which element would be most likely to lose electrons in chemical bond

Answer:

[tex]\huge\boxed{\sf n = 7.36 \ mol}[/tex]

Explanation:

Given Data:

Volume = v = 42.19 L

Pressure = P = 428.792 kPa = 4.23 atm

Temperature = 27.871 °C + 273 = 300.871 K

R = the gas constant = 0.08206 L atm K⁻¹mol⁻¹

Required:

No. of moles = n = ?

Formula:

nRT = Pv

Solution:

Rearranging formula

[tex]\displaystyle n = \frac{Pv}{RT} \\\\n = \frac{(4.23)(42.19)}{(0.08206)(300.871)} \\\\n = \frac{181.467}{24.69} \\\\n = 7.36 \ mol\\\\\rule[225]{225}{2}[/tex]

Explanation:

Big C carbon surrounded by He helium

Answer: Q

=

−

53

,

796.6

J

Explanation is right here instead

The equation for heat is

Q

=

m

(

t

f

−

t

i

)

C

p

Q = heat in Joules

m = mass in grams

t

f

= final temp

t

i

= initial temp

C

p

= Specific Heat Capacity

For this problem

Q

=

?

?

?

m

=

275

g

t

f

=

38.4

o

C

t

i

=

85.2

o

C

C

p

=

4.18

j

g

o

C

Q

=

275

g

(

38.4

o

C

−

85.2

o

C

)

4.18

J

g

o

C

Q

=

275

g

(

−

46.8

o

C

)

)

4.18

J

g

o

C

Q

=

−

53

,

796.6

J

The negative Joule value means heat is being lost in an exothermic reaction.

Explanation:

Answer:

(CH₃COO)₂Ca(aq) + Na₂CO₃(aq) = 2CH₃COONa(aq) + CaCO₃(s)

2CH₃COO⁻ + Ca²⁺ + 2Na⁺ + CO₃²⁻ = 2CH₃COO⁻ + 2Na⁺ + CaCO₃

Ca²⁺ + CO₃²⁻ = CaCO₃

Answer:

H3CS06

Explanation:

A chemical supply company sells sulfuric acid (H3CS06) in a concentration of 4.00 M. What volume of this solution would you need to make 12.0 mL of a 0.50 M H2SO4 s…

Molarity is the ratio of a mole of the solute of the substance to the liter of solution. The volume of solution required to make 12.0 ml of 0.50 M solution is 1.5 mL.

Molar dilution is the calculation of the molarity or the volume of the unknown value from the known value. It is given as,

[tex]\rm M_{1}V_{1}= \rm M_{2}V_{2}[/tex]

Given,

Initial molarity = 4.00 M

Initial volume =?

Final molarity = 0.50 M

Final volume = 12.0 mL

Substituting values in the equation:

[tex]\begin{aligned} \rm V_{1} &= \rm \dfrac{\rm M_{2}V_{2}}{M_{1}}\\\\&= \dfrac{0.50 \times 12.0 }{4.00}\\\\&= 1.5 \;\rm ml\end{aligned}[/tex]

Therefore, 1.5 ml of 4.00 M sulfuric acid must be used to make 12 ml of 0.50 M solution.

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In Ferromagnetism, materials are changed into permanent magnets.

Ferromagnetism is a process in which specific materials are turned into permanent magnets. The spins of electrons are shifted and electrons become more aligned and sequence with the direction of the field.

So we can conclude that in Ferromagnetism, materials are changed into permanent magnets.

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The mass of NiCl₂•6HO₂ needed to prepare a 0.035 M 500 mL solution of NiCl₂•6HO₂ is 4.165 g

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

Mole = Molarity × Volume

Mole of NiCl₂•6HO₂ = 0.035 × 0.5

Mole of NiCl₂•6HO₂ = 0.0175 mole

Mass = mole × molar mass

Mass of NiCl₂•6HO₂ = 0.0175 × 238

Mass of NiCl₂•6HO₂ = 4.165 g

Thus, 4.165 g of NiCl₂•6HO₂ is needed to prepare the solution

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The grams of NiCl₂.6H₂O will be used to prepare a 0.0350M, 500ml of NiCl₂ solution is 2.268 grams.

Mass in grams of any substance will be calculated by using moles as:

n = W/M, where

W = given mass

M = molar mass

Moles from molarity will be calculated by using the below formula:

M = n/V, where

M = molarity of NiCl₂ solution = 0.0350M

V = volume of solution = 500mL = 0.5L

On putting values, we get

n = (0.035)(0.5) = 0.0175 mol

Now we convert these moles into grams by using the first formula as:
W = (0.0175mol)(129.6g/mol) = 2.268g

Hence required mass of NiCl₂.6H₂O is 2.268g.

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After subtracting the volume needed from the volume dispensed, we got a remainder of 35ml

Given Data

Let us compute the amount of excess hexane/ the volume that will remain

Remainder = The difference in volume dispensed and the volume needed

Remainder = 40-5

Remainder = 35 ml

The remainder is 35ml

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If you dispense 40 ml of hexane, but it turns out you only need 5 ml, then we should have 35 mL of remained hexane.

Remaining volume of any liquid will be calucted as:

Remaining Volume = Total volume - Used volume

Given that, total volume of hexane = 40 mL

Used volume of hexane = 5 mL

On putting values in above equation, we get

Remaining volume = 40 - 5 = 35 mL

Hence required value of remaining volume is 3 mL.

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Answer:

Explanation:

When you balance a chemical equation, you change coefficients. You never change subscripts. A coefficient is a whole number multiplier. To balance a chemical equation, you add these whole number multipliers (coefficients) to make sure that there are the same number of atoms on each side of the arrow

Answer:

Explanation:

The elements in Group I of the periodic table are called alkali metals. They are called alkali metals because they react with water to form alkali solutions. These metals are very reactive; hence they have to be stored under oil to protect them from corrosion by air and waterwaterwater

The group 1A elements, called alkali metals because they form alkalies on reacting with water. Alkalies are strong bases.

They are the metals that are soft, lustrous, and have a low melting point. Air and moisture react readily with alkali metals.

Special precautions must be taken when using and storing these metals due to their reactivity.

The seven alkali metals are lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr).

Thus, the group 1A elements, called alkali metals because they form alkalies on reacting with water. Alkalies are strong bases.

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Answer:

Acrylonitrile Styrene Acrylate

Answer:

0.14 liters nitric acid

Explanation:

Molarity = moles / liter

7.0 M = x / 0.03 L

= 0.21 moles NaOH

0.21 moles NaOH x ( 1 mole HNO3 / 1 mole NaOH) = 0.21 moles HNO3

Molarity = moles / liter

1.5 M  = 0.21 moles / x

x = 0.21 moles / 1.5 M

x = 0.14 Liters HNO3

Answer:

[tex]140mL[/tex]

Explanation:

[tex]M_1V_1=M_2V_2[/tex]

[tex]M_1=1.5M[/tex] molarity of nitric acid

[tex]V_1=?[/tex]  volume of nitric acid

[tex]M_2=7.0M[/tex] molarity of sodium hydroxide

[tex]V_2=30.0mL[/tex] volume of sodium hydroxide

[tex](1.5M)(V_1)=(7.0M)(30.0mL)[/tex]

[tex]V_1 =\frac{(7.0M)(30.0mL)}{1.5M}=140mL[/tex]

Hope this helps whoever needs it :)

Have a good day!!!

Answer:

Chlorine exists as gaseous state while potassium chloride as a solid

Physical properties between the chlorine and potassium chloride are totally different because chlorine is available in gaseous form while potassium chloride available in solid form. ​

Potassium chloride crystals are composed of face-centered cubic (FCC) unit cells. KCl has a molar mass of 74.5513 grams/mol.

It has a density of 1.984 grams per cubic centimeter when it is solid and crystalline. Potassium chloride has melting and boiling temperatures of 1040 K and 1690 K.

A metal halide salt made of potassium and chlorine is known as potassium chloride. It appears as a white or colorless vitreous crystal and has no odor.

Thus, chlorine is present in gaseous state while ptassium chloride present in solid state.

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ANSWER:

Physical chemistry is the branch of chemistry that deals with the physical structure of chemical compounds, the way they react with other matter and the bonds that hold their atoms together. An example of physical chemistry is nitric acid eating through wood.

Answer:

formula of concentration ion.

The molar mass of Oz is 48 g/mol is true.

Molar mass of a substance is the mass of 1 mole of that substance or it is the number of grams per mole of a substance. The units for molar mass is grams/mole.

Therefore,The molar mass of Oz is 48 g/mol is correct because ozone have three oxygen and the molar mass of one oxygen is 16g/mol.

Ozone= 16×3

Ozone=48g/mol.

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When a solution of MgCl₂ and a solution of AgNO₃ are mixed, the net ionic equation obtained is:

2Cl¯(aq) + 2Ag⁺(aq)  —> 2AgCl(s)

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

In solution

MgCl₂(aq) —> Mg²⁺(aq) + 2Cl¯(aq)

AgNO₃(aq) —> Ag⁺(aq) + NO₃¯(aq)

The reaction proceeds as follow

MgCl₂(aq) + AgNO₃(aq) —>

Mg²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO₃¯(aq) —> 2AgCl(s) + Mg²⁺(aq) + NO₃¯(aq)

Cancel out the spectator ions (i.e Mg²⁺ and NO₃¯) to obtain the net ionic equation

2Cl¯(aq) + 2Ag⁺(aq)  —> 2AgCl(s)

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When a solution of MgCl₂ and one of AgNO₃ are mixed, the net ionic equation is 2Cl¯(aq) + 2Ag⁺(aq) → 2AgCl(s).

Net ionic reactions are those reactions in which each species are written in their respective ions form except the spectator ions.

Given chemical reaction is:

MgCl₂(aq) + 2AgNO₃(aq) → 2AgCl(s) + Mg(NO₃)₂(aq)

Ionic form of the given reaction will be written as

Mg²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO₃¯(aq) → 2AgCl(s) + Mg²⁺(aq) + NO₃¯(aq)

Spectator ions are those which are commonly present on both side of the reaction and for this reaction they are Mg²⁺ and NO₃¯. So the net ionic reaction will be:

2Cl¯(aq) + 2Ag⁺(aq) → 2AgCl(s)

Hence required net ionic reaction is 2Cl¯(aq) + 2Ag⁺(aq) → 2AgCl(s).

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Answer:

Molybdenum is M, Einsteinium is E, and N is Nitrogen. Lastly, S is sulfur.

Answer:

dam aye someone give this person a medal

Explanation:

Answer:

The aspirin is more soluble in ethanol than water - the water helps the crystals separate from solution.

Explanation:

Hope this helps!

Answer:

Yes

Explanation:

The process of respiration and burning are similar in the following ways: Both respiration and burning require oxygen. Energy is released during both respiration and burning. The products produced (carbon dioxide and water) are the same for both respiration and burning.

Answer:

Yes

Both Respiration and Burning uses oxygen. Both Respiration and Burning produces energy. Both Respiration and Burning gives out carbon dioxide as the end product. The overall chemical reactions of both Respiration and Burning are the same.

Explanation:

Please mark me brainliest if correct

From the available options with respect to Taylor's experiment, none of the data is qualitative.

These are data that cannot be measured using any instrument or assigned a numerical value.

Qualitative data are observable data based on perception.

This is unlike quantitative data that can be measured using relevant instruments and assigned numeric figures.

Mass can be measured in grams using a weighing balance, angle of inclination can be measured using relevant instruments, and time can be measured using a stopwatch.

Thus, none of the options is qualitative.

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Answer:

None are Qualitative

Explanation: I took the test and got a 100%

Decomposition reaction results in the formation of the products by splitting the reactants. Moles of mercury(ii) oxide needed are 15.63 moles.

Moles are the ratio of mass and the molar mass of the compound or the molecule.

Moles of oxygen are calculated as:

[tex]\begin{aligned}\rm n &= \rm \dfrac {mass}{molar\; mass}\\\\&= \dfrac{250}{32}\\\\&= 7.8125 \;\rm moles\end{aligned}[/tex]

The balanced chemical reaction can be shown as,

[tex]\rm 2HgO \rightarrow 2Hg + O_{2}[/tex]

From the reaction, it can be said that 1 mole of oxygen requires 2 moles of mercury oxide.

Moles of mercury oxide are calculated as:

[tex]\begin{aligned} \rm n HgO& = (7.8125 \;\rm moles \; O_{2}) \times (\dfrac{2 \;\rm moles\; HgO}{1 \;\rm mole \; O_{2}})\\\\\rm n HgO &= 15.625 \;\rm moles \end{aligned}[/tex]

Therefore, option C. 15.63 moles of mercury (II) oxide is needed.

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From the calculations performed, the free energy change for the reaction is 72 kJ/mol.

The equilibrium constant is a value that shows the extent to which reactants have been converted to products.

Given that the equation of the reaction is;

3CH4(g)→C3H8(g)+2H2(g)

Then;

PC3H8 = 0.013 atm

PH2 =  2.3×10−2 atm

PCH4 = 41 atm

Now;

ΔG = ΔG° + RTlnQ

ΔG°reaction = ΔG°products - ΔG°reactants

ΔG°reaction = [( -23.4) +2(0)] - 3(-50.8)

ΔG°reaction = 129 kJ/mol

Q = PC3H8 * PH2^2/PCH4^3

Q = 0.013 * (2.3×10−2)^2/( 41)^3

Q = 6.877 * 10^-6/68921

Q= 9.9* 10^-11

Hence;

ΔG = 129 * 10^3  + [8.314 * 298 * (ln  9.9* 10^-11 )]

ΔG = 129 * 10^3 - 57073

ΔG = 72 kJ/mol

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If 25 milliliter of 0. 80M HCl is used to completely neutralize 40. milliliters of NaOH solution, the molarity of the base is 0.5M.

The molarity of a solution can be calculated using the following expression:

M1V1 = M2V2

Where;

25 × 0.80 = 40 × M2

20 = 40M2

M2 = 20/40

M2 = 0.5M

Therefore, if 25 milliliter of 0. 80M HCl is used to completely neutralize 40. milliliters of NaOH solution, the molarity of the base is 0.5M.

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a leguminous plant, Phaseolus aureus, whose seeds are used as food in India.

Answer:

Green Gram is a small round edible green bean which is also known as moong ki daal in the subcontinent.

Explanation:

The green gram bean which is also known as the mung, maash or moong, is a plant species in the legume family. The green gram bean is mainly cultivated in East, Southeast and South Asia. It is used as an ingredient in both savoury and sweet dishes.

The concentration of the final solution after mixing water into the H₂SO₄ is 0.375 M.

Concentration in terms of molarity will be calculated by using the below formula as:

M₁V₁ = M₂V₂, where

M₁ = molarity of H₂SO₄ = 1.50 M

V₁ = volume of H₂SO₄ = 50 mL

M₂ = molarity of water = ?

V₂ = volume of water = 200 mL

On putting all values on the above equation, we get

M₂ = (1.50)(50) / (200) = 0.375 M

Hence option (2) is correct.

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Answer:

Enthalpy

Explanation:

The term entropy is used to express the particle scattering of a system.The term joule is a unit of energy.

Answer:

Bison were saved through the combined efforts of conservationists, scientists, ranchers and ultimately the general public. As their comeback continues, I believe that they can teach us how to be better stewards of the land and provide a future for the Plains where ecosystems and human cultures thrive.

Explanation:

[tex]watch.some.anime[/tex]