Which is the least electronegative element?Group of answer choicescarbonnitrogenoxygenaluminum

The third law of thermodynamics states that the entropy of a system approaches a constant value as the temperature approaches absolute zero.

Or:

The third law of thermodynamics states, regarding the properties of closed systems in thermodynamic equilibrium: The entropy of a system approaches a constant value when its temperature approaches absolute zero.

The IUPAC name of the structure (9) is 4-ethyl-2,3-dimethyl-heptane.

The first step is to select the longest, most substituted carbon chain containing a functional group is chosen. Then the identification of the primary suffix indicates the degree of saturation such as 'ane' or 'ene.

Then the identification of the secondary suffix indicates the functional group present in the molecule which depends on the number of occurrences of the same functional group such as di. tri tetra etc. Carbon atoms in the carbon chain are numbered from the reactive end of the molecule where the functional group is present.

In the given structure the longest carbon chain of seven carbon atoms. The methyl groups are present at the second and third position and the ethyl group is present at the fourth position. All the bonds in the structure are single bonds so the suffix is 'ane'. Therefore, the IUPAC name is 4-ethyl-2,3-dimethyl-heptane.

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Answer

226 K

Explanation

To change from C to K, you add 273

Therefore -47 C + 273 = 226 K

T

Answer: 189.5g of Ag would be produced from 0.88 moles of Ag2S

Explanation:

The question requires us the amount of Ag, in grams, that would be produced from 0.88 moles of Ag2S, according to the following equation:

To solve this problem, which is a mol to mass stoichiometry problem, we'll need to follow the steps:

moles of Ag2S → moles of Ag → mass of Ag

To do that, we'll need to use the molar mass of Ag (107.87 g/mol) and the mole ratio between Ag2S and Ag, as given by the balanced chemical equation (6 moles of Ag are produced from 3 moles of Ag2S).

We can calculate the number of moles of Ag that would be produced from 0.88 moles of Ag2S as:

3 mol Ag2S -------------------------- 6 mol Ag

0.88 mol Ag2S --------------------- x

Solving for x, we'll have:

Therefore, 1.76 moles of Ag would be produced from 0.88 moles of Ag2S.

Next, we need to convert the number of moles of Ag calculated to its correspondent mass. Knowing that the molar mass of Ag is 107.87 g/mol, we can calculate:

Therefore, 189.5g of Ag would be produced from 0.88 moles of Ag2S.

The electron configurations that are not valid among the options are 1s²2s²2p 3s 3p 4s²4d¹04p5 and 1s²2s²2p 3s³3d5. Options 1 and 2.

The electron configuration of atoms using the various orbital levels follows the order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p.

Also, according to Afbau principle, orbitals with low energy levels are filled with electrons before orbitals with higher energy levels.

Using the above,  1s²2s²2p 3s 3p 4s²4d¹04p5 is incorrect for some reasons:

1s²2s²2p 3s³3d5 is incorrect because:

The remaining electron configurations are correct with correctly placed electrons in the various orbitals.

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Assuming the third quantum number is the question is the magnetic quantum number, it is limited by the angular momentum quantum number. This is inditaced in the quastion: since the orbital is 4p, the "p" indicates that the angular momentum quantum number is 1.

The magnetic quantum number can only be -1, 0 or +1.

The only alternative with one os these is alternative A.

We have to remember the rules to determine to which period and which group belongs an element, depending on its electronic configuration:

We always have to see the last level of energy, in this case is 3 (the highest number in the electronic configuration). It determines the period (the horizontal lines)

Now, we have to see the last letter which is with the 3, in this case the letter is p. It determines that the element is part of the A groups of the periodic table, also called the representative groups. In case of ending in d, it means that the element belongs to the transition metals. And trhe last possibility is ending in f, it means that the element belongs to the lanthanides and actinides.

The last thing, is to add up the valence electrons. Those are the ones in the last energy level, that as we mentioned before, it is 3 in this case. So, we have to add up, the exponents of the different letters that are in the last energy level. In this particular case, are the 2 and the 6, which is equal to 8.

So, we have to search in the periodic table, the element which is in the period 3, group VIII A. If we go, we will find it is the argon (Ar)

Answer:

Molecular formula = KSO4.

Empirical formula = K2S2O4.

Explanation:

What is given?

Mass of K (potassium) = 0.2361 g.

Mass of S (sulfur) = 0.1936 g.

Mass of O (oxygen) = 0.8162 g - 0.2361 g - 0.1936 g = 0.3865 g.

Molar mass of K = 39.1 g/mol.

Molar mass of S = 32 g/mol.

Molar mass of O = 16 g/mol.

Weight of compound = 270 g/mol.

Step-by-step solution:

Remember that empirical formulas show the simplest whole-number ratio of atoms in a compound, and molecular formulas show the number of each type of atom in a molecule. So first, let's see what would be the molecular formula:

Let's find the number of moles of each element using its molar mass:

The next step is to divide each number of moles obtained by the least number of moles, in this case, the least number is 0.006038:

Our molecular formula would contain 1 mol of K, 1 mol of S, and 4 moles of O, so it would be KSO4.

But remember that we need to find the empirical formula too, based on the molecular weight. In the statement, they're telling us that the molecular weight is 270 g/mol, but the molecular weight of KSO4 is 135 g/mol (you can calculate it using the given molar masses and by doing an algebraic sum). So, to obtain the empirical formula with 270 g/mol as molecular weight, we have to multiply by two each number of moles of the compound (135 g/mol * 2 = 270 g/mol):

So, you can realize that K2S2O4 would be the empirical formula because its molecular weight would be 270 g/mol.

Molecular formula = KSO4.

Empirical formula = K2S2O4.

Answer

c. Fe2(SO4)3

Explanation

The polyatomic ion (SO₄)⁻² has a net charge of -2 and iron (III) ion, Fe⁺³ has an oxidation number of +3. For a compound to be formed between them, two of Fe⁺³ will need three of the polyatomic ion, (SO₄)⁻² and the formula of the compound will be Fe2(SO4)3.

The gas bubbles you see exists made of carbon dioxide, which exists released when baking soda and vinegar react to balance each other out.

Alkaline baking soda combines with acids like vinegar to produce water and carbon dioxide (a gas). The resulting fizz is fantastic entertainment for kids to watch, especially if you combine it with dish soap to create even more bubbles or if you add some food coloring, ice, or a theme.

The gas bubbles you see are made of carbon dioxide, which exists released when baking soda and vinegar react to balance each other out (vinegar exists an acid and baking soda is an alkali).

The project's objective is to demonstrate the potency of the gas created when vinegar and baking soda are combined. The goal is for the balloon to be blown up by the gas created.

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The role of the force of gravity and/or fusion force in the formation of new stars form from a hydrogen and dust cloud is by providing the required force and conditions needed for the reaction.

This is referred to as an astronomical object which has a luminous spheroid of plasma which is held together by its gravity.

In the formation of stars, the fusion force helps in the initiation of the nucleosynthesis reaction which occurs. The outward pressure from heating of the gas must balance gravity for a new star to be formed thereby making it the correct choice.

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ANSWER

3.52 moles are in 95 grams of aluminum

STEP-BY-STEP EXPLANATION:

As you can see from the question provided, you are asked to find the moles of aluminum

Given data

Mass of aluminum = 95 grams

To find the moles of aluminum, we will need to apply the below formula

From the question provided, you can see that the molar mass of aluminum was given

From your periodic table, you will see that the molar mass of aluminum is 27 g/mol

Molar mass of aluminum = 27g/mol

The next thing is to substitute the data given in the above formula

Therefore, we have 3.52 moles are in 95 grams of aluminum

The wavelength and the energy would be2.67 × 10⁻⁴ meters and 7.02998 × 10 ⁻²⁰ Joules and respectively if the photon has a frequency of 11.23 × 10¹³ Hz.

It can be understood in terms of the distance between any two similar successive points across any wave.

C = λν

As given in the problem we have to calculate the energy and the wavelength of a photon with a frequency of 11.23 × 10¹³ Hz.

The wavelength of the photon = 3 × 10 ⁸ / 11.23 × 10¹³ Hz.

                                                   = 2.67 × 10⁻⁴  meter

The energy of the photon of light = h × ν

                                                       = 6.26 × 10⁻³⁴ × 11.23 × 10¹³ Hz.

                                                      = 7.02998 × 10 ⁻²⁰ Joules

Thus, the wavelength and the energy would be 2.67 × 10⁻⁴  meter and  7.02998 × 10 ⁻²⁰ Joules and respectively if the photon has a frequency of 1.1 × 10¹⁷ Hz.

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The answer in correct significant figures of the addition of the two numbers mentioned is 100.70.

Significant figures are used for establishment  of a number which is presented in the form of digits. These digits give a meaningful representation  to the numbers.

The significant figures are the significant digits which convey the meaning according to the accuracy. These provide precision to the numbers and hence are called as significant numbers.There are rules for counting significant figures which are as follows:

1)All non-zero digits are significant .

2)All zeroes which occur between non-zero digits are significant.

3)All zeroes to the left and right of  a non-zero digit are not significant.

4) All zeroes on right  of decimal are significant if a non-zero number follows them.

5)All zeroes on right side of non-zero digit are significant.

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According to the explanation given in a previous session, the compounds that comes after the arrow are classified as product, and the compounds that comes before are classified as reactant, therefore in this reaction, (NH4)2CO3 is the product of the reaction, letter D

Answer:

Explanation:

the answer is D

Answer:

D

Explanation:

capillaries veins and arteries

They give us the grams of solute and the molarity of the solution. To find the liters we must take into account the definition of molarity. Molarity is defined as:

The definition of molarity asks us for the moles of solute, so we must pass the grams that give us to moles. For them, we divide the 500 grams by the molar mass of MgF2. The molar mass of MgF2 is 62.3018g/mol.

The moles of MgF2 will be:

Now, we find the liters of solution:

Answer: It must be present 3L of solution

Answer:

No. of moles [tex]\approx[/tex] 0.020

Explanation:

To calculate the number of moles of a substance in a solution given its concentration and volume, we use the following formula:

[tex]\boxed{\mathrm{No. \ of \ moles = Concentration \times Volume}}[/tex],

where concentration is in mol/dm³ (or M) and volume is in L.

In the question, we are told that the volume of the solution is 0.085 L and that its concentration is 0.23 M. Substituting these values into the formula above, we get:

No. of moles = 0.23 × 0.085

                     = 0.01955

                     [tex]\approx[/tex] 0.020 mol  (3 s.f.)

Therefore, there are 0.020 moles of NH₄NO₃ in the solution.

The original pressure of argon in the cylinder is 5.68 atm.

The original pressure of argon in the cylinder is calculated as follows.

Apply the concept of molar ratio or molar proportion to determine the original pressure of argon in the cylinder.

Pr = [(Pn x Vn) + (Pa x Va) ] / (Vn + Va)

where;

7.15 = [(11.08 x 4.5) + (12 x Pa)] / (4.5 + 12)

7.15(4.5 + 12) = 49.86 + 12Pa

117.98 = 49.86 + 12Pa

68.12 = 12Pa

Pa = 68.12/12

Pa = 5.68 atm

Thus, the original pressure of argon in the cylinder is determined by applying concept of molar ratio.

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The question requires us to determine the mass number of an atom with 37 protons, 50 neutrons and 37 electrons.

The atomic number of an atom is determined by its number of protons, while the mass number of an atom is defined as the sum of number of protons and number of neutrons.

Therefore, we can calculate for the atom given by the question:

Therefore, the mass number of this atom is 87 and the best option to answer the question is letter D.

Cl is the limiting reactant and the mass of tin chloride that can be formed is 31.9g.

- First, we need to balance the equation:

- Second, we need to know the molar weight of the compounds:

Sn: 118.7 g/mol

Cl: 35.5 g/mol

SnCl4: 260.7 g/mol

- Third, we need to know how much Sn can react with Cl according to the balanced equation:

If 118.7g of Sn needs 142g of Cl to react according to the balanced equation, we found that the 15.7g of Sn will need 18.8g of Cl to complete the reaction.

As we have 17.4g of Cl available, we can see that we are going to need more Cl and therefore Cl is the limiting reactant.

- Now, to find the mass of tin chloride that can be formed, we use the limiting reactant amount for the calculation:

According to the balanced equation we need 142g of Cl to produce 260.7g of tin chloride, so with 17.4g of chlorine we will obtain 260.7g of SnCl4.

So, the mass of tin chloride that can be formed is 31.9g.

To see the total number of atoms we need to multiply coefficient which is written in foot of the molecule or element to the number that is written on the foot of that element

The balanced reaction is

2 Al(s) + 2 KOH(aq) + 4 H₂SO₄(aq) + 22 H₂O(l) → 2 KAl(SO₄)₂·12H₂O(s) + 3 H₂(g)

Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side

The unbalanced equation is

Al(s) + KOH(aq) +  H₂SO₄(aq)→  KAl(SO₄)₂·12H₂O(s)

sulfur atoms on reactant side is 1 while on the product side it is 2 so multiply  H₂SO₄ by 2

Al(s) + KOH(aq) +  2H₂SO₄(aq)  →  KAl(SO₄)₂·12H₂O(s)

Now add    H₂O(l) and H₂(g) to balance oxygen and hydrogen. The balanced equation becomes

2 Al(s) + 2 KOH(aq) + 4 H₂SO₄(aq) + 22 H₂O(l) → 2 KAl(SO₄)₂·12H₂O(s) + 3 H₂(g)

Thus the balanced equation is

2 Al(s) + 2 KOH(aq) + 4 H₂SO₄(aq) + 22 H₂O(l) → 2 KAl(SO₄)₂·12H₂O(s) + 3 H₂(g)

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The shortest wavelength of light capable of dissociating the Cl–Cl bond in one molecule of chlorine is 493 nanometer.

The formula to calculate Energy is given as follows :

E = BE / Na

E = energy

BE = bond energy = 243 KJ / mol

Na = Avogadro number = 6.02 × 10²³

substituting the values in the formula:

E = 243 × 10³ / 6.02 × 10²³

E = 4.03 × 10⁻¹⁹ J

By using Einstein equation for photon , we can calculate the shortest wavelength :

E = (h c) / λ

E = energy

h = Planck constant = 6.626 × 10⁻³⁴ J.s

c = speed of light =  3 × 10⁸ m/s

λ = wavelength

therefore,

λ = (hc )/ E

λ =( 6.626 × 10⁻³⁴ J.s × 3 × 10⁸ m/s ) /  4.03 × 10⁻¹⁹ J

λ = 4.93 × 10⁻⁷ m

λ = 493 × 10 ⁻⁹ m

1 nm = 1 × 10 ⁻⁹ m

Shortest wavelength = 493 nanometer.

Thus, The shortest wavelength of light capable of dissociating the Cl–Cl bond in one molecule of chlorine if the bond energy, or bond dissociation energy, is 243 kJ/mol  is 493 nanometer.

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Answer

T = 226.21 K

Explanation

Given:

Pressure = 123 kPa

Volume = 10.0 L

number of moles = 0.654 moles

We know R = 8.314 L kPa/mol k.

Required: Temperature

Solution:

Pv = nRT

T = PV/nR

T = (123 kPa x 10.0 L)/(0.654 mol x 8.314 L kPa/mol k)

T = 226.21 K

CO2 particles move faster through the solution. Gas solubility increases as liquid CO2 partial pressure rises.

Dynamic equilibrium occurs when the solution rate matches the escape rate, and neither the gas above the liquid nor the gas dissolved in it changes.

This is further explained below.

Generally, The idea of partial pressure is connected to the changes that occur in soft drink containers. Since there are no gas particles in the liquid when we add CO2 at a typical partial pressure of 0.00035, the CO2 gas begins to move into the solution at a faster pace than it can leave.

But when the concentration of CO2 gas rises, it begins to diffuse into the liquid, and eventually, a dynamic equilibrium is attained when the rate of the solution equals the rate of escape.

However, as we continue to add CO2 to this dynamic equilibrium, its partial pressure will rise until it reaches 4 atm, and this rise in partial pressure accelerates the rate of solution. Thus, raising the partial pressure of CO2 causes this reversible transformation to occur.

When the rate of the solution equals the rate of escape, this is known as dynamic equilibrium, and neither the quantity of gas above the liquid nor the amount of gas dissolved in it changes in any significant way.

Now here comes what role is played by partial pressure. When the rate of solution and the rate of escape reach a dynamic equilibrium and we begin to introduce additional CO2 gas to this dynamic equilibrium stage.

The CO2 gas particle's partial pressure and concentration both rise. Because of the increased rate of collision between the surface of CO2 gas and the surface of the liquid particles due to the increasing concentration, the rate of solution also rises. The pace of solution has now surpassed the rate of escape.

As a result, the rate at which CO2 gas particles travel through the solution increases. This is how a rise in CO2 partial pressure over liquid causes a rise in gas solubility.

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The likely to be TRUE about a hair sample that is four centimeters long and lacks a root or follicular tissue is there will be mitochondrial DNA present (Option A).

Mitochondrial DNA is a type of genetic material that is independent of nuclear DNA and is contained in an organelle known as mitochondrion. These organelles (mitochondria) are the energy factors of the cell because they generate ATP through the process of cellular respiration.

Generally, the cells that contain cell nuclei also contain different organelles such as mitochondria, and this observation also includes the hair cell follicles that are differentiated specialized types of cells present in the hair.

Therefore, with this data, we can see that mitochondrial DNA  is different from nuclear DNA and it is found in tissues that are subject to differentiation such as follicular tissues which need energy to differentiate.

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The mass of aluminum metal that reacts to form 2.80 g of iron according to the reaction would be 0.9017 g.

The percent yield of the reaction if 0.450 g of potassium chlorate reacts according to the equation would be 87.05%.

Consider the first reaction:

[tex]3 FeO (l) + 2 Al (l) -- > 3 Fe (l) + 1 Al_2O_3[/tex]

The mole ratio of Al and Fe is 2:3.

2.80 g of Fe = 2.8/55.85

                    = 0.0501 moles

Equivalent mole of Al = 2/3 x 0.0501

                              = 0.0334 moles

Mass of 0.0334 moles Al = 0.0334 x 26.98

                                        = 0.9017 g

Consider the second reaction:

[tex]2 KCIO_3 (s) -- > 2KCl (s) + 3 O_2[/tex]

The mole ratio of potassium chlorate to oxygen is 2:3.

Mole of 0.450 g potassium chlorate = 0.450/122.55

                  = 0.0037 moles

Equivalent moles of oxygen = 3/2 x 0.0037

                           = 0.0056 moles

Mass of 0.0056 moles oxygen = 0.0056 x 32

                                   = 0.1792 g

Percent yield = 0.156/0.1792 x 100

                = 87.05%

In other words, the mass of aluminum metal that reacts in the first reaction would be  0.9017 g while the percent yield of the second reaction is 87.05%.

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The fact that some of the solid was transferred would decrease the mass of the limiting reactant.

We know that in a chemical reaction, there are at least two substances that are combined in order to give the product of the reaction. We also know that the product that we obtain must be in accordance to the stoichiometry of the reaction.

It is common to see that one of the reactants would be present in a very large amount while the other reactant would be present only in quite a small amount. The reactant that is present in a small amount is said to be the limiting reactant while the one that is present in the large amount is said to be the reactant that is in excess.

Having said this, we know that the mass of the limiting reactant can be obtained from the mass of the solid that is obtained after the reaction.

If we do not take out all of the solid from the centrifuge, the mass would not be accurately weighed and the mass of the limiting reactant would not be accurately determined.

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The balanced equation

2H2 +O2 =====> 2H2O

What is balanced equation ?

An equation for a chemical reaction is said to be balanced if both the reactants and the products have the same number of atoms and total charge for each component of the reaction. In other words, both sides of the reaction have an equal balance of mass and charge.

The balanced equation

2H2 +O2 =====> 2H2O

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