 - √2) - 2]² = 2

Simplifying:

-√2² = 2

-2 = 2

This solution does not work, so we discard it. Therefore, the only value of x that makes the quadratic equation (x-2)² = 2 true is: x = 2 + √2.

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Answer:

514.38 units²

Step-by-step explanation:

Answer: 0

Step-by-step explanation:

To find the coefficient of x in the equation:

x/8 + 4 = 6

We can begin by isolating x on one side of the equation. We can do this by subtracting 4 from both sides:

x/8 = 2

Next, we can multiply both sides by 8 to get rid of the fraction:

x = 16

Since there is no x-term on one side, the coefficient of x is 0.

Therefore, the coefficient of x in the given equation is 0.

Answer:

The polygon has 9 sides, and it is a nonagon.

Step-by-step explanation:

The formula to find the sum of the interior angles of a regular polygon is:

S = (n - 2) × 180

where S is the sum of the interior angles and n is the number of sides.

If each interior angle of the polygon is 140 degrees, we can use the formula to solve for n:

n = (S / 140) + 2

Plugging in S = 180(n-2) and simplifying, we get:

n = (180(n-2) / 140) + 2

n = (9n - 18) / 7

7n = 9n - 18

-2n = -18

n = 9

Therefore, the polygon has 9 sides, and it is a nonagon.

Hope this helps! I'm sorry if it's wrong. If you need more help, ask me! :]

In response to the stated question, we can state that As a result, there coordinates are 7 units between the points (1, 0) and (8, 0).

When locating points or other geometrical objects precisely on a manifold, such as Euclidean space, a coordinate system is a technique that uses one or more integers or coordinates. Locating a point or item on a two-dimensional plane requires the use of coordinates, which are pairs of integers. Two numbers called the x and y coordinates are used to describe a point's location on a 2D plane. a collection of integers that indicate exact locations. The figure often has two numbers. The first number denotes the front-to-back measurement, while the second number denotes the top-to-bottom measurement. For example, in (12.5), there are 12 units below and 5 above.

The distance formula can be used to determine the separation between two points in a two-dimensional Cartesian coordinate system:

[tex]\sqrt[(x2 - x1)2 + (y2 - y1)2] = d[/tex]

and d .

As both of the points in this instance have y-coordinates of 0, we may condense the expression to:

[tex]d = \sqrt[(8 - 1)^² + (0 - 0)^²]\\d = \sqrt[(7)^² + (0)^²]\\d = \sqrt[49]\\ d= 7[/tex]

As a result, there are 7 units between the points (1, 0) and (8, 0).

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The nearest whole number, the maximum value of S is equivalent to approximately 323 m², which is the area of the lawn.

We are given that the perimeter of the lawn is 90 m. Therefore, we can write:

2y + 4x + 2πx = 90

where π is the constant pi. Simplifying this equation gives:

y = 22.5 - 2x - πx

The area of the lawn is given by:

S = y(2x) + πx²

Substituting y in terms of x gives:

S = (22.5 - 2x - πx)(2x) + πx²

Simplifying this expression gives:

S = 45x - 2πx² - 4x²

We are asked to find the maximum value of S. To do this, we can differentiate S with respect to x and set the derivative equal to zero:

dS/dx

= 45 - 4πx - 8x = 0

Solving for x gives:

x = (45 - 4π)/8

Substituting this value of x into the expression for S gives:

S ≈ 323 m²

Rounding this value to the nearest whole number gives:

S ≈ 323 m².

Therefore, the maximum value of S is approximately 323 m².

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Complete question is:

Figure 2 shows the lawn ABCDEF, where ABDE is a rectangle of length y meters and width 2x meters. (Refer the image)

Each end of the lawn is a semi-circle of radius x meters.

The lawn has perimeter 90 m and area S m ²

dS/ dx= 90 - 2

Given S = 90x-x², then

The value x = 14. 32 gives a maximum value of S

Find, to the nearest whole number, the maximum value of S

Answer: 4

Step-by-step explanation:

Area of rose garden = 5.5 * 3.75 = 20.625

Area of vegetable garden = 13.75 * 6 = 82.5

To find how many times greater the area of the vegetable garden is, we simply divide 82.5 by 20.825

82.5 / 20.625 = 4

We can use a two-way ANOVA to compare the means of the three coefficients for OECD and non-OECD countries and assess whether the differences are probability significant.

To test the hypothesis that the three coefficients in the population regression are equal for OECD and non-OECD countries, we can run a two-way ANOVA. The two factors in this ANOVA would be OECD status (OECD or non-OECD) and the three coefficients in the population regression (income, population density, and urbanization). This will enable us to compare the means of the three coefficients for OECD and non-OECD countries and assess whether the differences are statistically significant. We can also use the F-statistic to see if the differences between the means of the two groups are statistically significant. This will allow us to assess whether the coefficients in the population regression are indeed different for OECD and non-OECD countries.

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The ordered pairs from the table are (22, 152), (28, 94), (35, 134), and (46, 110). Plotting them on a coordinate plane would produce a scatterplot.

The form of the scatterplot is a line of negative slope that is decreasing from left to right. The direction of the scatterplot is downward.

The relationship between the average price of jeans and number of jeans sold appears to be negative, which means that as the average price of jeans increases, the number of jeans sold decreases. In other words, there is an inverse relationship between the price and quantity demanded of jeans. This relationship is consistent with the law of demand in economics, which states that as the price of a good or service increases, the quantity demanded of that good or service will decrease, ceteris paribus (all else being equal).

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Tom and Gwen have an adjusted annual gross income of $111,480. Their front end ratio, which measures how much of their income is dedicated to housing costs, is 5.19%. Their back end ratio, which measures how much of their income is dedicated to all debt obligations, is 11.72%.

The front end ratio is a measure of how much of an individual’s gross income is dedicated to housing costs. It is calculated by taking the total housing costs, which includes mortgage payments, property taxes, and homeowners insurance premiums, and dividing it by the annual gross income. For Tom and Gwen, this would be:

Front End Ratio = (Mortgage Payment + Property Taxes + Homeowner’s Insurance Premium) / Annual Gross Income

Front End Ratio = (1,725 + 3,660 + 685) / 111,480

Front End Ratio = 5.19%

The back end ratio is a measure of how much of an individual’s gross income is dedicated to all debt obligations, including housing costs and other debts. It is calculated by taking all debt obligations, which includes mortgage payments, property taxes, homeowner’s insurance premiums, car payments, and credit card payments, and dividing it by the annual gross income. For Tom and Gwen, this would be:

Back End Ratio = (Mortgage Payment + Property Taxes + Homeowner’s Insurance Premium + Car Payment + Credit Card Payment) / Annual Gross Income

Back End Ratio = (1,725 + 3,660 + 685 + 154 + 2,021) / 111,480

Back End Ratio = 11.72%

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Answer:

We can use trigonometry to solve this problem. Let θ be the angle formed between the wire and the ground. Then, using the right triangle formed by the wire, the tower, and the ground, we have:

cos θ = adjacent/hypotenuse

where the adjacent side is 19 ft. (distance from the base of the tower to the anchor point) and the hypotenuse is 40 ft. (length of the guy wire). Solving for θ, we get:

θ = cos^-1(19/40) ≈ 62°

Therefore, the measure of the angle formed between the wire and the ground is approximately 62 degrees. Answer C.

Step-by-step explanation:

In order to map polygon ABCDE onto polygon A'B'C'D'E', a series of transformations must be performed. A common method of transforming a figure is to use a combination of translations, reflections, rotations, and dilations.

Transformation of a figure is the process of changing the shape, size, position or orientation of a 2D or 3D shape. This can be done using various techniques such as translations, rotations, reflections and enlargements. The transformation of a figure can help to visualize the change and understand the different properties of the shape. It can also be used to solve mathematical problems.

A transformation is a process in which a figure is changed in size, shape, or position.

A translation is a transformation that moves a figure in any direction. To move polygon ABCDE to polygon A'B'C'D'E', one must translate the figure to the right, left, up, or down.

A reflection is a transformation that flips a figure over a line, called the line of reflection. To reflect the figure onto the new polygon, the line of reflection must be chosen.

A rotation is a transformation that turns a figure around a point, called the center of rotation. To rotate the figure onto the new polygon, the center of rotation must be chosen.

A dilation is a transformation that changes the size of a figure. To scale the figure onto the new polygon, the scale factor must be chosen.

After the transformations are applied to the original figure, it will be mapped onto the new polygon. The combination of transformations must be chosen carefully in order to achieve the desired result.

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Answer:

The answer to your problem is, Area = 104.1 square feet.

Step-by-step explanation:

Area of semicircle = 1/2 the area of a circle:

[tex]A_{sc} = \frac{1}{2} tt r^{2}[/tex]

Radius is half the diameter of 6ft.

[tex]A_{sc} = \frac{1}{2} tt ( 3^{2} ) = 14.13ft^{2}[/tex]

Area of the rectangle:

[tex]A_{r} = lw = 15 * 6 = 90ft^{2}[/tex]

Add them:

[tex]90 + 14.13 = 104.13[/tex]

Round to the nearest tenth (one decimal place)

Which is 104.1

Thus the answer to your problem is 104.1 of 104.13

Answer:

The equation of the line with gradient -1 that passes through the point (-3, 0) can be found using the point-slope form of a line. The point-slope form of a line is given by:

y - y1 = m (x - x1)

Where m is the gradient and (x1, y1) is a point on the line.

For this line, m = -1 and (x1, y1) = (-3, 0). Thus, the equation of the line is:

y - 0 = -1 (x - (-3))

y = -x + 3

Answer:

x + y + 3 = 0

Step-by-step explanation:

equation of line ( point slope format)

(y-y1) = m(x - x1)

they had given the point as (-3,0) on comparing with (x1, y1) and substituting the values in equation we get

y = -1(x +3)

final ans

x + y + 3 = 0

The result of the evaluation and simplification of [tex]f(x)=5x^2+3x is f(x+h)-f(x)/h = h + 3[/tex], which is a line with a slope of 1 and a y-intercept of 3.

The function[tex]f(x)=5x^2+3x[/tex], when evaluated and simplified, is equal to [tex]f(x+h)-f(x)/h[/tex]. To calculate [tex]f(x+h)-f(x)/h[/tex], the first step is to subtract f(x) from f(x+h). This will leave us with the expression . After this, we can simplify the expression to [tex]h^2 + 3[/tex]h. Next, we divide this expression by h which will leave us with h + 3.

This means that our result is [tex]f(x+h)-f(x)/h = h + 3[/tex]. This can be visualized as a line on a graph with a slope of 1 and a y-intercept of 3. This means that as the value of x increases, the value of [tex]f(x+h)-f(x)/h[/tex]increases by 1 for every increase in x.

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Answer:

7

Step-by-step explanation:

(number of sides - 2) x 180 = sum of interior angles

(number of sides - 2) x 180 = 900

Reverse the formula.

900 / 180 = 5

5 + 2 = 7

Therefore, number of sides = 7

The centroid (C) of the upper half of the circle is, C = (x_c, y_c) = (-2a/3π, 4a/3π)

We can find the centroid of the upper half of the circle by using integration. Let's denote the upper half of the circle as a function of x:

y = f(x) = sqrt(a^2 - x^2)

To find the centroid (C) of this region, we need to find the coordinates (x_c, y_c) such that:

x_c = (1/A) × ∫(a, -a) x*f(x) dx

y_c = (1/A) × ∫(a, -a) [F(x) - f(x)] dx

where A is the area of the upper half of the circle and F(x) is the equation of the circle.

First, let's find A:

A = ∫(a, -a) f(x) dx

= (1/2) × ∫(a, -a) sqrt(a^2 - x^2) dx

= (1/2) × [a^2 × sin^(-1)(x/a) + x × sqrt(a^2 - x^2)]_a^(-a)

= (1/2) × [a^2 × π + 0 - (-a^2 × π) + 0]

= πa^2/2

Next, let's find x_c:

x_c = (1/A) × ∫(a, -a) x×f(x) dx

= (2/πa^2) × ∫(a, 0) x × sqrt(a^2 - x^2) dx

(Note: We only integrate from 0 to a because the function f(x) is symmetric about the y-axis)

Let u = a^2 - x^2

Then du/dx = -2x, and dx = -du/(2x)

So the integral becomes:

(2/πa^2) × ∫(0, a^2) [(a^2 - u) × sqrt(u)] × (-du/(2x))

= -(1/πa^2) × ∫(0, a^2) sqrt(u) du

= -(1/πa^2) × [(2/3) × u^(3/2)]_0^(a^2)

= -(2/3πa^2) × (a^3)

= -2a/3π

Therefore, x_c = -2a/3π.

Finally, let's find y_c:

y_c = (1/A) × ∫(a, -a) [F(x) - f(x)] dx

= (2/πa^2) × ∫(a, 0) (a^2 - x^2) dx

(Note: We only integrate from 0 to a because the function f(x) is symmetric about the y-axis)

= (2/πa^2) × [a^2x - (1/3)x^3]_0^a

= (2/πa^2) × [(2/3)a^3]

= 4a/3π

Therefore, y_c = 4a/3π.

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The equation expressing the visible area an of the sheet of paper in terms of the number of times it has been folded n is a = 93.5/2^n.

Every time a sheet of paper is folded in half, the visible area is reduced by half. If the original area of the sheet of paper is A, then after the first fold, the visible area is A/2. After the second fold, the visible area is (A/2)/2 = A/4. In general, after n folds, the visible area is A/[tex]2^n[/tex].

In this problem, the original area of the sheet of paper is given as 93.5 square inches. Therefore, the equation expressing the visible area a of the sheet of paper in terms of the number of times it has been folded n is a = 93.5/[tex]2^n[/tex]. As the number of folds increases, the visible area of the sheet of paper decreases rapidly, approaching zero as n approaches infinity.

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Answer:

0.765 km

Step-by-step explanation:

85*9=765 m

765/1000 to get km

0.765 km

Answer:

x or half the hypotenuse

Step-by-step explanation:

You can look up special triangles for more info:

Opposite 30 = x

Opposite 60 = x*(sqrt3)

Opposite 90 = 2x

Answer:

x= -12, 5

Step-by-step explanation:

im so sorry for the late response it has been a whirlwind for me with trying to graduate with school lately

zeros of a function is when f(x) is equal to zero

with the graph we can see that -12 and 5 are where f(x) is equal to zero so these are the zeros of the function

we can find this out with the equation too like this

first we find the square of the function by finding a factors of -60 that will also add to be 7

12 and -5 are 2 factors

(12)(-5)= -60

12+ -5=7

now we can use this to make 2 equations

(x+12)(x-5)=0

x+12=0

x= -12

x-5=0

x=5

I hope this helps and isn't too confusing

Answer: yes

Step-by-step explanation:

Answer:

119. Proofs attached to answer

Step-by-step explanation:

Proofs attached to answer

The inverse οf f(x) is y = -2 - √[(x + 5)/3]

Tο find the inverse οf a functiοn, we can swap the pοsitiοns οf x and y and sοlve fοr y.

Starting with f(x) = 3(x + 2)² - 5:

y = 3(x + 2)² - 5

Swap x and y:

x = 3(y + 2)² - 5

Sοlve fοr y:

x + 5 = 3(y + 2)²

(x + 5)/3 = (y + 2)²

±√[(x + 5)/3] = y + 2

y = ±√[(x + 5)/3] - 2

Since x ≤ -2, we can οnly use the negative square rοοt tο ensure that y is a functiοn. Therefοre, the inverse οf f(x) is y = -2 - √[(x + 5)/3]

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Quadratic function that has vertex in the third quadrant and has no x-intercept is f(x) = 2(x+3)² - 4.

Quadratic function is a polynomial function of the second degree of the form f(x)= ax² + bx + c where a is a non-zero coefficient and x is the variable. Vertex is the point on the parabola which has a minimum or maximum point. The third quadrant is where both the x and y coordinates are negative. The question requires finding a quadratic function with vertex in the third quadrant and has no x-intercept. Quadratic function with no x-intercept means that the graph does not cross the x-axis. Here is how to find such function: Step-by-step We can start by using the vertex form of a quadratic function. f(x) = a(x-h)² + k Where (h, k) is the vertex of the parabola. Since the vertex is in the third quadrant, h and k should be negative numbers.

Also, since the graph should not cross the x-axis, the leading coefficient (a) should be either positive or negative. If a>0, the parabola opens upwards, and if a<0, the parabola opens downwards. To find a quadratic function that has no x-intercept and has a vertex in the third quadrant, let's choose any negative value of h and k such that |k|>|h|, and a>0. For instance, let h=-3 and k=-4. Then, substituting these values in the vertex form, we get:f(x) = a(x+3)² - 4If we want the parabola to have a minimum point at the vertex, then a should be positive. We can choose any positive value of a. For example, let's take a=2. Then, the quadratic function with the required conditions is:f(x) = 2(x+3)² - 4f(x) = 2x² + 12x + 14The graph of this function has vertex (-3, -4) and does not cross the x-axis.  Quadratic function that has vertex in the third quadrant and has no x-intercept is f(x) = 2(x+3)² - 4.

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Therefοre, the sοlutiοn οf the given prοblem οf unitary methοd cοmes οut tο be the same respοnse: 3,840 pοssibilities exist.

The task can be cοmpleted by integrating what was learned and putting this variable technique intο practise, which alsο incοrpοrates all supplemental data frοm twο individuals whο used a specific tactic. Or, tο put it anοther way, if the desired expressiοn οutcοme happens, either the entity stated in the algοrithm will alsο be fοund, οr bοth essential prοcesses will actually bypass the cοlοur. Fοr fοrty pens, a refundable charge οf Rupees ($1.01) might be required.

Here,

⇒ [tex]$\mathrm{_n C_r=\frac{n !}{r ! (n-r) !}}[/tex]

where r is the number of chοices you select, and n is the total number of options in a category.

For instance, there are 5 οptions for bread, but you can only select 1 (since there are only 1 types of bread):

[tex]$\Rightarrow \ \mathrm{_5 C_1=\frac{5 !}{1 ! (5-1) !}}[/tex]

Similar to this, there are 6 οptions for beef, and you can only pick one:

[tex]$\Rightarrow \ \mathrm{_6 C_1=\frac{6 !}{1 ! (6-1) !}} = 6[/tex]

There are 4 options for cheese, and yοu only get to pick one:

[tex]$\Rightarrow \ \mathrm{_4 C_1=\frac{4 !}{1 ! (4-1) !}} = 4[/tex]

There are 3,840 possible sandwich cοmbos, which can be calculated using the formula

₅C₁ × ₆C₁ × ₄C₁ × 25

= 5 × 6 × 4 × 32

= 3,840

Either approach will result in the same respοnse: 3,840 possibilities exist.

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