Answer:
C) 4Fe + 3O2 → 2Fe2O3
Explanation:
For this question, first you would go through all the options and make sure that there is an equal amount of elements on each side.
For the first option: 2Fe +02 → 2Fe2O3
You have only 2Fe atoms and 2O atoms on your reactant side and 4Fe and 6O atoms on your product side. This is not balanced.
For option b: 3Fe +302 → 3Fe2O3
You have 3Fe and 6O atoms on your reactant side while on your product side you have 6Fe and 6O atoms. This is not balanced.
For option c: 4Fe +302 → 2Fe2O3
You have 4Fe and 6O atoms on your reactant side and 4Fe and 6O atoms on your product side. This is balanced!
For option d: Fe +0₂ → Fe₂O3
You have 1Fe and 2O atoms on your reactant side and 2Fe and 3O atoms on your product side. This is not balanced.
***Remember to multiply the subscript of an element by their coefficient (number in front of molecule) if there is any.
3. 135 g of ice is placed in a beaker of water. The water temperature in the beaker is 67 °C. After all the icemelts, the final water temperature in the beaker is 19.7 °C. 4 ptsHeat of fusion for water = 334 J/g. Specific heat of water = 4.184 J/g °C. T2-T1 = 47.3 °C.Note there are a couple different ways to solve this problems to sove this por(a) Determine the initial volume of water in the beaker (before the ice was added).(b) Determine the final volume of water in the beaker (after all the ice has melted).
Answer:
Explanation:
Answer to the 1st one. I have my doubts for the second one so didn't post :)
What is the number of formula units in a 9.21 mol sample of CaO ?
Answer:
5.546262 x 10^24 formula units
Explanation:
Use avogadro's number
9.21 mol CaO ((6.022 x 10^23 formula units CaO)/1 mol CaO)) = 5.546 x 10^24.
I rounded to 3 sig figs.
How do I write the Empirical Formula for: A compound composed of: 9.93% carbon, 58.6% chlorine, and 31.4% fluorine
The empirical formula for a compound composed of 9.93% carbon, 58.6% chlorine, and 31.4% fluorine is CCl₂F₂.
To write the empirical formula, let us assume that total mass of the compound is 100 g, then-
Mass of carbon = 9.93 g
Mass of chlorine = 58.6 g
Mass of fluorine = 31.4 g
We know that,
Molar mass of Carbon = 12.0 g/mol
Molar mass of Chlorine = 35.5 g/mol
Molar mass of Fluorine = 18.9 g/mol
Now, we will calculate the number of moles of each using the formula -
Number of moles = Given mass
Molar mass
Moles of Carbon = 9.93 g = 0.82 mol
12.01 g/mol
Moles of Chlorine = 58.6 g = 1.65 mol
35.5 g/mol
Moles of fluorine = 31.4 g = 1.66 mol
18.9 g/mol
Now, divide each value with the smallest amount of mole we got,
carbon = 0.82 = 1
0.82
chlorine = 1.65 = 2
0.82
fluorine = 1.66 = 2
0.82
Therefore, the empirical formula of the compound can be written as - CCl₂F₂
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If a volcano erupts and ejects 12.5 moles of sulfur into the atmosphere how many atoms of sulfur is this
In this question, we have to find the number of atoms in 12.5 moles of Sulfur, and the way to do it is by using the Avogadro's number, which is 6.02*10^23 atoms, this value represents how many atoms we have in 1 single mol of any element. Therefore in 12.5 moles we will have:
1 mol = 6.02*10^23 atoms
12.5 moles = x atoms
x = 7.52*10^24 atoms of Sulfur in 12.5 moles
Which of the following will not affect the rate of a reaction?nature of the reactantscolor of reactanttemperatureconcentration of a reactant
Color of reactant. Option B is correct
Explanations:What is a rate of reactions?This is defined as the speed at which a reaction takes place. It can be expressed in terms of the concentration of reactants or products formed per unit time.
The following are the factors that affects reaction rate.
- concentration of a reactant
- Temperature
- Nature of the reactant
- Surface Area
- Catalysts.
Based on the explanations above, we can conclude that the color of reactant will not affect the rate of a reaction
What is the total pressure in kPa exerted by a mixture containing two gases if the partial pressure of one gas is 64 kPa and the partial pressure of the other gas is 50.8 kPa?
Dalton's Law or Law of Partial Pressures says that the total pressure of a mixture of gases is equal to the sum of the partial pressures of each gas that composes it. The partial pressure of a gas on the other hand is defined as the pressure it would exert if it were alone in the container.
So we need to sum all the values:
64 + 50.8 = 114.8 kPa
Answer: 114.8 kPa
A bike rides at an average speed of 25 km/h. How many minutes will it take for this rider to ride a distance of 20 km?
Answer:
48 minutes
Explanation:
60 divided by 25 equals 2.4 then you times 2.4 by 20
I get 11 pls help and see if I’m right
Answer
None of these
Explanation
The option for 2-bromo-5propylbenzaldehyde does not seem to be provided
number of litres of gas in 4.51 mol Xe
First, we assume STP conditions and Ideal gas conditions.
In STP conditions, we say that:
1 mol of any gas = 22.4 L (liters)
Procedure:
1 mol Xe ------ 22.4 L (STP)
4.51 moles Xe ------- X
X = 101 L
Answer: 101 L
Which of the following is an element located in group 17?
a) Ne
b) Li
c) Mn
d) Br
Answer:
D- Br
Explanation:
Which of the following best describes what happens when salt dissolves in water?A.) The polar solvent molecules surround the positive sodium ions.B.) The polar solvent molecules surround the positive sodium ions and the negativechloride ions.C.) The solute and solvent molecules form a crystalline structure.D.) The solute and solvent molecules do not interact.
When salt dissolves in water, dissociation occurs. This dissociation forms two ions, one positive and one negative. Water is polar and its molecules has poles negatives and positives. So positive poles of water will surround the negative ions. While negative poles will surround the positive ions.
Answer: Alternative "B"
determine the number of significant figures in each of the following numbers.1.) 32.05 =2.) 36541 =3.) 300,012,345 =4.) 36,000 =5.) 100 =6.) 100.0 =7.) 1,0000 =8.)250 =9.) 250. =10.) 407 =
we are required to determine the significant figures in each of the numbers.
1) 4 significant figures
2) 5 significant figures
3) 9 significant figures
4) 5 significant figures
5) 3 significant figures
6) 4 significant figures
7) 5 significant figures
8) 3 significant figures
9) 3 significant figures
10) 3 significant figures
A 5.325-gram sample of methyl benzoate, a compound used in the manufacture of perfumes, is found to contain 3.758 g carbon, .316 g hydrogen, and 1.251 grams of oxygen. What is the empirical formula for this substance?
Answer
The empirical formula for the compound is C₄H₄O₁Explanation
Given:
Mass composition: 3.758 g carbon, 0.316 g hydrogen, and 1.251 grams oxygen.
What to find:
The empirical formula for the substance.
Step-by-step solution:
The first step is to convert the number of grams of each element into moles as shown below using the molar masses of H = 1.00784 g/mol and C = 12.011 g/mol and O = 15.999 g/mol
Note: Mole = Mass/Molar mass
Moles C = 3.758g/12.011 g/mol = 0.31 mol
Moles H = 0.316g/1.00784 g/mol = 0.31 mol
Moles O = 1.251g/15.999 g/mol = 0.078 mol
Now, let's divide the number of moles of each element by the smallest number obtained:
C = 0.31/0.078 = 4
H = 0.31/0.078 = 4
O = 0.078/0.078 = 1
The empirical formula for the compound is C₄H₄O₁
what is the volume (in L) in a cylinder filled with 23.0 g of N2 gas at a temperature of 65 C and a pressure of 2.37 atm?
The volume of the cylinder filled with 23.0 g of N₂ gas at a temperature of 65 °C and a pressure of 2.37 atm is 9.6 L
Given that,
Mass of the nitrogen gas in the cylinder (m) = 23 g
Temperature (T) = 65 ℃ = 65 + 273 = 338 K
Pressure (P) = 2.37 atm
R (gas constant) = 0.082057338 L.atm.K⁻¹.mol⁻¹
In Ideal gas law or general gas equation,
PV = nRT
Number of moles in nitrogen (n) = Given mass (m) of nitrogen/ Molar mass of nitrogen
Given mass (m) = 23 g
Molar mass of Nitrogen = 28 g/mol
Number of moles of nitrogen (n) = 23 / 28 = 0.82 moles of nitrogen
PV = nRT
2.37 * V = 0.82 * 0.0821 * 338
2.37 * V = 22.75
V = 22.75 / 2.37
V = 9.6 L
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what are the limiting and excess reactants when 3.22 moles of Al react with 6.96 moles of HBr
Answer
HBr is the limiting reactant
Al is the excess reactant.
Explanation
Given:
Moles of Al = 3.22 mol
Moles of HBr = 6.96 mol
Equation: 2 Al + 6 HBr → 2 AlBr₃ + 3 H₂
What to find;
The limiting and excess reactants.
Solution:
Note: The limiting reactant is the reactant that is completely used up in a reaction, and thus determines when the reaction stops. While the excess reactant is the opposite.
From the given balanced chemical equation;
2 moles of Al require 6 moles of HBr
Therefore, the given 3.22 moles of Al will require (3.22/2) x 6 = 9.66 moles of HBr
Since the given moles of HBr is 6.96 mol not up to 9.66 moles required, then HBr is the limiting reactant and Al is the excess reactant.
HBr is the limiting reactant
Al is the excess reactant.
2. Suppose you are testing the gas in laboratory. If you inserted the burning magnesium ribbon inside the gas jar and magnesium ribbon burnt completely and formed light yellow ash as residue, then which gas was there in the gas jar and what is the name of compound present in yellow ash?
When the magnesium ribbon is burned, it enters the carbon dioxide gas jar and continues to burn. The carbon is left behind as a black soot and extra energy is released as a result of the reaction where the magnesium atoms join the oxygen in the carbon dioxide to form magnesium oxide.
Magnesium ribbon is used in pyrotechnics to ignite thermite reactions or to create certain firework mixes. One of the most popular techniques to start chemical reactions that need a higher temperature to ignite is with magnesium ribbon.The light produced by the burning magnesium ribbon is strong enough to temporarily impair vision. Avert looking at the light source directly. Magnesium combustion in air generates strong heat that can result in burns and start the combustion process in combustible materials.To know more about magnesium ribbon
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The combustion of glucose is represented by the following balanced equation:
In order to find limiting and excess reactants, we need to first, set up the equation, and it must be properly balanced:
C6H12O6 + 6 O2 -> 6 H2O + 6 CO2
1 gram of C6H12O6
1 gram of O2
From the balanced equation, we see that the molar ratio between C6H12O6 and O2 is 1:6, this means that 1 mol of C6H12O6 will react with 6 times the number of moles of O2
Now let's find the number of moles of C6H12O6, the molar mass is 180.16g/mol
180.16 g = 1 mol
1 g = x moles
x = 0.005 moles of C6H12O6, now we will need this number of moles times 6 in order to proceed with the reaction
1 C6H12O6 = 6 O2
0.005 C6H12O6 = x O2
x = 0.03 moles of O2
And this amount of moles with the molar mass of O2, which is 32g/mol
32 g = 1 mol
x grams = 0.03 moles
x = 0.96 grams of O2 in 0.03 moles
Since we have more oxygen than what we actually need, Oxygen is in excess and C6H12O6 is the limiting reactant