the Army had a fight in unfamiliar territory but with the combination of disadvantages and a loss of public support what to the United States withdrawing from Vietnam
Explanation:
I hope this helps
If an electron is released at the equator and falls toward earth under the influence of gravity, the magnetic force on the electron will be toward the
0. 85 kg of lead, specific heat 128 J/kgC, is heated from 50 C to 95 C. How much heat energy did the sample absorb?
Why was the light peppered moth able to flourish prior to the Industrial Revolution?
O by blending in with the trees
o the ability to fly
O an abundance of food
O fewer predators
Answer:
B. by blending in with the trees
Answer:
B. by blending in with the trees
Explanation:
A metal spoon was placed in a dish of ice cream and became cool. Which correctly describes the heat transfer process that resulted in the cooling of the spoon?.
Answer:
The heat went from the i cream to the spoon making it cool.
Explanation:
i just know.
A 20 Ohm resistance is connected
across the secondary winding of a
single-phase power transformer
whose secondary voltage is 150 V.
Calculate the primary voltage if the
supply current is 5 A, neglecting
losses.
Answer: 225 V
Explanation:
Given:
Secondary voltage,V2 = 150v
Resistance is connected across secondary winding,∴R2 = 20Ω
Supply current, ie, I1 = 5A
[tex]\text{Now, secondary current,} \ $I_{2}=\frac{V_{2}}{R_{2}}=\frac{150}{20}=7.5$$$\therefore I_{2}=7.5 \mathrm{~A}$$For Transformers, we have $\frac{N_{2}}{N_{1}}=\frac{V_{2}}{V_{1}}=\frac{I_{1}}{I_{2}}$ so, Taking $\frac{N_{2}}{N_{1}}=\frac{l_{1}}{l_{2}}$ inserting all given \& obtained values, we get $\frac{N_{2}}{N_{1}}=\frac{5}{7.5}$$$\therefore \text { Turns ratio }=\frac{N_{1}}{N_{2}}=\frac{7.5}{5}=\frac{3}{2}=3: 2$$[/tex]
[tex]\text{Again taking,}\frac{N_{1}}{N_{2}}=\frac{V_{2}}{V_{1}}$ \\So, \\$V_{1}=\frac{N_{1}}{N_{2}} V_{2}\\$ inserting all values, we get, $V_{1}=\frac{7.5}{5} * 150=225$\\Therefore, \fbox{Primary voltage, {$V_{1}=225 \mathrm{~V}$}}[/tex]
Derive an expression for the block's centripetal acceleration ac in terms of m , θ , and physical constants, as appropriate
The expression for the block's centripetal acceleration is derived as ω²r or v²/r.
What is centripetal acceleration?The centripetal acceleration of an object is the inward or radial acceleration of an object moving in a circular path.
The expression for the block's centripetal acceleration is derived as follows;
ω = dθ/dt
where;
ω is the angular speed θ is the angular displacementt is the time of motionac = ω²r
where;
r is the radius of the circular pathAlso, ω = v/r
ac = (v/r)²r
ac = v²/r
Thus, the expression for the block's centripetal acceleration is derived as ω²r or v²/r.
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In most cultures, the difference between the majority viewpoint and the minority viewpoint is that the majority group is made to feel __________ and the minority group is made to feel __________. A. Divergent. . . Normal B. Equal. . . Superior C. Superior. . . Equal D. Normal. . . Divergent Please select the best answer from the choices provided A B C D.
The difference between the majority viewpoint and the minority view is that the majority group is made to feel normal and the minority group is made to feel divergent.
What is the viewpoint?A vantage point or point of view from which something is viewed or assessed is known as the viewpoint The story is narrated from a variety of perspectives, including two major ones and several smaller ones.
Most studies comparing majority versus minority influence argue the author, places a premium on influence in the sense of prevailing. In this context.
There is evidence that majorities have greater public influence than minorities, and that minority impact when it happens, is mostly latent. In the current version,
Hence the difference between the majority viewpoint and the minority view is that the majority group is made to feel normal and the minority group is made to feel divergent.
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Answer: D
Explanation:
Simplified for you.
If you have 10 ounces of meat, what percentage of the calories comes from fat if the meat is 90% lean?
Answer:
There are 602 calories in 10 ounces of Ground Beef (85% Lean / 15% Fat). serving sizes of Ground Beef
Explanation:
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what is the medium for an ocean wave? Provide evidence that the medium is not transferred when a water wave moves on a lake
The medium for an ocean wave is the ocean water which involves movement on the water body.
What is a Medium?This is defined as a substance or material that carries the wave. In the case of ocean waves, the medium is referred to the ocean water.
The medium is not transferred when a water wave moves on a lake as energy is transported but the water molecules aren't which is why lakes have water present in them.
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How does energy affecf a wave?
An aircraft is in a steady climb, at an airspeed of 100 knots, and the flight path makes a positive 10 degree angle with the horizontal. Find the Rate of Climb.
The rate of climb of the aircraft in a steady climb making a 10 degree angle with the horizontal is : 17.36 knots
Given data
Airspeed = 100 knots
Angle with the horizontal ( ∅ ) = 10°
Determine the rate of climb of the aircraftwe will apply the formula below
Vy ( rate of climb ) = Airspeed * sin ∅
= 100 * sin ( 10 )
= 17.36 Knots
Hence we can conclude that rate of climb of the aircraft in a steady climb is : 17.36 knots.
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The Earth's biosphere is consists of
A(only the water on Earth that is in its solid form.
B(all of the Earth's water, including surface water, groundwater, snowcover, ice, and water in the atmosphere.
C(the part of the earth and its atmosphere in which living organisms exist or that is capable of supporting life.
D(the solid part of the earth consisting of the crust and outer mantle.
Answer:
The part of the earth and its atmosphere in which living organisms exist or that is capable of supporting life.
Explanation:
It’s in the definition of biosphere. “Bio” means “life,” so “biosphere” is that portion of the Earth capable of supporting life.
1. The Particle Theory of Matter says that. A. Particles are in constant motion
b. Everything is made up of particles
c. Plasmas have charged particles
d. Solids have no particles
Answer:
a. Particles are in constant motion.
When charging objects by induction which of the following must be true
A. A path to ground is not needed when using a positive source
B. The objects being charged must be conductors
C. The objects takes on the same charge as it's source
D. The source loses some of its charge
Answer:
C
Explanation:
because that's how science works
The change in momentum that occurs when a 1. 0 kg ball traveling at 4. 0 m/s strikes a wall and bounces back at 2. 0 m/s is.
Answer:
The change is momentum is given by ∆p=p(inital) - p(final) =4-2=2 kg.m/s
Explanation:
momentum is the product of mass and velocity (speed)
So it's initial momentum would be:
p=mv=(1)(4)=4 kg.m/s
It's final momentum is given by:
p=mv=(1)(2)=2 kg.m/s
The particles that make up matter are ______, ions or molecules.
Answer:
Atoms.
Explanation:
Atoms are purely one bit of an element. Ions are positive or negative atoms. Molecules are not pure, they have other stuff with it.
The free-body diagram below represents all the forces acting on an object. What is the net force acting on this object?
300 N right
100 N down
0 N up
200 N right
Answer:
200 N to the right
Explanation:
The 50 N forces cancel each other since they are opposing each other.For ____________, the error is calculated by finding the sum of squared distance between actual and predicted values
Answer: It is minimising
For minimizing, the error is calculated by finding the sum of the squared distance between actual and predicted values.
What is the error?The difference between the measured and analysis of the financial statements might well be defined as an error. For instance, if the two operators use the same complete and precise tool.
We have:
For ____________, the error is calculated by finding the sum of the squared distance between actual and predicted values
The correct answer is minimizing because according to the information provided in the problem. The sum of squared distance between actual and anticipated values is calculated to "minimize" the mistake.
This is one of the most significant aspects of statistics, and it involves mathematical computations involving error calculations for various values.
Thus, for minimizing, the error is calculated by finding the sum of the squared distance between actual and predicted values.
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Two planets are orbiting a star in a distant galaxy the first has a semimajor axis of 150 x 10^6 km an eccentricity of 0. 20 and a period of 1. 0 earth years
For two planets orbiting a star in a distant galaxy, having the first semimajor axis of 150 x 10^6 km, the period of the second plane is mathematically given as
T=2.2earth year
What is the period of the second planet?Generally, the equation for the time period is mathematically given as
[tex]T^{2} \appox a^{3}[/tex]
Therefore, for planet one
[tex]1^2\approx (150 x 10^6)^3[/tex]
In conclusion, For planet 2
T^2=(250/150)^3
T=√4.632
T=2.2earth year
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The period of the second planet for two planets circling a star in a faraway galaxy with a first semimajor axis of 150× 10⁶ km. The time period of the planet will be 2.2 earth years.
What is the time period of the revolution?The time period of the revolution is the time required to complete one revolution. It is guven by T. It is measured in seconds.
The equation of the time period is found as;
[tex]\rm T = \frac{250}{150} ^3 \\\\ T= \sqrt{4.632} \\\\ T=2.2 \ earth \ year[/tex]
Hence the time period of the planet will be 2.2 earth years.
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What type of charge is acquired when a rubber is rubbed with a fur
Answer:
The triboelectic charging process (a.k.a., charging by friction) results in a transfer of electrons between the two objects that are rubbed together. Rubber has a much greater attraction for electrons than animal fur.
Explanation:
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Tuning a piano to tune middle c on a piano, a tuner hits the key and at the same time sounds a 261 hz tuning fork. if the turner hears 3 beats per second, what are the possible frequencies of the piano key?
This question deals with the physics of resonance and sound. The possible frequency of the pano key is 258hz.
How to compute the variation in frequencyThe beat of a frequency is the difference (an absolute value) in the frequencies produced by the two waves.
Beat per second equals |f1 - f2| Where
ft = Frequency of the Tunning fork and
fp= Frequency of the Piano Key
Hence
3 = 261 - fp
Solving for fp,
fp = 261-3
= 258hz
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A thundercloud has an electric charge of 48.8 C near the top of the cloud and –41.7 C near the bottom of the cloud. The magnitude of the electric force between these two charges is 7980000 N. What is the average separation between these charges
a/ 1.51 km
b/ 2.53 Km
c/ 1.51 m
d/ 1001 m
Answer: 1.51 km
Explanation:
Coulomb's Law: The electrostatic force between two charge particles Q: and Q2 is directly proportional to product of magnitude of charges and inversely proportional to square of separation distance between them.
Or, [tex]\vec{F}=k \frac{Q_{1} Q_{2}}{r^{2}}[/tex]
Where Q1 and Q2 are magnitude of two charges and r is distance between them:
Given:
Q1 = Charge near top of cloud = 48.8 C
Q2 = Charge near the bottom of cloud = -41.7 C
Force between charge at top and bottom of cloud (i.e. between Q: and Q2) (F) = 7.98 x 10^6N
k = 8.99 x 109Nm^2/C^2
So,
[tex]\begin{aligned}&7.98 \times 10^{6}=\left(8.99 \times 10^{9} \mathrm{Nm}^{2} / \mathrm{C}^{2}\right) \frac{48.8 \mathrm{C} \times 41.7 \mathrm{C}}{\mathrm{r}^{2}} \\&r=\sqrt{\frac{1.8294 \times 10^{13}}{7.98 \times 10^{6}}}=1.514 \times 10^{3} \mathrm{~m}=1.51 \mathrm{~km}\end{aligned}[/tex]
Therefore, the separation between the two charges (r) = 1.51 km
Which is NOT a characteristic of
the temperate region?
A. a lot of organic matter
B. moderate temperatures
C. moderate rainfall
D. under-developed soil horizons
Answer:
under developed soil horizons
The amount of potential energy possessed by an elevated object is:.
4. An archer pulls a bowstring back 0.440 m, and the spring constant of the bow is 545 N/m.
a.) Find the amount of work the archer did to draw the bow.
b.) Find the speed an arrow of mass 0.060 kg will have when it is shot from the bow.
Assume no losses from friction
Answer: (a)part:545nm multiply by 0.440m=239.8JEWELS(J)
(B):1/2MULTIPLY BY MVSQUARE(APPLY THE FORMULA OF KINETIC ENERGY)REARANGE THE FORMULA,V=2.13MS
Explanation:
SO FOR PART A, IN ORDER TO CALCULATE THE WORK DONE YOUR SUPPOSE TO APPLY THE FORMULA FORCE MULTIPLY BY DISTANCE WHICH IS THE FORMULA FOR WORK DONE,IN THIS SCENARIO YOU HAD A FORCE OF 545NM AND A DISANCE OF 0.440,SO I ORDER TO FIND THE WORK DONE WE MULTIPLIED THEM BOTHE ACCORDING TO THE FORMULA AND GOT THE ANSWER.
FOR PARTB,I JUST SIMPLY APPLIED THE FORMULA FOR KINETIC ENERGY AND SIMPLY REARRANGED IT IN ORDER TO FIND THE VELOCITY.I MADE V THE SUBJECT OF THE FORMULA.
A soft foam block of mass m slides without friction in the
positive x-direction with speed v. At time t = 0, a student briefly
pushes the block with a force probe in the positive x-direction. The
graph to the right shows the force probe's measurements as a
function of time during the push. Which of the following statements
is true about the block's momentum between t = 0 and t = t;?
The true statement about the blocks momentum is : The momentum of the block has increased by approximately 1/2 F₀t₁ ( B )
Change in MomentumGiven that the change in momentum is equivalent to the Area which is under the force time graph
where :
Area under the force time graph = 1/2 F₀t₁ . Therefore we can conclude that the momentum of the block has increased by an equivalent value of the are under the time graph.
Hence we can conclude that the true statement about the blocks momentum is The momentum of the block has increased by approximately 1/2 F₀t₁ .
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Attached below is the missing part of your question
missing options
The momentum of the block has decreased to zero at time t1. - AThe momentum of the block has increased by approximately 1/2 F0t1 - BThe momentum of the block has decreased by approximately 1/2 F0t1 - CThe change in momentum cannot be determined without knowing the distance by which the force probe compressed the block. - DA solid cylindrical disk has a radius of 0.15 m. It is mounted to an axle that is perpendicular to the circular end of the disk at its center. When a 50-N force is applied tangentially to the disk, perpendicular to the radius, the disk acquires an angular acceleration of 110 rad/s2. What is the mass of the disk?
For A solid cylindrical disk has a radius of 0.15 m, The mass of the disk is mathematically given as
M=6.06kg
What is the mass of the disk?Generally, the equation for the Torque is mathematically given as
t=Ia
Therefore
FR=Ia
50*0.15=M((15^2)/2*10)
M=100/110*15
M=6.06kg
In conclusion, the mass of the disk
M=6.06kg
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how far does a 1.2g bullet with kinetic energy of 1.2 j go in 2 seconds ?
Answer:
To calculate the energy in joules, simply enter the mass of ammunition (in grams) that you use, and the fps that you've read from your Chrono unit.
HELP MEEEE, question number 5
Explanation:
The gravitational potential energy of an object is given by GPE=mgh
where m is the mass of the object, g is the gravitational field strength (9.81 m/s² on earth) and h the height it is lifted at above the GPE reference ground.
Mass 1 has a GPE=m¹gh=(2)(9.81)(10)=196.2 Joule
Mass 2 has a GPE=m²gh=(4)(9.81)(10)=392.4 Joule
Object 2 has more potential energy and it makes sense since it's heavier
Hope this helps :))
Use F = 1/T as your basis:
9. Find the frequency of a tuning fork that takes 2.50×10−3s to complete one oscillation.
The answer is 400 Hz but please show your work.
Now
Frequency:-
[tex]\\ \rm\rightarrowtail \nu=\dfrac{1}{T}[/tex]
[tex]\\ \rm\rightarrowtail \nu=\dfrac{1}{2.5\times 10^{-3}}[/tex]
[tex]\\ \rm\rightarrowtail \nu=0.4\times 10^{3}[/tex]
[tex]\\ \rm\rightarrowtail \nu=400Hz[/tex]
The frequency for this time will be 400 Hz.
What is the frequency?Frequency is defined as the ratio of the number of waves to time. It is denoted by f.
f=[tex]\frac{1}{T}[/tex] where,
f is the frequency and,
T is the time period.
SI unit of frequency is Hz.
There are different types of frequency in sound :
Infrasonic-The frequency is less than 20 Hz.Audible-The frequency is between 20Hz to 20,000 Hz.Ultrasonic-The frequency is greater than 20,000 Hz.According to the question :
Given :
T= 2.50×[tex]10^{-3}[/tex]
f=[tex]\frac{1}{T}[/tex]
⇒f=1/(2.50×[tex]10^{-3}[/tex])
⇒400 Hz
Hence, the frequency for this time will be 400 Hz.
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