In order to determine which data sets should be displayed on a stem display, you consider that the stem display is usefull in the cases in which you have data which can be grouped easily. For instance, for data set in which there are differents number with the same first digit(s).
According with the previous definition you can notice that the options E) and A) are the best options, because there are different number that can be grouped, for example, according to the first number.
For other options you have other situations, for option D) there is no way to group the data. For option C) there is only one number on each data, so, there wouldn't be leafs in the diagram, and the same applies to option B), the first number is the same in all data, then, there is no way to group.
5. Graph the system of inequalities. Then, identify a coordinate point in the solution set.2x -y > -3 4x + y < 5
We have the next inequalities
[tex]\begin{gathered} 2x-y>-3 \\ 4x+y<5 \end{gathered}[/tex]as we can see if we graph these inequalities we will obtain the next graph
where the red area is the first inequality and the blue area is the second inequality
and the area in purple is the solution set of the two inequalities
one coordinate point in the solution set could be (0,0)
An arctic village maintains a circular cross-country ski trail that has a radius of 2.9 kilometers. A skier started skiing from the position (-1.464, 2.503), measured in kilometers, and skied counter-clockwise for 2.61 kilometers, where he paused for a brief rest. (Consider the circle to be centered at the origin). Determine the ordered pair (in both kilometers and radii) on the coordinate axes that identifies the location where the skier rested. (Hint: Start by drawing a diagram to represent this situation.)(x,y)= ( , ) radii(x,y)= ( , ) kilometers
The solution to the question is given below.
[tex]\begin{gathered} The\text{ 2.6km is some fraction of the entire Circumference which is: C= 2}\pi r\text{ = 2}\times\text{ }\pi\text{ }\times2.9 \\ \text{ = 5.8}\pi cm \\ \text{ The fraction becomes: }\frac{2.61}{5.8\pi}\text{ = }\frac{0.45}{\pi} \\ \text{The entire circle is: 2 }\pi\text{ radian} \\ \text{ = }\frac{0.45}{\pi}\text{ }\times2\text{ }\times\pi\text{ = 0.9} \\ The\text{ skier has gone 0.9 radian from (-.1.464, 2.503)} \\ \text{The x- cordinate become: =-1.}464\text{ cos}(0.9)\text{ = -1.4625} \\ while\text{ the Y-cordinate becomes: =-1.}464\text{ sin}(0.9)\text{ = -}0.0229 \\ \text{The skier rested at: (-1.4625, -0.0229)} \\ \end{gathered}[/tex]Graph the function and state the domain and range.g(x)=x^2-2x-15Domain-Range-Graphed function-
The domain: -∞ < x < ∞
The range: g(x) ≥ -16
Explanation:The given function is:
[tex]g(x)\text{ = x}^2\text{-2x-15}[/tex]The domain is a set of all the valid inputs that can make the function real
All real values of x will make the function g(x) to be valid
The domain: -∞ < x < ∞
The range is the set of all valid outputs
From the function g(x):
a = 1, b = -2
[tex]\begin{gathered} \frac{b}{2a}=\frac{-2}{2(1)}=-1 \\ g(-1)=(-1)^2-2(-1)-15 \\ g(-1)=1-2-15 \\ g(-1)=-16 \end{gathered}[/tex]Since a is positive, the graph will open upwards
Therefore, the range of the function g(x) is: g(x) ≥ -16
The graph of the function g(x) = x^2 - 2x - 15 is plotted below
In statistics, how do I find the p-value? I understand how to get the z-value. Please help! I am so confused. Thank you in advance!
SOLUTION:
Step 1:
In this question, we are meant to discuss the p-value.
1. The p-value is calculated using the sampling distribution of the test statistic under the null hypothesis, the sample data, and the type of test being done (lower-tailed test, upper-tailed test, or two-sided test).
2.
3. What is the p-value in statistics?
The p-value is a number, calculated from a statistical test, that describes how likely you are to have found a particular set of observations if the null hypothesis were true. P-values are used in hypothesis testing to help decide whether to reject the null hypothesis.
4. How do I know when the test is left-tailed, right-tailed, or two-tailed?
Left-tailed test: The critical region is in the extreme left region (tail) under the curve.
Right-tailed test: The critical region is in the extreme right region (tail) under the curve.
5. How do you know when to use a one - tailed or two - tailed test?
This is because a two-tailed test uses both the positive and negative tails of the distribution.
In other words, it tests for the possibility of positive or negative differences. A one-tailed test is appropriate if you only want to determine if there is a difference between groups in a specific direction.
6. The formulae that involves z-score:
7. The formulae that involves p -value and standard deviation:
Consider the graph of g(x) shown below. Determine which statements about the graph are true. Select all that apply.
SOLUTION
From the graph, the root of the equation is the point where the graph touches the x-axis
[tex]x=-4,x=0[/tex]Hence the equation that models the graph becomes
[tex]\begin{gathered} x+4=0,x-0=0 \\ x(x+4)=0 \\ x^2+4x=0 \\ \text{Hence } \\ g(x)=x^2+4x \end{gathered}[/tex]Since the solution to the equation are x=-4 and x=0
Hence the equation has two real zeros
The minimum of g(x) is at the point
[tex]\begin{gathered} (-2,-4) \\ \text{Hence minimum is at x=-2} \end{gathered}[/tex]The minimum of g(x) is at x=-2
The vertex of g(x) is given by
[tex]\begin{gathered} x_v=-\frac{b}{2a} \\ \text{and substistitute into the equation to get } \\ y_v \end{gathered}[/tex][tex]\begin{gathered} a=1,\: b=4,\: c=0 \\ x_v=-\frac{b}{2a}=-\frac{4}{2\times1}=-\frac{4}{2}=-2 \\ y_v=x^2+4x=(-2)^2+4(-2)=4-8=-4 \\ \text{vertex (-2,-4)} \end{gathered}[/tex]Hence the vertex of g(x) is (-2,-4)
The domain of the function g(x) is the set of input values for which the function g(x) is real or define
Since there is no domain constrain for g(x), the domain of g(x) is
[tex](-\infty,\infty)[/tex]hence the domain of g(x) is (-∞,∞)
The decreasing function the y-value decreases as the x-value increases: For a function y=f(x): when x1 < x2 then f(x1) ≥ f(x2)
Hence g(x) decreasing over the interval (-∞,-2)
Therefore for the graph above the following apply
g(x) has two real zeros (option 2)
The minimum of g(x) is at x= - 2(option 3)
the domain of g(x) is (-∞,∞) (option 4)
g(x) decreasing over the interval (-∞,-2)(option 4)
which point lies on the line with the slope of m=7 that passes through the point (2,3)
Answer:
B. Monkey Man
Step-by-step explanation:
M+o+n+k+e+y
Rafael is buying ice cream for a family reunion. The table shows the prices for different sizes of two brands of ice cream.
the correct answer is that the small size of the brand Cone dreams, because the price of each pint in it will be $2.125 =4.25/2, and if we calculate the price per pint with the other options it would be the minimum of all of them.
Which of the following ordered pairs is a solution to the equation 2x+y=2? Select all that apply.(11,0)(−4,10)(−13,4)(−11,−1)(0,2)
You have the following equation:
2x + y = 2
In order to determine which of the given pairs is a solution, replace the values of x and y of such pairs and verify the equation, as follow:
(11,0)
2(11) + 0 = 22 ≠ 2 it's not a solution
(-4,10)
2(-4) + 10 = -8 + 10 = 2 it's a solution
(-13,4)
2(-13) + 4 = -26 + 4 ≠ 2 it's not a solution
(-11,-1)
2(-11) + (-1) = -22 - 1 ≠ 2 it's not a solution
(0,2)
2(0) + 2 = 2 it's a solution
hello I'm stuck on this question and need help thank you
Explanation
[tex]\begin{gathered} -2x+3y\ge9 \\ x\ge-5 \\ y<6 \end{gathered}[/tex]Step 1
graph the inequality (1)
a) isolate y
[tex]\begin{gathered} -2x+3y\geqslant9 \\ add\text{ 2x in both sides} \\ -2x+3y+2x\geqslant9+2x \\ 3y\ge9+2x \\ divide\text{ both sides by 3} \\ \frac{3y}{3}\geqslant\frac{9}{3}+\frac{2x}{3} \\ y\ge\frac{2}{3}x+3 \end{gathered}[/tex]b) now, change the symbol to make an equality and find 2 points from the line
[tex]\begin{gathered} y=\frac{2}{3}x+3 \\ i)\text{ for x=0} \\ y=\frac{2}{3}(0)+3 \\ \text{sp P1\lparen0,3\rparen} \\ \text{ii\rparen for x=3} \\ y=\frac{2}{3}(3)+3=5 \\ so\text{ P2\lparen3,5\rparen} \end{gathered}[/tex]now, draw a solid line that passes troguth those point
(0,3) and (3,5)
[tex]y\geqslant\frac{2}{3}x+3\Rightarrow y=\frac{2}{3}x+3\text{\lparen solid line\rparen}[/tex]as we need the values greater or equatl thatn the function, we need to shade the area over the line
Step 2
graph the inequality (2)
[tex]x\ge-5[/tex]this inequality represents the numbers greater or equal than -5 ( for x), so to graph the inequality:
a) draw an vertical line at x=-5, and due to we are looking for the values greater or equal than -5 we need to use a solid line and shade the area to the rigth of the line
Step 3
finally, the inequality 3
[tex]y<6[/tex]this inequality represents all the y values smaller than 6, so we need to draw a horizontal line at y=6 and shade the area below the line
Step 4
finally, the solution is the intersection of the areas
I hope this helps you
A chef is going to use a mixture of two brands of italian dressing. the first brand contains 7% vinegar and the second brand contains 12% vinegar. the chef wants to make 280 milliliters of a dressing that is 9% vinegar. how much of each brand should she use
We know that
• The first brand contains 7% vinegar.
,• The second brand contains 12% vinegar.
,• The chef wants 280 milliliters with 9% vinegar.
Using the given information, we can express the following equation.
[tex]0.07x+0.12(280-x)=0.09(280)[/tex]Notice that 0.07x represents the first brand, 0.12(280-x) represents the second brand, and 0.08(280) represents the final product the chef wants to make.
Let's solve for x.
[tex]\begin{gathered} 0.07x+33.6-0.12x=25.2 \\ -0.05x=25.2-33.6 \\ -0.05x=-8.4 \\ x=\frac{-8.4}{-0.05} \\ x=168 \end{gathered}[/tex]Therefore, the chef needs 168 of the first brand and 112 of the second brand.Notice that 280-168 = 112.
please help me please
F (x) = (-1/20)x + 13.6
Then
Radmanovics car y -intercept is= 13.6 gallons
Mr Chin's car y-intercept is= 13.2
Then , in consecuence
Radmanovics car has a larger tank, than Mr Chin's car.
Answer is OPTION D)
Consider the angle shown below that has a radian measure of 2.9. A circle with a radius of 2.6 cm is centered at the angle's vertex, and the terminal point is shown.What is the terminal point's distance to the right of the center of the circle measured in radius lengths? ______radii What is the terminal point's distance to the right of the center of the circle measured in cm?_______ cm What is the terminal point's distance above the center of the circle measured in radius lengths?_____ radii What is the terminal point's distance above the center of the circle measured in cm? _____cm
Remember that we can use some trigonometric identities to find relations between distances in a circle when the central angle is provided:
If we measure each distance in radius lengths, it is equivalent to take r=1 on those formulas.
A)
The terminal point's distance to the right of the center of the circle, measured in radius lengths, would be:
[tex]\cos (2.9\text{rad})=-0.9709581651\ldots[/tex]This distance is signed since it indicates an orientation, but we can ignore the sign if we are only interested on the value of the distance.
Then, such distance would be approximately 0.97 radii,
B)
Multiply the distance measured in radius lengths by the length of the radius to find the distance measured in cm:
[tex]0.97\times2.6cm=2.52\operatorname{cm}[/tex]C)
The terminal point's distance above the center of the circle can be calculated using the sine function:
[tex]\sin (2.9\text{rad})=0.2392493292\ldots[/tex]Therefore, such distance is approximately 0.24 radii.
D)
Multiply the distance measured in radius length times the length of the radius to find the distance measured in cm:
[tex]0.24\times2.6\operatorname{cm}=0.62\operatorname{cm}[/tex]Y = X - 8. y = -x +6* Parallel Perpendicular Neither
The equation of a line given in slope-intercept form is written as
[tex]\begin{gathered} y=mx+b \\ \text{Where m is the slope. This means the coeeficient of x is the slope} \end{gathered}[/tex]For two lines to be parallel, their slopes must equal to each other. Also for the two lines to be perpendicular, their slopes must be a negative inverse of each other. An example of negative inverse is given as;
[tex]\begin{gathered} -\frac{1}{4}\text{ is a negative inverse of 4} \\ \text{Likewise, -4 is a negative inverse of }\frac{1}{4}\text{ } \end{gathered}[/tex]The slope of the first line is 1, since the line is given as,
y = x - 8
(The coefficient of x is 1)
The slope of the second line is -1, since the line is given as,
y = -x + 8
(The coefficient of x is -1)
Therefore, since both slopes are not equal and not negative inverses of each other, then the correct answer is NEITHER.
-1.5(x - 2) = 6. What is X equaled to
Answer:
x-2=6÷(-1.5)
x-2=-4
x=-4-2
x=-6
suppose that z varies jointly with x and y. When x=2, y=2, z=7 write the equation that models the relationship
Be specific with your answer thank you thank you thank you bye-bye
The y-axis on the graph, that shows us the cost, goes from 2 to 2 units.
To find the cost at option one, the red line, we look in the graph where the line is when x = 80.
For x= 80, y= 58
Now, the same for option 2:
For x = 80, y= 44.
58-44 = 14
Answer: The difference is 14.
The Max or Min can be found by using the line of symmetry. That line of symmetry can be found by finding the midpoint of the two x-intercepts.Since the line of symmetry is x =-1 Write the function rule to find the coordinate to the minimum of this parabola.[tex]f (x) = (x - 2)(x + 4)[/tex]your answer should be in the form (_,_)
We know that, for a parabola, the minimum, or the maximum, is given by the vertex of the parabola. The formula for the vertex of the parabola is given by:
[tex]x_v=-\frac{b}{2a},y_v=c-\frac{b^2}{4a}[/tex]And we have the coordinates for x and y for the vertex.
We can see that the line of symmetry is x = -1, and this is the same value for the value of the vertex for x-coordinate, that is, the x-coordinate is equal to x = -1.
With this value for x, we can find the y-coordinate using the given equation of the parabola:
[tex]f(x)=(x-2)\cdot(x+4)\Rightarrow f(-1)=(-1-2)\cdot(-1+4)\Rightarrow f(-1)=(-3)\cdot(3)[/tex]We can also expand these two factors, and we will get the same result:
[tex]f(x)=(x-2)\cdot(x+4)=x^2+2x-8=(-1)^2+2\cdot(-1)-8=1-2-8=-1-8=-9[/tex]Therefore, the value for the y-coordinate (the value for the y-coordinate of the parabola, which is, at the same time, the minimum point for y of the parabola) is:
[tex]f(-1)=(-3)\cdot(3)\Rightarrow f(-1)=-9[/tex]The minimum point of the parabola is (-1, -9) (answer), and we used the given function (rule) to find the value of the y-coordinate.
We can check these two values using the formula for the vertex of the parabola as follows:
[tex]f(x)=(x-2)\cdot(x+4)=x^2+2x-8[/tex]Then, a = 1 (it is positive so the parabola has a minimum), b = 2, and c = -8.
Hence, we have (for the value of the x-coordinate, which is, at the same time, the value for the axis of symmetry in this case):
[tex]x_v=-\frac{2}{2\cdot1}\Rightarrow x_v=-1[/tex]And for the value of the y-coordinate, we have:
[tex]y_v=c-\frac{b^2}{4a}\Rightarrow y_v=-8-\frac{2^2}{4\cdot1}=-8-\frac{4}{4}=-8-1\Rightarrow y_v=-9[/tex]
For 5 years, Gavin has had a checking account at Truth Bank. He uses a bank ATM 2 times per month and a nonbank ATM once a month. He checks his account statement online. How much money would Gavin save per month if he switched to Old River Bank?
EXPLANATION
Let's see the facts:
Number of years: 5
Account period = 2 times/month
Nonbank ATM -------> once/ month
If he switch the account to Old River Bank he would save:
$6 - $4.95 = $1.05
Transaction cost_Trust Bank = $1/transaction * 2 = $2
Nonbank_Trust Bank = $2/transaction = $2
Trust Bank Cost = 2 + 2 + 6 = $10
The account in the Old River Bank would be:
Account Services = $4.95
Bank ATM Cost = $0.00
Nonbank ATM Cost = $2.5/transactions * 1 = $2.5
----------------------
$7.45
The total cost at Old River would be = $7.45
The difference between Truth Bank and Old River would be $10-$7.45 = $2.55
Gavin would save $2.55 per month.
Assume that each circle shown below represents one unit. Express the sha amount as a single fraction and as a mixed number. One Fraction: Mixed Number:
The shaded portions for the first three circles are a total of 15 while for the fourth one is 1. As a fraction it is therefore,
[tex]\frac{16}{5}[/tex]As mixed numbers it is;
[tex]3\frac{1}{5}[/tex]cos(alpha + beta) = cos^2 alpha - sin^2 beta
The trigonometric identity cos(α + β)cos(α - β) = cos²(α) - sin²(β) is verified in this answer.
Verifying the trigonometric identityThe identity is defined as follows:
cos(α + β)cos(α - β) = cos²(α) - sin²(β)
The cosine of the sum and the cosine of the subtraction identities are given as follows:
cos(α + β) = cos(α)cos(β) - sin(α)sin(β).cos(α - β) = cos(α)cos(β) + sin(α)sin(β).Hence, the multiplication of these measures is given as follows:
cos(α + β)cos(α - β) = (cos(α)cos(β) - sin(α)sin(β))(cos(α)cos(β) + sin(α)sin(β))
Applying the subtraction of perfect squares, it is found that:
(cos(α)cos(β) - sin(α)sin(β))(cos(α)cos(β) + sin(α)sin(β)) = cos²(α)cos²(β) - sin²(α)sin²(β)
Then another identity is applied, as follows:
sin²(β) + cos²(β) = 1 -> cos²(β) = 1 - sin²(β).sin²(α) + cos²(α) = 1 -> sin²(α) = 1 - cos²(a).Then the expression is:
cos²(α)cos²(β) - sin²(α)sin²(β) = cos²(α)(1 - sin²(β)) - (1 - cos²(a))sin²(β)
Applying the distributive property, the simplified expression is:
cos²(α) - sin²(β)
Which proves the identity.
Missing informationThe complete identity is:
cos(α + β)cos(α - β) = cos²(α) - sin²(β)
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Find the value of x that makes ADEF ~AXYZ..yE1052x – 114D11FX5x + 2Zх=
Given that the triangles are similar, we can express a proportion between their sides. DE and XY are corresponding sides. EF and YZ are corresponding sides. Let's define the following proportion.
[tex]\begin{gathered} \frac{XY}{DE}=\frac{YZ}{EF} \\ \frac{10}{5}=\frac{14}{2x-1} \end{gathered}[/tex]Now, we solve for x
[tex]\begin{gathered} 2=\frac{14}{2x-1} \\ 2x-1=\frac{14}{2} \\ 2x=7+1 \\ x=\frac{8}{2} \\ x=4 \end{gathered}[/tex]Hence, the answer is x = 4.Sparkles the Clown makes balloon animals for children at birthday parties. At Bridget's party, she made 5 balloon poodles and 1 balloon giraffe, which used a total of 15 balloons. For Eduardo's party, she used 7 balloons to make 1 balloon poodle and 1 balloon giraffe. How many balloons does each animal require?
Let p be the number of balloons required to make one balloon poodle and g the number of balloons required to make one balloon giraffe.
Then we have:
I) 5p + g = 15
II) p + g = 7
Subtracting equation II from equation I, we have:
5p - p + g - g = 15 - 7
4p = 8
p = 8/4
p = 2
Replacing p with 2 in equation II we have:
2 + g = 7
g = 7 - 2
g = 5
Answer: Each poodle requires 2 balloons and each giraffe requires 5 balloons.
What are all of the x-intercepts of the continuousfunction in the table?Х-4-20246f(x)02820-20 (0,8)O (4,0)O (4,0), (4,0)O (4,0), (0, 8), (4,0)
The x-intercepts of any function f(x) occur when f(x)=0.
As a reminder, f(x) corresponds to the y coordinate for any given x.
So, we need to focus on the parts of the table where f(x)=0 and look at the x value, that will give us the coordinates of the x-intercepts.
We can see the first entry in the table has f(x)=0 and x= -4.
The only other entry in the table where f(x)=0 has x=4.
As such, the x-intercepts of the given function are (-4,0) and (4,0), which are the coordinates presented in the third option.
Write the first 4 terms of the sequence defined by the given rule. f(1)=7 f(n)=-4xf(n-1)-50
The first 4 terms of the sequence defined by the rule f(n) = -4 x f(n - 1) - 50 are 7,
Sequence:
A sequence is an enumerated collection of objects in which repetitions are allowed and order matters.
Given,
The rule of the sequence is f(n) = -4 x f(n - 1) - 50
Value of the first term = f(1) = 7
Now we need to find the other 4 others in the sequence.
To find the value of the sequence we have to apply the value of n.
Here we have to take the value of n as 1, 2, 3, and 4.
We already know that the value of f(1) is 7.
So, now we need to find the value of f(2), that is calculated by apply the value on the given rule,
f(2) = -4 x f(2 - 1) - 50
f(2) = -4 x f(1) - 50
f(2) = -4 x 7 - 50
f(2) = -28 - 50
f(2) = -78
Similarly, the value of n as 3, then the value of f(3) is,
f(3) = -4 x f(3 - 1) - 50
f(3) = -4 x f(2) - 50
f(3) = -4 x - 78 - 50
f(3) = 312 - 50
f(3) = 262
Finally, when we take the value of n as 4 then the value of f(4) is,
f(4) = -4 x f(4 - 1) - 50
f(4) = -4 x f(3) - 50
f(4) = -4 x 262 - 50
f(4) = -1048 - 50
f(4) = -1099
Therefore, the first 4 sequence are 7, - 78, 262 and -1099.
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Find equation of a parallel line and the given points. Write the equation in slope-intercept form Line y=3x+4 point (2,5)
Given the equation:
y = 3x + 4
Given the point:
(x, y ) ==> (2, 5)
Let's find the equation of a line parallel to the given equation and which passes through the point.
Apply the slope-intercept form:
y = mx + b
Where m is the slope and b is the y-intercept.
Hence, the slope of the given equation is:
m = 3
Parallel lines have equal slopes.
Therefore, the slope of the paralle line is = 3
To find the y-intercept of the parallel line, substitute 3 for m, then input the values of the point for x and y.
We have:
y = mx + b
5 = 3(2) + b
5 = 6 + b
Substitute 6 from both sides:
5 - 6 = 6 - 6 + b
-1 = b
b = -1
Therefore, the y-intercept of the parallel line is -1.
Hence, the equation of the parallel line in slope-intercept form is:
y = 3x - 1
ANSWER:
[tex]y=3x-1[/tex]
What is a solution of a system of linear equations in three variables?
Hello!
When we have a system with the same number of variables and equations, we can obtain the value for all variables.
Knowing it, the right alternative will be:
Alternative B.
Determine which is the better investment 3.99% compounded semi annually Lee 3.8% compounded quarterly round your answer 2 decimal places
Remember that
The compound interest formula is equal to
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]In the 3.99% compounded semiannually
we have
r=3.99%=0.0399
n=2
substitute
[tex]\begin{gathered} A=P(1+\frac{0.0399}{2})^{2t} \\ \\ A=P(1.01995)^{2t} \end{gathered}[/tex]and
[tex]\begin{gathered} A=P[(1.01995)^2]^t \\ A=P(1.0403)^t \end{gathered}[/tex]the rate is r=1.0403-1=0.0403=4.03%
In the 3.8% compounded quarterly
we have
r=3.8%=0.038
n=4
substitute
[tex]\begin{gathered} A=P(1+\frac{0.038}{4})^{2t} \\ A=P(1.0095)^{2t} \\ A=P[(1.0095)^2]^t \\ A=P(1.0191)^t \end{gathered}[/tex]the rate is r=1.0191-1=0.0191=1.91%
therefore
the 3.99% compounded semiannually is a better investmentA trapezoid has a height of 16 miles. The lengths of the bases are 20 miles and 35miles. What is the area, in square miles, of the trapezoid?
Given:
A trapezoid has a height of 16 miles.
The lengths of the bases are 20 miles and 35 miles.
To find:
The area of the trapezoid.
Explanation:
Using the area formula of the trapezoid,
[tex]A=\frac{1}{2}(b_1+b_2)h[/tex]On substitution we get,
[tex]\begin{gathered} A=\frac{1}{2}(20+35)\times16 \\ =\frac{1}{2}\times55\times16 \\ =440\text{ square miles} \end{gathered}[/tex]Therefore the area of the trapezoid is 440 square miles.
Final answer:
The area of the trapezoid is 440 square miles.
38. A right rectangular prism has a volume of 5 cubic meters. The length ofthe rectangular prism is 8 meters, and the width of the rectangular prismis a meter.What is the height, in meters, of the prism?Niu4© 30 10
It's important to know that the volume formula for a rectangular prism is
[tex]V=l\cdot w\cdot h[/tex]Where V = 5, l = 8, and w = 1. Let's use these values and find h
[tex]\begin{gathered} 5m^3=8m\cdot1m\cdot h \\ h=\frac{5m^3}{8m^2} \\ h=0.625m \end{gathered}[/tex]Hence, the height of the prism is 0.625 meters.How do we determine the number of hours each family used the sprinklers?
Given:
The output rate of Martinez family's sprinkler is 25L per hour and Green family's sprinkler is 35L per hour. The combined usage of sprinkler is 40 hours. The resulting water output is 1250L.
To find:
The number of hours each family used the sprinkler.
Solution:
Let Martinez family used sprinkler for x hours and Green family used sprinkler for y hours.
Since the combined usage of sprinklers is 40 hours. So,
[tex]x+y=40...\left(i\right)[/tex]The output rate of Martinez family's sprinkler is 25L per hour and Green family's sprinkler is 35L per hour. The resulting water output is 1250L. So,
[tex]\begin{gathered} 25x+35y=1250 \\ 5x+7y=250...\left(ii\right) \end{gathered}[/tex]Multiply (i) by 7 and subtract from (ii), to get:
[tex]\begin{gathered} 5x+7y-7\left(x+y\right)=250-7\left(40\right) \\ 5x+7y-7x-7y=250-280 \\ -2x=-30 \\ x=\frac{-30}{-2} \\ x=15 \end{gathered}[/tex]Now, we get x = 15, Put x = 15 in the equation (i):
[tex]\begin{gathered} 15+y=40 \\ y=40-15 \\ y=25 \end{gathered}[/tex]Thus, x = 15, y = 25.