Which point on the graph would have the most kinetic energy?
-Which point on the graph would have the least kinetic energy?
-What point on the graph would have just a little less potential energy than point E?
-What point on the graph would have just a little more potential energy than point F?
-What point on the graph would have just a little less potential energy than point G?
Answers
The total mechanical energy is kinetic energy + potential energy, so we can look at the object's potential energy to determine the place where it has maximum and minimum kinetic energy.
Potential energy is determined by the equation PE = mgh, where the height is the only changing variable here. Therefore, we look at the height to answer these questions.
Which point on the graph would have the most kinetic energy?
The point where the object's potential energy is the lowest, aka where its height is the lowest. Point D would have the most kinetic energy.Which point on the graph would have the least kinetic energy?
The point where the object's potential energy is the highest, aka where its height is the highest. Point A would have the least kinetic energy.What point on the graph would have just a little less potential energy than point E?
Look at the point that is just below point E. Point D has just a little less potential energy than point E.What point on the graph would have just a little more potential energy than point F?
Look at the point that is just above point F. Point B has just a little more potential energy than point F.What point on the graph would have just a little less potential energy than point G?
Look at the point that is just below point G. Point B has just a little less potential energy than point E.Related Questions
I need help with this please
Answers
Answer:
i think its 100
Explanation:
Radioactive isotopes can be used to find the age of rocks, fossils, or other artifacts. Carbon-14 has a half-life of 5,730 years. Suppose a sample of charcoal from a primitive fire pit contains one eighth of its original amount of carbon-14. How old is the sample?
Answers
Answer:
1/8 = (1/2)^3
This implies the sample has decayed for 3 half lives
3 * 5730 yrs = 17,200 years
Assume that the body's muscle mechanism can be approximated by a spring with a uniform continuous mass distribution that follows Hooke's law. Concerning this,
A) find the effective mass of the spring with mass m.
Then, estimate the potential energy which can be mechanically stored in B) the muscles of each arm, and
C) the muscles of each leg,
and estimate the spring constant of
D) each arm muscles, and
E) each leg muscle.
F) Now, could estimate the speed of a runner by using these results?
Answers
Based on Hooke's law, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.
What is the spring constant?The spring constant or stiffness constant of an elastic spring is constant which describes the extent a bit forceapplied to an elastic spring will extend it.
Spring constant, K = force/extensionAssuming, a body's muscle mechanism is a spring obeying Hooke's law, the effective mass of the spring with mass m is 1/3 of the mass of the spring = m/3
The potential energy that can be stored = ke^2 / 2
where K is spring constant and e is the extension produced.
Therefore, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.
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A student is investigating acceleration using objects with different masses. She claims that
mass affects the acceleration of objects when the force remains constant. The student
creates a graph to represent the findings of her investigation.
acceleration
mass
Which argument best supports the student's claim?
O As mass decreases, the accleration of an object decreases because less force is required.
As mass increases, the acceleration of an object increases because less force is required.
O As mass increases, the acceleration of an object decreases because more force is required.
As mass decreases, the acceleration of an object increases because more force is required.
Answers
Answer:
As mass increases, the acceleration of an object decreases because more force is required.
Explanation:
The question states that the student made a mass acceleration graph with the force being constant, if you think about this in everyday life, would pushing a 30 kg box be easier than that of a 15 kg box? Obviously not because if you have the same force for both of them the 15 kg box would have a greater acceleration than the 30 kg one (assuming they are on the same surfaces and the same amount of force is applied.)
Therefore we can say that as the mass of an object increases the acceleration must decrease because we need more force to push the object.
If you have a mass of 0.9kg and a velocity 12 m/s what is your momentum?
Answers
= mass x velocity
= 0.9 x 12
= 10.8 kgm/s.
Mrs. Martin is holding a ball from a height of 3.2 m that has the potential energy of 23 J, calculate the mass of the ball.
Answers
Answer:
0.73kg
Explanation:
Potential gravitational energy is equal to [tex]Pe=mgh[/tex], where Pe is potential gravitational energy, m is mass in kilograms, g is gravity in m/s^2 and h is height in meters.
Substitute:
[tex]Pe=mgh\\23=m*9.8*3.2\\23=31.36m\\0.73=m[/tex]
A potter's wheel is spinning with an initial angular velocity of 11 rad/s . It rotates through an angle of 80.0 rad in the process of coming to rest.
What was the angular acceleration of the wheel?
How long does it take for it to come to rest?
Answers
Hi ! I will help you to discuss about Proportionally Changes in Circular Motion. The analogy of proportionally changes in circular motion is same as the analogy of proportionally changes in direct motion. Here you will hear again the terms acceleration and change in speed, only expressed in the form of a certain angle coverage. Before that, in circular motion, it is necessary to know the following conditions:
1 rotation = 2π rad1 rps = 2π rad/s1 rpm = [tex] \sf{\frac{1}{60} \: rps}[/tex] = [tex] \sf{\frac{1}{30}\pi \: rad/s}[/tex] Formula UsedThe following equations apply to proportionally changes circular motion:
Relationship between Angular Acceleration and Change of Angular Velocity[tex] \boxed{\sf{\bold{\omega_t = \omega_0 + \alpha \times t}}}[/tex]
With the following conditions:
[tex]\sf{\omega_t}[/tex] = final angular velocity (rad/s)[tex]\sf{\omega_0}[/tex] = initial angular velocity (rad/s)[tex]\sf{\alpha}[/tex] = angular acceleration (rad/s²)t = interval of the time (s)Relationship between Angular Acceleration and Change of [tex]\sf{\theta}[/tex] (Angle of Rotation)[tex] \boxed{\sf{\bold{\theta = \omega_0 \times t + \frac{1}{2} \times \alpha \times t^2}}}[/tex]
Or
[tex] \boxed{\sf{\bold{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta}}}[/tex]
With the following condition :
[tex]\sf{\theta}[/tex] = change of the sudut (rad)[tex]\sf{\alpha}[/tex] = angular acceleration (rad/s²)t = interval of the time (s)[tex]\sf{\omega_t}[/tex] = final angular velocity (rad/s)[tex]\sf{\omega_0}[/tex] = initial angular velocity (rad/s) Problem SolvingWe know that :
[tex]\sf{\omega_t}[/tex] = final angular velocity = 0 rad/s >> see in the sentence "in the process of coming to rest."[tex]\sf{\omega_0}[/tex] = initial angular velocity = 11 rad/s[tex]\sf{\theta}[/tex] = change of the sudut = 80.0 radWhat was asked :
[tex]\sf{\alpha}[/tex] = angular acceleration = ... rad/s²t = interval of the time = ... sStep by step :
[tex]\sf{\alpha}[/tex] = ... rad/s²[tex] \sf{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta} [/tex]
[tex] \sf{0^2= (11)^2 + 2 \times \alpha \times 80} [/tex]
[tex] \sf{0 = 121 + 160 \alpha} [/tex]
[tex] \sf{-160 \alpha = 121} [/tex]
[tex] \sf{\alpha = \frac{121}{-160}}[/tex]
[tex] \sf{\alpha = -0.75625 \: rad/s^2 \approx \boxed{-0.76 \: rad/s^2}}[/tex]
t = ... s[tex] \sf{\alpha = \frac{\omega_0 - \omega_t}{t}}[/tex]
[tex] \sf{-0.76 = \frac{0 - 11}{t}}[/tex]
[tex] \sf{-0.76t = -11}[/tex]
[tex] \sf{t = \frac{- 11}{-0.76}}[/tex]
[tex] \boxed{\sf{t \approx 14.474 \: s}}[/tex]
ConclusionSo :
The angular acceleration of the wheel approximately -0.76 rad/s² or proportionally as deceleration approximately 0.76 rad/s.It need approximately 14.474 s to come to rest.Which nucleus completes the following equation?
Answers
Answer:
I think that CL IS THE ONLY BEST ANSWER
Explanation:
PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE
if a copper coin with a volume of exactly 50 cubic cm is dropped into the volume of water 4cubic cm,how much water will be overflown (water is half way of the can)
Answers
Answer:
50 cubic cm
Explanation:
As the water displaces 50 cubic centimeters the amount of water that must leave the container for it to be able to be dropped into it is also 50 cubic as the water which was in its place must have gone somewhere.
In the fishbowl, the glass, water, rocks, and plastic plants are in thermal equilibrium. This situation means the temperature of the rocks is...
Answers
Residents of a community currently pay a fee for recreational services in their neighborhood, such as tennis courts, running trails, a pool. To assess whether there is support for raising a fee for the upcoming summer, a random sample of 50 residents is contracted and asked this question: “Would you support a $10 increase in the recreational fee to support programs for the health and well-being of the children in the community?” Of the 50 residents contacted, 42 approved of the fee increase. Which statement describes a likely source of bias present in survey results?
Answers
A likely source of bias in the survey is undercoverage bias because some parts of the community may not be represented in the survey results.
Bias present in the surveyThe bias present in the survey may lead to error in the result obtained from the random sampling survey.
Source of bias in the surveyOne of the likely source of bias in the survey is undercoverage.
It is not possible to ascertain the accurate opinion of the entire community from the 50 residents chosen for the survey.
Thus, a likely source of bias present in survey is undercoverage bias because some parts of the community may not be represented in the survey results.
Learn more about undercoverage bias here: https://brainly.com/question/21977459
Answer:
B. Question wording bias may be present because the question leads those responding toward a certain response.
Explanation:
A turntable is switched from 11.3 rad/s to 1.9 rad/s, and the platter goes through an angle of 17.95 radian in reaching the new angular speed. What is the angular acceleration of the platter?
Answers
Hi there!
We can use the angular equivalent of the following kinematic equation:
[tex]\omega_f^2 = \omega_i^2 + 2\alpha \theta[/tex]
ωf = final angular velocity (1.9 rad/s)
ωi = initial angular velocity (11.3 rad/s)
α = angular acceleration (? rad/s²)
θ = angular displacement (17.95 rad)
We can rearrange the equation to solve for angular acceleration.
[tex]\omega_f^2 - \omega_i^2 = 2\alpha \theta\\\\\alpha = \frac{\omega_f^2 - \omega_i^2}{2\theta}[/tex]
Plug in the given values and solve.
[tex]\alpha = \frac{1.9^2 - 11.3^2}{2(17.95)} = \boxed{3.456 \frac{rad}{s}}[/tex]
15. A pattern of weather and
climate over three months is called a
Answers
Answer:
Explanation:
weather pattern
A pattern of weather over three months is called a climate.
What is climate?Climate is the long-term pattern of weather in a particular area. Weather can change from hour-to-hour, day-to-day, month-to-month or even year-to-year. A region's weather patterns, usually tracked for at least 30 years, are considered its climate.
Weather refers to short-term changes in the atmosphere, climate describes what the weather is like over a long period of time in a specific area.
A pattern of weather over three months is called a climate.
To study more about climate refer to the link:
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list down the general of the office of guardian and tutor
Answers
Answer:
legal guardians, the four types: personal guardians, financial guardians, conservators, and pet “guardians”
A garage hoist lifts a truck up 2 m above the ground in 15seconds.Find the power delivered to the truck (given 1000kg as the mass of the truck and gas 9.81m/s
Answers
The power delivered to the truck of mass 1000 kg that was lifted by a garage hoist, 2 m high above the ground in 15 seconds is 1308 W.
What is power?
Power can be deifned as the rate at which work is done.
To calculate the power delivered to the truck, we use the formula below.
Formula:
P = mgh/t.............. Equation 1Where:
P = Power delivered to the truckm = Mass of the truckh = Heightg = Acceleration due to gravityt = timeFrom the question,
Given:
m = 1000 kgh = 2 mt = 15 secondsg = 9.81 m/s²Subsitute these values into equation 1
P = (1000×2×9.81)/15P = 19620/15P = 1308 WHence, The power delivered to the truck of mass 1000 kg that was lifted by a garage hoist, 2 m high above the ground in 15 seconds is 1308 W.
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what are the two most important traits between a whale and a shark?
Answers
Answer:
Both are aquatic animals and are hunters
Explanation:
What is the momentum of a 35–kilogram cart moving at a speed of 1.2 meters/second
Answers
Answer:
42
Explanation:
P = M × V
so
P = 35 × 1.2
P = 42
Answer:
42kg•m/s
Explanation:
p=m*v
A ball is thrown directly upwards at 25 ms and the same time another ball is released from height of loom. At what height and time will the balls meets?
Answers
Answer:
Explanation:
When the balls meets, the time should be the same, let say t.
For the first ball (released from a loom):
[tex]\bar{h}=\frac{1}{2}gt^{2}[/tex] (Free fall motion) ([tex]\bar{h}[/tex] = the distance travelled by the first ball, measured from the loom)
So, we can find that [tex]\bar{h}=\frac{1}{2}(10t^{2})=5t^{2}[/tex]
For the second ball (which is thrown directly upwards):
[tex]y=v_{o}t-\frac{1}{2}gt^{2} = 25t-5t^{2}[/tex]
Because the height of the loom is h :
[tex]h=\bar{h}+y[/tex]
[tex]h=25t[/tex]
So, the time when two balls meets is : [tex]t=\frac{h}{5}[/tex] (In this question, the height of the loom h is not declared). When the height of the loom is known, you can calculate the time and the value of [tex]\bar{h}[/tex] or y
You perform an experiment to test how far a cannon will shoot a performer at
different angles. The data are shown below.
Angle
Distance (feet)
110
32°
36°
120
40°
128
440
133
48°
127
52
119
56°
109
60°
100
64°
91
68°
77
72°
63
At which angle will the performer travel the longest distance?
Answers
Answer:
44°
Explanation:
Look for the longest distance under the 'Distance ' column....look to the left to find the corresponding angle
Table clearly shows that the longest distance (133 ft) occurs at angle of 44°
What is the cycle of a breaststroke?
Answers
Answer:
Breaststroke can be divided up into 4 distinct phases, which consists of the out sweep, in sweep, breathing phase, and lunge, extension, or recovery phase.
Explanation:
pa follow po
In addition to their remarkable top speeds of almost 60 mph, cheetahs have impressive cornering abilities. In one study, the maximum centripetal acceleration of a cheetah was measured to be 18 m/s2. What minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?
Answers
coefficient of static friction is 1.7329
Explanation:
given data
velocity = 60 mph
acceleration = 17 m/s²
to find out
coefficient of static friction
solution
we will apply here centripetal force equation
that is
m×v²/r = µ × m × g ..................1
here v²/r is centripetal acceleration and m is mass and µ is coefficient static friction so
µ = a / g
µ = 17 / 9.81
µ = 1.7329
so coefficient of static friction is 1.7329
The power in an electrical current is given by the equation
Answers
Answer:
P = VI
Explanation:
the power is equal to the current × voltage
Answer:
P = V • I
Explanation:
Power = Voltage • Current
A kitten sits in a lightweight basket near the edge
Answers
Answer:
So where's the problem now?
A kitten is just sitting
A rock is suspended from the lower end of a light string. When the rock is totally immersed in water, the tension in the string is 1.20 N. When the rock is totally immersed in ethanol, the tension in the string is 1.60 N. Calculate the weight of the rock.
Answers
For a rock is suspended from the lower end of a light string, the weight of the rock is mathematically given as
W = 3.10 N
What is the weight of the rock.?Generally, the equation for the W = Fh1+ is mathematically given as
W = Fh+T1
Where
PiVg+T1 = P2V9+T
(1000) V(9.8) + 1.2 = (790) V(9.8) + 1.6
V = 1.944* 10^-4 m3
In conclusion
W = Fh+T1
W = (1000) (1.944 * 10-4) (9.8) + 1.2
W = 3.10 N
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For the statements based on whether they are described as outcomes of results from thermal energy being added or removed particles move faster particles move slower temperature increases temperature decreases kinetic energy increases kinetic energy decreases thermal energy added thermal energy removed
Answers
Thermal energy removed: particles move slower, temperature decreases, kinetic energy decreases
List three methods of energy transport in nature and explain how the energy is being transferred in each of those methods. Which two are means by which energy is transported inside the Sun?
This question is for my college astronomy class!
Answers
First normal transportation is the light energy of sun is transmitted to our earth .
Next for transportation inside sun they are
Fusion and fissionFusion means when two hydrogen atoms reacts to form helium nucleus .
Fission means when one nucleus is broken into two or more nucleus
Explanation:
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A total charge of Q coulomb is uniformly distributed along a rod 40cm in length.find find the electric field intensity 20cm away from the rod along its perpendicular bisector?
Answers
For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length, the electric field intensity 20cm away from the rod is mathematically given as
E1=1.598*10^11v/m
Generally, the equation for the initial electric field intensity is mathematically given as
[tex]dEp=\int{kd/r}cosd\theta[/tex]
Therefore
[tex]e1=kd/r{sin\theta2+sinR1}[/tex]
Hence
[tex]E1=(9*10^9/20*10^{-2})({sin45+sin45})*B/40*10^-2[/tex]
E1=B*9*10^{13})/(10*110)*[tex]\sqrt{2}[/tex]
E1=1.598*10^11v/m
In conclusion, the electric field intensity
E1=1.598*10^11v/m
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The current in the wires of a circuit is 60.0 milliAmps. If the
voltage impressed across the ends of the circuit were tripled
(with no change in its resistance), then its new current would
be milliAmps.
Answers
Answer:
180 m amp
Explanation:
V = IR
v/r = i mutiply both sides by
3
3v / r = 3 i so the current will triple to 180 mAmp
An unknown fluid flows at a speed of 31 m/s. Suppose the fluid has a mass of 47 kg runs at this speed. What is the fluid’s kinetic energy?
Answers
Answer:
22583.5J
Explanation:
KE=1/2 mv^2
=1/2*47Kg*(31m/s^2)
=23.5Kg * 961m/s^2
=22583.5J
A parachute falling to the ground.
Answers
Answer:
a parachute falling to the ground is uniform