When energy is added to a wave, how can the wave change?.

Answer:

No, the eggs are in direct contact with the metal pan, which is in direct contact with the gas flame, so this is conduction, not radiation

Reasons:
-Thermal energy is being transferred by conduction.

-Radiation transfers thermal energy by electromagnetic waves.

-Radiation does not transfer thermal energy by direct contact.

Radiation heat transfer is a process where heatwaves are emitted that may be absorbed, reflected, or transmitted through a colder "body". Sun heats the earth by electromagnetic waves. The sun does not come in physical contact with the Earth to transfer heat. (In my opinion, the Earth touching the sun would not be on my to-do list.)

Explanation:

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Answer:

Vaccum

Explanation:

You can test it .

The specific heat capacity of the calorimeter used in mixing the water is determined as 21.87 J/g⁰C.

The heat capacity of the calirometer is determined by applying the principle of conservation of energy.

Heat lost by the hot water = Heat gained by the calirometer

[tex]Q _w = Q_c\\\\M_w C_w\Delta \theta _w = M_c C_c\Delta \theta _c[/tex]

where;

mass = density x volume = ρV

Density of water = 1 g/ml

Mass of hot water = 1 x (50) = 50 g

Mass of water in calorimeter = 1 x (60) = 60 g

[tex]\Delta T_c = 5.5\\\\T - 25 = 5.5\\\\T = 30.5 \ ^0C[/tex]

[tex]50 \times 4.184 \times (65 - 30.5) = 60 \times C_c \times (30.5 - 25)\\\\7217.4 = 330C_c\\\\C_c = \frac{7217.4}{330} \\\\C_c = 21.87 \ J/g^0C[/tex]

Thus, the specific heat capacity of the calorimeter used in mixing the water is determined as 21.87 J/g⁰C.

The complete question is below

When using a different calorimeter, and mixing 50 ml of hot water at

65 degrees C with 60 ml of water in the calorimeter at 25 degrees C, the temperature of the calorimeter increased by 5.5 degrees C.

a. Calculate the heat capacity of this calorimeter?

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Answer: When you name an element, it's usually because the element is newly discovered. So by naming an element you are creating something that will last throughout history.

Explanation:

Astronomers suspected an eighth planet beyond Uranus because of the irregularities in the motion of Uranus suggested that gravity from another planet was affecting it.

It should be noted that an astronaut simply means an individual who is trained to travel in spacecrafts.

In this case, astronomers suspected an eighth planet beyond Uranus because of the irregularities in the motion of Uranus suggested that gravity from another planet was affecting it.

In mid-1800s, astronomers used the orbits of most asteroids to predict where a planet would have to be.

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Answer:

 The main reasons are two. Mercury's atmosphere is hard to hold onto because it is small and does not have much gravity. As Mercury is close to the Sun, any atmosphere is blasted away by material being blown off the Sun.

Hope this helps friend!

Answer:

no sabo por q no mi entender

The smooth muscle in the wall of the bladder when stretched triggers the micturition reflex (urination).

This is defined as a lined layers of muscle tissue that stretch to hold urine in organisms.

In older people the elasticity of the bladder is reduced which is why it makes it harder for them to hold urine for a long time.

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Answer:

is 200 J

Explanation:

hope this is the right answer

The angular acceleration of the rotating wheel at the given rate of change of angular velocity is 0.21 rad/s².

The angular acceleration of an object is the rate of change of anguar velocity of the object with time.

[tex]\alpha = \frac{\Delta \omega }{\Delta t}[/tex]

where;

Change in angular velocity of the wheel is calculated as follows;

[tex]\Delta \omega = 2 \ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} = 4\pi \ rad/s = 12.57 \ rad/s[/tex]

Change in time, Δt = 1 min = 60 s

The angular acceleration of the rotating wheel is calculated as follows;

α = (12.57) / (60)

α = 0.21 rad/s²

Thus, the angular acceleration of the rotating wheel at the given rate of change of angular velocity is 0.21 rad/s².

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Answer:

(D) light deflected around large objects because of their gravity

I hope this helps you

:)

Answer:

2.5A

Explanation:

We know the relation :

V = IR

By using the formula,

Answer :-

Explanation :-

As per the provided information in the given question, we have been given that the Potential Difference is 30 Volt . The Resistance is given as 12 Ohm . And, we have been asked to calculate the Current of the Device.

For calculating the Current , we will use the Formula :-

[tex] \bigstar \: \: \: \boxed { \sf{ \: Current \: = \: \dfrac{Potential \: Difference}{Resistance} \: }} [/tex]

Therefore , by Substituting the given values in the above Formula :-

[tex] \dag \: \: \: \sf { Current \: = \: \dfrac{Potential \: Difference}{Resistance} } [/tex]

[tex] \longmapsto \: \: \: \sf { Current \: = \: \dfrac{30}{12} } [/tex]

[tex] \longmapsto \: \: \: \textbf {\textsf {Current \: = \: 2.5 }} [/tex]

Hence :-

[tex]\underline {\rule {180pt} {4pt}} [/tex]

I believe the answer to your question would be True

The answers on the model of the human centrifuge ready for the launch to each question of the statement are listed below:

a) A force of 2479.210 newtons is acting on the astronaut's back.

b) A net centripetal force of 2479.210 newtons is acting on the astronaut.

c) The centripetal acceleration of the astronaut is 30.990 meters per square second.

d) The astronaut has a linear speed of approximately 19.284 meters per second.

e) The angular speed of the astronaut is 1.607 radians per second (15.346 revolutions per minute).

The human centrifuge experiments a centripetal acceleration when it reaches a peak angular speed. In this question we must apply Newton's laws of motion and concepts of centripete and centrifugal forces to answer the questions. Now we proceed to answer the questions:

By the third Newton's law the astronaut experiments a rection force (F), in newtons, which has the same magnitude to centrifugal force but opposed to that force. The magnitude of the force acting on the back of the astronaut is equal to:

[tex]F = 3.16\cdot (80\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]

[tex]F = 2479.210\,N[/tex]

A force of 2479.210 newtons is acting on the astronaut's back. [tex]\blacksquare[/tex]

By the second and third Newton's laws we know that the net centripetal force on the astronaut is equal to the magnitude of the force found in the previous question. Thus, a net centripetal force of 2479.210 newtons is acting on the astronaut. [tex]\blacksquare[/tex]

The centripetal acceleration of the astronaut (a), in meters per square second, is found by dividing the result of the previous question by the mass of the astronaut (m), in kilograms:

[tex]a = \frac{F}{m}[/tex]   (1)

If we know that F = 2479.210 newtons and m = 80 kilograms, then the centripetal acceleration of the astronaut is:

[tex]a = \frac{2479.210\,N}{80\,kg}[/tex]

[tex]a = 30.990\,\frac{m}{s^{2}}[/tex]

The centripetal acceleration of the astronaut is 30.990 meters per square second. [tex]\blacksquare[/tex]

By definition of uniform circular motion, we have the following formula for the linear velocity of the astronaut (v):

[tex]v = \sqrt{a\cdot r}[/tex]   (1)

Where r is the radius of the human centrifuge, in meters.

If we know that [tex]a = 30.990\,\frac{m}{s^{2}}[/tex] and [tex]r = 12\,m[/tex], then linear velocity of the astronaut is:

[tex]v = \sqrt{\left(30.990\,\frac{m}{s^{2}} \right)\cdot (12\,m)}[/tex]

v ≈ 19.284 m/s

The astronaut has a linear speed of approximately 19.284 meters per second. [tex]\blacksquare[/tex]

The angular speed of the astronaut (ω), in radians per second, is found by the following kinematic relationship:

[tex]\omega = \frac{v}{R}[/tex]   (1)

If we know that v ≈ 19.284 m/s and R = 12 m, then the angular speed is:

[tex]\omega = \frac{19.284\,\frac{m}{s} }{12\,m}[/tex]

ω = 1.607 rad/s (15.346 rev/m)

The angular speed of the astronaut is 1.607 radians per second (15.346 revolutions per minute). [tex]\blacksquare[/tex]

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Answer:

The answer is medial!

Explanation:

The vertebral region is medial to the scapula.

Hope This Helps!

-Justin:)

Here is the solution for previous question

[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{m}{k}}[/tex]

[tex]\\ \rm\rightarrowtail T\propto \sqrt{m}[/tex]

Hence

[tex]\\ \rm\rightarrowtail \dfrac{T_1}{T_2}=\sqrt{\dfrac{m1}{m2}}[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{1.5}{2}=\sqrt{\dfrac{0.5}{m2}}[/tex]

[tex]\\ \rm\rightarrowtail 0.75^2=\dfrac{0.5}{m2}[/tex]

[tex]\\ \rm\rightarrowtail m_2=\dfrac{0.5}{0.75^2}[/tex]

[tex]\\ \rm\rightarrowtail m_2=0.888888888\dots[/tex]

So

from this

So it's infinite in terms of 8 so must be greter than one 8

We rounded it up for 3 decimals

So

Error range=[1.99,2.01]

Very mere one

Now find percentage

[tex]\\ \rm\rightarrowtail \dfrac{0.02}{2}(100)=0.01(100)=1\%[/tex]

Mass should be lied in

But for increase mass

it would be

[tex]\\ \rm\rightarrowtail \nu=\dfrac{1}{T}[/tex]

[tex]\\ \rm\rightarrowtail T=\dfrac{1}{\nu}[/tex]

[tex]\\ \rm\rightarrowtail T=\dfrac{1}{60}[/tex]

[tex]\\ \rm\rightarrowtail T=1.67\times 10^{-4}s[/tex]

[tex]\\ \rm\rightarrowtail T=16.7\times 10^{-3}s[/tex]

[tex]\\ \rm\rightarrowtail T=16.7ms[/tex]

The acceleration of the garbage can is 2.55 m/s².

Acceleration is the rate of change of velocity with respect to time.

To calculate the acceleration of the can, we use the formula below

Formula:

Where:

Make a the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, the acceleration of the garbage can is 2.55 m/s².

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Answer:

answer down below

Explanation:

it has similar mass but the white dwarf is much denser

Answer:

15in2

Explanation:

The diagram shows part of a radio antenna.The plastic tube protects the radio antenna from bad weather.Dust particles carried by the wind rub against the plastic tube.After some time, the dust particles cause the tube to become positively charged.State the property of plastic that allows it to become electrostatically charged.

Have a good day!! :>

Answer:

Uranus

Explanation:

Your welcome

A planet is a celestial body. The third-largest planet in the solar system is Uranus.

A celestial body is differentiated from the fixed stars by its apparent mobility (including the moon and sun), especially in relation to its claimed impact on people and events.

A planet is a celestial body. The third-largest planet in the solar system is Uranus.

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Torque:-

[tex]\\ \rm\Rrightarrow \tau =14(0.018)[/tex]

[tex]\\ \rm\Rrightarrow \tau=0.25Nm[/tex]

option B

The new period of the pendulum when it is taken to the new planet is  double of its period on Earth.

The period of a pendulum is given by the following formula;

[tex]T = 2\pi \sqrt{\frac{l}{g} }[/tex]

where;

The acceleration due to gravity of the new planet is calculated as follows;

[tex]g_E = \frac{GM_E}{R_E^2} = 9.81 \ m/s^2 \\\\g(new \ planet) = \frac{G(4M_E)}{(4R_E)^2} = \frac{4GM_E}{16R_E^2} = \frac{GM_E}{4R_E^2} = \frac{9.81}{4} = 2.45 \ m/s^2[/tex]

[tex]T = 2\pi \sqrt{\frac{l}{g} } \\\\T =\frac{2\pi \sqrt{l} }{\sqrt{g} } \\\\T_1\sqrt{g_1} = T_2\sqrt{g_2} \\\\T_E\sqrt{g_E} = T\sqrt{g} \\\\T = \frac{T_E\sqrt{g_E}}{\sqrt{g} } \\\\T = \frac{T_E \times \sqrt{9.81} }{\sqrt{2.45} } \\\\T = 2T_E[/tex]

Thus, the new period of the pendulum when it is taken to the new planet is double of its period on Earth.

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Answer:

When a circuit breaker regularly trips or a fuse repeatedly blows, it is a sign that you are making excessive demands on the circuit and need to move some appliances and devices to other circuits. Or, it may indicate that your house has too few circuits and is in need of a service upgrade.

no

Explanation:

no not an vibration signal

Answer:

Edmond Locard

Explanation:

Hope this helps :)

The three types of equilibrium in an object are;  stable, unstable, or neutral equilibrium.

The term equilibrium refers to a situation in which all the forces acting on an object are balanced such that the object does not move. The question is incomplete as the images are missing.

There are three types of equilibrium:

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When an object standing on the floor is tipped, the height of its center of gravity (cg) for each case as stable, unstable, or neutral may increase, decreased and remain same respectively.

Equilibrium is the location of the body, in which the body be static or in motion and does not change it with respect to time.

The equilibrium of an object can be classified in the 3 following types.

When an object standing on the floor is tipped, the height of its center of gravity (cg) may or may not change.

The stability of object demands in the center of gravity. Lower the value of CG, results in more stable object. For each case,

Thus, when an object standing on the floor is tipped, the height of its center of gravity (cg) for each case as stable, unstable, or neutral may increase, decreased and remain same respectively.

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Answer:

A protostar is the earliest stage of a star's life. A star is born when the gas and dust from a nebula become so hot that nuclear fusion starts.

The origin of star is called nebula. The earliest stage of a star’s life before it begins to undergo fusion is known as a protostar.

Every star begins from nebula. A nebula is a huge gas and dust cloud. Some of the gas and dust in a nebula can be drawn together by gravity. The cloud's contraction is then described as a protostar. The first stage of a star's life is called a protostar.

As the gas and dust from a nebula heat up to a point where nuclear fusion begins, a star is created. A star is referred to as a main sequence star once it has "switched on". A main sequence star turns into a red giant or a red super giant when its hydrogen fuel runs exhausted.

An exploding red super massive star is possible. It is referred to be a supernova. After the star explodes, some of the ingredients from the star are left behind. Hence, the earlier stage of a star before fusion starts is called a protostar.

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Polarization refers to the tendency for acquiring specific orientation by the oscillation.

Polarization is a property that specifies the geometrical orientation of the oscillations. In a transverse wave, the direction of the oscillation is perpendicular as compared to other that have parallel.

So we can conclude that Polarization refers to the tendency for acquiring specific orientation by the oscillation.

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