Answer:
Plastic Glass and Paper
Explanation:
i just took the assignment
Glass, paper, and plastic are good insulators. The material that does not allow the flow of current through them is known as the insulators.
What are insulators?An electrical insulator is a substance that prevents electric current from flowing freely. The electrons in the insulator's atoms are closely bonded and cannot travel easily.
Other materials, such as semiconductors and conductors, carry electricity more easily. The characteristic that characterizes an insulator.
Gold and silver are good conductors of electricity. While glass, paper, and plastic are good insulators.
Hence glass, paper, and plastic are good insulators.
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A runner begins from rest at the starting line and travles for 6.5 seconds, a runner reaches a speed of 13.4 m/s what is the runners acceleration?
The acceleration of the runner in the given time is 2.06m/s².
Given the data in the question;
Since the runner begins from rest,
Initial velocity; [tex]u = 0[/tex]Final velocity; [tex]v = 13.4m/s[/tex]Time elapsed; [tex]t = 6.5s[/tex]Acceleration of the runner; [tex]a = \ ?[/tex]
Velocity is the speed at which an object moves in a particular direction.
Acceleration is simply the rate of change of the velocity of a particle or object with respect to time. Now, we can see the relationship from the First Equation of Motion
[tex]v = u + at[/tex]
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
To determine the acceleration of the runner, we substitute our given values into the equation above.
[tex]v = u + at\\\\13.4m/s = 0 + (a * 6.5s)\\\\13.4m/s = a * 6.5s\\\\a = \frac{13.4m/s}{6.5s}\\ \\a = 2.06m/s^2[/tex]
Therefore, the acceleration of the runner in the given time is 2.06m/s².
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If you wanted to melt ice, then heat it up, and get the water to just barely vaporize, how many equations would you need to solve for the energy used in this procedure?
Two equations will be needed to solve for the energy used in this procedure.
What is Energy?This is defined as the ability or capacity to do work. Ice being converted to vapor requires energy and the equations are seen below:
H₂O₍s₎ ⇒ H₂O₍l₎
H₂O₍l₎ ⇒ H₂O₍g₎
These are the equations which are used to calculate energy with heat being involved in both reactions.
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13. A mass of 1 kg undergoes simple harmonic motion with amplitude of 1 m. If the period of the oscillation is 1 s, calculate the internal energy of the system.
Please show all of your work.
first we need omega
T=1sHence
[tex]\\ \rm\rightarrowtail \omega=\dfrac{2\pi}{T}=2\pi[/tex]
Now
Total energy:-
[tex]\\ \rm\rightarrowtail \dfrac{1}{2}m\omega ^2A^2[/tex]
[tex]\\ \rm\rightarrowtail \dfrac{1}{2}(1)(2\pi)^2(1)^2[/tex]
[tex]\\ \rm\rightarrowtail \dfrac{1}{2}(4\pi ^2[/tex]
[tex]\\ \rm\rightarrowtail 2\pi ^2[/tex]
[tex]\\ \rm\rightarrowtail 2(3.14)^2[/tex]
[tex]\\ \rm\rightarrowtail 19.72J[/tex]
At a distance of 1.0 A.U. The earth takes 1.0 year to travel around the sun how far away is a planet that takes 64 years ro go around the sun
Answer:
This is from another brainly question so I hope this helps :)
The earth takes 1 year to orbit the sun and is about 150, 000, 000km. Given that, use the rule of 3 to find your answer:
1 - 150, 000, 000
64 - x
(150, 000, 000 * 64) / 1= x
9, 600, 000, 000 / 1
9, 600, 000, 000 km.
A planet located 9, 600, 000, 000 km from the sun takes about 64 years to complete its orbit around the sun.
If you create an equilibrium mixture from f e 3 and s c n − ions, adding c l − ions will choose. Highlight_off because choose. Highlight_off
Since chloride ions are not part of the ionic equilibrium, addition of chloride ions will only increase the concentration of the anions in the solution.
What is ionic equilibrium?An ionic equilibrium is an equilibrium that exists between two or more ions in an aqueous solution.
The ionic equilibrium between iron (iii) ion and thiocyanate ions is given below:
[tex]Fe^{3+}\rightleftharpoons SC \: N^{-}[/tex]
From the principle of equilibrium, addition of either ions in the ionic equilibrium will alter equilibrium position to the left or right.
Addition of chloride ions, Cl- which is not a part of the ionic equilibrium will only increase the concentration of the anions in the solution.
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The chloride ions are not part of the ionic equilibrium, adding them to the solution will merely raise the concentration of anions.
What is equilibrium?When a chemical reaction does not convert all reactants to products, it reaches equilibrium. Many processes attain a state of balance, or dynamic equilibrium, in which both reactants and products are present.
The following is the ionic equilibrium between iron (III) ion+ and thiocyanate ions:
[tex]\rm Fe^{3+} \rightleftharpoons SC \ N^{-}[/tex]
The addition of either ion in the ionic equilibrium will shift the equilibrium position to the left or right, according to the principle of equilibrium.
The inclusion of chloride ions, Cl-, which are not components of the ionic equilibrium, increases the levels of anions in the solution.
Thus, the chloride ions are not part of the ionic equilibrium, adding them to the solution will merely raise the concentration of anions.
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the earth exerts a gravitational force of 850N on John. What is Johns mass in kg
Answer:
86.73 kg
Explanation:
Remember that F=mg
Let's plugin our numbers
850N=m9.8m/s^2
850N=9.8m/s^2m
86.73=m
If a satelite with a mass of 9 x 10^2 kg is placed in an orbit around a planet with a mass of 6 x 10^20 kg, at a speed of 17000 m/s, find the distance from the center of the planet to the satelite.
Hi there!
We can begin by deriving an equation for the orbital radius.
For an object orbiting the earth, it is experiencing a centripetal force due to the force of gravitation.
Recall Newton's Law of Universal Gravitation:
[tex]F_g = \frac{Gm_1m_2}{r^2}[/tex]
G = Gravitational Constant (6.67 × 10⁻¹¹ Nm²/kg²)
m = masses (kg)
r = radius (m)
This is equivalent to the satellite's centripetal force experienced:
[tex]F_c = \frac{m_sv^2}{r}[/tex]
[tex]m_s[/tex] = mass of satellite (kg)
v = velocity (m/s)
r = radius (m)
Set the two equal, and rearrange for the orbital radius of the satellite.
[tex]\frac{Gm_sm_p}{r^2} = \frac{m_sv^2}{r}\\\\\frac{Gm_p}{r} = v^2\\\\r = \frac{Gm_p}{v^2}[/tex]
Notice that the orbital radius of the satellite does NOT depend on the satellite's mass. (we canceled it out).
Now, plug in the given values.
[tex]r = \frac{(6.67\times 10^{-11})(6\times 10^{20})}{17000^2} = \boxed{138.478 m}[/tex]
A builder drops a brick from a height of 15 m above the ground. The gravitational field strength g is 10 N/ kg. What is the speed of the brick as it hits the ground?
The speed of the brick dropped by the builder as it hits the ground is 17.32m/s.
Given the data in the question;
Since the brick was initially at rest before it was dropped,
Initial Velocity; [tex]u = 0[/tex]Height from which it has dropped; [tex]h = 15m[/tex]Gravitational field strength; [tex]g = 10N/kg = 10 \frac{kg.m/s^2}{kg} = 10m/s^2[/tex]Final speed of brick as it hits the ground; [tex]v = \ ?[/tex]
Velocityvelocity is simply the same as the speed at which a particle or object moves. It is the rate of change of position of an object or particle with respect to time. As expressed in the Third Equation of Motion:
[tex]v^2 = u^2 + 2gh[/tex]
Where v is final velocity, u is initial velocity, h is its height or distance from ground and g is gravitational field strength.
To determine the speed of the brick as it hits the ground, we substitute our giving values into the expression above.
[tex]v^2 = u^2 + 2gh\\\\v^2 = 0 + ( 2\ *\ 10m/s^2\ *\ 15m)\\\\v^2 = 300m^2/s^2\\\\v = \sqrt{300m^2/s^2}\\ \\v = 17.32m/s[/tex]
Therefore, the speed of the brick dropped by the builder as it hits the ground is 17.32m/s.
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A metal bar is in the xy-plane with one end of the bar at the origin. a force f⃗ =( 6.88 n )i^+( -2.62 n )j^ is applied to the bar at the point x= 2.88 m , y= 3.70 m .
A metal bar is in the xy-plane with one end of the bar at the origin, [tex]\[r = (3.87 \, \text{m}) \mathbf{i} + (3.21 \, \text{m}) \mathbf{j}\][/tex], [tex]\theta\approx 55.16^\circ\][/tex], magnitude of torque is 22.58 Nm.
a) Position Vector r can be calculated as:
Given:
[tex]\(x = 3.87 \, \text{m}\)[/tex]
y = 3.21 m
The position vector r for the point where the force is applied is:
[tex]\[r = (3.87 \, \text{m}) \mathbf{i} + (3.21 \, \text{m}) \mathbf{j}\][/tex]
b) Magnitude of Torque can be calculated as:
Magnitude of r:
[tex]\[|r| = \sqrt{(3.87 \, \text{m})^2 + (3.21 \, \text{m})^2} \approx 5.019 \, \text{m}\][/tex]
Magnitude of F:
[tex]\[|F| = \sqrt{(6.82 \, \text{N})^2 + (-3.24 \, \text{N})^2}\\\\ \approx 7.610 \, \text{N}\][/tex]
Calculate the dot product of r and F:
[tex]\[r \cdot F = (3.87 \, \text{m}) (6.82 \, \text{N}) + (3.21 \, \text{m}) (-3.24 \, \text{N})\\\\ \approx 16.658 \, \text{N} \cdot \text{m}\][/tex]
Calculate the angle [tex]\(\theta\)[/tex] using the dot product and magnitudes:
[tex]\[\cos(\theta) = \frac{r \cdot F}{|r| \cdot |F|} \\\\= \frac{16.658 \, \text{N} \cdot \text{m}}{(5.019 \, \text{m})(7.610 \, \text{N})}\\\\ \approx 0.5526\][/tex]
[tex]\[\theta \approx \cos^{-1}(0.5526)\\\\ \approx 55.16^\circ\][/tex]
Now calculate the magnitude of the torque using the sine of the angle:
[tex]\[|\tau| = |r| \cdot |F| \cdot \sin(\theta)\\\\ = (5.019 \, \text{m}) (7.610 \, \text{N}) \sin(55.16^\circ)\\\\ \approx 22.58 \, \text{N} \cdot \text{m}\][/tex]
c) Direction of Torque:
According to the right-hand rule, the torque points either into or out of the plane formed by r and F. Its direction is perpendicular to that plane. The sign of the angle determines the precise orientation.
In this case, since [tex]\(\theta \approx 55.16^\circ\)[/tex] is positive (counterclockwise rotation), the torque points out of the plane formed by r and F.
Thus, the direction of the torque is outward from the xy-plane.
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Your question seems incomplete, the probable complete question is:
A metal bar is in the xy-plane with one end of the bar at the origin. A force F=(6.82)i+ -3.24j is applied to the bar at the point x=3.87m , y=3.21m .
What is the position vector r for the point where the force is applied?
a Express your answer in terms of the unit vectors i and j .
b What are the magnitude of the torque with respect to the origin produced by F?
c What are direction of the torque with respect to the origin produced by F?
Use work and energy to find an expression for the speed
of the block in the following figure just before it hits the
floor.(Figure 1)
Since the kinetic energy is equal to the potential energy then the speed of the object is √2gh.
Work and energyThe term work refers to the product of force and distance moved by force while energy is the ability to do work. The question is incomplete as the figure is not shown.
We know that the kinetic energy is equal to the potential energy hence;
mgh = 1/2mv^2
gh= 1/2v^2
v = √2gh
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Which statement explains how the charges on objects determine the electric force between them? (1 point)
O Objects with positive charges repel each other, and objects with negative charges attract each other
O Objects with the same charge attract each other, and objects with opposite charges repel each other
O Objects with positive charges attract each other, and objects with negative charges repel each other.
O Objects with the same charge repel each other, and objects with opposite charges attract each other
Objects with the same charge repel each other, and objects with opposite charges attract each other
Effect of similar charges on each otherAccording to Coulomb, the electric force for charges at rest has the following properties: Like charges repel each other; unlike charges attract. Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges.
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Why wouldn’t you move during an earthquake?
Answer:
So you maybe don't fall, have something fall on you, and for a bunch of different reasons. EARFQUAKES are really dangrous.
Explanation:
Hope this helps you!
The kinetic energy of a javelin is 81 J, and its speed is 9.0 m/s. What is its mass?
A. 0.5 kg
B. 1.0 kg
C. 2.0 kg
D. 9.0 kg
Answer:
2 kg
Explanation:
K.E. = 1/2 m v^2
81 = 1/2 m (9^2)
1 = 1/2 m
m = 2 kg
Velocity of an object of mass 5 kg increases from 3 m/s to 7 m/s on applying a force continuously for 2 s. Find out the force applied. If the duration for which force acts is extended to 5 s, what will be the velocity of the object then?
Answer:
Force=10N
Velocity=13m/s
Explanation:
Given,
Mass = 5kg
initial velocity=3m/s
Final velocity=7m/s
Time=2s
Now acceleration= v-u/t
=7-3/2
=4/2
=2m/s²
So, acceleration=2m/s²
Now,
F=ma
=5*2
=10N
Consider the following processes: The temperature of two identical gases are increased from the same initial temperature to the same final temperature. Reversible processes are used. For gas A the process is carried out at constant volume while for gas B it is carried out at constant pressure. The change in entropy:_________.
i. is greater for B
ii. is the same for A and B
iii. is greater for A only if the initial temperature is high
iv. is greater for A
v. is greater for A only if the initial temperature is low
The entropy at constant pressure is always greater than that at constant volume and the change in entropy for the two processes is greater for gas B.
Second law of thermodynamicsAccording to the second law of thermodynamics, entropy in the isolated system always stays the same or increases.
Since gas does work in isobaric (constant pressure) change processes, the entropy at constant pressure will be greater than that at constant volume.
Thus, for gas A the process is carried out at constant volume while for gas B that is carried out at constant pressure. The change in entropy is greater for gas B.
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3. Describe comets and their orbits in the solar system.
Comets have an extremely eccentric orbit around the Sun. They can travel hundreds of thousands of years through the solar system before returning to the Sun at perihelion. Comets, like all orbiting bodies, obey Kepler's Laws, which state that the closer they get to the Sun, the faster they move.
A comet is a dirty snowball many kilometers across that exists at a considerable distance from the Sun. However, when it gets closer to the Sun, the comet's surface warms up, causing its components to melt and vaporize, resulting in the comet's distinctive tail. The distance between the Earth and the Sun can be measured in comet tails.
Consider a system consisting of three particles: m1 = 4 kg, vector v1 = < 10, -5, 15 > m/s, m2 = 9 kg, vector v2 = < -15, 5, -3 > m/s, m3 = 3 kg, vector v3 = < -24, 36, 18 > m/s.
a) what is the total momentum of this system?
b) what is the velocity of the center of mass of this system?
c) what is the total kinetic energy of this system?
d) what is the translational kinetic energy of this system?
e) what is the kinetic energy of this system relative to the center of mass?
one way to calculate krel is to calculate the velocity of each particle relative to the center of mass, by subtracting the center-of-mass velocity from the particle's actual velocity to get the particle's velocity relative to the center of mass, then calculating the corresponding kinetic energy, then adding up the three relative kinetic energies. however, there is a much simpler way to determine the specified quantity, without having to do all those calculations; think about what you know about the relationships among the various kinds of kinetic energy in a multiparticle system.
The answers to your questions are as listed below
A) The total momentum of the system is : < - 167, 133, 87 > kg m/s
B) Velocity of the center of mass of this system : < - 10.44 , 8.31, 5.44 > m/s
C) Total kinetic energy of the system : 5159.5 J
D) Translational kinetic energy of the system : 1660.84 J
E) kinetic energy relative to the center of mass : 3498.66 J
Given data :
m₁ = 4 kg , V₁ = < 10, -5, 15 > m/s
m₂ = 9 kg, V₂ = < -15, 5, -3 > m/s
m₃ = 3 kg V₃ = < -24, 36, 18 > m/s.
A) Determine the total momentum of the systemTotal momentum = Σ mv
= < 4*10 + 9*(-15) + 3*(-24), 4*(-5) + 9*5 + 3*36, 4*15 + 9 (-3) + 3*18 >
= < - 167, 133, 87 > kg m/s
B) Velocity at the center of mass of this systemVelocity = < - 167 / 16 , 133/ 16, 87/ 16 >
= < - 10.44 , 8.31, 5.44 > m/s
C) Determine the total kinetic energy of the systemTotal Kinetic energy = 1/2 m₁v₁² + 1/2 m₂v₂² + 1/2 m₃v₃² --- ( 1 )
where : v² = v₁² + v₂² + v₃²
therefore
Total kinetic energy = 700 + 1165.5 + 3294
= 5159.5 J
D) Determine the translational kinetic energy of the system
Translational kinetic energy ( Kcm ) = 1/2 ( m₁ + m₂ + m₃ ) * Velocity²
= 1/2 ( 16 ) * ( - 10.44² + 8.31² + 5.44² )
Hence translational kinetic energy = 1660.84 J
E) The Kinetic energy of the system relative to the center of mass
Krel = Ktotal - Kcm
= 5159.5 - 1660.84
= 3498.66 J
Hence we can conclude that the answers to your questions are as listed above.
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does a five pound ball weigh more or less 40000 miles above sea level
It would weigh less bc the higher you are the less gravity there is.
Suppose that two point charges, each with a charge of 1 coulomb are separated by a distance of 1 meter. Determine the magnitude of the electrical force between them
The magnitude of the electrical force between the two identical electrical charges is 8.98755 × 10⁹N.
Given the data in the question;
Single charge each with; [tex]q_1\ and\ q_2[/tex] [tex]= 1C[/tex]Distance between; [tex]r = 1m[/tex]Electric force between; [tex]F = \ ?[/tex]Coulomb's lawCoulomb's law states "that the force between two electrical charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them".
It is expressed as;
[tex]F = k\frac{q_1q_2}{r^2}[/tex]
Here, [tex]q_1\ and\ q_2[/tex] are the two electrical charges, r is the distance between them and k is the Coulomb constant ( [tex]k = 8.98755*10^9 kgm^3/s^2C^2[/tex])
To determine the electrical force between the two charges, we substitute our values into the expression above.
[tex]F = k\frac{q_1q_2}{r^2}\\\\F = (8.98755*10^9 kgm^3/s^2C^2)*\frac{(1C)(1C)}{(1m)^2}\\\\F = (8.98755*10^9 kgm^3/s^2C^2)*\frac{1C^2}{1m^2}\\\\F = 8.98755*10^9 kgm/s^2\\\\F = 8.98755*10^9 N[/tex]
Therefore, the magnitude of the electrical force between the two identical electrical charges is 8.98755 × 10⁹N.
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The magnitude of the electrical force between the two charges is 8.987×10⁹ N.
What is coulomb's law?As per the coulomb's law, the electrical force between any two charges separated by a distance of r is given by the formula,
[tex]F = k\dfrac{q_1q_2}{r^2}[/tex]
Given that the value of q₁ and q₂ is 1 coulomb, while the distance between them is 1 meter. Also, the value of k is 8.987×10⁹ N·m²·C⁻², therefore, the force can be written as,
[tex]F = k\dfrac{q_1q_2}{r^2}\\\\F = (8.987 \times 10^{9}) \times (\dfrac{1 \times 1}{1^2})\\\\F= 8.987 \times 10^{9}\rm\ N[/tex]
Hence, the magnitude of the electrical force between the two charges is 8.987×10⁹ N.
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Assume that a gravitational anomaly in the solar system has shifted a field of asteroids into Earth’s orbit, and the field is now moving directly towards Earth. The asteroid field has a density of rho (asteroids/volume), and each asteroid has an average mass of m. The asteroid field stretches over a distance d in Earth’s path. Assume that the Earth moves with a velocity of v, the asteroids with u, and that be the radius of the Earth. The Earth collides with the asteroid field:
Show that the slow-down ∆v of the Earth due to the asteroid collisions is given by:
Answer:
An asteroid is a minor planet of the inner Solar System. Historically, these terms have been applied to any astronomical object orbiting the Sun.
A ball that has a mechanical energy of 65 J haas 10 j of kinetic energy. The ball has j of potential energy
Answer:
55 j
Explanation:
Mechanical energy = kinetic + potential
65 = 10 + P.E.
55 j = PE
What happens to force when two charges move away?
If the distance between the two charges is doubled, the attraction or repulsion becomes weaker.
Explanation:
A student measures the voltage and current between two points in an
electrical circuit. If the voltage is 120 V and the current is 0.5 A, what is the
resistance, according to Ohm's law?
A. 0.00402
Β. 240 Ω
C. 1200
D. 60.00
Answer:
B. 240Ω
Explanation:
The formula between voltage, current and resistance is:
voltage = current × resistance
So resistance = voltage ÷ current
Therefore resistance = 120 ÷ 0.5
Resistance = 240Ω
what is the frequency of a light wave that has a wavelength of 0.039 m?
Answer:
Convert your wavelength into meters. Divide the speed of light, ~300,000,000 m/s, by the wavelength in m. This gives you the wave's frequency
Explanation:
Which reaction connects the citric acid cycle to the electron‑transport chain and amino acid synthesis?
Conversion of succinylcoA to succinate is the reaction that link acid cycle to the electron‑transport chain and amino acid synthesis.
Conversion of succinylcoA to succinateSuccinylCoA is converted into succinate through the hydrolytic release of coenzyme A by succinyl-CoA synthetase Also succinyl-CoA is porphyrin synthesis, where it combine with glycine by ALA synthase to form δ-aminolevulinic acid.
Succinyl CoA is catalytically converted to succinate. The enzyme stimulates the hydrolysis of succinyl CoA into succinate and ATP and this represents a remarkable point of substrate level phosphorylation. After this, it link up to the electron transport chain via citric acid cycle.
Therefore, Conversion of succinylcoA to succinate is the reaction that link citric acid cycle to the electron‑transport chain and amino acid synthesis.
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The electron‑transport chain reaction connects the citric acid cycle to the electron‑transport chain and amino acid synthesis.
What is an electron‑transport chain reaction?The electron transport chain is a set of protein complexes that link redox processes to create an electrochemical potential that leads to the production of ATP in a process known as
Both photosynthesis and cellular respiration occur in mitochondria.
As a result, the process that connects the citric acid cycle to the electron transport chain and amino acid synthesis is succinyl-CoA to succinate conversion.
Hence the electron‑transport chain reaction connects the citric acid cycle to the electron‑transport chain and amino acid synthesis.
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What would happen if you placed a compass near an electromagnet when there is an electric current in the coil of the electromagnet? Why would this happen? What if you flipped the electromagnet around so the end that was closest to the compass is now farthest away?
Answer:
Here's the answer
Explanation:
since an electromagnet has a magnetic field, it will always follow the electromagnet.
What is the direction of the normal contact force of the road on the wheels?
Tick one box.
Down
Left
Right
Up
The direction of the normal contact force of the road on the wheels is : ( B ) Left
Contact force
The contact force of the road on the wheels will act in a direction opposite to the movement of the wheel on the road. therefore as the wheel moves forward ( right ), the contact force will move backwards ( left ) of the direction of motion.
Hence we can conclude that the direction of the normal contact force of the road on the wheels is : ( B ) Left
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The physical meaning of 220 volts
Answer:
a particular level of electical potential from a power source
If a runner exerts 457 j of work to make 321 w of power then how long did it take the runner to do the work
The time taken by the runner to do the work is 1.42 seconds.
Given the data in the question;
Work done; [tex]W = 457J[/tex]Power; [tex]P = 321W[/tex]Time elapsed; [tex]t = \ ?[/tex]PowerPower can be simply referred to as the quantity of energy transferred per unit time.
It is expressed as;
[tex]P = \frac{W}{t}[/tex]
Where W is work done and t is time elapsed.
To determine the time it took the runner to do the work, we substitute our given values into the expression above.
[tex]P = \frac{W}{t} \\\\t = \frac{W}{P} \\\\t = \frac{457J}{321W} \\\\t = \frac{457 kgm^2/s^2}{321 kgm^2/s^3}\\\\t = 1.42s[/tex]
Therefore, the time taken by the runner to do the work is 1.42 seconds.
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How many ounces in a cup?
Answer:
8 oz
Explanation: