Which type of macromolecule is the sugar fructose? It ends in "ose" which is a clue.
O lipid
O nucleic acid
O carbohydrate
protein

Answer: c

because gasses are less dense than liquids

Answer: how do we answer when there are no options??

Explanation:

Answer:

An amide and water are the products formed

Explanation:

Here, we want to know the possible products that could be formed from the reaction of a carboxylic acid with an amine.

An anime has the functional group NH2 while for an organic acids, we have COOH.

So essentially we want to know the result of these two functional groups coming together to react.

The reaction between these two will form an amide in conjunction with water.

Take for example;

R-COOH + R’-NH2 ———> R-COHN -R’ + H2O

Where R and R’ may be the same or different alkyl or aryl groups

Answer:

c

Explanation:

the other one doesn't make sense and when you read them with the sentence it kinda makes sense

Answer:

Tendons and ligaments

Explanation:

Tendons connect the skeletal system to the muscular system by attaching muscle to bone.

Answer:

the law of conversation of mass States that mass is an isolated system is neither created or destroyed by chemical reactions or physical transformations. according to the law of conversation of mass the mass of the product in a chemical reaction must equal to the mass of reactants

hope It helped you

Answer:

yeasts, moulds, bread, beer, wine, ...

Explanation:

Answer:

peer reveiw

Explanation:

Answer:

Peer review.

Explanation: Ask Edu

Answer:

V = 10.12 mL

Explanation:

Given that,

Density, d = 0.79 g/mL

Mass, m = 8 g

We need to find the volume of the object. Density is equal to the mass per unit volume. It can be given by :

[tex]d=\dfrac{m}{V}[/tex]

Where V is the volume of the object

[tex]V=\dfrac{m}{d}\\\\=\dfrac{8\ g}{0.79\ g/mL}\\\\V=10.12\ mL[/tex]

So, the volume of the object is 10.12 mL.

Answer:f has 14 electrons in 7 sublevel orbitals,d has 10 electrons in 5 sublevel orbitals,p has 6 electrons in 3 sublevel orbitals,s has 2 electrons in 1 sublevel orbital.

Explanation:

Answer:

14 i think

Explanation:

i googled it

Answer:

There was more erosion in the Colorado Rockies scenario where there was steady rain compared to the scenario in the same area where there was only a drizzle. There is more erosion because the steady rain increased the volume of the river more than the drizzle did. Because there was more water added to the river, the river flowed faster. The faster a river flows, the more sediments it transports or erodes.

Explanation:

Edge

There was greater erosion inside the Colorado Rockies situation when there was persistent rain.

Erosion is the loss of soil or rock from the Earth's crust's surface, as well as the movement of the removed material by natural forces (such as wind or water). The term "erosion" is used in its broadest sense to refer to the overall thinning and moulding of all landmasses on the surface of the planet, such as the corrosion of rock in its natural position, the vehicles and public of weathered material, as well as erosion brought on by wind action, marine, as well as glacial processes.

In contrast to the situation within the identical region where there was simply a drizzle, there was greater erosion inside the Colorado Rockies situation when there was persistent rain. Because the volume of a river was raised by the constant rain more than by the drizzle, there is more erosion. The river flowed more quickly as a result of the additional water. A river transfers or erodes more material the quicker it runs.

Therefore, there was greater erosion inside the Colorado Rockies situation when there was persistent rain.

To know more about erosion, here:

https://brainly.com/question/7567484

#SPJ2

Answer:

The correct answer is "[tex]\frac{0.65}{V} \ percent[/tex]".

Explanation:

The given values are:

[tex]M_r=0.130 \ g[/tex]

[tex]M_o=20 \ g/L\times V(L)[/tex]

     [tex]=20 \ V[/tex]

As we know,

⇒ [tex]Recovery \ percent=\frac{Amount \ of \ substance \ recovered}{Amount \ of \ substance \ originally \ taken}\times 100[/tex]

On substituting the given values, we get

                                [tex]=\frac{0.130}{20 \ V}\times 100[/tex]

                                [tex]=\frac{0.65}{V} \ percent[/tex]

Note: percent = %

Answer:

the answer is the line that starts at zero and ends in the right corner i have the question and got it right

Explanation:

Answer: 360.3056 grams i think

Explanation:

Answer: The answer is Molecule bond.

Answer:

Q = 7.7 KJ

Explanation:

The complete question carries the following data:

Specific Heat Capacity of Liquid State = C(l) = 1.45 J/mol.°C

Specific Heat Capacity of Gaseous State = C(g) = 0.65 J/mol.°C

Boiling Temperature = Tb = 88.5°C

Heat of Vaporization = ΔH(vap) = 1.23 KJ/mol

Now, first we calculate the heat required (Q₁) to raise he temperature to boiling point:

Q₁ = n*C(l)*ΔT₁

where,

n = no. of moles = 5.31 mol

ΔT₁ = Temperature difference from 40°C to Tb = 88.5°C - 40°C = 48.5°C

Therefore,

Q₁ = (5.31 mol)(1.45 J/mol.°C)(48.5°C)

Q₁ = 373.4 J = 0.37 KJ

Now, we calculate the heat required (Q₂) to change its phase:

Q₂ = nΔH(vap)

Q₂ = (5.31 mol)(1.23 KJ/mol)

Q₂ = 6.53 KJ

Now, we calculate the heat required (Q₃) to raise he temperature to boiling point:

Q₃ = n*C(g)*ΔT₃

where,

n = no. of moles = 5.31 mol

ΔT₃ = Temperature difference from Tb to 113°C = 113°C - 88.5°C = 24.5°C

Therefore,

Q₃ = (5.31 mol)(0.65 J/mol.°C)(24.5°C)

Q₃ = 84.5 J = 0.08 KJ

So, the total heat required to convert 5.31 mol of this pure substance from a liquid at 40°C to a gas at 113°C is:

Q = Q₁ + Q₂ + Q₃

Q = 0.37 KJ + 6.53 KJ + 0.08 KJ

Q = 7.7 KJ

The total heat required to convert the pure substance from liquid to gas at the given temperature is 814 J.

The given parameters;

The total heat required to convert the pure substance from liquid to gas at the given temperature is calculated as follows;

[tex]Q = nc_l \Delta \theta + nc_g \Delta \theta \\\\ \Delta \theta = (113 - 40) = 73^0 C \\\\Q = (5.31 \ mol \times 1.45 \frac{J}{mol .\ ^0C} \times 73\ ^0C) + (5.31 \ mol \times 0.65 \frac{J}{mol .\ ^0C} \times 73 \ ^0C)\\\\Q = 814 \ J[/tex]

Thus, the total heat required to convert the pure substance from liquid to gas at the given temperature is 814 J.

"Your question is not complete, it seems to be missing the following information;"

How much heat would be required to convert 5.31 mol of a pure substance from a liquid at 40.0°C to a gas at 113.0°C? (molar heat capacity of liquid, C(l) is 1.45 J/mol.⁰C and molar heat capacity of gas, C(g) is 0.65 J/mol.⁰C).

Learn more here:https://brainly.com/question/8428922

Answer:

208.125g

Explanation:

Given parameters:

 Number of moles of HCl = 3.75moles

Unknown:

 Mass of CaCl₂ that will be produced = ?

Solution:

The reaction equation is given as:

  2HCl  + Ca(OH)₂   →   CaCl₂ + 2H₂O

Now, to find the mass of CaCl₂, we have to work from the known to the unknown.

The known specie here is the number of moles of HCl;

        2 mole of HCl will produce 1 mole of  CaCl₂

       3.75moles of HCl will produce [tex]\frac{3.75}{2}[/tex]   = 1.875moles

The mass of  CaCl₂;

  Mass of  CaCl₂ = number of moles of  CaCl₂ x molar mass

Molar mass of  CaCl₂ = 40 + 2(35.5) = 111g/mol

  Mass of  CaCl₂ = 1.875 x 111 = 208.125g

Answer:

[tex]-23592.19\ \text{J/mol}[/tex]

Explanation:

T = Temperature = 309 K

[tex]\Delta G^{\circ}[/tex] = Standard Gibbs free energy = -65.0 kJ/mol

R = Gas constant = 8.314 J/mol K

[tex][H^+][/tex] = Biological standard state has hydrogen ions = [tex]10^{-7}\ \text{molar}[/tex]

Reaction quotient is given by

[tex]Q=\dfrac{1}{[H^+]}\\\Rightarrow Q=\dfrac{1}{10^{-7}}\\\Rightarrow Q=10^7[/tex]

Standard biological Gibbs free energy is given by

[tex]\Delta G=\Delta G^{\circ}+RT\ln Q\\\Rightarrow \Delta G=-65000+8.314\times 309\times \ln10^7\\\Rightarrow \Delta G=-23592.19\ \text{J/mol}[/tex]

The standard biological Gibbs free energy of the reaction is [tex]-23592.19\ \text{J/mol}[/tex]

Answer:129.839 g/mol

Explanation:

Answer:

d

Explanation:

Answer:

Its d

Explanation:

Ik you already know this, I just wanted the points tbh

Hey there !

Molecular Weight: 262.86 g/mol

Volume in liters : 1,000 mL => 1,000 / 1000 => 1 L

Number of moles of solution :

number of moles = volume x molarity

number of moles = 1 x 0.3  => 0.3 moles

Therefore:

1 mole Mg₃(PO₄)₂ ------------------- 262.86 g

0.3 moles ----------------------------- mass of Mg₃(PO₄)₂  ??

mass of Mg₃(PO₄)₂ = 0.3 x 262.86 / 1

mass of Mg(PO₄)₂ => 78.858 g

Hope this helps!

Answer:

Chemical

Explanation:

Cause it is

Answer:

Be replacement

Explanation:

srry they delted my answer before:( someone from brainly all i did was added a link for a quizlet that would help you.. :(

Answer:

Be

Replacement

Explanation:

Answer:

1. a

Explanation:

2. c

Answer:

1 is A number two is C

Answer:

The answer is "0.35".

Explanation:

please find the complete question in the attached file.

Mass of [tex]CH_3C0_2 H[/tex][tex]= 77 \ g \\\\[/tex]

Molar mass of [tex]CH_3C0_2 H[/tex] [tex]= 60.05 \ \frac{g}{mol} \\\\[/tex]

No of moles in [tex]n_{CH_3CO_2H}[/tex] [tex]= 77 \ g \times \frac{1 \ mol \ CH_3C0_2H}{60.05 \ g}[/tex]  

                                          [tex]= 1.28 \ mol \ CH_3CO_2H[/tex]

Mass of water [tex](H_2O)[/tex][tex]= 42 \ g[/tex]

The molar mass of water [tex](H_2O)[/tex][tex]= 18.02 \ \frac{g}{mol}[/tex]

moles of water [tex]n_{H_2O}[/tex]:

[tex]= 42 \ g \times \frac{1 mol H_2O}{18.02 \ g} \\\\= 2.33 \ mol \ H_2 O[/tex]

Molfraction of acetic acid:

[tex]X CH_2CO_2H = \frac{n_{CH_3CO_2H}}{n_CH_3CO_2H +n_{H_2}}\\\\[/tex]

                     [tex]=\frac{1.28 \ mol}{1.28 \ mo1 + 2.33 mol}\\\\ = 0.354\\\\= 0.35[/tex]