WILL GIVE BRAINLIEST PLS HELP

Design a repeatable experiment using various seismograph stations around the
globe to verify the hypothesis that the Earth has a liquid outer core and a solid
inner core. Describe how you would set up the experiment, what equipment would
be needed, and what information you would gather. What evidence would prove
that the outer core is liquid? What evidence would prove that the inner core is not
liquid? How would you use repeatability to show whether the hypothesis is valid or
not?

Answer:

Explanation:

The rate of heat transfer from the transistor to the heat sink through the mica sheet can be calculated using Fourier’s Law of heat conduction. The formula for this law is Q = kA(T1 - T2)/d where Q is the rate of heat transfer, k is the thermal conductivity of the material, A is the cross-sectional area through which heat is transferred, T1 and T2 are the temperatures at either end of the material and d is its thickness.

In this case, we know that Q = 1.00 W (the rate at which energy enters the device), k = 0.0753 W/m·°C (the thermal conductivity of mica), A = 8.25 mm * 6.25 mm = 5.15625e-5 m² (the cross-sectional area of the mica sheet), T2 = 35°C (the temperature of the heat sink) and d = 0.0852 mm = 8.52e-5 m (the thickness of the mica sheet).

Substituting these values into Fourier’s Law gives us:

1.00 W = (0.0753 W/m·°C)(5.15625e-5 m²)(T1 - 35°C)/(8.52e-5 m)

Solving for T1 gives us:

T1 ≈ 35 + (1 / ((0.0753 * 5.15625e-5) / 8.52e-5)) ≈ 35 + 22 ≈ 57°C

So under steady-state conditions with an energy input rate of 1 W and a heat sink temperature of 35°C, we can expect that the operating temperature of this power transistor would be approximately 57°C.

Planck's frequency (h) and indeed the light's velocity (c) are used to connect a photon's energy (E) to its wavelength (), frequency (v), and wavelength. E = hν = hc/λ.

We frequently use the word "energy" in our everyday speech. Energy has an unique physical meaning even if the term is frequently used figuratively. Energy is defined in physics as something's capacity to perform work. Many types of energy are possible. All energy is kinetic in some way.

Energy is present everywhere and comes in a variety of shapes and sizes. Objects at rest have potential energy that, if released, will cause them to move. All moving things contain kinetic energy.

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Answer:

35J

Explanation:

The mass of the ball=2.5kg

The initial speed=10m/s

we have to calculate the height= h

s=ut+1/2at^2

h=10*0.2 -1/2*10*0.04

h=2-0.2

h= 1.8m

the potential energy= mgh

                                 = 2.5kg*10*1.8

                                = 25*1.8

                                 = 35J

P = [M1 L1 T-2] × [L2]-1 = M1 L-1 T -2. Therefore, the pressure is dimensionally represented as M1 L-1 T -2.

Hence, R = 28.97 m, 24.5 degrees is the vector sum of T and U.

A vector's direction is frequently stated as a rotation of the vector's "tail" anticlockwise with respect to due East. In accordance with this practise, a vector having a direction of 30 degrees is a vector that has been anticlockwise rotated 30 degrees with respect to due east.

Let's begin by separating the components of the vector T:

T~ = 40 m, 30 degrees

T_x = 40 cos(30) = 34.64 m

T_y = 40 sin(30) = 20 m

Let's now decompose the vector U into its constituent parts:

U~ = 12 m, 225 degrees

U_x = 12 cos(225) = -8.49 m

U_y = 12 sin(225) = -8.49 m

It is possible to combine elements of the same type (x and y):

R_x = T_x + U_x = 34.64 m - 8.49 m = 26.15 m

R_y = T_y + U_y = 20 m - 8.49 m = 11.51 m

The Pythagorean theorem can be used to determine the size of the resulting vector R:

|R~| = sqrt(R_x² + R_y²) = sqrt((26.15 m)² + (11.51 m)²) = 28.97 m

The inverse tangent function can be used to determine the direction of the resulting vector R:

theta = tan⁻¹(R_y/R_x) = tan⁻¹(11.51 m/26.15 m) = 24.5 degree.

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Answer: false

Explanation:

A typical 16-line poem that described centripetal force can be found below.

In circular motion, a force we call,

Centripetal, it keeps things in thrall.

Directed towards the center of the path,

Without it, objects would face a wrath.

Angular velocity is key,

The rate of change of the angle we see.

And the radius of the circle too,

Both play a role in what we must do.

The mass of the object cannot be ignored,

It factors in with gravity's cord.

As the force pulls towards the center,

Centripetal force is what we enter.

It is the sum of all the forces in play,

Equal to mass times velocity squared, we say.

And if the force is too weak or too strong,

Off the circular path, the object goes wrong.

Thus, centripetal force is what we need,

To keep objects moving at the speed,

In a circular path, they're meant to be,

A force that keeps them in harmony.

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The pair of cities moving apart because of plate motion is London and Boston.

London and Boston are moving apart due to the motion of tectonic plates. The Earth's lithosphere is divided into several large plates that are in constant motion due to the underlying mantle convection. The movement of these plates is driven by the forces generated by the mantle convection, which causes the plates to move away from each other, move towards each other, or move sideways past each other.

London and Boston are located on separate tectonic plates that are moving away from each other. London is located on the Eurasian Plate, while Boston is located on the North American Plate.

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The magnitude οf A + B is 1.95 m and its directiοn is 31.3° clοckwise frοm the pοsitive x-axis when the displacement vectοrs A and B is shοwn in the figure belοw bοth have magnitudes οf 1.95 m. The directiοn οf vectοr A is = 29.0°.

Tο determine the magnitude and directiοn οf A + B, we can measure the length οf the resulting vectοr and the angle it makes with the pοsitive x-axis, respectively.

Alternatively, we can use trigοnοmetry tο find the cοmpοnents οf vectοrs A and B and then add them up tο find the cοmpοnents οf A + B. Then, we can use inverse trigοnοmetric functiοns tο find the magnitude and directiοn οf the resulting vectοr.

Let's use the secοnd methοd tο sοlve this prοblem.

We are given that the magnitudes οf vectοrs A and B are 1.95 m each. The directiοn οf vectοr A is 29.0° cοunterclοckwise frοm the pοsitive x-axis. Let's call the angle between vectοr B and the pοsitive x-axis θ.

Using trigοnοmetry, we can find the x and y cοmpοnents οf vectοrs A and B as fοllοws:

Ax = 1.95 cοs 29.0° = 1.695 m

Ay = 1.95 sin 29.0° = 0.939 m

Bx = 1.95 cοs θ

By = 1.95 sin θ

Tο find θ, we need tο use the fact that the magnitude οf vectοr A + B is alsο 1.95 m. This means that:

[tex](Ax + Bx)^2 + (Ay + By)^2 = (1.95)^2[/tex]

Substituting the values of Ax and Ay, we get:

(1.695 + 1.95 cos θ)² + (0.939 + 1.95 sin θ)² = (1.95)²

Simplifying and solving for cos θ and sin θ, we get:

cos θ = -0.359

sin θ = -1.695

Since sin θ is negative, we know that vector B is pointing downwards.

Now, we can use inverse trigonometric functions to find the magnitude and direction of vector A + B:

[tex]|A + B| = sqrt((Ax + Bx)^2 + (Ay + By)^2) = 1.95 m[/tex]

θ = atan2(Ay + By, Ax + Bx) = atan2(-0.756, 1.336) = -31.3°

Therefore, the magnitude of A + B is 1.95 m and its direction is 31.3° clockwise from the positive x-axis.

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Answer: Applying a weight limit to a road is often done in an attempt to protect a roadway's appearance in particular. It also aims to protect the character and environment of rural areas, villages, and residential estates. Restricting overweight freights may just prevent damages like pot holes and cracks in the road.

Explanation:

I HOPE THIS HELPED GOOD LUCK AND I AM OPEN FOR FREE ANSWERS!

The tire rotates at a rate of 223.7 rpm, while the frequency  layer of a tire is moving at a rate of 24.0 m/s plus 7.50 m/s, or 31.5 m/s. 24.0 m/s - 7.50 m/s = 16.5 m/s is the speed of a spot on the tire's bottom edge.

Frequency refers to the quantity of waves passing a defined location in a predetermined period of time. As a result, the rate is 2 per second if a wave passes through in 1/2 of a second. In this case, the rate is 100 times per hour if it takes 1/10 of an hour.

The quantity of observations that take place during a specific predetermined timeframe is the frequency of such a class interval. So, the frequency for such 5–9 age range is 20 if, for instance, 20 individuals between the ages of 5 and 9 exist in the study's data.

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Kirchhoff's current law is applied in nodal analysis. There will be 'n-1' simultaneous equations to solve when there are 'n' nodes in a given electrical circuit. 'n-1' must be solved in order to retrieve all of the node voltages.

Hence, we can solve for V1 and V2:

V1=Vi(R2+R3−k)k(1−nR3)−R2−R3.

V2=Vi(k−R2−R3(1+nR2))k(nR3−1)+R2+R3.

Nodal analysis is a fundamental approach used to investigate voltage and current distribution in a circuit and is one of the simulations included in SPICE simulators. This method successfully integrates Kirchhoff's and Ohm's laws into a single matrix equation.

The distinction between mesh and nodal analysis is that nodal analysis uses Kirchhoff's current law to calculate the voltages at each node in an equation. Mesh analysis, on the other hand, is an application of Kirchhoff's voltage law, which is used to calculate current.

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37. Segment B of the graph corresponds to the only solid state. ,38. Segment E of the graph corresponds to the melting point. and all answer given below:

Segment is a customer data platform (CDP) that enables businesses to collect, store, and analyze customer data from multiple sources. It allows companies to unify their customer data into one place, which can then be used to create more personalized customer experiences. With Segment, businesses can create custom segments of their customers and create targeted campaigns to meet their specific needs.

39. The melting point (temperature) is 300°C.

40. Segment F of the graph corresponds to the only liquid state.

41. Segment A of the graph corresponds to the only gas state.

42. Segment D of the graph corresponds to the boiling point.

43. No, the temperature decreases during freezing.

44. Segment C of the graph corresponds to the freezing point.

45. The boiling point (temperature) is 450°C.

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The force per unit length of Y would be 1.25 * [tex]10^{-3[/tex] N/m.

The force per unit length between two parallel wires carrying currents can be calculated using the equation:

F = μ0 * I1 * I2 * L / (2 * π * d)

where:

Substituting the given values, we get:

F_X = μ0 * 3A * 5A * L / (2 * π * d) = 5 * 10^-5 N

Solving for F_Y, we get:

F_Y = 2 * F_X * π * d / (μ0 * 5A * L)

= 2 * (5 * 10^-5 N) * π * d / (4π * 10^-7 T·m/A * 5A * L)

= 1.25 * [tex]10^{-3[/tex] N/m

Therefore, the force per unit length experienced by wire Y is 1.25 * 10^-3 N/m.

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The gravitational potential energy of the two climbers would be 26,460 J.

The gravitational potential energy (PE) of an object is given by the formula:

PE = mgh

where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above some reference point.

In this case, the combined mass of the two climbers is 150 kg, and they are 18 m above the ground. Using g = 9.8 m/s², we can calculate their gravitational potential energy as:

PE = (150 kg) x (9.8 m/s²) x (18 m) = 26,460 J

Rounded to the nearest thousand, the gravitational potential energy of the two climbers is 26,000 J.

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The magnitude of the normal force of the car is given by Fn = Fg cotθ.

The normal force is the force exerted by the racetrack perpendicular to the car's motion. Let's now derive the expression for the magnitude of the normal force of the car:

The perpendicular component of the normal force is given by:

Fn⊥ = Fg cosθ

The parallel component of the normal force provides the centripetal force required for circular motion.

The centripetal force (Fc) is given by:

Fc = mv²/r

where;

The centripetal force can also be expressed in terms of the parallel component of the normal force:

Fc = Fn∥ = Fn sinθ

Equating the two expressions for Fc, we get:

Fn sinθ = mv²/r

Solving for Fn, we get:

Fn = mv²/(r sinθ)

Substituting the expression for Fg cosθ, we get:

Fn = Fg cosθ / sinθ

or

Fn = Fg cotθ

where;

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The complete question is below:

Circular turns of radius r in a racetrack are often banked at an angle θ to allow the cars to achieve higher speeds around the turns. Assume friction is not present.

Now write the magnitude of the normal force of the car, in terms of the gravitational force Fg, g, θ, the radius of the track r, and the velocity that the car is traveling v.

Answer:

The force acting on the train due to the air resistance is given by the formula:

F = (1/2) * p * A * v^2 * Cd

where p is the density of air, A is the cross-sectional area of the train, v is the speed of the train, and Cd is the drag coefficient.

We can assume that the drag coefficient is constant for a given shape of the train, and we can take it to be 0.5 for a train moving through air.

The pressure difference between the front and back of the train is given by:

P = (1/2) * p * v^2

The pressure difference between the sides of the train and the tunnel walls is given by:

2 * P = 2 * (1/2) * p * v^2 = p * v^2

The force acting on the train due to this pressure difference is given by:

F' = 2 * P * S = 2 * p * v^2 * S

The net force acting on the train is given by:

Fnet = F - F' = (1/2) * p * A * v^2 * Cd - 2 * p * v^2 * S

We can simplify this expression by factoring out p * v^2:

Fnet = p * v^2 * [(1/2) * A * Cd - 2 * S]

We are given that So = 4St, so we can substitute A = St and S = St/4:

Fnet = p * v^2 * [(1/2) * St * Cd - 1/2 * St * Cd] = 0

Therefore, the net force acting on the train is zero. This means that the force due to air resistance is exactly balanced by the force due to the pressure difference between the sides of the train and the tunnel walls.

We are given that Po - P = 2 * Pu, so we can substitute P = (1/2) * Po - Pu:

F' = 2 * P * S = 2 * [(1/2) * Po - Pu] * S = (Po - Pu) * 4 * St

We can equate this expression for F' to the expression for air resistance force:

F' = p * v^2 * [(1/2) * St * Cd - 2 * St/4] = p * v^2 * [(1/2) * St * Cd - St/2]

Equating these two expressions, we get:

(Po - Pu) * 4 * St = p * v^2 * [(1/2) * St * Cd - St/2]

Simplifying and solving for Pu, we get:

Pu = Po - (p * v^2 * Cd) / 8

We are given that Cd = 2N, so we can substitute this value:

Pu = Po - (p * v^2 * 2N) / 8

Pu = Po - (p * v^2 * N) / 4

Therefore, the pressure inside the train is Po - (p * v^2 * N) / 4.

Answer:

if the temperature of the sink is lowered by 6.7%, the efficiency of the Carnot engine will increase by 10%.

Explanation:

The efficiency of a Carnot engine is given by the equation:

η = 1 - T_sink / T_source

where η is the efficiency, T_sink is the temperature of the sink, and T_source is the temperature of the source.

In this case, we are given that the efficiency of the engine is 40%. Therefore, we can write:

0.4 = 1 - T_sink / T_source

Rearranging this equation, we get:

T_sink / T_source = 1 - 0.4

T_sink / T_source = 0.6

Next, we are asked to find the temperature of the sink needed to increase the efficiency of the engine by 10%. Let's call this new efficiency η_new. Since the efficiency of a Carnot engine is given by the same equation as before, we can write:

η_new = 1 - T_sink_new / T_source

where η_new is the new efficiency, and T_sink_new is the new temperature of the sink.

We know that the new efficiency is 10% higher than the original efficiency, so we can write:

η_new = η + 0.1η = 0.4 + 0.1(0.4) = 0.44

Substituting this into the equation above, we get:

0.44 = 1 - T_sink_new / T_source

Rearranging this equation, we get:

T_sink_new / T_source = 1 - 0.44

T_sink_new / T_source = 0.56

Now we can set up an equation to find the new temperature of the sink:

0.56 = T_sink_new / T_source

T_sink_new = 0.56T_source

To find the temperature difference between the old and new sink temperatures, we can subtract the two equations we have derived:

T_sink_new - T_sink = 0.6T_source - 0.56T_source

T_sink_new - T_sink = 0.04T_source

Finally, we can substitute the given efficiency of 40% to find the source temperature:

0.4 = 1 - T_sink / T_source

T_source = T_sink / (1 - 0.4)

T_source = T_sink / 0.6

Substituting this expression for T_source into the equation for the temperature difference, we get:

T_sink_new - T_sink = 0.04(T_sink / 0.6)

Simplifying, we get:

T_sink_new - T_sink = 0.067T_sink

Multiplying both sides by 100, we get:

(T_sink_new - T_sink) * 100 = 6.7T_sink

Therefore, if the temperature of the sink is lowered by 6.7%, the efficiency of the Carnot engine will increase by 10%.

Answer: (0.17 * 6) + ( 0.16 * 0 ) = (0.17 * 0) + ( 0.16 *  v2)

v2 = 6.375 m/s

Explanation:

The answer is v2 = 6.375 m/s

(I did the equation and everything but just in case, check with someone else so you don't get the wrong answer)

Answer

explanation

requirments

Answer:

last choice

Explanation:

With a single fixed pulley, you pull down (working with the force of gravity) to lift the load up.

Maria is taking the Rorschach inkblot test.

The test is designed to assess an individual's personality traits and psychological functioning based on their responses to the images.

The Rorschach inkblot test, which  uses a set of inkblot images and asks participants to describe what they see. The Rorschach test is a projective test that is often used to assess an individual's personality, emotional functioning, and thought processes.

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While submerged in water (n = 1.33) for two convex lenses, the focal lengths of Lens 1 is 19.67 cm and Lens 2 is 18.9 cm.

Lens is a transparent device that is used to focus or redirect light, allowing it to be magnified, focused, or projected onto a surface. It is made of a curved, transparent material like glass, plastic, or crystal. Lenses are commonly used in eyeglasses, cameras, microscopes, and other optical devices. They can be used to magnify, reduce, or otherwise change the direction of light in order to produce a desired effect. They are also used in other applications such as laser cutting and welding, as well as medical imaging and laser treatments.

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Answer:

(a) The thrust of the rocket can be found using the formula:

Thrust = (mass flow rate) x (exhaust velocity)

The mass flow rate is the rate at which mass is expelled from the rocket, which is equal to the burn rate times the mass fraction of fuel:

mass flow rate = burn rate x (mass of rocket) x (mass fraction of fuel)

mass flow rate = 200 kg/s x 20,000 kg x 0.8

mass flow rate = 32,000 kg/s

The exhaust velocity is given as 1.80 km/s. Therefore, the thrust of the rocket is:

Thrust = 32,000 kg/s x 1.80 km/s

Thrust = 57,600 kN

(b) The time it takes to exhaust the fuel can be found using the formula:

time = (mass of fuel) / (burn rate)

The mass of fuel is 80% of the initial mass of the rocket:

mass of fuel = 0.8 x 20,000 kg

mass of fuel = 16,000 kg

Therefore, the time it takes to exhaust the fuel is:

time = 16,000 kg / 200 kg/s

time = 80 seconds

(c) The rocket's speed at the end of its engine burn can be found using the rocket equation:

Δv = (exhaust velocity) x ln[(initial mass) / (final mass)]

The final mass is the mass of the rocket after it has burned all of its fuel, which is:

final mass = (mass of rocket) - (mass of fuel)

final mass = 20,000 kg - 16,000 kg

final mass = 4,000 kg

The initial mass is 20,000 kg. Therefore, the change in velocity is:

Δv = 1.80 km/s x ln[(20,000 kg) / (4,000 kg)]

Δv = 1.80 km/s x ln(5)

Δv = 3.89 km/s

Since the rocket was initially at rest, its final speed is equal to the change in velocity:

final speed = 3.89 km/s

Therefore, the rocket's speed at the end of its engine burn is 3.89 km/s.

The explanation of each of their observations can be found below.

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To derive the equation for the buoyant force, we can start with the equation for the pressure from a fluid at a certain depth:

P = ρgh + Patm

where P is the pressure at a depth h, ρ is the density of the fluid, g is the acceleration due to gravity, and Patm is the atmospheric pressure at the surface of the fluid.

Now, let's consider a simple submerged object, such as a perfect cube with sides of length s, as the hint suggests. The object is fully submerged in the fluid, so it experiences a pressure difference between the top and bottom surfaces. The pressure at the top surface of the object is Ptop = ρghtop + Patm, where htop is the depth of the top surface below the surface of the fluid. The pressure at the bottom surface of the object is Pbottom = ρghbottom + Patm, where hbottom is the depth of the bottom surface below the surface of the fluid. Since the object is at rest in the fluid, the net force acting on the object must be zero. Therefore, the buoyant force must be equal and opposite to the weight of the object:

Buoyant force = Weight of object

The weight of the object is given by its mass multiplied by the acceleration due to gravity:

Weight of object = mg

where m is the mass of the object and g is the acceleration due to gravity.

To find the buoyant force, we need to find the difference between the pressure at the top and bottom surfaces of the object, and then multiply that difference by the surface area of the object:

Buoyant force = Pressure difference × Surface area

The pressure difference is given by:

Pressure difference = Pbottom - Ptop

= (ρghbottom + Patm) - (ρghtop + Patm)

= ρg(hbottom - htop)

Therefore, the buoyant force is:

Buoyant force = ρg(hbottom - htop) × Surface area

For a perfect cube with sides of length s, the surface area is given by A = 6s^2. Therefore, the buoyant force on the cube is:

Buoyant force = ρg(hbottom - htop) × 6s^2

This is the equation for the buoyant force on a submerged object, derived from the equation for the pressure from a fluid at a certain depth and the concept of the buoyant force being due to the pressure difference between the top and bottom of an object.

Answer:

Metals, nonmetals, and metalloids are three different categories for the elements. Metals may be hammered into sheets and are malleable, ductile, and excellent conductors of heat and electricity (they can be drawn into wire).

Explanation:

Brainliest pls

Answer:

A. Non-metals, metals, metalloids

Explanation:

metals are Group I, II and III and IV

Non metals are Group VII, VI and VIII

To accurately measure the distance traveled by the fire ants, we could use a measuring tape or a GPS device. For short distances, a measuring tape would suffice, while for longer distances, a GPS device would provide more accurate measurements.

How to investigate the distance traveled by fire ants to collect resources?

To investigate the distance traveled by fire ants to collect resources, we could follow the following plan:

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