Which property of matter is conserved in chemical reactions and shown by balanced equations?
O mass
O volume

O density
O shape

Explanation:

[tex]\longmapsto\: \red{ hello \: mate}[/tex]

OPTION (C) 3

is the angle of refraction

Answer:

Option C. 3

Explanation:

Refraction is the change in direction of light passing from one medium to another. Angle 1 and 2 are reflection due to the bouncing of light.

Answer:B

Explanation:sorry they removed my answer for some reason.

Answer: B

Explanation: Sorry these brainly trolls deleted my first one

Answer:

(B)

Explanation:

Time = change of velocity ÷ acceleration

= (6-0) ÷ 5

= 1.2

1.2 s it take for an object accelerating at a constant rate of 5 m/s to change its velocity from 0 to 6 m/s.

Hence, the correct option is D.

To calculate the time it takes for an object to change its velocity from 0 to 6 m/s, we can use the formula:

time = change in velocity / acceleration

Given that the change in velocity (Δv) is 6 m/s and the acceleration (a) is 5 m/s², we can plug these values into the formula:

time = 6 m/s / 5 m/s²

time = 1.2 seconds

Therefore, 1.2 s it take for an object accelerating at a constant rate of 5 m/s to change its velocity from 0 to 6 m/s.

Hence, the correct option is D.

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#SPJ2

Answer:

Heat is a form of energy. It is measured in Joules. ... The temperature of an object relates to both the kinetic energy of its particles and the number of particles. Temperature is the average kinetic energy of the particles in a substance.

Explanation:

Answer:

787.5m/s

Explanation:

Speed = wavelength x frequency

speed = 2.25m x 350 Hz

= 787.5m/s

Answer:

1. Two bright bands would appear on the screen in line with the slits.

2. Waves that make up the radiation collide with each other so that they add together or cancel each other out.

3. Waves that are in phase constructively interfere to create bright bands.

4. Waves that are out of phase destructively interfere to form dark bands.

5. The spacing between the bright fringes will decrease.

6. 581 nm

Explanation:

Answer:

volume , mass

Explanation:

the 3 basic properties of a matter is volume, mass and shape.

(1.a) The surface area being vibrated by the time the sound reaches the listener is 5,026.55 m².

(1.b) The intensity of the sound wave as it reaches the person listening is 0.02 W/m².

(1.c) The relative intensity of the sound as heard by the listener is 103 dB.

(2.a) The speed of sound if the air temperature is 15⁰C is 340.3 m/s.

(2.b) The frequency of the sound heard by the suspect is 614.3 Hz.

The surface area being vibrated by the time the sound reaches the listener is calculated as follows;

A = 4πr²

A = 4π x (20)²

A = 5,026.55 m²

The intensity of the sound is calculated as follows;

I = P/A

I = (100) / (5,026.55)

I = 0.02 W/m²

[tex]B = 10log(\frac{I}{I_0} )\\\\B = 10 \times log(\frac{0.02}{10^{-12}} )\\\\B = 103 \ dB[/tex]

[tex]v= 331.3\sqrt{1 + \frac{T}{273} } \\\\v = 331.3\sqrt{1 + \frac{15}{273} } \\\\v = 340.3 \ m/s[/tex]

The frequency of the sound heard is determined by applying Doppler effect.

[tex]f_o = f_s(\frac{v \pm v_0}{v \pm v_s} )[/tex]

where;

[tex]f_0 = f_s(\frac{v-v_0}{v- v_s} )[/tex]

[tex]f_0 = 512(\frac{340.3 - 10}{340.3 - 65} )\\\\f_0 = 614.3 \ Hz[/tex]

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Answer:

Helium, Water, Glass, Diamond

Explanation:

light travels slowest though a diamond

Answer:

Forces on the test (test is positive) charge

Σ Fx = 0       net result of x-compoment charges is zero

Σ Fy = 2 F sin θ      where F is the force due to the distance of the test charge from one of the charges and sin θ  is the component of that force that is perpendicular to the line separating the charges

The direction of the force is perpendicular to the line separating the two given charges

Answer:

Mass

Explanation:

In the core of the red giant, helium fuses into carbon. All stars evolve the same way up to the red giant phase. The amount of mass a star has determines which of the following life cycle paths it will take from there. The life cycle of a low mass star (left oval) and a high mass star (right oval).May 7, 2015

Answer:

it can be used for communication, industrial application and also for instrumentation application

(a) The frequency of the motion after the collision is 0.71 Hz.

(b) The maximum angular displacement of the motion after the collision is 16.3⁰.

The speed of the 2.2 kg ball which was initially 10 cm higher that 2.7 kg ball is calculated as follows;

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 0.1)

v = 1.4 m/s

The final speed of both balls after the collision is determined from the principle of conservation of linear momentum.

Pi = Pf

m₁v₁ + m₂v₂ = vf(m₁ + m₂)

2.2(1.4) + 2.7(0) = vf(2.2 + 2.7)

3.08 = 4.9vf

vf = 3.08/4.9

vf = 0.63 m/s

P.E = K.E

[tex]mgh_f = \frac{1}{2} mv_f^2\\\\h_f = \frac{v_f^2}{2g} \\\\h_f = \frac{(0.63)^2}{2(9.8)} \\\\h_f = 0.02 \ m[/tex]

The maximum angular displacement of the balls after the collision is calculated as follows;

[tex]cos \theta = \frac{L - h_f}{L} \\\\cos\theta = \frac{0.5 - 0.02}{0.5} \\\\cos\theta = 0.96\\\\\theta = cos^{-1}(0.96)\\\\\theta = 16.3 \ ^0[/tex]

[tex]f = \frac{1}{2\pi} \sqrt{\frac{g}{L} } \\\\f = \frac{1}{2\pi } \sqrt{\frac{9.8}{0.5} } \\\\f = 0.71 \ Hz[/tex]

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Hi there!

Recall the following relationship:
[tex]E = -\frac{dV}{dx}[/tex]

E = Electric field strength (V/m)
V = Potential Difference (V)

Take the derivative of the given electric potential equation using the power rule:
[tex]\frac{d}{dx}x^n = nx^{n-1}[/tex]

[tex]-\frac{dV}{dx} = -(3 \cdot 3 \cdot x^2) = -9x^2[/tex]

Evaluate at x = 2:
[tex]E(2) = -9(2^2) = \boxed{-36 \frac{V}{m}}[/tex]

**The magnitude of the field strength would simply be 36 V/m.

Answer:

They eat Himalayan blue sheep, boar, deers, wild mountain goats, pikas etc.

Explanation:

Answer:

Explanation:

Because we assume the pendulum is a "mathematical pendulum" (neglecting the moment of inertia of the bob), we can find:

[tex]T=2\pi\sqrt{\frac{L}{g}} \rightarrow 4=2\pi\sqrt{\frac{L}{9.81}} \rightarrow \frac{4}{\pi^{2}}=\frac{L}{9.81} \rightarrow L \approx 3.97 m[/tex]

By using the [tex]y=A\sin(\omega t) \rightarrow v = \frac{dy}{dt}=\omega A \cos\omega t = \omega\sqrt{A^{2}-y^{2}}[/tex]

The mean position is the position when y = 0, so:

[tex]\omega = \frac{2\pi}{T}=\frac{2\pi}{4}=0.5\pi[/tex] rad/s

and [tex]v = \omega A \rightarrow A=\frac{40}{0.5\pi}=\frac{80}{\pi}[/tex] in centimeters (cm).

Answer: I would buy the thermometer with the most features because they all cost the same price so why not you getting more than what you are paying for than buying something the same but with less feature and things it can do for the same price.

Hope this helps :) If so brainliest would mean alot thanks!

Explanation:

A Vernier caliper has total of four jaws, with two upper jaws used for measuring the internal distances and two lower jaws for measuring the internal distances of objects. The two upper jaws are the smaller jaws of the vernier that are used to measure the internal distances between two parallel sides of an object or an internal diameter.

Answer:

i beleave cuz of the Earth is spherical

Explanation:

build a fence.....................

Answer:

a water is heating up

Explanation:

the water's temperature is inceasing

(a) At a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

(b) If the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.

The effect of height  and gravity on speed on the given planet Epislon is determined by applying the principle of conservation of mechanical energy as shown below;

ΔK.E = ΔP.E

¹/₂m(v²- u²) = mg(hi - hf)

¹/₂(v²- u²) = g(0 - hf)

v² - u² = -2ghf

v² = u² - 2ghf

where;

when u² = 2gh, then v² = 0,

when gravity reduces, u² > 2gh, and v² > 0

Thus, at a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

v² = u² - 2ghf

where;

Since g on Epislon is less than 9.8 m/s² of Earth;

5² - 2ghf > 3 m/s

Thus, if the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.

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The speed of the block after it has moved the given distance away from the initial position is 1.1 m/s.

The angular speed of the pulley after the block m1 fall through a distance, d, is obatined from conservation of energy and it is given as;

K.E = P.E

[tex]\frac{1}{2} mv^2 + \frac{1}{2} I\omega^2 = mgh\\\\\frac{1}{2} m_2v_0^2 + \frac{1}{2} \omega^2(m_1R^2_2 + m_2R_2^2) + \frac{1}{2} \omega^2( \frac{1}{2} MR_1^2 + \frac{1}{2} MR_2^2) = m_1gd- \mu_km_2gd\\\\\frac{1}{2} m_2v_0^2 + \frac{1}{2} \omega^2[R_2^2(m_1 + m_2)+ \frac{1}{2} M(R_1^2 + R_2^2)] = gd(m_1 - \mu_k m_2)\\\\[/tex]

[tex]\frac{1}{2} m_2v_0 + \frac{1}{4} \omega^2[2R_2^2(m_1 + m_2) + M(R^2_1 + R^2_2)] = gd(m_1 - \mu_k m_2)\\\\2m_2v_0 + \omega^2 [2R_2^2(m_1 + m_2) + M(R^2_1 + R^2_2)] = 4gd(m_1 - \mu_k m_2)\\\\\omega^2 [2R_2^2(m_1 + m_2) + M(R^2_1 + R^2_2)] = 4gd(m_1 - \mu_k m_2) - 2m_2v_0^2\\\\\omega^2 = \frac{ 4gd(m_1 - \mu_k m_2) - 2m_2v_0^2}{2R_2^2(m_1 + m_2) + M(R^2_1 + R^2_2)} \\\\\omega = \sqrt{\frac{ 4gd(m_1 - \mu_k m_2) - 2m_2v_0^2}{2R_2^2(m_1 + m_2) + M(R^2_1 + R^2_2)}} \\\\[/tex]

Substitute the given parameters and solve for the angular speed;

[tex]\omega = \sqrt{\frac{ 4(9.8)(0.7)(0.365 \ - \ 0.25\times 0.825) - 2(0.825)(0.82)^2}{2(0.03)^2(0.365 \ + \ 0.825)\ \ +\ \ 0.35(0.02^2\ + \ 0.03^2)}} \\\\\omega = \sqrt{\frac{3.25}{0.00214\ + \ 0.000455 } } \\\\\omega = 35.39 \ rad/s[/tex]

The linear speed of the block after travelling 0.7 m;

v = ωR₂

v = 35.39 x 0.03

v = 1.1 m/s

Thus, the speed of the block after it has moved the given distance away from the initial position is 1.1 m/s.

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Answer:

4 J

Explanation:

Original KE

Mass increases x 2

Velocity decreases x 4

Answer:

Explanation:

The point P is influenced by two electric fields, that are from Q1 and Q2. Because Q1 is a positive point charge, the E-fields is going to the right and the E-fields from Q2 is going to the left because of negative point charge. So:

[tex]E_{1}=\frac{kQ_{1}}{R_{1}^{2}}[/tex]

[tex]E_{2}=\frac{kQ_{2}}{R_{2}^{2}}[/tex]

Where R1 = 2 + 3 = 5 m, and R2 = 3 m. With k = [tex]k=9\times 10^{9}[/tex] in [tex]Nm^{2}/C^{2}[/tex], we can obtain:

[tex]E_{1}=(9\times 10^{9})\frac{500\times10^{-6}}{25}=180\times 10^{3}[/tex] N/C (+)

[tex]E_{2}=(9\times 10^{9})\frac{100\times 10^{-6}}{9}=100\times 10^{3}[/tex] N/C (-)

So: the Electric Field at P : [tex]E_{P}=E_{1}-E_{2}=(180-100)\times 10^{3}=8\times 10^{4}[/tex] N/C in magnitude

Answer:

The mechanical advantage would depend on where the load force and the balancing force were placed on the stick

MA = (50 - F) / (L - 50)

Supoose the balancing force was placed at zero and the load at 75 cm

then MA = (50 - 0) / (75 - 50) = 50 / 25 = 2

or the balancing force was applied at 10 cm and the load force was applied at 60 cm then

MA =  (50 - 10) / (60 - 50) = 40 / 10 = 4