Answer:
1. Tsunami
2.Divergent
3.Sensor
4.Convergent
5.Magnitude
Explanation:
Two ice-skaters are skating in circles on a frozen pond. Maria is making large circles with a radius of 12 m and skating 4.5 m/s. Her friend, Samantha, is making smaller circles with a radius of 6 m but is not skating as quickly, going only 3.8 m/s.
How could each skater increase her centripetal acceleration without changing the size of her path? Explain your reasoning.
Answer: Samantha has the largest centripetal acceleration of 2.4 m/s^2. Maria has only 1.69 m/s^2.
Explanation:
What do we call the potential mechanical energy stored in an object when work is performed to change its shape?
A.) elastic energy
B.) sound energy
C.) kinetic energy
What average net force is required to stop a 1950 kg car in 10.5 s if it’s initially traveling at 28m/s
Answer:
An average net force of 5200 N is needed to stop the car
Explanation:
Cinematics and Dynamics
Cinematics describes the variables involved in the movement without dealing with its causes. There are four main concepts in cinematics: Velocity (or its scalar equivalent, the speed), acceleration, time, and displacement (or the scalar equivalent, distance).
The acceleration can be calculated by:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
The initial speed is vo=28 m/s, it stops (vf=0) in t=10.5 seconds, thus the acceleration is:
[tex]\displaystyle a=\frac{0-28}{10.5}[/tex]
[tex]a = -2.67~m/s^2[/tex]
The acceleration is negative because the car loses speed.
Knowing the mass of the car m=1950 Kg, we can calculate the net force required to stop the car by using the formula:
F = m.a =1950*2.67
F = 5200 N
An average net force of 5200 N is needed to stop the car
Typically, a bullet leaves a standard 45-caliber pistol (5.0-in. barrel) at a speed of 262 m/s. If it takes
1 ms to traverse the barrel, determine the average acceleration experienced by the 16.2-3 bullet withim
the gun and then compute the average force exerted on it.
In its American colonies, Spain helped the Catholic Church meet its goal of
finding gold.
gaining territory.
converting people.
achieving glory.
This is from ed please help thank you
Answer: Converting people
Explanation: In Spanish colonies such as Florida, Spanish moved up into the other states to spread their christianity and were successful with doing so.
The temperature of a substance is 45 C. Convert this to Kelvin.
Answer:
it will be 318.5 Kelvin
Near the surface of Earth, what is the acceleration of an object due to the force of gravity? !!!!! Please answer !!!!!
Answer:
Weight. Recall that the acceleration of a free-falling object near Earth's surface is approximately g=9.80m/s2 g = 9.80 m/s 2 . The force causing this acceleration is called the weight of the object, and from Newton's second law, it has the value mg.
Explanation:
Which source of energy causes most of the water evaporation on Earth’s surface?
A.
wind
B.
solar
C.
gravity
D.
electrical
Answer:
I think it will be b. solar
Hope I can help.
Answer:
Explanation:
its b
What is meant by the components of a vector
Which type of energies make up the mechanical energy of a roller coaster moving along a track?
Answer:
gravitational potential energy and kinetic energy
Explanation:
What makes the yardstick test a direct measurement of reaction time?
A.
The further the yardstick falls, the slower the reaction time.
B.
Yardsticks have numerical markings for length.
C.
Yardsticks are designed to measure reaction time.
D.
all of the above
Please select the best answer from the choices provided.
A
B
C
D
Answer:
A. the further the yardsticks falls, the slower the reaction time.
Answer:
The further the yardstick falls, the slower the reaction time.
Explanation:
its A
HELP ASAP FAST PLEASE I NEED HELP
Mechanical energy is defined as
Question 1 options:
the energy of motion and position, which is represented by the formula KE + PE = ME
potential energy
Energy of motion
Energy of machines and tools
Answer:
energy of motion is represented by formula KE+PE=ME
Answer:
formula:
KE+PE=ME
Explanation:
HOPE IT HELPS!
thank me later
What year was the RoboSapien toy robot released?
a) 2007
b) 2004
c) 2020
d) dunno
option b )2004........
2. (1) A piece of rubber is 50 cm long when a weight of
35 N hangs from it and is 85 cm long when a weight
of 70 N hangs from it. What is the spring constant
of this piece of rubber?
Answer
By F = -kx {-ve just indicating the sign of the force}
=>35 = k x (85-50) x 10^-2
=>k = 100 N/m
Again by F = -kx
examples of uniform motion
Answer:
An airplane cruising at a level height and a steady speed.
A car going along a straight level road at steady speed.
A vibrating spring in a sewing machine.
A ship steaming on a straight course at steady speed.
A train going along the tracks at steady speed.
Explanation:
Hope this helps :)
Answer:
Examples of Uniform Motions.
The hr. ...
An airplane cruising at a level height and a steady speed.
A car going along a straight level road at steady speed.
A vibrating spring in a sewing machine.
A ship steaming on a straight course at steady speed.
A train going along the tracks at steady speed
When velocity is graphed with respect to time, what does the area under
the line represent?
A) velocity
B) distance
C) acceleration
D) displacement
Answer:
the answer is D
Explanation:
Since the velocity of the object is the derivative of the position graph, the area under the line in the velocity vs. time graph is the displacement of the object.
Matt is driving his car around a curve that has a radius of 40 m. If his speed is 25 m/s as he negotiates the curve, find the centripetal acceleration for the curve.
A- 13.9 m/s2
B- 24.6 m/s2
C- 15.6 m/s2
D- 7.25 m/s2
Answer:
[tex]\huge\boxed{\sf a_{c} = 15.6\ m/s^2}[/tex]
Explanation:
Given Data:
Radius = r = 40 m
Speed = v = 25 m/s
Required:
Centripetal Acceleration = [tex]\sf a_{c}[/tex] = ?
Formula:
[tex]\sf a_{c} = \frac{v^2 }{r}[/tex]
Solution:
[tex]\sf a_{c} = \frac{v^2}{r} \\\\a_{c} = \frac{(25)^2}{40} \\\\a_{c} = \frac{625}{40} \\\\a_{c} = 15.6 m/s^2\\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807What 2 factors affect the impulse on an object in a collision?
A large ball of Play-Doh with a mass of 0.04kg is launched from a catapult with an initial
speed of 5m/s and an
initial height of 1.0m. What is the final speed of the ball right before it strikes the ground? Draw a picture!
Answer:
≈ 6.68 m/s
Explanation:
A suitable formula is ...
vf^2 -vi^2 = 2ad
where vi and vf are the initial and final velocities, a is the acceleration, and d is the distance covered.
We note that if the initial launch direction is upward, the velocity of the ball when it comes back to its initial position is the same speed, but in the downward direction. Hence the problem is no different than if the ball were initially launched downward.
Then ...
vf = √(2ad +vi^2) = √(2·9.8 m/s^2·1.0 m+(5 m/s)^2) = √44.6 m/s
vf ≈ 6.68 m/s
The ball hits the ground with a speed of about 6.68 meters per second.
__
We assume the launch direction is either up or down.
what polarity must the red tip of the compass needle be since it points toward the south pole of the magnet?
Answer: positive
Explanation: because opposites attract and north=positive and south=negative the answer should be positive.
The polarity of the red tip of the compass needle must be at the north of the earth, since it points toward the south pole of the magnet.
What is meant by polarity of a magnet ?Polarity of a magnet is defined as the orientation of both the north and south poles of the magnet in space.
Here,
We know that, the opposite poles attract.
The magnetic needle is arranged in a such a way that, the red tip of the magnetic compass needle is actually pointing towards the geographic north pole of the earth.
In order to point the compass needle towards the magnetic south pole, the south pole of the magnet must be located in the geographic north pole.
Hence,
The polarity of the red tip of the compass needle must be at the north of the earth, since it points toward the south pole of the magnet.
To learn more about polarity of magnet, click:
https://brainly.com/question/15329793
#SPJ2
1. What is power, and what is its relationship to voltage and amperage? (4 points)
power is reffering to force
A stretched spring attached to two fixed points is compressed on one end and released, as shown. The resulting wave travels back and forth between the two fixed ends of the spring until it comes to a stop. This is an example of _____ .
a Transverse wave
b
longitudinal wave
c
surface wave
d
electromagnetic wave
Answer:
B. Longitudinal wave
Explanation:
It's the only option that makes sense. Hope this helped :)
As we know, the moon is a satellite of our earth, what is the
theoretical period of the moon? The average radius of the
moon's orbit is 3.84 108 m and the mass of the earth is 5.97 x
1024 kg (in hours, G = 6.67 x 10-9 N (m/kg) 3).
Answer:c
Explanation:c
This question involves the concepts of the time period, orbital radius, and gravitational constant.
The theoretical period of the moon is "658 hr".
The theoretical time period of the moon around the earth can be found using the following formula:
[tex]\frac{T^2}{R^3}=\frac{4\pi^2}{GM}[/tex]
where,
T = Time Period of Moon = ?
R = Orbital Radius = 3.84 x 10⁸ m
G = Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
M = Mass of Earth = 5.97 x 10²⁴ kg
Therefore,
[tex]\frac{T^2}{(3.84\ x\ 10^8\ m)^3}=\frac{4\pi^2}{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(5.97\ x\ 10^{24}\ kg)}\\\\T^2=(9.91\ x\ 10^{-14}\ s^2/m^3)(56.62\ x\ 10^{24}\ m^3)\\\\T=\sqrt{561.34\ x\ 10^{10}\ s^2}[/tex]
T = 2.37 x 10⁶ s[tex](\frac{1\ h}{3600\ s})[/tex]
T = 658 hr
Learn more about the orbital time period here:
https://brainly.com/question/14494804?referrer=searchResults
The attached picture shows the derivation of the formula for orbital speed.
Can someone help me in this please any one good in science.
Let's calculate the equivalent resistances on both circuits.
On Diagram A we have a series connection of the resistors. The equivalent resistance will be the sum of all resistances:
[tex]R_{eq}=1+1+1\\\\\boxed{R_{eq}=3\Omega}[/tex]
On diagram B we have a parallel connection of the resistors. The reciprocal of the equivalent resistance will be the sum of the reciprocals of all the resistances:
[tex]\frac{1}{R_{eq}} = \frac{1}{1} +\frac{1}{1} +\frac{1}{1} \\\frac{1}{R_{eq}}=3\\\\\boxed{R_{eq}=\frac{1}{3}}[/tex]
Therefore, the larger resistance occurs on diagram A.
For the current, recall
[tex]V=IR[/tex]
Where [tex]I[/tex] stands for current [tex]R[/tex] is the resistance and [tex]V[/tex] is the voltage. Rearranging the equation we have
[tex]I = \frac{V}{R}[/tex]
We can see that the larger the resistance, the smaller the current gets. So the larger current must happen in the diagram with smaller resistance. Therefore, the larger current occurs on diagram B.
Glad to help, wish you great studies ;)
Mark brainliest if you deem the answer worthy
A boy is exerting a force of 70 N at a 50-degree angle on a lawnmower. He is accelerating at 1.8 m/s2. Round the answers to the nearest whole number.
What is the mass of the lawnmower?
What is the normal force exerted on the lawnmower?
The lawnmower accelerates in the positive horizontal direction, so that the net horizontal force is, by Newton's second law,
(70 N) cos(-50°) = m (1.8 m/s²)
where m is the mass of the lawnmower. Solve for m :
m = ((70 N) cos(-50°)) / (1.8 m/s²)
m ≈ 25 kg
The lawnmower presumably doesn't get lifted off the ground, so that the net vertical force is 0. If n is the magnitude of the normal force, then by Newton's second law,
n - m g + (70 N) sin(-50°) = 0
n = m g + (70 N) sin(50°)
n = (25 kg) (9.8 m/s²) + (70 N) sin(50°)
n ≈ 300 N
A jet aircraft is traveling at 214 m/s in hor-
izontal flight. The engine takes in air at a
rate of 115 kg/s and burns fuel at a rate of
2.53 kg/s. The exhaust gases are ejected at
276 m/s relative to the aircraft.
Find the thrust of the jet engine.
Answer in units of N.
Answer:
The thrust is [tex]F = 7828.3 \ N [/tex]
Explanation:
From the question we are told that
The speed of the jet aircraft is [tex]v = 214 \ m/s[/tex]
The rate at which the engine takes in air is [tex]\^ Q = 115 \ kg/s[/tex]
The rate at which the engine burns fuel is [tex]\r m = 2.53 \ kg/s[/tex]
The speed of the exhaust gases is [tex]u = 276 \ m/s[/tex]
Generally the thrust of the engine is mathematically represented as
[tex]F =[ \^ Q * ( u - v )] + (\r m * u)[/tex]
=> [tex]F =[ 115 * ( 276 - 214 )] + (2.53 * 276)[/tex]
=> [tex]F = 7828.3 \ N [/tex]
PLEASE HELP ME IM TIMED
A car traveling at 50 m/s comes to a stop in 5 seconds. What is the
acceleration of this?
Answer:
10
Explanation:
10 is the answer because you divide 50 and 5 and your answer is 10.
Hope this helps:)
Pls mark brainlist
Answer:
a = -10m/s²
Explanation:
Givens:
Vf = 0m/s
Vi = 50m/s
t = 5s
Use the following kinematic equation:
Vf = Vi+at
Rearrange
a = (Vf-Vi)/t
a = -10m/s²
Which of the following is true about particles of matter?
Answer:
Matter is a substance which has mass and takes up space by volume the properties of matter are,
States of matter (solid,liquid,gas)are inter convertable.
Force of attraction varies from one kind of matter to another.
States of matter can be varied by varying temperature and pressure.
Explanation:
Rodney hits a 0.060 kg tennis ball straight up with a speed of 15 m/s from a height of 2.2 m above the ground. How fast is the ball going when it is 9.5 m above the ground?
Answer:
Explanation:
From the question we are told that
The mass of the tennis ball is [tex]m = 0.060 \ kg[/tex]
The speed is [tex]u = 15 \ m/s[/tex]
The initial height of the ball is [tex]h_o = 2.2 \ m[/tex]
The height considered is [tex]h = 9.5 \ m[/tex]
Generally the time taken to reach the considered height is mathematically evaluated from the equation of motion as follows
[tex]h = h_o + ut - \frac{1}{2} gt^2[/tex]
=> [tex]9.5 = 2.2 + 15t - \frac{1}{2} * 9.8 t^2[/tex]
=> [tex]7.3 = 15t - 4.9t^2[/tex]
=> [tex]4.9t^2 -15t + 7.3[/tex]
solving the above equation using quadratic formula
[tex]t= 0.6070 \ s[/tex] and [tex]t_1 = 2.454 \ s[/tex]
Generally from kinematic equation we have that
[tex]v = u - gt[/tex]
=> [tex]v= 15 - 9.8 * 0.6070[/tex]
=> [tex]v= 9.0514 \ m/s[/tex]
Note if we had used the second values of time the velocity at 9.5 \ m would have been negative which is not correct given that at maximum height velocity is zero