which substance will experience the greatest temperature change if 100J of energy is used to warm it? 100g of moist air, 100g of water or 100g of ice​

Answers

Answer 1
Sensible temperature change will be greatest for 100

Related Questions

What is the pH of a 0.00001 M solution of HCI?

Answers

Answer:

0.00001= 1 x 10^-5. Since HCl is an acid, 1 x10^-5 is the H+ concentration. Write only the number of the exponent. Therefore, pH = 5.

what does newton’s first law of motion explain

Answers

Answer:

Newton's first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

What conversion factors
determine the number of
molecules from the mass of a
compound?

Answers

Answer: Multiply the mass by the inverse of molar mass, and then multiply by Avogadro's number.

Explanation: Convert the mass to moles, multiply the number of moles by the ratio of the number of atoms or ions to one mole, multiply by Avogadro's number.


How many moles are in 43 grams of lithium (LI)?

Answers

Answer:

6.19507275608684

Explanation:

Select the correct answer from each drop-down menu.

Researchers stationed at different areas on a mountain and in a tunnel midway through the mountain boiled water at the same time. Even though the water at every station was at the same temperature, the pot at the top of the mountain started boiling before the others. Why?

Water boils when the vapor pressure is
the atmospheric pressure. The atmospheric pressure
at the top of the mountain.

Answers

Water boils when the vapour pressure is least the atmospheric pressure.

The atmospheric pressure is equal at the top of the mountain.

What is atmospheric pressure?

The air around you has weight, and it presses against everything it touches. That pressure is called atmospheric pressure, or air pressure. It is the force exerted on a surface by the air above it as gravity pulls it to Earth.

As we go up in altitude the air pressure becomes less. When the pressure decreases, it takes less energy to get the water molecules to escape the surface. So the temperature is less than it would be at sea level.

Air pressure is higher or greater at the bottom of a mountain. This is because the height of the air above that level is thicker than at the top.

Pressure is given by the equation, P=rho*g*h, where rho is the air density, g is the gravity value and h is the thickness of the air layer on top of the level where we are considering the pressure.

Therefore, as we can see, at the bottom of the mountain, the thickness h of air is greater, and so is the pressure.

Hence, water boils when the vapour pressure is least the atmospheric pressure and the atmospheric pressure is equal at the top of the mountain.

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Our Sun will eventually turn into a red giant and, finally, a white dwarf. Use the Hertzsprung-Russell
diagram to describe how the Sun's luminosity and temperature will change as it goes through these
stages.

Answers

Our Sun will eventually turn into a red giant in the cooler temperature and high luminosity and in the white dwarf phase has a hot temperature & dim luminosity.

What is Hertzsprung-Russell diagram?

In astronomy, the Hertzsprung-Russell diagram, often known as the H-R diagram, is a graph that plots the absolute magnitudes (intrinsic brightness) of stars against their spectral classifications (temperatures).

From the given diagram it is clear that when sun turns into a red giant then the temperature decreases and luminosity increases as it becomes large in size. And when it finally become a white dwarf then temperature comparatively increases and luminosity gets dim due to smaller size.

Hence in the red giant phase sun has a cooler temperature and high luminosity and in the white dwarf phase has a hot temperature & dim luminosity.

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A sample of gas has a volume of 20.0 mL at STP. What will the volume be if the temperature is changed to 546 K and the pressure is changed to 2.0 atm.? (show work plz)

Answers

The volume did not change, it remained at 20 ml

Further explanation

Given

20 ml a sample gas at STP(273 K, 1 atm)

T₂=546 K

P₂=2 atm

Required

The volume

Solution

Combined gas Law :

[tex]\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}[/tex]

Input the value :

[tex]\tt \dfrac{1\times 20}{273}=\dfrac{2\times V_2}{546}\\\\V_2=\dfrac{1\times 20\times 546}{273\times 2}\\\\V_2=20~ml[/tex]

The volume does not change because the pressure and temperature are increased by the same ratio as the initial conditions (to 2x)

CAN SOMEONE PLEASE GET THE OXIDATION NUMBERS FOR THIS PLEASE
H2O+CO2-> H2CO3

Answers

Answer:

H2O = 0

CO2 = +4

H2CO3 = +4

Explanation:

what percent of the sun's energy is used by the living organism on earth
a. 1%
b. 10%
c. 20%
d. 35%
e. 50%

Answers

B 10%


Hope I’m right tho

A 10.0-liter flask contains 1.013 grams of oxygen and .572 grams of carbon dioxide at 180C. What are the partial pressures of oxygen and carbon dioxide? What is the total pressure? What is the mole fraction of oxygen in the mixture?

Answers

P tot = 0.1065 atm

The mole fraction of oxygen in the mixture : 0.709

Further explanation

Given

10 L flask

1.013 g O₂

572 g CO₂

T = 18 °C = 291 K

Required

P O₂ and P CO₂

Solution

Dalton Law's of partila pressure

P tot = P₁ + P₂ + ..Pₙ

From ideal gas Law :

[tex]\tt P_{O_2}=\dfrac{\dfrac{1.013}{32}\times 0.082\times 291 }{10}\\\\P_{O_2}=0.0755~atm[/tex]

[tex]\tt P_{CO_2}=\dfrac{\dfrac{0.572}{44}\times 0.082\times 291}{10}\\\\P_{CO_2}=0.031~atm[/tex]

P tot = P O₂ + P CO₂

P tot = 0.0755 + 0.031

P tot = 0.1065 atm

The mole fraction of  O₂ :

[tex]\tt P_{O_2}=X_{O_2}\times P_{tot}\\\\X_{O_2}=\dfrac{P_{O_2}}{P_{tot}}\\\\X_{O_2}=\dfrac{0.0755~atm}{0.1065~atm}\\\\X_{O_2}=0.709[/tex]

Which is caused by the refraction of waves?
A. Two sounds canceling each other out
B. Seeing yourself in a mirror
C. Something looking bent under water
D. Sound bending around a door

Answers

Answer:

C: Something looking bent under water.

If 2.5 grams of calcium bromide reacted with excess lithium oxide, how many grams of bromide product would be formed?

Answers

Answer: 2.17 g of  bromide product would be formed

Explanation:

The reaction of calcium bromide with lithium oxide will be:

[tex]CaBr_2+Li_2O\rightarrow 2LiBr+CaO[/tex]

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of calcium bromide}=\frac{2.5g}{199.9g/mol}=0.0125moles[/tex]

As lithium oxide is in excess, calcium bromide is the limiting reagent.

According to stoichiometry :

1 mole of [tex]CaBr_2[/tex] produce = 2 moles of [tex]LiBr[/tex]

Thus 0.0125 moles of [tex]CaBr_2[/tex] will require=[tex]\frac{2}{1}\times 0.0125=0.025moles[/tex]  of [tex]NH_3[/tex]

Mass of [tex]LiBr=moles\times {\text {Molar mass}}=0.025moles\times 86.8g/mol=2.17g[/tex]

Thus 2.17 g of  bromide product would be formed

What is the atomic number of an element that has seven protons and eight neutrons and seven electrons?

Answers

Answer:

Nitrogen has an atomic number of 7 (Z=7) because it has 7 protons in its nucleus. Some nitrogen atoms have an atomic mass number of 15 (A=15). A is the number of neutrons plus protons in the nucleus. However, we already know that there are 7 protons

Answer:

Atomic number = Number of protons = Number of electrons

Atomic number = 7

PLEASE HURRY
Which layer of Earth is the densest and why is that so?
A: The outer core is densest due to gravitational compression.
B: The outer core is densest due to generation of radiogenic heat.
C: The outer core is densest due to accretion.
C: The inner core is densest due to gravitational compression.
D: The inner core is densest due to generation of radiogenic heat.

Answers

Answer:

D

Explanation:

Answer: C: The inner core is densest due to gravitational compression

Explanation:  

define the following terms

A) chemical family


B) period


C) metalloid


Answers

Answer:

Chemical Family means a group of elements in the Periodic Table or, more commonly, compounds that share certain physical and chemical characteristics and have a common name.

A period in the periodic table is a row of chemical elements.

metalloid is an element (e.g. arsenic, antimony, or tin) whose properties are intermediate between those of metals and solid nonmetals or semiconductors.


1. To calculate the molarity of a solution, you need to know the moles of solute and the
O volume of the solvents
O mass of the solution
O volume of the solution
volume of the solute

Answers

Answer:

O volume of the solution

Explanation:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / volume of solution  in L

For example:

if we dissolve the 1 mole of NaCl to make the solution of volume 2 L. The molarity of solution is,

M = 1 mol / 2 L

M = 0.5 M

do activity for brainiest:)

Answers

What’s are the matters

Is Mg(CH3COO)2 soluble or insoluble

Answers

Answer:

It is Soluble

Explanation:

Name- Magnesium acetate

It dissolves easily in water and alcohol.

What type of chemical reaction occurs when more energy is released during a chemical reaction than is needed to start a chemical reaction

Answers

Answer:

exothermic reaction

Explanation:

your welcome :)

If alcohol has a density of 0.84 g/ml, would it float or sink in a cup of water (density of 1.00 g/ml)?

Answers

Denser materials will always sink below less dense materials.

So in this case, the alcohol would float since it has a lower density.

The temperature of a city during a week was 35° C, 36°C, 34°C, 38°C, 40°C, 39°C and 44°C. What was the average daily temperature of the town for the week?

Answers

Answer:38°

Explanation:

Calculate the new pressure if a 2300 mL of a gas at a pressure of 1.88 atm is allowed to contract to a volume of 2.21 L.

Answers

Answer:

V₂ = 0.958 atm

Explanation:

Given data:

Initial volume = 2300 mL (2300/1000 = 2.3 L)

Initial pressure = 1.88 atm

Final volume = (2.21 L + 2.3L) = 4.51 L

Final pressure = ?

Solution;

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.88 atm × 2.3 L =  P₂ × 4.51 L

V₂ = 1.88 atm × 2.3 L / 4.51 L

V₂ = 4.32 atm.L /  4.51 L

V₂ = 0.958 atm

why is magneisum a metal​

Answers

Answer:

Chemical element, metallic, symbol Mg, situated in group IIa in the periodic table, atomic number: 12, atomic weight: 24,312. ... Magnesium is known for a long time as the lighter structural metal in the industry, due to it's low weight and to it's capability of forming mechanically resistant alloys.

DUE VERY VERY VERY SOON
What are the rows of elements called on the periodic table?

Answers

Answer:

"The elements are arranged in seven horizontal rows, called periods or series, and 18 vertical columns, called groups."

Explanation:

I GIVE OUT FREE POINTS

How many molecules of nitrogen dioxide NO2 are in 1 mole of NO2?

Answers

Answer:

The answer is 46.0055. We assume you are converting between grams NO2 and mole. You can view more details on each measurement unit: molecular weight of NO2 or mol This compound is also known as Nitrogen Dioxide.

Explanation:

hope this helps

Which feature does an iron metal have?
O electrons that transfer between atoms to make cations and anions
O a sea of electrons
O firmly bonded electrons
O electrons shared between single pairs of atoms

Answers

Answer:

a sea of electrons

Iron metal has a sea of electrons.

Iron metal is an element which possesses a sea of electrons as a result of it

containing cations which are usually surrounded by electrons which move at

a very fast pace .

This property makes Iron metal to be reactive when exposed to air( oxygen)

and it then forms various compounds such as Iron(II) oxide, Iron(III) oxide and

rust.

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Explain the process of ionic bond formation between K
(potassium, a metal) and Br (bromine, a nonmetal).
I

Answers

Answer:

Metals transfers electrons to nonmetals. So K transfers one electron to Br because K is located at 1A in the periodic table. Br has seven electrons, now both K and Br are stable by gaining and losing one electron. The transfer of electrons makes metals to become positive ions and nonmetal to become negative ions. When an ionic bond is formed, the charges attract each other.

Answer: Metals transfers electrons to nonmetals. Potassium -K transfers one electron to bromine- Br because K is located in group 1A on periodic table. Br has seven electrons and located group 7A. Both K and Br stable by gaining and losing one electron. The transfer of electrons makes metals to become + positive ions and nonmetal to become - negative ions. An ionic bond is formed, the charges attract each other.

Explanation: Metals donate, or transfer, electrons to the nonmetal.

The transfer of electrons creates a positive ion and a negative ion.

An ionic bond is formed when the charges attract each other.

Please help... giving a lot of points and awarding brainliest.

Answers

Theoretical Yield of H2SO3: 31.2 g
Percent Yield: 67.4%

Theoretical Yield of C2H6: 6.50
Percent Yield: 88.7%

Theoretical Yield of HF: 3.84
Percent Yield: 71.4%

0.00099989
3 sig figs, scientific notation

Answers

1.00*10^3
You’d need to lower the exponent because rounding to 3 sig figs changes the 9’s to - 1000. Keep the 0’s.

SOMEONE HELP PLEASE! ​

Answers

Answer:

The nose consists of the visible external nose and the internal nasal cavity. The nasal septum divides the nasal cavity into right and left sides. Air enters two openings, the external nares (nostrils; singular, naris), and passes into the vestibule and through passages called meatuses. The bony walls of the meatuses, called concha, are formed by facial bones (the inferior nasal concha and the ethmoid bone). From the meatuses, air then funnels into two (left and right) internal nares. Hair, mucus, blood capillaries, and cilia that line the nasal cavity filter, moisten, warm, and eliminate debris from the passing air.

The pharynx (throat) consists of the following three regions, listed in order through which incoming air passes:

The nasopharynx receives the incoming air from the two internal nares. The two auditory tubes that equalize air pressure in the middle ear also enter here. The pharyngeal tonsil (adenoid) lies at the back of the nasopharynx.

The oropharyrnx receives air from the nasopharynx and food from the oral cavity. The palatine and lingual tonsils are located here.

The laryngopharynx passes food to the esophagus and air to the larynx.

The larynx receives air from the laryngopharynx. It consists of several pieces of cartilage that are joined by membranes and ligaments, shown in Figure 2:

The epiglottis, the first piece of cartilage of the larynx, is a flexible flap that covers the glottis, the upper region of the larynx, during swallowing to prevent the entrance of food.

The thyroid cartilage protects the front of the larynx. A forward projection of this cartilage appears as the Adam's apple (anatomically known as the laryngeal prominence).

The paired arytenoid cartilages in the rear are horizontally attached to the thyroid cartilage in the front by folds of mucous membranes. The upper vestibular folds (false vocal cords) contain muscle fibers that bring the folds together and allow the breath to be held during periods of muscular pressure on the thoracic cavity (straining while defecating or lifting a heavy object, for example). The lower vocal folds (true vocal cords) contain elastic ligaments that vibrate when skeletal muscles move them into the path of outgoing air. Various sounds, including speech, are produced in this manner.

The cricoid cartilage, the paired cuneiform cartilages, and the paired corniculate cartilages are the remaining cartilages supporting the larynx.

The trachea (windpipe) is a flexible tube, 10 to 12 cm (4 inches) long and 2.5 cm (1 inch) in diameter (Figure 2).

The mucosa is the inner layer of the trachea. It contains mucus‐producing goblet cells and pseudostratified ciliated epithelium. The movement of the cilia sweeps debris away from the lungs toward the pharynx.

The submucosa is a layer of areolar connective tissue that surrounds the mucosa.

Hyaline cartilage forms 16 to 20 C‐shaped rings that wrap around the submucosa. The rigid rings prevent the trachea from collapsing during inspiration.

The adventitia is the outermost layer of the trachea. It consists of areolar connective tissue.

The primary bronchi are two tubes that branch from the trachea to the left and right lungs.

Inside the lungs, each primary bronchus divides repeatedly into branches of smaller diameters, forming secondary (lobar) bronchi, tertiary (segmental) bronchi, and numerous orders of bronchioles (1 mm or less in diameter), including terminal bronchioles (0.5 mm in diameter) and microscopic respiratory bronchioles. The wall of the primary bronchi is constructed like the trachea, but as the branches of the tree get smaller, the cartilaginous rings and the mucosa are replaced by smooth muscle.

Alveolar ducts are the final branches of the bronchial tree. Each alveolar duct has enlarged, bubblelike swellings along its length. Each swelling is called an alveolus. Some adjacent alveoli are connected by alveolar pores.

The respiratory membrane consists of the alveolar and capillary walls. Gas exchange occurs across this membrane. Characteristics of this membrane follow:

Type I cells are thin, squamous epithelial cells that constitute the primary cell type of the alveolar wall. Oxygen diffusion occurs across these cells.

Type II cells are cuboidal epithelial cells that are interspersed among the type I cells. Type II cells secrete pulmonary surfactant (a phospholipid bound to a protein) that reduces the surface tension of the moisture that covers the alveolar walls. A reduction in surface tension permits oxygen to diffuse more easily into the moisture. A lower surface tension also prevents the moisture on opposite walls of an alveolus or alveolar duct from cohering and causing the minute airway to collapse.

Alveolar macrophage cells (dust cells) wander among the other cells of the alveolar wall, removing debris and microorganisms.

The answer is lungs. Your welcome
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