When are zeros significant when found in front of (to the left) of the decimal point?

Answer:

30 feet

Explanation:

First off, if they are throwing at 12.0 m/s and it takes 2.5 seconds. It will be the act of multiplication.

12 times 2.5 is 30, because 12 times 2 is 24 plus 12 divided by 2 which is 6 so 24 plus 6 is 30.

Answer:The answer is this Positive acceleration describes an increase in speed, negative sexeleration desnibes a decrease in speed

Explanation:

Answer:

Explanation:

angular velocity ω = 2π / T where T is time period of rotation .

= 2 x 3.14 / .34 = 18.47 rad /s

Total mechanical energy = 1/2 m ω²Α² where A is amplitude .

spring constant = k

[tex]\omega=\sqrt{\frac{k}{m} }[/tex]  

m is mass

[tex]\omega^2=\frac{k}{m} }[/tex]

18.47² = k / .3

k = 102.34 N /m

b )

energy = 1/2 m ω²Α²

3 = .5 x 18.47² x A²

A² = .01759

A = .1326

13.26 cm .

c )

If energy becomes 5 J

5 = .5 x 18.47² x A²

A² = .0293

A = .1711

= 17.11 cm

percent increase

= (17.11 - 13.26 )x100 / 13.26

= 29%

Answer:

matter

Explanation:

Hope I helped :)

The net force on the cart is 100 N in the direction of its motion, so by Newton's second law we can find the acceleration a applied to it:

100 N = (50 kg) a

a = (100 N) / (50 kg)

a = 2 m/s²

The cart starts at rest and travels a distance of 10 m, so that its final velocity v satisfies

v ² - 0² = 2 (2 m/s²) (10 m)

v ²= 40 m²/s²

and so the cart ends up with kinetic energy

KE = 1/2 m v ² = 1/2 (50 kg) (40 m²/s²) = 1000 J

Answer: what’s the model

Explanation:

it's B hope this help's

Answer:

a = 0.9139 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

The forces are on two different axes, x & y axes (North and East). In this way, the Pythagorean theorem should be used to determine the total force.

Fx = 1800 [N]

Fy = 1050 [N]

[tex]F = \sqrt{(F_{x} )^{2} +(F_{y} )^{2} } \\F=\sqrt{(1800)^{2} +(1050)^{2} } \\F=2083[N][/tex]

Now using Newton's second law.

ΣF = m*a

where:

F = force = 2083.8 [N] (units of Newtons)

m = mass = 2280 [Kg]

a = acceleration [m/s²]

2083.8 = 2280*a

a = 0.9139 [m/s²]

The car's rate of centripetal acceleration in the circular path is 4.8 m/s².

The given parameters;

The centripetal acceleration of the car is calculated as follows;

[tex]a_c = \frac{v^2}{r}[/tex]

where;

Substitute the given parameters and solve for the centripetal acceleration;

[tex]a_c = \frac{12^2}{30} \\\\a_c = 4.8 \ m/s^2[/tex]

Thus, the car's rate of centripetal acceleration is 4.8 m/s².

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Answer:

OB. Heat

Explanation:

I hope this helped :)

Explanation:

Given parameters:

Power of the toaster  = 600W

Voltage  = 120V

Unknown:

Current = ?

Resistance = ?

Solution:

The power in the circuit is related to resistance and current using the expression below;

       P = IV  

       P = [tex]\frac{V^{2} }{R}[/tex]

P is the power

I is the current

V is the voltage

R is the resistance

    To find the current;

        I = [tex]\frac{P}{V}[/tex]   = [tex]\frac{600}{120}[/tex]  = 5A

     Now, resistance;

       V²   = PR

       R = [tex]\frac{V^{2} }{P}[/tex]   = [tex]\frac{120^{2} }{600}[/tex]  = 24ohms

Current, I=5A

Resistance, R=24 ohms

Firstly, let's write the given values:

Power, P=600W

Voltage, V=120V

To find:

Current, I=?

Resistance, R=?

Lets understand ohm's Law:

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.

Formula for Ohm's law:

[tex]V=I.R[/tex]

The relation between power, current and resistance can be represented as:[tex]P=I.V[/tex]

Or

[tex]P=\frac{V^2}{R}[/tex]

To find current:

[tex]I=\frac{P}{V}[/tex]

So on substituting given values,

[tex]I=\frac{600}{120} =5A[/tex]

To find resistance:

[tex]R=\frac{V^2}{P}[/tex]

So on substituting given values,

[tex]R=\frac{14400}{600} =24 \text{ohms}[/tex]

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The ball rolls to a rest from 4.0 m/s in a span of 23.3 s - 10.0 s = 13.3 s, so the average acceleration is

(0 - 4.0 m/s) / (13.3 s) ≈ -0.30 m/s²

Answer:

-4

Explanation:

Electrons are negative while protons are positive.

To find the charge, add the number of protons to the number of electrons.

6+(-10)

6-10

-4 is the charge

The correct answer is Ammonia

Answer:

Solution A has a pH of 6 and solution B has a pH of 8. Which of the following is true regarding the concentration of hydrogen ions in each solution? A) A has 100 times greater H+ concentration than B. B) B has 100 times greater H+ concentration than A. C) A has 7/9 of the H+ concentration of B. D) A has 9/7 of the H+ concentration of B. E) none of these

Explanation:

Hey im super sorry if i get this wrong :)

Answer:

when the rubber band is realeased the potential energy is quickly converted to kinetic energy this is equal to one mass of the the rubber band multiplied by its velocity( in meters per second)

The jogger would have ran about 10 km/h.

Answer:

Condensation

Explanation:

Answer:When water changes from a gas in the atmosphere to a liquid droplet in a cloud, this is known as

Group of answer choices

transpiration

condensation

evaporation

precipitation,←, that one is right

Explanation: so ur answer is precipitation

Answer:

The velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.

Explanation:

To find the velocity of the blood we need to use the continuity equation:

[tex] n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2} [/tex]   (1)  

Where:

n: is the number of branches

A: is the cross-sectional area

v: is the velocity

For artery 1, we have:

n₁ = 1, A₁ = 1 cm², v₁ = v

For the 20 arteries (2), we have:

n₂ = 20, A₂ = 0.5 cm², v₂ =?

By using equation (1):

[tex] n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2} [/tex]

[tex] 1 cm^{2}*v = 20*0.5 cm^{2}*v_{2} [/tex]

[tex] v_{2} = \frac{1 cm^{2}*v}{20*0.5 cm^{2}} = \frac{v}{10} = 0.1v [/tex]

Therefore, the velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.

I hope it helps you!      

Answer:

Option B: 9 kg.m/s North

Explanation:

We are told;

One player has a mass of

66 kg and is traveling at 1.5 m/s north.

Thus, velocity is positive since it's acting in the positive direction upwards.

Thus;

m1 = 66 kg

v1 = 1.5 m/s

Also, The other has a mass of 75 kg and is traveling at 1.2 m/s south.

Since it's traveling south, it means that velocity is negative. Thus;

m2 = 75 kg

v2 = -1.2 m/s

From conservation of mass, total momentum is;

m_total = m1•v1 + m2•v2

m_total = (66 × 1.5) + (75 × -1.2)

m_total = 99 - 90

m_total = 9 kg.m/s

This is positive and thus it will be in the direction of the north.

Answer:

9 kg-m/s north

Explanation:

Answer:

METALLICA = HOT BAND

Explanation:

The answer is a, you're welcome babes

Answer: A B D

Explanation:

Answer:

Explanation:

Kinetic energy is expressed as;

KE =1/2 mv²

M is the mass

v is the velocity of the object

1) Given

Mass = 155lb

Velocity = 3.1mi/hr

Since 1kg = 2.2lb

x = 155lb

x= 155/2.2

x = 70.45kg

Also

1m/s = 2.24mi/hr

y = 3.1mi/hr

y = 3.1/2.24

y = 1.384m/s

KE = 1/2(70.45)(1.384)²

KE = 0.9577×70.45

KE = 67.47Joules

2) M = 5g =0.005kg

V = 400m/s

KE = 1/2(0.005)400²

KE = 80000×0.005

KE = 400Joules

3} Since a body decelerates (negative acceleration) this mean that the velocity of a body can be a negative value showing that it is possible for a moving body to possess negative kinetic energy.

Answer:

D

Explanation:

Answer:

A

Explanation:

The toaster was too high so its the increase in eat

Answer:

Electromagnetic Induction by a Moving Magnet

Then the action of moving a coil or loop of wire through a magnetic field induces a voltage in the coil with the magnitude of this induced voltage being proportional to the speed or velocity of the movement.

Explanation:

Answer:

1) t = 3.45 s, 2)  x = 138 m, 3) v_{y} = -33.81 m /s, 4) v = 52.37 m / s ,

5) θ = -40.2º

Explanation:

This is a projectile exercise, as they indicate that the projectile rolls down the cliff, it goes with a horizontal speed when leaving the cliff, therefore the speed is v₀ₓ = 40 m / s.

1) Let's calculate the time that Taardaen reaches the bottom, we place the reference system at the bottom of the cliff

      y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²

When leaving the cliff the speed is horizontal  v_{oy}= 0 and at the bottom of the cliff y = 0

      0 = y₀ - ½ g t2

      t = √ 2y₀ / g

      t = √ (2 60 / 9.8)

      t = 3.45 s

2) The horizontal distance traveled

     x = v₀ₓ t

     x = 40 3.45

     x = 138 m

3) The vertical velocity at the point of impact

     v_{y} = I go - g t

     v_{y} = 0 - 9.8 3.45

     v_{y} = -33.81 m /s

the negative sign indicates that the speed is down

4) the resulting velocity at this point

   v = √ (vₓ² + v_{y}²)

   v = √ (40² + 33.8²)

   v = 52.37 m / s

5) angle of impact

    tan θ = v_{y} / vx

    θ = tan⁻¹ v_{y} / vx

    θ = tan⁻¹ (-33.81 / 40)

    θ = -40.2º

6) sin (-40.2) = -0.6455

7) tan (-40.2) = -0.845

8) when the projectile falls down the cliff, the horizontal speed remains constant and the vertical speed increases, therefore the resulting speed has a direction given by the angle that is measured clockwise from the x axis

Answer:

a 0.41

plug number into equation

A horizontal baseball pitch is launched at 44 m/s. The ball will stay for 4.1 sec (approx) in the air. Hence, option C is correct.

The rate at which an object's position changes when observed from a specific point of view and when measured against a specific unit of time is known as its velocity.

Its SI unit is represented as m/s, and it is a vector quantity, it means that it has both magnitude and direction.

According to the question, the given values are :

Initial Velocity, u = 44 m/s,

Distance travelled, s = 18 m and,

Final velocity, v = 0.

Use equation of motion :

v = u + at

0 = 44 + (-9.8)t

t = 44 / 9.8

t = 4.3 (approx)

Hence, the time for which the ball stay in the air is 4.1 sec (approx).

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Answer:

5 .07 s .

Explanation:

The child will move on a circle of radius r

r = 1.5 m

Let the velocity of rotation = v

radial acceleration = v² / r

v² / r = 2.3

v² = 2.3 r = 2.3 x 1.5

= 3.45

v = 1.857 m /s

Time of revolution = 2π r / v

= 2 x 3.14 x 1.5 / 1.857

= 5 .07 s .

The merry-go round will take 5.07 s to complete one complete revolution.

Given data:

The distance of child from the center is, r = 1.5 m.

The magnitude of radial acceleration is, [tex]a = 2.3 \;\rm m/s^{2}[/tex].

Since, the child is on merry-go round, which is undergoing a rotational motion. And radial acceleration means that it is under the acceleration, whose value is given as,

[tex]a=\dfrac{v^{2}}{r}\\\\v=\sqrt{a \times r}[/tex]

Here, v is the linear velocity.

Solving as,

[tex]v=\sqrt{2.3 \times 1.5} \\\\v=1.857 \;\rm m/s[/tex]

Now, we to obtain the time taken by merry-go round to complete one revolution. Then the expression for the time taken to complete one revolution is,

[tex]T=\dfrac{2 \pi r}{v}\\\\T=\dfrac{2 \pi \times 1.5}{1.857}\\\\T = 5.07 \;\rm s[/tex]

Thus, we can conclude that the merry-go round will take 5.07 s to complete one revolution.

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