Which two elements would have the same number of energy levels

The first thing will be to finish the reaction that happens in the experiment to the reactional HCl and sodium bicarbonate (NaHCO3). The balanced reaction is the following:

Now, we must determine which is the limiting reactant. To do this we are going to convert all the data they give us to moles.

For HCl we are given the molarity, so the moles will be:

Now the moles of sodium bicarbonate are found using its molar mass:

By stoichiometry, we have that one mole of NaHCO3 reacts with one mole of HCl. We have more moles of NaHCO3 than HCl. Therefore, HCl will be the limiting reactant.

So the reaction will occur according to the number of moles of HCl. Now the ratio between HCl and CO2 gas formed is 1 to 1. For one mole of HCl that reacts, 1 mole of CO2 will be formed.

so, the number

Answer:

Explanation:

Here, we want to get the functional group is found in amino acids

In the amino acids, we can get amines, carboxylic acid groups, and the carbon chain

Looking at the options, we can see that the amine group is the right option here as the other two are not available

Answer: C4H10O2

Explanation:

At first find the percentage composition, in 1.67 g compound what percentage of Carbon, Hydrogen and Oxygen are there. Then from those percentages through unitary method find out how much Carbon, Hydrogen and Oxygen would be there in 90.1 g of compound. From those amounts finds their mole number, as in divide the obtained amount by their gram equivalent mass. The numbers you obtain are the corresponding number of Carbon Hydrogen and Oxygen in one molecule of the compound. Hope this helps

87.77 ml will provide the recommended daily allowance of vitamin C.

- To calculate the milliliters of vegetable juice that will provide 100% of the recommended daily allowance of vitamin C, we can use a mathematical Rule of Three:

So, 87.77 ml will provide the recommended daily allowance of vitamin C.

In order to answer this question we will use the molar mass of Chromium, which is 52 g/mol, that means that in every 1 mol of Cr, we will have 52 grams of it:

52 g = 1 mol

260 g = x moles

52x = 260

x = 5 moles of Chromium

Answer

The percent yield = 83.36%

Explanation

Given:

Experimental yield = actual yield = 15.68 g

Theoretical yield = 18.81 g

What to find:

The percent yield for the reaction.

Step-by-step solution:

The percent yield for the reaction can be calculated using the formula below:

Hence, the percent yield for the reaction is 83.36%

The limiting reactant, given that 5.0 moles of CH₄ and 1.0 mole of O₂ are in the reactor is O₂

We'll begin by obtainig the balanced equation for the reaction. This is given below:

CH₄ + 2O₂ —> CO₂ + 2H₂O

The limiting reactant for the reaciont can be obtained as illustrated below:

From the balanced equation above,

1 mole of CH₄ reacted with 2 moles of O₂

Therefore,

5 moles of CH₄ will react with = 5 × 2 = 10 moles of O₂

From the above illustration, we can see that a higher amount of O₂ is needed to react completely with 5 moles of CH₄.

Thus, we can conclude that O₂ is the limiting reactant.

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As the question gave us the formula in which we have to use to calculate the volume of this type of wood:

V = m/d

We have:

m = 1700 grams

d = 0.85

Now we add these values into the formula:

V = 1700/0.85

V = 2000 cm3, letter D

Answer:

Explanation:

Here, we want to calculate the density of the gas at STP

We use a modification of the general gas law as follows

Mathematically:

where:

P1 is the initial pressure which is 0.95 atm

D1 is the initial density which is 0.066 g/l

T1 is the initial temperature in Kelvin (we add the temperature in Celsius with 273 K : 32 + 273 = 305 K)

P2 is the pressure at STP which is 1 atm

D2 is the density that we want to calculate

T2 is the temperature at STP which is 273 K

Substituting the values, we have it that:

The set of quantum numbers (3, 3, -3, -1/2), and  (2, 1, 2, +1/2) are not possible. Therefore, options c and e are correct.

The set of numbers that can describe the position and energy of the electron. We have four quantum numbers principal, azimuthal, magnetic, and spin quantum numbers.

Principal quantum numbers (n) tell about the principal electron shell of the atom and the most probable distance between the electrons and the nucleus. The azimuthal quantum number (l) tells about the shape of an orbital in which an electron is present. It has values equal to l = n - 1.

The magnetic quantum number tells about the total number of orbitals in a subshell and the orientation of these orbitals.  The value of m lies in between -l to +l. The value of the spin quantum number describes the direction of spin of an electron and it has only two values +½ and -½.

In option c, the principle (n) and azimuthal (l) quantum number has the same value but when n = 3 the possible values of l are 2, 1, 0. In option d, the magnetic quantum number has the value of 2 while l has 1 which is not possible because when l= 1 the values of m can be  +1, 0, and -1.

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1. The concentation of the magnesium ion, Mg²⁺ in the solution is 0.01 M

2. The concentation of the nitrate ion, NO₃⁻ in the solution is 0.02 M

We'll begin by obtaining the concentration of the stock solution. This can be obtained as follow:

Concentration = mole / volume

Concentration = 0.25 / 1

Concentration = 0.25 M

Next, we shall determine the concentration of the diluted solution

C₁V₁ = C₂V₂

0.25 × 20 = M₂ × 500

5 = M₂ × 500

Divide both side by 500

C₂ = 5 / 500

C₂ = 0.01 M

1. How to determine the concentration of magnesium ion, Mg²⁺

Mg(NO₃)₂(aq) <=> Mg²⁺(aq) + 2NO₃⁻(aq)

From the balanced equation above,

1 mole of Mg(NO₃)₂ contains 1 mole of Mg²⁺

Therefore,

0.01 M Mg(NO₃)₂ will also contains 0.01 M Mg²⁺

Thus, the concentration of Mg²⁺ is 0.01 M

2. How to determine the concentration of nitrate ion, NO₃⁻

Mg(NO₃)₂(aq) <=> Mg²⁺(aq) + 2NO₃⁻(aq)

From the balanced equation above,

1 mole of Mg(NO₃)₂ contains 2 mole of NO₃⁻

Therefore,

0.01 M Mg(NO₃)₂ will contain = 0.01 × 2 = 0.02 M NO₃⁻

Thus, the concentration of NO₃⁻ is 0.02 M

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Answer

The specific heat of the glass = 0.7366 J/g°C

Explanation

Given:

Mass of the glass sample, m = 9.3 g

Quantity of heat given off, Q = 87 J

Change in temperature, ΔT = 12.7 °C

What to find:

The specific heat, c of the glass.

Step-by-step solution:

The specific heat, c of the glass can be calculated using the given formula below.

Putting the values of the given parameters into the formula, we have;

Therefore, the specific heat of the glass is 0.7366 J/g°C

Empirical formula:

Step 1

Information already provided

The mass percent composition:

40.9 % C

4.58 % H

54.5 % O

Information needed: from the periodic table

For C) 1 mol = 12.01 g

For H) 1 mol = 1.008 g

For O) 1 mol = 15.99 g

---------------------------

Step 2

A sample of 100 g is assumed, so:

40.9 % C => 40.9 g C

4.58 % H => 4.58 g H

54.5 % O => 54.5 g O

--------------------------

Step 3

Convert mass into moles:

40.9 g C x (1 mol/12.01 g) = 3.40 moles C

4.58 g H x (1 mol/1.008 g) = 4.54 moles H

54.5 g O x (1 mol/15.99 g) = 3.40 moles O

------------------------

Step 4

All moles calculated in step 3 need to be divided by the smallest one.

3.40 moles C/3.40 moles = 1

4.54 moles H/3.40 moles = 1.33

3.40 moles O/3.40 moles = 1

-----------------------

Step 5

Integer numbers are needed, so let's multiply by 3 all of them in step 4

Therefore,

For C) 3

For H) 3.99 = 4 approx.

For O) 3

All these numbers calculated will be the subindexes in ascorbic acid

Answer:

Empirical formula: C3H4O3

(1)

The molecule NH4NO3 is ammonium nitrate, which makes a redox reaction.

It produces N2, O2, and H2O, which are nitrogen, oxygen, and water.

The ions are 2NH4+ and 2NO3-.

2 molecules of N2, 4 molecules of H2O, and 1 molecule of O2.

(2)

There are 2 moles of NH4NO3, 2 moles of N2, 4 moles of H2O, and 1 mole of O2.

(3)

The molar mass of NH4NO3 is 80.043 grams per mole, but there are 2 moles of it, so there are 160.09 grams of NH4NO3.

There are 56.03 grams of N2 because there are 2 moles of it. (1 mole N2 = 28.0134 g/mol).

There are 72.06 grams of H2O because there are 4 moles of it (1 mole H2O = 18.02 g/mol).

There are 31.998 grams of O2 because there's just 1 mole of it.

(4)

The formula units of NH4NO3 is 1.204x10^24, which is equivalent to 2 moles.

Nitrogen has the same formula units because there are 2 moles of it, so it's 1.204x10^24.

Water has 2.409x10^24 because there are moles of it.

Oxygen has 6.022x10^23 because there's just 1 mole, inis Avogadro's Number.

The oxidation number of O is usually -2 and in this case it is.

Our ion is ReO₄⁻. It has a total charge of -1. The charge of the four atoms of O is -8. With this information we can write an equation. X will represent the oxidation state of Re.

Total charge = Oxidation state of Re + 4 * Oxidation state of O

- 1 = x + 4 * (-2)

- 1 = x - 8

-1 + 8 = x

x = +7

So the oxidation state of Re is +7.

Answer

101.3 mL

Explanation

Given:

The initial temperature, T₁ = 148.5 °C = (148.5°C + 273) = 421.5 K

The initial volume, V₁ = 241.8 mL

Final temperature, T₂ = -96.4 °C = (-96.4°C + 273) = 176.6 K

What to find:

The final volume of the gas.

Step-by-step solution:

The final volume, V₂ of the gas can be calculated using Charle's law formula.

The final volume of the gas is 101.3 mL

Answer:

80g

Explanation:

The law of conservation of matter states that matter cannot be created nor destroyed. Basically, whatever mass you have at the beginning of a reaction, should be the same as at the end of the reaction on the product side.

Since here it lets you know that a total of 100g (30g + 70g) were produced on the product side, that means that we started off with 100g in our reactant side.

We have given that one material is 20g on our reactant side but we need the mass of the other. To find the mass of the other material, simply subtract 20g from the total mass created on the product side.

100g - 20g = 80g

The 80g would be the missing amount from the reactant side that isn't stated.

We will reconstruct the model in the following manner :

From the above diagram we can see that :

• number of Carbon atom = 3

• number of hydrogen atom = 8

• rewrite this in an alphabetical order, you get :

mL and cm³ have a 1 to 1 conversion, so we have:

But we don't have this option, so we will need to find another.

The other are in m³, so we can use the conversion from cm to m to get this:

So, we can apply this to what we have:

We have an option with 0.054m³, so the correc alternative is 0.054 m³.

[tex]2K_(s) + Cl_2_(g)[/tex] ⇒ [tex]2KCl_(aq)[/tex]

Type of Reaction: Synthesis

What is a synthesis reaction?

When 2 or more substances react to form a single compound.

Answer

Density = 0.267 g/L

Explanation

Given:

Pressure of H2S = 0.2 atm

Temperature = 311 K

We know:

The molar mass of H2S = 34,1 g/mol

R constant = 0.08206 L.atm/K.mol

Solution:

From the ideal gas law:

PV = nRT

We know that:

density = m/V

n = m/M

Therefore we can use the following equation to solve for density of H2S

3.01×10²³molecules.

The formula for the number of molecules of a compound given the number of moles is expressed as:

Get the moles of ethane gas using the formula:

Determine the required number of molecules of ethane

Hence the molecule of ethane gas that is in 15 grams of the compound is 3.01×10²³molecules.

Co-60 is used medically for radiation therapy as implants and as an external source of radiation exposure the half-life of Co-60 is 5, 272 years 2.000 mg sample will remain after 21, 088 years is 0.0625 gm left

Radiation therapy is the cancer treatment that uses high doses of radiation to kill cancer cell and shrink tumor

Here given data is Co-60 is 5, 272 years and we have to find the number of half lives in 21, 088 years = ?

21, 088/5, 272 = 4 half lives

(1/2)⁵   = 1/32 nd  of the original will be left

1/32×2.000mg = 0.0625 gm left

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Answer:

60.0 mL of 0.322 M potassium iodide are combined with 20.0 mL of 0.530 M lead (II) nitrate.

How many grams of lead (II) iodide will precipitate? (you must write your own reaction)

Explanation:

Answer

B. The bonds in the compound are covalent

Explanation

The carbon, oxygen, and hydrogen that combine in a specific ratio to form the sugar are nonmetals. From what was learned about elements and the periodic table, nonmetals form covalent bonds among themselves to form compounds.

So what is true about the bonding in sugar is:

B. The bonds in the compound are covalent.

0.167L

In order to know how much L of the 3M NaOH solution would you need, we will simply set up an equal proportion solution expressed as;

C1 and C2 are the concentration of the solutions

V1 and V2 are the volumes of the solutions

Given the following parameters;

C1 = 1M

V1 = 500mL

C2 = 3M

V2 = ?

Substitute the given parameters into the formula above to get the required litre of solution needed.

Divide both sides by 3:

Converting to litres

Since 1mL = 0.001L

166.67mL = x

Cross multiply

Hence the amount of L of the 3M NaOH solution would you need is 0.167L